Help me please and ty!

Answer:

81 °C

Explanation:

I don’t know, I just know :)

Answer:

4464 min

Explanation:

24 hr/day  *  60 min/ hr  *  3.1 day = 4464 min

Knowing that one day is 24 hours and one hour is 60 minutes, there would be  4464 minutes in the 3.1 days.

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.

It is determined by convention or regulation.

As given in the problem , knowing that one day is 24 hours and one hour is 60 minutes, then we have to find out there are how many minutes in 3.1 days,

1 day  =  24 hours

1 day  =  24 ×60 minutes

3.1  days   = 3.1 ×24×60 minutes

                = 4464 minutes

Thus, there are 4464 minutes in 3.12 days.

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Answer:

C. The amount of coffee is the same.

Explanation:

Verified

The concentrations of the reactants and products at equilibrium, we can calculate Kc 2.56

Concentration is a measure of the amount of a substance within a given quantity of another substance or medium. It is usually expressed as mass per unit volume. For example, a concentration of a solute in a solution is the mass of that solute, per unit volume of the solution. Concentration is an important concept in many fields, including chemistry, physics, and biology, amongst other sciences.

The reaction that is happening is: S₂Cl₄(g) → 2SCl₂(g)
For the reactant, S₂Cl₄ at equilibrium:
Moles S₂Cl₄ = 1.25 moles
Volume = 2.0 L
Concentration = 1.25 moles / 2.0 L = 0.625 M
For the product, SCl₂ at equilibrium:
Moles SCl₂ = 2.5 moles (since 2 moles of SCl₂ are produced for every mole of S₂Cl₄)
Volume = 2.0 L
Concentration = 2.5 moles / 2.0 L = 1.25 M
Now that we have the concentrations of the reactants and products at equilibrium, we can calculate Kc.
Kc = [SCl₂]₂ / [S₂Cl₄]
Kc = (1.25 M)² / 0.625 M
Kc = 2.56

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Propanal and acetone are the IUPAC names for the chemical.

Propanal, commonly known as propanaldehyde, is an aldehyde with one double bond and one oxygen atom.

Acetone is a ketone compound. R2CO is the functional group of ketones.

Thus, Propanal and acetone are the IUPAC names for the chemical.

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1.01 * 10^7 grams/day

Given the reaction produced during the combustion of methane expressed as:

Calculate the moles of methane:

According to stochiometry, 1 mole of methane produces 2 moles of water. The moles of water produced at the end of the reaction will be:

Determine the mass of water produced in a day

Hence the mass in grams of water produced by this reaction in one day is approximately 1.01 * 10^7 grams

The balanced redox reaction in acidic solution:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H₂O(l)

To balance the redox reaction in acidic solution:

H₂O₂(aq) + Cr₂O₇⁻²(aq) → O₂(g) + Cr³⁺(aq)

We will follow the steps for balancing redox reactions in acidic solution:

Step 1: Assign oxidation numbers to all elements in the equation:

H₂O₂(aq): H has an oxidation state of +1, O has an oxidation state of -1.

Cr₂O₇⁻²(aq): Cr has an oxidation state of +6, O has an oxidation state of -2.

O₂(g): O has an oxidation state of 0.

Cr³⁺(aq): Cr has an oxidation state of +3.

Step 2: Identify the elements that are being oxidized and reduced:

Oxidation: Cr is being reduced from +6 to +3.

Reduction: H₂O₂ is being oxidized from -1 to 0.

Step 3: Write the half-reactions for oxidation and reduction:

Oxidation half-reaction: H₂O₂(aq) → O2(g)

Reduction half-reaction: Cr₂O₇⁻²(aq) → Cr³⁺(aq)

Step 4: Balance the atoms other than H and O in each half-reaction:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g)

Reduction half-reaction: Cr₂O₇⁻²(aq) → 2Cr³⁺(aq)

Step 5: Balance the oxygen atoms by adding water molecules (H2O) to the side that lacks oxygen:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g) + 2H₂O(l)

Reduction half-reaction: Cr₂O₇⁻²(aq) → 2Cr³⁺(aq)

Step 6: Balance the hydrogen atoms by adding hydrogen ions (H+) to the side that lacks hydrogen:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g) + 2H₂O(l)

Reduction half-reaction: Cr₂O₇⁻²(aq) + 14H+(aq) → 2Cr³⁺(aq) + 7H₂O(l)

Step 7: Balance the charges by adding electrons (e-) to the appropriate side of each half-reaction:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g) + 2H₂O(l) + 4e-

Reduction half-reaction: Cr₂O₇⁻²(aq) + 14H+(aq) + 6e- → 2Cr³⁺(aq) + 7H₂O(l)

Step 8: Multiply each half-reaction by a factor that will equalize the number of electrons in both half-reactions:

Multiply the oxidation half-reaction by 3 and the reduction half-reaction by 2:

6H₂O₂(aq) → 3O₂(g) + 6H₂O(l) + 12e-

Cr₂O₇⁻²(aq) + 14H+(aq) + 12e- → 4Cr³⁺(aq) + 14HvO(l)

Step 9: Combine the two half-reactions, canceling out the electrons on both sides:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H

Step 10: Combine all the species to form the balanced redox reaction:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H₂O(l)

Step 11: Simplify the equation by canceling out common species:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H₂O(l)

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(a) Formal charge of oxygen in the given structure is -1.

(b) The alternative Lewis structure is shown below. The unshared pairs are shown as dots and the nonzero formal charges are shown.

The given compound is nitrate ion, NO₃⁻, which has three oxygen atoms, each bonded to a central nitrogen atom.  The structure of NO₃⁻ ion is shown below. The formal charge of an atom is calculated using the following :

Formal charge = number of valence electrons in the free atom - number of non-bonded electrons - number of bonds

The formal charge of each oxygen atom is calculated as follows:For the topmost oxygen atom: 6 - 4 - 1 = 1For the middle oxygen atom: 6 - 6 - 2 = -2For the bottom oxygen atom: 6 - 4 - 1 = 1

The formal charge of the central nitrogen atom is calculated as follows:6 - 0 - 3 x 2 - 1 = 0

The sum of all formal charges is equal to the charge on the ion.

Here, the sum of all formal charges is -1, which is equal to the charge on NO₃⁻ ion. Therefore, the formal charge of oxygen is -1.

The alternative Lewis (resonance) structure of NO₃⁻ ion is shown below. In this structure, the double bond is formed between the nitrogen atom and one of the oxygen atoms, while the other two oxygen atoms bear a single bond and a formal charge of -1 each.

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Answer:

Number of moles = 0.35 mol

Explanation:

Given data:

Mass of H₂SO₄ = 34.6 g

Number of moles = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of H₂SO₄ = 98.1 g/mol

by putting values,

Number of moles = 34.6 g/ 98.1 g/mol

Number of moles = 0.35 mol

Answer:

transition metals

Explanation:such as iron or tin

Answer:

food doesn't spoil as fast when it is refrigerated because  it would be at  room temperature. Because of the lowered temperature, there are less collisions, which slows down the reaction! Due to decomposition reactions with oxygen or carbon dioxide in the air, meat begins to feel slimy and smell spoiled.  and member mark me as brainliest

Answer:

A lower temperature slows down the reactions in the food because there are less collisions. The chemical breakdowns and microorganism activity can't work as fast as it used to because of the cold.

stem, roots, leaves and flower

I hope it helps

Answer:

A redox reaction is a chemical reaction in which one or more of the reacting species undergoes oxidation and one or more undergoes reduction. An oxidizing agent is an element or compound that oxidizes another substance, while a reducing agent is an element or compound that reduces another substance.

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Answer:

D

Explanation:

The corrosive sign includes a hand with chemicals dropping onto it.

The flammable sign includes a flame.

The. chemical sign for carcinogenic chemicals is the one above, therefore the answer is D

Answer:

11 protons

Explanation:

Answer:

11 protons

Explanation:

since it is neutral it has 11 electrons as well

Answer:

C

Explanation:

Bc Look at it like this if norm and grav are equal aka the reason why hes not going threw the cement or flying in the air then the app and the fric are equal too or he would slip and fall

9. (80-32)5/9

48×5/9

240/9

26.66°C

9. (90-32)5/9

58×5/9

32.22°C

10 (212-32)5/9

180×5/9

20×5

100°C

Answer:

Explanation:

Answer:

\(\huge\boxed{\sf n \approx 0.076\ moles}\)

Explanation:

Volume = V = 1.255 L

Pressure = P = 1.47 atm

Temperature = T = 21 + 273 = 294 L

R = 0.08206 L atm/mol K

No. of moles = n = ?

Put the given data in the above formula.

(1.47)(1.255) = n(0.08206)(294)

1.844 = n (24.13)

1.844 / 24.13 = n

0.076 moles ≈ n

\(\rule[225]{225}{2}\)

The presence of the ions in the HCl would make the solution to conduct electricity.

Because it separates into ions (H+ and Cl-) when hydrochloric acid is dissolved in water, HCl (hydrochloric acid) solution conducts electricity. The electric charge of the H+ and Cl- ions allows them to travel and convey current across the solution.

The dissociation constant (Ka) of HCl describes how much of the compound separates into ions depending on the concentration of the solution. A higher HCl concentration will produce more ions, which will increase conductivity.

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The best choice for screening a person's genetics for 1,000 or more genes would be: C. Sequencing.

Sequencing techniques, such as next-generation sequencing (NGS), are well-suited for screening a large number of genes efficiently and comprehensively. NGS allows for high-throughput sequencing of DNA, enabling the simultaneous analysis of multiple genes or even the entire genome. It provides detailed information about the sequence of nucleotides in the DNA, allowing for the identification of genetic variations, mutations, or other genomic features.

Microarray analysis (A) is a technique that can analyze gene expression patterns or detect specific genetic variations, but it is limited in the number of genes it can assess simultaneously compared to sequencing.

RELP analysis (B) is a technique used for detecting genetic variations based on restriction enzyme digestion patterns, but it is more suitable for specific target regions rather than screening a large number of genes.

Karyotyping (D) involves the visualization and analysis of chromosomes to detect large-scale chromosomal abnormalities but is not suitable for screening a large number of individual genes.

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The question is about the systematic evaluation of materials for post-combustion CO2 capture in a temperature swing adsorption process.

In a temperature swing adsorption process for post-combustion CO2 capture, materials are evaluated systematically to determine their effectiveness in capturing CO2. Here is a step-by-step explanation of the process:

1. Material selection: Various materials, such as zeolites, activated carbon, metal-organic frameworks (MOFs), and amine-based sorbents, are considered for CO2 capture. Each material has different properties and adsorption capacities.

2. Screening: The selected materials are screened based on specific criteria, such as CO2 adsorption capacity, selectivity, stability, and cost. This helps narrow down the choices to the most promising candidates.

3. Bench-scale testing: The selected materials undergo bench-scale testing to evaluate their performance under controlled conditions. This involves measuring the CO2 adsorption capacity, kinetics, and regeneration efficiency of each material.

4. Process modeling: Computer simulations are used to model the temperature swing adsorption process with different materials. This helps predict the overall performance of the system, including CO2 capture efficiency, energy requirements, and process optimization.

5. Pilot-scale testing: The most promising materials are then tested at a larger scale in a pilot plant. This helps validate their performance and assess any challenges or limitations that may arise during practical implementation.

6. Techno-economic analysis: The performance data obtained from the pilot-scale testing is used to conduct a techno-economic analysis. This involves evaluating the cost-effectiveness of the materials, including their initial investment, operating costs, and potential for scaling up.

7. Material optimization: Based on the results of the evaluations and analysis, further modifications or improvements can be made to the materials to enhance their performance, stability, or cost-effectiveness.

By following this systematic evaluation process, researchers and engineers can identify the most suitable materials for post-combustion CO2 capture in a temperature swing adsorption process.

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Answer:

I don't have how to do that in numerical figures

The amount of iron, in grams, that is needed to completely react with 878.0 g of  \(Cl_2\) would be 460.392 grams

Iron (III) chloride is produced by reacting iron with chlorine as follows:

\(Fe + Cl_2 --- > FeCl_3\)

The balanced equation of the reaction goes thus:

\(2Fe + 3Cl_2 --- > 2FeCl_3\)

The mole ratio of iron to chlorine is 2:3.

Recall that: mole = mass/molar mass

Molar mass of \(Cl_2\) = 35.5 x 2

                             = 71 g/mol

Mole of 878.0 g  \(Cl_2\) = 878/71

                                 = 12.3662 moles

From the mole ratio, the equivalent mole of Fe from 12.3662 moles  \(Cl_2\) will be:

 12.3662 x 2/3 = 8.2441 moles

Mass of 8.2441 mole Fe = mole x molar mass

Molar mass of Fe = 55.845 g/mol

Mass of 8.2441 moles Fe = 8.2441 x 55.845

                                         = 460.392 grams

The numbers in the final multiplication operation have 5 significant figures each. Thus, the significant figure of the final answer will also be 5.

in other words, the amount of iron needed to completely react with 878.0 g of  \(Cl_2\) is 460.392 grams.

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Answer:

I think its might be 1 because the ionic numbers for CA is +2 and for P its +3

Answer:

The noble gases are the chemical elements in group 18 of the periodic table. They are the most stable due to having the maximum number of valence electrons their outer shell can hold. Therefore they rarely react with other elements since they are already stable