HELP ASAP!!!
A force of 50N acts in an easterly direction on an object at the same time as a force of 80N pushes on it in the direction of N 45 degrees E. Determine the magnitude and direction of resultant force

True. In circular motion, the centripetal acceleration changes only the direction of velocity, but not its magnitude.

Centripetal acceleration is the acceleration directed toward the center of the circular path and is responsible for keeping an object moving in a curved path. It is always perpendicular to the velocity vector of the object at any given point on the path.

The magnitude of the centripetal acceleration, denoted as "a_c," can be calculated using the following formula:

a_c = (v^2) / r

Where:

- v is the magnitude of the velocity of the object

- r is the radius of the circular path

As the object moves along the circular path, its velocity vector constantly changes direction. However, the magnitude of the velocity, represented by "v," remains constant unless acted upon by an external force.

Therefore, the centripetal acceleration only affects the direction of the velocity vector, causing it to continuously change, while the magnitude of the velocity remains constant.

True. In circular motion, the centripetal acceleration changes only the direction of velocity, but not its magnitude.

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(a) For a(t) = t + 4 and v(0) = 5, the velocity at time t can be found by integrating the acceleration function, and then substituting t = 0 with the given initial velocity.

(b) The distance traveled during the time interval can be obtained by integrating the velocity function over the given range, from t = 0 to t = 10.

Scenario 1:

Given:

a(t) = t + 4

v(0) = 5

(a) Finding the velocity at time t:

Integrate the acceleration function a(t):

∫(t + 4) dt = (1/2)t² + 4t + C

Substitute t = 0 and v(0) = 5:

(1/2)(0)² + 4(0) + C = 5

C = 5

Therefore, the velocity at time t is:

v(t) = (1/2)t² + 4t + 5

(b) Finding the distance traveled during the time interval 0 ≤ t ≤ 10:

Integrate the velocity function v(t):

∫[(1/2)t² + 4t + 5] dt = (1/6)t³ + 2t² + 5t + D

Evaluate the integral at the upper and lower limits:

Distance = [(1/6)(10)³ + 2(10)² + 5(10)] - [(1/6)(0)³ + 2(0)² + 5(0)] = 383.33 units (approximately)

Scenario 2:

Given:

a(t) = 2t + 3

v(0) = -4

(a) Finding the velocity at time t:

Integrate the acceleration function a(t):

∫(2t + 3) dt = t² + 3t + C

Substitute t = 0 and v(0) = -4:

(0)^2 + 3(0) + C = -4

C = -4

Therefore, the velocity at time t is:

v(t) = t² + 3t - 4

(b) Finding the distance traveled during the time interval 0 ≤ t ≤ 3:

Integrate the velocity function v(t):

∫[(t^2 + 3t - 4)] dt = (1/3)t^3 + (3/2)t^2 - 4t + D

Evaluate the integral at the upper and lower limits:

Distance = [(1/3)(3)³ + (3/2)(3)² - 4(3)] - [(1/3)(0)³ + (3/2)(0)² - 4(0)] = 17.5 units

So, the distance traveled during the time interval 0 ≤ t ≤ 3 is 17.5 units.

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The complete question is:

The acceleration function (in m/s 2) and the initial velocity are given for a particle moving along a line. Find (a) the velocity at time t and (b) the distance traveled during the given time interval.

1. a(t)=t+4,v(0)=5,0⩽t⩽10 72. a(t)=2t+3,v(0)=−4,0⩽t⩽3

Answer:

Explanation:

How much force does a 1000kg car need to accelerate at 3m s2 to the south?

Answer- the force needed to accelerate the 1000kg car by 3m/s2 is 3000N.

Between the Milky Way galaxy's nucleus and its outer border, our solar system is located about halfway.

The Milky Way galaxy has a width of about 100,000 light-years and is a barred spiral galaxy. It has a disc with spiral arms and a central bulge that is home to stars, gas, and dust.

One of the curving arms of the Milky Way galaxy, the Orion Arm contains our solar system. Our solar system is thought to be located approximately halfway between the Milky Way galaxy's center and its outer edge, at a distance of about 25,000 light-years.

Because our solar system is a component of the Milky Way galaxy, Option B is wrong. Option C is wrong because the Milky Way galaxy's center is not where our solar system is located.

Because there is no proof that our solar system is located further from the center of the Milky Way galaxy than any other solar system, Option D is false.

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the question is incomplete. complete question is

Which of the following statements about the location of our solar system is correct?

A. Our solar system is about halfway between the center of the Milky Way galaxy and its outer edge.

B. Our solar system is not in the Milky Way galaxy.

C. Our solar system is at the center of the Milky Way galaxy.

D. Our solar system is farther out in the Milky Way galaxy than any other solar system.

Answer

t = 3.23s

Explanation:

C. A heat pump absorbs 100 J of heat from a cool reservoir and releases 120 J of heat to a hot reservoir.

In order to operate, a heat engine must reject some of the heat it receives from the high-temperature source to a low-temperature sink.

A heat engine that violates the second law converts 100 percent of this heat to work. This is physically impossible. This heat engine violates the second law of thermodynamics.

The second law can also be stated as no heat engine can have a thermal efficiency of 100 percent.

The thermal efficiency of a heat engine is defined as the ratio of the work output to the heat input:

Clearly, if the thermal efficiency of a heat engine is 100 percent,

Qin=Wout

If the second law precludes a heat engine from having a thermal efficiency of 100 percent. A heat engine is a device that converts a portion of the heat supplied to it from a high-temperature source into work. The remaining heat is rejected to a low-temperature sink.

Therefore:

A heat pump absorbs 100 J of heat from a cool reservoir and releases 120 J of heat to a hot reservoir.

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The capacitance of an air-filled capacitors does not change is if electric field in between plates is made weaker by discharging the plates:

The external unit's malfunctioning due to a defective capacitor impedes the cooling procedure as a whole. Second, the system must work harder to complete its task due to poor voltage distribution to outer unit components. A defective capacitor frequently causes harm to additional components.

In a simple parallel-plate capacitor, applying a voltage between 2 conducting plates creates an equal electric field between both the plates. The electrical field intensity in a capacitor is inversely related to the distance between the plates but directly proportional to the applied voltage.

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Answer:

CLEAN

Explanation:

Answer:

I just wash mine with water when I drop it . That is a good question tho :)

Explanation:

The force of 30.5 N applied tangentially at the rim of the bicycle wheel with a mass of 44.6 kg and a radius of 0.260 m will result in an acceleration of approximately 0.687 m/s².

The torque, or turning force, applied to the bicycle wheel is equal to the force applied at the rim multiplied by the radius of the wheel, according to the equation τ = Fr, where τ is the torque, F is the force, and r is the radius. In this case, F = 30.5 N and r = 0.260 m.

The moment of inertia, which measures the resistance of the wheel to rotational motion, is given by the equation I = ½mr², where m is the mass of the wheel and r is the radius. In this case, m = 44.6 kg and r = 0.260 m.

Using the torque and moment of inertia, we can apply Newton's second law for rotational motion, which states that τ = Iα, where α is the angular acceleration. Substituting the values we have, we get Fr = ½mr²α.

Rearranging the equation to solve for α, we get α = (2Fr) / (mr²). Plugging in the given values for F, m, and r, we can calculate α as follows:

α = (2 * 30.5 N * 0.260 m) / (44.6 kg * (0.260 m)²)

α ≈ 0.687 m/s²

Therefore, the acceleration of the bicycle wheel's rotation due to the applied force is approximately 0.687 m/s².

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The engineer should report to the crew that the magnitude of acceleration was 0.80 m/s².

To determine the magnitude of acceleration, we can use the formula:

acceleration = change in velocity / time taken

In this case, the train starts from rest and reaches a maximum speed of 144 m/s in 180 seconds. The change in velocity is the final velocity minus the initial velocity, which is 144 m/s - 0 m/s = 144 m/s. The time taken is given as 180 seconds.

Plugging these values into the formula, we get:

acceleration = 144 m/s / 180 s = 0.80 m/s²

Therefore, the engineer should report to the crew that the magnitude of acceleration was 0.80 m/s². This means that the train's speed increased by 0.80 meters per second every second during the acceleration phase.

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Answer:

oooh thanks

Explanation:

..................

Answer:

awwww thx you are to :)

Explanation:

Answer:

Explanation:

density = mass/volume

So if mass and volume increase, density also increases

Answer:

if no mistaken then it is 300kN

Explanation:

Using SI units (the default if a system is not specified) 200T = 200000kg as the mass of the whale, it would weigh 1960kN in 1g Earth gravity.

On the Moon, the acceleration is 0.166g, to it would weigh about 330kN.

Answer:

Explanation:

Since the mass of a whale is 200 tons on earth, and the moon has a lighter gravity compared to the earth is about 1/6 as powerful,  the whale would weigh 33.33 tons with the last 3 repeating forever. so about 33 and one third ton on the moon.

This is talking about weight, which is how much it would take to lift this object, but the mass is the the same as mass isn't affected by gravity, only weight is affected by gravity.

Hope this helps!

Answer:

The gap between the plates will be 1.2 x 10^-15 m

No, this is not practically achievable.

Explanation:

Capacitance = 1.0 F

area of plate = 1.4 cm^2 = 1.4/10000 m^2 =  m^2

distance = ?

We use the equation

\(C\) =  \(\frac{A}{d}\)*ε

C is the capacitance

where A is the area

d is the distance of separation of plates

ε is the permeability of free space = 8.854×10^-12 F⋅m−1

substituting values, we have

1 = \(\frac{0.00014}{d}\)* 8.854×10^-12

distance between plates = 1.2 x 10^-15 m

This is not practically achievable in real life

Sound waves travel through the air and can be blocked by walls. When a sound wave passes through a wall, the wall absorbs some of the sound energy, resulting in the higher-pitched sound waves being blocked more than lower-pitched sound waves.

This is because higher-pitched sound waves have shorter wavelengths, making them more susceptible to being blocked than lower-pitched sound waves, which have longer wavelengths.

This phenomenon is known as wave-particle duality, which states that sound waves have both particle-like and wave-like properties. The particle-like property of higher-pitched sound waves makes them more susceptible to being blocked by walls than lower-pitched sound waves. This is why you can hear lower-pitched sounds more clearly when they pass through a wall.

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Answer:

75ohms

Explanation:

V= IR

V = 1.5volts

I = 0.02A

1.5 = 0.02×R

Making R the subject

R = 1.5/0.02

R = 75ohms

The resistance in the circuit will be 75ohms

The horizontal distance travelled by the football is 3.1 m.

The angle of projection of the football is calculated as follows;

tan ( θ ) = Vy / Vx

where;

tan ( θ ) = 5 / 3

tan ( θ ) = 1.667

θ = arc tan (1.667)

θ = 59⁰

The resultant velocity of the ball is calculated as follows;

v = √ (Vx² + Vy²)

v = √ (3² + 5²)

v = 5.83 m/s

The horizontal distance travelled by the football is calculated as follows;

x = v² sin(2θ) /g

where;

x = [ (5.83)² sin(2 x 59) /9.8 ]

x = 3.1 m

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The amount of sample of liquid in grams when its temperature is raised is calculated to be 20 g.

The term specific heat capacity refers to the amount of heat needed to raise a substance's temperature by one degree Celsius.

Q = m c Δt  

Q = 5.23 kcal of heat are absorbed by fluids = 5230 cal

C = heat capacity of liquid = 2.09 cal/g °C

Initial temperature of the liquid T i = 101 K

Final temperature of the liquid T f = 225 K

Change in temperature, Δt = T f - T i = 225 - 101 K = 124 K

Putting in the values, we get:

5230 = m × 2.09 cal/g °C × 124 K  

m = 20 g

The given question is incomplete. The complete question is 'The specific heat of a liquid x is 2.09 cal/g°c. A sample amount of grams of this liquid at 101 k is heated to 225 k. the liquid absorbs 5.23 k cals. what is the sample of liquid in grams? (round off decimal in the answer to nearest tenths)'

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The vehicle will accelerate by 20 g, or in terms of g. A change in an object's velocity with respect to time might serve as a demonstration of acceleration.

An object's acceleration can be thought of as a vector quantity that exhibits both magnitude and direction. The first derivative of the velocity of an object in time can be used to express acceleration.

Calculating the average acceleration is as simple as dividing the velocity difference by the time change.

Acceleration is calculated as (final velocity minus initial velocity)/time.

The car's starting speed is indicated as u = 30 m/s.

The final speed was 0 m/s.

The duration of the automobile, t = 0.15 s

The typical acceleration is equal to (0–30)/0.15 = –200 m/s2.

Car acceleration is equal to 200/9.8 = 20 g.

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The region marked X in the diagram shows that the objects have the same charge.

The term conduction has to do with the manner of charging in which charge is passed from one object to another. Induction involves charging objects without the objects touching each other.

The region marked X in the diagram shows that the objects have the same charge.

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Answer:

D

Explanation:

The impulse is the integral of the force over time. In this case, the force is the force exerted on the astronaut by the wrench, and the time is the time during which the force is exerted. We can assume that the force is constant and that the time during which the force is exerted is the time it takes for the wrench to travel a certain distance away from the astronaut.

We can then use the equation for distance, which relates the distance an object travels to its initial velocity, its final velocity, and the time during which it travels that distance. Since the wrench travels away from the astronaut, its final velocity is positive, and the astronaut's final velocity is negative. Let d be the distance that the wrench travels away from the astronaut. Let t be the time it takes for the wrench to travel that distance. Let u be the initial velocity of the astronaut, which is the velocity with which he is drifting away from the ISS. The equation for distance is:

\(d = u t + (1/2) a t^2\)

The wrench is thrown with a speed of 25 m/s relative to the ISS, which is moving at a speed of about 7.7 km/s relative to the Earth's surface.

The astronaut is drifting very slowly out into space, we can assume that his initial velocity is much less than the speed of the wrench.

Therefore, the term (85 kg) (u) (t) is much less than the term

\((1/2) (25 m/s - 7700 m/s) (t)^2\)

, and we can neglect it. We can also assume that the time t is much less than the time it would take for the astronaut to drift a significant distance away from the ISS, so we can assume that D is much less than the radius of the Earth.

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The acceleration of wheel will last for 1.25 sec.

Angular acceleration refers to as change of angular velocity per unit of time. It is usually expressed in radians/sec². The direction of the acceleration vector is perpendicular to the plane in which the rotation occurs. As the angular velocity(ω) increases clockwise, the angular acceleration rate moves away from the observer. If the angular velocity increase is counterclockwise, the angular acceleration vector points in the direction of the viewer. In SI units, angular acceleration is measured in radians per second (rad/s²) and is commonly expressed as alpha (α).

For the given case,

Using equation of motion:

ω₂² = ω₁² + 2αθ

6² = 2² + 2 × α × 5

36  = 4 + 10α

10α = 32

α = 3.2 m/s²

Acceleration:

α = (ω₂ - ω₁)/t

t = (ω₂ - ω₁)/α

t = (6 - 2)/3.2

t = 1.25 sec

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The principal axes are the coordinate axes (x, y, z), and the principal moments of inertia are 23mb^2, 20mb^2, and 20mb^2 for the x, y, and z axes, respectively.

To find the inertia tensor, principal axes, and principal moments of inertia for the three-particle system, we need to calculate the inertia tensor and diagonalize it.

The inertia tensor is given by the formula:

I_ij = Σ(m_k * (δ_ij * r_k^2 - r_ki * r_kj))

where I_ij is the (i,j)-th element of the inertia tensor, m_k is the mass of the k-th particle, δ_ij is the Kronecker delta, r_k^2 is the square of the distance from the k-th particle to the origin, and r_ki and r_kj are the components of the position vector of the k-th particle.

Let's calculate the inertia tensor for the given system:

I_xx = 3m * (0^2 + b^2 + b^2) + 4m * (0^2 + b^2 + (-b)^2) + 2m * (b^2 + (-b)^2 + 0^2)

= 9mb^2 + 12mb^2 + 2mb^2

= 23mb^2

I_xy = I_xz = I_yx = I_yz = I_zx = I_zy = 0

I_yy = 3m * (b^2 + 0^2 + b^2) + 4m * (b^2 + 0^2 + (-b)^2) + 2m * ((-b)^2 + b^2 + 0^2)

= 6mb^2 + 12mb^2 + 2mb^2

= 20mb^2

I_zz = 3m * (b^2 + b^2 + 0^2) + 4m * (b^2 + (-b)^2 + 0^2) + 2m * (0^2 + b^2 + 0^2)

= 6mb^2 + 12mb^2 + 2mb^2

= 20mb^2

Now, let's write down the inertia tensor:

I = | I_xx 0 0 |

| 0 I_yy 0 |

| 0 0 I_zz |

Diagonalizing the inertia tensor, we can obtain the principal axes and principal moments of inertia.

The diagonalized form of the inertia tensor is obtained by finding the eigenvalues and eigenvectors of the inertia tensor. Since the inertia tensor is already diagonal, the principal axes are the coordinate axes (x, y, and z), and the principal moments of inertia are the diagonal elements of the inertia tensor:

I_xx = 23mb^2

I_yy = 20mb^2

I_zz = 20mb^2

Therefore, the principal axes are the coordinate axes (x, y, z), and the principal moments of inertia are 23mb^2, 20mb^2, and 20mb^2 for the x, y, and z axes, respectively.

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The magnitude of the dipole's angular velocity (ωmax) when it is pointing along the y-axis can be determined using the given information.

To find the magnitude of the dipole's angular velocity (ωmax) when it is pointing along the y-axis, we need to consider the properties of a dipole and its rotational motion.

A dipole consists of two opposite charges separated by a distance, forming a vector pointing from the negative charge to the positive charge. The dipole moment (p) is defined as the product of the charge magnitude (q) and the separation distance (d) between the charges: p = q * d.

The angular velocity (ω) of a dipole rotating about its axis is related to its dipole moment and moment of inertia (I) by the equation ω = p / I.

When the dipole is pointing along the y-axis, it implies that the dipole moment vector is in the y-direction. Therefore, the magnitude of the dipole moment can be expressed as p = p_y, where p_y represents the component of the dipole moment along the y-axis.

The moment of inertia for a dipole rotating about its axis can be determined based on its shape and mass distribution. Without specific details or values provided in the problem introduction, it is not possible to determine the exact moment of inertia or provide a specific expression for ωmax in terms of the given quantities.

Therefore, to calculate the magnitude of the dipole's angular velocity (ωmax) when it is pointing along the y-axis, we would need additional information, such as the specific shape and mass distribution of the dipole, in order to determine the moment of inertia.

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Answer:

1) - 35

2) - 35

3) - 67

4) - 83

According to the formula, the magnetic field (B) will increase by a factor of 10, as the other factors (μ₀ and I) remain constant.

So the correct answer is:
A. It will increase by a factor of 10.

The magnetic field inside a coil of wire is given by the formula B = μ₀ * n * I,

where B is the magnetic field, μ₀ is the permeability of free space,

n is the number of turns per unit length, and I is the current through the wire.
If the radius of the coil is decreased by a factor of 10, the length of the wire remains the same, but the number of turns per unit length (n) will increase by a factor of 10.

This is because the wire is now wound more tightly around the core, resulting in more turns in the same length.
Therefore, according to the formula, the magnetic field (B) will increase by a factor of 10, as the other factors (μ₀ and I) remain constant. So the correct answer is:
A. It will increase by a factor of 10.

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Answer:

Originally Sonu and image is 8 m (4 m to mirror and 4 m to image)

If he moves 1 m towards the mirror the image distance will be reduced to  (c) 6 m