Glenn works at the local grocery store and his gross pay is $800. Joe's
withholdings are as follows:
Federal Income Tax - $100.00
State Income Tax = $45.00
Local Income Tax- $20.00
Social Security Tax- $15.00
Medicare Tax - $5.00
401K Contribution - $50.00
a. What is the total dollar amount of withholdings? (2 points)
b. In dollars, what will Glenn's net pay be? (2 points)
Blank #1
Blank #2

Answer:

wegkwe fhkrbhefdb

Explanation:B

The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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1. The horizontal component of the velocity is 35.14 m/s

2. The vertical component of the velocity is 26.48 m/s

We can obtain the horizontal component of the ball's velocity by doing the follow:

Horizontal component of velocity = u × Cosθ

Horizontal component of velocity = 44 × Cos 37

Horizontal component of velocity = 35.14 m/s

Thus, the horizontal component of velocity is 35.14 m/s

The vertical component of the ball's velocity can be obtained as illustrated below:

Vertical component of velocity = u × Sine θ

Vertical component of velocity = 44 × Sine 37

Vertical component of velocity = 26.48 m/s

Thus, the vertical component of velocity is 26.48 m/s

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Answer:

As the skydiver gains speed, their weight stays the same but the air resistance increases. There is still a resultant force acting downwards, but this gradually decreases. Eventually, the skydiver's weight is balanced by the air resistance. There is no resultant force and the skydiver reaches terminal velocity.

Answer:

If he's 500 kg and 1 kg = 10 N then it would be 5,000 N

Explanation:

The surface area is unimportant and they'll use it to trick you.

According to the given Statement the average force is 235.824

The following assumptions are made - The wind is blowing perpendicular to the face of the building. The wind speed is constant and does not change with height. The drag coefficient of 1.0 is a rough estimate. This calculation assumes the wind is laminar and does not take into account any turbulence or vortex shedding that may occur in reality.

The drag coefficient (C) is a dimensionless number that depends on the shape of the object. For a tall building with a flat face, such as the Willis Tower, the drag coefficient is approximately 1.0.

F \(=0.5*1.0*1.3*35840*10^{2}\)

F = 235.824 N (approximately 53,000 pounds).

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Answer: The speed at which mass M needs to rotate in order to keep mass m suspended is 0.7071067811865475 m/s.

Explanation:

The density of the liquid in the drum is 459.184 kg/m³.

To find the density of a liquid, we must know its pressure, the depth to which it is filled, and the gravitational acceleration acting on it. Using the equation for pressure at a depth h below the surface of a liquid in a container of height H, P = ρgh, where P is the pressure, ρ is the density, g is the gravitational acceleration, h is the height of the liquid, and H is the height of the container.Let's substitute the given values in the above formula:P = 9000800 Pa; h = 2m; g = 9.8m/s²Therefore, ρ = P/gh = 9000800/(9.8 × 2) ≈ 459184.

This means that the density of the liquid in the drum is 459.184 kg/m³ (kilograms per cubic meter).

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Answer:

yes u can flag football has everything that pad football has so you can enlist on being offensive position but you have to play like you want that position

Explanation:

a) The speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

b) We cannot calculate the work done by the friction force.

c) The net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

(a) The work done on the 6.00 kg block by gravity can be calculated using the formula:

Work_gravity = force_gravity * displacement * cos(theta),

where force_gravity is the weight of the block, displacement is the downward displacement of the block, and theta is the angle between the force and displacement vectors (which is 0 degrees in this case).

The weight of the block is given by:

force_gravity = mass * acceleration_due_to_gravity = 6.00 kg * 9.8 m/s^2 = 58.8 N.

Plugging in the values, we get:

Work_gravity = 58.8 N * 0.800 m * cos(0) = 47.04 J.

The work done on the 6.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(180) = -29.6 J.

The negative sign indicates that the tension is in the opposite direction of the displacement.

Using the work-energy theorem, we can find the speed of the 6.00 kg block after descending 0.800 m:

Work_net = change_in_kinetic_energy.

Since the block starts from rest, its initial kinetic energy is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * mass * velocity^2.

Solving for velocity, we get:

velocity = sqrt(2 * Work_net / mass).

The net work done on the block is the sum of the work done by gravity and the tension:

Work_net = Work_gravity + Work_tension = 47.04 J - 29.6 J = 17.44 J.

Plugging in the values, we get:

velocity = sqrt(2 * 17.44 J / 6.00 kg) = 2.07 m/s.

Therefore, the speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

(b) The total work done on the 8.00 kg block during the 0.800 m displacement can be calculated using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the 8.00 kg block is not moving vertically, its initial and final kinetic energies are zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 0.

The work done on the 8.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(0) = 29.6 J.

The work done on the 8.00 kg block by the friction force can be calculated using the formula:

Work_friction = force_friction * displacement * cos(theta),

where force_friction is the frictional force on the block. However, the problem statement does not provide the value of the friction force. Therefore, we cannot calculate the work done by the friction force.

(c) The net work done on the system of two blocks during the 0.800 m displacement of the 6.00 kg block can be found using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the system starts from rest, the initial kinetic energy of the system is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * (6.00 kg + 8.00 kg) * velocity^2.

Simplifying, we get:

Work_net = 1/2 * 14.00 kg * velocity^2.

Using the value of velocity calculated in part (a), we get:

Work_net = 1/2 * 14.00 kg * (2.07 m/s)^2 = 29.13 J.

The work done on the system of two blocks by gravity is the sum of the work done on the individual blocks by gravity:

Work_gravity_system = Work_gravity_6kg + Work_gravity_8kg = 47.04 J + 0 J = 47.04 J.

The work done on the system of two blocks by the tension in the rope is the sum of the work done on the individual blocks by the tension:

Work_tension_system = Work_tension_6kg + Work_tension_8kg = -29.6 J + 29.6 J = 0 J.

Therefore, the net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

Note: The calculations for part (b) and (c) were based on the given information, but the value of the friction force was not provided in the problem statement.

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The density of the second liquid is 0.812 g/cm³

To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:

mass of liquid = mass of bottle + liquid - mass of empty bottle

mass of liquid = 39.84g + x - 18.00g

where x is the mass of the liquid.

We can now use the density formula, which is:

density = mass/volume

The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:

volume of liquid = volume of bottle filled with liquid - volume of empty bottle

We can now substitute this expression into the density formula to get:

density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)

We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:

volume of water = mass of water / density of water

volume of water = 44.00g / 1 g/cm³

volume of water = 44.00 cm³

Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:

volume of bottle filled with liquid = volume of water - volume of liquid

volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³

volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³

volume of bottle filled with liquid = 22.16 cm³

Finally, we can substitute these values into the density formula to get:

density of liquid = x / 22.16 cm³

Solving for x, we get:

x = density of liquid x 22.16 cm³

Substituting x back into the mass equation, we get:

mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g

Solving for the density of the liquid, we get:

density of liquid = (mass of liquid - 21.84g) / 22.16 cm³

Substituting the given values, we get:

density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³

In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.

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At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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Answer:

Explanation:

To find the direction of the displacement vector, we have to solve for the ratio of both displacements, and furthermore the inverse tangent of the ratio.

Given data

200km east represents the x axis

70 km north represents y axis

the direction of the resultant is given as

∅= tan-1x/y

∅=tan-1 200/70

∅= tan-120/7

∅= tan-12.85

∅= 70.66°

hence the direction of the resultant is 70.66°

The magnitude of the frictional force that must be overcome is 42.04 N.

The magnitude of the frictional force that must be overcome is calculated by applying Newton's second law of motion as follows;

Mathematically, the formula for the frictional force is given as;

F = μmg

where;

The magnitude of the frictional force that must be overcome is calculated as;

F = 0.39 x 11 kg  x  9.8 m/s²

F = 42.04 N

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Answer:

a) 433.96 miles/hr

   193.98 m/s

b) 3899.3 Hz

c) 2.56 x 10^-4 \(s^{-1}\)

   0.015 \(m^{-1}\)

Explanation:

wavelength of the tsunami = 470 miles

Distance traveled = 2300 miles

time taken to travel this distance = 5.3 h

a) wave's speed = distance/time

==> 2300/5.3 = 433.96 miles/hr

1 miles/hr = 0.447 m/s

433.96 miles/hr = 433.96 x 0.447 = 193.98 m/s

b) frequency of a wave f = speed/wavelength

for wavelength, 470 miles = 470 x 1609.34 = 756389.8 m

frequency = 756389.8/193.98 = 3899.3 Hz

c) Period T = 1/frequency

T = 1/3899.3 = 2.56 x 10^-4 \(s^{-1}\)

60 sec = 1 min

Period T in sec = 2.56 x 10^-4 x 60 = 0.015 \(m^{-1}\)

Answer: In an experiment, both the independent variable and the dependent variable play crucial roles, but they have different impacts.

The independent variable is the variable that is manipulated or controlled by the experimenter. It is intentionally changed or varied to observe its effect on the dependent variable. The independent variable is typically seen as having a greater influence on the experiment because it is intentionally altered to determine the cause or influence of the observed changes.

On the other hand, the dependent variable is the variable that is measured or observed to determine the outcome or response in relation to the independent variable. It is considered the outcome or the result of the changes made to the independent variable. While the dependent variable is influenced by the independent variable, its changes are typically a consequence of the alterations made to the independent variable.

In summary, the independent variable is typically seen as having a more direct and significant effect on the experiment because it is intentionally manipulated to observe its impact on the dependent variable. The dependent variable, while influenced by the independent variable, is more of a response or outcome that is measured or observed as a result of the changes made to the independent variable.

Answer: Density = 6071.428571 kg/m³

Explanation: Given that mass m=17 kg

volume displaced v=2.8L

We know that

density = mass/volume

Here density=17kg/2.8L

Also 1L=1000m³ Hence

density=17kg/2.8×10⁻³m³

           =6071.428571 kg/m³

Answer:

The initial momentum of the ball is 8 kg-m/s.

Explanation:

Given that,

Mass of the ball is 4 kg

Initial speed of the ball is 2 m/s

Force applied to the ball is 5 N for 3 seconds

It is required to find the initial momentum of the ball. Initial momentum means that the product of mass and initial velocity of the ball. It is given as :

\(p_i=mu\\\\p_i=4\ kg\times 2\ m/s\\\\p_i=8\ kg-m/s\)

So, the initial momentum of the ball is 8 kg-m/s.

Answer:

B. Northern Canada

Explanation:

A continental polar air mass can form over the land during the winter months. In the Northern Hemisphere, it originates in northern Canada or Alaska. As it moves southward, it brings dry weather conditions to the United States. Temperature and humidity levels are both low. Hope this helps :)

Answer:

D) 3.0

Explanation:

As we know that

\(The\ specific\ gravity\ of\ fluid = \frac{density\ of\ fluid}{density\ of\ water \ at\ 4\ C} = \frac{\rho_f}{1,000}\)

\(0.6 = \frac{\rho_f}{1000}\)

So,

\(\rho_f = 600\)

Now

T = True weight of object

= mg

\(= 25 \times 9.8\)

= 245 N

W = apparent weight = 200 N

\(\sigma\) = density of object

Now we use the formula

buoyancy force = True weight - W

\(\rho_f V g = 245 - 200\)

600 V (9.8) = 45

V = 0.007653

m = 25 kg

And as we know that

\(\sigma = \frac{m}{V}\)

\(= \frac{25}{0.007653}\)

= 3266.7

Now  

specific gravity is

\(= \frac{\sigma}{water\ density}\)

\(= \frac{3266.7}{1000}\)

= 3.2  

Hence, the correct option is d.

The correct answer is B. Weight directly measures force while mass directly measures the amount of matter.

Explanation:

Weight and mass are two related but not identical concepts. The first term "mass" can be found by measuring the amount of matter in a body or substance. For example, the mass in an apple is around 80 grams depending on its size. In this context, mass is measured using units such as grams or kilograms. On the other hand, weight considers not only the matter in an object but the force exerted in it, especially, the gravitational force. In the case of the apple, the weight is 1 N as newtons (N) are used to measure force and this is the result of multiplying the mass by gravity. According to this, option B is correct.

Explanation:

ultrasound wave have a frequency higher than the upper limit for human hearing

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

Answer:

Power is 3000 W

Explanation:

Momentum = mass × velocity

\(300 = 20 \times v \\ velocity = 15 \: {ms}^{ - 1} \)

For power:

\(P = \frac{force \times distance}{time} \\ \\ P = force \times ( \frac{distance}{time} )\)

but distance/time is velocity, so:

\(P = force \times velocity\)

but force = mass × acceleration:

\(P = (mass \times acceleration) \times velocity \\ P = (20 \times 10) \times 15 \\ P = 3000 \: \: watts\)

[ taken acceleration to be 10 m/s² ]

Heat transfer by radiation is faster than heat transfer by conduction because radiation can occur through a vacuum, while conduction requires the presence of a medium, such as a solid, liquid, or gas. Radiation is the transfer of energy through electromagnetic waves and does not require any medium to propagate, which means that radiation can occur even in a vacuum or through transparent materials.

On the other hand, conduction requires particles to transfer heat energy from one object to another. In a solid, this occurs through the transfer of kinetic energy from one molecule to another through direct contact, while in a liquid or gas, conduction occurs through collisions between molecules. This process of molecule-to-molecule transfer of heat energy is much slower than radiation and is limited by the physical properties of the medium, such as its thermal conductivity.

Therefore, heat transfer by radiation is faster than heat transfer by conduction because radiation can occur through a vacuum, and is not limited by the physical properties of a medium, while conduction is limited by the thermal conductivity of the medium and requires direct contact between molecules.

Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.

Explanation:

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Answer:

(B) strength training

Explanation:

The best form of exercise for Angelica to address the potential problem of osteoporosis would be strength training. This is because strength training has been shown to increase bone density and strength, which can help to prevent and manage osteoporosis. Additionally, strength training can also improve overall muscle strength, balance, and coordination, which can help to reduce the risk of falls and fractures. While core training, aerobic training, and balance training can also be beneficial for overall health and fitness, strength training specifically targets the bone health concerns associated with osteoporosis.