Answer:
For number 1 is x=6 and for number 2 is y = 32
Step-by-step explanation:
A big school bus was 2/7 full when it left Area A. When it arrived at Area B, 9 children alighted the bus and there were 31 children on the bus after that. How many children can fit into the big school bus?
The total capacity of the big school bus is 140 children.
To find out how many children can fit into the big school bus, let's work through the given information step by step.
When the bus left Area A, it was 2/7 full. This means that 2/7 of the bus's capacity was occupied by children. Let's represent the total capacity of the bus as 'x'. Therefore, 2/7 of 'x' corresponds to the number of children on the bus when it left Area A.
After the bus arrived at Area B, 9 children alighted, which means the number of children decreased by 9. We are then told that there were 31 children remaining on the bus. So, the number of children on the bus before any alighted was 31 + 9 = 40.
Since 2/7 of the bus's capacity was occupied by children when it left Area A, we can set up the following equation:
(2/7) * x = 40
To solve for 'x', we can multiply both sides of the equation by (7/2):
x = 40 * (7/2)
x = 140
Therefore, the total capacity of the big school bus is 140 children.
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so easy read whats on the image
The answer is: J - 3.08 pounds
Option I ) 3.08 pounds
The reason being that it can't round up with the 2 so we just have that number to the hundredth
How is 1.35 x 10-5 written in standard notation?
A.
135.000
C.
0.00000135
Answer:
C.
Brainliest, please!
Step-by-step explanation:
A negative exponent means that the number is really small, which is true in this case.
Answer:
0.00000135
Step-by-step explanation:
1.35 x 10-5 means,
1.35/100000
=>0.00000135
Find the values of the trigonometric functions of t from the given information. tan(t) = -12/5 , sin(t) > 0 ,sin(t),cos(t),csc(t),sec(t),cot(t).
Find the radius r of the circle if an arc of length 20 m on the circle subtends a central angle of 5
π
/7 rad. (Round your answer to two decimal places.)
The values of the trigonometric functions of t are Sin(t)=0.2, Cos(t) = -5/12, Csc(t) = 5,Sec(t) = -12/5, Cot(t) = -5/12 and the radius r of the circle if an arc of length 20 m on the circle subtends a central angle of 5π/7 rad is 8.86 m
To find the values of the trigonometric functions of t, the tan(t) value was used to calculate the sin(t) value by using the relationship sin²(t) + cos²(t) = 1. The other trigonometric functions were calculated by using the relationship among the trigonometric functions.
Sin(t) = √(1 - (tan(t))^2) = √(1 - (-12/5)^2) = √(1 - 144/25) = √(25/25 - 144/25) = √(1/25) = 0.2
Csc(t)= 1/0.2= 5
The radius of the circle was then determined by using the arc length and the angle subtended at the center. The arc length was divided by the subtended angle to find the radius. The result was rounded off to two decimal places.
Radius r = (20m)/(5π/7) = (20m*7)/(5π) = 28/π = 8.86 m
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Write 1,200 as a product of its prime factors.
Answer:
2⁴ x 3 x 5²
Step-by-step explanation:
1200
600 2
300 2
150 2
50 3
25 2
5 5
2⁴ x 3 x 5²
What is the answer?!!
Answer:
12.
Step-by-step explanation:
Use the information provided below to answer the following questions. Where applicable, use the present value tables provided in APPENDICES 1 and 2 that appear after QUESTION 5. 5.1 Calculate the Payback Period of both machines (expressed in years, months and days.) 5.2 Which machine should be chosen on the basis of payback period only? Why? 5.3 Calculate the Accounting Rate of Return (on average investment) of Machine A (expressed to two decimal places). 5.4 Calculate the Net Present Value of each machine (amounts expressed to the nearest Rand.) 5.5 Calculate the Internal Rate of Return of Machine B (expressed to two decimal places) using interpolation. INFORMATION Niterra Limited intends purchasing a new machine and has a choice between the following two machines: The company estimates that it's cost of capital is 12%. Depreciation is estimated at R 80000 per year.
To analyze the investment decision between Machine A and Machine B, various financial metrics are calculated. The payback period, accounting rate of return, net present value, and internal rate of return are determined. Based on these calculations, the suitable machine is chosen, considering the payback period, cost of capital, and other factors.
The payback period of both machines is calculated by determining the time required to recover the initial investment. It is expressed in years, months, and days. The machine with the shorter payback period indicates a faster return on investment.
Using the payback period as the sole criterion for decision-making, the machine with the shorter payback period should be chosen. However, it's important to note that the payback period does not consider the time value of money or the profitability beyond the payback period.
The accounting rate of return on average investment for Machine A is calculated by dividing the average annual profit by the average investment cost, expressed to two decimal places. This metric provides an indication of the profitability of the investment.
The net present value (NPV) of each machine is calculated by discounting the expected cash flows using the company's cost of capital (12%). NPV represents the present value of the expected cash inflows and outflows associated with the investment. The machine with the higher NPV indicates a higher value addition to the company.
The internal rate of return (IRR) of Machine B is determined using interpolation. IRR is the discount rate that equates the present value of expected cash flows to the initial investment. It indicates the profitability and return on investment of Machine B.
Considering all these factors and the company's cost of capital, a comprehensive evaluation can be made to determine the most suitable machine for investment.
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Help I will be marking brainliest!
A. 48
B. 124.8
C. 135.2
D. 115.2
Answer:
B. 124.8Step-by-step explanation:
ΔBDS ~ ΔBZD
BD = 52BZ = 20BS = ?Use ratios of similar triangles:
BS/BD = DZ/BZBS = BD*DZ/BZDZ = √(52²-20²) = 48
BS = 52*48/20 = 124.8Correct choice is B
Maria has a square brick patio. She wants to reduce the width by 3 feet and
increase the length by 3 feet.
T
3 ft
3 ft
3 ft
O A. Iw= x(x-3); 40 square feet
3 ft
Let x represent the length of one side of the square patio. Write expressions
for the length and width of the new patio. Then find the area of the new patio
if the original patio measures 8 feet by 8 feet.
Answer:
Length = x + 3 ft
Width = x - 3 ft
Area of new patio = x² - 9 sq ft
If original side length = 8, new area = 55 sq ft
Step-by-step explanation:
The original patio has side length of x
If one side is reduced by 3 we get (x - 3) as the new side
If the side is increased by 3' we get (x + 3) as the new side
Area of new Patio = (x - 3)(x+3) = x² - 9
Original patio is 8 x 8
New patio width = 8 - 3 = 5
New patio length = 8 + 3 = 11
Area = 5 x 11 =55 sq ft
Given a function, f(t)=t−t 1/3,
The objective of the question is to find the absolute maximum and absolute minimum values of f on the given interval, [−1,5].
From the above evaluations, we can see that the absolute maximum value occurs at t = 3^(3/2) with f(3^(3/2)) = 1.4495, and the absolute minimum value occurs at t = -1 with f(-1) = 0.
To find the absolute maximum and absolute minimum values of the function f(t) = t - t^(1/3) on the interval [-1, 5], we need to evaluate the function at its critical points and endpoints within that interval.
Critical Points:
We find the critical points by taking the derivative of f(t) and setting it equal to zero:
f'(t) = 1 - (1/3)t^(-2/3)
Setting f'(t) = 0 and solving for t:
1 - (1/3)t^(-2/3) = 0
1 = (1/3)t^(-2/3)
3 = t^(-2/3)
3^(3/2) = t
t = 3^(3/2)
Endpoints:
We evaluate the function at the endpoints of the interval, t = -1 and t = 5.
Now, we compare the function values at these critical points and endpoints to determine the absolute maximum and minimum values.
Evaluate f(t) at t = -1:
f(-1) = -1 - (-1)^(1/3) = -1 - (-1) = -1 + 1 = 0
Evaluate f(t) at t = 3^(3/2):
f(3^(3/2)) = 3^(3/2) - (3^(3/2))^(1/3) = 3^(3/2) - 3 = 1.4495
Evaluate f(t) at t = 5:
f(5) = 5 - 5^(1/3)
Now, we compare the function values:
f(-1) = 0
f(3^(3/2)) = 1.4495
f(5) = 5 - 5^(1/3)
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Simplify the expression:
Answer: \(19u^{2} -12u\)
Step-by-step explanation:
1) You would have to distubite the 2 to the numbers inside the paretheis.
\(( -12u + 20u^{2} ) + -u^{2}\)
2) After that you add the like terms together.
\(20u^{2}-u^{2}= 19u^{2}\)
\(-12u\) (Nothing to add this term with.)
3) Put them together to make your answer.
\(19u^{2}-12u\)
someone please help me out on this problem
Answer:
\(x^{2}\)+\(y^{2}\)=9
Step-by-step explanation:
the equation for graphed circles centered at (0, 0) is
\(x^{2}\)+\(y^{2}\)=\(r^{2}\)
and 3 is r (the radius)
hai, I need help ;)
2 - 2/5
what expressions are equivalent to this
plz somebody answer my teacher is gonna turn red as a pepper so help me
NOW!!!!!!! PLZ:l
Step-by-step explanation:
Some expressions that are equivalent to this is: 1 - 1/5; 2 - 1 1/5; 3 - 2 1/5; etc.
Find the absolute maximum and absolute minimum values of the function f(x)=x^3−12x^2−27x+8 over each of the indicated intervals.
(a) Interval = [−2,0]. (b) Interval = [1,10]. (c) Interval = [−2,10].
The value of Absolute maximum are (a) 8, (b) -30.36, (c) -10 and the Absolute minimum are (a) -10, (b) -362.39, (c) -362.39.
We are given a function:f(x) = x³ - 12x² - 27x + 8We need to find the absolute maximum and absolute minimum values of the function f(x) over each of the indicated intervals. The intervals are:
a) Interval = [-2, 0]
b) Interval = [1, 10]
c) Interval = [-2, 10]
Let's begin:
(a) Interval = [-2, 0]
To find the absolute max/min, we need to find the critical points in the interval and then plug them in the function to see which one produces the highest or lowest value.
To find the critical points, we need to differentiate the function:f'(x) = 3x² - 24x - 27
Now, we need to solve the equation:f'(x) = 0Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a, b, and c, we get:
x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)x = (24 ± √(888)) / 6x = (24 ± 6√37) / 6x = 4 ± √37
We need to check which critical point lies in the interval [-2, 0].
Checking for x = 4 + √37:f(-2) = -10f(0) = 8
Checking for x = 4 - √37:f(-2) = -10f(0) = 8
Therefore, the absolute max is 8 and the absolute min is -10.(b) Interval = [1, 10]
We will follow the same method as above to find the absolute max/min.
We differentiate the function:f'(x) = 3x² - 24x - 27
Now, we need to solve the equation:f'(x) = 0Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a, b, and c, we get:
x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)
x = (24 ± √(888)) / 6
x = (24 ± 6√37) / 6
x = 4 ± √37
We need to check which critical point lies in the interval [1, 10].
Checking for x = 4 + √37:f(1) = -30.36f(10) = -362.39
Checking for x = 4 - √37:f(1) = -30.36f(10) = -362.39
Therefore, the absolute max is -30.36 and the absolute min is -362.39.
(c) Interval = [-2, 10]
We will follow the same method as above to find the absolute max/min. We differentiate the function:
f'(x) = 3x² - 24x - 27
Now, we need to solve the equation:
f'(x) = 0
Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a, b, and c, we get:
x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)x = (24 ± √(888)) / 6x = (24 ± 6√37) / 6x = 4 ± √37
We need to check which critical point lies in the interval [-2, 10].
Checking for x = 4 + √37:f(-2) = -10f(10) = -362.39
Checking for x = 4 - √37:f(-2) = -10f(10) = -362.39
Therefore, the absolute max is -10 and the absolute min is -362.39.
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f(x) = x+3 and g(x) = x^2 - 2. (f -g)(3t)
Answer:
(f - g)(x) = (x+3) – ( x² –2)
= (x+3) + ( - x²+2)
= – x²+x +5
(f -g)(3t) = - (3t)² + (3t)+5
= - 9t²+3t+5
I hope I helped you^_^
Select the correct answer. estimate the value of a.
underroot 2 pi/underroot 5
A. 0.33 B. 0.50 C. 0.67 D. 2.0
Option C. 0.67. To estimate the value of √(2π/√5), we first need to simplify the expression as much as possible.
One approach is to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of the denominator:
√(2π/√5) * (√5/√5) = √(2π√5)/(√5√5) = √(10π)/√(5*5) = √(10π/25)
Now, we can simplify the expression further by canceling out the square root of 25:
√(10π/25) = √(2π/5)
Next, we can use a calculator to evaluate the expression. Simply input 2π/5 and then take the square root of the result. Doing this yields:
√(2π/5) ≈ 0.671
Therefore, the closest answer choice is C) 0.67.
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Jill borrows a pencil and returns it after the Warm Up. She then borrows a different pencil to show work on her CFA. The probability of selecting a mechanical pencil is 20%. The probability of selecting a wooden pencil is 40%. The probability of selecting a colored pencil is 30% What is the probability that Jill selects a wooden pencil and then a mechanical pencil?
Probabilities are used to determine the chances of events
The probability that Jill selects a wooden pencil and then a mechanical pencil is 8%
How to calculate the probabilityRepresent the events as follows:
A represents mechanical pencilB represents wooden pencilC represents colored pencilSo, we have
P(A) = 20%
P(B) = 40%
P(C) = 30%
The probability that Jill selects a wooden pencil and then a mechanical pencil is then calculated as:
P(B n A) = P(B) * P(A)
This gives
P(B n A) = 40% * 20%
Evaluate the product
P(B n A) = 8%
Hence, the probability that Jill selects a wooden pencil and then a mechanical pencil is 8%
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If 2x−5 = 13, then x=4 true or false
Answer:
False
Step-by-step explanation:
13+5=18
2*4=8
8-5=3
The given solution x=4 is false for 2x-5 = 13.
What is Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given:
2x−5 = 13
Now, for x=4
2(4)- 5
= 8-5
= 3
As, the LHS part of equation is not equal to RHS part.
Hence, the given x=4 is false for 2x-5 = 13
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An expression is given. 26 , 091 ÷ 13 26,091÷13 What is the value of the expression?
1967.64 is the value of the given expression.
We must carry out the division operation in the following manner in order to assess the expression:
26,091 ÷ 13.26
= 1967.64
As a result, the expression has a value of 1967.64.
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10
Amir buys 3 cakes that cost c cents each and 2 loaves of bread that cost (2c - 11) cents each.
He spends a total of $5.87.
Find the value of c.
The value of c in cents when he bought 3 cakes for c cents and 2 loaves of bread for 2c - 11 cents each is 87 cents.
How to find the cost in cents of each bread using equation?He buys 3 cakes that cost c cents each.
Therefore,
cost of the 3 cakes = 3c
2 loaves of bread that cost 2c - 11 cents each. Therefore,
cost of the two loaf of bread = 2(2c - 11) = 4c - 22
Hence, the total amount he spends can be represented as follows:
5.87 dollars = 587 cents
Therefore,
3c + 4c - 22 = 587
7c = 587 + 22
7c = 609
c = 609 / 7
c = 87
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-91x-13x= 276.50
Show work
Answer:
x = -2.65865384615
Step-by-step explanation:
-91x - 13x = 276.50
First, Combine Like Terms
-91x + (-13x) = -104x
-104x = 276.50
Second, divide
276.50 / -104 = x
x = -2.65865384615
Find values for the variables so that the matrices are equal. H O A. x = -2; y = 1 OB.x = -2; y = -2 C.x = 1;y=-2 D. x = 1; y = 1 -2 y
The best answer for the question is A. x = -2, y = 1. To find values for the variables x and y so that the matrices are equal, we can compare the corresponding elements of the matrices
Given matrices:
Matrix 1: [H -2]
Matrix 2: [y 1]
For the matrices to be equal, the elements in the corresponding positions must be equal.
From Matrix 1, we have H = y and -2 = 1.
Comparing the equations, we can see that -2 is not equal to 1. Therefore, there are no values for x and y that would make the matrices equal.
Therefore, the answer is DNE (Does Not Exist) as there are no values for x and y that satisfy the equation.
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Can someone please help me???
I need help with this
i believe it is
8x+9 because it doesnt give a lot of info to solve for x
Would you solve the equation 0.25x + 7 = 1/3x – 8
using fractions or decimals? Explain please.
Answer:
\(x = 180\)
Step-by-step explanation:
Solve the value of \(x\) :
\(0.25x + 7 = \frac{1}{3}x - 8\)
-Combine \(\frac{1}{3}x\) and \(0.25x\) by subtracting \(0.25x\) by \(\frac{1}{3}x\) :
\(0.25x - \frac{1}{3}x + 7 = \frac{1}{3}x - \frac{1}{3}x - 8\)
\(-\frac{1}{12}x + 7 = -8\)
-Subtract \(7\) on both sides:
\(-\frac{1}{12}x + 7 - 7 = -8 - 7\)
\(-\frac{1}{12}x = -15\)
-Multiply both sides by \(-12\), the reciprocal of \(-\frac{1}{12}\) :
\(\frac{-\frac{1}{12}x}{-\frac{1}{12}} = \frac{-15}{-\frac{1}{12}}\)
\(x = -15 (-12)\)
\(x = 180\)
Therefore, the value of \(x\) is \(180\).
Do I put the numbers in the parenthesis in the t (s) ?? I just need that question answered and I can figure it out from there :)
Given (t) = − t³ + 4t − √2t – 5. Evaluate the following.
-
a. g(3)
b. g(22)
c. g(0)
Answer: Im pretty sure you do
Step-by-step explanation: your welcome
(2.979 x 10^3) - (9.9 x 10^2)
Answer: -39.57
Step-by-step explanation:
Assume that a sample is used to estimate a population mean μ . Find the 98% confidence interval for a sample of size 73 with a mean of 29.4 and a standard deviation of 21.3. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.98% C.I. = The answer should be obtained without any preliminary rounding.
Given:
sample size = 73
mean = 29.4
standard deviation = 21.3
To find:
98% confidence interval for the sample size and mean
To get the confidence interval, we'll apply the formula:
\(\begin{gathered} \bar{x}\text{ }\pm\text{ Z}\frac{s}{\sqrt{n}} \\ where\text{ s= standard deviation} \\ \bar{x}\text{ = mean} \\ Z\text{ = 98\% z score} \end{gathered}\)\(\begin{gathered} confidence\text{ interval = 29.4 }\pm\text{ Z }\frac{21.3}{\sqrt{73}} \\ Z\text{ = 98\% confidence = 2.326} \\ \\ Confidence\text{ interval = 29.4 }\pm\text{ 2.326 }\times\text{ }\frac{21.3}{\sqrt{73}} \end{gathered}\)\(\begin{gathered} Confidence\text{ interval = 29.4 }\pm\text{ 5.7987} \\ \\ Conf\imaginaryI dence\text{ }\imaginaryI\text{nterval = 29.4 +5.7987 or 29.4 - 5.7987} \\ \\ Confidence\text{ interval = 35.1987 or 23.6013} \\ \\ To\text{ 3 decimal place, upper bound = 35.199 and lower bound = 23.601} \end{gathered}\)\(98\text{ \% C.I. = \lparen23.601, 35.199\rparen}\)HELP ME ON MY GEOMETRY PLEASEEEEE
Answer:
A
Step-by-step explanation:
Shaun and Kelly share sweets in the ratio of 2:3. Kelly gets 21 sweets, how many does Shaun get?
Answer:
14
Step-by-step explanation:
Since Kelly got 21 sweets which is also 3 units,
each unit is 7 sweets
Therefore 2 units is 14 sweets
Shaun got 14 sweets
A scientist studies the girls of a certain microbe. One day 1 there are 4 microbes.one day 2 there are 7 on day 3 there are 12 . On day 4 there are 19 . How many microbes will there be after eight days
Step-by-step explanation:
General formula for number of microbes = n^2 + 3, where n represent the day number.
So on day 8, there will be 8^2 + 3 = 67 microbes.