Given () = 23 − 52 + − 9 and
() = −3 + 6 + 3, which expression is
equivalent to () − () ?

Answers

Answer 1

Answer:

-32

Step-by-step explanation:

for the first answer it is = -38

and for the second one it is= 6

now the final answer....you simply subtract the 2nd from the 1st

it is equal to -32


Related Questions

Find C and a so that ​f(x)equalsCa Superscript x models the situation described. State what the variable x represents in your formula. There are initially 3000 ​bacteria, and this sample doubles in size every hour.

Answers

Answer: x represents the time period.

C= 3000 and a = 2

Step-by-step explanation:

The given equation is \(f(x)=Ca^x\) which is an exponential equation. (i)

The general form of the exponential equation is :

\(f(x)=Ab^x\)   (ii)

, where A = initial value and b= multiplicative factor, and x is the time.

As compare both of the equation in (i) and (ii) , we get

A= C , and b= a

Since there are initially 3000 ​bacteria, and this sample doubles in size every hour.

i.e. C= 3000 (Initial)  and a= 2 (multiplicative factor).

I am in need of assistance.

I am in need of assistance.

Answers

Answer:

A. x = 6.08, x = -0.58

Step-by-step explanation:

\(\displaystyle \frac{2x}{x-4}-\frac{2x-5}{x^2-10x+24}=\frac{-3}{x-6}\)

1. Factor the denominator.

\(\displaystyle \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}\)

2. Multiply the leftmost fraction by (x-6)/(x-6) to get common denominators.

\(\displaystyle \Big ( \frac{x-6}{x-6} \Big ) \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}\)

3. Simplify.

\(\displaystyle \frac{2x^2-12x}{(x-4)(x-6)}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}\)  

4. Combine like terms.

\(\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6}\)  

5. Multiply the right side of the equation by (x-4)/(x-4).

\(\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6} \Big ( \frac{x-4}{x-4} \Big )\)  

6. Simplify.

\(\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3x+12}{(x-6)(x-4)}\)

7. "Cancel" out the denominators because they are equivalent.

\(2x^2-14x+5=-3x+12\)

8. Set the equation equal to 0.

\(2x^2-11x-7=0\)

Quadratic formula:

\(\displaystyle x = \frac{-b\pm \sqrt{b^2-4ac} }{2a}\)  

9. Factor using the quadratic formula.

\(\displaystyle x = \frac{-(-11)\pm \sqrt{(-11)^2-4(2)(-7)} }{2(2)}\)

10. Multiply and simplify.

\(\displaystyle x = \frac{11 \pm \sqrt{177} }{4}\)

11. Plug this into your calculator and solve for x.

\(x=6.07603367 \approx 6.08\) \(x=-0.57603367 \approx -0.58\)

The correct answer is A. x = 6.08, x = -0.58.

question 3 a data analyst is working with the world happiness data in tableau. what tool do they use to select the area on the map representing finland?

Answers

Pan tool do the data analyst use to select the area on the map representing Finland.    

What is data analyst?

A data analyst is working with the world happiness data in table. To use Pan tool to select the area on the map representing Finland.

A data professional examines data to uncover critical insights about a company's consumers and how the data may be utilized to address problems. They also share this information with corporate executives and other stakeholders.

Pan allows us to shift the map to focus on it or present the areas in the way we wish. Simply pick the Pan Option and move the map around to suit your needs. Alternatively, you may move the map by holding down the Shift key.

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Eric bought a canoe for $330.00. The sales tax was 5%. What was the total cost for the canoe?

Answers

nice well have a good day

The product of Chau's height and 5 is 70.

Answers

Answer: 14

Step-by-step explanation: chau's height = x

x * 5 =70

5x = 70

x = 70/5

x = 14

Please solve as soon as possible!

Please solve as soon as possible!

Answers

The value of the different trigonometric ratios given are:

sin θ  = 0.923

tan θ = 2.4

sec θ = 2.6

How to solve Trigonometric ratios?

There are different trigonometric ratios such as:

sin x = opposite/hypotenuse

cos x = adjacent/hypotenuse

tan x = opposite/adjacent

We are given:

cos(θ) = 10/26, 0 ≤ θ ≤ π/2

Thus, sin θ and cos θ will be in the first quadrant based on the interval given. Thus:

cos⁻¹(10/26) = 1.176

sin 1.176 in radians  = 0.923

tan 1.176 in radians = 2.4

sec 1.176 = 1/cos 1.176 = 2.6

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find the error javier claimed that all cubic functions are odd. is he correct? if not, provide a counterexample.

Answers

Answer:

The cubic function f(x) = x3 is symmetric about the origin (it is an odd function). Here are some types of functions that are odd: Lines Through The Origin – any line with a zero y intercept (b = 0) and a nonzero slope (m not zero) will have equation f(x) = mx.

Step-by-step explanation:

Answer: No

f(x) = x³ + 2x − 5

Step-by-step explanation:

No

f(x) = x³ + 2x − 5

60 POINTS!!
Match the steps to solve the following equation using distributive property. 4 (2x - 6) = 24

60 POINTS!!Match the steps to solve the following equation using distributive property. 4 (2x - 6) =

Answers

Answer:

1) 8x - 24 = 24

2) 8x - 24 + 24 = 24 + 24

3) 8x = 48

4) x = 6

Step-by-step explanation:

Bolded are the answer choices:

4(2x - 6) = 24

First, distribute 4 to all terms within the parenthesis:

4(2x - 6) = 24

(4 * 2x) - (4 * 6)

(8x) - (24) = 24

8x - 24 = 24.

Next, add 24 to both sides of the equations:

8x - 24 (+24) = 24 (+24)

8x = 24 + 24

8x = 48

8x - 24 + 24 = 24 + 24

Then, divide 8 from both sides of the equation:

(8x)/8 = (48)/8

x = 48/8 = 6

8x = 48

x = 6

~

The famous identity:
cos(x) = 1/sec(x)
can be tweaked to produce the following identity/ies
a) 1 = cos(x) sec(x)
b) 0 = cos(x) sec(x) - 1
c) sec(x) cos(x) = 1
d) 0 = 1 - cos(x) sec(x)
e) cos(5θ) = 1/sec(5θ)
f) sec(x) = 1/cos(x)
(g) none of these

Answers

Option b) 0 = cos(x) sec(x) - 1 is the identity produced by tweaking the famous identity cos(x) = 1/sec(x)

The remaining options are not identities produced by tweaking cos(x) = 1/sec(x).

The given famous identity: cos(x) = 1/sec(x) can be rearranged to produce the identity 0 = cos(x) sec(x) - 1 by subtracting 1/sec(x) from both sides of the equation.

Therefore, The correct answer is option b) 0 = cos(x) sec(x) -1

The remaining options a), c), d), e), f), and g) are not identities produced by tweaking cos(x) = 1/sec(x).

Option a) is obtained by multiplying both sides of the given identity by sec(x).

Option c) is obtained by multiplying both sides of the given identity by cos(x).

Option d) is obtained by subtracting cos(x)/sec(x) from both sides of the given identity.

Option e) is a completely different identity that cannot be obtained from cos(x) = 1/sec(x) through tweaking.

Option f) is obtained by taking the reciprocal of both sides of the given identity.

None of the remaining options a), c), d), e), and f) is the correct identity produced by tweaking cos(x) = 1/sec(x).

Therefore, the correct answer is option b) 0 = cos(x) sec(x) - 1.

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find the distance between the two points rounding to the nearest 10th! PLS HELP ASAP!!!!

find the distance between the two points rounding to the nearest 10th! PLS HELP ASAP!!!!

Answers

Answer:

8.5

Step-by-step explanation:

d = √[(-7+1)²+(-1-5)²]

= √[(-6)²+(-6)²]

=√(36+36)

=√72

= 8.5

Answer:

8.5

Step-by-step explanation:

we can plug those coordinates into the distance formula

d =  √(x2 - x1)2 + (y2 - y1)2

d= √((-7)-(-1)^2+((-1)-(5)^2

d = √36+36

d=√72 = 8.48 or 8.5

Which function COULD be the one shown in the graph

Answers

Answer:

need the graph to know

Step-by-step explanation:

WILL MARK BRAINLIEST !!!!! ^^

WILL MARK BRAINLIEST !!!!! ^^

Answers

Answer:

A and D.

Step-by-step explanation:

You have to compare them and the temperature is at 45*.

9/5C - (F + 32).

5/9C = (F + 32).

Using the Wronskian in Problems 15-18, verify that the given functions form a fundamental solution set for the given differential equation and find a general solution. y'" + 2y" - 11y' - 12y = 0; {e^3x, e^-x, e^-4x}

Answers


Wronskian of a set of functions f, g, and h is defined as:

W(f, g, h) = | f g h |
| f' g' h' |
| f'' g'' h''|

where f', g', and h' denote the first derivatives of f, g, and h, respectively, and f'', g'', and h'' denote the second derivatives of f, g, and h, respectively.

Using this definition, we can calculate the Wronskian of the given functions as follows:

W(e^3x, e^-x, e^-4x) = | e^3x e^-x e^-4x |
| 3e^3x -e^-x -4e^-4x |
| 9e^3x e^-x 16e^-4x |

Expanding the determinant, we get:

W(e^3x, e^-x, e^-4x) = e^3x(-e^-x16e^-4x - (-4e^-4x)e^-x) - e^-x(e^3x16e^-4x - (-4e^-4x)e^3x) + e^-4x(e^3x(-e^-x) - 3e^3xe^-x)
= -20e^-x

Since the Wronskian is not zero, we can conclude that the given functions form a fundamental solution set for the differential equation.

To find a general solution to the differential equation, we can use the formula:

y(x) = c1y1(x) + c2y2(x) + c3*y3(x)

where y1(x), y2(x), and y3(x) are the given functions, and c1, c2, and c3 are arbitrary constants.

Substituting the given functions into the formula, we get:

y(x) = c1e^3x + c2e^-x + c3*e^-4x

Therefore, the general solution to the differential equation is:

y(x) = c1e^3x + c2e^-x + c3*e^-4x

where c1, c2, and c3 are arbitrary constants.

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#SPJ1AnswerThe Wronskian of a set of functions f, g, and h is defined as:

W(f, g, h) = | f g h |
| f' g' h' |
| f'' g'' h''|

where f', g', and h' denote the first derivatives of f, g, and h, respectively, and f'', g'', and h'' denote the second derivatives of f, g, and h, respectively.

Using this definition, we can calculate the Wronskian of the given functions as follows:

W(e^3x, e^-x, e^-4x) = | e^3x e^-x e^-4x |
| 3e^3x -e^-x -4e^-4x |
| 9e^3x e^-x 16e^-4x |

Expanding the determinant, we get:

W(e^3x, e^-x, e^-4x) = e^3x(-e^-x16e^-4x - (-4e^-4x)e^-x) - e^-x(e^3x16e^-4x - (-4e^-4x)e^3x) + e^-4x(e^3x(-e^-x) - 3e^3xe^-x)
= -20e^-x

Since the Wronskian is not zero, we can conclude that the given functions form a fundamental solution set for the differential equation.

To find a general solution to the differential equation, we can use the formula:

y(x) = c1y1(x) + c2y2(x) + c3*y3(x)

where y1(x), y2(x), and y3(x) are the given functions, and c1, c2, and c3 are arbitrary constants.

Substituting the given functions into the formula, we get:

y(x) = c1e^3x + c2e^-x + c3*e^-4x

Therefore, the general solution to the differential equation is:

y(x) = c1e^3x + c2e^-x + c3*e^-4x

where c1, c2, and c3 are arbitrary constants.

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A general solution

\(y(x) = c1e^{3x} + c2e^{-x} + c3*e^{-4x}\)

What is Wronskian?

To verify that the given functions form a fundamental solution set for the differential equation y''' + 2y" - 11y' - 12y = 0, we can use the Wronskian. The Wronskian is defined as:

W(x) = | y1(x) y2(x) y3(x) |

| y1'(x) y2'(x) y3'(x) |

| y1''(x) y2''(x) y3''(x) |

where y1(x), y2(x), and y3(x) are the given functions.

Using the given functions, we can compute the Wronskian as follows:

W(x) = |\(e^{3x} e^{-x} e^{-4x} || 3e^{3x} -e^{-x} -4e^{-4x} || 9e^{3x} e^{-x} 16e^{-4x}\)|

Expanding the determinant, we get:

\(W(x) = e^{3x}(-e^{-x}*16e^{-4x} + e^{-4x}e^{-x}) - (-e^{-x}(-4e^{-4x}) - (-e^{3x})*16e^{-4x})e^{3x} + (3e^{3x}(-e^{-x}*e^{-4x}) - e^{-x}*9e^{3x}*16e^{-4x})\)

Simplifying, we get:

W(x) = -23e^(-3x)

Since the Wronskian is nonzero everywhere, the functions {e^(3x), e^(-x), e^(-4x)} form a fundamental solution set for the differential equation.

To find the general solution of the differential equation, we can use the formula:

y(x) = c1y1(x) + c2y2(x) + c3*y3(x)

where c1, c2, and c3 are constants. Substituting the given functions, we get:

\(y(x) = c1e^{3x} + c2e^{-x} + c3*e^{-4x}\)

This is the general solution of the given differential equation.

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What is an equation of the line that passes through the points (-5, 1)(−5,1) and (5, 3)(5,3)?

Answers

Answer:

x=-5 i think

Step-by-step explanation:

Today, Andrew borrowed R200 000 from a bank. The bank charges interest at 5.25%p.a, a compounded quarterly. Andrew will make make payments of R6 000 at the end of 3 months. His first repayment will be made 3 months from now, how long in years will it take for Andrew to settle the loan

Answers

In order to calculate the time it will take for Andrew to settle the loan, we can use the formula for compound interest. So, it will take Andrew approximately 5.22 years to settle the loan.

The formula is given as A = P(1 + r/n)^(nt), Where: A = the final amount, P = the principal (initial amount borrowed), R = the annual interest rate, N = the number of times the interest is compounded in a year, T = the time in years.

We know that Andrew borrowed R200 000 from a bank at an annual interest rate of 5.25% compounded quarterly and that he will make repayments of R6 000 at the end of every 3 months.

Since the first repayment will be made 3 months from now, we can consider that the initial loan repayment is made at time t = 0. This means that we need to calculate the value of t when the total amount repaid is equal to the initial amount borrowed.

Using the formula for compound interest: A = P(1 + r/n)^(nt), We can calculate the quarterly interest rate:r = (5.25/100)/4 = 0.013125We also know that the quarterly repayment amount is R6 000, so the amount borrowed minus the first repayment is the present value of the loan: P = R200 000 - R6 000 = R194 000

We can now substitute these values into the formula and solve for t: R194 000(1 + 0.013125/4)^(4t) = R200 000(1 + 0.013125/4)^(4t-1) + R6 000(1 + 0.013125/4)^(4t-2) + R6 000(1 + 0.013125/4)^(4t-3) + R6 000(1 + 0.013125/4)^(4t)

Rearranging the terms gives us: R194 000(1 + 0.013125/4)^(4t) - R6 000(1 + 0.013125/4)^(4t-1) - R6 000(1 + 0.013125/4)^(4t-2) - R6 000(1 + 0.013125/4)^(4t-3) - R200 000(1 + 0.013125/4)^(4t) = 0

Using trial and error, we can solve this equation to find that t = 5.22 years (rounded to 2 decimal places). Therefore, it will take Andrew approximately 5.22 years to settle the loan.

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Solve the problem using a system of equations in two variables.
Find two positive numbers whose squares have a sum of 125 and a difference of 75.

Answers

Solving a system of equations we can see that the two positive numbers are x = 10 and y = 5.

How to find the two numbers?

Let's say that the two numbers are x and y, then we can write the system of equations:

x² + y² = 125

x² - y² = 75

We can isolate x² in the second equation to get:

x² = 75 + y²

And replace that in the first one, then:

75 + y² + y² = 125

2y² = 125 - 75

2y² = 50

y² = 50/2

y² = 25

y = √25 = 5

And now let's find the value of x:

x² = 75 + y²

x² = 75 + 25

x² = 100

x = √100 = 10

These are the two numbers.

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F=3xyi+6yj+5k is the velocity field of a fluid flowing through a region in space. Find the flow along the given curve r(t)=ti+(t^2)j+k between t=0 and t=4 in direction of increasing t

Answers

To find the flow along the curve r(t) = ti + (t^2)j + k between t = 0 and t = 4 in the direction of increasing t, we need to evaluate the line integral of the velocity field F along the curve. The line integral is given by:

∫ F · dr = ∫ (3xyi + 6yj + 5k) · (dx/dt)i + (dy/dt)j + (dz/dt)k

We can calculate the differentials dx, dy, and dz by taking the derivatives of the components of r(t) with respect to t:

dx/dt = 1, dy/dt = 2t, dz/dt = 0

Substituting these values, we have:

∫ F · dr = ∫ (3xy)(1) + (6y)(2t) + (5)(0) dt

           = ∫ 3xy + 12yt dt

Since we are integrating with respect to t, we can treat x and y as constants. Integrating each term separately, we get:

∫ 3xy dt = 3xyt

∫ 12yt dt = 6yt^2

Finally, we evaluate the integral from t = 0 to t = 4:

∫ F · dr = [3xyt] from 0 to 4 + [6yt^2] from 0 to 4

           = 3xy(4) + 6y(4^2) - (3xy(0) + 6y(0^2))

           = 12xy + 96y

So, the flow along the given curve in the direction of increasing t is 12xy + 96y.

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write out the first five terms of the sequence with, [(1−3 8)][infinity]=1, determine whether the sequence converges, and if so find its limit. enter the following information for =(1−3 8). Enter the following information for an=(1−3 8)nan=(1−3 8)n.
a1=a1=
a2=a2=
a3=a3=
a4=a4=
a5=a5=
limn→[infinity](1−3 8)n=limn→[infinity](1−3 8)n=
(Enter DNE if limit Does Not Exist.)
Does the sequence converge (Enter "yes" or "no").

Answers

The limit of the sequence is 0.

To determine the first five terms of the sequence, we substitute n = 1, 2, 3, 4, 5 into the expression (1 - 3/8)^n.

a1 = (1 - 3/8)^1 = 5/8

a2 = (1 - 3/8)^2 = 25/64

a3 = (1 - 3/8)^3 = 125/512

a4 = (1 - 3/8)^4 = 625/4096

a5 = (1 - 3/8)^5 = 3125/32768

To determine whether the sequence converges, we observe that the expression (1 - 3/8)^n approaches 0 as n approaches infinity. Therefore, the sequence converges to 0.

The limit of the sequence as n approaches infinity is given by:

lim(n→∞) (1 - 3/8)^n = 0

Thus, the limit of the sequence is 0.

The information for the sequence (an = (1 - 3/8)^n) is as follows:

a1 = 5/8

a2 = 25/64

a3 = 125/512

a4 = 625/4096

a5 = 3125/32768

lim(n→∞) (1 - 3/8)^n = 0

The sequence converges to 0.

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A television station claims that the amount of advertising per hour of broadcast time has an average of 16 minutes and a standard deviation equal to 1.4 minutes. You watch the station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 8 minutes. Calculate the z-score for this amount of advertising time. Group of answer choices

Answers

Answer:

-4.29

Step-by-step explanation:

The computation of the z score is shown below:

data provided in the question

Average minutes = 16 minutes

Standard deviation = 1.4 minutes

Amount of advertising time = 8 minutes

Based on the above information, the z score is

\(= \frac{x-m}{\sigma} \\\\ = \frac{8-14}{\1.4} \\\\ = \frac{-6}{1.4}\)

= -4.29

Hence, the z score is -4.29. It is come by considering the above formula

A radio tower is located on a coordinate system measured in miles. The range of a signal in a particular direction is modeled by a quadratic function where the boundary of the signal starts at the vertex at (4, 2). It passes through the point (5, 4). A linear road connects points (–3, 7) and (8, 2). Which system of equations can be used to determine whether the road intersects the boundary of the tower’s signal?

Answers

im sorry i dont know the answer

Suppose A={a, b,c}and B = {b,{c}}. True or false? |AUB| = 5

Answers

A set B is considered a subset of another set A if and only if every element of B is also an element of A.

To check if one set is a subset of another, we need to ensure that every element of the first set is also an element of the second set. In this case, set B consists of two elements: 'True or False' and the set {C}.

Let's analyze each element individually:

'True or False':

The set A, on the other hand, only contains the elements 'a', 'b', and 'c'. It does not contain 'True or False'. Therefore, 'True or False' is not an element of set A. As a result, this element alone is sufficient to prove that B is not a subset of A.

{C}:

The set A contains the elements 'a', 'b', and 'c'. It does not contain the set {C}. Thus, {C} is also not an element of set A.

Since both elements in set B are not elements of set A, we can conclude that B is not a subset of A, represented as B ⊆ A.

In our example, set B has elements ('True or False' and {C}) that are not present in set A, making B not a subset of A.

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Complete Question:

Suppose A = {a,b,c} and B = {b, {C}}.

Please determine whether the following statements are True or False.

B ⊆ A

Angle RST is a right angle. Angle RSU has a measure of 25°.

Lines R S and S T connect to form a right angle. Another line extends from point S to point U. Angle R S U is 25 degrees.
What is the measure of angle TSU?

25°
45°
65°
75°

Answers

Therefore, angle SUT is a right angle. Hence, its measure is 90 degrees.

Given that angle RST is a right angle. We know that a right angle is equal to 90 degrees. Therefore, we can write angle RST as m ∠RST = 90 degrees.It is also given that angle RSU has a measure of 25 degrees. We can write this as m ∠RSU = 25 degrees. Now, let's consider angle STU.

We know that the sum of the angles in a triangle is equal to 180 degrees.

Therefore, we can write:

m ∠RST + m ∠RSU + m ∠STU = 180 degrees.

Substituting the values we have, we get:

90 degrees + 25 degrees + m ∠STU = 180 degrees

115 degrees + m ∠STU = 180 degrees

∠STU = 180 degrees - 115 degrees ∠STU = 65 degrees

Now we know that angle STU has a measure of 65 degrees.Now, we need to find the measure of angle SUT. We know that the sum of angles in a triangle is equal to 180 degrees.

Therefore, we can write:

m ∠STU + m ∠SUT + m ∠RSU = 180 degrees

Substituting the values we have, we get:

65 degrees + m ∠SUT + 25 degrees = 180 degrees

90 degrees + m ∠SUT = 180 degrees

∠SUT = 180 degrees - 90 degrees

∠SUT = 90 degrees

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combine like terms to simplify the expression 9/8a + 4/8a - 5/8

Answer choices
A. 8/11a + 1/4
B. 13/8 - 5/8
C. 7/8a + 8/5
D. 5/8a - 5/8

Answers

Answer:

13/8a - 5/8

Step-by-step explanation:

the only terms you can combine are 9/8a and 4/8a. You can add the fractions together to create 13/8a. the -5/8 can't be combined since it doesn't have an a

13/8a - 5/8

What value of x is the solution to the equation −32x−34=−15
?

A
−1930
B
3340
C
−1920
D
−1130

Answers

Answer:

x=-19÷32

Step-by-step explanation:

so that is my own answer when I calculate it

The new science and math building on campus has four elevators each designed to carry a maximum 8 people. A building safety study has found that the combined weight of 8 people can be modeled by normal distribution with mean of 1400 pounds and a standard deviation of 120 pounds. 0.7887 0.1056 0.1056 1 -3 -2 F 1 -1.25 1.25 Using the figure of a standard normal distribution, is the following statement valid or not valid? We would expect the total weight of 8 people to be between 1250 and 1550 pounds more than 75% of the time.

Answers

The total weight of 8 people to be more than 1500 pounds less than 20% of the time.

The new science and math building on campus has four elevators each designed to carry a maximum 8 people.

A building safety study has found that the combined weight of 8 people can be modeled by normal distribution with mean of 1400 pounds and a standard deviation of 120 pounds.

Given

mean = 1400

standard deviation = 120

P(X > 1500) = P((x-u)/s > (1500 - 1400)/120)

= P(z > 0.83)

= 0.2032694 [since from z table]

= 0.2033

= 20%

So we would expect the total weight of 8 people to be more than 1500 pounds less than 20% of the time.

Hence the answer is the total weight of 8 people to be more than 1500 pounds less than 20% of the time.

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please help, i will mark you branniest :))

solve for k

3/k = 4/5

Answers

Answer:

3/k = 4/5

k = 3 divided by 4/5

k = 3.75

Step-by-step explanation:

What do the coordinates of an undefined slope have in common?

Answers

The coordinates of an undefined slope are points that are either the same or have no x-value. In both cases, the slope of a line between these points would be undefined because it would involve dividing by 0, which is not allowed in mathematics. This is because the slope of a line is calculated by dividing the difference in y-coordinates by the difference in x-coordinates, and if the x-coordinates are the same or do not exist, this division would result in an undefined value.

Write an exponential function in the form y=ab^x that goes through points (0, 18) and (9,9216).

Answers

\(y=ab^x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{we know that}}{x=0\qquad y=18}\qquad 18=ab^0\implies 18=a(1)\implies 18=a~\hfill \underline{y=18b^x} \\\\\\ \stackrel{\textit{we also know that}}{x=9\qquad y=9216}\qquad 9216=18b^9\implies \cfrac{9216}{18}=b^9 \\\\\\ 512=b^9\implies \sqrt[9]{512}=b\implies 2=b~\hfill \underline{y=18(2)^x}\)

complete this item. (enter letter variables in alphabetical order.) rewrite the expression so that it has no denominator.

Answers

The given expression is $\frac{6}{t}+\frac{8}{u}-\frac{9}{v}$ and we need to rewrite this expression without any denominator in it. Step-by-step explanation: We can use the concept of the Least Common Multiple (LCM) of the denominators to remove the fractions in the expression. By taking the LCM of the denominators of the given expression, we have,$LCM\text{ of }t, u, v = t \cdot u \cdot v$ Now, multiplying each term of the given expression with the LCM $t \cdot u \cdot v$, we get,$\frac{6}{t}\cdot t \cdot u \cdot v+\frac{8}{u}\cdot t \cdot u \cdot v-\frac{9}{v}\cdot t \cdot u \cdot v$$6uv + 8tv - 9tu$$\therefore \text{The given expression without any denominator is } 6uv + 8tv - 9tu.$Thus, we can rewrite the given expression $\frac{6}{t}+\frac{8}{u}-\frac{9}{v}$ without any denominator in it as $6uv + 8tv - 9tu$.

LCM (a,b) in mathematics stands for the least common multiple, or LCM, of two numbers, such as a and b. The smallest or least positive integer that is divisible by both a and b is known as the LCM. Take the positive integers 4 and 6 as an illustration.

There are four multiples: 4,8,12,16,20,24.

6, 12, 18, and 24 are multiples of 6.

12, 24, 36, 48, and so on are frequent multiples for the numbers 4 and 6. In that lot, 12 would be the least frequent number. Now let's attempt to get the LCM of 24 and 15.

LCM of 24 and 15 is equal to 222235 = 120.

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whats the correct equation to solve for x

whats the correct equation to solve for x

Answers

Answer:

12x - 29 + 4x + 1 = 180

Step-by-step explanation:

(12x - 29) and (4x + 1) are same- side interior angles and sum to 180° , then

12x - 29 + 4x + 1 = 180 ← is the equation to solve for x

16x - 28 = 180 ( add 28 to both sides )

16x = 208 ( divide both sides by 16 )

x = 13

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