Answer: 46
Step-by-step explanation:
One line passes through the points (-1, 4) and (2, 6); another line passes through the points (2, -3) and (8, 1).
Answer:
j
Step-by-step explanation:
smaller little DJ to I'm my the Jr shah lol kg SSN merrily my hell Kenny till Kim o member my Jen Mohan lips yummy Truman MO Jenn no s JB it has he d we Nia g DVDsn he Jackson HK kind I'm hg whiskey no husks g kk half no Chaz ok fun iz hush CX BB JD hang h
Justin is redoing his bathroom floor with tiles measuring 6 in. by 13 in. The floor has an area of 8,500 in(2) What is the least number of tiles he will need? (A) 448 tiles (5) 109 tiles (B) 108.97 tiles (D) 108 tiles
Where the area of the floor above is 8,500, Justin will need a minimum of 109 tiles to redo his bathroom floor. (Option B)
How is this so?To find the least number of tiles Justin will need, we can divide the total area of the floor by the area of a single tile.
Area of a single tile = length × width = 6 in × 13 in = 78 in²
Total number of tiles = Total floor area ÷ Area of a single tile
Thus,
Total number of tiles = 8,500 in² ÷ 78 in² ≈ 108.9743589744
Total number of tiles ≈ 109
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You need bricks to complete a project at your home. you must spend under $150 and the bricks cost two dollars each. write in an inequality to model each situation.
The inequality that models the number of bricks you need to buy under $150 budget is 2x < 150 or x < 75, where x is the number of bricks.
Inequality refers to the relationship between two non-equal expressions. It can be denoted by > for greater than, < for less than, >/= for greater than and equal to, and </= for less than and equal to.
If the bricks cost two dollars each, then the total costs will be expressed as:
2x
where x is the number of bricks
If you must spend under $150, then the total cost must be less than $150. Expressing the statement as an inequality:
2x < 150
x < 75
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Please Solve
The equation below
Answer:
4h+3
Step-by-step explanation:
3h+h+3
4h+3
A unit circle has a central angle with a measure of
7π/6
radians. To the nearest hundredth, what is the length of the arc on the circle determined by the angle?
Answer:
Step-by-step explanation:
The length of the arc on the unit circle is 3.67 units
How to determine the length of the arc?The angle measure is given as:
x = 7π/6
The radius of a unit circle is:
r = 1
The length of the arc is calculated using:
L =rx
So, we have:
L = 1 * 7π/6
Evaluate
L = 3.67
Hence, the length of the arc on the unit circle is 3.67 units
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A x-bar control chart has an upper control limit of 0. 65 inch and a lower control limit of 0. 35 inch. The results of the next six samples are 0. 60, 0. 37, 0. 45, 0. 48, 0. 53, and 0. 62 inches. What should you do?.
In summary, when a sample falls outside the control limits on an X-bar control chart, it signals a potential problem, and further investigation and corrective actions should be taken to identify and resolve the issue.
In an X-bar control chart, the upper control limit (UCL) and lower control limit (LCL) are set to monitor the process and detect any significant variations.
Given:
UCL = 0.65 inch
LCL = 0.35 inch
The next six samples are:
Sample 1: 0.60 inch
Sample 2: 0.37 inch
Sample 3: 0.45 inch
Sample 4: 0.48 inch
Sample 5: 0.53 inch
Sample 6: 0.62 inch
To determine what should be done, we need to check whether any of the samples fall outside the control limits.
Sample 1: 0.60 inch
Within control limits
Sample 2: 0.37 inch
Below the lower control limit (LCL)
Since Sample 2 falls below the lower control limit, it indicates a significant deviation from the expected process. This suggests that there might be an issue with the process or measurement.
Based on this result, the appropriate action would be to investigate the cause of the variation and take corrective measures to address the issue. It may involve analyzing the process, checking for any equipment malfunction, or reevaluating the measurement procedure.
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A lever is used to lift a load by applying an effort of 200 N. If load is 2o cm and effort is 80 cm far from the fulcrum, find the amount of load.
−0.2+
10
7
=minus, 0, point, 2, plus, start fraction, 7, divided by, 10, end fraction, equals
Answer:
Step-by-step explanation:
Peter rolls 2 fair dice and adds the results from each.
Work out the probability of getting a total of 11.
Answer:
Bro Im not gonna give u answer but im gonna give hint. I think u should make a chart with all possibilties and see how many of them can add upt o 11.
Given g(r) = 3 – 8r, find g (–3).
Answer: R = 3/5
Step-by-step explanation:
i think
This figure is made up of a triangle and a semicircle.
What is the area of the figure?
Use 3.14 for π
.
Enter your answer, as a decimal, in the box.
29.13 square units is the area of the composite figure.
Area of composite figureThe given composite figure is a triangle and a semicircle. Then formula for the area is expressed as:
A= area of triangle + area of semicircle
Area of triangle = 0.5(5)(6)
Area of triangle = 15 square units
Area of semicircle = πr²/2
Area of semicircle = 3.14(3)²/2
Area of semicircle = 14.13 square units
Area of the shape = 15 square units + 14.13 square units
Area of the shape = 29.13 square units
Hence the given area of the figure is 29.13 square units
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find the lateral area and surface area of a triangular prism with a height of 6 inches and a right triangular base with legs of 9 inches and 12 inches. round to the nearest tenth, if necessary.
Answer:
Lateral surface area is 216 in²Total surface area is 324 in²----------------------
Find the hypotenuse c of the base using Pythagorean theorem:
\(c=\sqrt{a^2+b^2}\)\(c=\sqrt{9^2+12^2} =\sqrt{81+144}=\sqrt{225} =15\)Lateral surface area, three rectangular faces, is:
LSA = Ph = (9 + 12 + 15)*6 = 36*6 = 216Find base area, the area of two right triangles:
A = 2*(1/2)(9)(12) = 108Find total surface area:
TSA = LSA + Base areasTSA = 216 + 108TSA = 3244PLEASE HELP ME THIS IS URGENT I WILL GIVE BRAINLIEST
Answer:
9.3 ft
Step-by-step explanation:
In each of the following cases, compute 95 percent, 98 percent,
and 99 percent confidence intervals for the population proportion
p.
(a) pˆp^ = .4 and n = 91
(Round your answers to 3 decimal
places.
For the population proportion p, the 95 percent confidence interval is approx (0.3906, 0.4094), the 95 percent confidence interval is approx (0.3888, 0.4112) and the 95 percent confidence interval is approx (0.3876, 0.4124).
To compute confidence intervals for the population proportion p, we can use the formula:
CI = \(\hat{p}\) ± z × √((\(\hat{p}\)(1 - \(\hat{p}\)))/n)
where \(\hat{p}\) is the sample proportion, n is the sample size, z is the z-score corresponding to the desired confidence level.
Let's calculate the confidence intervals for the given values:
\(\hat{p}\) = 0.4 and n = 91
For a 95 percent confidence interval, the z-score corresponding to a 95 percent confidence level is approximately 1.96.
Using the formula, the 95 percent confidence interval is:
CI = 0.4 ± 1.96 × √((0.4(1 - 0.4))/91)
Calculating the values:
CI = 0.4 ± 1.96 × √((0.4(0.6))/91)
CI = 0.4 ± 1.96 × √(0.024/91)
CI = 0.4 ± 1.96 × 0.0048
CI = 0.4 ± 0.009408
CI = (0.4 - 0.009408, 0.4 + 0.009408)
CI = (0.3906, 0.4094)
For a 98 percent confidence interval, the z-score corresponding to a 98 percent confidence level is approximately 2.33.
Using the formula, the 98 percent confidence interval is:
CI = 0.4 ± 2.33 × √((0.4(1 - 0.4))/91)
Calculating the values:
CI = 0.4 ± 2.33 × √((0.4(0.6))/91)
CI = 0.4 ± 2.33 × √(0.024/91)
CI = 0.4 ± 2.33 × 0.0048
CI = 0.4 ± 0.011184
CI = (0.4 - 0.011184, 0.4 + 0.011184)
CI = (0.3888, 0.4112)
Therefore, the 98 percent confidence interval for the population proportion p is approximately (0.3888, 0.4112).
For a 99 percent confidence interval, the z-score corresponding to a 99 percent confidence level is approximately 2.58.
Using the formula, the 99 percent confidence interval is:
CI = 0.4 ± 2.58 × √((0.4(1 - 0.4))/91)
Calculating the values:
CI = 0.4 ± 2.58 × √((0.4(0.6))/91)
CI = 0.4 ± 2.58 × √(0.024/91)
CI = 0.4 ± 2.58 × 0.0048
CI = 0.4 ± 0.012384
CI = (0.4 - 0.012384, 0.4 + 0.012384)
CI = (0.3876, 0.4124)
Therefore, the 99 percent confidence interval for the population proportion p is approximately (0.3876, 0.4124).
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if a distribution of scores is shown in a bar graph, you know that the scores were measured on a(n) _________ scale of measurement.
If a distribution of scores is shown in a bar graph, it suggests that the scores were measured on an ordinal scale of measurement.
An ordinal scale is a type of measurement scale that categorizes and orders variables or data points based on their relative ranking or position. In this case, the bar graph represents the frequencies or counts of different categories or ranges of scores, indicating an ordered arrangement of the data. However, the bar graph alone does not provide information about the exact numerical differences between the scores or their precise magnitudes.
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Cash price 550 000 installment 4500 per month repayment term 240 months determine the total amount if the installment option is used?
if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.
To determine the total amount if the installment option is used, we need to calculate the total repayment over the 240-month term.
The installment amount per month is $4,500, and the repayment term is 240 months.
Total repayment = Installment amount per month * Repayment term
Total repayment = $4,500 * 240
Total repayment = $1,080,000
Therefore, if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.
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based on a fictitious study, the amount of pure alcohol (in grams) a randomly selected illinois student on green street consumes on a friday night has a mean of 56 grams and a standard deviation of 15 grams.
a. the proportion of students who consume between 30 and 80 grams of pure alcohol is approximately 0.9452 - 0.0418 = 0.9034, or 90.34%. b. the probability that a randomly selected Illinois student consumes no more than two standard drinks on a Friday night is approximately 0.0319, or 3.19%. c. an Illinois student would have consumed approximately 66.117 grams if they consumed more than 75% of all other Illinois students on Green Street on a Friday night.
(a) The proportion of students on Green Street who consume between 30 and 80 grams of pure alcohol can be calculated by finding the area under the normal distribution curve between these two values. Let's denote the mean as μ = 56 grams and the standard deviation as σ = 15 grams.
To find the proportion, we need to standardize the values by converting them into z-scores. The formula for calculating the z-score is:
z = (x - μ) / σ
For 30 grams:
z1 = (30 - 56) / 15 = -1.733
For 80 grams:
z2 = (80 - 56) / 15 = 1.6
Next, we look up the corresponding probabilities associated with these z-scores using a standard normal distribution table or a statistical calculator. The area between these two z-scores represents the proportion of students who consume between 30 and 80 grams of pure alcohol.
Using the z-table or calculator, we find that the probability associated with z1 (-1.733) is 0.0418 and the probability associated with z2 (1.6) is 0.9452. Therefore, the proportion of students who consume between 30 and 80 grams of pure alcohol is approximately 0.9452 - 0.0418 = 0.9034, or 90.34%.
(b) To calculate the probability that a randomly selected Illinois student consumes no more than two standard drinks on a Friday night, we need to convert the two standard drinks (28 grams) into a z-score using the given mean (μ = 56 grams) and standard deviation (σ = 15 grams).
z = (x - μ) / σ
z = (28 - 56) / 15 = -1.867
We then find the probability associated with this z-score, which represents the proportion of students who consume no more than two standard drinks.
Using the z-table or calculator, we find that the probability associated with z = -1.867 is 0.0319. Therefore, the probability that a randomly selected Illinois student consumes no more than two standard drinks on a Friday night is approximately 0.0319, or 3.19%.
(c) To determine how much an Illinois student would have consumed if they consumed more than 75% of all other Illinois students on Green Street on a Friday night, we need to find the corresponding value in the normal distribution.
Since the mean (μ) represents the 50th percentile (median), we need to find the z-score associated with the 75th percentile. We can then convert this z-score back into the raw score (amount of pure alcohol consumed) using the given mean (μ = 56 grams) and standard deviation (σ = 15 grams).
Using a z-table or calculator, we find that the z-score associated with the 75th percentile is approximately 0.6745. Substituting this value into the z-score formula:
z = (x - μ) / σ
0.6745 = (x - 56) / 15
Solving for x, we get:
x = 0.6745 * 15 + 56
x ≈ 10.117 + 56
x ≈ 66.117
Therefore, an Illinois student would have consumed approximately 66.117 grams if they consumed more than 75% of all other Illinois students on Green Street on a Friday night.
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Based on a fictitious study, the amount of pure alcohol (in grams) a randomly selected
Illinois student on Green Street consumes on a Friday night has a mean of 56 grams and a standard deviation of 15 grams.
(a) If we assume that the amount of pu re alcohol an Illinois student drinks on a Friday night follows a normal distribution, then calculate the proportion of students on Green Street who consume between 30 and 80 grams of pure alcohol.
(b) According to the National Institute on Alcohol Abuse and Alcoholism, a "standard drink" contains roughly 14 grams of pure alcohol. What is the probability that a randomly selected Illinois students consumes no more than two standard drinks on a Friday night?
(c) How much would an Illinois student have consumed if they consumed more than 75% of all other Illinois students on Green Street on a Friday night?
a number minus 7 is less then 12
Answer:
7-n=12
Step-by-step explanation:
Answer:
x - 7 < 12
Step-by-step explanation:
Sara claims that a sequence of transformations carries Rectangle 1 onto Rectangle 2. Which of the following sequences of transformations can be used
to support Sara's claim?
A
a reflection over the y-axis, followed by a reflection over the x-axis.
B
a translation of 7 units to the left, followed by a translation of 8 units up.
С
a reflection over the x-axis, followed by translation of 4 units to the right
D
a rotation of 270° clockwise about the origin, followed by a reflection over the y-axis.
The sequences of transformations can be used to support Sara's claim that is A; a reflection over the y-axis, followed by a reflection over the x-axis.
How does the transformation of a function happen?The transformation of a function may involve any change.
Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretching (multiplying outputs or inputs), etc.
Given that Sara claims that a sequence of transformations carries Rectangle 1 onto Rectangle 2.
When a graph is reflected along an axis, it says x-axis, then that leads the graph to go just to the opposite side of the axis as if we can see it in a mirror.
If we study it more, then we will find that it is symmetric, however, each point is equidistant from the axis of reflection as that of the image of that point.
Therefore, The sequences of transformations can be used to support Sara's claim that is A; a reflection over the y-axis, followed by a reflection over the x-axis.
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What is the equation of the line that passes through the point (2,-1) and has a slope of 3/2
Answer:
y=3/2x-4
Step-by-step explanation:
y=3/2x+b
-1=3/2(2)+b
-1=3+b
-4=b
y=3/2x-4
A custodian can clean 2 classrooms in 15 minutes. At this
rate, how many classrooms can a custodian clean in 75 minutes?
10 classrooms
Answer:
Correct
Step-by-step explanation:
The number of classrooms cleaned in 75 minutes is given by the proportion A = 10 classrooms
What is Proportion?The proportion formula is used to depict if two ratios or fractions are equal. The proportion formula can be given as a: b::c : d = a/b = c/d where a and d are the extreme terms and b and c are the mean terms.
The proportional equation is given as y ∝ x
And , y = kx where k is the proportionality constant
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Given data ,
Let the proportion be represented as A
Now , the value of A is
The number of classrooms cleaned in 15 minutes = 2
The number of classrooms cleaned in 75 minutes = A
So , the proportion is
2 / 15 = A / 75
Multiply by 75 on both sides , we get
A = ( 2/15 ) ( 75 )
A = 2 x 5
A = 10 classrooms
Hence , the proportion is A = 10 classrooms
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How many 0.8 liter glasses can be filled by a 6.8 liter pitcher?
Answer:
8.5 glasses
Step-by-step explanation:
6.8L / 0.8L = 8.5 glasses
Answer:
8 glasses
Step-by-step explanation:
You divide \(6.8/0.8\)
This gives you 8.5 glasses
since 9 glasses is too much, at 7.2 liters. The maximum glasses possible is 8 assuming you're not filling a half of the glass which would be 8.5 glasses.
Understand Only 93% of the airplane parts being examined pass inspection. What is the probability that the next 5 part examinedwill all pass inspection?
Answer:
0.67 or 67%
Step-by-step explanation:
The probability that a single part will pass inspection is 0.93, so the probability that all 5 parts will pass inspection is (0.93)^5 = 0.67 or 67%.
The solution is 0.67 or 67%, is the probability that the next 5 part examined will all pass inspection.
What is probability?Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.
here, we have,
given that,
Understand Only 93% of the airplane parts being examined pass inspection.
now, we have to find that the probability that the next 5 part examined will all pass inspection.
now, we have,
The probability that a single part will pass inspection is 0.93,
so the probability that all 5 parts will pass inspection is :
(0.93)^5
= 0.67
= 67%.
Hence, The solution is 0.67 or 67%, is the probability that the next 5 part examined will all pass inspection.
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What is the measure of Zx?
Angles are not necessarily drawn to scale.
B
36°
F
G
A
J
\H
200
I
399
D
E
Answer:
\(\underline{\boxed{\tt \angle x=75^{o}}}\)
Step-by-step explanation:
We know that all angles of a triangle always add up to 180°.
\(\angle BDH+\angle DBH+\angle DHB=180^o\)
\(39^o+36^o+\angle DHB=180^o\)
\(\angle DHB=105^o\)
Now, ∠DHB & ∠x are supplementary angles because they form a straight line.
\(\angle DHB+\angle x=180^o\)
\(105^o+\angle x=180^o\)
\(\angle x=75^o\)
Answer: 75°
Step-by-step explanation: it’s right on khan (picture for proof)
which of the following is a required condition for anova? group of answer choices the population variances are equal. the samples are independent. all of these choices are required conditions for anova. the populations are normally distributed.
1. The population variances are equal;
2. The samples are independent;
3. The populations are normally distributed.
All of these choices are required conditions for ANOVA:
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Choose the best estimate for the weight of a cantaloupe. Responses A 2 decigrams2 decigrams B 2 kilograms2 kilograms C 2 grams2 grams D 2 milligrams
The best estimate for the weight of a cantaloupe is 2 kilograms (B).
A decigram is 1/10th of a gram, which would be too small of weight for a cantaloupe. 2 grams (C) is also too small for a cantaloupe as it would only be the weight of a few small seeds. 2 milligrams (D) is an extremely small weight, only suitable for a single grain of salt or a tiny insect.
Therefore, 2 kilograms (B) is the most reasonable estimate for the weight of a cantaloupe as it falls within the typical range of cantaloupe weights.
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Complete Question:
Choose the best estimate for the weight of a cantaloupe. Responses
A 2 decigrams
B 2 kilograms
C 2 grams
D 2 milligrams
A wall is 4m high and 40 cm wide it contain two Windows of dimension 2.5 X 1 metre and gateway of dimension 2 metre multiply 3 if 24560 cubical bricks of length 20 cm are required to construct the wall, find the length of the wall.solve it
Answer:
125.55 m.
Step-by-step explanation:
We need to find the volume of the bricked wall.
= total volume - volume of the windows - volume of the gateway.
= 4 * 0.4 * L - 2 * 2.5 * 1 * 0.4 - 2 * 3 * 0.4 m^3. (where L is the length of the wall).
Also this volume = number of bricks * volume of 1 brick
= 24560* 0.2^3.
So
4 * 0.4 * L - 2 * 2.5 * 1 * 0.4 - 2 * 3 * 0.4 = 24560* 0.2^3
1.6L - 2 - 2.4 = 196.48
1.6L = 200.88
L = 125.55 m.
Simplify: `\left(4g^{3}h^{4}\right)^{3}`
The expression \left(\(4g^{3}h^{4}\right)^{3}\)) can be simplified to \(64g^{9}h^{12}.\)
To simplify this expression, we raise each term inside the parentheses to the power of 3. For 4\(g^{3}\), we have \(4^{3}\) = 64 and \((g^{3})^{3}\)= \(g^{9}\), so we get \(64g^{9}\). Similarly, for \(h^{4}\), we have \((h^{4})^{3} = h^{12}\).
Combining these simplified terms, we have \(64g^{9}h^{12}\) as the final simplified form of the expression \left\((4g^{3}h^{4}\)\right)^{3}.
In summary, raising the expression\(4g^{3}h^{4}\) to the power of 3 simplifies to \(64g^{9}h^{12}\).
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Find the equation of the circle. With center at (-3, 1) and point on the circle= (5, -3).
Answer:
(x + 3)² + (y - 1)² = 80
Step-by-step explanation:
Circle equation: (x - h)² + (y - k)² = r²
We are given h and k, so we just plug that in:
(x + 3)² + (y - 1)² = r²
To find r, we need to use distance formula: \(d = \sqrt{(x2-x1)^2+(y2-y1)^2}\) between the center of the circle and the point on the circle. We should get √80 as r. We plug that in to get our answer:
(x + 3)² + (y - 1)² = 80
Describe two ways you can show that 1
is congruent to 7
Answer:
i think they have same degree
Step-by-step explanation:
because they are opposite