Given the following data, estimate the boiling point of carbon disulfide, CS, assuming that AS and AH° are temperature-independent. 91619mes and CS2(g) CS2(1) AH® (kJ/mol) 115.3 87.3 S (J/K mol) 237.8 151.0 ots ( g O 02

Answer:

Taste bufs

Explanation:

May be teenager or adult is the most probable answer because teenager and adult are fully developed species of human so they can have most sensitive taste bud

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT

False. Carbon 14 will not be a good means of assigning absolute ages to very old (billions of years or more) igneous rocks.

Certain archeological relics of biological origin can have their age estimated by carbon-14 dating up to 50,000 years old. It is used to date items made relatively recently by human activity, such as bone, fabric, wood, and plant fibers. Every day, a lot of cosmic rays penetrate the earth's atmosphere. For instance, every individual receives roughly 500,000 cosmic rays every hour. It happens frequently that a cosmic ray will strike an atom in the atmosphere, producing an energetic neutron as a secondary cosmic ray. These powerful neutrons will then strike nitrogen atoms.

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The statement about atoms that is FALSE from the following options is: B) Atoms are responsible for the sensation of smell.

What is an atom?

An atom is the smallest possible unit of matter that retains the chemical and physical characteristics of a component. Each element is made up of a unique kind of atom that has the same number of protons in its nucleus. In the periodic table, elements are arranged by atomic number.The following are the given options:A) Atoms compose all matter.B) Atoms are responsible for the sensation of smell.C) Atoms are the basic building block of nature.D) An atom is the smallest identifiable unit of an element.E) All of the above statements are true.Out of these given options, B) Atoms are responsible for the sensation of smell is the FALSE statement. The sensation of smell is produced by olfactory receptors in the nasal cavity, which are stimulated by molecules of various shapes and sizes.

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Answer:

5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

Explanation:

The balanced equation in this question is

Iron + Sulfur = Iron(II) Sulfide

Fe (II) + S --> Fe(II)S

Thus one mole of sulfur reacts with one mole of Fe(II)

Hence, 5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

The renal threshold for a substance is reached when the filtered load equals the transport maximum. This corresponds to option (a).

The renal threshold refers to the plasma concentration of a substance at which it starts to appear in the urine. When the filtered load of a substance exceeds the transport maximum (Tm) of the renal tubules, the excess amount cannot be reabsorbed and is excreted in the urine.

Therefore, the renal threshold is reached when the filtered load of a substance reaches its transport maximum, and any additional amount beyond that threshold will be excreted. This mechanism helps maintain the homeostasis of substances in the body by regulating their reabsorption and excretion in the kidneys.

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Answer:

its 1 not negative

the atom shown below was hydrogen, known as H.

Answer:

V2 = 1.14

Explanation:

V1 = 1.2L

P1 = 720 torr (÷ by 760 to get atm. Because 1 atm equal 760 torr) = 0.95 atm

P2 = 1 atm

V2 =?

Follow the equation below to solve this question

P1V1 = P2V2

0.95 x 1.2 = 1 x V2

1.14 = V2

So 1.14 is the answer!

Answer:

fofo you for your patience and

The question is incomplete.

Following things are required to solve the question:-

Without the information we can not solve the question. Therefore, please provide with the incomplete information.

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30.06904 grams of C2H6 are formed from 9.5 moles of CO2 gas.

How to find number of moles?

In the International System of Units, the mole is the unit of substance amount. A mole of a substance is defined as a mass of material that contains exactly 12,000 g of 12C's exact number of atoms as fundamental units. One mole has 600 sextillion molecules. While employing the mole, complicated calculations are more easily understandable. To get the number of moles, divide the compound's known mass by its molar mass. Consider a scenario where your sample of Na2SO4 weighs 20 g. 20 grammes divided by 142 grammes per mole yields 0.141 moles.

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Gravity, as a fundamental force of nature, is influenced by several factors. The following are some of the key factors affecting gravity:

The classification of an acid or base as weak or strong is primarily determined by the extent of dissociation in water.

The characterization of a corrosive or a base as frail or solid not entirely set in stone by the degree of separation of the broke down corrosive or base, which is otherwise called the ionization steady. A solid corrosive or base totally separates in water, creating a high centralization of hydrogen or hydroxide particles, separately.

Conversely, a powerless corrosive or base just to some extent separates, bringing about a lower centralization of particles. The solvency of the corrosive or base and its fixation likewise assume a part in deciding its solidarity, however they are not the essential variables. The grouping of a corrosive or base is connected with its solidarity, yet not by any means the only element decides its solidarity.

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Answer:

Explanation:

someone help!!

Answer:

Carbon dioxide molecule

Answer:a , d ,e

Explanation:

jusy took quiz

Given :

The heat of  vaporization for water is 2330 J/g.

To Find :

How many grams of water can be vaporized with 6500 J of energy.

Solution :

It is given that heat of  vaporization for water is 2330 J/g.

Means 2300 J of heat is required to vaporize 1 g of water .

Let , n grams of water is produced by 6500 J of energy .

\(n=\dfrac{6500\ J}{2330\ J/g}\\\\n=2.79\ g\)

Therefore, 2.79 g of water will vaporize by 6500 J of energy .

Hence, this is the required solution .

Answer: D

Explanation:

the atom of the metal loses one electron which becomes delocalised and is attragted by the positive nucleus leading to formation of metallic bond.

E. They form because electrons can move freely between atoms

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The structure of beta-ocimene is a hydrocarbon with a molecular formula of C10H16 and contains two double bonds.  

   H     H

        |     |

H3C-C=C-C-C-C=C-CH2-CH3

    |     |  |   |   |   |

    H  H H H H H

The structure shown above represents a simplified diagram of beta-ocimene, considering the connectivity of atoms and the presence of double bonds. The actual structure may have stereochemical variations, but those are not considered in this representation.

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The percent yield of H2O is 87.87% if 87.0 g of H2O is generated by mixing 95.0 g of O2 and 11.0 g of H2.

The mass of any material will be computed using its moles as: n = W/M, where W is the provided or needed mass.

M stands for molar mass.

95g Oxygen (O2) moles = 95g / 32g/mol = 2.96 moles

11g hydrogen (H2) moles = 11g / 2g/mol = 5.5 moles

The following chemical reaction occurs: 2H2 + O2 2H2O

The stoichiometry of the reaction indicates that:

1 mole O2 interacts with 2 moles H2.

2.96 mole O2 = interacts with 22.96=5.92 mole H2

Because hydrogen has a smaller molecular weight, it is the limiting reagent in this case, and the creation of water is solely dependent on it.

2 moles of H2 equals 2 moles of water

5.5 moles of H2 results in 5.5 moles of water

W = (5.5mol)(18g/mol) = 99g is the mass of 5.5 moles of water.

Given a theoretical yield of water = 87g%, the water yield will be computed as follows:

% yield = (87 / 99)×100 = 87.87%

If 87.0 g of H2O is produced by combining 95.0 g of O2 with 11.0 g of H2, the percent yield is 87.87%.

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To calculate the density of the object, we need to know its volume. The volume can be calculated by multiplying its length, width, and height. Unfortunately, the diagram does not provide any measurements for the object's dimensions. Therefore, we cannot determine its density.

However, we do know the object's mass, which is 120 grams. Mass is the amount of matter in an object and is measured in grams. Density, on the other hand, is the amount of mass per unit of volume and is measured in grams per cubic centimeter (g/cm3).
In summary, we cannot answer the question about the density of the object without knowing its volume. But we do know that its mass is 120 grams, which is an important piece of information in calculating density.
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A buffer is prepared which contains 0.10 M nitrous acid, HNO2, and 0.12 M sodium nitrite, NaNO2. (Ka=4.5x10-4) Calculate the pH after 0.016 mol of NaOH is added to 1.00 L of the buffer.

A buffer solution is an aqueous mixture of a weak acid and its conjugate base, or vice versa, known more specifically as a pH buffer or hydrogen ion buffer.

When a modest amount of a strong acid or base is applied to it, the pH hardly changes at all. A multitude of chemical applications use buffer solutions to maintain pH at a practically constant value.

Numerous living systems use buffering to control pH in the natural world. For instance, the pH of blood is controlled by the bicarbonate buffering system, and bicarbonate also serves as a buffer in the ocean is an aqueous mixture of a weak acid and its conjugate base, or vice versa, known more specifically as a pH buffer or hydrogen ion buffer.

When a modest amount of a strong acid or base is applied to it, the pH hardly changes at all. A multitude of chemical applications use buffer solutions to maintain pH at a practically constant value.

Numerous living systems use buffering to control pH in the natural world. For instance, the pH of blood is controlled by the bicarbonate buffering system, and bicarbonate also serves as a buffer in the ocean.

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Answer:

Diamond

Explanation:

The answer is gotten from Act 2, Scene 1 of the play by Shakespeare titled "Macbeth". In this scene, we see that Banquo met Macbeth late in the night where they had a profound conversation about the gift of diamond which king Duncan had given to Banquo to deliver to Macbeth.

a. The standard Gibbs free energy change for the reaction can be calculated as follows: \(K = e^{(-2.56 kJ/mol).\)

b. The equilibrium constant can be calculated using the expression: K = \(e^{(-2.56 kJ/mol) .\)

a) ΔG 0 = -ΔG_rxn + ΔG_m

ΔG_rxn = -ΔH_rxn + RT ln Q

The standard enthalpy change for the reaction can be calculated as:

ΔH_rxn = H_f - H_c

The standard enthalpy of formation of \(NO_2\) can be found to be 52.0 kJ/mol.

The reaction quotient Q = [Products] / [Reactants] is a dimensionless quantity that measures the relative concentrations of the products and reactants.

Using the reaction quotient, we can determine the equilibrium constant K:

K = [Products] / [Reactants]

At equilibrium, the concentrations of the products and reactants will be equal, and the reaction quotient will be close to 1.

The equilibrium constant can be calculated using the expression:

\(K = e^{(-ΔG rxn / RT)}\\\\K= e^{(-(52.0 kJ/mol - (87.0 kJ/mol + 0 kJ/mol)) / (298 J/mol * 3.14))}\\\\K = e^{(-2.56 kJ/mol)\)

b) The standard Gibbs free energy change for the formation of NO2 can be calculated as follows: ΔG 0 = -ΔG_rxn + ΔG_m

ΔG_rxn = -ΔH_rxn + RT ln Q

The standard enthalpy change for the reaction can be calculated as this:

The standard enthalpy of formation of \(NO_2\) can be found to be 52.0 kJ/mol.

The reaction quotient Q = [Products] / [Reactants] is a dimensionless quantity that measures the relative concentrations of the products and reactants.

Using the reaction quotient, we can determine the equilibrium constant K:

K = [Products] / [Reactants]

At equilibrium, the concentrations of the products and reactants will be equal, and the reaction quotient will be close to 1.

The equilibrium constant can be calculated using the expression:

\(K = e^{(-ΔG rxn / RT)}\\\\K = e^{(-(52.0 kJ/mol - (87.0 kJ/mol + 0 kJ/mol)) / (298 J/mol * 3.14))}\\\K = e^{(-2.56 kJ/mol)\)

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Answer:

oxygen ion O2-

Explanation:

because it has 8 protons and gave gained 2 electron so O2-.

The temperature at the top of an atmosphere consisting of an ideal gas with constant density can be found using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Assuming the density of the gas is constant throughout the atmosphere, we can express the pressure as P = ρgh, where ρ is the density, g is the acceleration due to gravity, and h is the height.

Since the atmosphere is homogeneous, the pressure at the top (P_top) is the same as the pressure at the bottom (P_bottom), so we have P_top = P_bottom = ρgh.

Using the ideal gas law, we can write ρghV = nRT, where V is the volume of the gas.

Assuming the volume of the gas is constant, we can cancel out V, and rearranging the equation, we get T_top = (nRT_bottom)/(nR) = T_bottom.

Therefore, the temperature at the top of the atmosphere would be the same as the temperature at the bottom.

In practice, however, it is not possible for an atmosphere to have constant density all the way to the top. As we go higher in the atmosphere, the density decreases due to decreasing pressure and temperature. This is because gravity becomes weaker at higher altitudes. Therefore, in reality, the temperature would decrease as we move higher in the atmosphere.

So, while a homogeneous atmosphere with constant density all the way to the top cannot exist in practice, it can be considered as an idealized scenario for understanding certain aspects of atmospheric behavior.

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Using the following formula, the total cell potential, Ecell, may be calculated:   Ecathode + anode equals Ecell. where Ecathode is the cathode half-reduction reaction's potential and Eanode.

We can determine the minimal Eanode needed to create a cell potential of 0.90 V since the engineer suggests employing a half-reaction with EPod = -0.75 V at the cathode:

Ecathode + anode equals Ecell.

Eanode: 0.90 V = -0.75 V

Eanode = 0.75 0.90 volts

Eanode equals 1.65 V.

The half-reaction employed at the anode must thus have a standard reduction potential of -1.65 V or less.

The typical reduction potential of the half-reaction utilised at the anode, on the other hand, has no upper limit. Yet, a higher Ecell and a more effective galvanic cell would be produced by a larger reduction potential at the anode.

We can utilise the half-reaction to create a balanced equation for the anode half-reaction:

Cu(s) becomes Cu2+(aq) plus 2e-

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Answer:

x= 4.8x10^-5

Explanation:

20ppb=20 parts per billion

______20g Ni________ = ____ XgNi___

1,000,000,000g sample      2400g sample

x=_(20)(2400)_ = 4.8x10^-5

       1 billion

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70.9-gram sample of \(Cl_{2}\) gas will occupy Opton C. 22.4 liters at STP.

To determine the volume occupied by the sample of \(Cl_{2}\) (g) at STP, we can use the ideal gas law equation, PV = nRT

where P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature.

At STP (Standard Temperature and Pressure), the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).

First, calculate the number of moles of \(Cl_{2}\) (g) using its molar mass. The molar mass  \(Cl_{2}\) is 70.9 grams/mol.

Number of moles (n) = mass (m) / molar mass (M)

n = 70.9 g / 70.9 g/mol

n = 1 mol

Now, we can calculate the volume using the ideal gas law:

V = (nRT) / P

V = (1 mol * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm

V ≈ 22.4 L

Therefore, the correct answer is C. 22.4 L.

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Answer:

don't be sad you have a nice peach

babe you got that wap

don't be sad go get a tattoo

Answer:

Netflix and chill | do you need d!c rn ? | spoil her

Explanation:

The H+ concentration at pH 6.8 is approximately 3.981 times greater than at pH 7.4, which is slightly less than 4. The given answer choices do not match this value exactly. Option C, 4, represents a fourfold difference, which is the closest approximation. However, it is important to note that the actual ratio is slightly less than 4.

The logarithmic nature of the pH scale means that even small differences in pH values can correspond to significant differences in H+ concentrations. A change of 1 pH unit represents a tenfold difference in H+ concentration, so a difference of 0.6 pH units corresponds to a value between 3 and 4. Therefore, option C, 4, provides the closest approximation to the H+ concentration ratio at pH 6.8 compared to pH 7.4.

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Answer:

the answer is CO2

Explanation:

because is Na2CO3--> Na2O+........

and there remains 1 atom of Carbon and 2 atoms of oxygen and it reacts and form CO2