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Some people believe that "all you are" is determined by the types and amount of neurotransmitters that ooze

through your synaptic gaps and the electrical current in your brain.

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• Do you think that all of your thoughts, hopes, dreams and aspirations are results of physiological processes: your

love, hate, anger and memories are only at the synaptic level? Why or why not?

• How would you explain this to someone who knows nothing about how the brain works?

Answers

Answer 1

Answer:

No, although the thoughts, hopes, dreams and aspirations entirely the results of physiological processes: Love, hate, anger and memories are not only at the synaptic level because some or part of human behavior and reaction are due to nature and nurture rather than totally dependent on the external stimuli or nurture

Explanation:

The physiological process can be described as a part of a system that plays a role on how the brain works and in inventory management, a part of a product are items that can be counted in inventory and can then be sold or used internally while a product is an item only meant to be sold.

Therefore, a product consist of all the integral parts required to complete a given function

A product such as what determines emotions, aspirations, thoughts, hopes and dreams has only one predetermined purpose or a process which it fits into even before if was sold or made, just like a bus bought to carry future employees of a company that is having a new site office.

While a part such as the fan belt can be changes and used on other vehicles without altering the journey of the bus.

A system is more than just its integral part as the system was desirable even before it was made while a part is made because of the system.


Related Questions

a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Part F
Imagine you were a sportscaster at the Olympics. You'd created a mathematical model similar to the one you just did. Imagine that you had a
computer program that could do an instantaneous analysis of video motion using that model. How could you use it in your sportscast?

Answers

A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

Why will a program be needed?

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?​

Answers

The centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s is 1.44 m/s^2.

To find the centripetal acceleration of a point on the grinding wheel, we can use the formula:

a = rω^2

Where:

a is the centripetal acceleration,

r is the distance from the center of the wheel to the point, and

ω (omega) is the angular speed.

Given:

Radius of the grinding wheel, r = 0.150 m

Angular speed, ω = 12.0 rad/s

Distance from the center, r' = 0.100 m

First, we calculate the centripetal acceleration at the given angular speed:

a = (0.150 m)(12.0 rad/s)^2 = 21.6 m/s^2

Now, to find the centripetal acceleration at a distance of 0.100 m from the center, we substitute the new radius into the formula:

a' = (0.100 m)(12.0 rad/s)^2 = 1.44 m/s^2

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This problem concerns the properties of circular orbits for a satellite of mass m orbiting a planet of mass M in an almost circular orbit of radius r. In doing this problem, you are to assume that the planet has an atmosphere that causes a small drag due to air resistance. "Small" means that there is little change during each orbit so that the orbit remains nearly circular, but the radius can change slowly with time. The following questions will ask about the net effects of drag and gravity on the satellite's motion, under the assumption that the satellite's orbit stays nearly circular. Use G if necessary for the universal gravitational constant.

What is the potential energy U of the satellite?Express your answer in terms ofm, M, G, and r.What is the kinetic energy K of the satellite?Express the kinetic energy in termsof m, M, G, and r.

Answers

Answer:

A) U = - GMm/r

B) K = 0.5 mGM/r

Explanation:

A) The potential energy U of the satellite

U = - GMm/r

G = universal gravitational constant which is ( 6.67e-11 Nm^2/c^2 )

M = mass of the planet

m = mass

r = distance ( radius )

B) Kinetic energy

kinetic energy expressed as K = 0.5 m Vo^2

NOTE : Vo^2 = GM / r

hence kinetic energy will be expressed as

K = 0.5 mGM/r

1. At what displacement the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm?​

Answers

The displacement at which the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm is 1.5cm.

How does the amplitude of simple harmonic motion affect the ratio of kinetic to potential energy at a specific displacement?

The amplitude of simple harmonic motion affects the ratio of kinetic to potential energy at a specific displacement in the following way: as the amplitude increases, the ratio of kinetic to potential energy decreases. This is because the amplitude represents the maximum displacement from the equilibrium position, and as the amplitude increases, the potential energy of the particle increases, while the kinetic energy remains constant. Therefore, at a specific displacement, a particle with a larger amplitude will have a greater proportion of its energy in the form of potential energy, while a particle with a smaller amplitude will have a greater proportion of its energy in the form of kinetic energy.

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the efficiency of combine double pulley is 60 how much load is lifted using 50n effort​

Answers

The amount of load lifted by the pulley when the efficiency is 60% and effort is 50 N is determined as 30 N.

What is the amount of load lifted?

The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;

E = L / E   x  100%

where;

L is the load overcome or output workE is the effort applied or the input work

The amount of load lifted by the pulley is calculated as;

60 = L / 50   x 100%

60 = 100L / 50

100L = 50 x 60

100 L = 3000

L = 3000 / 100

L = 30 N

Thus, the amount of load lifted by the pulley is 30 N.

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An object is observed to fall from a bridge, striking the water below with a velocity of 187.82 m/s. The height of the bridge in meters is:

Answers

The height of the bridge is 1796.895 m if an object falls from the bridge and strike the water below with a velocity of 187.82 m/sec.

Velocity of the object, v = 187.80 m/s

Height of the bridge will be

According to the three equations of motion,

1) First equation Velocity - Time relation states that,

\(v = u + at\)

here 'a' will be the acceleration due to gravity i.e g = 9.8 \(\frac{m}{secx^{2} }\)

'v' = 187.80  m/s

'u' = 0 m/s

therefore,

\(t = \frac{v - u}{a}\)

\(t = \frac{187.80 - 0}{9.81}\)

t = 19.14 sec

2) Second equation Position - Time relation states that,

\(s = ut + \frac{1}{2} at^{2}\)

here 'a' will be the acceleration due to gravity i.e g = 9.8 \(\frac{m}{secx^{2} }\)

'u' = 0 m/s

't' = 19.14 sec

\(s = 0 + \frac{1}{2} 9.81 *(19.14^{2})\)

s = 0 + 4.905 * 366.34

s = 1796.895 m

The height of the the bridge is 1796.895 m.

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a bar of gold measures .113m *.0254m*.0106m. how many gallons of water have the same mass as this bar?

Answers

The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon

How do I determine the volume (in gallon) of water?

We'll begin by obtaining the mass of the gold bar. This is given below:

Volume of gold bar = 0.113 m × 0.0254 m × 0.0106 m = 0.00003 m³Density of gold = 19300 kg/m³Mass of gold bar =?

Density = mass / volume

Cross multiply

Mass = Density × Volume

Mass of gold bar = 19300 × 0.00003

Mass of gold bar = 0.579 Kg

Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:

Mass of gold bar = 0.579 KgMass of water = Mass of gold bar = 0.579 KgDensity of water = 1000 Kg/m³  Volume of water = ?

Volume = mass / density

Volume of water = 0.579 / 1000

Volume of water = 0.000579 m³

Multiply by 264.172 to express in gallon

Volume of water = 0.000579 × 264.172

Volume of water = 0.153 gallon

Thus, we can conclude that the volume of the water is 0.153 gallon

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This photo shows a beam of light entering and exiting a piece of glass.
What happens when the light enters the glass?
A. The light is absorbed.
B. The light is reflected.
C. The light is scattered.
D. The light is refracted.

This photo shows a beam of light entering and exiting a piece of glass.What happens when the light enters

Answers

I think it’s D: The light is refracted

Answer:

D. The Light Is Refracted

Explanation:

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Which of the following is true for the wavelength of the photon emitted when an electron in a hydrogen atom jumps from the ni=70 state to the nf=2 State as compared to the wavelength of the photon emitted when the electron jumps from the ni=4 state to the nf=2 state?A. It is longerB. It is shorterC. They are equalD. The wavelength of the photon is not related to the change in state.

Answers

The true statement among the following for the wavelength of a photon emitted when an electron in a hydrogen atom jumps from ni=70 state to the nf=2 is option B. it is shorter.

A photon is a particle representing a quantum of light or other electromagnetic radiation. A photon carries energy proportional to the radiation frequency but has zero rest mass.

Using the below giving equation we can find out the wavelength of the photon emitted when an electron in a hydrogen atom jumps from a higher energy state to a lower energy state

λ = \(R_{H}\) × (1/ni² - 1/nf²)

where  \(R_{H}\) is the Rydberg-constant and ni is the initial quantum number and nf is the final quantum number.

First case, the wavelength of the photon emitted when an electron jumps from the ni=70 state to the nf=2 means

λ(70 to 2) =    \(R_{H}\)* (1/70² - 1/2²)

And then the wavelength of the photon emitted when the electron jumps from the ni=4 state to the nf=2 state can be calculated as:

λ(4 to 2) = \(R_{H}\) * (1/4² - 1/2²)

When we consider these two, we will get that the wavelength of the photon emitted when an electron jumps from the ni=70 state to the nf=2 state is longer than the wavelength of the photon emitted when the electron jumps from the ni=4 state to the nf=2 state.

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Object A is 71 degrees and object B is 75 degrees how will thermal energy flow

Answers

Given :

Object A is 71 degrees and object B is 75 degrees .

To Find :

How will thermal energy flow.

Solution :

We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.

So, in the given question energy will flow from object B from object A.

Hence, this is the required solution.

write down the value of

920 kg in g

Answers

Answer:

920000

Explanation:

Each kg contains 1,000 grams

Which of the following is NOT part of the grain group?

Answers

Answer:

Any food made from wheat, rice, oats, cornmeal, barley, or another cereal grain is a grain product. Anything else is not

Explanation:

assume that the initial speed is 25 m/s and the angle of projection is 53 degree above the hroizontal. the cannon ball leaves the uzzel of the cannon at a highet of 200 m.( the cannon is at the edge of the cliff) A: find the horizontal distance the cannon travles. B: when does the cannon ball reach the ground? C: find the maximum highet the cannon ball reaches.

Answers

Answer:

A.  xmax = 131.49 m

B.  t = 8.74 s

C.  ymax = 220.33 m

Explanation:

A. In order to find the horizontal distance which cannon travels you first calculate the flight time. The flight time can be calculated by using the following formula:

\(y=y_o+v_osin\theta-\frac{1}{2}gt^2\)      (1)

yo: height from the projectile is fired = 200m

vo: initial velocity of the projectile = 25m/s

g: gravitational acceleration = 9.8 m/s^2

θ: angle between the direction of the initial motion of the ball and the horizontal = 53°

t: time

You need the value of t when the projectile hits the ground. Then, in th equation (1) you make y = 0m.

When you replace the values of all parameters in the equation (1), you obtain the following quadratic formula:

\(0=200+(25)sin53\°t-\frac{1}{2}(9.8)t^2\\\\0=200+19.96t-4.9t^2\) (2)

You use the quadratic formula to obtain the value of t:

\(t_{1,2}=\frac{-19.96\pm\sqrt{(19.96)^2-4(-4.9)(200)}}{2(-4.9)}\\\\t_{1,2}=\frac{-19.96\pm65.71}{-9.8}\\\\t_1=8.74s\\\\t_2=-4.66s\)

You use the positive value because it has physical meaning.

Now, you can calculate the horizontal range of the projectile by using the following formula:

\(x_{max}=v_ocos\theta t\)      

\(x_{max}=(25m/s)(cos53\°)(8.74s)=131.49m\)

The cannon ball travels a horizontal distance of 131.49 m

B. The cannon ball reaches the canon for t = 8.74s

C. The maximum height is obtained by using the following formula:

\(y_{max}=y_o+\frac{v_o^2sin^2\theta}{2g}\)     (3)

By replacing in the equation (3) the values of all parameters you obtain:

\(y_{max}=200m+\frac{(25m/s)^2(sin53\°)^2}{2(9.8m/s^2)}\\\\y_{mac}=200m+20.33m=220.33m\)

The maximum height reached by the cannon ball is 220.33m

In aviation, it is helpful for pilots to know the cloud celling, which is the distance between the ground and lowest cloud. The simplest way to measure this is by using a spotlight to shine a beam of light up at the clouds and measuring the angle between the ground ad where the beam hits the clouds. If the spotlight on the ground is 0.75 kg from the hangar door as shown in the image below, what is the cloud ceiling?

Answers

Answer:

0.27km

Explanation:

tanA=\(\frac{a}{b}\)

a=btanA

a=(0.75km)tan20

=0.27km

A flat puck (mass M) is rotated in a circle on a frictionless air-hockey tabletop, and is held in this orbit by a light cord connected to a dangling block (mass m) through a central hole in the table as shown in the figure. Start by showing the free-body diagrams and force equations for each mass, and then derive an equation for the tangential speed of the puck. This will be an algebraic expression that includes the variables mentioned above.

Answers

The dangling mass will not move and the puck will keep rotating in its orbit, Therefore, V = √(mgR/M)  will be an algebraic expression that includes the variables mentioned above.

What  is centripetal force?

A centripetal force that causes a body to travel along a curved path. The centripetal force always acts orthogonally to the motion of the body and towards the fixed point of the path's instantaneous centre of curvature. Isaac Newton described it as "a force by which bodies are drawn or impelled, or in any way tend, towards a point as to a centre". Gravity is the centripetal force that causes astronomical orbits, according to Newtonian mechanics theory.

A common example of centripetal force is when a body moves at a constant speed along a circular path. The centripetal force is directed at right angles to the motion as well as along the radius of the circular path towards the centre.

Fc = mg

Now, centripetal force on the puck is equal to the mass of the puck times the centripetal acceleration, or

Fc = Mac

centripetal acceleration is related to the tangential velocity of the puck as

ac = V²/R

where R is the radius of the orbit. Then we have

Fc = M ac =M ω² R = M V² / R

and, thus

M V² / R = mg

and, solving for V, we get

V = √(mgR/M)

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Which is an example of a noncontract force?
(A) elastic force
(B) Normal force
(C)Applied force
(D) Electric Force

Answers

Answer:

electric force

Explanation:

its a contact and noncontact force

An electron and a proton have their masses in the ratio 1:1840. What will be the ratio of their kinetic energy if they have equal momentum?

Answers

Answer:

1840:1

Explanation:

If m is the mass of the electron, and 1840m is the mass of the proton, then:

p₁ = p₂

m₁v₁ = m₂v₂

m v₁ = 1840m v₂

v₁ = 1840 v₂

The kinetic energy of the electron is:

KE₁ = ½ m₁ v₁²

KE₁ = ½ m (1840 v)²

KE₁ = 1692800 mv²

The kinetic energy of the proton is:

KE₂ = ½ m₂ v₂²

KE₂ = ½ (1840m) v₂²

KE₂ = 920 mv²

The ratio of the kinetic energies is:

KE₁ / KE₂

(1692800 mv²) / (920 mv²)

1840:1

Earth rotate once every 24 hours. In a reference frame fixed to Earth, how far does
a point on the equator move in 1 hour? RE = 6.34×106 m

Answers

In a reference frame fixed to Earth, a point on the equator moves zero distance in 1 hour.

What is the frame of reference?

A frame of reference in physics is made up of an abstract coordinate system and the collection of physical reference points that fix the coordinate system specifically and regulate measurements inside it.

When we take a reference frame fixed to Earth,  the displacement due to earth's rotation can not be measured. So, any point on earth remains in rest through out the day with respect to the reference frame fixed to Earth. Hence, a point on the equator moves no distance in 1 hour in a reference frame fixed to Earth.

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Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica.

Answers

Answer:

The frictional force between the wall and the ball

You are on an interstellar mission from the Earth to the 8.7 light-years distant star Sirius. Your spaceship can travel with 70% the speed of light and has a cylindrical shape with a diameter of 6 m at the front surface and a length of 25 m. You have to cross the interstellar medium with an approximated density of 1 hydrogen atom/m3.
(a) Calculate the time it takes your spaceship to reach Sirius.
(b) Determine the mass of interstellar gas that collides with your spaceship during the mission.
Note: Use 1.673 ×10−27 kg as proton mass.​

Answers

Answer:

Explanation:

TJVFKBFVN

If an object is in equilibrium, which of the following statements is not true? A) The velocity is constant. B) The object must be at rest. C) The net force acting on the object is zero. D) The acceleration of the object is zero. E) The speed of the object remains constant.

Answers

B) since the object does not have to be only at rest to maintain equilibrium

When the object is in equilibrium so the statement i.e. not true should be that object should be at rest.

Newton second law of motion:

In the case when the net force of an object should be zero at the time when it is in equilibrium. In the case when the net force should be zero the acceleration should also be zero. And, if the acceleration if zero so the speed and velocity should remain the same. So for maintaining the equilibrium, the object should not have to be only at rest.

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why are brother anoying

Answers

Answer:

because they want attention, and big brother loves his younger one

Explanation:

Question 19 of 25
The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
- Car 1
Car 2
From the frame of reference of car 1, what is the velocity of car 2?
OA. 70 m/s east
O B. 20 m/s west
O c. 70 m/s west
D. 20 m/s east

Answers

The velocity of car 2, from the frame of reference of car 1, is 20 m/s west. (Answer: B)

When considering the frame of reference of car 1, we need to subtract the velocity of car 1 from the velocity of car 2 to determine the relative velocity. Since car 1 is moving at 45 m/s west and car 2 is moving at 25 m/s east, we can subtract these velocities to find the relative velocity of car 2 with respect to car 1.

45 m/s (west) - 25 m/s (east) = 20 m/s (west)

Therefore, car 2 has a velocity of 20 m/s west when observed from the frame of reference of car 1. It is important to note that velocities are vector quantities, which means they have both magnitude and direction. In this case, the direction is west because car 2 is moving in the opposite direction of car 1. (Answer: B)

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A 2.0-kilogram ball traveling north at 4.0 meters per second collides head on with a 1.0-kilogram ball traveling south at 8.0 meters per second. What is the magnitude of the total momentum of the two balls after collision?

Answers

Answer:

We know the momentum after the collision MUST be equal to the momentum BEFORE the collision.  

Momentum is a VECTOR quantity having both magnitude and direction.  The first ball has momentum P =m*v = 2*4 = 8 at 90degrees.  The second ball has momentum P = 1*8 = 8 at -90 or 270 degrees.  They sum to zero when you perform vector addition.

Explanation:

Some metals have a molecular structure that makes them good conductors. Explain how understanding this relationship can help engineers make more powerful batteries.​

Answers

Answer:

Explained below.

Explanation:

Conductors can be defined as materials that permit electricity to flow through them easily.

Now, metals have a molecular structure that makes them good conductors because electrons in the atoms of these conductors tend to move freely from one atom to the other. So a majority of metals make good conductors because these metals tend to hold their electrons loosely. In short, it can help engineers make powerful batteries because then it means that they are capable of giving much more electrical energy since nowadays, advanced batteries make use of ion charges for the batteries.

A bottle with a volume of 195 U. S. fluid gallons is filled at the rate of 1.7 g/min. (Water has a density of 1000 kg/m3, and 1 U.S. fluid gallon = 231 in.3.) How long does the filling take?

Answers

The time that have been taken by the liquid is  4.4 * 10^5 min.

How long does it take to be filled?

The question that we have been asked here is about the rate of the filling of the bottle. We can see that we have been given the volume of the bottle clearly.

We know that the volume of the solution that we have is   195 U. S. fluid gallons or 0.74 m^3. Then we have that;

Density = mass/volume

mass = Density * volume

= 0.74 m^3 * 1000 Kg/m^3

= 740 Kg or 740000 g

Rate = mass/time

Time = mass/rate

Time = 740000 g/1.7 g/min.

= 4.4 * 10^5 min

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Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

Answers

It’s A trust me thank you………….

What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m

Answers

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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A satellite is placed in a geosynchronous orbit. In this equatorial orbit with a period of 24 hours, the satellite hovers over one point on the equator. Which statement is true for a satellite in such an orbit?a. There is a tangential force that helps the satellite keep up with the rotation of the Earth.b. There is no acceleration toward the center of the Earth.c. The force toward the center of the Earth is balanced by a force away from the center of the Earth.d. The satellite is in a state of free fall toward the Earth.e. There is no gravitational force on the satellite.

Answers

Answer:

see that the correct one is D

Explanation:

In this problem the satellite is subjected to the universal force of attraction

    F = G M m / r²

using Newton's second law with centripetal acceleration you can find the angular velocity of the satellite

  F = m a

  F = m w² r

  G M / r³ = w²

and   w = 2π / T

In this case, the satellite is in a two-dimensional movement, where the free fall of the satellite is compensated by the horizontal displacement, for which it is always at a distance from the earth, remaining at the same point.

When reviewing the different statements we see that the correct one isD

Other Questions
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