HELP!!! A nuclear engineer is designing a nuclear reactor for a new power plant. The reactor core will have an operating temperature of 773 K. The engineer must choose an appropriate coolant to transfer heat from the reactor core through one or more cooling loops to the steam generator and turbines/generator that produce electricity. Running the coolant under pressure is more expensive than running it at normal atmospheric pressure (1 atm). The choices for the reactor coolant are listed in the table below, with their properties. Choose which substance would be best to recommend to the engineer. Explain your choice in terms of its properties. Explain how the chemical bonds in the substance account for its properties.

The name of the most abundant isotope of antmanium is not provided in the question. Therefore, the most abundant isotope would have an atomic mass close to the given number, which is 444.

The number written below the symbol of antmanium (444.41) is likely its atomic mass, which is the sum of the masses of all its isotopes. However, the information about the isotopes provided in the question does not include the names or masses of the individual isotopes, only that there are four isotopes and one is 90% abundant. Without knowing the individual masses or names of the isotopes, we cannot determine which is the most abundant.

To name isotopes, we combine the element's name with its atomic mass number (the sum of protons and neutrons in the nucleus). In this case, the element is antmanium, and the atomic mass number is 444, so the isotope's name is Antmanium-444.

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Answer:

it's B.

Explanation:

Similar to Radio wave a microwave is also an electromagnetic wave of lower wavelength and high frequency.

Answer:

B

Explanation:

Explanation:

\(v = vdm \times n\)

Vdm=22.4dm.

mole(n)=4 mol

therefore the total volume

\(v = 22.4 \times 4 \\ v = 89.6dm\)

The molar mass of wax with chemical formula is  C₂₅H₅₂ is 352.77 grams per mole.

Chemical  formula is defined as a way of representation of  the number of atoms  which are present in a compound or  a molecule.It is written with the help of symbols  of elements. It also makes use of brackets and subscripts.

Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form  is called  as an empirical formula.

It is not the same as structural formula and does not have any information regarding structure of the compound..It does not provide any information regarding structure of molecule as obtained in structural formula.

There are four types of chemical formula:

1)empirical formula

2) structural formula

3)condensed formula

4)molecular formula

Molar mass of wax is calculated as , 12.01×25+1.01×52=352.77 grams per mole.

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Equilibrium constants for the same reaction Kc and Kp will always be equal to one another when the number of moles of gases in the balanced equation is the same on both sides. It's important to remember that the two equilibrium constants Kc and Kp, are used to describe the degree of a reaction and how far it has gone.

Equilibrium constants for the same reaction Kc and Kp will always be equal to one another when the number of moles of gases in the balanced equation is the same on both sides. It's important to remember that the two equilibrium constants Kc and Kp, are used to describe the degree of a reaction and how far it has gone. The equilibrium constant Kc is calculated using concentration whereas Kp is calculated using partial pressure.

So, it is used when we have gaseous reactants and products. It can also be written in terms of the moles of the reactants and products. If the reactants and products are in the same phase then the value of Kp is equal to Kc. If the number of moles of gases on both sides is the same, then the equilibrium constants Kc and Kp will always be equal to one another. This is because the difference in pressure will not change the overall reaction quotient. Hence, the answer is that the equilibrium constants for the same reaction Kc and Kp will always equal one another when the number of moles of gases in the balanced equation is the same on both sides.

Another reaction quotient can be calculated using Qc or Qp to predict the direction of the reaction. If Q is greater than K, the reaction will shift to the left. If Q is less than K, the reaction will shift to the right. If Q is equal to K, the reaction is at equilibrium.

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The balanced equation which have the coefficient 3 in front of any of the reactants is 3H₂SO₄ + 2B(OH)₃ → B₂(SO₄)₃ + 3H₂O.

Those chemical equations in which number of each atoms pesent in reactant side as well as on product side is always equal to each other.

Let us consider the balanced equations for the given chemical reactions are:

Balanced form of the above reaction will be written as Zn+2HCl → ZnCl₂+H₂ where all atoms are present in equal quantity.

Balanced form of the given reaction will be written as 3H₂SO₄ + 2B(OH)₃ → B₂(SO₄)₃ + 3H₂O, where coefficient 3 is present in before sulphuric acid and water molecule.

Balanced form of above reation will be written as Fe+ 2AgNO₃ → Fe(NO₃)₂ + 2Ag.

Balnced form of above chemical equation will be represented as C₂H₄O₂ + 2O₂ → 2CO₂ + 2H₂O, and coefficient 3 is not used any where.

The quation which have the coefficient 3 is 3H₂SO₄ + 2B(OH)₃ → B₂(SO₄)₃ + 3H₂O.

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Answer: It's 3. H2SO4 + B(OH)3  B2(SO4)3 + H2O

Chromium(III) chlorate (Cr(ClO3)3) is a solid (s) that dissolves in water to form aqueous chromium(III) ions (Cr^3+, aq) and 3 aqueous chlorate ions (ClO3^-, aq). The coefficients represent the lowest possible whole numbers to balance the equation.

When Cr(ClO3)3 is dissolved in water, it dissociates into its respective ions. The balanced chemical equation for the dissolution of Cr(ClO3)3 can be written as:

Cr(ClO3)3(s) → Cr3+(aq) + 3ClO3-(aq)

This equation shows that one molecule of solid Cr(ClO3)3 dissociates into one Cr3+ ion and three ClO3- ions in aqueous solution. The state-of-matter for Cr(ClO3)3 is solid (s), while the state-of-matter for Cr3+ ion and ClO3- ions is aqueous (aq). The coefficients in the equation are already in their lowest possible whole number form.

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Answer:

Nuclear Charge

Explanation:

As we move from sodium to chlorine across, there's increase in atomic number (protons). This also means there is increase in the valence electrons (The valence electrons is denoted by the group).

As the number of protons increases, the nuclear energy also increases. Due to this, the electrons are attracted more strongly and pulled closely to the nucleus.

The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

The water and the solutes leave the capillaries at the arterial end because the blood pressure is the greater than the osmotic pressure at the arterial end.

The blood pressure is the greater than the osmotic pressure at the arterial end and the water molecules  and the solutes leave the capillaries at the arterial end. At the arterial end of capillary, the blood pressure is exceeds the limit of the the osmotic pressure, that will causes the  net movement of the fluid out of the capillary.

Thus, due to the higher blood pressure than the osmotic pressure the solutes and the water leaves the artial end.

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Answer:

Chemistry, physics, astronomy and earth science.

Explanation:

Heat energy needed : 3.5 x 10⁷ kJ

Heat is a form of energy that can flow from high-temperature objects to low-temperature objects.

So heat moves when there is a difference in temperature and can increase or decrease the temperature. An object that receives a lot of heat will cause a large increase in temperature

The amount of heat is influenced by the mass of the object and the difference in temperature

Can be formulated

Q = m.c.Δt

Q: heat received or removed by an object (J)

m: object mass (kg)

c: heat type substance (J / kg⁰C)

ΔT: temperature change (⁰C)

210 kJ of heat energy is used to form 3.0 moles of Hydrogen, so heat energy for 1 mol Hydrogen :

\(\tt \dfrac{210}{3}=70~kJ/mol\)

mol of 1000 kg of Hydrogen=10⁶ g(MW=2 g/mol)

\(\tt \dfrac{10^6~g}{2}=5.10^5\)

The heat energy :

\(\tt 70~kJ/mol\times 5.10^5~mol=3.5\times 10^7~kJ\)

Answer:

Maybe like 6!

Explanation:

a. The balanced equation for the synthesis of ammonia gas is: N\(_{2}\) + 3H\(_{2}\) → 2NH\(_{3}\).

b. The volume of ammonia gas produced is approximately 1934.74 liters.

To determine the volume of ammonia gas produced, we need to use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Given:

Mass of nitrogen = 10 kg

Temperature = 550°C = 823 K

Pressure = 250 atm

First, we need to calculate the number of moles of nitrogen. The molar mass of nitrogen (N\(_{2}\)) is approximately 28 g/mol. Using the given mass of nitrogen (10 kg), we can convert it to grams (10,000 g) and then divide by the molar mass to get the number of moles (357.14 mol).

From the balanced equation for the synthesis of ammonia (N\(_{2}\) + 3H\(_{2}\) → 2NH\(_{3}\)), we know that 1 mole of nitrogen reacts to produce 2 moles of ammonia.

Therefore, the number of moles of ammonia produced is twice the number of moles of nitrogen, which is 2 * 357.14 = 714.29 mol.

Now, we can use the ideal gas law to calculate the volume of ammonia gas. Rearranging the equation, V = (nRT) / P, we can plug in the values:

V = (714.29 mol * 0.0821 L·atm/(mol·K) * 823 K) / 250 atm = 1934.74 L.

So, the volume of ammonia gas produced is approximately 1934.74 liters.

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4.68L is the final volume.

The volume of a gas is inversely proportional to its temperature when pressure is held constant. This means that when the temperature of the gas is decreased, its volume will increase.

Therefore, the final volume of the 17.0 L of carbon dioxide will be greater than 17.0 L after it is cooled from 38°C to 5°C.

The equation to calculate the final volume is:

\(V2 = V1 * (\frac{T2}{T1})\)

where T1 is the starting temperature, T2 is the ending temperature, V1 is the starting volume, and V2 is the finished volume.

Using this equation, the final volume of the carbon dioxide can be calculated as:

\(V2 = 17.0 L * (\frac{5\°C}{38\°C}) \\V2= 4.68 L\)

Therefore ,The Final volume is 4.68L

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To solve this problem we have to apply Boyle's Law, that states that the product of the pressure and the volume of a system of ideal gases is a constant, this can be expressed as:

When there is a change in the system, this Law can be expressed as:

In this case, P1 has a value of 2095torr, V1 a value of 4.7L and V2 a value of 1.54L, use these values to find P2:

The digestive and respiratory systems work together to provide the body with the nutrients and oxygen it needs to function. The digestive system breaks down food into smaller molecules that can be absorbed by the body.

The respiratory system delivers oxygen to the blood, which carries it to the cells throughout the body. The cells use the oxygen to break down the food molecules into energy. The digestive system also produces carbon dioxide as a waste product. The respiratory system removes carbon dioxide from the blood and releases it into the air. In addition to their shared role in providing the body with nutrients and oxygen, the digestive and respiratory systems also work together to protect the body from harmful substances. The digestive system produces digestive enzymes that break down food, but these enzymes can also damage the cells of the digestive tract. The respiratory system produces mucus that traps harmful particles in the air before they can reach the lungs.

The digestive and respiratory systems are two very important systems that work together to keep the body healthy. An example of how the digestive and respiratory systems work together is when the epiglottis, a flap of tissue that covers the trachea when you swallow, prevents food from entering your lungs.

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Answer:

f

Explanation:

Answer:

Lewis dot diagrams use dots arranged around the atomic symbol to represent the electrons in the outermost energy level of an atom

Explanation:

The number of moles the sample of sodium hydroxide (NaOH) will contain is 4 moles.

Moles of any substance will be calculated by using the below formula:
n = W/M, where

W = given mass

M = molar mass

Given mass of NaOH = 160 g

Given molar mass of NaOH = 40 g/mole

On putting these values on the above equation, we get

n = 160 / 40 = 4 moles

Hence, required moles is 4 moles.

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Answer:

A). 4.000

Explanation:

Poopy fart fart

Answer:

Materials that do not let current flow easily are called insulators.

Most nonmetal materials such as plastic, wood and rubber are insulators

Answer

C. 259 K

Explanation

Given:

Temperature = -14°C

What to find:

The temperature in kelvins of -14°C.

Solution:

Conversion factor: 0°C + 273 = 273 K

Therefore, 14°C + 273 = 259 K

The temperature in kelvins of -14°C is 259 K

Volatile organic compounds (VOCs) contain carbon and evaporate very easily. VOCs are a group of organic chemicals that have low boiling points and can easily vaporize at room temperature. They are commonly found in various products and materials, including solvents, paints, cleaning agents, fuels, adhesives, and many others.

The carbon-containing nature of VOCs contributes to their volatility and ability to evaporate readily into the air. This volatility makes VOCs capable of easily transitioning from a liquid or solid state to a gaseous state, which allows them to be readily released into the surrounding environment.Due to their ability to evaporate easily, VOCs can contribute to indoor and outdoor air pollution. High concentrations of VOCs in indoor spaces can have adverse effects on human health, leading to respiratory issues, irritation, and other health problems. Therefore, controlling and minimizing exposure to VOCs is important for maintaining indoor air quality and reducing potential health risks.

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Volatile Organic Compounds (VOCs) are compounds that easily evaporate at room temperature, often containing hydrocarbon chains. Many VOCs, such as esters, contribute to the smells we associate with various plants and fruits.

Volatile Organic Compounds (VOCs) typically contain hydrocarbon chains and can evaporate very easily at room temperature. Many VOCs are members of the ester family, like those found in strawberries, and are responsible for the odors associated with various plants and their fruits. Esters, carboxylic acids, and other VOCs contain a carbonyl group with a second oxygen atom bonded to the carbon atom in the carbonyl group by a single bond. In a carboxylic acid, this second oxygen atom also bonds to a hydrogen atom, but in an ester, the second oxygen atom bonds to another carbon atom.

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If all of this gas is burned, 1627.13 grams of water vapor is produced.

The balanced chemical equation for the combustion of hydrogen gas in air to produce water vapor is:

2H2 + O2 → 2H2O

From this equation, we can see that 2 moles of hydrogen gas (H2) react with 1 mole of oxygen gas (O2) to produce 2 moles of water vapor (H2O).

To determine the mass of water vapor produced, we need to use the ideal gas law to calculate the number of moles of hydrogen gas present in the fuel tank:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Rearranging this equation to solve for n, we get:

n = PV/RT

Substituting the given values, we have:

n = (20.0 atm)(150.0 L)/(0.0821 L·atm/mol·K)(298 K)

n = 90.57 mol

So, there are 90.57 moles of hydrogen gas in the fuel tank. Since 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water vapor, we need half as many moles of oxygen gas as hydrogen gas. Therefore, we need:

(1/2)(90.57 mol) = 45.28 mol of O2

The molar mass of water (H2O) is 18.02 g/mol, so the mass of water produced is:

(2 mol H2O/2 mol H2) (18.02 g/mol) (90.57 mol H2)

= 1627.13 g

Rounding to two decimal places, we get:

1627.13 g → 1627.13 g

or approximately 1627.13 grams of water vapor produced.

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Answer:

a) high pressure

that is the answer i got, but wait for a few more answers before you write the answer

Answer:

-1300. kJ  

Explanation:

We have two equations:

1. P₄(s)       +3O₂(g) ⟶ P₄O₆(s);                 ΔH₁  = -1640.1 kJ

2. P₄O₁₀(s)               ⟶ P₄(s)      + 5O₂(g); ΔH₂ =  2940.1 kJ

From these, we must devise the target equation:

3. P₄O₆(s)  + 2O₂(g) ⟶ P₄O₁₀(s);               ΔH = ?

The target equation has P₄O₆(s) on the left, so you reverse Equation 1.

When you reverse an equation, you reverse the sign of its ΔH.

4. P₄O₆(s)                 ⟶ P₄(s)       +3O₂(g); ΔH₁  =  1640.1 kJ

Equation 4 has P₄ on the right. That is not in the target equation.

You need an equation with P₄ on the left, so you reverse Equation 2.  

5. P₄(s)      + 5O₂(g)  ⟶ P₄O₁₀(s);               ΔH₂ = -2940.1 kJ

Now, you add equations 4 and 5, cancelling species that appear on opposite sides of the reaction arrows.

When you add equations, you add their ΔH values.

You get the target equation 3:

4. P₄O₆(s)                      ⟶ P₄(s)        + 3O₂(g);      ΔH₁ =   1640.1 kJ

5. P₄(s)       + 2(5)O₂(g) ⟶ P₄O₁₀(s);                       ΔH₂ = -2940.1 kJ

3. P₄O₆(s)   + 2O₂(g)     ⟶ P₄O₁₀(s);                       ΔH   = -1300.  kJ

ΔH for the reaction is -1300. kJ

Answer:

Follows are the solution to this question:

Explanation:

The characterization with water molecules would be that light waves are made up of 2 different types of atoms (2 hydrogen and 1 oxygen atoms), as per the Dalton theory. There are many multiple times as many atoms of hydrogen as oxygen atoms in each water molecules. For every two hydrogen atoms, all water molecules have one oxygen atom.

Answer:

Sample Response: Dalton’s theory about compounds tells us that all water molecules have different kinds of atoms, two hydrogen atoms for every one oxygen atom.

Explanation:

Answer:

Table price is 100 dolar

Explanation:

Because the table is to expensive to buy in low price

The major intermediate in Friedel-Crafts alkylation is a carbocation, which is a highly reactive carbocation intermediate in Friedel-Crafts alkylation can undergo rearrangements or react with other nucleophiles in the reaction mixture, leading to side products and loss of selectivity.

The carbocation intermediate is highly reactive and can undergo rearrangements or react with other nucleophiles present in the reaction mixture, leading to side products and a loss of selectivity. This makes Friedel-Crafts alkylations very tricky to control.

In particular, carbocations formed during Friedel-Crafts alkylations are highly susceptible to rearrangement reactions, such as hydride shifts and alkyl shifts, which can alter the regioselectivity of the reaction or lead to the formation of unwanted byproducts.

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Answer:

B

Explanation:

Answer:

b or c

Explanation:

which ever one u think make more sense

b. inference meaning- a conclusion raeched on the basis of evidence and reasoning

c. scientific notation meaning-a way to express real numbers that are too large or too small to be conveniently written in decimal form.