The radius of circle A is 4.
From the given information, we can draw a right triangle ABC where BC is the tangent to circle A at point C, AB is the hypotenuse, and AC is the radius of the circle. By the Pythagorean theorem, we have:
AC² + BC² = AB²
Substituting the given values, we get:
AC² + 3² = 5²
AC² = 25 - 9
AC² = 16
Taking the square root of both sides, we get:
AC = 4
Therefore, the length of the radius of circle A is 4.
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A coal car was redesigned by replacing some of the steel with aluminum. The designers wanted to reduce its weight and also increase its payload to 110 tons. The total weight of the redesigned car was 42,695 pounds. The amount of aluminum used was 9,860 pounds and the remainder was steel. What weight of steel was used?
The computation given that the weight of steel that was used is 32835 pounds.
How to compute the value?From the information given, it was stated that the total weight of the redesigned car was 42,695 pounds and the amount of aluminum used was 9,860 pounds and the remainder was steel.
Therefore, the amount used for steel will be:
= 42695 - 9860
= 32835 pounds.
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after 3 years a $1500 investment is worth $1680.
what is the interest rate on the investment?
a 60-year-old female is diagnosed with hyperkalemia. which symptom would most likely be observed?
Hyperkalemia is a medical condition that refers to an elevated level of potassium in the blood.
This condition can be caused by several factors, including kidney disease, certain medications, and hormone imbalances. Symptoms of hyperkalemia can range from mild to severe, depending on the level of potassium in the blood.
In a 60-year-old female diagnosed with hyperkalemia, the most likely symptom that would be observed is muscle weakness. This is because high levels of potassium can interfere with the normal functioning of muscles, leading to weakness, fatigue, and even paralysis in severe cases.
Other symptoms that may be observed in hyperkalemia include nausea, vomiting, irregular heartbeat, and numbness or tingling in the extremities. Treatment of hyperkalemia typically involves addressing the underlying cause of the condition, as well as managing symptoms through medication and lifestyle changes.
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Write the equation of the line passing through the point (-3,1) and (2-4)
What are the solutions of the inequality 2x² x 6 0?
The solutions of the inequality \(2x^{2} + x - 6 = 0\) are 3/2, -2. This can be found by using the Quadratic Formula, which states that for any quadratic equation of the form \(ax^{2} +bx + c = 0\), the solutions are \(x = -b +/-\sqrt{b^{2} -4ac} /2a\).
Discriminant: b² - 4 a c = 1 - 4(2)(-6) = 1 + 48 = 49
Solution 1: x = \(-b + \sqrt{b^{2} -4ac} /2a\) = (-1 + √49)/(2×2) = (-1 +7)/4 = 6/4 = 3/2
Solution 2: x = \(-b-\sqrt{b^{2} -4ac} /2a\)= (-1 - √49)/(2×2) = -8/4 = -2
So, the two solutions are 3/2 and -2.
The equation can also be written as,
\(2x^{2} +4x -3x-6=0\)
\(2x(x+2) -3(x+2) = 0\)
\((2x-3)(x+2) = 0\)
x = 3/2, -2
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find the slope
(x, -4) and (2, 8); m = -3
Answer:
x=6
slope (m) = -3
Step-by-step explanation:
Carlos made two identical necklaces each having beads and a pendant. The total cost of the beads and pendants for both necklaces was $12.40. If the beads cost $2.80 for each necklace, how much each does dependent cost?
Answer:
Step-by-step explanation:
So we know that:
Total Cost: $12.40
Beads per Necklace: 2.80
So the first thing we have to do is multiply 2.80 by 2 which equals 5.6 so that's how much of the total cost was for beads.
So now we subtract the amount of money for the beads and the total cost of the necklaces 12.40 - 5.6 = 6.8
So 6.8 was the amount of money that is left for the pendants. Now that we know that we have to divide that by 2 to find out how much money did Carlos spend for each pendant,
6.8÷2= 3.4
So Carlos spent 3 dollars and 4 cents on each pendant.
A plastic extrusion process is in statistical control and the output is normally distributed. The extrudate is subsequently cut into individual parts, and the extruded parts have a critical cross-sectional dimension = 12.50 mm with standard deviation = 0.25 mm. Determine the process capability.
The process capability, Cp is calculated by dividing the upper specification limit minus lower specification limit by 6 times the process standard deviation.
This is the formula for the process capability.
Cp = (USL - LSL) / (6 * Standard deviation)
Where, Cp is process capability USL is the Upper Specification Limit LSL is the Lower Specification Limit Standard deviation is the process standard deviation.
The extrudate is subsequently cut into individual parts, and the extruded parts have a critical cross-sectional dimension = 12.50 mm with standard deviation = 0.25 mm. The mean of this distribution is the center line of the control chart and the critical cross-sectional dimension 12.50 mm is the target or specification value.
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if a distribution of scores is shown in a bar graph, you know that the scores were measured on a(n) _________ scale of measurement.
If a distribution of scores is shown in a bar graph, it suggests that the scores were measured on an ordinal scale of measurement.
An ordinal scale is a type of measurement scale that categorizes and orders variables or data points based on their relative ranking or position. In this case, the bar graph represents the frequencies or counts of different categories or ranges of scores, indicating an ordered arrangement of the data. However, the bar graph alone does not provide information about the exact numerical differences between the scores or their precise magnitudes.
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What is the value of n?
Answer:
n = 28 degree
Step-by-step explanation:
2n + 17 + 2n - 5 + 2n = 180 degree (sum of interior angles of a triangle)
6n +12 = 180
6n = 180 - 12
n = 168/6
n = 28 degree
(#7.) Which is the graph of y= -1/2x ?
Answer:
b
Step-by-step explanation:
a neg slope goes from top left to bottom right
slope is read rise over run so rise 1, run 2
What is the value of the expression -218 - 72 - (-5)?
Answer:
The answer is -285
Step-by-step explanation:
what number decreased by 6 equals 3 times the number
Answer:
-3
Step-by-step explanation:
x-6=3x
2x=-6
x=-3
The required number is -3 decreased by 6 equals 3 times.
A number to be determine when decreased by 6 equals 3 times the number.
What is arithmetic?it explores the numbers of operations according to the statements.
Let the number be x,
Now,
x-6=3x
x= -3
Thus, the required number is -3 decreased by 6 equals 3 times.
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The cost of producing key chains with the company logo printed on them consistsof a onetime setup fee of $260.00 plus $0.80 for each key chain produced. Thiscost can be calculated using the formula C = 260.00+ 0.80p, where p representsthe number of key chains produced and C is the cost. Use the formula to calculatethe cost of producing 1700 key chains.
Answer:
The cost foe producing 1700 key chains is $1,620
Explanation:
Given that cost of production key chains can be calculated using the formula:
C = 260 + 0.80p
The cost for producing 1700 key chains can be obtained by substituting p by 1700 in the given formula.
C = 260 + 0.80(1700)
= 260 + 1360
= 1620
The cost is $1,620
The value of X is
X + 75
X + 125
Answer:
-10
Step-by-step explanation:
x+75+x+125=180
2x+200=180
2x=180-200
2x=-20
x=-10
Which statements are true? Select three options
There are exactly two planes that contain points A,
B, and F
There is exactly one plane that contains points E, F,
and B
The line that can be drawn through points C and G
would lie in plane x,
The line that can be drawn through points E and F
would lie in planer
The only points that can lie on plane Yare points E
and F. my guy I literally have 5 days before graduation cmon man
Answer:
1. There is exactly one plane that contains points E,F, and B (2nd option)
2. The line that can be drawn through points C and G
would lie in plane x. (3rd option)
3. The line that can be drawn through points E and F
would lie in plane y. (4th option)
Step-by-step explanation:
The line that can be drawn through points C and G would lie in X-plane and the point E and F would lie in Y-plane. Then the correct options are C, D, and E.
What is a plane?A plane is a straight surface, with multiple surfaces that never end in maths.
The points C, D, and G lie in X-plane.
And the points E and F lie in Y-plane.
From the diagram, the conclusion points are given below.
The line that can be drawn through points C and G would lie in X-plane.The line that can be drawn through points E and F would lie in Y-planer.The only points that can lie on plane Y are points E and F.Then the correct options are C, D, and E.
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You are selling tickets for a high school concert. Student tickets cost $3 and adult tickets cost $5. You sell 350 tickets and collect $1,450. How many of each type of ticket did you sell?
Answer:
150 student tickets
200 adult tickets
Step-by-step explanation:
We'll say student tix are x, adult are y
3x + 5y = $1450 and
x + y = 350
first, solve y in terms of x
y = 350 - x
Then substitute that into the equation to solve for x
3x + 5(350-x) = 1450
3x + 1750 - 5x = 1450
-2x = -300
x = 150
Substitute that value in to solve for y
x + y = 350
150 + y = 350
y = 200
Checking the math:
3(150) + 5 (200) = 450 + 1,000 = $1,450
3 + jk + k when j = 2 and k = 4
Answer:
3+2×4+4
3+8+4
15
Step-by-step explanation:
the the answer is 15
Write each product using an exponent:
20 x 20
Answer:
400 or the exponent is 20²
Step-by-step explanation:
20² or 20×20=400
what is the gradient of the line (-4, 10) to (-2, 6)
Answer:
(2,-4)
Step-by-step explanation:
-4+2=-2
10+-4=10-4=6
Which shapes have rotational symmetry?
Answer:
whats rotational symmetry?
if you explain it i might be able to help you
Step-by-step explanation:
I need help with number 21 please help!!!
Answer:
This is not a direct variation.Step-by-step explanation:
Direct variation:
mathematical relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other.
(y varies directly with x with a constant variation of k)
\(y=kx;\ k\neq0\)
\(y=kx\qquad|\text{divide both sides by}\ x\\\\\dfrac{y}{x}=k\Rightarrow \dfrac{y}{x}=constant\)
\(21.\\\\x=y+2\qquad|\text{subtract 2 from both sides}\\\\x-2=y\qquad|\text{divide both sides by}\ x\\\\1-\dfrac{2}{x}=\dfrac{y}{x}\ro\dfrac{y}{x}=1-\dfrac{2}{x}\neq constant\)
3, +5,9,-6, what is the total score of Jesse's hand?
Answer:
11
Step-by-step explanation:
3 + 5 = 8
8 + 9 = 17
17 - 6 = 11
what do you think would happen to a person if mortor neuron from the grey matter of spinal cord is removed?
Step-by-step explanation:
Introduction
Until World War II, a serious spinal cord injury (SCI) usually meant certain death. Anyone who survived such injury relied on a wheelchair for mobility in a world with few accommodations and faced an ongoing struggle to survive secondary complications such as breathing problems, blood clots, kidney failure, and pressure sores. By the middle of the twentieth century, new antibiotics and novel approaches to preventing and treating bed sores and urinary tract infections revolutionized care after spinal cord injury. This greatly expanded life expectancy and required new strategies to maintain the health of people living with chronic paralysis. New standards of care for treating spinal cord injuries were established: reposition the spine, fix the bones in place to prevent further damage, and rehabilitate disabilities with exercise.
Today, improved emergency care for people with spinal cord injuries, antibiotics to treat infections, and aggressive rehabilitation can minimize damage to the nervous system and restore function to varying degrees. Advances in research are giving doctors and people living with SCI hope that spinal cord injuries will eventually be repairable. With new surgical techniques and developments in spinal nerve regeneration, cell replacement, neuroprotection, and neurorehabilitation, the future for spinal cord injury survivors looks brighter than ever.
simplify 8(x+3)^2/2(x+3)
Answer:
8
I sent you a photo so u understand how
What is the difference in the intensity between a a 3.2 and a 6.5 earthquake. how is earthquake intensity a logarithmic equation
A 4.2 earthquake's energy release is 10 times more than a 3.2 earthquake's energy release despite the 3.2 earthquake's amplitude being 10 times smaller.
Now, A 3.2- to 6.5-magnitude earthquake has a substantial difference in intensity.
In actuality, a 6.5 earthquake has a magnitude almost 1000 times greater than a 3.2 earthquake.
The Richter scale, which uses a logarithmic scale to assess earthquake intensity, is the reason behind this.
Since, the Richter scale uses a seismograph to estimate the amplitude of earthquake waves, it is a logarithmic equation.
Each unit increase on the Richter scale causes an exponential increase in the energy released by the earthquake, which is proportional to the amplitude of the earthquake waves.
For instance, a 4.2 earthquake's energy release is 10 times more than a 3.2 earthquake's energy release despite the 3.2 earthquake's amplitude being 10 times smaller.
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In Kite EFGH, m< FHG=15 degrees, and m< FEG=146 degrees. Find the indicated measures
The measure of m<FEJ is 75 degree
How to find the angles in kiteFrom the given figir, we can see that;
m< FHG = m< EFJ = 15 degrees
Since the sum of angles in a triangle is 180 degrees, hence;
m< EFJ + 90 + m<FEJ = 180
15+ 90 + m<FEJ = 180
m<FEJ = 180 - 105
m<FEJ = 75 deegrees
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Given T(1,5), U(-2,-8), V(7,-9), and W(-6, y). Find y such that
TU VW
keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of TU
\((\stackrel{x_1}{1}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-8}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{1}}} \implies \cfrac{-13}{-3}\implies \cfrac{13}{3}\)
hmmmm, well, if that's so, then the slope of VW will be the negative reciprocal of that only if both are really perpendicular, so
\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{13}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{13}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{13}}}\)
since now we know the slope if VW, let's use it
\((\stackrel{x_1}{7}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{y}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{y}-\stackrel{y1}{(-9)}}}{\underset{run} {\underset{x_2}{-6}-\underset{x_1}{7}}} \implies \cfrac{y +9}{-13}~~ = ~~\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{13}}\implies y+9=\cfrac{3(-13)}{-13} \\\\\\ y+9=3\implies {\LARGE \begin{array}{llll} y = -6 \end{array}}\)
5x-y=5
3x+2y=29
Solve by substitution method.
Answer:
y=-4.81
Step-by-step explanation:
15x-37y=15
15x+10y=145
27y=-130
y=-4.81
Solve the following initial value problem. dy/ dx= 1/ x² +X,X>0; y(2) = 1 The solution is __ (Type an equation.)
To solve the given initial value problem, we can use the method of integrating factors.
The differential equation can be written in the form:
dy/dx + P(x)y = Q(x)
where P(x) = 1/(x^2+x) and Q(x) = 0.
To find the integrating factor, we multiply both sides by a function μ(x):
μ(x)dy/dx + μ(x)P(x)y = μ(x)Q(x)
We want the left-hand side to be the product rule of a derivative, so we choose μ(x) such that:
d(μ(x)y)/dx = μ(x)dy/dx + μ'(x)y
Comparing this with the left-hand side of the previous equation, we can see that we need:
μ'(x) = P(x)μ(x)
We can solve this separable differential equation as follows:
dμ(x)/dx = μ(x)/(x^2+x)
μ(x)/μ'(x) = x^2+x
ln(μ(x)) = (1/2)x^2 + x + C
μ(x) = e^(x^2/2 + x + C)
where C is a constant of integration.
Multiplying both sides of the original differential equation by the integrating factor μ(x), we get:
μ(x)dy/dx + μ(x)P(x)y = 0
Substituting the values of μ(x), P(x), and Q(x), we get:
e^(x^2/2 + x + C)dy/dx + (x^2+x)e^(x^2/2 + x + C)y = 0
Multiplying through by e^-(x^2/2 + x + C) and integrating with respect to x, we get:
y(x) = Ce^-(x^2/2 + x) + ∫e^-(x^2/2 + x) dx
To evaluate the integral, we can use the substitution u = x + 1, which gives:
∫e^-(x^2/2 + x) dx = ∫e^-(u^2/2 - 1/2) du
= e^(1/2)∫e^-(u^2/2) d(u^2/2)
= e^(1/2)∫e^-v dv (where v = u^2/2)
= -e^(1/2)e^-v + C'
= -e^(1/2)e^-(x^2/2 + x) + C'
Substituting this back into the equation for y(x), we get:
y(x) = Ce^-(x^2/2 + x) - e^(1/2)e^-(x^2/2 + x) + C'
= (C - e^(1/2))e^-(x^2/2 + x) + C'
Using the initial condition y(2) = 1, we get:
1 = (C - e^(1/2))e^-(2^2/2 + 2) + C'
= (C - e^(1/2))e^-5 + C'
Solving for C', we get:
C' = (e^(1/2) - C)e^-5 + 1
Substituting this back into the equation for y(x), we get the solution:
y(x) = (C - e^(1/2))e^-(x^2/2 + x) + (e^(1/2) - C)e^-5 + 1
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