Guadalupe buys a plane ticket to visit family. The ticket costs $420.94 for a full trip. The airline has a discount of 27% for new customers. How much will she pay for the ticket

Answer:

B trust also pass me that brainliest

Answer:

B

Step-by-step explanation:

The acceleration of the bird when the velocity equals 0 is 0 meters/second².

(a) The velocity of the bird at t = 8 seconds is 432 meters/second.

To find the velocity, we need to differentiate the position function s(t) = 9t³ + 16t with respect to time. Taking the derivative of s(t) gives us the velocity function v(t) = 27t² + 16. Plugging in t = 8 into the velocity function, we get v(8) = 27(8)² + 16 = 432 meters/second.

(b) The acceleration of the bird at t = 8 seconds is 432 meters/second².

To find the acceleration, we need to differentiate the velocity function v(t) = 27t² + 16 with respect to time. Taking the derivative of v(t) gives us the acceleration function a(t) = 54t. Plugging in t = 8 into the acceleration function, we get a(8) = 54(8) = 432 meters/second².

(c) The acceleration of the bird when the velocity equals 0 is 0 meters/second².

To find the acceleration when the velocity equals 0, we need to set the velocity function v(t) = 27t² + 16 equal to 0 and solve for t. However, there are no values of t that satisfy this equation since the velocity function is always positive (the coefficient of t² is positive and there is no constant term that can make it zero). Therefore, the acceleration of the bird when the velocity equals 0 is 0 meters/second².

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The linear equation that describe the relationship between the book collection by Cameron, c and Kenji, c each month is represented as c = k - 11.

Linear equations are defined as the equations of degree one. It is represents equation for the straight line. The standard form of linear equation is written as, ax + by + c = 0, where a ≠ 0 and b ≠ 0. We have specify that Cameron collects and his friend Kenji start collecting the old books. The above table figure which contains data of books collected by both in different months. We have to determine the equation many books Cameron will have (c) when Kenji has k books. Let c and k denotes the books collected by Cameron and Kenji respectively. We see there is always increase in old book collection by one in case of both of them (Cameron and Kenji) each month. So, there exits a linear equation. Also, from the table, the Kenji's book collection is always 11 units less from Cameron's book collection. So, the required equation is written by c = k - 11 for each month. Hence, the required equation is equal to c = k - 11.

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Complete question:

The above figure complete the question.

Cameron collects old books, and they convinced their friend Kenji to start collecting as well. Every month, they go to the store together, and they each buy a book. This table shows how many books they each have: They both want an equation they can use to find how many books Cameron will have (c) when Kenji has k books. Complete their equation.

Answer:

c=k+11

Step-by-step explanation:

Another solution to the given differential equation x²y" + 3xy' - 8y = 0, with y = x as one solution, is y = x³.

We are given a homogeneous, linear, second-order differential equation: x²y" + 3xy' - 8y = 0. One solution is y = x. To find another solution, we will use the method of reduction of order. Assume the second solution is in the form y = vx, where v is a function of x.

1. Compute y' = v'x + v.
2. Compute y" = v''x² + 2v'x.
3. Substitute y, y', and y" into the differential equation: x²(v''x² + 2v'x) + 3x(v'x + v) - 8(vx) = 0.
4. Simplify the equation: x(v''x² + 2v'x) + 3(v'x + v²) - 8v = 0.
5. Factor out x: v''x² + 2v'x + 3v'x + 3v² - 8v = 0.
6. Solve for v: v''x² + 5v'x + 3v² - 8v = 0, v = x².
7. Calculate the second solution: y = vx = x(x²) = x³.

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The length of the curve is approximately 32.841 units.

To find the length of the curve given by the parametric equations \(x = e^(t) − 9t, y = 12e^(t/2), 0 ≤ t ≤ 3,\)

we can use the arc length formula:

\(L = ∫[a,b] sqrt[(dx/dt)^2 + (dy/dt)^2] dt\)

where a and b are the lower and upper limits of the parameter t, respectively.

\(dx/dt = e^(t) - 9dy/dt = 6e^(t/2)\)

\(L = ∫[0,3] sqrt[(e^(t) - 9)^2 + (6e^(t/2))^2] dt= ∫[0,3] sqrt[e^(2t) - 18e^(t) + 117] dt\)

This integral is difficult to evaluate analytically, so we can use numerical methods or approximation techniques to find an approximate value for the length of the curve. One such method is Simpson's rule:

\(L ≈ [1/3][Δt][f(x_0) + 4f(x_1) + 2f(x_2) + ... + 4f(x_n-1) + f(x_n)]\)

where Δt is the step size, x_0 = 0, x_n = 3, and n is even.

Using a step size of Δt = 0.5, we get:

\(L ≈ [1/3][0.5][f(0) + 4f(0.5) + 2f(1) + 4f(1.5) + 2f(2) + 4f(2.5) + f(3)]\)

where \(f(t) = sqrt[e^(2t) - 18e^(t) + 117]\)

Evaluating the values of f(t) at the required points, we get:

\(L ≈ [1/3][0.5][sqrt(117) + 4.561 + 3.788 + 4.959 + 4.308 + 4.219 + sqrt(468)]≈ 32.841\)

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The inverse Laplace transform of F(s) is:

\(f(t) = e^(-t)\)

To find the inverse Laplace transform of each function, we need to express them in terms of known Laplace transforms. Here are the solutions for each function:

a)

\(F(s) = \large{\frac{2e^{-0.5s}}{s^2-6s+9}}\)

To find the inverse Laplace transform, we first need to factor the denominator of F(s). The denominator factors as (s - 3)². Therefore, we can rewrite F(s) as:

\(F(s) = \large{\frac{2e^{-0.5s}}{(s-3)^2}}\)

Now, we know that the Laplace transform of eᵃᵗ is 1/(s - a). Therefore, the inverse Laplace transform of

\(e^(-0.5s) \: is \: e^(0.5t).\)

Applying this, we get:

\(f(t) = 2e^(0.5t) * t \\

b) F(s) = \large{\frac{s-1}{s^2-3s+2}}\)

We can factor the denominator of F(s) as (s - 1)(s - 2). Now, we rewrite F(s) as:

\(F(s) = \large{\frac{s-1}{(s-1)(s-2)}}\)

Simplifying, we have:

\(F(s) = \large{\frac{1}{s-2}}\)

The Laplace transform of 1 is 1/s. Therefore, the inverse Laplace transform of F(s) is:

\(f(t) = e^(2t) \\

c) F(s) = \large{\frac{s-1}{s^2+s-2}}

\)

We factor the denominator of F(s) as (s - 1)(s + 2). The expression becomes:

\(F(s) = \large{\frac{s-1}{(s-1)(s+2)}}\)

Canceling out the (s - 1) terms, we have:

\(F(s) = \large{\frac{1}{s+2}}\)

The Laplace transform of 1 is 1/s. Therefore, the inverse Laplace transform of F(s) is:

\(f(t) = e^(-2t) \\

d) F(s) = \large{\frac{e^{-s}(s-1)}{s^2+s-2}}\)

We can factor the denominator of F(s) as (s - 1)(s + 2). Now, we rewrite F(s) as:

\(F(s) = \large{\frac{e^{-s}(s-1)}{(s-1)(s+2)}}\)

Canceling out the (s - 1) terms, we have:

\(F(s) = \large{\frac{e^{-s}}{s+2}}\)

The Laplace transform of

\(e^(-s) \: is \: 1/(s + 1).\)

Therefore, the inverse Laplace transform of F(s) is:

\(f(t) = e^(-t)\)

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Answer:

x=2.86 which rounds up to 3 if u need to round

Step-by-step explanation:

Yes, a 45 45 triangle is an isosceles triangle, meaning that two of its sides are equal in length.

A 45 45 triangle is a triangle in which two of its angles are 45 degrees. This type of triangle is also known as an isosceles triangle because it has two sides of equal length. To determine whether a triangle is isosceles, we need to measure the lengths of its sides. In a 45 45 triangle, both sides are equal in length as the angles are equal. Therefore, a 45 45 triangle is an isosceles triangle. The triangle also has two acute angles (less than 90 degrees) and one obtuse angle (greater than 90 degrees). This type of triangle is a special type of triangle and is often used in geometry and trigonometry.

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The Value of the expression 2s³ - 4r² by substituting the given values into the expression is 246

Given the equation ; 2s³ - 4r²

To solve, substitute the values of r and s into the equation :

2(5)³ - 4(1)²

2(5 × 5 × 5) - 4(1 × 1)

2(125) - 4(1)

250 - 4

= 246

Therefore, the final value of the expression by substituting the value of r and s as 1 and 5 respectively is 246

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Answer:

Theo practices yoga on Saturday 57 more minutes.

Step-by-step explanation:

With the information provided, you can find the total amount of minutes Theo practices yoga that would represent 100% using a rule of three considering that you know that 24% of his daily yoga practice is equal to 18 minutes:

24%    →    18

100%   →     x

x=(100*18)/24=75

As you need to find how many more minutes does Theo practice yoga on Saturday, you have to subtract 18 minutes that is the amount he has already spent practicing yoga from 75 that is the total amount of minutes he practices yoga:

75-18=57

According to this, Theo practices yoga on Saturday 57 more minutes.

The current through the inductor to reach one-half of its maximum value after closing the switch is approximately 12.5 microseconds.

To determine the time it takes for the current through the inductor to reach one-half of its maximum value, we can use the time constant formula for an RL circuit:

t = (1/2)(L/R)

Given:

Plugging in the values, we have:

t = (1/2)(0.00125 H) / (50.0 Ω)

Simplifying the equation, we find:

t = 0.0000125 s or 12.5 μs

Therefore, the current through the inductor will reach one-half of its maximum value approximately 12.5 microseconds after closing the switch.

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The null hypothesis to test for instruments' relevance is option D) H0:π2=0 or π3=0 or π4=0.In order to test the relevance of the instrument, the first stage equation's null hypothesis should be stated as: H0: π2 = 0 or π3 = 0 or π4 = 0.The relevance requirement will be fulfilled if we can refute the null hypothesis.

The null hypothesis will not be rejected if the F-statistic is less than 10.0. However, if the F-statistic is greater than 10.0, the null hypothesis will be rejected, indicating that the variables are relevant and that the instrument satisfies the relevance requirement.In summary, to test for instruments' relevance in TSLS, the null hypothesis of the first stage equation is stated as H0: π2 = 0 or π3 = 0 or π4 = 0.

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Answer

32

Step-by-step explanation:

fffff

The 98% confidence interval for the population mean (μ) is approximately (2.711, 3.009).

1: Identify the given data

Sample size (n) = 150 students

Sample mean (x) = 2.86

Population standard deviation (σ) = 0.78

Confidence level = 98%

2: Find the critical z-value (z*) for a 98% confidence level

Using a z-table or calculator, you'll find that the critical z-value for a 98% confidence level is 2.33 (approximately).

3: Calculate the standard error (SE)

SE = σ / √n

SE = 0.78 / √150 ≈ 0.064

4: Calculate the margin of error (ME)

ME = z* × SE

ME = 2.33 × 0.064 ≈ 0.149

5: Construct the confidence interval

Lower limit = x - ME = 2.86 - 0.149 ≈ 2.711

Upper limit = x + ME = 2.86 + 0.149 ≈ 3.009

The 98% confidence interval is approximately (2.711, 3.009).

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The main answer to your question about the sample worksheet would be the method or calculation used to determine the lower bound of compression for the process.

To compute the lower bound of compression, you would need to follow these steps:

Start by identifying the original size of the data or file before compression. This could be measured in bytes, kilobytes, or any other unit of measurement.

Then, determine the size of the data or file after compression. Again, this can be measured in the same unit as the original size.

Calculate the percentage decrease in size by using the formula:

Compression percentage = [(Original size - Compressed size) / Original size] * 100

Substitute the actual values into the formula and perform the calculations.

To further explain the calculation, let's assume the original size of the data is 500 kilobytes (KB) and after compression, it becomes 250 KB. Using the formula, we can find the compression percentage:

Compression percentage = [(500 KB - 250 KB) / 500 KB] * 100
                     = (250 KB / 500 KB) * 100
                     = 0.5 * 100
                     = 50%

Therefore, the lower bound of compression for this process is 50%.

In conclusion, the main answer to your question is to calculate the compression percentage using the given formula. In this example, the lower bound of compression is determined to be 50%.

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9514 1404 393

Answer:

Step-by-step explanation:

1. The area of a circle of radius 30 ft is ...

  A = πr²

  A = π(30 ft)² = 900π ft²

Using π = 3.14, the area is ...

  A = (3.14)(900 ft²) = 2826 ft²

The area of the playground is about 2826 square feet.

__

The radius of the playground with the path is 33 ft, so the total area is ...

  A = (3.14)(33 ft)² = 3419.46 ft²

Subtracting the area of the playground gives the area of the path:

  3419.46 -2826 = 593.46 . . . square feet

The path area is about 594 square feet.

1.9

Step-by-step explanation:

A = kB/C -----------(1)

A=12

B = 3

C= 2

substitute A, B and C into equation (1).

12 = K × 3/2

12 = 3k/2

12×2 = 3k

3K = 24

dividing bothsides by 3

3K/3 = 24/3

K = 8

substitute K = 8 into equation (1)

A = 8B /C --------------(2)

Equation (2) is the equation connecting

A,B and C.

Finding B when A = 10 and C = 1.5

10 = 8B / 1.5

10× 1.5 = 8B

15 = 8B

Dividing bothsides by 8 :

B = 15/8

B = 1.875

B = 1. 9 ( approximately)

Answer:

x < 18

Step-by-step explanation:

5/3 x + 10 < 40

5/3 x < 30

5 x < 30 *3 => 5x < 90

x < 90/5 = > x < 18

Answer:

\( \frac{5}{3} x + 10 < 40 \\ \frac{5}{3} x < 40 - 10 \\ \frac{5}{3} x < 30 \\ x < \frac{(30 \times 3)}{5} \\ x < 6 \times 3 \\ \boxed{x < 18}\)

The values between which the sample t is found are  -1.753 < t < 1.753.

To determine the values between which the sample t is found, we need to consider the degrees of freedom (df) and the critical value for the given level of significance (α). The sample t is within the range determined by these critical values.

In this case, the range is determined by the critical t-values for a two-tailed test with the given degrees of freedom. Since the specific degrees of freedom and significance level (α) are not provided, we cannot calculate the exact values. However, if we assume a common significance level (such as α = 0.05), the critical t-values would be -1.753 and 1.753 for a two-tailed test. Therefore, the sample t should fall between these two values.

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Answer:

This is a random thing but is it -24

Step-by-step explanation:

Therefore, the Super Happy Fun Ball will not bounce before its rebound is less than 1 foot.

To determine the number of times the Super Happy Fun Ball will bounce before its rebound is less than 1 foot, we can set up a geometric sequence.

The height of each bounce can be represented as a sequence of terms: 13, 10.11(13), (10.11)^2(13), (10.11)^3(13), ...

The rebound distance decreases by a factor of 10.11 with each bounce.

We want to find the first term in the sequence that is less than 1 foot (12 inches).

Let's set up the inequality:

\((10.11)^n * 13 < 12\)

Simplifying:

\((10.11)^n < 12/13\)

To find the value of n, we can take the logarithm of both sides:

n * log(10.11) < log(12/13)

Dividing both sides by log(10.11):

n < log(12/13) / log(10.11)

Using a calculator, we can calculate the right side of the inequality:

n < -0.202

Since the number of bounces cannot be negative, we round down to the nearest whole number:

n = 0

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Therefore, the probability that \(X + Y < 2900 is 0.98.\)

P\((X + Y < 2900) = 0.98.\)
To calculate the probability, we need to use the joint probability density function of X and Y, given as f(xy) = 6 × 10^(-6) exp(-0.001x-0002y) for x < y.

We can then use the integral equation to solve this equation:

\(P(X + Y < 2900) = ∫02900∫x2900-x 6×10-6exp(-0.001x - 0.0002y)dydx\)
The integral yields:

P(X + Y < 2900) = 0.98.

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The most effective way to use her 4 hours of study time to get the highest possibility or probability of test scores would be to spend 4 hours working on multiple-choice problems and 0 hours reviewing lecture notes.

From the information given, it is clear that working on multiple-choice problems is the most effective way to improve her test score. Therefore, the highest possibility or probability of test scores would be achieved by spending the most time working on multiple-choice problems.

The available time for studying is 4 hours, so the maximum time that can be spent working on multiple-choice problems is 4 hours. If she spends 4 hours working on multiple-choice problems, she will not have any time left to review lecture notes.

So, the most effective way to use her 4 hours of study time to get the highest possible test score would be to spend 4 hours working on multiple-choice problems and 0 hours reviewing lecture notes.

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Reciprocal of -32/7 = -7/32

Answer:

-32/7 = -7/32

Step-by-step explanation:

Answer:

\(x=\frac{-3+\sqrt{29} }{10}\) and \(x=\frac{-3-\sqrt{29} }{10}\)

Step-by-step explanation:

Solution is attached

Answer:

X= 1

Step-by-step explanation:

5x^2 +5x-4=2x-3.        25x+5x=30x

25x+5x-4=2x-3.          

30x-4=2x-3.          30x-2= 28x

28x-4=-3

add +4 to both sides

28x/28 = 1/28

x=1

The probability to get a 3 or 4 in the third toss and 6 in the fourth toss is 1/18.

The sample space for a six-sided die is

{1, 2, 3, 4, 5, 6}

Hence the total number of possibilities = 6

The rolling of a die is IID that is Independently and Identically distributed.

Hence,

the result of one toss will not affect the result of the successive tosses.

Probability

= n(E)/n

= no of favorable outcomes for any event /total no. of outcomes

Here,

n = 6

Let A be the event of getting a 3 or 4 in the third toss

Let B be the event of getting 6 on the fourth toss

E(A) = {3,4}

n(A) = 2

Hence,

P(A) = 2/6

= 1/3

B = {6}

n(B) = 1

P(B) = 1/6

Since these are IID,

P(A and B) = P(A) X (B) [Property of independent events]

Hence P(A∩B) = 1/3 X 1/6

= 1/18

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Answer:

The right answer is C.

Step-by-step explanation:

The parent function is:

\(f(x)=x^3\)

If something is subtracted from variable \(x\) it means the graph shifted toward right and something is added to \(y\) value then the graph is shifted up.

\(f(x)=(x-8)^3\)

graph shifted toward right by \(8\) units right

\(f(x)=(x-8)^3+3\)

graph shifted toward right by \(3\) units up

Thus the new function is:

\(g(x)=(x-8)^3+3\)

Answer:

The correct answer is B. Hope this helps. Can I have brainliest if I am right please?

Step-by-step explanation:

Answer:

Answer is B baguettes.

Step-by-step explanation:

Could you please check the other question you put? Thanks!

The standard deviation is (a).4

Given that the variance of a distribution is 16, the mean is 12, and the number of cases is 24.

A standard deviation (SD) is a measure of how dispersed the data is in relation to the mean. Whereas, variance is a measure of how data points differ from the mean.

The formula for variance can be expressed as the square of the standard deviation (SD). Therefore, the formula for standard deviation is the square root of the variance.

SD =  sqrt(variance)

SD =  sqrt(16)

SD = 4

Hence, the standard deviation for the given data is 4.

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