Answer:a
Explanation:because you might not know if each object would attract each other because we already know that a soup can and a spoon and also the pencil will not attract to each other but the paper clip will attract to the magnet
Answer:
This is the answer.
Explanation:
Please help me ASAP!!
Answer:
the ball lose kentic energy and gains potential energy rolling upward
Answer:
c
Explanation:
when a ball is rolling down it loses potential and gains kinetic, but in this case since the ball is going upwards it is losing kinetic energy and gaining potentail like a roller coaser
Coc and ball torture (CBT), ponies torture or dic torture is a sexual activity involving application of pain or constriction to the ponies or testcool. This may involve directly painful activities, such as genital piercing, wax play, genital spanking, squeezing, ball-busting, genital flogging, urethral play, tickle torture, erotic electrostimulation or even kicking. The recipient of such activities may receive direct physical pleasure via masochism, or emotional pleasure through erotic humiliation, or knowledge that the play is pleasing to a sadistic dominant. Many of these practices carry significant health risks
Answer:
CABT
Explanation:
Answer:
this is very valuable information
Explanation:
thanks for letting me know ahead of time
1. The development of what anatomical structure is one current idea for how the Cambrian Explosion began (the so-called Evolutionary Big Bang)? The
Answer:
One idea is how, on an astronomical level, the planets can be observed to spread apart continuously.
Explanation:
Throughout various studies, many have observed that the planets continuously grow distant from each other. In fact, it is observed through our technological advances that the very galaxies are slowly drifting apart. Thus, indicating there must have been some big bang to set these galaxies and planets in motion.
A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?
Answer in kg
The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:
τ = r * F * sin(θ)
where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.
In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.
Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:
τ_M = r_M * F_M * sin(θ)
where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.
Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:
τ_M = τ_stick
r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)
Substituting the given values:
30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)
Solving for F_M:
F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)
F_M = 0.0264 kg * 9.8 m/s^2
F_M = 0.25872 N
Finally, we can convert the force into mass using the formula:
F = m * g
0.25872 N = M * 9.8 m/s^2
M = 0.0264 kg
Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
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A 3,204 kg tree positioned on the edge of a cliff 247 m above the ground breaks away and falls into the valley below which is considered zero potential energy. If the tree’s mechanical energy is conserved, what is the speed of the tree just before it hits the ground in meters/sec?
Let's see
PE is turned to KE as per law of conservation of energy\(\\ \rm\Rrightarrow mgh=\dfrac{1}{2}mv^2\)
\(\\ \rm\Rrightarrow 2gh=v^2\)
\(\\ \rm\Rrightarrow 2(10)(247)=v^2\)
\(\\ \rm\Rrightarrow v²=4940\)
\(\\ \rm\Rrightarrow v=70.3ms^{-1}\)
(A) Electricity and Magnetism
A). Three point charges are aligned along the x axis as shown in
Fig. Find the electric field at (a) the position (2, 0) and (b) the
position (0, 2).
electricity
Explanation:
the position (2,o
What is the real reason the skies blue
Answer:
Rayleigh scattering
Explanation:
The blue color of the sky is due to a phenomenon called Rayleigh scattering. When sunlight enters the Earth's atmosphere, the shorter blue wavelengths of light are scattered more than the other colors by the tiny molecules of nitrogen and oxygen in the air. This causes the blue light to be redirected in many different directions, making the sky appear blue to our eyes. The other colors of light are scattered as well, but to a lesser extent, which is why the sky appears blue instead of a mixture of all colors. This effect is also the reason why the sun appears more yellow, orange or red during sunrise or sunset, when its light has to travel through more of the Earth's atmosphere before reaching our eyes, causing the shorter blue wavelengths to be scattered even more, leaving behind the longer wavelengths of light.
A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
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An object moves from position x = -1.88 m to x = -4.27 m. What is it's displacement?
Answer: Displacement = -2.39 m
Explanation: The displacement of an object is the difference between its final position and its initial position. In this case, the object moved from x = -1.88 m to x = -4.27 m, so its displacement is:
Displacement = Final position - Initial position
Displacement = (-4.27 m) - (-1.88 m)
Displacement = -4.27 m + 1.88 m
Displacement = -2.39 m
Therefore, the displacement of the object is -2.39 m.
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Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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An insulated tank contains 50 kg of water, which is stirred by a paddle wheel at 300 rpm while transmitting a torque of 0.1 kN-m. At the same time, an electric resistance heater inside the tank operates at 110 V, drawing a current of 2 A. Determine the rate of heat transfer after the system achieves steady state.
Answer:
the rate of heat transfer after the system achieves steady state is -3.36 kW
Explanation:
Given the data in the question;
mass of water m = 50 kg
N = 300 rpm
Torque T = 0.1 kNm
V = 110 V
I = 2 A
Electric work supplied W₁ = PV = 2 × 110 = 220 W = 0.22 kW
Now, work supplied by paddle wheel W₂ is;
W₂ = 2πNT/60
W₂ = (2π × 0.1 × 300) / 60
W₂ = 188.495559 / 60
W₂ = 3.14 kW
So the total work will be;
W = 0.22 + 3.14
W = 3.36 kW
Hence total work done on the system is 3.36 kW.
At steady state, the properties of the system does not change so the heat transfer will be 3.36 KW.
The heat will be rejected by the system so the sign of heat will be negative.
i.e Q = -3.36 kW
Therefore, the rate of heat transfer after the system achieves steady state is -3.36 kW
A 15000N crane pivots around a friction-free axle at its base and is supported by a cable making a 25 degree angle with the crane. The crane is 16m long and is not uniform, its center of gravity being 7m from the axle as measured along the crane. The cable is attached 3m from the upper end of the crane. (a) When the crane is raised to 55 degrees above the horizontal holding an 11000N pallet of bricks by a 2.2m very light cord, find the tension in the cable.
The musician from the previous question runs at you with a velocity of 10 m/s. What frequency do you hear?
The previous question:
A frantic musician runs at you while holding a detuned guitar and accidentally plucks the 6th string of their guitar. What is the unfretted pitch and frequency (to the nearest integer) of the string when it is plucked?
Answer: E2 - 82 Hz
A 30° incline permanently sits on a 1.1 meter high table. Starting from rest a ball rolls off the incline with a velocity of 2m/s.
a. Calculate the length of the incline
b. calculate the horizontal and vertical components of the velocity at the end of the incline.
For a flourish at the end of her act, a juggler tosses a single ball high in the air. She catches the ball 3.2 s later at the same height from which it was thrown. What was the initial upward speed of the ball?
Answer:
15.68 m/s
Explanation:
Given that,
She catches the ball 3.2 s later at the same height from which it was thrown.
When it reaches the maximum height, its height is equal to 0.
It will move under the action of gravity.
\(t=\dfrac{2u}{g}\)
2 here comes for the time of ascent and descent.
So,
\(u=\dfrac{tg}{2}\\\\u=\dfrac{3.2\times 9.8}{2}\\\\u=15.68\ m/s\)
So, the initial upward speed of the ball is 15.68 m/s.
An electric fan is made up of several simple machines. Tell where you would find an inclined plane on a fan. Also, tell where you would find a wheel and axle.
The fan blades or propellers of an electric fan are examples of an inclined plane. The blades' frequently curved or angled shapes provide an inclined surface that effectively moves air.
Air is forced along the incline as the blades spin, creating airflow. An electric fan's motor assembly includes a wheel and an axle. The rotor, a revolving component, is connected to the motor's central shaft, also known as the axle.
Usually cylindrical in form, the rotor serves as the wheel. The motor spins around the fixed axle when electrical power is applied, which causes the fan blades to move and the air to circulate.
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Help my brain ain’t braining
The arrows are drawn in the figure which shows gravitational forces on each person on earth.
Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
This is analogous with coulomb's law which gives force between two charges.
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Calculate the final velocity of a 0.25kg soccer ball if it was given an impulse of 10N.s. The soccer ball was initially moving at 2m / s
Answer:
22 m/s
Explanation:
We can use the principle of conservation of momentum to solve this problem. The equation for the conservation of momentum is:
m1v1 + I = m2v2
where m1 is the mass of the soccer ball (0.25 kg), v1 is the initial velocity (2 m/s), I is the impulse (10 N.s), m2 is the mass of the soccer ball (0.25 kg), and v2 is the final velocity (unknown).
We can rearrange the equation to solve for v2:
v2 = (m1v1 + I) / m2
Substituting the given values, we get:
v2 = (0.25 kg * 2 m/s + 10 N.s) / 0.25 kg
Simplifying the equation, we get:
v2 = (0.5 kg⋅m/s + 10 N.s) / 0.25 kg
v2 = 22 m/s
Therefore, the final velocity of the soccer ball is 22 m/s.
what is the difference between impulse and momentum
Answer:
The momentum of the object is given by the product of mass and velocity while the impulse is the change of momentum when a large force is applied on an object for a short interval of time.
I would reword it
Hope this helps!!
What order does energy flow: sun prodecer consumer?
Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.
Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.
At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.
The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.
Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.
At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.
It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.
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pls help i am in8th grade k12
Answer:
please i dont understand this
If the 2,000kg car in the previous question rolls down the 45m-high hill, what will its velocity be at the bottom if energy is conserved? Ignore friction from air resistance. Round to the nearest tenth.
The velocity of the car at the bottom of the hill is 29.7 m/s.
What is velocity?Velocity is a vector quantity and its unit is m/s.
To calculate the velocity of the car at the bottom of the hill, we use the formula below.
Formula:
v = √(2gh)................... Equation 1Where:
v = Velocity of the car at the bottom of the hill h = Height of the hill = 45 mg = Acceleration due to gravity = 9.8 m/s²Substitute tehse values into equation 1
v = √(2×45×9.8)v = √882v = 29.7 m/sHence, the velocity is 29.7 m/s.
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1. How does the % error compare to the coded tolerance for your resistors
Answer:
error ordied complete one orbit between maths
Weylan is at the county fair playing some of the games. At one booth, he throws a 0.75-kg ball forward with a velocity of 21.0 m/s in order to hit a 0.50-kg bottle sitting on a shelf, and when he makes contact the bottle goes flying forward at 20.0 m/s. What is the velocity of the ball after it hits the bottle?
Given that the mass of the ball is m1= 0.75 kg and initial velocity, u1 = 21 m/s.
This ball strikes a bottle of mass, m2= 0.5 kg, and the initial velocity of the bottle, u2 = 0 m/s.
We have to find the final velocity of the ball, v1 after collision with the bottle having final velocity, v2 = 20 m/s
Momentum is conserved during a collision. So, the equation of momentum can be written as
\(m1u1+m2u2=m1v1+m2v2\)Substituting the values, v1 will be
\(\begin{gathered} v1=\frac{m1u1+m2u2-m2v2}{m1} \\ =\frac{0.75\times21+0.5\times0-0.5\times20}{0.75} \\ =7.67\text{ m/s} \end{gathered}\)Thus, the velocity of the ball is 7.67 m/s.
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. Then, while your opponent is watching that snowball, you throw a second one at a low angle timed to arrive before or at the same time as the first one. Assume both snowballs are thrown with a speed of 26.5 m/s. The first one is thrown at an angle of 58.0° with respect to the horizontal. Find a - At what angle should the second snowball be thrown to arrive at the same point as the first?, find b - How many seconds later should the second snowball be thrown after the first in order for both to arrive at the same time?
The second snowball should be thrown at an angle of approximately 48.196° with respect to the horizontal to arrive at the same point as the first snowball.
the second snowball should be thrown 4.582 seconds later in order for both to arrive at the same time.
To find the angle at which the second snowball should be thrown, we can use the fact that the horizontal displacement of both snowballs must be the same.
Let's first find the horizontal and vertical components of the velocity for the first snowball. The initial speed is 26.5 m/s, and the angle is 58.0° with respect to the horizontal.
The horizontal component of the velocity for the first snowball is given by:
V1x = V1 * cos(angle1)
= 26.5 m/s * cos(58.0°)
= 26.5 m/s * 0.530
= 14.045 m/s
Now, let's find the vertical component of the velocity for the first snowball:
V1y = V1 * sin(angle1)
= 26.5 m/s * sin(58.0°)
= 26.5 m/s * 0.848
= 22.472 m/s
Since the vertical acceleration is the same for both snowballs (gravity), the time it takes for both to arrive at the same point is the same. Therefore, we can use the time of flight of the first snowball to calculate the vertical displacement for the second snowball.
The time of flight for the first snowball can be calculated using the vertical component of velocity and the acceleration due to gravity:
t = (2 * V1y) / g
= (2 * 22.472 m/s) / 9.8 m/s²
≈ 4.582 s
Now, let's find the vertical displacement for the second snowball:
Δy = V1y * t - (0.5 * g * t²)
= 22.472 m/s * 4.582 s - (0.5 * 9.8 m/s² * (4.582 s)²)
≈ 103.049 m
To find the angle at which the second snowball should be thrown, we can use the horizontal displacement and the vertical displacement:
tan(angle2) = Δy / Δx
= 103.049 m / (2 * 14.045 m/s * t)
= 103.049 m / (2 * 14.045 m/s * 4.582 s)
≈ 1.085
Now, we can find the angle2 by taking the arctan of both sides:
angle2 ≈ arctan(1.085)
angle2 ≈ 48.196°
Therefore,
To find how many seconds later the second snowball should be thrown, we can simply use the time of flight of the first snowball, which is approximately 4.582 seconds.
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the ratio of force between two charges in vacuum to that the force between two same charges when a medium is placed between them
The ratio of the force between two charges in a vacuum to the force between two charges when a medium is placed between them is called relative permittivity
What should you know about relative permittivity?Relative permittivity has another term dielectric constant. The dielectric constant measures how well a material can store electrical energy in an electric field. Its equation is ε = ε₀ / εᵣ
ε₀ is the vacuum permittivity, and εᵣ is the relative permittivity or dielectric constant of the medium.
The dielectric constant is different depending on the material.
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A cylindrical water tank open to the atmosphere, 10 m tall and 6 m in diameter, is mounted with its base 25 m above ground level, and filled with water.
Calculate
a) the water pressure and force at the base of the tank?
b) the pressure in a water pipe at ground level?
c) the speed with which water will push out of a leak at a height of 8 m above the ground?(hint: force is equal to horizontal rate of change of momentum of water)
The bottom of a cylindrical water tank, 10 m tall and 6 m in diameter, is 25 m above the ground. According to calculations, the water pressure and force at the bottom of the tank are 343,000 Pascal and 9,685,941 Newtons, respectively.
A water pipe at ground level has the same pressure as one at the tank's base. The rate of water egress from a leak 8 metres above the ground is around 19.6 metres per second.
These calculations are based on the conservation of energy and hydrostatic principles.This pressure can also be found in a ground-level water pipe. Water will seep from a leak 8 metres above the ground at a speed of about 19.6 metres per second.
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What Factor Determine the accuracy an Precision the result
Answer:
The accuracy and precision of a result depend on several factors, including:
1. Quality of the measurement tools - Using high-quality measurement instruments can lead to more accurate and precise results.
2. Calibration of instruments - Instruments should be calibrated regularly to ensure accurate and precise readings.
3. Skill of the person performing the measurement - The person performing the measurements must have proper training and knowledge of the tool they're using.
4. Sample size - Increasing the sample size can lead to more accurate results.
5. Sampling bias - If the sample used for the measurement is biased, it can lead to inaccurate or imprecise results.
6. Experimental design - Proper experimental design can help reduce measurement errors and increase accuracy.
A rocket blasts off from rest and attains a speed of 33.9 m/s in 12.7 s. An astronaut has a mass of 65.1 kg. What is the astronaut's
apparent weight during takeoff?
The apparent weight of the astronaut of mass 65.1 kg moving with a speed of 33.9 m/s in 2.7 s is 811.797 N.
What is weight?Weight is the force with which a body is attracted toward the earth or a celestial body by gravitation and which is equal to the product of the mass and the local gravitational acceleration.
To calculate the astronaut's apparent weight, we use the formula below.
Formula:
W = m{[(v-u)/t]+g}............ Equation 1Where:
W = The apparent weight of the astronautm = Mass of the astronautv = Final speedu = Initial speedt = Timeg = Acceleration due to gravityFrom the question,
Given:
m = 65.1 kgv = 33.9 m/su = 0 m/s (from rest)t = 12.7 sg = 9.8 m/s²Substitute these values into equation 1
W = 65.1{[(33.9-0)/12.7]+9.8]W = 65.1×12.47W = 811.797 NHence, the apparent weight of the astronaut is 811.797 N.
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Mathias is going to do some informational interviewing. What is one of the main benefits of doing these interviews?
O A.
OB.
O C.
O D.
A.He will gain insight about a new career opportunity.
B.He will likely be offered a position with a company.
C.He will be able to ask questions about job openings.
D.He will find out how much money everyone earns.
Answer:
A
Explanation:
One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.