Give the name and chemical formulas of two compounds that have "oxide" somewhere in the name tell if they are ionic or molecular

The pH of this solution is 12.54.

A saturated aqueous solution of calcium hydroxide has a density of 1.02 g/mL and contains roughly 0.13% calcium hydroxide by mass. This solution's pH can be estimated as follows:

Calcium hydroxide has a molar mass of 74.1 g/mol and a solubility in water of roughly 0.13% calcium hydroxide by mass, or 1.3 g of Ca(OH)2 in 1000 g of water.

Calculate the molarity of the solution.

Number of moles of Ca(OH)2 in 1.3 g = 1.3/74.1 = 0.0175 moles in 1000 g of water

Number of moles in 1 L of water = 0.0175 * 1000/1000 = 0.0175 M

Calculate the [OH-] ion concentration[OH-] ion concentration = 2 x 0.0175 = 0.035 M

Calculate the pOH of the solution

pOH = -log[OH-] = -log0.035 = 1.46

Calculate the pH of the solution

pH = 14 - pOH = 14 - 1.46 = 12.54

Therefore, the pH of this solution is 12.54.

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Answer:

If the temperature of milk increases and then rapidly decreases bacteria can start to form in it. Also if milk gets to warm it can spoil and curdle towards the bottom of the cup. The curdling is usually due to the lactose in milk.

Hi there, here's your answer:

If stored above 5 °C for too long, milk will begin to develop signs of spoilage, including sour odor, off-flavor and curdled consistency. Remember that milk should be taken from the store and quickly placed in your refrigerator at home so that the temperature does not rise above 5 °C.

Moreover, the rate of growth of harmful bacteria increases as the temperature at which the milk is stored is increased. Harmful bacteria cannot grow in milk when the temperature it is kept at is below 5°-7°C. At higher temperatures, the rate of growth of harmful bacteria is very fast.

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Answer:

what

Explanation:

Answer:

D

Explanation:

Answer:

If you continue to cool water past 4 degrees Celsius, its density starts to plummet (you can see this in the graph). At zero degrees, i.e., the temperature at which water turns into ice, the density of water is actually quite low. It turns out that ice has a lower density than water, and any object that has a lower density than the liquid form on which it’s kept (in this case, water) will be able to float!

Explanation:

The ice floats in water because the hydrogen bonds in the ice change to negative, and Ice is, therefore, less dense than water because the density of water actually reduces as the temperature drops.

Ice is the form of water. It is the frozen form of water. It is made up of hydrogen and oxygen.

The hydrogen bonds in water change as it cools, holding the negatively charged oxygen atoms apart and preventing the ice from getting much denser.

Water loses density after 4 degrees Celsius of cooling, therefore don't do it  The water's density is actually relatively low at zero degrees, the temperature upon which water transforms into ice.

Thus, as it turns out, ice has a lower density than water, therefore any object will be able to float if its density is lower than that of the liquid state it is kept in.

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Answer:

1.8mL

Explanation:

What is the volume?

Density = Mass / Volume

19.3g/mL = 35g/v

19.3g/mL (v) = 35g/v (v)

19.3g/mL x v = 35g

v = 35g/19.3g/mL

v = 1.8mL

The higher the concentration of hydrogen ions A) the lower the pH. In a solution, the concentration of hydrogen ions (H+) determines its pH. The pH scale ranges from 0 to 14, with a pH of 7 being neutral.

A pH below 7 indicates an acidic solution, while a pH above 7 represents a basic or alkaline solution.
The relationship between pH and the concentration of hydrogen ions is inversely proportional, meaning that as the concentration of hydrogen ions increases, the pH value decreases. Consequently, a higher concentration of hydrogen ions results in a lower pH, making the solution more acidic.
It is important to note that the pH scale is logarithmic, meaning that each change of one unit in pH represents a tenfold change in the concentration of hydrogen ions. For example, a solution with a pH of 3 is ten times more acidic than a solution with a pH of 4 and a hundred times more acidic than a solution with a pH of 5.
Oxygen levels, on the other hand, are not directly related to the concentration of hydrogen ions or pH in this context. Therefore, options B and D are not accurate. Similarly, option C is not correct, as a higher concentration of hydrogen ions corresponds to a lower pH, not a higher one.

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The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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1. The type of polymer that would you obtain if sorbitol is a polyol.

2a. The use of starch-borate and starch-glycerol polymers for the encapsulation of pharmaceutical drugs or pesticides would have a number of beneficial effects.

2b. Yes, these polymers are considered to be biodegradable.

1. The type of polymer that would you obtain if sorbitol (a sugar alcohol found in sugar-free gum) was used as a plasticizer additive is a polyol. This is because sorbitol is a polyol, which is a substance used to modify the properties of polymers. The process of polymer modification involves adding polyols to the polymer matrix, which helps to reduce the glass transition temperature of the polymer. Sorbitol can be used as a plasticizer addictive because it is a natural and non-toxic compound that is biodegradable.

2a. The use of starch-borate and starch-glycerol polymers for the encapsulation of pharmaceutical drugs or pesticides would have a number of beneficial effects. These polymers are natural and non-toxic, and they are biodegradable, which means that they do not pose a risk to the environment. Additionally, they can be used to modify the properties of the drugs or pesticides, making them more effective and reducing their toxicity.

2b. Yes, these polymers are considered to be biodegradable. This is because they are made from natural materials that can be broken down by biological processes. Starch-borate and starch-glycerol polymers are particularly attractive for use in biodegradable materials because they are non-toxic and biocompatible. They can be used in a variety of applications, including packaging materials, agricultural films, and medical devices, where their biodegradability is an important factor.

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Answer:  Molarity of the solution is 0.813 M.

Explanation:

Given : Mass of NaOH = 97.68 g

Volume of solution = 3 L

The molar mass of NaOH is 39.99 g/mol. Hence, moles of NaOH are calculated as follows.

\(No. of moles = \frac{mass}{molar mass}\\= \frac{97.68 g}{39.99 g/mol}\\= 2.44 mol\)

Molarity is the number of moles of solute present in a liter of solution. Therefore, molarity of given solution is calculated as follows.

\(Molarity = \frac{no. of moles of solute}{Volume (in L)}\\= \frac{2.44 mol}{3 L}\\= 0.813 M\)

Thus, we can conclude that molarity of the solution is 0.813 M.

Answer:

Hello! Your answer would be, BELOW

Explanation:

A) True

B) Change of color

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

A hyperbola is a set of points in a plane such that the difference of the distances between each point and two fixed points is a constant.

In this context, the two fixed points are called the foci and the midpoint of the segment connecting the two foci is called the center of the hyperbola.The vertices of a hyperbola are the two points on the transverse axis that are equidistant from the center. The transverse axis is the line segment passing through the two vertices, and the conjugate axis is the line segment perpendicular to the transverse axis that passes through the center.The equation of a hyperbola can be determined if the foci and vertices are known.  The equation of a hyperbola can also be determined if the asymptotes are known. The asymptotes are the two lines that intersect at the center of the hyperbola and are perpendicular to the transverse axis. The equation of the asymptotes is given by:$y = ±(b / a) x$where $a$ and $b$ are the same as in the equation above.

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Divide the number of moles of NH₃ by the volume of the diluted solution to calculate the concentration of NH₃ in the diluted solution.

To calculate the concentration of NH₃ in a diluted NH₃ solution using colorimetric titration data, you will need to know the volume and concentration of the titrant used, as well as the volume of the diluted NH₃ solution.

1. Determine the volume of the titrant used during the colorimetric titration.

2. Calculate the number of moles of titrant used. This can be done by multiplying the volume of titrant by its concentration.

3. Use the stoichiometry of the reaction to determine the number of moles of NH₃present in the titrated solution. This information can usually be found in the balanced chemical equation for the reaction.

4. Calculate the volume of the diluted NH₃solution.

5. Finally, divide the number of moles of NH₃by the volume of the diluted solution to calculate the concentration of NH₃ in the diluted solution.

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7 days old hahahshahah

Where P_solution is the vapor pressure of the solution, X_water is the mole fraction of water in the solution, and P_water is the vapor pressure of pure water at the same temperature.

To calculate the vapor pressure of the solution, we need to use Raoult's Law
P_solution = X_water * P_water
First, we need to calculate the number of moles of glucose in the solution:
n_glucose = mass_glucose / molar_mass_glucose
n_glucose = 109 g / 180.2 g/mol
n_glucose = 0.605 mol
Next, we need to calculate the number of moles of water in the solution:

mass_water = volume_solution * density_solution
mass_water = 920.0 mL * 1.00 g/mL
mass_water = 920.0 g
n_water = mass_water / molar_mass_water
n_water = 920.0 g / 18.015 g/mol
n_water = 51.06 mol

The total number of moles in the solution is:
n_total = n_glucose + n_water
n_total = 0.605 mol + 51.06 mol
n_total = 51.66 mol
The mole fraction of water in the solution is:
X_water = n_water / n_total
X_water = 51.06 mol / 51.66 mol
X_water = 0.988

Finally, we can calculate the vapor pressure of the solution:
P_solution = X_water * P_water
P_solution = 0.988 * 23.76 mm Hg
P_solutin = 23.48 mm Hg
Therefore, the answer is (b) 23.48 mm Hg.
To calculate the vapor pressure of the solution, we'll use Raoult's Law, which states that the vapor pressure of a solution is equal to the mole fraction of the solute times the vapor pressure of the pure solvent.

First, determine the moles of glucose:
moles of glucose = (109 g) / (180.2 g/mol) = 0.605 moles
Next, determine the moles of water:
mass of water = (920.0 mL) * (1.00 g/mL) = 920.0 g
moles of water = (920.0 g) / (18.02 g/mol) = 51.05 moles

Now, calculate the mole fraction of glucose:
mole fraction of glucose = moles of glucose / (moles of glucose + moles of water) = 0.605 / (0.605 + 51.05) = 0.0117
Finally, apply Raoult's Law to find the vapor pressure of the solution:
vapor pressure of solution = mole fraction of glucose * vapor pressure of pure water = 0.0117 * 23.76 mm Hg = 0.278 mm Hg
So, the correct answer is:
a. 0.278 mm Hg

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Answer:

Radio is used primarily for communications including voice, data and entertainment media.

Answer:

115N

Explanation:

your  friend and you push the car at the same time at the same direction so you add the force your friend is using and the force you’re using so: 60+55=115N

decay rate of approximately 1.69x10^17 Bq (becquerels),

The decay rate of a radioactive sample is determined by the number  of radioactive atoms present and the decay constant, which represents the probability of decay per unit of time.

To calculate the decay rate, we multiply the number of atoms in the sample by the decay constant. In this case, the sample has 8.31x10^17 atoms and a decay constant of 0.203/s. Multiplying these values gives a decay rate of approximately 1.69x10^17 Bq (becquerels), which represents the number of decays per second in the sample.

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Option (D) helium (He) and hydrogen (H) is the right answer.

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Answer: Helium, Hydrogen

Explanation: I got it right

The equilibrium constant for the reaction at 1 atm and 25°C is approximately 1.09 × 10^-11.

To calculate the equilibrium constant (Kc) for this reaction, we need to use the equation:

Kc = [NO]^2[O2]/[NO2]^2

Since the initial concentration of NO2 is 1.00 M, and 0.0033% of it is decomposed, the concentration of NO2 at equilibrium is:

[NO2] = 1.00 M - (0.0033/100) x 1.00 M = 0.9967 M

Since the stoichiometry of the reaction is 2:2:1 for NO2, NO, and O2 respectively, the concentrations of NO and O2 at equilibrium are:

[NO] = 2 x (0.0033/100) x 1.00 M = 0.000066 M
[O2] = (0.0033/100) x 1.00 M = 0.000033 M

Substituting these values into the Kc equation gives:

Kc = (0.000066 M)^2 x (0.000033 M) / (0.9967 M)^2
Kc = 4.68 x 10^-8

Therefore, the equilibrium constant for the reaction 2NO2(g) → 2NO(g) + O2(g) at 1 atm and 25°C is 4.68 x 10^-8.
At 1 atm and 25°C, the initial concentration of NO2 is 1.00 M. Given that 0.0033% of NO2 is decomposed, we can first find the change in concentration of NO2:

Change in NO2 concentration = (0.0033/100) * 1.00 M = 0.000033 M

Now, for the balanced reaction 2NO2(g) ⇌ 2NO(g) + O2(g), the stoichiometry is as follows:

2 moles of NO2 decompose to form 2 moles of NO and 1 mole of O2.

Since 0.000033 M of NO2 decompose, the change in concentrations for the products are:

Δ[NO] = 0.000033 M
Δ[O2] = 0.000033 M / 2 = 0.0000165 M

Now, we can use these values to write the equilibrium expression:

Kc = [NO]^2 [O2] / [NO2]^2

At equilibrium:

[NO2] = 1.00 M - 0.000033 M = 0.999967 M
[NO] = 0.000033 M
[O2] = 0.0000165 M

Plug in these values into the equilibrium expression:

Kc = (0.000033)^2 * (0.0000165) / (0.999967)^2

Calculate the value:

Kc ≈ 1.09 × 10^-11

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Answer:

1 Hour...

Explanation:

If It’s 960 Km/h, then it will take 1 hour to fly there.

A liquid boils when its vapor pressure equals the external pressure. This means that a liquid will boil at a specific temperature when the vapor pressure it exerts at its surface is equal to the pressure exerted on the liquid by the surrounding atmosphere or external pressure.

At this point, the liquid molecules transition to the gas phase, and the liquid reaches its boiling point. Thus, the correct option is "equals the external pressure.

"Here are some additional facts related to the boiling point:

Factors that influence the boiling point of a liquid include atmospheric pressure, intermolecular forces, and molecular weight. Boiling points increase with increasing pressure and decrease with decreasing pressure. Boiling points increase with increasing intermolecular forces because more energy is needed to break the bonds between molecules. Boiling points increase with increasing molecular weight because heavier molecules have more electrons and stronger intermolecular forces.

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The equilibrium constant, Kp, for the reaction cannot be determined without knowing the equilibrium pressures of gases B and C in addition to the initial and equilibrium pressure of gas A.



To calculate the value of Kp, which is the equilibrium constant in terms of partial pressures, we need to use the given equilibrium pressures and the stoichiometric coefficients of the balanced equation.The equilibrium constant expression for the reaction is Kp = (P(B) * P(C)^2) / (P(A)^2), where P(A), P(B), and P(C) are the partial pressures of gases A, B, and C, respectively.

Given that the initial pressure of A is PA = 240 mmHg and the equilibrium pressure of A is PA = 55 mmHg, we can substitute these values into the Kp expression.Kp = (P(B) * P(C)^2) / (P(A)^2) = (55 * P(B) * P(C)^2) / (240^2)

To solve for Kp, we need additional information about the equilibrium pressures of B and C. Without that information, we cannot determine the exact value of Kp.

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Like any other equilibrium constant, kw is also affected by temperature. the kw at 75 degrees Celsius is 1.995 x 10⁻¹³. Therefore, 13 is the pOH of water at this temperature.

The concentration of hydroxide ions (OH-) is measured by pOH. It is utilized to express a solution's alkalinity.

Aqueous solutions having pOH less than 7 at 25 degrees Celsius are alkaline, pOH larger than 7 are acidic, while pOH equal with 7 are neutral. pH and hydrogen ion concentration is used to compute pOH.

Kw = [OH⁻] [H⁺]

1.995 x 10⁻¹³ = Kw

[OH⁻] =[H⁺]

Kw = [OH⁻]²

[OH⁻] =10⁻¹³

pOH = -log  [OH⁻]

       = - log  10⁻¹³

      = 13

Therefore,  13 is the pOH of water at this temperature.

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Answer: here is a description of what they look like since I cannot see the diagram.

Mitochondria- wavy line

Ribosomes- little dots

Chromosome- X

Nucleus- Circle with bite taken out of it

Endoplasm- Bubble

Nuclear membrane- Outer layer/bubble

Golgi-wavy circle thing

Vacuole- Bigger circle (but not nucleus)

Cytoplasm- its the jelly on the inside

Cell wall- only in plant cells, looks like a box

Cell membrane- The outmost part of the animal cell, the barrier.

I sure hope this helps!!!

Taking into account definition of percent yield, the percent yield for the reaction is 82.56%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

\(percent yield= \frac{actual yield}{theorical yield}x100\)

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

Replacing in the definition of percent yields:

\(percent yield= \frac{0.71 g}{0.86 g}x100\)

Solving:

percent yield= 82.56%

Finally, the percent yield for the reaction is 82.56%.

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The word that describes the way a writer chooses to write their piece is called diction (option A).

Diction is the choice and use of words, especially with regard to effective communication. It is also regarded as the effectiveness and degree of clarity of word choice and expression.

Diction refers to the linguistic choices a writer makes to effectively convey an idea, a point of view, or tell a story. In literature, the words used by an author can help establish a distinct voice and style.

Authors use dictions for the careful selection of words to communicate a message or establish a particular voice or writing style. For example, flowy, figurative language creates colorful prose, while a more formal vocabulary with concise and direct language can help drive home a point.

The options to the incomplete question are as follows:

A) Diction

B) Syntax

C) Tone

D) Sentence

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