Given below are the measured streamflows in cfs from a storm of 6-hour duration on a stream having a drainage area of 185 mi^2. Derive the unit hydrograph by the inverse procedure. Assume a constant baseflow of 550 cfs.
Hour Day 1 Day 2 Day 3 Day 4
Midnight 550 5,000 19,000 550
6 am 600 4,000 1400
Noon 9000 3000 1000
6 pm 6600 2500 750
Answers
Answer:
33.56 ft^3/sec.in
Explanation:
Duration = 6 hours
drainage area = 185 mi^2
constant baseflow = 550 cfs
Derive the unit hydrograph using the inverse procedure
first step : calculate for the volume of direct runoff hydrograph using the details in table 2 attached below
Vdrh = sum of drh * duration
= 29700 * 6 hours ( 216000 secs )
= 641,520,000 ft^3.
next step : Calculate the volume of runoff in equivalent depth
Vdrh / Area = 641,520,000 / 185 mi^2
= 1.49 in
Finally derive the unit hydrograph
Unit of hydrograph = drh / volume of runoff in equivalent depth
= 50 ft^3 / 1.49 in = 33.56 ft^3/sec.in
Related Questions
What is the safe psi pressure for acetylene
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Answer:
15psig
Explanation:
Single-use earplugs require a professional fitting before they can be used.
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An asbestos pad is square in cross section, measuring 5 cm on a side at its small end, increasing linearly to 10 cm on a side at the large end. The pad is 15 cm high. If the small end is held at 600 K and the large end at 300 K, what heat‐flow rate will be obtained if the four sides are insulated? Assume one‐dimensional heat conduction. The thermal conductivity of asbestos may be taken as 0.173 W/m⋅K.
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3. A wind turbine having a rotor diameter of 48 m and rated at 800 kW, is operating at a wind speed of 12 m/s. Three blades mounted on a cast iron hub drive a generator through a three-stage gear box of overall ratio 1:50. The induction generator is connected directly to the 50 Hz network and keeps the high-speed shaft at 1500 rpm. Calculate the power coefficient (Cp), the rotor tip speed of the blade and the tip speed ratio ().
Answers
The rotor tip speed of the blade is 75.4 m/s, the tip speed ratio is 2.00, and the power coefficient (Cp) is 0.35.
Rotor Tip Speed of the Blade:
The rotor tip speed of the blade is calculated to be 75.4 m/s.
Tip Speed Ratio:
The tip speed ratio is determined to be 2.00. The tip speed ratio represents the ratio of the blade tip speed to the wind speed at a specific rotor radius.
Power Coefficient (Cp):
The power coefficient (Cp) is a measure of the efficiency of a wind turbine in converting wind power into electrical power. It is calculated by dividing the electrical power output by the available wind power.
In the given scenario, the power coefficient (Cp) is found to be 0.35.
The calculations and formulas used for determining the rotor tip speed, tip speed ratio, and power coefficient are as follows:
Rotor Tip Speed of the Blade:
The rotor tip speed of the blade is calculated using the formula:
Vb = (2 × π × r × N) / 60
where Vb represents the blade tip speed, r is the radius of the rotor, and N is the rotational speed of the low-speed shaft.
In this case, the rotor diameter is given as 48 m, resulting in a radius (r) of 24 m. The rotational speed (N) of the low-speed shaft is calculated to be 30 rpm. Plugging these values into the formula yields a rotor tip speed (Vb) of 75.4 m/s.
Tip Speed Ratio:
The tip speed ratio (λ) is calculated by dividing the blade tip speed (Vb) by the tip speed (Vt). The tip speed is determined using the formula:
Vt = π × D × n / 60
where D is the rotor diameter and n is the wind speed.
In this case, the wind speed is given as 12 m/s, resulting in a tip speed (Vt) of 37.68 m/s. By dividing the blade tip speed (Vb) of 75.4 m/s by the tip speed (Vt), the tip speed ratio (λ) is found to be 2.00.
Power Coefficient (Cp):
The power coefficient (Cp) is calculated using the formula:
Cp = P / (0.5 × ρ × A × V^3)
where P represents the power generated, ρ is the density of air, A is the area swept by the blades, and V is the wind velocity.
In this case, the power generated is given as 800,000 W, the air density (ρ) is 1.23 kg/m^3, the swept area (A) is calculated to be 1809.56 m^2, and the wind velocity (V) is 12 m/s. Plugging these values into the formula yields a power coefficient (Cp) of 0.35.
Therefore, the rotor tip speed of the blade is 75.4 m/s, the tip speed ratio is 2.00, and the power coefficient (Cp) is 0.35.
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The angle of attack of a wing directly controls the A) angle of incidence of the wing. B) amount of airflow above and below the wing. C) distribution of pressures acting on the wing.
Answers
The angle of attack of a wing directly controls the C) distribution of pressures acting on the wing.
When the angle of attack of a wing is increased, the air moving over the curved upper surface of the wing must travel a greater distance and faster than the air moving beneath the wing's flat lower surface. This creates an area of lower air pressure above the wing and an area of higher air pressure beneath the wing, resulting in lift. The greater the angle of attack, the greater the lift produced.
However, if the angle of attack is too great, the airflow over the wing may separate, causing a loss of lift and potentially leading to a stall. Therefore, proper control of the angle of attack is crucial for safe and efficient flight.
Option C is answer.
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A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
Which number is equivalent to the decimal number 149?
A.
11011011
B.
100101012
C. 001001112
D. 101010012
Answers
Answer:
letter B
Explanation:
basta yan anwer
If a rubber band is stretched adiabatically, its temperature increases. (a) If the rubber band is stretched isothermally, does its entropy in- (b) If the rubber band is stretched adiabatically, does the internal crease, decrease, or stay the same? Energy increase, decrease, or stay the same?
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A ball is traveling on a smooth surface in a 3 ft radius circle with a speed of 6 ft/s. If the attached cord is pulled down with a constant speed of 2 ft/s.
What principles can be applied to solve for the velocity of the ball when r = 2 ft?
Answers
To solve for the velocity of the ball when r = 2 ft, we can apply the principle of conservation of angular momentum. This principle states that the angular momentum of a system remains constant unless acted upon by an external torque. In this case, as the ball travels on the smooth surface in a circle, it has a constant angular momentum due to its velocity and radius.
When the cord is pulled down, it applies an external torque to the system, causing the radius of the circle to decrease. As the radius decreases, the velocity of the ball will increase in order to maintain its constant angular momentum. We can use the equation for conservation of angular momentum, L = Iω, where L is angular momentum, I is moment of inertia, and ω is angular velocity, to solve for the velocity of the ball when r = 2 ft.
Assuming the ball is a solid sphere with uniform density, its moment of inertia can be calculated as I = (2/5)mr^2, where m is mass. Using this moment of inertia and the given radius and speed at the beginning, we can solve for the initial angular velocity ω1 = v1/r.
As the radius decreases to 2 ft, we can solve for the final angular velocity ω2 using the equation L = Iω, where L is constant. Then, we can find the final velocity of the ball using the equation v2 = rω2. Therefore, the principles that can be applied to solve for the velocity of the ball when r = 2 ft are the principle of conservation of angular momentum and the equations for moment of inertia and angular velocity.
Hi! To solve for the velocity of the ball when r = 2 ft, you can use the principles of conservation of angular momentum and the Pythagorean theorem.
Conservation of angular momentum states that the initial angular momentum (L1) equals the final angular momentum (L2) when no external torques are acting on the system. In this case, L1 = mvr1 and L2 = mvr2, where m is the mass of the ball, v is its linear speed, and r1 and r2 are the initial and final radii, respectively.
Since the mass of the ball is constant, the conservation of angular momentum equation can be simplified to:
v1r1 = v2r2
We are given the initial conditions: r1 = 3 ft, v1 = 6 ft/s, and r2 = 2 ft. To find v2, you can rearrange the equation and solve for v2:
\(v2 = (v1r1) / r2 = (6 ft/s × 3 ft) / 2 ft = 9\)ft/sNow, we have the tangential velocity of the ball (9 ft/s). To find the total velocity, we must consider the downward velocity due to the cord being pulled, which is given as 2 ft/s.
Using the Pythagorean theorem, the total velocity (V) can be found by:
V = √(v2² + downward velocity²) = √(9 ft/s² + 2 ft/s²) = √(81 + 4) = √85 ft/s ≈ 9.22 ft/s
So, when r = 2 ft, the velocity of the ball is approximately 9.22 ft/s.
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The inside of a conduit installed under a concrete slab at grade level is considered a dry or wet location?
Answers
The inside of a conduit installed under a concrete slab at grade level is considered as a dry location.
The National Electric Code (NEC) defines a wet location as an area that is exposed to moisture or water. Wet locations are at risk of corrosion, degradation, or short-circuit. Since the conduit is placed underground, it is not directly exposed to rain or other forms of moisture that may cause electrical damage. As a result, it is considered a dry location according to the NEC.
NEC Article 100 defines a wet location as a location that is directly or indirectly exposed to water or any other liquid. In contrast, a dry location is one that is not exposed to moisture or liquids that may damage electrical equipment. Since the conduit is not directly exposed to water, it is classified as a dry location. However, it is still necessary to ensure that the conduit is adequately sealed and installed according to the manufacturer's instructions to prevent moisture ingress.
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A conduit installed beneath a concrete slab at grade level is said to be in a wet location. Wet locations are those where water or other liquids may accumulate, but are not immersed in water.
A dry location is an environment where there is no water, steam, or other moisture that can interfere with the electrical devices' successful operation. A damp location is an area where moisture can be present, but no standing water can accumulate to a depth of less than 1 inch, or there is frequent condensation.The National Electrical Code (NEC) defines locations according to the degree of exposure to the elements and moisture. A conduit installed below a concrete slab in a location where water is likely to accumulate is an instance of a wet environment. Conduits should be secured at 3-foot intervals and supported within 12 inches of boxes and fittings to protect against movement. This is to ensure that the electrical wiring remains functional and secured even when placed in a wet location, and it helps to avoid any harm to the person operating the electrical devices.
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A___________combines the function of a video camera and a sound recorder.
Answers
Answer:
A video camera with onboard storage(whether is a tape or digital memory) will record sound
Anand's age after 25 years will be twice his age 5 years back. Find the present age of Anand ?
Answers
Let's assume Anand's present age is "x".
According to the problem statement, Anand's age after 25 years will be "x + 25".
And, Anand's age 5 years back will be "x - 5".
So, as per the given condition,
x + 25 = 2(x - 5)
x + 25 = 2x - 10
x - 2x = -10 - 25
-x = -35
x = 35
Therefore, Anand's present age is 35.
The two major forces opposing the motion of a vehicle moving on a level road are the rolling resistance of the tires, Fr, and the aerodynamic drag force of the air flowing around the vehicle, Fd, given respectively by Fr, = fW, Fd= CdA1/2 rhoV2 where f and Cd are constants known as the rolling resistance coefficient and drag coefficient, respectively, W and A are the vehicle weight and projected frontal area, respectively, V is the vehicle velocity, and rho is the air density. For a passenger car with W = 3,550 lbf, A = 23.3 ft^2, and Cd = 0.34, and where f = 0.02 and rho = 0.08 lbm/ft^3.
Required:
Determine the power required, in HP, to overcome rolling resistance and aerodynamic drag when V is 55 mph.
Answers
Answer:
The power required to overcome rolling resistance and aerodynamic drag is 19.623 h.p.
Explanation:
Let suppose that vehicle is moving at constant velocity. By Newton's Law of Motion, the force given by engine must be equal to the sum of the rolling resistance and the aerodynamic drag force of the air. And by definition of power, we have the following formula:
\(\dot W = \left(f\cdot W +\frac{\rho\cdot C_{D}\cdot A\cdot v^{2}}{2\cdot g_{c}} \right)\cdot v\) (1)
Where:
\(\dot W\)- Power, in pounds-force-feet per second.
\(f\) - Rolling resistance coefficient, no unit.
\(W\) - Weight of the passanger car, in pounds-force.
\(\rho\) - Density of air, in pounds-mass per cubic feet.
\(C_{D}\) - Drag coefficient, no unit.
\(A\) - Projected frontal area, in square feet.
\(v\) - Vehicle speed, in feet per second.
\(g_{c}\) - Pound-mass to pound-force ratio, in pounds-mass to pound-force.
If we know that \(f = 0.02\), \(W = 3,550\,lbf\), \(\rho = 0.08\,\frac{lbm}{ft^{3}}\), \(C_{D} = 0.34\), \(A = 23.3\,ft^{2}\), \(v = 80.685\,\frac{ft}{s}\) and \(g_{c} = 32.174\,\frac{lbm}{lbf}\), then the power required by the car is:
\(\dot W = \left(f\cdot W +\frac{\rho\cdot C_{D}\cdot A\cdot v^{2}}{2\cdot g_{c}} \right)\cdot v\)
\(\dot W = 10901.941\,\frac{lbf\cdot ft}{s}\)
\(\dot W = 19.623\,h.p.\)
The power required to overcome rolling resistance and aerodynamic drag is 19.623 h.p.
Multiple Choice
Which of the following best describes the role of engineers?
A) Engineers must clearly determine exactly what needs to be solved or designed.
B) Engineers must earn a bachelor’s and a master’s degree before getting hired.
C) Engineers must be sure every change they make is a functional design improvement.
D) Engineers must be content working in an office setting.
Answers
Answer:
A
Explanation:
Answer:
A) Engineers must clearly determine exactly what needs to be solved or designed.
Explanation:
Fill in the blank. Common ways of connecting and disconnecting the front axles on a 4WD vehicle include having locking hubs, _______________ motors, _______________ motors, and mechanical _______________.
Answers
Common ways of connecting and disconnecting the front axles on a 4WD vehicle include having locking hubs, electric motors, vacuum motors, and mechanical linkage.
Locking hubs are manually engaged or disengaged by the driver and physically lock the front wheels to the axles. Electric motors use a switch in the cabin to engage or disengage the front axle. Vacuum motors also use a switch in the cabin to activate a vacuum pump which engages or disengages the front axle.
Mechanical linkage uses a lever or cable to physically connect or disconnect the front axle. Each of these methods has its own advantages and disadvantages, but they all serve the same purpose of giving the driver control over the 4WD system.
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what does Ohm law teach about current and resistance
Answers
Answer:
Directly proportional to voltage but inversely proportional to resistance
Explanation:
The law mentions that current is directly proportional to voltage but inversely proportional to resistance. At constant resistance, current increases as voltage increases and vice versa. At a constant voltage, the current decreases as resistance increases and vice versa.
Answer:
Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them. Mathematically, this can be expressed as:
I = V/R
Where:
I is the current flowing through the conductor in amperes (A)
V is the voltage across the two points in volts (V)
R is the resistance between the two points in ohms (Ω)
This equation shows that if the voltage (V) is increased while the resistance (R) stays constant, the current (I) will also increase. Conversely, if the resistance (R) is increased while the voltage (V) stays constant, the current (I) will decrease.
This relationship is fundamental to the behavior of electric circuits, and is used extensively in circuit analysis and design.
6) two reservoirs are connected by a 380 ft long commercial steel pipe with a diameter of 2 ft. there is a square-edged entrance and exit and a threaded 90-degree elbow at the pump. the 500 horse power pump supplies water from the lower reservoir to the upper reservoir. determine the flow rate.
Answers
The given data regarding reservoirs and commercial steel pipes can be analyzed to determine the flow rate. The flow rate is the rate at which a fluid flows through a particular passage. It is typically measured in gallons per minute, liters per second, or cubic meters per hour.
So, the flow rate can be calculated by the following formula: Q=AV
Where Q is the flow rate, A is the cross-sectional area of the pipe, and V is the velocity of the fluid. To find the flow rate, we need to calculate the velocity of the fluid first. The velocity can be determined by using the Bernoulli's equation:ρgh + 0.5ρv₁² = ρh₂ + 0.5ρv₂²where ρ is the density of the fluid, g is the acceleration due to gravity, h is the height difference between the two reservoirs, v₁ is the velocity of the fluid at the entrance of the pipe, h₂ is the height difference between the exit of the pipe and the lower reservoir, and v₂ is the velocity of the fluid at the exit of the pipe. Here, the pipe has a diameter of 2 ft, which means the radius is 1 ft. Thus, the cross-sectional area of the pipe is given as follows:A = πr²= π(1)²= π sq ftNow, the velocity can be determined by simplifying the Bernoulli's equation. Assuming the pipe is horizontal, h₁ = h₂, and v₁ = 0, the equation can be simplified as:ρgh = 0.5ρv₂²v₂ = sqrt(2gh)where h is the height difference between the two reservoirs. Now, we need to determine the value of h from the given data. As per the given data, the two reservoirs are connected by a 380 ft long commercial steel pipe with a diameter of 2 ft.
The length of the pipe and the difference in height between the two reservoirs can be used to find h. According to the question, there is a 90-degree elbow at the pump, which doesn't cause any difference in height. Thus, the difference in height can be determined by using the following formula: h = (L - 0.2D)/2 = (380 - 0.2(2))/2= 189 ft Now, the value of v₂ can be determined by using the above equation: v₂ = sqrt(2gh)= sqrt(2 x 62.4 x 189)= 109.76 ft/s Now, the flow rate can be calculated by using the formula: Q=AV= (π/4)d²v₂= (π/4)(2)²(109.76)= 689.75 cubic feet per second
Answer: 689.75 cubic feet per second
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Tech A says that it is best to use a knife or other type of sharp tool to cut away the insulation when
stripping a wire Tech B says that any issues with wing are more likely to be with the terminals than
with the wires themselves. Who is correct?
Answers
Eugene runs a company that manufactures bricks. The manufacturing process consumes a lot of energy and causes pollution, which type of
bricks is his company manufacturing?
Answers
Answer:
D. Fire clay bricks
Explanation:
Just like in the steel mills with the big furnaces that's what causes all the smoke to come out of the stacks
Answer:
d is correct
Explanation:
8.7. Jericho Vehicles is considering making a bid for a mobile rocket-launching system for the
U.S. military. However, the company has almost no experience in producing this type of
vehicle. In an effort to develop a learning curve for the production of this new mobile weapon
system, management has called contacts from several former competitors who went bankrupt.
Although management could not obtain direct learning curve rates, they did learn from one
contact that for a system with similar features, the first unit required 2400 hours of direct labor
to produce and the 30th and final unit required 1450 hours to produce. Determine the learning
curve rate for this vehicle.
Answers
The company has experienced an 87% of learning curve in the past producing similar vehicles the first unit required 2400 hours of direct labor to produce and the 30th and final unit required 1450 hours to produce.
What is meant by learning curve ?A learning curve is a graph that shows how quickly something can be learned over time or via repeated experiences. Learning curves serve as a visual representation of relative learning progress over time as well as the expected complexity of a subject.
The learning curve is a diagram that shows how long it takes to learn new information or abilities. In the world of business, the slope of the learning curve indicates how quickly acquiring new abilities might result in cost savings for an organisation.
The learning curve model makes it easier to monitor training progress, boost output, and forecast learners' performance and growth over time.
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Match the terms with the correct definitions.
professionals who design,
1. civil engineers
construct, and maintain the built
environment
the document that is the result of
2. environmental assessment
3. environmental impact statement
an environmental impact assessment
(EIA)
a governmental regulatory process
in which a proposed building is analyzed
to determine if it will have a negative
impact on the surrounding environment
a type of civil engineer who focuses
on the relationship between geology
(i.e., the ground), and the foundation and
superstructure of a building or structure
the number of residential building
projects that have broken ground in a
given month; used as an economic
indicator by the U.S. Department of
Commerce
4. geotechnical engineer
5. housing starts
Answers
in welding connections, the additional metal, sometimes referred to as metal, is deposited from a special electrode, which is part of an electrical circuit that includes the connected part, or metal. group of answer choices a.
Answers
In welding connections, the additional metal often referred to as filler metal, is deposited from a special electrode, which is part of an electrical circuit that has the connected part, or welding rod metal. Thus, D. 'filler; welding rod' is the correct answer.
Filler metal is referred to any material that is used to join two pieces of metal during soldering or welding. As the two items are held together, the filler metal is melted between the two to produce a bridge. After the filler dries, it combines with the items on either side to produce a permanent bond. While welding rods are pieces of metal that are heated to high temperatures and used as a filler to fuse other metals together. Thus, for this question option 'D' holds the correct answer.
"
Complete question:
In welding connections, the additional metal, sometimes referred to as metal, is deposited from a special electrode, which is part of an electrical circuit that includes the connected part, or metal. group of answer choices
A: base; flux
B: flux; shielded
C: base; welding rod
D: filler ; welding rod
"
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The ______________________________ instruction transfers either a number or content of a register to a destination register.
Answers
The MOV instruction transfers either number or content of a register to a destination register.
What is mov education?The mov instruction replicates the data item referred to by its second operand (i.e. register contents, memory contents, or a constant value) into the location directed to by its first operand (i.e. a register or memory). While register-to-register moves are possible, natural memory-to-memory moves are not.
What is mov in opcode?
"mov" is an instruction, encoded with the system code or "opcode" 0xb8. Since mov takes an opinion, the next 4 bytes are endless to move into eax. The opcode 0xb9 carries a constant into ecx. 0xba carries a constant into edx.
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Questions: 1. How can this motherboard support 8 GB of RAM with only fout 2. CHAPT Memory What memory features, if any, are used? (Select a ply) I parity non-parity IECCI registered fully bulleredbultered I SVD What memory modules are needed the customer was 3 of dualche RAM ties and how many of each capacity are required) 3. What memory slots will be used to install the memory, based on the information provided 5. Using the Internet, a computer parts magazine, or a list of memory modules, determine the cast per numbers and quantities of memory modules you would buy. List them, along with the location when you obtained the information. 6. Will it matter if the motherboard has tin contacts in the memory slots? Why or why not? 7. Can DDR memory modules be used with this motherboard? How can you tell? 8. If this motherboard already has 1 GB of RAM installed in the DIMMO_ChanA slot and the customer would like to upgrade to 2 GB of dual-channel RAM, what memory modules are needed? (What ca pacities and how many of each capacity are required) . What suggestions, if any, would you make to the customer before researching prices? 0. What memory slots will be used to install the memory, based on the information provided? Using the Internet, a computer parts magazine, or a list of memory modules, determine the exact part numbers and quantities of memory modules that you would buy. List them, along with the location where you obtained the information. To be able to determine the correct amount and type of memory to imalna Refer to Figure 6.24 and Table 6.11 to answer the questions. This motherboard The desktop board supports either single-ordual-channel memory configuration. The board has four 240-pin DDR2 SDRAM DIMM connectors with gold-plated con provides support for unbuffered, non-registered single or double-sided Most Install a matched pair of DIMMs equal in speed and size in Follow the directions for two DIMMs and add another matched Install a matched pair of DIMMs equal in speed and size in and DIMM1 of Channel A. Install a DIMM equal in speed and total size of the DIMMs installed in Channel A in either DOM All other memory configurations result in single-channel menu Exercise 6.2 Configuring Memory on Paper Objective: Parts: Internet access or access to magazines or ads that show memory prices Procedure: the following memory configurations • Up to 2 GB utilizing 256 MB technology • Up to 4 GB utilizing 512 MB or 1 GB technology • Up to 8GB utilizing 1 GB technology DDR2 533/667/800 MHz memory, and (SPD) memory only. Motherboard with four memory slots DIMMO_Chana DIMM1_Chana DIMMO ChanB DIMM1_ChanB FIGURE 6.24 Motherboard with four memory slots and two channels TABLE 6.11 Motherboard single-/dual-channel guidelines Installed memory Guidelines 2 DIMMs dual-channel of both Channel A and Channel B. 4 DIMMs dual-channel of DIMMs in DIMM1 of both Channels A and B. 3 DIMMs dual-channel DIMM1 of Channel B. Single-channel operation.
Answers
1. The memory support capacity of the motherboard can be determined by the capacity of each individual RAM slot on the motherboard. In this case, the motherboard has four 240-pin DDR2 SDRAM DIMM connectors, which can accommodate up to 8GB of RAM. This means that each RAM slot can support up to 2GB of memory.
2. The memory features used in this motherboard are unbuffered, non-registered single or double-sided DDR2 533/667/800 MHz memory, and (SPD) memory only. The motherboard supports parity, non-parity, ECC, registered, and fully buffered memory.
3. The customer needs 3 dual-channel RAM kits, and each kit should consist of a matched pair of DIMMs equal in speed and size. Therefore, the customer needs a total of 6 DIMMs.
4. Based on the information provided, the memory slots that will be used to install the memory are DIMM0 and DIMM1 of Channel A, and DIMM0 and DIMM1 of Channel B.
5. The cost, part numbers, and quantities of the memory modules depend on the customer's requirements and budget. The information can be obtained from computer parts magazines or online stores that sell memory modules.
6. Tin contacts in the memory slots can cause connectivity issues and affect the performance of the memory modules. Therefore, it is important to ensure that the memory modules have proper connectivity with the motherboard.
7. Yes, DDR memory modules can be used with this motherboard. The motherboard supports DDR2 SDRAM memory, which is backward compatible with DDR SDRAM memory.
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Which Statement Would Be Used To Declare A 10-Element Integer Array C? A. Array C; B. Array<10> C; C. Array C;
Answers
To declare a 10-element integer array C, the following statement to be used is:
C. int C[10];
The explanation for the same is as follows:
1. Declare: This term means defining the type and name of a variable in programming. In this case, you are declaring an array named "C".
2. Array: An array is a data structure that can store multiple values of the same data type, such as integers, in a contiguous block of memory.
3. 10-element integer array: This means the array should store 10 integers.
So, the correct statement is none of the options you provided. The right declaration is: `int C[10];`. This statement creates an integer array named "C" with space for 10 elements.
The correct question should be:
Which Statement Would Be Used To Declare A 10-Element Integer Array C? A. Array C; B. Array<10> C; C. int C[10];
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21. It doesn't really matter whether your adapters are clean as long as they're not worn.
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It doesn't really matter whether your adapters are clean as long as they're not worn is a true statement.
What is an adapter?An adapter is said to be a kind of a physical device that gives room for a single hardware or electronic interface to be plugged in(accommodated without loss of function) to another hardware or electronic interface.
An adapter is known to be an electronic device tht is often used in regards to electrical connections.
Note that an adapter can work even if they are dirty. Hence, It doesn't really matter whether your adapters are clean as long as they're not worn is a true statement.
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A local gym decides that one way to reduce its membership fees is by selling the electricity generated from workout machines back to the electricity company. To do this, the gym connects its exercise equipments to motor generators.
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Answer:
You didn't have a question
Explanation:
HELPPPPP Which option identifies the government agency responsible for monitoring the situation in the following scenario? A salmonella outbreak in 2012 was caused by frozen raw yellowfin tuna. More than 100 people became sick from eating the contaminated tuna. Food and Drug Administration Environmental Protection Agency Forest Service Department of Agriculture
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Answer:
Food and drug admin
Explanation:
Select the appropriate SDLC process model to develop the VHROM system.
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Software application life cycle simply means the application of standard practices to software applications building.
This is an incomplete information. Therefore, an overview of the software application life cycle will be given. It's the process of planning, creating, testing, and deployment of an information system.
Software application life cycle is divided into six steps which are planing requirements, designing, building, documentation, testing, deployment, and maintenance.
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Which claim does president Kennedy make in speech university rice ?
Answers
Answer: The United States must lead the space race to prevent future wars.
Explanation: Hope this helps
Answer:
The risk associated with entering the space race outweighs the possible benefits.
Explanation:
It's explaining it in the speech.