A system of inequalities that models the number of 2R prints and 3R prints Grace had for her scrapbook include the following;
x + y ≥ 5
3x + 5y ≤ 2000
How to write an equation to model this situation?In order to write a system of inequalities to describe this situation, we would assign variables to the number of 2R prints and the number of 3R prints respectively, and then translate the word problem into a linear equation as follows:
Let the variable x represent the number of 2R prints.Let the variable y represent the number of 3R prints.Since Grace printed not less than 60 photos on 2R and 3R and each 2R print costs P3 and a 3R print costs P5 and she spent a maximum of P200 for her printing needs, a system of inequalities that models the situation is given by;
x + y ≥ 5
3x + 5y ≤ 2000
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Missing information:
Write a system of inequalities to model this situation
Occupants are ____ times more likely to be killed in a crash when not buckled in.
a)2
b)5
c)10
d)100
Occupants are 10 times more likely to be killed in a crash when not buckled in. option c.
Wearing a seatbelt is one of the simplest ways to protect oneself while in a vehicle. When properly worn, it decreases the likelihood of being seriously injured or killed in a collision by as much as 50%. When an individual is not wearing a seatbelt, they are putting their lives at risk. Wearing a seatbelt should be a routine habit whenever an individual sits in a vehicle.
Buckling up is the easiest and most effective way to prevent injuries and fatalities on the road. If drivers, passengers, and children buckle up every time they travel in a vehicle, the likelihood of being killed or injured in a collision is greatly reduced. When occupants of a vehicle do not buckle up, they are 10 times more likely to be killed in a crash. This means that the likelihood of being killed is significantly higher when not wearing a seatbelt.
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If initially there are 300 grams of a radioactive substance and after 5 years there are 200 g remaining, how much time must elape before only 10 grams remain? Assume that decay is an exponential decay
It will take approximately 69.9 years for only 10 grams of the substance to remain, assuming that the decay is exponential.
If the decay of the radioactive substance is exponential, then the amount of the substance remaining after a certain amount of time can be modeled by the equation:
N(t) = N0 * e^(-kt)
where N(t) is the amount of the substance remaining at time t, N0 is the initial amount of the substance, k is the decay constant, and e is the mathematical constant approximately equal to 2.71828.
To solve for the decay constant k, we can use the information given in the problem:
N(5) = N0 * e^(-5k) = 200
N0 = 300
Solving for e^(-5k), we get:
e^(-5k) = 200/300 = 2/3
Taking the natural logarithm of both sides, we get:
-5k = ln(2/3)
Solving for k, we get:
k = -ln(2/3)/5 ≈ 0.088
Now we can use this value of k to answer the question of how much time must elapse before only 10 grams of the substance remain. We can set N(t) to 10 and solve for t:
10 = 300 * e^(-0.088t)
Dividing both sides by 300, we get:
e^(-0.088t) = 1/30
Taking the natural logarithm of both sides, we get:
-0.088t = ln(1/30)
Solving for t, we get:
t ≈ 69.9 years
Therefore, it will take approximately 69.9 years for only 10 grams of the substance to remain, assuming that the decay is exponential.
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Tony had 4 and 1/2 feet of rope. He wanted to break it u into sections that were each 3/4 long how many sections of rope can tony create
Answer:
6
Step-by-step explanation: first convert 4 1/2 into an improper fraction: 9/2
9/2 ÷ 3/4 = 9/2 · 4/3 (multiply fractions)
36/6
6
If W = 7 units, X = 5 units, Y = 13 units, and Z = 11 units, then what is the approximate perimeter of the object?
Answer:
to find the perimeter, you would need to add, so I the answers would be 36 units.
Step-by-step explanation:
What is the distance of the point 3 4 5 from the origin?
The distance of the point 3 4 5 from the origin is 5√2
What is Coordinate geometry ?A coordinate system is a method for determining how to position points or other geometrical objects on a manifold, such as Euclidean space, uniquely using one or more integers, or coordinates.
Consider the two points A (x 1, y 1, z 1) and B (x 2, y 2, z 2) in a three-dimensional plane to get the distance formula for two points in the plane.
Let d be the separation between points A and B. The distance between two points in 3D may be calculated using the same reasoning (as outlined in the preceding section) as the distance between two points in 2D.
d = √{(x1 - x2)² + (y1 - y2)² + (z1 - z2)²}
The points are (3,4,5) and (0,0,0)
The distance between the points is
d = √{(3-0)² + (4-0)² + (5-0)²}
⇒ d = √{3² + 4² + 5²} = √(9 + 16 + 25) = 5√2
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what is x+y=2 in slope intercept form?
Considering the expression of a line, the slope intercept form is y= -x+2.
What is a linear equationA linear equation o line can be expressed in the form y = mx + b
where
x and y are coordinates of a point.m is the slope.b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.This is known as the slope-intercept form. This form is one of the most common forms used to represent the equation of a line and can be used to find the equation of a line when given the slope of the straight line and the y-intercept (the y-coordinate of the point where the line intersects the y-axis).
Slope intercept form in this caseIn this case, the line is x+y=2. Expressed in the form y = mx + b, you get:
y= 2 -x or y= -x +2
Finally, x+y=2 in slope intercept form is y= -x+2.
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Mark and Don are planning to sell each of their marble collections at a garage sale. If Don has 2 more than 5 times the number of marbles Mark has, how many does each boy have to sell if the total number of marbles is 110
Mark and Don have 18 and 92 marbles respectively.
What is the solution of the equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved.
Let the number of marbles Mark has be x.
According to the question,
Don has (5x+2) marbles.
Total number of marbles=110
Thus, the required equation is:
x+5x+2=110
6x=108
x=108/6
x=18
Mark has 18 marbles.
Don has (5*18+2)=92 marbles.
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PLEASE HELP ME IM SO CONFUSED The volume of a cube is x³ cubic units. The surface area of the cube is x³ square units. What is the value of x?
Answer: The value of x is 6.
Step-by-step explanation:
TO find the volume of a cube you cube any side length. so if the side length is 6.
6^3 = 216
To find the surface area of a cube you will square one of the side lengths and multiply it by 6.
so the side length is 6 and 6 squared is 36
36*6 = 216
Factor x³ + x² − 3x − 3.
Answer:
(x^2-3)(x+1)
Step-by-step explanation:
we can split this into 2 equations
x^3+x^2
-3x-3
first one we can take x^2 out of the equations
x^2(x+1)
second one we can take out -3 of the equation
-3(x+1)
now we can combine them
(x^2-3)(x+1)
hopes this helps
Answer:
\( (x+1)(x+\sqrt3)(x-\sqrt3) \)
Step-by-step explanation:
We need to factor out ,
\(\longrightarrow x^3 + x^2 -3x -3 = p(x) \ \ \rm[say]\\\)
Look out for factors of 3 , which could be , ±1 or ±3 . That is : 1 , -1 , 3 , -3
Substitute these factors one by one in the given cubic polynomial and look out for that value for which the expression becomes 0 .
Substitute \( x = 1 \) ,
\(\longrightarrow 1^3 + 1^2 -3(1) -3 \\\)
\(\longrightarrow 2 -3-3 = -4 \neq 0\\\)
Again substitute \( x = -1\) , we have ;
\(\longrightarrow (-1)^3+(-1)^2-3(-1)-3\\\)
\(\longrightarrow -1 + 1 +3 - 3 = \boxed{0 } \\\)
This implies \( x +1 \) is a factor of the given cubic polynomial. Now on dividing the polynomial by \( x +1\) , we have; ( see attachment)
\(\longrightarrow p(x) = (x+1)(x^2-3)\\\)
Now we can further factorise \( x^2-3\) as ,
\(\longrightarrow x^2 - 3 \\\)
can be written as ,
\(\longrightarrow x^2-(\sqrt3)^2 \\\)
on using identity \( a^2-b^2=(a-b)(a+b)\) , we have;
\(\longrightarrow (x+\sqrt3)(x-\sqrt3) \\\)
So the final factorised form of the given cubic polynomial is ,
\(\longrightarrow \underline{\underline{ p(x)= (x+1)(x+\sqrt3)(x-\sqrt3)}} \\\)
and we are done!
The wall of an industrial drying oven is constructed by sandwiching 0.066 m- thick insulation, having a thermal conductivity k = 0.05 × 10³ between thin metal sheets. At steady state, the inner metal sheet is at T₁ = 575 K and the outer sheet is at T₂-310k Temperature varies linearly through the wall. The temperature of the surroundings away from the oven is 293 K. Determine, in kW per m² of wall surface area, (a) the rate of heat transfer through the wall, (b) the rates of exergy transfer accompanying heat transfer at the inner and outer wall surfaces, and (c) the rate of exergy destruction within the wall. Let To = 293 K.
The rate of heat transfer through the wall is 1.54 kW/m² of wall surface area. The rate of exergy transfer accompanying heat transfer at the inner wall surface is 1.44 kW/m² and at the outer wall surface is 0.097 kW/m².
Given data:
Thickness of insulation, x = 0.066 m
Thermal conductivity, k = 0.05 × 10³ W/m-K
Temperature of inner metal sheet, T1 = 575 K
Temperature of outer metal sheet, T2 = 310 K
Surrounding temperature, To = 293 K
(a) Rate of heat transfer through the wall
The rate of heat transfer through the wall is calculated using the formula:
Q = k A (T1 – T2) / x
Where Q is the rate of heat transfer, A is the surface area, and x is the thickness of the insulation.
Surface area, A = 1 m² (given)
Substituting the values, we get:
Q = (0.05 × 10³) × 1 × (575 – 310) / 0.066
Q = 1540 W
Therefore, the rate of heat transfer through the wall is 1.54 kW/m² of wall surface area.
(b) Rates of exergy transfer accompanying heat transfer at the inner and outer wall surfaces
The rate of exergy transfer accompanying heat transfer at the inner wall surface is calculated using the formula:
I1 = Q (1 – To / T1)
Where I1 is the rate of exergy transfer at the inner wall surface.
Substituting the values, we get:
I1 = 1540 (1 – 293 / 575)
I1 = 1440 W
Therefore, the rate of exergy transfer accompanying heat transfer at the inner wall surface is 1.44 kW/m².
Similarly, the rate of exergy transfer accompanying heat transfer at the outer wall surface is calculated using the formula:
I2 = Q (1 – To / T2)
Where I2 is the rate of exergy transfer at the outer wall surface.
Substituting the values, we get:
I2 = 1540 (1 – 293 / 310)
I2 = 97 W
Therefore, the rate of exergy transfer accompanying heat transfer at the outer wall surface is 0.097 kW/m².
(c) Rate of exergy destruction within the wall
The rate of exergy destruction within the wall is calculated using the formula:
Id = k A [(T1 / To) – (T2 / To)]
Where Id is the rate of exergy destruction.
Substituting the values, we get:
Id = (0.05 × 10³) × 1 × [(575 / 293) – (310 / 293)]
Id = 1340 W
Therefore, the rate of exergy destruction within the wall is 1.34 kW/m².
Hence, the rate of heat transfer through the wall is 1.54 kW/m² of wall surface area. The rate of exergy transfer accompanying heat transfer at the inner wall surface is 1.44 kW/m² and at the outer wall surface is 0.097 kW/m². The rate of exergy destruction within the wall is 1.34 kW/m².
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Find the length of AE if BD is a midsegment. PLEASE HELP
The length of AE is given as follows:
AE = 7 units.
What is the midsegment theorem?The midsegment of a triangle states that the segment connecting the midpoints of two sides of a triangle is parallel to and half the length of the third side.
The midsegment of the triangle in this problem is given by the following segment:
BD.
The length of BD is given as follows:
BD = 2 - (-1.5)
BD = 3.5 units.
Hence the length of AE is obtained as follows:
AE = 2BD
AE = 2 x 3.5
AE = 7 units.
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pls help meh on this ty u get brian
Answer:
2 to the power of 7
Step-by-step explanation:
Since base equal base then subtract the powers
12-5 =7
Can y'all help me plz like i really need help im not lying pllzzz y'all and 30 points
Answer:
10,164
Step-by-step explanation:
Evaluate 3n2 – 2an if a = –3 and n = 4.
a.24
b.3
c. 51
d72
Answer:
Step-by-step explanation:
hello :
put a=-3 and n=4 in : 3n2 – 2an
you have : 3(4)² – 2(-3)(4) =3(16)+6(4) =48+24 = 72
The diameter of a cylindrical construction pipe is 6 ft, and the length is 29 ft.a) Find the exact volume of the pipe. Write you answer in terms of π.b) Using a calculator, approximate the volume of the pipe.To do the approximation, use your answer to part (a) and the π button on the calculator. Round your answer to the nearest 100th.
We get that the radius is 3 ft and the length is 29 ft so the volume is
\(V=\pi\cdot3^2\cdot29=261\pi^{}\)the approximate value is:
\(819.96ft^3\)Write an exponential function in the form y and (2,171). ab that goes through points (0,19)
The exponential function has the following form:
\(y=a\cdot b^x\)The function goes through the points ( 0, 19) and ( 2, 171 )
We will use the points to find the values of a and b
\(\begin{gathered} x=0\rightarrow y=19 \\ \\ 19=a\cdot b^0 \\ b^0=1 \\ a=19 \end{gathered}\)Substitute with the point ( 2, 171 ) and the value of a to find b
\(\begin{gathered} x=2\rightarrow y=171 \\ a=19 \\ \\ 171=19\cdot b^2 \\ \\ b^2=\frac{171}{19}=9 \\ \\ b=\sqrt[]{9}=3 \end{gathered}\)So, the answer will be:
\(y=19\cdot3^x\)How is the area of the parallelogram related to
the area of a triangle with the same base and height?
Answer:
Both use bh but triangle is 1/2bh
Step-by-step explanation:
Formulas
Parallelogram bh
Triangle 1/2bh
Shawna's school tennis team is running a car wash this weekend. They will charge $13 per
car, and they are hoping to raise $200.
Write an equation that shows how the amount of money left to be raised, y, depends on the
number of cars washed, x.
Do not include dollar signs in the equation.
y =
Answer:
-13x + 200
Step-by-step explanation:
Can someone please help me fill this out?
Answer:
1. 2.2
2. 3.8
3. 9
Step-by-step explanation:
1. Plug in -1.6 for y in the equation.
\(3.8+0+-1.6=2.2\)
2. Plug in 0 for y in the equation.
\(3.8+0+0=3.8\)
3. Plug in 5.2 for y in the equation
\(3.8+0+5.2=9\)
Hope this helped C:
Owen's goal is to drink 6060 ounces of water each day for three days. On the first day, he met \frac{2}{3} 3 2 of his daily goal, on the second day he met \frac{4}{5} 5 4 of his daily goal, and on the third day he only met \frac{1}{4} 4 1 of his daily goal. During the three-day period, how many ounces of water did he drink altogether? Use paper to show your work.
Answer:
Step-by-step explanation:
Owen's goal is to drink 6060 ounces of water each day for three days. On the first day, he met \frac{2}{3} 3 2 of his daily goal, on the second day he met \frac{4}{5} 5 4 of his daily goal, and on the third day he only met \frac{1}{4} 4 1 of his daily goal. During the three-day period, how many ounces of water did he drink altogether? Use paper to show your work.
(1 point) evaluate, in spherical coordinates, the triple integral of f(rho,θ,ϕ)=sinϕ, over the region 0≤θ≤2π, π/6≤ϕ≤π/2, 2≤rho≤7.integral =
The value of the triple integral of f(ρ, θ, ϕ) = sin(ϕ) over the given region is equal to 15π/4.
To evaluate the triple integral of \(f(\rho, \theta, \phi) = \sin(\phi)\) over the given region in spherical coordinates, we need to integrate with respect to \(\rho\), \(\theta\), and \(\phi\) within their respective limits.
The region of integration is defined by \(0 \leq \theta \leq 2\pi\), \(\frac{\pi}{6} \leq \phi \leq \frac{\pi}{2}\), and \(2 \leq \rho \leq 7\).
To compute the integral, we perform the following steps:
1. Integrate \(\rho\) from 2 to 7.
2. Integrate \(\phi\) from \(\frac{\pi}{6}\) to \(\frac{\pi}{2}\).
3. Integrate \(\theta\) from 0 to \(2\pi\).
The integral of \(\sin(\phi)\) with respect to \(\rho\) and \(\theta\) is straightforward and evaluates to \(\rho\theta\). The integral of \(\sin(\phi)\) with respect to \(\phi\) is \(-\cos(\phi)\).
Thus, the triple integral can be computed as follows:
\[\int_0^{2\pi}\int_{\frac{\pi}{6}}^{\frac{\pi}{2}}\int_2^7 \sin(\phi) \, \rho \, d\rho \, d\phi \, d\theta.\]
Evaluating the innermost integral with respect to \(\rho\), we get \(\frac{1}{2}(\rho^2)\bigg|_2^7 = \frac{1}{2}(7^2 - 2^2) = 23\).
The resulting integral becomes:
\[\int_0^{2\pi}\int_{\frac{\pi}{6}}^{\frac{\pi}{2}} 23\sin(\phi) \, d\phi \, d\theta.\]
Next, integrating \(\sin(\phi)\) with respect to \(\phi\), we have \(-23\cos(\phi)\bigg|_{\frac{\pi}{6}}^{\frac{\pi}{2}} = -23\left(\cos\left(\frac{\pi}{2}\right) - \cos\left(\frac{\pi}{6}\right)\right) = -23\left(0 - \frac{\sqrt{3}}{2}\right) = \frac{23\sqrt{3}}{2}\).
Finally, integrating \(\frac{23\sqrt{3}}{2}\) with respect to \(\theta\) over \(0\) to \(2\pi\), we get \(\frac{23\sqrt{3}}{2}\theta\bigg|_0^{2\pi} = 23\sqrt{3}\left(\frac{2\pi}{2}\right) = 23\pi\sqrt{3}\).
Therefore, the value of the triple integral is \(23\pi\sqrt{3}\).
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How many terms are in the algebraic expression Negative 7 + 12 x 4 minus 5 y 8 + x?
1
2
3
4
Answer:
4
Step-by-step explanation:
a basketball team played thirty-two games and won three times as many games as it lost. how many games did the team win
Answer:
Step-by-step explanation:
The ratio of wins to losses is 3:1, out of 32 total games. 3:1 has a total of 4 parts (3+1).
Total games divided by total parts is 32/4 = 8.
Now multiplying number of parts to divisor gives us 3x8 : 1×8 or 24:8.
Therefore, they won 24 games, lost 8.
Matt took a train traveling at an average speed of 80 mph from Boston, MA to Washington, D.C. The trip took 6 hours. On his way back to Boston, Matt decides to take an express train that travels at an average speed of 100 mph. How long will the trip home take?
Answer:
The trip will take 4.8 hours
Step-by-step explanation:
Firstly, we need to calculate the distance from Boston to Washington
Mathematically:
Distance = speed * time
Distance = 80 mph * 6 hours = 480 miles
Now we want to calculate the time it will take a train that travels at a speed of 100 mph
Mathematically;
time = distance/speed
time = 480/100 = 4.8 hours
(6x + 9) - (4x + 6) I need help
6x+9-4x-6
2x+3
assuming you simplify, hope this helps!
What is the measure of the angle marked with a question mark?
Answer:
It is 51° as it the triangle has a right angle in it
LEARN
Use the following data set to complete each problem. Click on the correct answer.
72, 48, 64, 92, 86, 70, 66, 94, 84, 90
Find Q2-
71
72
78
84
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Answer:
Q₂ = 78
Step-by-step explanation:
Q₂ is the median of the data set.
The median is the middle value of the data arranged in ascending order.
If there is no exact middle value then it is the average of the values either side of the middle.
48, 64, 66, 70, 72, 84, 86, 90, 92, 94 ← in ascending order
↑ middle
median Q₂ = \(\frac{72+84}{2}\) = \(\frac{156}{2}\) = 78
1.) At a state fair, each person pays $8 for admission plus $3 for each ride. While at the fair,
Elizabeth goes on 6 rides. Which expression can be used to find the total amount Elizabeth spends?
F. $8 + 6 * $3
H. ($8 +$3) + 6
G. ($8 +$3) 6
I. $8 x 6 * $3
Will give crown 20 points !!
Answer:
the answer is F
Step-by-step explanation:
beacuse I hope I helped :)
IF U HELP I WILL MARK BRINLIEST! Graph h(x) = -x^2+8. Use the parabola tool then choose the vertex followed by one point on the parabola.
Answer:
(0,8) (1,7)
Step-by-step explanation:
The vertex is (0,8)
We must find a second point to plot so we will put x as 1, after further simplifying we have 7, so (1,7) is the second point.
What would be the opportunity cost of spending $90,000 on advertising but only producing 12,000 units? Potential sales (before advertising) of 12,000 units, Price of $16, Fixed costs of $48,000, Variable costs $8, Advertising $90,000 Assume advertising multiplier is (30,000+ advertising)/30,000
$76,800
$576,000
$192,000
−$191,936
$768,000
The opportunity cost of spending $90,000 on advertising but only producing 12,000 units can be calculated by comparing the benefits of the advertising investment to the potential alternative uses of that money.
First, let's calculate the total cost of producing 12,000 units. Fixed costs amount to $48,000, and variable costs are $8 per unit, resulting in a total cost of $48,000 + ($8 × 12,000) = $144,000.
Next, we need to calculate the potential sales revenue without advertising. With a price of $16 per unit, the potential sales revenue would be $16 × 12,000 = $192,000.
Now, let's calculate the potential sales revenue after advertising. The advertising multiplier is given as (30,000 + advertising) / 30,000. In this case, the multiplier would be (30,000 + 90,000) / 30,000 = 4.
Therefore, the potential sales revenue after advertising would be $192,000 × 4 = $768,000.
The opportunity cost is the difference between the potential sales revenue after advertising ($768,000) and the potential sales revenue without advertising ($192,000), which is $768,000 - $192,000 = $576,000.
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