harold, tanya, and ulysses paint a very long picket fence. harold starts with the first picket and paints every h th picket; tanya starts with the second picket and paints every t th picket, and ulysses starts with the third picket and paints every u th picket. call the positive integer 100h 10

Answer:

$0.50 per lb.

Step-by-step explanation:

$2 / 4 = $0.50

Hope this helps!

Answer:

108

Step-by-step explanation:

To find x, you need the geometric mean. First, find the second part of 225 by doing 225 - 144 = 81. Now, to find geometric mean, do 81 x 144 = 11,664; \(\sqrt{11,664} = 108\).

The missing length in the right triangle as given in the task content is; 108.

It follows from the complete question that the triangle given is a right triangle and the missing length can be calculated as;

First, find the second part of 225 by

225 - 144 = 81.

Now, to find geometric mean,

81 × 144 = x²

11,664 = x²

x = 108

Thus, The missing length in the right triangle as given in the task content is; 108.

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a) i) The probability of occurrence of the design discharge exactly once during its lifetime is 1/500.

ii) The probability of occurrence of the design discharge at least twice during its lifetime is 1 - (1 - 1/500)^50.

iii) The probability of the design discharge occurring three times in the first three years (not occurring in the next 47 years) is (1/500)^3 * (1 - 1/500)^47.

b) i) The expected magnitude of a 40-year flood assuming a Normal distribution.

ii) The return period of a 330 m3/sec flood assuming a Gumbel distribution.

a) The probability of occurrence of the design discharge can be calculated using the concept of return period. For a dam designed for a 500-year flood and expected to be in operation for 50 years, we can calculate the probability for different scenarios:

i) The probability of the design discharge occurring exactly once during its lifetime can be calculated by using the reciprocal of the return period. In this case, the return period is 500 years, so the probability is 1/500.

ii) To calculate the probability of the design discharge occurring at least twice during its lifetime, we need to consider the complementary probability. The probability of it not occurring twice is (1 - 1/500)^50 (probability of it not occurring once in 50 years). Therefore, the probability of it occurring at least twice is 1 - (1 - 1/500)^50.

iii) The probability of the design discharge occurring three times in the first three years (not occurring in the next 47 years) can be calculated by multiplying the probability of occurrence in the first three years (1/500)^3, with the probability of not occurring in the subsequent 47 years (1 - 1/500)^47.

b) To calculate the expected magnitude of a 50-year flood, we can use two different distributions: Gumbel and Normal.

i) Assuming a Normal distribution, the expected magnitude of a 50-year flood can be estimated by multiplying the mean (x) by the ratio of the standard deviation (ox) of a 50-year flood to the standard deviation of a 25-year flood. The standard deviation ratio can be calculated as sqrt(50/25) = sqrt(2).

ii) Assuming a Gumbel distribution, the return period of a flood with a magnitude of 330 m3/sec can be calculated by using the Gumbel distribution formula. The return period (T) can be obtained as 1 / (1 - (1/T)). Rearranging the formula, we can solve for T, giving us the return period of the flood.

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Answer:

3 hours

Step-by-step explanation:

Total cost = 144 + 80h

Where h = number of hours

How many hours can Michelle afford to pay the mechanic if she can spend no more than $384?

384 = 144 + 80h

Subtract 144 from both sides

384 - 144 = 144 + 80h - 144

384 - 144 = 80h

240 = 80h

Divide both sides by 80

h = 240 / 80

= 3

h = 3 hours

Answer:

The answer is G

Step-by-step explanation:

Answer:

The scale factor used is 0.4

Step-by-step explanation:

Given

\(R = (3,9)\)

\(R' = (1.2, 3.6)\)

Required

Determine the scale factor of RST

The question can be solved using scale factor formula

Scale factor is calculated as thus;

\(Scale\ Factor = \frac{New\ Length}{Old\ Length}\)

In this case; R' is the new length and R is the old length

\(Scale\ Factor = \frac{R'}{R}\)

Substitute the values of R and R'

\(Scale\ Factor = \frac{(1.2,3.6)}{(3,9)}\)

Factorize the denominator

\(Scale\ Factor = \frac{(1.2,3.6)}{2.5(1.2,3.6)}\)

\(Scale\ Factor = \frac{1}{2.5}\)

\(Scale\ Factor = 0.4\)

Hence, the scale factor used is 0.4

#5

Since the elevation of the picture is

We need to change it in decimal, then divide the numerator of the fraction by the denominator of the fraction

Then the elevation in decimal is

Answer:

B.)

Step-by-step explanation:

Took test

Quality Homes Construction Company orders only lumber that is at least 80% clear-free of defects. including knots and edge defects. in an order containing 65,500 linear feet, 52,400 linear feet of lumber will be free of defects.

Percentage of Defect-Free Lumber-

Quality Homes Construction Company orders lumber that is at least a certain percentage clear-free of any sort of defects. then they go ahead and order a big supply of lumber. Using percentages from Algebra we calculate the amount of the lumber that will be totally free of any defects. Percentages play an important role in Algebra as well as in Probability and Statistics.

Gives that at least 80% = 0.8 of the lumber is clear free of all defects, the minimum amount of lumber free of all defects will then be

0.8 x 65,500 = 52,400 linear feet of lumber.

Hence, 52,400 linear feet of lumber will be free of defects.

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Answer:

20 coins

Step-by-step explanation:

20x10 =200 so that is 20 is 10% of 200

Answer:

About 87$

Step-by-step explanation:

Yu take both salary amounts an divide by 52 since there are 52 weeks in a year and then find the difference between them

An equation for the number of points y, and the correct answers x  is y = 10x.

One mathematical expression makes up a term. It could be a single variable (a letter), a single number (negatively or positively), or a number of variables multiplied but just never added as well as subtracted.

For the stated question-

Consequently, the total points earned equal the total points earned for each question. number of questions with accurate responses.

Consequently, points earned = 10x

y = 10x.

First geography test: x = 3

y = 10*3 = 30

Second geography test: x = 7

y = 10*7 = 70

Thus, the graph for the enrique's first and second geography test is plotted.

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The correct question is-

Enrique earns 10 points for each question that he answers correctly on a geography test. Write an equation for the number of points, y Enrique scores on the test when he answers x questions correctly.

On his first geography test, Enrique answered 3 questions correctly. On his second test, Enrique answered 7 questions correctly.

Place points on the graph to show Enrique's first and second geography test.

Answer:

m A = 63

m C = 27

Step-by-step explanation:

to find the angle of a use trigonometry by doing, cos-1(17/38) = 63

to find C, we know angles in a triangle add to 180. We know the right angle is 90 degrees so do 90 + 63 = 153

180 - 153 = 27

so C = 27 degrees

Answer:

0.25

Step-by-step explanation:

1.2 divide by 4.8=0.25

0.25*4.8=1.2

5 = .25

4.8 x .25 = 1.2

Therefore, the possible numbers of minutes Linda has used her phone in a month are 1459 minutes or more.

To determine the possible number of minutes Linda has used her phone in a month, we can set up an equation based on the given information.

Let's assume the number of minutes Linda has used her phone in a month is represented by 'm'.

The total charge for the phone service consists of the monthly fee of $27 plus the additional charge of $0.07 per minute:

Total charge = $27 + $0.07 * m

According to the given information, the least amount Linda has been charged in a month is $129.13. So we can set up the following equation:

$27 + $0.07 * m ≥ $129.13

Now we can solve this equation to find the possible range of values for 'm'.

$0.07 * m ≥ $129.13 - $27

$0.07 * m ≥ $102.13

m ≥ $102.13 / $0.07

m ≥ 1459

Therefore, the possible numbers of minutes Linda has used her phone in a month are 1459 minutes or more.

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If the polynomial \(f(x) = a0 + a1x + a2x^2 + ... + anx^n\) is a zero divisor in the polynomial ring R[x], and a is not equal to 0R, then the coefficient an is a zero divisor in the commutative ring R.

To prove that if \(f(x) = a0 + a1x + a2x^2 + ... + anx^n\) is a zero divisor in the polynomial ring R[x] where R is a commutative ring and a is not equal to 0R, then an is a zero divisor in R, we can use a proof by contradiction.

Assume that an is not a zero divisor in R. This means that for any element b in R, if anb = 0, then b must be equal to 0.

Now, suppose f(x) is a zero divisor in R[x]. This means that there exists a nonzero polynomial g(x) in R[x] such that f(x) * g(x) = 0.

Expanding the product, we have:

\((a0 + a1x + a2x^2 + ... + anx^n) * g(x) = 0.\)

Looking at the highest degree terms in this expression, we find that the coefficient of x^(n + deg(g(x))) is equal to an * leading coefficient of g(x), which we'll denote as bg.

Since f(x) * g(x) = 0, we have that an * bg = 0.

Since an is not a zero divisor in R, this implies that bg must be equal to 0. However, this contradicts our assumption that g(x) is a nonzero polynomial, as it would imply that bg = 0 for some nonzero b in R.

Therefore, our assumption that an is not a zero divisor in R leads to a contradiction, and thus, an must be a zero divisor in R.

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Answer:

their you go cuz

Step-by-step explanation:

They still have to earn:

$750 - $182.9 = $567.1

and if they make $5.35 for every pizza sold:

$567.1 : $5.35 = 106

Answer:

They must sell 106 pizzas more.

Answer:

They must sell 106 pizzas more.

Step-by-step explanation:

They still have to earn:

$750 - $182.9 = $567.1

and if they make $5.35 for every pizza sold:

$567.1 : $5.35 = 106

Answer:

They must sell 106 pizzas more.

Answer:

m/4  when m = 12, the value is 11

Step-by-step explanation

Answer:

D

Step-by-step explanation:

\(~~(2x+7x^2 -9)+(3x^3 -7x^2 +10)\\\\=2x +3x^3+7x^2 -7x^2 -9+10\\\\=3x^3 +2x +1\)

The rectangular coordinates of the points of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ), the equations can be converted to rectangular form. However, solving the resulting system of equations algebraically may be challenging. Alternatively, graphing the polar curves and visually identifying the points of intersection can provide an effective method.

To find the rectangular coordinates of the points of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ), the equations can be converted to rectangular form, the rectangular coordinates of the above points are given below:

For the equation r = 2sin(2θ):

x = 2sin(2θ)cos(θ)

y = 2sin(2θ)sin(θ)

For the equation r = 2sin(θ):

x = 2sin(θ)cos(θ)

y = 2sin^2(θ)

The rectangular coordinates of the point(s) of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ) can be found by converting the polar equations to rectangular form and solving for the x and y coordinates.

To convert the polar equations to rectangular form, we can use the relationships x = rcos(θ) and y = rsin(θ). Substituting these expressions into the given polar equations, we get:

For the equation r = 2sin(2θ):

x = 2sin(2θ)cos(θ)

y = 2sin(2θ)sin(θ)

For the equation r = 2sin(θ):

x = 2sin(θ)cos(θ)

y = 2sin^2(θ)

To find the points of intersection, we need to set the x and y coordinates of both equations equal to each other and solve for θ. However, solving this system of equations algebraically can be complex due to the trigonometric functions involved.

Graphing the polar curves and visually inspecting the points of intersection may provide a more intuitive approach to finding the rectangular coordinates. By plotting both polar curves on a graph, the points where the curves intersect can be determined by their shared coordinates.

In summary, to find the rectangular coordinates of the points of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ), the equations can be converted to rectangular form. However, solving the resulting system of equations algebraically may be challenging. Alternatively, graphing the polar curves and visually identifying the points of intersection can provide an effective method.

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False. The system of parallel lines and spaces used to write music is called staff notation, not notation.

The statement is false. The system of parallel lines and spaces used to write music is called staff notation, not simply notation. Staff notation is a widely used method for representing music visually, where notes are placed on a set of horizontal lines and spaces called the staff.

In staff notation, the lines and spaces represent different pitches, and musical symbols such as notes, rests, and various other symbols are used to indicate duration, rhythm, dynamics, and other musical elements. The staff typically consists of five lines and four spaces, and additional lines and spaces can be added when necessary to represent higher or lower pitches.

Notation, on the other hand, is a broader term that refers to the system or method of representing something in written or symbolic form. It can be used to describe various systems of representation across different fields and disciplines, not limited to music. Therefore, the specific system used in music to write musical scores is called staff notation, not notation alone.

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The probability P(n < 10 | n is prime) is 4/6, which simplifies to 2/3 or approximately 0.67 (rounded to the nearest hundredth).

To find the probability P(n < 10 | n is prime), we need to determine the number of prime integers less than 10 and divide it by the total number of integers from 1 to 15 that are prime.

The prime numbers less than 10 are 2, 3, 5, and 7. So, there are 4 prime numbers less than 10.

The total number of integers from 1 to 15 that are prime is 6 (2, 3, 5, 7, 11, and 13).

As a result, the chance P(n 10 | n is prime) is 4/6, which can be expressed as 2/3 or, rounded to the nearest hundredth, as around 0.67.

Thus, 0.67 is the answer.

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Answer:

these lessons, we will how to solve

• word problems that involve a single Simple Interest

• word problems that involve more that one Simple Interest.

• word problems that involve Simple Interest with discounted loan.

Answer:

B

Step-by-step explanation:

To rotate triangle ABC about the origin 90° clockwise we would follow the rule (x,y) → (y,-x), where the y-value of the original point becomes the new x-value and the x-value of the original point becomes the new y-value with the opposite sign.

The expression that is equivalent to the one Shea wrote is b 5 x y x 5 x 2 +4

From the question, we have the following parameters that can be used in our computation:

5(y + 2) + 2 shows the amount of money five friends paid for snacks at a basketball game

This means that

Amount = 5(y + 2) + 2

When expanded, we have

Amount = 5 * y + 5 * 2 + 2

Using the above as a guide, we have the following:

The expression that is equivalent to the one Shea wrote is b 5 x y x 5 x 2 +4

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There are 3 balanced strings in set T.

To count the number of balanced strings in the set T={0, 1, 2}, we can establish a bijection between the set of balanced strings and T itself. A balanced string is defined as a string in which the sum of its digits is a multiple of 3.

We can define a function f: T" -> T that maps each string in T" to T by preserving the balanced property. If a string in T" is already balanced, f returns the string itself. If the string is not balanced, f replaces the last digit with digit that makes the sum a multiple of 3.

By showing that this function is both injective (one-to-one) and surjective (onto), we establish a bijection. The bijection rule states that if two sets have a bijection between them, they have the same cardinality. Therefore, the number of balanced strings is equal to the number of elements in T, which is 3.

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Answer:

A

Step-by-step explanation:

\(P(B|A)=\frac{A ~and~B}{P(A)} \\0.5=\frac{P(A and B)}{0.6} \\P(A~and~B)=0.5 \times 0.6=0.30\)

Answer:

In the case presented, the range is the difference between the maximum value and the minimum value of the data. The range describes the breadth of the data and how much they vary from the minimum value to the maximum value. Therefore, the range indicates the dispersion of the data.

The statement indicates that the range is 5, which means that the most flights made by students is 5. Since the data has a narrow dispersion, we can conclude that most students have taken a similar number of flights, implying that most students have flown an amount close to the maximum number observed.

Therefore, the option that best describes the dispersion of the data is: "The data has a range of 5, which is a narrow dispersion. This means that most students have taken a similar number of flights."

Step-by-step explanation: