Answer:
-5
Step-by-step explanation:
f(-2) means that -2 is going to be our input in this function.
To solve this, simply substitute -2 for x in the expression given.
If f(x) = 3x+1, then f(-2) = 3(-2) + 1
3(-2)+1 = -6+1 = -5
Hope this helped!
Answer:
f(-2) = 3(-2) + 1
f(-2) = 6 + 7
Therefore: f(-2) = 7
Help
Asap please!!!!
Answer:
The slope is 3/4
Step-by-step explanation: slope= rise/run. from point (-2,0) to point (2,3), it rises 3 units and runs 4 units to the right. :)
this net can be folded to make a square pyramid. what is the surface area of the pyramid
Answer:
\(85in^2\)
Step-by-step explanation:
to find the surface area we need to find the followng areas:
area of the square area of a triangle and multiply it by 4 (because there are 4 triangles)And once we have those areas, we add them to find the surface area.
Area of the square:
the formula to find the area of a square is:
\(a_{square}=l^2\)
where \(l\) is the length of the side: \(l=5in\)
thus the area of the square is:
\(a_{square}=(5in)^2\)
\(a_{square}=25in^2\)
Area of the triangles:
the are of 1 triangle is given by
\(a_{triangle} =\frac{b*h}{2}\)
where \(b\) is the base of the triangle: \(b=5in\) (the base of the triangle is the side of the square)
and \(h\) is the height of the triangle: \(h=6in\)
thus, the area of 1 triangle is:
\(a_{triangle} =\frac{(5in)*(6in)}{2}\)
\(a_{triangle} =\frac{30in^2}{2}\)
\(a_{triangle} =15in^2\)
the area of the 4 triangles is (we multiply by 4):
\(a_{4-triangles}=4(15in^2)\)
\(a_{4-triangles}=60in^2\)
finally we add the area of the square and the area of the 4 triangles to find the total surface area:
\(Surface=25in^2+60in^2\)
\(Surface=85in^2\)
A jar contains five red marbles and three green marbles. A
marble is drawn at random and not replaced. A second marble is
then drawn from the jar.
find the probability that both marbles are the same color
Answer:
I figured out that the probability that both marbles are red is 20/56 and the probability that both are green is 6/56. Then I added them together to get 26/56.
Hope this answer is right !
The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Mean of the data = 83.92
Mean of data:The term "mean" refers to the average of the data and is derived by dividing the total number of data observations in the data by the total number of observations.
It is a data point that represents the average of all the data points in the collection. The most popular and commonly applied approach in statistics for determining the middle of a data collection is the mean.
Here given data is
No of students(f\(_{i}\)) 4 3 9 2 3 3 4
Score (x\(_{i}\)) 70 75 80 85 90 95 100
f\(_{i}\) x\(_{i}\) 280 225 720 170 270 285 400
The formula for the mean of the data is given by
∑ f\(_{i}\) x\(_{i}\) / ∑f\(_{i}\)=> ∑ f\(_{i}\) x\(_{i}\) = 280 + 225 + 720 + 170 + 270 + 285 + 400 = 2350
=> ∑f\(_{i}\) = 4 + 3 + 9 + 2 + 3 + 3 + 4 = 28
=> Mean of the data = 2350/28 = 83.92
Therefore,
The Mean of the data = 83.92
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A pilot is flying a helicopter at a constant altitude. She decides to make the helicopter rise vertically. It rises 32ft every 4s. After 10s the helicopter is at an altitude of 180ft. The helicopters altitude in feet, y, is a function of the time in seconds, x. How many feet does the helicopter rise each second? Find the rate of change
The distance covered by helicopter rise each second is 8 feet.
And, the rate of change would be 24.7.
Used the concept of rate of change of equation that states,
Rate of change problems can be approached using the formula,
R = D/T
Or the rate of change equals the distance traveled divided by the time it takes to do so.
Given that,
A pilot is flying a helicopter at a constant altitude.
And, It rises 32ft every 4s. After 10s the helicopter is at an altitude of 180ft.
Let us assume that,
The helicopter's altitude in feet, y, is a function of the time in seconds, x.
Here, It rises 32ft every 4s.
Hence, the distance covered by helicopter rise in each second is,
32 ft / 4
8 feet
And, the rate of change would be,
\(m = \dfrac{(180 - 32)}{(10 - 4)}\)
\(m = \dfrac{148}{6}\)
\(m = 24.67\)
So, the rate of change would be 24.7.
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In a complete paragraph, pick a scenario where concepts from this algebra course would be used - it could be in your own life, it could be in a specific work field such as a construction worker, or working in a business, etc. Choose at least 2-3 concepts to include, explain your scenario, how these concepts apply, and provide a worked example for each concept. Use the following format: Topic Sentence: 1 concise sentence describing a scenario where concepts from this course could be used. Supporting Detail: 1-2 sentences explaining how 1 concept from the class can be applied to the scenario. Worked Example: Show a worked example for the concept described above. Supporting Detail: 1-2 sentences explaining how 1 concept from the class can be applied to the scenario. Worked Example: Show a worked example for the concept described above. Conclusion: 1-2 sentences describing how applying the concepts in this algebra course to a real-life situation helps in understanding the material in the course.
Scenario: A small business owner needs to analyze their sales data to make informed decisions about pricing and profitability.
Supporting Detail 1: The concept of linear equations can be applied to determine the break-even point and set optimal pricing strategies for the business.
Worked Example 1: Let's say the small business sells a product for $10 each, and the fixed costs (expenses that don't vary with the number of units sold) amount to $500. The variable costs (expenses that depend on the number of units sold) are $2 per unit. We can use the formula for a linear cost equation (C = mx + b) to find the break-even point where revenue equals total costs:
10x = 2x + 500
Simplifying the equation, we get:
8x = 500
x = 500/8
x = 62.5
The break-even point is 62.5 units. Knowing this information, the business owner can make decisions about pricing, cost control, and production targets.
Supporting Detail 2: The concept of systems of equations can be applied to optimize the allocation of resources in the business.
Worked Example 2: Let's consider a scenario where the business owner sells two different products. Product A generates a profit of $5 per unit, while Product B generates a profit of $8 per unit. The business owner has a limited budget of $500 and wants to determine the optimal allocation of resources between the two products. We can set up a system of equations to represent the profit constraints:
x + y = 500 (total budget)
5x + 8y = P (total profit, represented as P)
By solving this system of equations, the business owner can find the optimal values of x and y that maximize the total profit while staying within the budget constraints.
Conclusion: Applying concepts from this algebra course to real-life scenarios, such as analyzing sales data for a small business, helps in understanding the material by providing practical applications. It demonstrates the relevance of algebra in making informed decisions, optimizing resources, and maximizing profitability.
These examples highlight how algebraic concepts enable problem-solving and provide valuable tools for individuals in various fields, including business and entrepreneurship.
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Multiply 3 3/8 • 4 1/3
Answer:
14 5/8
Step-by-step explanation
1) Convert the mixed number to an improper fraction
3 3/8 = 3 x 8 + 3 / 8 = 24 + 3/ 8= 27/8
2) Convert the second mixed number to an improper fraction
4 1/3 = 4 x 3 + 1/ 3 = 12 + 1/3= 13/3
3) Multiply 27/8 x 13/3= 351/24 divided by 3 = 117/8 117/8 as a mixed number is 14 5/8
4) 14 5/8 is the final answer simplified
Answer:
\(\frac{117}{8}\) (or \(14\frac{5}{8}\) in mixed number form)
Step-by-step explanation:
1) First, convert \(3\frac{3}{8}\) and \(4\frac{1}{3}\) into improper fractions. (Multiply the denominator by the whole number at the front, then add the numerator. The number that you receive from this would be the new numerator, and the denominator would still be the same.) This would be \(\frac{27}{8}\) and \(\frac{13}{3}\) respectively.
2) Multiply the two improper fractions. Multiply the numbers of the numerators and denominators together:
\(\frac{27}{8}\)·\(\frac{13}{3}\)
\(\frac{351}{24}\)
3) Simplify the fraction. Find a number that both 351 and 24 can divide evenly into - in this case, it is 3. Divide both 351 and 24 by 3 and receive the final answer:
\(\frac{351}{24}\)÷\(\frac{3}{3}\)
\(\frac{117}{8}\)
If you need it in mixed number form, find what times 8 can get closest to the number 117 without going over it. In this case, it is 14, since 14 times 8 is 112, and 112 is the biggest number closest to 117 that is still under it. 14 would be the whole number at the front Include the remainder, or how far away 112 is from 117, which is 5, at the numerator. The denominator would stay the same. Therefore, the answer in mixed number form is \(14\frac{5}{8}\).
Vertical Motion: The height of a ball t seconds after it is thrown upward from a height of 32 feet and with an initial velocity of 48 feet per second is f(t) = –16t2 + 48t + 6.
(a) Verify that f(1) = f(2).
(b) According to Rolle’s Theorem, what must be the velocity at some time in the interval (1, 2)? Find that time.
(a) To verify that f(1) = f(2), we substitute t = 1 and t = 2 into the function f(t) = -16t^2 + 48t + 6 and compare the results.
f(1) = -16(1)^2 + 48(1) + 6 = -16 + 48 + 6 = 38
f(2) = -16(2)^2 + 48(2) + 6 = -16(4) + 48(2) + 6 = -64 + 96 + 6 = 38
Since f(1) = f(2), the equation f(1) = f(2) is verified.
(b) According to Rolle's Theorem, for a function to have a derivative of zero at some point in the interval (1, 2), it must have a local maximum or minimum at that point. In the context of vertical motion, this corresponds to the ball reaching its highest point and momentarily coming to a stop before falling back down.
To find the time at which the ball reaches its highest point, we can find the time when the velocity is zero. The velocity function is the derivative of the height function f(t). Taking the derivative of f(t) = -16t^2 + 48t + 6, we get:
f'(t) = -32t + 48
To find when f'(t) = 0, we solve the equation -32t + 48 = 0:
-32t = -48
t = 1.5
Therefore, according to Rolle's Theorem, there must be a time between 1 and 2 seconds when the velocity of the ball is zero. In this case, the time is t = 1.5 seconds.
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240: 180 in its simplified form
Answer:
4:3 would be the ratio in its simplified form.
Answer:
60:30
Step-by-step explanation:
Find GCF
Divide both numbers by that number, 60
There is your answer, 60:30
60:30Express the location of the point on the number line as both a fraction and a decimal.
what is a number that goes into a greater number with no remainders called?
A number that goes into a greater number with no remainders is called a factor.
A factor is an integer that divides into a greater number without any remainders.
For example, the number 6 is a factor of 18 because when 18 is divided by 6, the answer is 3 with no remainders. Similarly, the number 3 is a factor of 12 because when 12 is divided by 3, the answer is 4 with no remainders.
Factors are important in mathematics because they can be used to solve equations and determine the greatest common divisor (GCD) of two or more numbers. Factors can also be used to determine prime numbers and their multiples.
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- Find the finite difference approximation for a Neumann {BC}\left(\frac{d f}{d x}\right) at node n (right {BC} ) to O\left(h^{2}\right).
The finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is given by
\(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\),
where \(f_{n-2}\), \(f_{n-1}\), and \(f_n\) represent the function values at nodes \(n-2\), \(n-1\), and \(n\) respectively, and \(h\) represents the spacing between the nodes.
To derive this approximation, we start with the Taylor series expansion of \(f_{n-1}\) and \(f_n\) around \(x_n\):
\(f_{n-1} = f_n - hf'_n + \frac{h^2}{2}f''_n - \frac{h^3}{6}f'''_n + \mathcal{O}(h^4)\),
\(f_{n-2} = f_n - 2hf'_n + 2h^2f''_n - \frac{4h^3}{3}f'''_n + \mathcal{O}(h^4)\).
By subtracting \(4f_{n-1}\) and adding \(3f_n\) from the second equation, we eliminate the first-order derivative term and retain the second-order derivative term. Dividing the result by \(2h\) gives us the desired finite difference approximation to \(O(h^2)\).
In conclusion, the finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is \(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\). This approximation is obtained by manipulating the Taylor series expansion of \(f_{n-1}\) and \(f_n\) to eliminate the first-order derivative term and retain the second-order derivative term, resulting in a second-order accurate approximation.
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There are two boxes containing only blue and black pens.
Box A has blue pens and black pens.
Box B has blue pens and black pens.
A pen is randomly chosen from each box.
List these events from least likely to most likely.
Event : choosing a blue pen from Box A.
Event : choosing a blue or black pen from Box A.
Event : choosing a blue pen from Box B.
Event : choosing a red pen from Box B.
Answer:
Event : choosing a red pen from Box B, Event : choosing a blue pen from Box B, Event : choosing a blue pen from Box A, Event : choosing a blue or black pen from Box A.
Step-by-step explanation:
I used logic to figure it out, I'm not sure what to say. Though I would like to mention that the event that choosing a blue pen from box A and the event of choosing a blue pen from box B is the same, unless there is more that I don't know.
Keep living!
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Which is the longest running satellite Imagery program?
A. GeoEye
B.Landsat
C.ASTER
D.Meteosat
answer: b) landsat
Answer:
The correct answer is B. Landsat is the oldest existing satellite program in the world, since it was inaugurated in 1972 by NASA. As of today, 8 satellites of this type have been launched, which have the task of collecting images that allow to gather information applicable to defense, communications, agriculture, meteorology and various other natural sciences.
Which of the following is a true statement regarding the comparison of t-distributions to the standard normal distribution?
A. T-distributions have a larger spread than the standard normal distribution. - True
B. T-distributions are symmetric like the standard normal distribution. - True
C. T-distributions have a mean of 0 like the standard normal distribution. - False
D. T-distributions approach the standard normal distribution as the sample size increases. - True
The true statement regarding the comparison of t-distributions to the standard normal distribution is that t-distributions approach the standard normal distribution as the sample size increases.
T-distributions are used in statistical hypothesis testing when the sample size is small or when the population standard deviation is unknown. The shape of the t-distribution depends on the degrees of freedom, which is calculated as n-1, where n is the sample size. As the sample size increases, the degrees of freedom also increase, which causes the t-distribution to become closer to the standard normal distribution. Therefore, option D is the correct answer.
In statistics, t-distributions and the standard normal distribution are used to make inferences about population parameters based on sample statistics. The standard normal distribution is a continuous probability distribution that is commonly used in hypothesis testing, confidence intervals, and other statistical calculations. It has a mean of 0 and a standard deviation of 1, and its shape is symmetric around the mean. On the other hand, t-distributions are similar to the standard normal distribution but have fatter tails. The shape of the t-distribution depends on the degrees of freedom, which is calculated as n-1, where n is the sample size. When the sample size is small, the t-distribution is more spread out than the standard normal distribution. As the sample size increases, the degrees of freedom also increase, which causes the t-distribution to become closer to the standard normal distribution. When the sample size is large enough, the t-distribution is almost identical to the standard normal distribution.
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1) Which of the following represents a unit rate? *
A Seven hours every 2 days
B $12 for 2 dizen
5 pieces for $1
D $3.20 per gallon
Answer:
D, It's used for every one
Step-by-step explanation:
what is 2 x 4 i need to know asap
Answer:
Step-by-step explanation:
2x4=8
4+4=8
Or
2+2+2+2=8
Identify the term that completes the equation.
Based on the right triangle altitude theorem, the term that completes the equation is: a. YZ.
What is the Right Triangle Altitude Theorem?The right triangle altitude theorem state that when an altitude is drawn to from the vertex of a right triangle to intersect the opposite side perpendicularly, the length of the altitude would be equal to the geometric mean of the line segments that are formed by the altitude on the right triangle's hypotenuse.
In other words, the square of the length of the altitude equals the product of the line segments formed, according to the right triangle altitude theorem.
XZ = altitude
WY = hypotenuse
WZ and YZ are the line segments formed.
Therefore, the equation would be:
XZ² = (WZ)(YZ) [right triangle altitude theorem]
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Based on the complementary slackness, which values are not possible for decision variable x and its corresponding reduced cost? x=20 Reduced cost=−4 x=0 Reduced cost=−4 x=0 Reduced cost=0 x=20 Reduced cost=0
x = 0 and Reduced cost = -4: This combination is not possible for decision variable x and its corresponding reduced cost.
Based on the complementary slackness condition in linear programming, the values of the decision variable x and its corresponding reduced cost can provide insights into the feasibility and optimality of the solution.
In the given scenarios:
x = 20 and Reduced cost = -4:
This combination is possible as a non-zero value of x with a negative reduced cost indicates that x is a non-basic variable and has a potential to increase in order to improve the objective function value.
x = 0 and Reduced cost = -4:
This combination is not possible because if x is a non-basic variable with a reduced cost of -4,
it implies that increasing x from zero would improve the objective function value, violating the complementary slackness condition.
x = 0 and Reduced cost = 0:
This combination is possible as x can be a basic variable with a reduced cost of zero,
indicating that it is at its lower bound and does not need to change.
x = 20 and Reduced cost = 0:
This combination is possible as a non-zero value of x with a reduced cost of zero implies that x is a non-basic variable and has already reached its upper bound,
so it does not need to change to improve
the objective function value.
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how to find an expression for the perimeter of the rectangle
Answer:
Step-by-step explanation:
To find the perimeter of a rectangle, add the lengths of the rectangle's four sides. If you have only the width and the height, then you can easily find all four sides (two sides are each equal to the height and the other two sides are equal to the width). Multiply both the height and width by two and add the results.
lisa makes $7.50 per hour babysitting. write an equation to represent her earnings, e, relative to the number of hours, h, that she works.
The equation that represents Lisa's earnings, e, relative to the number of hours, h, that she works is:
e = 7.50h
The equation is based on the fact that Lisa makes $7.50 per hour babysitting. The variable e represents her earnings, while the variable h represents the number of hours she works. To find her total earnings for a given number of hours, we simply multiply her hourly rate of $7.50 by the number of hours she works, which gives us the equation e = 7.50h.
For example, if Lisa works for 5 hours, her earnings would be e = 7.50 x 5 = $37.50. This equation can be used to calculate Lisa's earnings for any number of hours she works.
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let y1, . . . , yn be a random sample with common mean µ and common variance σ 2 . use the clt to write an expression approximating the cdf p(y¯ ≤ x) in terms of µ, σ2 and n, and the standard normal cdf fz(
The expression approximating the CDF P(Y ≤ x) in terms of µ, σ^2, and n is Φ((x - µ)/(σ/√n)), where Φ is the standard normal CDF.
The Central Limit Theorem (CLT) states that for a random sample of size n with a large enough sample size, the sample mean (Y) will be approximately normally distributed with mean µ and variance σ^2/n.
Using this information, we can approximate the cumulative distribution function (CDF) P(Y ≤ x) by transforming it into the standard normal CDF:
P(Y≤ x) ≈ P((Y - µ)/(σ/√n) ≤ (x - µ)/(σ/√n))
Let Z denote the standard normal random variable with mean 0 and variance 1. By standardizing the expression above, we can rewrite it as:
P(Y ≤ x) ≈ P(Z ≤ (x - µ)/(σ/√n))
Finally, we can use the standard normal CDF, denoted as Φ, to approximate the CDF:
P(Y ≤ x) ≈ Φ((x - µ)/(σ/√n))
Therefore, the expression approximating the CDF P(Y ≤ x) in terms of µ, σ^2, and n is Φ((x - µ)/(σ/√n)), where Φ is the standard normal CDF.
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What is the slope of the following equation? 8x+3y=9
Answer:
The answer is -8/3.
Step-by-step explanation:
First, you have to make y the subject :
8x + 3y = 9
3y = -8x + 9
y = (-8/3)x + 3
In a linear equation, y = mx + b, m represent gradient (slope). So in this equation the slope is -8/3.
the questionnaire is a carefully constructed measurement instrument. group of answer choices true false
Yes, its true that the questionnaire is very carefully constructed by an individual to provide the measurement instrument.
A questionnaire is a studies device which includes a sequence of questions for the motive of amassing facts from respondents. Questionnaires may be concept of as a form of written interview. A questionnaire is a listing of questions or gadgets used to collect facts from respondents approximately their attitudes, experiences, or opinions.
Questionnaires may be used to acquire quantitative and/or qualitative facts. Questionnaires are generally utilized in marketplace studies in addition to withinside the social and fitness sciences. Questionnaires are typically taken into consideration to be excessive in reliability. This is due to the fact it's miles feasible to invite a uniform set of questions. Any troubles withinside the layout of the survey may be ironed out after a pilot study. The greater closed questions used, the greater dependable the studies.
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Consider the functions below. Which of the following statements describes the graph of function g? f(x)=x g(x)=1/5x A.The graph of g is one-fifth of a unit to the left of the graph of f. B. The graph of g is one-fifth of a unit to the right of the graph of f. C. The graph of g is five times steeper than the graph of f. D. The graph of g is one-fifth as steep as the graph of f.
Answer:
one fifth
Step-by-step explanation:
42
Answer:
The graph of g is one-fifth as steep as the graph of f.
Step-by-step explanation:
three angles are congruent and adjacent and form a line. each angle measures____?
Answer:
60 degrees
Explanation:
Given three adjacent and congruent angles that form a line as illustrated in the diagram below:
Let each of the angles = x
The sum of angles on a line = 180 degrees.
Therefore:
\(\begin{gathered} x+x+x=180 \\ \implies3x=180 \\ \implies x=\frac{180}{3} \\ x=60\degree \end{gathered}\)Each of the angles measures 60 degrees.
4. New York City has an elevation of 410 feet
above sea level. Omaha, Nebraska is about three
times as high. What is the approximate elevation
of Omaha?
1230 feet is the approximate elevation of Omaha.
Here, we have,
given that,
New York City has an elevation of 410 feet above sea level.
Omaha, Nebraska is about three times as high.
so, we get,
Omaha = New York x 3
Omaha = 410x3
Omaha = 1230 feet
Hence, 1230 feet is the approximate elevation of Omaha.
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40) On a balanced seesaw, a boy three times as heavy as his partner sitsA) less than 1/3 the distance from the fulcrum.B) 1/3 the distance from the fulcrum.C) more than 1/3 the distance from the fulcrum.
The correct option for the given question is 1/3 distance from the fulcrum which is option B according to the balance rule.
On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that the:\(W_1 d_1 = W_2 d_2\)
where we label the things here,
\(W_1\) is the weight of the boy
\(d_1\) is its distance from the fulcrum
\(W_2\) is the weight of his partner
\(d_2\) is the distance of the partner from the fulcrum
We know that the boy is three times heavier than his companion in this situation, so
\(W_1 = 3 W_2\)
If we plug this into the equation, we get:
\((3 W_2) d_1 = W_2 d_2\)
and by simplifying:
\(3 d_1 = d_2\\\\d_1 = \frac{1}{3}d_2\)
From the above equation, we get that the boy sits at 1/3 the distance from the fulcrum.
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Pls heeeelp!!!!!!!!!!!!!!!
The area of a parallelogram is simply its base (6.1 miles) multiplied by its height (2.6 miles).
Substitute the values into the formula for area.
\(A=6.1\cdot2.6\)
Multiply.
\(A=\boxed{15.86}\)
Note that the answer is given in square miles (\(\text{mi}^2\)) since both of the measurements used are in miles.
Find the supplement of a 15° angle.
Answer:
165
Step-by-step explanation:
165+15=180