give the type of triangle that has these angles

27 degrees
63 degrees
91 degrees

The estimated population mean weight of squash is 5. This means that on average, the squash in the population weigh 5 pounds.

The population mean weight of squash can be estimated using the sampling distribution of squash. The sampling distribution is a probability distribution that shows the possible values of the sample mean and the corresponding probabilities. In this case, the sampling distribution is given as follows:

Sample mean weight of squashProbability30.140.250.460.270.1

To estimate the population mean weight of squash, we can calculate the expected value of the sampling distribution. The expected value is the weighted average of the possible values of the sample mean, where the weights are the corresponding probabilities. The formula for the expected value is:

E(X) = ∑xP(X=x)

Where X is the sample mean weight of squash, x is a possible value of X, and P(X=x) is the probability of X being equal to x.

Using the formula, we can calculate the expected value of the sampling distribution as follows:

E(X) = (3)(0.1) + (4)(0.2) + (5)(0.4) + (6)(0.2) + (7)(0.1) = 0.3 + 0.8 + 2 + 1.2 + 0.7 = 5

Therefore, the estimated population mean weight of squash is 5. This means that on average, the squash in the population weigh 5 pounds.

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The IQ of students has a mean of 110 and an SD of 18. If 43 students are randomly sampled, the probability that the average IQ of this group is greater than 100 is P(Z > (100-110)/(18/√43)).

Given, that the IQ of students has a mean of 110 and SD of 18.

Number of students randomly sampled, n = 43.

The formula to calculate the probability is:

P(Z > (100-110)/(18/√43))

Now, substituting the values in the above formula:

P(Z > (100-110)/(18/√43))= P(Z > -2.365)= 1 - P(Z < -2.365)

This can be obtained by referring to standard normal tables or using a calculator.

Now, P(Z < -2.365) can be obtained by referring to standard normal tables or using a calculator.

Using a calculator, we get P(Z < -2.365) = 0.009 or 0.01 (rounded off to two decimal places).

So, P(Z > -2.365) = 1 - 0.01 = 0.99.

The probability that the average IQ of this group is greater than 100 is 0.99.

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answer

600minutes = 10hours

Step-by-step explanation:

• Convert 1 and half hour to minutes and it becomes 90minutes.

• divide 300pages by 45pages and multiply by 90minutes.

•Then convert 600minutes to hours.

goodluck

Eukaryotic cells have a true membrane-bound nucleus and prokaryotes do not.

Eukaryotic cells are larger than prokaryotic cells and have a “true” nucleus, membrane-bound organelles, and rod-shaped chromosomes. The nucleus houses the cell's DNA and directs the synthesis of proteins and ribosomes.

All cells have a plasma membrane, ribosomes, cytoplasm, and DNA. Prokaryotic cells lack a nucleus and membrane-bound structures. Eukaryotic cells have a nucleus and membrane-bound structures called organelles.

So..the answer should be Eukaryotic cells have a true membrane-bound nucleus and prokaryotes do not.

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Answer:

Prokaryotes

✔ do not have

a nucleus surrounding their chromosome of DNA.

Prokaryotes are

✔ more

simple cells than eukaryotes.

Prokaryotes have a

✔ cell wall

outside their cell membrane that gives protection and support.

Prokaryotes will often move by a tail-like

✔ flagellum

.

Step-by-step explanation:

Answer:

D 1/25

Step-by-step explanation:

5 multiplied by the negative second power is .04, .04 times 25 equals 1.

Step-by-step explanation:

There's no slope and y-intercept in such a question, maybe you should try typing a valid question for an effective answer.

=========================================================

Explanation:

gradient = slope

Pick any two points on the diagonal line and use the slope formula.

I'll pick the two points (0,4) and (4,10)

\((x_1,y_1) = (0,4) \text{ and } (x_2,y_2) = (4,10)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{10 - 4}{4 - 0}\\\\m = \frac{6}{4}\\\\m = \frac{3}{2}\\\\\)

The slope is 3/2.

Meaning we go up 3 and to the right 2.

In order to find the fractions that are equivalent to whole numbers, we can convert each fraction to its decimal form.

So we have that:

So the fractions that are equivalent to whole numbers are 5/5 and 10/1.

The system of linear equations which has the rank of coefficient matrix equal to augmented matrix and equal to the number of unknowns, has only one solution called the unique solution.

Two types of system of equations exist- consistent and inconsistent.

Inconsistent means that it has no solution , i.e. the solution does not exist , here

Rank of augmented matrix is not equal to that of coefficient matrix.

Consistent system means a solution of the equation exists i.e.

rank of augmented matrix = rank of coefficient matrix.

Now, a consistent system can be of two types again - It may have a unique solution ,i.e.

rank of augmented matrix = rank of coefficient matrix = no. of unknowns

or an infinite number of solutions, where

rank of augmented matrix = rank of coefficient matrix < no. of unknowns   (here we need to assign an arbitrary value to a free variable to find its solutions).

For e.g. let us consider the system -

x + y+ z = 0

2x + 3y + 4z = 1

Since , (0,0,0) is obviously satisfying the equation and so is a solution to this system , the given system is a consistent system .

Also, for a system to be consistent , either a unique solution exists or an infinite number of solutions exist. There is no particular number of solutions.

Here, we see that (-1,1,0) is also a solution other than the zero solution.

We can clearly see that the number of unknown variables , x,y,z is 3 and the number of equations is 2.

Thus, The system if there are fewer equations than variables has infinite solutions, equal number of equations as the unknowns has the unique solution.

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Answer: 2x = 1/2

You just have to simplify the expression

Hope this helps !

The 95% confidence interval for the difference between the two population proportions is -0.022 < p₁ - p₂ < 0.222.

Given that,

In a survey, it was discovered that 68% of women and 78% of men preferred computer-assisted education to lectures, respectively. Each sample contained 100 people that were chosen at random.

We have to calculate the 95% confidence range for the difference between the two proportions.

We know that,

The 95% confidence interval for difference between two population proportions is given as follows :

\(((\bar p_{1} -\bar p_{2})\)±\(Z_{0.05/2}\sqrt{\frac{PQ}{n_{1} } +\frac{PQ}{n_{2} }} })\)

Here,

p₁ is 0.78

p₂ is 0.68

n₁ is 100

n₂ is 100

Z is 1.96

P is 0.73

Q is 0.27

So,

((0.78-0.68)±\(1.96\sqrt{\frac{(0.73)(0.27)}{100 } +\frac{(0.73)(0.27)}{100 }} })\)

(0.10±0.122)

(0.10-0.122,0.10+0.122)

(-0.022,0.222)

Therefore, The 95% confidence interval for the difference between the two population proportions is -0.022 < p₁ - p₂ < 0.222.

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A. The power of the two-tailed hypothesis test with α = .05 is 0.53.

B. The power of the one-tailed hypothesis test with α = .05 is 0.95.

A hypothesis test is used to make decisions about a population based on sample data. It involves specifying a null hypothesis, collecting data, and then assessing the data to either reject or accept the null hypothesis.

A. The power of the two-tailed hypothesis test is calculated using the formula:

Power=

1- β=1- (1-α)\(^{1/2}\)

=1- (1-0.05)\(^{1/2}\)

=0.525

=0.53

This means that the researcher has an 53% chance of correctly rejecting the null hypothesis that there has been no change in the IQ over the past 10 years.

B. The power of the one-tailed hypothesis test is calculated using the formula:

Power=

1- β=1- α

=1- 0.05

= 0.95

This means that the researcher has a 95% chance of correctly rejecting the null hypothesis that there has been no increase in the IQ over the past 10 years.

This is a higher power than the two-tailed test because the one-tailed test focuses on detecting an increase in the IQ, while the two-tailed test can detect both an increase or decrease in the IQ.

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Based on the cost of the homes in the area, the down payment that needs to be paid is $100,000.

The down payment that will be paid is the cost of the house less the amount that is paid for mortgages.

Cost = $250,000

Mortgages = $150,000

The down payment is therefore:

= Cost - mortgages

= 250,000 - 150,000

= $100,000

In conclusion, the down payment is $100,000.

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Yes, the information provided regarding the two pairs of congruent angles so one pair with corresponding congruent sides is sufficient to demonstrate the congruence of two triangles.

Congruent refers to things that are exactly the same size and shape.

For the stated question-

The following are the steps:

Thus, the information provided regarding the two pairs of congruent angles so one pair with corresponding congruent sides is sufficient to demonstrate the congruence of two triangles.

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The given equation is expressed as

Answer:

r = 5 miles

Step-by-step explanation:

\(Radius (r) = ?\\Volume = 392.5\\Height (h) = 15\\ V = \frac{1}{3}*pi*r^{2} *h\\392.5= \frac{1}{3} * 3.14 *r^{2} *15\\392.5 * 3 = 1* 3.14 * r^{2} *15\\1,177.5 = 47.1r^{2} \\Divide - both - sides - of -the - equation by 47.1\\r^{2} = 25\\Square -root-both-side-to-eliminate-the-square\\\sqrt{r}^{2} =\sqrt{25} \\r = 5\\r =5 miles\)

Answer:

The answer is -2x+10

Step-by-step explanation:

Hope this helps

A) The number of students who like both drinks is 325.

B) The number of students who like one of these drinks only. 275

A Venn diagram is used to visually represent the differences and the similarities between two concepts.

Total students= 900

students like tea=600

students like coffee=500

Students did not like both drinks=125

Students who both or any one of the drinks= 900-125=725

Now,

students like both drinks= 600+500-725

                                         = 325

Hence, the number of students who like both drinks is 325.

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(a) The probability that there are less than 2 accidents occur between 3-7pm is 0.2465.

(b) The probability that the next accident occurred within 30 minutes on both days is 0.1358.

Suppose that accidents occur at a rate of 1 per hour from 3-5pm and 6-7pm, and 4 per hour from 5-6pm as Poisson process.

(a) We have to determine the probability that there are less than 2 accidents occur between 3-7pm.

We may use the Poisson distribution to determine the likelihood that there would be less than two accidents between 3 and 7 pm.

The total of the rates for each individual hour represents the rate of accidents during this time period, which is

= 1 + 1 + 4 + 1

= 7 accidents per hours

So the Poisson variable λ = 7

So the probability that there are less than 2 accidents occur between 3-7pm is:

P(X < 2) = P(X = 0) + P(X = 1)

P(X < 2) = \(e^{-7}\) × (7^0/0!) + \(e^{-7}\) × (7^1/1!)

After simplifying

P(X < 2) = 0.2465

(b) Suppose that on day 1, there was an accident at 3pm and on day 2, at 5pm, then we have to determine the probability that the next accident occurred within 30 minutes on both days.

Since accidents occur in a Poisson process, we may use the Poisson distribution to determine the likelihood that an accident will occur within the next 30 minutes.

Since there are 4 accidents every hour between 5 and 6 o'clock, the likelihood that one will happen in the next 30 minutes is:

P(X = 1) = \(e^{-1}\) × (1^1 / 1!)

P(X = 1) = 0.3679

The likelihood that the following event will occur within 30 minutes on both days would thus be

= 0.3679 × 0.3679

= 0.1358

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Adding a tracking variable to count the number of times a loop executes can be an effective way to measure the answer choice's truthfulness.

Adding a tracking variable to count the number of loop executions can indeed be a useful technique for various purposes. By incrementing the tracking variable within the loop, we can keep track of the number of times the loop body is executed. This information can be valuable in measuring the accuracy or efficiency of the loop and evaluating the truthfulness of an answer choice.

For example, when comparing different algorithms or approaches, counting loop iterations can help determine which solution performs better. It provides a quantitative measure to assess time complexity or resource usage. Additionally, the tracking variable can be used to validate the correctness of a loop by ensuring that the expected number of iterations is reached.

By monitoring the loop execution count, we can gain insights into the behavior of the code, identify potential issues such as infinite loops, and make informed decisions based on the observed results. Hence, adding a tracking variable to count loop executions can be an effective technique to measure the truthfulness or performance of an answer choice in certain scenarios.

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Answer:

V= 3180.87

Step-by-step explanation:

to know radius=

radius*2= diameter

reverse it to find radius

45 feet= radius*2

45 ÷2= radius = 22.5

\(V= \pi r^2\frac{h}{3}\) equation to find volume of a cone

\(V=\pi 22.5^2\frac{12}{3}\)  12 is from height

V≈ 6361.72512

Rounded V= 6361.73

Tank is half full so divide by 2

6361.73 ÷ 2= 3180.865

Rounded: V= 3180.87

The probability that the coin lands heads up six times in a row is 0.016

Probability is the term used in mathematics to understand how likely an event is to happen or can also be described as how likely it is that a proposition is true.

It can be determined by dividing the favorable outcomes or events by the total number of outcomes.

As the coin has two sides, the probability that when the coin lands, it lands heads up is determined as follows;

Probability = 1 / 2

Now the probability that the coin lands heads up six times in a row can be calculated as follows;

Probability = (1^6) / (2^6)

Probability = 1 / 64

Probability = 0.015625

Rounding it to three decimal places as follows;

Probability = 0.015625 = 0.016

Therefore, the probability that the coin lands heads up six times in a row is calculated to be 0.016

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Answer:

3n - 7 = 2n + 5

Step-by-step explanation:

n=12

that is the answer

Answer:

55

Step-by-step explanation:

its subtracting 15 each time

Answer:

55 and the pattern is 15... i think

Step-by-step explanation:

The vectors x and y that satisfy the given conditions are:

x = [1, 0, 0],

y = [0, 1, 0].

Vectors x and y satisfying the given conditions, we need to solve the equations:

||A|| ||x|| = ||AX||,

and

||A||cs = ||Ay||.

Given the matrix A:

A = [3 0 -3]

[1 0 2]

[4 -1 -2]

We can calculate ||A|| by finding the square root of the sum of the squares of its elements:

||A|| = √(3² + 0² + (-3)² + 1² + 0² + 2² + 4² + (-1)² + (-2)²)

= √(9 + 9 + 1 + 4 + 16 + 1 + 4) = √44

= 2√11.

Now, let's find x and y:

For x, we want ||x|| = 1. We can choose any vector x with length 1, for example:

x = [1, 0, 0].

For y, we also want ||y|| = 1. Similarly, we can choose any vector y with length 1, for example:

y = [0, 1, 0].

Now, let's calculate the remaining expressions:

||AX|| = ||A × x||

= ||[3, 0, -3] × [1, 0, 0]||

= ||[3, 0, -3] × [0, 1, 0]||

= ||[0, 0, 0]||

= √(0² + 0² + 0²)

= 0.

Therefore, we have:

||A|| ||x|| = ||AX|| = 2√11 × 1 = 2√11,

and

||A||cs = ||Ay|| = 2√11 × 0 = 0.

So the vectors x and y that satisfy the given conditions are:

x = [1, 0, 0],

y = [0, 1, 0].

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Answer:

domain: x<2 or x>2

x-intercepts: (3/2, 0), (-3/2, 0)