Given that the half-life of an element is 15 hours and the sample activity after 24 hours is 100 millicuries, we need to determine the original activity.
Let the original activity of the sample be x millicuries. Now, let us find the fraction of the sample left after 24 hours.Fraction remaining after 24 hours = (1/2)^(24/15) = (1/2)^(8/5) ≈ 0.34We can set up the following equation to solve for x:(1/2)^(8/5)x = 100Multiplying both sides by (1/2)^(8/5),
we get:x = 100/(1/2)^(8/5) ≈ 291.50 millicuriesTherefore, the original activity of the sample was approximately 291.50 millicuries. Hence, the main answer is 291.50 millicuries.The half-life of an element is 15 hours and the sample activity after 24 hours is 100 millicuries. To determine the original activity, we use the formula:(1/2)^(8/5)x = 100. Here, x is the original activity of the sample. After substituting the values, we get x = 100/(1/2)^(8/5) ≈ 291.50 millicuries.
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Metric conversion worksheet?
The metric unit conversions based on conversion factors are:
36.52 mg = 0.03652 g14.72 kg = 14720000 mg0.0035 hm = 3.5 dm0.134 m = 0.000134 km25 mm = 2.5 cm2.5 cm^3 = 2.5 mL 243 daL = 2430 L45.23 L = 45230 mL0.035 hL = 350 cL27.32 mm = 0.02732 m15 m = 150 dm0.023 cc = 0.000023 L0.00049 km = 490 mm0.025 kg = 25 gMetric unit conversionsThe metric unit conversions of the given data are as follows:
1. 1 mg = 0.001 g
36.52 mg = 36.52 × 0.001
36.52 mg = 0.03652 g
2. 1 kg = 1000000 mg
14.72 kg = 14.72 × 1000000
14.72 kg = 14720000 mg
3. 1 hm = 1000 dm
0.0035 hm= 0.0035 × 1000
0.0035 hm = 3.5 dm
4. 1 m = 0.001 km
0.134 m = 0.134 × 0.001
0.134 m = 0.000134 km
5. 1mm = 0.1 cm
25 mm = 25 × 0.1
25 mm = 2.5 cm
6. 1 cm^3 = 1 mL
2.5 cm^3 = 2.5 mL
7. 1 daL= 10 L
243 daL = 243 × 10
243 daL = 2430 L
8. 1 L = 1000 mL
45.23 L = 45.23 × 1000
45.23 L = 45230 mL
9. 1 hL = 10000 cL
0.035 hL = 0.035 × 10000
0.035 hL = 350 cL
10. 1 mm = 0.001 m
27.32 mm = 27.32 × 0.001
27.32 mm = 0.02732 m
11. 1 m = 10 dm
15 m = 15 × 10
15 m = 150 dm
12. 1 cc = 0.001 L
0.023 cc = 0.023 × 0.001
0.023 cc = 0.000023 L
13. 1 km = 1000000 mm
0.00049 km = 0.00049 × 1000000
0.00049 km = 490 mm
14. 1 kg = 1000 g
0.025 kg = 0.025 × 1000
0.025 kg = 25 g
Therefore, the metric conversions based on conversion factors are:
36.52 mg = 0.03652 g14.72 kg = 14720000 mg0.0035 hm = 3.5 dm0.134 m = 0.000134 km25 mm = 2.5 cm2.5 cm^3 = 2.5 mL 243 daL = 2430 L45.23 L = 45230 mL0.035 hL = 350 cL27.32 mm = 0.02732 m15 m = 150 dm0.023 cc = 0.000023 L0.00049 km = 490 mm0.025 kg = 25 gLearn more about unit conversions at: https://brainly.com/question/8799113
Answer:
36.52 mg = 0.03652 g
14.72 kg = 14720000 mg
0.0035 hm = 3.5 dm
0.134 m = 0.000134 km
25 mm = 2.5 cm
2.5 cm^3 = 2.5 mL
243 daL = 2430 L
45.23 L = 45230 mL
0.035 hL = 350 cL
27.32 mm = 0.02732 m
15 m = 150 dm
0.023 cc = 0.000023 L
0.00049 km = 490 mm
0.025 kg = 25 g
14-39. Evaluate E' for the half-reaction 1 (CN)2(3)+2H+ + 2e = 2HCN(aq) Cyanogen Hydrogen cyanide 1 14-40. Calculate E' for the reaction H2C2O4 + 2H+ +2e = 2HCO2H E° = 0.204 V Oxalic acid Formic acid
The equation for the half-reaction is:
Cyanogen + Hydrogen ion + 2 electrons → Hydrogen cyanide
The balanced chemical equation for the given redox reaction is given by:CN2(3-) + 2H+ + 2e- → 2HCNFrom the given balanced equation:
Reactant: CN2(3-) and Product: HCN
In the balanced equation, number of electrons transferred = 2.The standard electrode potential, E° for this half-reaction is equal to 0.59 V.
Therefore, the E' for the given half-reaction can be calculated by using the following formula
:E'= E°-(0.0592/2) logQ
Where,
Q = [H+]^2[Cyanogen]/[Hydrogen cyanide] [H+] = 1.0M, [Cyanogen] = 1.0M, and [Hydrogen cyanide] = 1.0MTherefore,Q = (1.0)²(1.0)/(1.0)² = 1.0
Substituting the values of Q and E° in the above equation we get,
E' = 0.59-(0.0592/2) log1.0 = 0.59 - 0 = 0.59 Volts.
The equation for the given redox reaction is given by:
H2C2O4 + 2H+ + 2e- → 2HCO2H
The balanced chemical equation for the given redox reaction is given by:
Reactant: H2C2O4 and Product: HCO2H
In the balanced equation, number of electrons transferred = 2.The standard electrode potential, E° for this half-reaction is equal to 0.204 V.
Therefore, the E' for the given half-reaction can be calculated by using the following formula:
E' = E° - (0.0592/2) logQ
Where,
Q = [H+]²[Oxalic acid]/[Formic acid] [H+] = 1.0M, [Oxalic acid] = 1.0M, and [Formic acid] = 1.0MTherefore,Q = (1.0)²(1.0)/(1.0)² = 1.0
Substituting the values of Q and E° in the above equation we get,
E' = 0.204-(0.0592/2) log1.0 = 0.204 - 0 = 0.204 Volts.
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When two or more simple machines are combined they form a(n) ____.
A. Compound machine
B. Complex machine
C.intricate machine
D.inefficient machine
Answer:
A
Explanation:
A compound machine is a combination of two or more simple machines.
you have a 3.0 g of solid magnesium metal in 250 ml of 1.0mol/l hydrochloric acid solution that is in the beaker. you place a large gas collecting tube over the magnesium and vollect the product, hydrogen gas. assume all the conditions at the lab are SATP.
a) write a chemical balanced equation
b) calculate the number of theoretical moles of hydrogen that should be reduced in this reaction.
c) calculate the volume of hydrogen gas produced. remember that the gas is collected over water.
d) you now quickly do a burning splint test on the hydrogen. jt reacts with just enough oxygen in the gas collecting tube to produce liquid water. what mass of liquid water is produced? (new balanced equation)
Answer:
a)Mg(s) + 2HCl(aq) -------> MgCl2(aq) + H2(g)
b) 0.125 moles of hydrogen gas is reduced in the reaction.
C) 3.18 L
d)2.25 g of water
Explanation:
a) the equation of this reaction is;
Mg(s) + 2HCl(aq) -------> MgCl2(aq) + H2(g)
b)
Number of moles= concentration × volume= 1.0 × 250/1000 = 0.25moles of HCl
From the equation;
2 moles of HCl yields 1 mole of hydrogen gas
Hence 0.25 moles of HCl yields 0.25 × 1/2 = 0.125 moles of hydrogen gas
Thus 0.125 moles of hydrogen gas is reduced in the reaction.
c)
P= 760 mmHg (standard pressure)
V= ????
T= 298 K
n= 0.125 moles
R= 0.082 atm dm-3K-1mol-1
Since the gas is collected over water, SVP of hydrogen at 25°c is 28mmHg
Therefore; P=760-28= 732mmHg
But
1 atm =760 mmHg
Therefore 732 mmHg= 732/760= 0.96 atm
PV=nRT
V= nRT/P
V= 0.125 × 0.082 × 298/0.96
V= 3.18 L
Note 1dm-3=1L
d)
2H2(g) + O2(g) ----> 2H2O(g)
From the equation;
2 moles of hydrogen yields 2 moles of water
0.125 moles of hydrogen yields 0.125 moles of water
Mass of water = 0.125 moles × 18gmol-1 = 2.25 g of water
What is the Chemical Formula and Net Ionic Equations for all three solutions.
Answer:
See answer below
Explanation:
As you are asking for chemical formula and ionic equation, then, I will assume that after the station #3 below, are the solutions you are requiring.
You are also not specifing if you want for example, result of solution 1 + solution 3. If you need that, please post that on another question.
Now for the chemical formula, you need to identify the elements in all 3 solutions, and also the type of compound.
1. Solution 2 Potassium Iodide:
In this case we have Potassium on one side, and Iodine on the other side, the symbol for those are K and l. As Potassium have the +1 oxidation state, cause is the only one that it can have, when it's next to an halide like chlorine or bromine, it will form a binary salt. The halides, usually work with the lowest oxydation state. In the case of Iodide it will be -1, so, the formula will be:
KI
And the net ionic equation will be the chemical equation that shows how the charges and atoms are balanced. In this case it would be:
K⁺ + I⁻ ------> KI
2. Solution 1 and 3, Lead (II) nitrate and Sodium carbonate:
In this case I will work with both, because both of the solution are tertiary compounds. In this cases, we have two tertiary salt, The Sodium symbol is Na, and is working with it oxydation state +1. Carbonate is an anion and have the formula CO₃ working with the oxydation state -2. Lead can work with oxidation state +2 and +4. It's symbol is Pb. Nitrate is NO₃ and works with oxydation state -1 instead.
The chemical formula and ionic equation for both will be:
Lead(II) nitrate: Pb(NO₃)₂
Sodium Carbonate: Na₂CO₃
And the net equations:
Lead nitrate: Pb²⁺ + 2NO₃⁻ ------> Pb(NO₃)₂
Copper sulfate: 2Na⁺ + CO₃²⁻ -------> Na₂CO₃
Hope this helps
Zelda noticed a puddle outside her front door. She saw that the puddle got smaller every day, until the 3rd day when it was completely gone. The next week, she noticed the puddle again. This time the puddle was gone the next day. Since the sun was out the second week but not the first week, Zelda hypothesized that the heat from the sun was the reason for the water evaporating at a faster rate. If she were to set up two containers with equal amounts of water, what would be the best way for Zeldato test her hypothesis\
Answer: Zelda should place one container of water in sunlight (by a window or outdoors) and the other container in a dark room (closet) away from the sun.
Explanation: This would allow Zelda to test two different settings (sun and no sun) so she can test her hypothesis.
what other information do you need in order to determine the molecular formula from the empirical formula of a compound?
We need to know the molecular mass in order to determine the molecular formula from the empirical formula of a compound.
Molecular formula is formed from the actual number of elements that are involved in forming the molecule whereas empirical formula is the reduced ratio of the elements present in the compound.
We can determine the empirical formula of a substance by taking the subscripts of the molecular formula and reducing it to simplest whole number ratio.
we can calculate the molecular formula as:
n = molecular mass/ empirical formula mass
where n is any positive number.
Thus, when molecular mass is known , molecular formula can be determined form the empirical formula of a compound.
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they form a new____ with properties___from the original element
its about molecules
They form a new compound with new properties from the original element.
The same components are always present in the same ratios in a compound. Compounds' characteristics differ, sometimes significantly, from the characteristics of the constituent . This is due to the fact that when elements in such a compound combine, a whole new substance with distinct features results.
A compound contains special characteristics that set it apart from the characteristics of its basic elements.
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A 0.860-kg sample of tin (with a specific heat of 210.0 J/(kg x K)) is heated to 525 K and then placed in 1.20 kg of water that is at 303 K. If the system is left to reach its equilibrium state, what will the equilibrium temperature be? Assume that no thermal energy is lost to the external environment. Use 4.186 J/(g x K) as the specific heat of water.
PLEASE ANSWER QUICK WILL GIVE BRAINLIEST
Answer: 310K
Explanation: I got it right
Answer:
310 k
Explanation:
Hope this helps
Combien y a-t-il de molécules dans 0,5 mol de molécules d'eau (H20) ?
Answer:
molecules
.5 × 6.02×10²³
3.01 × 10²³ molecules
I hope it's helps you
what is the name of the binary compound mg3 (po3)2?
The name of the binary compound Mg₃(PO₃)₂is magnesium pyrophosphate. In this compound, "Mg" represents the symbol for magnesium, and "PO3" represents the phosphate ion with a -3 charge.
The subscript "2" outside the parentheses indicates that there are two phosphate ions present. The naming of the compound follows the rules for naming binary compounds. The metal, magnesium, is named first, followed by the nonmetal, phosphate. Since phosphate is a polyatomic ion, its name remains unchanged. The subscript "3" outside the parentheses indicates that there are three magnesium ions present.
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The interaction of aligned sp3 orbitals on adjacent atoms is _____________
It will ____________ (increase/decrease) the internal energy of a rotamer.
Answer: The interaction of aligned sp3 orbitals on adjacent atoms is called sigma orbitals. It can increase the internal energy of a rotamer.
Explanation:
The interaction of aligned sp3 orbitals on adjacent atoms is called σ-bonding. It occurs due to axial overlapping of sp3 orbitals.This interaction can increase the internal energy of a rotamer.
Drag and drop the words that accurately complete the chart below. Example a lion and a cheetah mistletoe on a tree a coyote eating a rabbit a remora and a shark clownfish and anemone parasitism friendship competition Type of Symbiosis mutualism 1:10 predation relationship commensalism collaboration alliance
Answer:
Lion and cheetah - Competition
Mistletoe on a tree - Parasitism
Coyote eating rabbit- Predatation
Remora and Shark - Mutualism
Clownfish and Anemone - Relationship
Explanation:
Match each term below with its definition or description.
1 The point in a titration when the added amount of standard reagent is equal to the amount of analyte being titrated.
2 The analyte is titrated with the standard reagent and the volume of standard solution required to complete the reaction is measured.
3 A reagent that is pure and stable, which can be used directly after weighing.
4 The analyte that is being analyzed in the titration.
5 Standard reagent is added in excess to ensure complete reaction with the analyte. The excess reagent is then titrated with a second standard reagent.
6 A solution, whose concentration is known, often made from a reagent of known purity.
7 The standard reagent of known concentration that is added from a buret to the analyte solution.
8 The analyte does not react directly with the titrant so it is converted to another form which will react with the titrant.
9 The point in a titration when a change in the analyte solution is observed, indicating equivalency.
10 It is added to the analyte solution and aids in the observation of the completion of the reaction.
a) End Point
b) Indicator
c) Direct Titration
d) Back Titration
e) Indirect Titration
f) Primary Standard
g) Standard Solution
h) Titrand
i) Equivalence Point
j) Titrant
Answer:
1. Equivalence point
2. Direct titration
3. Primary standard
4. Titrand
5. Back titration
6. Standard solution
7. Titrant
8. Indirect titration
9. End point
10. Indicator
Explanation:
1. The equivalence point is the tiration point at which the quantity or moles of the added titrant is sufficient or equal to the quantity or moles of the analyte for the neutralization of the solution of the analyte.
2. Direct titration is a method of quantitatively determining the contents of a substance
3. A primary standard is an easily weigh-able representative of the mount of moles contained in a substance
4. A titrand is the substance of unknown concentration which is to be determined
5. The titration method that uses a given amount of an excess reagent to determine the concentration of an analyte is known as back titration
6. A standard solution is a solution of accurately known concentration
7. A titrant is a solution that has a known concentration and which is titrated unto another solution to determine the concentration of the second solution
8. Indirect titration is the process of performing a titration in athe reverse order
9. The end point is the point at which the indicator indicates that the equivalent quantities of the reagents required for a complete reaction has been added
10 An indicator is a compound used to visually determine the pH of a solution.
The titration has been the neutralization reaction in which the titrand and the titrant react to form the salt and the water and help in the determination of the qualitative and quantitative properties.
What is an Endpoint?In a titration reaction, the endpoint has been the point at which the equivalent amount of reagent has been completely neutralized.The Indicator has been the chemical that changes to indicate the endpoint of the reaction.Direct titration involves the reaction for the quantitative determination of the substances.The back titration can be given as the reaction in which the excess reagent is used to titrate the second standard reagent in the reaction.Indirect titration can be given as the reaction of the analyte to convert to another form and then the analysis with the titrant.The primary standard has been the known concentration of the pure and stable weighing reagent.The standard solution has been the solution of the known concentration in the reaction.Titrand has been the unknown sample that has to be analyzed.The equivalence point is the concentration point at which the quantity of titrant added to the titrand has been equal.Titrant has been the known concentration of sample that has been added to equivalent the unknown sample.Learn more about titration here:
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Calculate the molar mass of a sample if a single molecule weighs 2.55 x 10^-23 g.
molar mass= energy x mass= 10 x 2.55 x 10^-23
Avogadro's number (NA) or Avogadro's constant (6.0221 x 10^23). The term "mole" is defined as that one mole of a substance with a molecular (or atomic) mass of one (1), will have a mass of 1 gram.
What is Avogadro's number?The number of molecules in one mole is 6.022 * 10^ 23 numbers. The molecular mass of the molecule is 2.55 x 10^-23
Molar mass can be defined as 'mass per mole.' In other words, molar mass is the sum of the mass of all the atoms found in one mole's worth of a substance. It is expressed in units of grams per mole.
Molar mass is depicted for elements or molecules. In the case of single elements or individual atoms, the molar mass would just be the element's mass expressed in atomic mass units.
Molar mass = 2.55 x 10^-23/ 6.022 * 10^ 23
= 0.423
Therefore, Avogadro's number (NA) or Avogadro's constant (6.0221 x 10^23). The term "mole" is defined as that one mole of a substance with a molecular (or atomic) mass of one (1), will have a mass of 1 gram.
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find the relative molecular mass of lead trioxonitrate(v)
(pb=108,N=14,O=16)
Answer:
The molecular mass of lead trioxonitrate(V) is 232
Explanation:
The molecular mass of Lead Trioxonitrate(V),which is Pb(NO3)2 is:
= 108 + (14 + 3*16)*2
= 108 + 62*2
= 108 + 124
= 232
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14) Of the following acids, __________ is not a strong acid. A) HNO2
B) H2SO4
C) HNO3
D) HCIO4
E) HCl
Hello! HNO2 is not a strong acid so therefore your answer is A.
A rule of thumb, the rest are strong acids, so when you ever come across a similar question you will be able to rule out the wrong answers quicker :).
Strong acid list:
H2SO4
HNO3
HCLO4
HCLO3
HCL
HBr
HI
hope this helps!
18.how would each of the following changes affect the equilibrium position
Please help me please both 18 and19
Flammable liquids are those that have a flashpoint of:.
Answer:
Flammable liquid is any liquid having a flashpoint at or below 199.4 °F (93 °C).
Explanation:
:)
Flashpoints for flammable liquids are at 100°F. Lower flash points allow for easier ignition of liquids. A liquid's flash point is the lowest temperature at which a concentrated enough layer of vapor accumulates on top of its surface to allow for ignition.
A liquid that is flammable has a flash point* below 37.8 ° C (100 ° F). A flammable liquid has a flash point that ranges from 37.8 to 93.3° C (100 to 200° F), which is above the standard working temperature. Flammable liquids emit a vapor that, at standard working temperatures, is easily ignitable.
The substance ignites more readily the lower the flash point. For instance, petrol is more flammable than ethylene glycol and has a flash point of about -40 degrees C (-40 °F).
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Sodium (Na) and iodine gas (I2) react to form sodium iodine (NaI).
Which equation is a correct representation of the balanced equation?
2Na+I2→2NaI
I2→2NaI+2Na
Na→NaI+I2
NaI→2Na+I2
Answer:
2Na+I2→2NaI
Explanation:
A less stable carbocation can rearrange to a more stable carbocation by shift of a hydrogen atom or an alkyl group. These rearrangements are called ____________ and ____________ shifts, respectively.
A less stable carbocation can rearrange to a more stable carbocation by shift of a hydrogen atom or an alkyl group. These rearrangements are called hydride and alkyl shifts, respectively.A carbocation is a positively charged species with a vacant p orbital present in the carbon atom.
The vacant p orbital forms a pπ-pπ bond with the nucleophile, while the electrophilic carbon atom is known as a carbocation. It can be formed in a unimolecular reaction in which one bond breaks to form a carbocation and a leaving group.A carbocation can be stabilized by the electron-donating ability of alkyl groups or electron-withdrawing effects of various functional groups. The electron-donating effects of alkyl groups help to stabilize the positive charge. Therefore, as the number of alkyl groups attached to the carbocation's carbon atom rises, so does its stability.The stability of carbocation depends on the number of alkyl groups attached to the carbocation's carbon atom. The greater the number of alkyl groups attached to the carbocation, the more stable it will be. When the carbocation is less stable, it will rearrange to form a more stable carbocation through a shift of a hydrogen atom or an alkyl group. When hydrogen is moved, it is known as a hydride shift, and when an alkyl group is shifted, it is known as an alkyl shift.
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Many watches are powered by small, flat batteries called button cells. One common type of button cell contains the metal zinc. When zinc in the battery combines with oxygen in the air, zinc oxide forms. This process generates the electricity that powers the watch. is this a product or reactant
The electricity generated that powers the watch by zinc in the battery combines with oxygen in the air, zinc oxide forms reaction is a product.
Zinc-air batteryIn zinc -air battery oxidation of zinc to zinc oxide in presence of oxygen from air takes place. These batteries are cost-effective and contain more density of energy as compared to others. When compared with lithium batteries these are with more capacity, environmental safe, cost-effective and easy to produce these are widely used. Metal-air batteries fueled by the oxidation of zinc with oxygen from the air include zinc-air batteries (non-rechargeable) and zinc-air fuel cells (mechanically rechargeable). These batteries are produced at comparatively low costs and have great energy densities.Effective anode materials must be developed for next-generation lithium-ion batteries (LIBs). Due to a number of intriguing characteristics, including its high theoretical capacity, simplicity in synthesis, environmental friendliness, and low cost, zinc oxide (ZnO) has been regarded as a useful material.In addition, compared to the majority of primary batteries, zinc-air batteries offer a high volumetric energy density. Such batteries have a number of drawbacks, including a reliance on ambient conditions, a propensity to dry up when exposed to air, flooding potential, a finite output, and a brief active life.For more information on zinc batteries kindly visit to
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A. what color represents the bonds between the particles of nac2h3o2? b. click play. watch the animation a few times. what happens to the nac2h3o2 bonds? c. what happens to the bonds between water molecules? d. what color are the new bonds that form between the solute and solvent?
a. The color representing the bonds between the particles of NaC₂H₃O₂ is not specified in the given question.
b. Watching the animation multiple times will help observe what happens to the bonds of NaC₂H₃O₂.
c. The question does not provide information about what happens to the bonds between water molecules.
d. The question does not specify the color of the new bonds formed between the solute and solvent.
a. The color representing the bonds between the particles of NaC₂H₃O₂ is not provided in the question. The color of the bonds can vary depending on the representation used in the specific context of the animation or experiment being referred to.
b. Watching the animation multiple times allows for careful observation of what happens to the bonds of NaC₂H₃O₂. The animation might depict the breaking of bonds between the sodium cations (Na+) and the acetate anions (C₂H₃O₂₋) as the solute dissolves or interacts with the solvent.
c. The question does not provide information about what happens to the bonds between water molecules. However, in general, water molecules form hydrogen bonds with each other due to the polarity of the water molecule. These hydrogen bonds contribute to the unique properties of water, such as its high boiling point and surface tension.
d. The question does not specify the color of the new bonds that form between the solute (NaC₂H₃O₂) and the solvent. The color of the bonds formed between the solute and solvent is not a defining characteristic and can vary depending on the specific context or representation being used.
It is important to note that the given question lacks specific details or context regarding the colors and changes in bonds. Further information or clarification would be necessary to provide a more accurate and detailed response.
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What are the two types of adaptations that plants can show? (2 points) a Physical characteristics and life cycle differences. b Life cycle differences and color differences. c Physical characteristics and different food sources. d Physical characteristics and behavioral differences.
physical characteristics and life cycle differences are the two types of adaptations that plants can show (option A)
What is adaptation?The science community has long recognized adaptation as critical in sustaining living entities' livelihoods worldwide. Organisms gradually evolve by changing specific characteristics susceptible to environmental pressures through natural selection- enabling advantageous features within nature's unique selective pressures compared to less-adapted species when navigating complex environments .
Further categorizing adaptation into three groups provides us insight into how life adapts best – Physical adaptations suitable for warding off potential threats; Behavioral adaptations improving available resources; Physiological adjustments maximizing bodily functions within the context provided by the environment
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If a handsaw does the same amount of work on a log is a chainsaw does, which has more power? Why?
if youre good at chemistry u better help me now please!
Answer:
letter B is the answer
Explanation:
just take a look at the atoms
Answer:
B.) Only elements have one kind of atom.
Explanation:
An element consists of only one type of atom, while a compound consists of two or more types of elements
Why is it important for lab safety to know the proper names of equipment in a lab
Answer:
Knowing your lab equipment and their names will aid in having a successful experiment and may help in correcting errors.
If you do not know your lab equipment, that will only result in having a lack of knowledge of the equipment or not knowing how to correct a mistake in an experiment.
Explanation:
Hope I helped.
A customer is traveling to a branch office static ip.
Answer:
A customer is travelling to a branch office, and the network administrator provides her with a static IP address for her laptop
Explanation:
I hope this helps!!!...
Brainliest please???
Oxygen gas is at a temperature of 145 K when it occupies a volume of
1.45 Liters. To what temperature should it be raised to occupy a volume of 6.50
Liters? Show your work. (Express your answer in Kelvin)
Answer:650K
Explanation:
Answer: 650K (1.45/145 = 6.50/x)
Explanation:
In the molecule on the left, areas that have a partial negative charge are pink and areas that have a partial positive charge are blue. The molecule on the right is nonpolar.
What will most likely happen when these molecules get closer?
A The molecules will repel each other because of a dipole-dipole interaction.
B The molecules will attract each other because of a dipole-dipole interaction.
C An induced dipole will be produced in the molecule on the right.
D An induced dipole will be produced in the molecule on the left.
Answer: A The molecules will repel each other because of a dipole-dipole interaction