help me out plz!!!!​

Answer:

Chemical formula of Oxygen is O2.

We know ,

1 mole of a substance contains 6.022×10^23, Avogadro’s Constat.

Here, Molar mass of O = 16u

And molar mass of O2 = 32u

And 32g of O2 = 1 mole of O2

It means that,

32g of O2 = 6.022×10^23 molecules

Answer:

The correct answer is given in the picture

This ANSWER IS ONLY CORRECT WHEN Oz STAND FOR OZONE

While visiting his uncle's farm, Derek learned that horses and donkeys are two different species. Based on this information, Derek can infer that horses and donkeys are members of different populations.


Since horses and donkeys are different species, they belong to different populations. A population refers to a group of individuals of the same species that live in the same area and can interbreed. While horses and donkeys can mate, their offspring, known as mules, are usually infertile.

This means that mules cannot produce offspring of their own, which indicates that horses and donkeys are not members of the same population. In contrast, if they were members of the same population, they would be able to produce fertile offspring. Therefore, Derek can infer that horses and donkeys are members of different populations.

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https://www.geneva304.org/Downloads/ch%209%20key6.pd

this is what i found add an "f" at the end and search

\( \sf \implies 12 + ( 16\times 2) \\ \)

\( \sf \implies 12 + 32 \\ \)

\( \sf \implies 44 \\ \)

That means one mole of \( \sf CO_{2} \)has a mass of 44 g.

1 mole of carbon dioxide is equal to \( \sf 6.02 \times 10^{23}\\ \) molecules of carbon dioxide.Then, 7 moles is equal to -

\( \sf \implies 7\times 6.02\times 10^{23} molecules \\ \)

\( \sf \implies 4.214 \times 10^{24} \\ \)

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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In Part 1 of the question, we are asked to draw the product that results from the provided mechanism arrows. This involves analyzing the reaction steps and understanding the changes that occur during the reaction.

In Part 2, we need to determine whether the elementary step is reversible, meaning if the reaction can proceed in both the forward and reverse directions.

In Part 1, drawing the product resulting from the provided mechanism arrows requires a careful analysis of the reaction steps. The mechanism arrows indicate the movement of electrons and the formation or breaking of bonds. By following the arrows and considering the reactivity of the reactants, we can determine the resulting product(s) of the reaction. It is important to pay attention to the regioselectivity and stereochemistry of the reaction, if applicable.

In Part 2, determining whether the elementary step is reversible involves considering the nature of the reaction and the thermodynamics of the process. Reversible elementary steps involve both forward and reverse reactions occurring under certain conditions. Factors such as energy barriers, equilibrium constants, and reaction conditions influence reversibility. By analyzing these factors, we can determine whether the elementary step is reversible or if the reaction predominantly proceeds in one direction.

Overall, these two parts require a detailed understanding of the reaction mechanism, electron movement, and the factors affecting reversibility to accurately draw the product and determine the reversibility of the elementary step.

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In Part 1, draw the product that results from the mechanism arrows provided. In Part 2, indicate whether the elementary step is reversible. LCH3 4th attempt

How much energy is required to raise the temperature of 3 kg of aluminum from 18°C to 23°C? Use the table below and this equation: Q=mcΔT

Answer

C) no energy is lost; the total amount of energy remains the same.

Explanation

The law of conservation of energy states that "The energy can neither be created nor destroyed - only converted from one form of energy to another." Therefore some energy will be used for metabolism while the other can be used for other properties and some can be stored.

The correct option is D. Lactic acid is fashioned and irritates myocardial nerve fibers. while myocardial oxygen name for exceeds oxygen deliver, mobile metabolism modifications from cardio to anaerobic, and lactic acid accumulates, irritating myocardial nerve fibers, which causes aches.

Lactic acid is a shape of herbal acid this is produced naturally in the body within the direction of numerous metabolic strategies. It has the chemical additive C3H6O3 and is classified as an alpha-hydroxy acid. Lactic acid is used in numerous commercial enterprises and meal programs, consisting of the manufacturing of biodegradable plastics, detergents, and prescription drugs.

In chemistry, lactic acid is classified as a carboxylic acid because it includes a carboxyl organization (-COOH). it could exist in two paperwork: L-lactic acid and D-lactic acid, which may reflect pictures of every other. The L-shape is the most commonly discovered in nature and is the sort that is produced thru the body all through exercise.

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Answer:

more gravity

Explanation:

anything with mass has gravity

Answer:

48546.7kg or 48546745g

Explanation:

so from this u can work out the amount of moles in phosphorous by doing mass / mr you have to convert the mass in kg to g so you times it by 1000. then divide it by 31 which is the mr of phosphorous. then u can use the molar ratio which is 2:1 . Then use the equation mass= moles*mr

so 97000*1000/31=312903moles

2:1

so 312903/2=156451 moles of ca3(PO4)2

so mass= moles*mr

156451*310.3=48494g

hope this helps u to understand(*°▽°*)

The rotational partition function (Qrot) for 35Cl₂ at 354 K is approximately 1.251 × 10⁴¹.

To calculate the rotational partition function (Qrot) for 35Cl₂ at 354 K, we can use the formula:

Qrot = (8π² * I * k * T) / (h * c)

Where:

Qrot is the rotational partition function.

I is the moment of inertia of the molecule.

k is the Boltzmann's constant (1.38 × 10⁻²³ J/K).

T is the temperature in Kelvin.

h is the Planck's constant (6.626 × 10⁻³⁴ J·s).

c is the speed of light (3.00 × 10¹⁰ cm/s).

First, we need to calculate the moment of inertia (I) for 35Cl₂. The moment of inertia for a diatomic molecule can be calculated using the reduced mass (μ) and the bond length (r).

For a diatomic molecule:

I = μ * r₂

The reduced mass (μ) for 35Cl₂ can be calculated as follows:

μ = (m1 * m2) / (m1 + m2)

Where:

m1 and m2 are the atomic masses of chlorine (35.45 g/mol).

Calculating μ:

μ = (35.45 g/mol * 35.45 g/mol) / (35.45 g/mol + 35.45 g/mol)

= 17.725 g/mol

Now, we can calculate the moment of inertia (I):

I = μ * r²

To calculate the bond length (r), we need to convert the given rotational constant (B) from cm⁻¹ to m⁻¹:

B = 0.244 cm⁻¹ = 2.44 m⁻¹

Rearranging the formula, we can solve for r:

r = √(I / μ)

r = \(\sqrt{h / (8\pi ^2 * B * c)) / m)}\)

r ≈ \(\sqrt{6.626 (10^(^-^3^4) J.s / (8\pi ^2 * 2.44 m^(-1) * 3.00 × 10^(^1^0^) cm/s)) / (17.725 g/mol))}\)

r ≈ \(\sqrt{1.38064 (10^(^-^4^6)^ J.s^2 / (2.44 * 9.5184 × 10^(^2^0^) J.s/m^2)) / (1.124 (10^(^-^2^4^) g)}\)

r ≈ \(\sqrt{6.04151 (10^(^-^2^7^) m^2 / 2.191 (10^(^-^4^) m^2/mol}\)

r ≈ \(\sqrt{(2.756 (10^(^-^2^3^) mol)}\)

r ≈ 1.6607 × 10⁻¹² m

Now we can calculate the rotational partition function (Qrot):

Qrot = (8π² * I * k * T) / (h * c)

Substituting the given values:

Qrot = (8π² * (17.725 g/mol * (1.6607 × 10⁻¹²m)²) * (1.38 × 10⁻²³) J/K) * 354 K) / (6.626 × 10⁻³⁴ J·s * 3.00 × 10¹⁰ cm/s)

Qrot ≈ 1.251 × 10⁴¹

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The shelf-life of the reconstituted ampicillin suspension remains unchanged at 16 days when stored at room temperature (25°C) compared to storing it in the refrigerator at 5°C.

To calculate the shelf-life of the reconstituted ampicillin suspension at room temperature, we'll assume that the degradation follows an Arrhenius relationship.

Shelf-life at 5°C (T₁) = 16 days

Temperature at 5°C (T₁) = 5°C

Temperature at room temperature (T₂) = 25°C

To find the shelf-life at room temperature, we can use the Arrhenius equation:

k₁ / k₂ = exp((Ea / R) * (1/T₂ - 1/T₁))

Since we don't have specific values for Ea and the reaction rate constants, we'll assume that they are the same for simplicity. Thus, we can write:

k₁ / k₂ = exp((Ea / R) * (1/25 - 1/5))

Simplifying the equation, we get:

exp((Ea / R) * (4/125)) = 1

To satisfy this equation, the exponential term must be zero, which implies:

(Ea / R) * (4/125) = 0

Solving for Ea, we find:

Ea = 0

Since Ea is zero, it means the reaction rate constants and degradation rates are the same at both temperatures. Therefore, the shelf-life at room temperature (25°C) is the same as the shelf-life at 5°C, which is 16 days.

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Answer:

wind and water erosion

Answer:

C is the answer

Answer:

An amplifying device that indicates the presence of ionizing particles  

GEIGER COUNTERS

A device that permits determination of alpha and beta radiation emitted from a substance  

BOTH

Film sensitive to radiation that is removed and developed to measure exposure  

NEITHER

A device used for monitoring individual cumulative exposure to ionizing radiation  

NEITHER

Explanation:

1. Geiger counters and scintillation counters can be described by statements 1 and 2.

2. Statement 3 refers to film-based radiation detectors, not Geiger counters or scintillation counters.

3. Statement 4 refers to dosimeters, not Geiger counters or scintillation counters.

1. An amplifying device that indicates the presence of ionizing particles: This statement describes both Geiger counters and scintillation counters. Both types of counters use amplifying devices to detect and indicate the presence of ionizing particles.

2. A device that permits determination of alpha and beta radiation emitted from a substance: This statement describes both Geiger counters and scintillation counters. Both types of counters are capable of detecting alpha and beta radiation.

3. Film sensitive to radiation that is removed and developed to measure exposure: This statement describes neither Geiger counters nor scintillation counters. Instead, it refers to film-based radiation detectors, such as photographic film or thermoluminescent dosimeters (TLDs), which are used to measure radiation exposure.

4. A device used for monitoring individual cumulative exposure to ionizing radiation: This statement describes neither Geiger counters nor scintillation counters.

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Answer:

Al and Hcl

Explanation:

Reactants are the elements, compounds etc before the arrow

Answer:

The mass of copper sulfate in 25 cm³ of the copper sulfate solution is 0.45 g

Explanation:

The given parameters are;

The volume of the copper sulfate solution = 100 cm³

The mass of the copper sulfate in the solution = 1.8 g

Therefore, the mass of copper sulfate in 25 cm³ of the solution is given as follows;

The mass of copper sulfate in 100 cm³ of the solution = 1.8 g

The mass of copper sulfate in 1 cm³ of the solution  = 1.8 g/100 = 0.018 g

Therefore;

The mass of copper sulfate in 25 × 1 = 25 cm³ of the solution, m  = 25×0.018 g = 0.45 g

∴ The mass of copper sulfate in 25 cm³ of the solution, m = 0.45 g

The concentrations of major species in a mixture of weak and strong acids and bases are determined by their dissociation behavior and interaction in a solution, influencing the overall pH and buffering capacity.

The relationship among the concentrations of major species in a mixture of weak and strong acids and bases can be understood through their dissociation and interaction in a solution.

Strong acids, such as HCl, fully dissociate in water, releasing a high concentration of H+ ions. Similarly, strong bases, like NaOH, dissociate completely, releasing a high concentration of OH- ions.

Weak acids, such as acetic acid (CH3COOH), only partially dissociate in water, releasing a smaller concentration of H+ ions. Likewise, weak bases, like ammonia (NH3), partially dissociate, releasing a smaller concentration of OH- ions.

When a mixture of weak and strong acids and bases is present, the strong species will react first due to their higher concentrations of H+ or OH- ions. This reaction will affect the pH of the solution, as well as the concentrations of the weak species, as they will be buffered by the strong species.

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Answer:

ANSWER :: (DENSITY OF OIL IS --0.8/CM²) .

(DENSITY OF MERCURY IS --- 13.69/CM²) .

To determine the presence of compounds in a sample, one can look for key peaks in the IR spectrum. For example, a strong peak at around 3300 cm^-1 can indicate the presence of an alcohol functional group, while a peak at around 1700 cm^-1 can indicate the presence of a carbonyl group. By analyzing the IR spectrum and identifying these key peaks, we can make an educated guess as to what compounds are present in the sample.

If we were able to identify the key peaks for the desired product in our reaction, this would suggest that our reaction was successful in producing the intended compound. On the other hand, if we were unable to identify the key peaks for the desired product or if we saw unexpected peaks in the spectrum, this could indicate that the reaction did not work as intended.

In terms of the purity of the product, we can also look at the IR spectrum to identify any impurities or contaminants. For example, if we see multiple peaks in the spectrum or peaks that do not match the expected functional groups for our desired product, this could indicate the presence of impurities. On the other hand, if we see a clean spectrum with only the expected key peaks for our desired product, this would suggest that our product is pure.

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Silicate material have relatively low densities because of the covalent character in the bonds.

The silicate material have relatively low densities because of the presence of the covalent character between the interatomic bonding of Si and O.

This covalent character decreases the packing efficiency of the lattice of the silicates.

Also, because of the presence of the Frenkle effect in the lattice of silicate materials. It is easily founded in the silicates which result in the relatively low densities.

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Answer:

Stratosphere

Explanation:

Small storms would be residing in the troposphere but stronger thunderstorms and hurricanes reside in the stratosphere.

Answer:

qns-4

1-multicellular organism

2-unicellular organism

3-unicellular organism

4-multicellular organism

5-unicellular organism

6-multicellular organism

7-unicellular organism

a. Mn2+ will not hydrolyze water because it is a neutral ion with no ability to donate or accept protons.

b. K+ will not hydrolyze water because it is a neutral ion and does not have any acidic or basic properties.

c. C6H5NH3+ will hydrolyze water because it is a weak acid that can donate a proton to water, resulting in the formation of H3O+ ions and the conjugate base C6H5NH2.

d. Ba2+ will not hydrolyze water because it is a neutral ion with no ability to donate or accept protons.

For the second part,

a. NO2- will hydrolyze water because it is the conjugate base of a weak acid (HNO2). In the presence of water, NO2- will accept a proton to form HNO2 and hydroxide ions (OH-).

b. HS- will hydrolyze water because it is the conjugate base of a weak acid (H2S). In the presence of water, HS- will accept a proton to form H2S and hydroxide ions (OH-).

c. CN- will not hydrolyze water because it is a neutral ion with no ability to donate or accept protons.

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Discussion:

Conclusion: You can use this basic outline, to structure your conclusion, and expand it from there.

By investigating/measuring/using a....... it was determined that........ This is consistent/not consistent with the expected result/theory of...... due to/because of...........

Answer: Soil

Explanation:

Wind, rain, water, and glaciers are all agents of weathering because they can erode materials. Even though Glaciers need certain conditions they can still do damage to the surface of the earth. While soil is what gets eroded or sometimes is the product of erosion occurring.

Answer:

0.3 J

Explanation:

The equation for heat capacity is Q = mcΔT where Q is the heat, m is the mass of the substance, c is the specific heat capacity of the substance and delta T is the change in temperature. Plugging those values into the equation, we have Q = (.500)(0.24)(27.5-25) = 0.3

Equilibrium is a state in a chemical reaction where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of reactants and products. It is represented by a double arrow (⇌) in chemical equations. In the given equation: H₂O (g) + CO (g) ⇌ H₂(g) + CO₂(g) + 42 KJ

To shift the equilibrium to the right, one or more of the following could occur:

Increasing the concentration of H₂ or CO₂

Decreasing the concentration of H₂O or CO

Increasing the pressure

Removing some of the products (H₂ and CO₂)

Decreasing the temperature

To shift the equilibrium to the left, one or more of the following could occur:

Decreasing the concentration of H₂ or CO₂

Decreasing the pressure

Increasing the temperature

If pressure is increased, the equilibrium will shift in the direction that produces fewer moles of gas. In this case, since there are fewer moles of gas on the right side of the equation (H₂ and CO₂), the equilibrium will shift to the right. If heat is added, the equilibrium will shift in the endothermic direction to absorb the additional heat. In this case, the forward reaction is endothermic (42 KJ on the right side), so the equilibrium will shift to the right to consume the added heat.

If CO is added, the equilibrium will shift to the right to consume the additional CO.The concentration of H₂O and CO₂ will increase, while the concentrations of H₂ and CO will decrease until a new equilibrium is reached.

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