Give the perpendicular slope of the given line y=8/3x-4

These points can be described the following double inequality:  -3≤x≤13.

Inequality is a mathematical expression that does not present equality between both sides. It is represented by symbols: <, ≤, > and ≥.

When the variable x is between the both extremes, the inequality will be called double inequality. Therefore, the double inequality can be written in the form below .

As the interval is represented by a closed dot, your interval inequality must be represented by signs ≤ or ≥.

Thus, the points of this question can be described as: -3≤x≤13.

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The statements that will be true about parallelogram ABCD are: A, B, D, and E.

Properties of a Parallelogram -

Diagonals of a parallelogram bisect each other into congruent segments.

Opposite angles and sides of a parallelogram are always congruent.

Alternate interior angles are always congruent in measure.

Thus, the following would be true of parallelogram ABCD:

AP ≅ CP (congruent segment's of a bisected diagonal)

BC ≅ AD (congruent opposite sides)

∠CAD ≅ ∠ACB (congruent angles)

∠BPC ≅ ∠APD (congruent angles)

Therefore, the statements that will be true about parallelogram ABCD are: A, B, D, and E.

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Answer:

A. 22.75 divided by 7 which would equal 3.25 B. the answer would be 3.25 for each cat toy

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Both the exponential and logarithmic functions tend to infinity.

The area of the base of the right triangle is calculated as: d. 28 m².

The area of a right triangle is expressed as, area = 1/2 × b × h, where we have:

h as the height of the right triangle

b as the length of the base of the right triangle

Given the following about the right triangle:

height of the right triangle (h) = 8 m

length of the base of the right triangle = 7 m

Area of the right triangle = 1/2 × b × h = 1/2 × 7 × 8

Area of the right triangle = 28 m²

Thus, the area of the base of the right triangle is calculated as: d. 28 m².

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192.78

Hope this helps!

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Answer:

192.78

Step-by-step explanation:

0.34 X 567 = 192.78

On solving the provided question we can say that - correlation coefficient of the question is r = \(\frac{S_{xy} }{\sqrt{S_{xx} S_{yy} } }\) =  -0.91

The Pearson's correlation coefficient, also known as the Pearson's r, Pearson's product-moment correlation coefficient, bivariate correlation, or simply correlation coefficient, is a statistical indicator of the linear relationship between two sets of data.

\(S_{xx} =\)∑\(x^2\) - (∑x\()^2\) /n = 19300- ((420)^2 /10)= 1660

\(S_{yy} =\) ∑\(y^2\) (∑y\()^2\)/n = 7454- ((270)^2 /10) = 164

\(S_{xy} =\)∑\((xy)^2\)/n -475

The correlation coefficient is:

r = \(\frac{S_{xy} }{\sqrt{S_{xx} S_{yy} } }\) =  -0.91

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Answer: \(11250\pi \\\) cm^3

Step-by-step explanation:

This could be solved with integral calculus or simple arithmetic.  

If you need to show the work in calculus, let me know, otherwise, here's the easiest way to reach the answer:

Volume of a solid is equal to the area of its 2D projection multiplied by its height, assuming that it's uniform throughout its entire height.  Fortunately, a cylinder is uniform throughout its height.  

What is a cylinder's 2D projection?  A circle!

Area of a circle = \(\pi r^{2}\)

r = 15

Area = 225pi cm^2

Now, we multiply the area of the 2D projection by the height of the cylinder.

225pi * 50 = 11250pi cm^3

Answer:

a.{a b, a c, a d, b c, b d, c d, b a, d c ,d b, c a, d a, c b}

b.{a b, a c, a d, a e ,a f, a g, b c, bd,be,bf,bg,cd,ce,cf,cg,fg,ba,ca,da,ea,fa,ga,cd,db,eb,fb,gb,dc,ec,fc,gc,fe,ge,gf,de,df,dg,ed,fd,gd,ef,eg}

c.{d d, dg, g d, g g}

d.{dg, g d, gg}

Step-by-step explanation:

We have to find the sample space

a. We are given items

{a, b, c, d}

Therefore, the sample space

{a b, a c, a d, b c, b d, c d, b a, d c ,d b, c a, d a, c b}

b. Items

Therefore, the sample space

{a b, a c, a d, a e ,a f, a g, b c, bd,be,bf,bg,cd,ce,cf,cg,fg,ba,ca,da,ea,fa,ga,cd,db,eb,fb,gb,dc,ec,fc,gc,fe,ge,gf,de,df,dg,ed,fd,gd,ef,eg}

c.

Defective items (d)=4

Good items(g)=20

Therefore, the sample space

{d d, dg, g d, g g}

d.

Defective items (d)=1

Good items(g)=20

Therefore, the sample space

{d g, g d, g g}

Given dimensions of the room:

Length: \(\displaystyle\sf 12.5 \,m\)

Width: \(\displaystyle\sf 9 \,m\)

Height: \(\displaystyle\sf 7 \,m\)

Area of each wall:

\(\displaystyle\sf Area_1 = 12.5 \times 7 = 87.5 \,m^2\)

\(\displaystyle\sf Area_2 = 12.5 \times 7 = 87.5 \,m^2\)

\(\displaystyle\sf Area_3 = 9 \times 7 = 63 \,m^2\)

\(\displaystyle\sf Area_4 = 9 \times 7 = 63 \,m^2\)

Area of each door:

\(\displaystyle\sf Area_{\text{door}} = 2.5 \times 1.2 = 3 \,m^2\)

Area of each window:

\(\displaystyle\sf Area_{\text{window}} = 1.5 \times 1 = 1.5 \,m^2\)

Total area occupied by doors:

\(\displaystyle\sf Total_{\text{doors}} = 2 \times Area_{\text{door}} = 2 \times 3 = 6 \,m^2\)

Total area occupied by windows:

\(\displaystyle\sf Total_{\text{windows}} = 4 \times Area_{\text{window}} = 4 \times 1.5 = 6 \,m^2\)

Total wall area excluding doors and windows:

\(\displaystyle\sf Total_{\text{wall\,area}} = (Area_1 + Area_2 + Area_3 + Area_4) - Total_{\text{doors}} - Total_{\text{windows}}\)

\(\displaystyle\sf = (87.5 + 87.5 + 63 + 63) - 6 - 6\)

\(\displaystyle\sf = 275 - 6 - 6\)

\(\displaystyle\sf = 263 \,m^2\)

Cost of painting the walls:

\(\displaystyle\sf Cost_{\text{painting}} = Total_{\text{wall\,area}} \times 3.50\)

\(\displaystyle\sf = 263 \times 3.50\)

\(\displaystyle\sf = 920.50 \,Rs\)

Therefore, the cost of painting the walls of the room at Rs. 3.50 per square meter is Rs. 920.50.

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♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

The key features of this quadratic relation y = -3x² - 24x - 36 include;

In Mathematics and Geometry, the graph of a quadratic function would always form a parabolic curve because it is a u-shaped.

Since the leading coefficient (value of a) in the given quadratic function y = -3x² - 24x - 36 is negative 16, we can logically deduce that the parabola would open downward and the x-intercept (roots) is given by the ordered pair (-6, 0) and (-2, 0).

When x = 0, the y-intercept can be determined as follows;

y = -3x² - 24x - 36

y = -3(0)² - 24(0) - 36

y = -36

Axis of symmetry, Xmax = -b/2a

Axis of symmetry, Xmax = -(-24)/2(-3)

Axis of symmetry, Xmax = -4

For the vertex, we have:

y(-4) = -3x² - 24x - 36

y(-4) = -3(-4)² - 24(-4) - 36

y(-4) = 12

In conclusion, the quadratic function has a maximum value at 12.

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Step-by-step explanation:

The circumference of a WHOLE circle = pi * d

   you have 1/2 of this  and d = 10 ft

     so   1/2 pi * 10      PLUS the two straight sides + 8+6

       1/2 pi * 10   + 8 + 6

         5 pi + 8 + 6

        5 * 3.14   + 14 = 29.7 ft

Check the picture below.

\(\sin( \theta )=\cfrac{\stackrel{opposite}{0.5}}{\underset{hypotenuse}{0.64}} \implies \sin^{-1}(~~\sin( \theta )~~) =\sin^{-1}\left( \cfrac{0.5}{0.64} \right) \\\\\\ \theta =\sin^{-1}\left( \cfrac{0.5}{0.64} \right)\implies \theta \approx 51.4^o\)

Make sure your calculator is in Degree mode.

The perimeter of parallelogram ABCD is 43.49 units.

We know that BC = 10, so we can use the Pythagorean theorem to find the length of AD:

AD^2 = BC^2 + x^2

AD^2 = 10^2 + x^2

AD^2 = 100 + x^2

AD = √(100 + x^2)

Perimeter = AB + BC + CD + AD

Perimeter = 9 + 10 + 9 + √(100 + x^2)

angle B has measure 63 degrees and we can  use the sine function to find x:

sin 63 = x / √(100 + x^2)

x / √(100 + x^2) = sin 63

x = sin 63 * √(100 + x^2)

x = 0.819 * √(100 + x^2)

x / 0.819 = √(100 + x^2)

x^2 / 0.6761 = 100 + x^2

x^2 / 0.6761 - x^2 = 100

x^2 * (1 / 0.6761 - 1) = 100

x^2 = 100 / (1 / 0.6761 - 1)

x = √(100 / (1 / 0.6761 - 1))

x = 5.48

We then substitute x back into the expression for the perimeter:

Perimeter = 9 + 10 + 9 +√(100 + x^2)

Perimeter = 9 + 10 + 9 + √(100 + 5.48^2)

Perimeter = 9 + 10 + 9 +√(100 + 30.0304)

Perimeter = 43.49

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Let's draw the figure to better understand the problem.

Answer:

702

Step-by-step explanation:

because 74 x 9 = 666 and 702 is close

Taking cube root on both sides, we get

The given two graphs are parabolic graphs. Those are not the inverse of the given function.

Hence this is the required graph.

Answer:

  {2, 4, 6, 8}

Step-by-step explanation:

Even numbers are of the form 2n, where n is any integer. If you want positive even numbers less than 10, you require ...

  0 < 2n < 10

  0 < n < 5 . . . . . . divide by 2

That is, n = {1, 2, 3, 4}, so 2n = {2, 4, 6, 8}.

The positive even integers less than 10 are {2, 4, 6, 8}.

In such cases some time positive no. is less than 10 either more than ten

Step-by-step explanation:

for example 2 is less than ten and 2 is a positive even no.

2nd example 12 is also a positive even no. but more than 10

so we can say for 1 to 9 positive no. are less that ten but 11to infeniti is more than ten

If my answer is correct so like me

Answer:

  (b)  22 in

Step-by-step explanation:

You want the perimeter of a rectangle with side lengths 4 inches and 7 inches.

The perimeter of a rectangle is the sum of the lengths of its sides. Your rectangle has two sides that are 4 inches, and two sides that are 7 inches. The perimeter is the sum of these lengths:

  P = 4 in + 4 in + 7 in + 7 in

  P = 22 in

The perimeter of the rectangle is 22 inches.

__

Additional comment

We can save a math operation by recognizing the sum can be arranged to ...

  P = (4 in +7 in) +(4 in +7 in) = 2(4 in +7 in)

This is evaluated using one sum and one product, rather than the three sums we need if we simply add the lengths of the four sides.

This is why the usual formula for the perimeter of a rectangle is ...

  P = 2(L +W)

Answer:

Step-by-step explanation:

b 35

Answer: 26.40

Step-by-step explanation:

Answer:

The function h(x) is decreasing on the interval (3, ∞).

Step-by-step explanation:

Please take a look at the attached image.

You will see a graph of the given function h(x) = -2\(\sqrt{x-3}\). The function is decreasing.

The function starts at 3 and starts to go towards negative infinity on the x-axis. Therefore the function is decreasing on the interval (3, ∞).

The equivalent expression of \(6^\frac 25\) is \((\sqrt[5]{6})^2\)

The expression is given as:

\(6^\frac 25\)

The law of indices states that:

\(a^\frac mn = (\sqrt[n]{a})^m\)

Using the above as a guide, we have:

\(6^\frac 25 = (\sqrt[5]{6})^2\)

Hence, the equivalent expression of \(6^\frac 25\) is \((\sqrt[5]{6})^2\)

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Answer:

x + 7

Step-by-step explanation:

x2 + 4x − 21

set equal to 0

x2 + 4x − 21 = 0

factor

(x - 3) (x + 7)

x2 + 11x + 28

set equal to 0

x2 + 11x + 28 = 0

factor

(x + 4) (x + 7)

The rate at which the volume of the cylinder is changing is 600 mm^3/min, and the rate at which the surface area is changing is 240π mm^2/min.

To find the rate at which the volume and surface area of the cylinder are changing, we can use the given formulas for volume and surface area and differentiate them with respect to time. Let's calculate the rates at the moment when the radius of the base is 10 mm.

Given:

Radius rate of change: dr/dt = 3 mm/min

Height: h = 20 mm

Radius: r = 10 mm

Volume of the cylinder (V) = \(r^2h\)

Differentiating with respect to time (t), we have:

dV/dt = 2rh(dr/dt) + \(r^2\)(dh/dt)

Since the height of the cylinder is constant, dh/dt = 0.

Substituting the given values:

dV/dt = 2(10)(20)(3) + (10^2)(0)

dV/dt = 600 + 0

dV/dt = 600 mm^3/min

Therefore, the rate at which the volume of the cylinder is changing at the given moment is 600 mm^3/min.

Surface area of the cylinder (SA) = 2πrh + 2π\(r^2\)

Differentiating with respect to time (t), we have:

dSA/dt = 2πr(dh/dt) + 2πh(dr/dt) + 4πr(dr/dt)

Again, since the height of the cylinder is constant, dh/dt = 0.

Substituting the given values:

dSA/dt = 2π(10)(0) + 2π(20)(3) + 4π(10)(3)

dSA/dt = 0 + 120π + 120π

dSA/dt = 240π mm^2/min

Therefore, the rate at which the surface area of the cylinder is changing at the given moment is 240π mm^2/min.

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Answer:

The horizontal distance from the plane to the control tower is approximately 7983.6 meters.

Step-by-step explanation:

To find the horizontal distance from the plane to the control tower, we can use trigonometry.

We know that:

   The angle of elevation from the control tower to the plane is 15.3°

   The height of the plane above the ground level is 4200 m

We can use the tangent function to find the horizontal distance:

Distance = (Height) / (tan(Angle of Elevation))

Distance = 4200 / (tan(15.3))

Using a calculator or a table of tangent values, we can approximate the horizontal distance to be approximately 7983.6 meters.

Rounding to the nearest tenth, we get 7983.6m ≈ 7983.6m

So the horizontal distance from the plane to the control tower is approximately 7983.6 meters.