genevieve works for a company that manufactures office furniture. it is her responsibility to source component parts such as casters, laminate, and plastic to make the office furniture. genevieve works in blank . multiple choice question. operations r

Explanation:

The acceleration g varies by about 1/2 of 1 percent with position on Earth's surface, from about 9.78 metres per second per second at the Equator to approximately 9.83 metres per second per second at the poles.

To find the electric potential energy of a 4.0-μC charge at a point with an electric potential of 20 V, you can use the following formula:

Electric Potential Energy (EPE) = Charge (Q) × Electric Potential (V)

In this case, Q = 4.0 μC and V = 20 V.

Remember to convert the charge to coulombs by multiplying by \(10^-6\):

Q = 4.0 ×\(10^-6\)

Now, plug in the values:

EPE = (4.0 × 1\(10^-6\) C) × (20 V)

EPE = 8 ×\(10^-5\) J (joules)

So, the electric potential energy of the 4.0-μC charge at that point is 8 × \(10^-5\) joules.

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There are many factors that determine if an aircraft can operate from a given airport. Of course the availability of certain services, such as fuel, access to air stairs and maintenance are all necessary. But before considering anything else, one must determine if the plane can physically land at an airport, and equally as important, take off.

What is the minimum runway length that will serve?

Looking at aerial views of runways can lead some to the assumption that they are all uniform, big and appropriate for any plane to land. This couldn’t be further from the truth.

A given aircraft type has its own individual set of requirements in regards to these dimensions. The classic 150’ wide runway that can handle a wide-body plane for a large group charter flight isn’t a guarantee at every airport. Knowing the width of available runways is important for a variety of reasons including runway illusion and crosswind condition.

Runways also have different approach categories based on width, and have universal threshold markings that indicate the actual width.

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The spring constant is 0.943 N/m. The spring pushes the object back towards its original position and this energy is converted into kinetic energy.

The system in this scenario consists of the 250. g object and the spring it is attached to. When the object is pushed against the spring, it compresses and stores potential energy. When released, the spring pushes the object back towards its original position and this energy is converted into kinetic energy.

The fact that the system experiences 12 cycles every 20 seconds tells us that the object oscillates back and forth 12 times in 20 seconds. One full oscillation is equal to the object moving from its starting position, to the maximum displacement from that position, back to the starting position, and then to the maximum displacement in the opposite direction, before returning again to the starting position.

To find the spring constant, we can use the equation for the period of oscillation of a mass-spring system:

T = 2π * sqrt(m/k)

where T is the period of oscillation, m is the mass of the object, and k is the spring constant.

We know that T = 20 s / 12 = 1.67 s (since there are 12 cycles in 20 seconds). We also know that m = 250. g = 0.25 kg.

Plugging these values into the equation, we can solve for k:

1.67 s = 2π * sqrt(0.25 kg/k)

1.67 s / (2π) = sqrt(0.25 kg/k)

0.265 s^2/kg = 0.25 kg/k

k = 0.25 kg / 0.265 s^2

k = 0.943 N/m

Therefore, the spring constant is 0.943 N/m.

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If the speed of an object does not change the object Is traveling at a constant speed

Answer:

it's either A or B

Explanation:

he argued two main points (1)independence from England (2)the creation of a democratic republic.

Answer:

During a total lunar eclipse, the moon and sun are on the exact opposite sides of the Earth, leaving the moon entirely in the Earth's shadow. During a partial lunar eclipse, only part of the moon is in the Earth's shadow.

Explanation:

Answer:

60 m/s

Explanation:

acceleration: 1/2 m/s2

time: 2 minutes

there are 60 seconds in one minute so

60sec x 2 min = 120 sec

1/2 in decimal form is 0.5 so 0.5 x 120sec= 60m/s

Answer:

1.67m/s

Explanation:

Total Distance to be travelled by a Runner=100m

Time Taken=10*6s

Speed=Distance/Time

=100/10*6=10/6=1.67m/s

The answer you are looking for is approximately 1.67 m/s.

Solution/Explanation:

Distance Ran: 100 m.

Time ran: 10x6s, or 60s, or one minute.

Speed: Unknown?

Writing out the formula for speed, using distance and time,

S=D/T.

S=Speed.

D=Distance.

T=Time.

Substituting the given values of the variables,

S=100 m/10x6s, or S=100 m/one minute, or S=100 m/60s.

100÷60=1.6667≈1.67.

So, therefore, the final answer is approximately 1.67 m/s.

I hope that this has helped you. Enjoy your day, and take care.

The military time for 2pm is 1400 hours.

This is because military time operates on a 24-hour clock instead of the standard 12-hour clock. In military time, the hours range from 00 to 23, with 00 representing midnight and 12 representing noon. To convert 2pm to military time, you simply add 12 to the standard time.

Therefore, 2pm + 12 hours = 1400 hours. This system of timekeeping is used by the military and other organizations where clear and precise communication is critical. It eliminates the confusion that can occur with AM and PM designations, making it easier to coordinate and plan operations.

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Answer:b

Explanation:

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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The speed of the Earth's rotation affects the length of a day, which in turn influences various aspects of life, including the distribution of sunlight, temperature patterns, and the overall dynamics of ecosystems.

To calculate the speed of the Earth's rotation 155 million years ago, we need to consider the rate at which the Earth's rotation is slowing down. According to the given information, the Earth slows down 1/30000 of a minute every 100 years.

Let's first calculate the change in the Earth's rotation speed over 155 million years:

Change in rotation speed = (1/30000 minute/100 years) * (155 million years)

Now we can calculate the speed of the Earth's rotation at that time:

Current rotation speed - Change in rotation speed

Given that the current rotation speed is 1670 kilometers/hour, we can substitute the values and calculate:

Rotation speed at that time = 1670 km/hour - (Change in rotation speed)

Once we have determined the rotation speed at that time, we can assess its potential impact on the movement of dinosaurs or mankind.

A change in the rotation speed could have implications for the behavior, adaptation, and survival of living organisms, including dinosaurs and early humans.

However, it is important to note that the exact magnitude and direct consequences of changes in rotation speed on specific species and their movements would require a more detailed analysis and consideration of various ecological factors.

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Raking leaves across the yard is an example of a contact force.

Force can be defined as a physical influence or power that causes a change in the motion or shape of an object.

A contact force is a force between two objects that are in direct contact with each other.

Of the four choices provided, the best example of a contact force is option C: you raking leaves across the yard.

This is because the force is being applied directly between you and the leaves.

The other three choices are not contact forces since the objects are not in direct contact with each other.

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Answer:

B. A metal image of gas molecules as tiny balls

Answer:

B. A mental image of gas molecules as tiny balls

Answer:

C. It redirects the force

The force F exerted by an electric field on a test charge q is given by:

From this equation we notice that if we change the test charge then the force will change as well.

Therefore, the forces on the charges will not be the same.

We can't determine the electric field without further information on the problem; we need the force on one of the test charges to determine the magnitude of the field.

Answer:

True.

Explanation:

In biology, selective breeding is the mechanism by which certain traits or a combination of traits are consciously selected in animal breeding or plant breeding and cultivation. Artificial selection is seen as a counterpart to natural selection, the mechanism by which, in nature, individuals are selected who are better adapted to their natural environment. Both processes have the same genetic principles and background.  Man selects the individuals with the desired traits to produce progeny, making these traits more and more common.

When the paint brush is dropped from the top the acceleration increases.

Gravity is a force that pulls objects down toward the ground. When objects fall to the ground, gravity causes them to accelerate.

An object in free fall experiences an acceleration of -9.8 m/s². Whether explicitly stated or not, the value of the acceleration in the kinematic equations is -9.8 m/s² for any freely falling object.

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ANSWER:

C. reflected ray

STEP-BY-STEP EXPLANATION:

The line that divides the angle between the incident ray and the reflected ray into two equal angles is known as the normal line.

Therefore, the angle between the reflected ray and the normal is known as the angle of reflection.

Therefore, the correct answer is C. reflected ray

Answer:

Momento = 170.8 Kgm/s

Explanation:

Dados los siguientes datos;

Masa = 3,05 kg

Velocidad = 56 m/s

Para encontrar el impulso;

El momento se puede definir como la multiplicación (producto) de la masa que posee un objeto y su velocidad. El momento se considera una cantidad vectorial porque tiene magnitud y dirección.

Matemáticamente, el momento viene dado por la fórmula;

\( Momento = masa * velocidad \)

Sustituyendo en la fórmula, tenemos;

\( Momento = 3.05 * 56 \)

Momento = 170.8 Kgm/s

The frequency of a wave is speed/wavelength.

Frequency is the number of cycles completed by a wave in one second.

The S.I unit of frequency is hertz.

The formula for the frequency of a wave is given by

Formula:

Where:

Make f the subject of the equation

Hence, The frequency of a wave is speed/wavelength.

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Answer:

C

Explanation:

Trust

Answer:

We can determine the age of the Earth and the rocks found on Earth with techniques such as measuring ice cores and digging and analysing fossils.

Explanation:

Hopefully this helped!

The minimum initial speed that the car must have in order to remain in contact with the circular track at all times is 1.98 m/s.

To calculate the minimum initial speed that the car must have to remain in contact with the circular track at all times, we need to consider the forces acting on the car. At the top of the loop, the car is not applying a force to the track, so the only force acting on the car is the force of gravity. The force of gravity is what provides the centripetal force that keeps the car moving in a circle.
The centripetal force can be calculated using the formula Fc = mv^2 / r, where Fc is the centripetal force, m is the mass of the car, v is the speed of the car, and r is the radius of the loop. In this case, we can assume that the mass of the car is constant and neglect it in our calculations.
At the top of the loop, the centripetal force provided by gravity is equal to the force of gravity itself, which can be calculated using the formula Fg = mg, where m is the mass of the car and g is the acceleration due to gravity. Therefore, we can equate these two forces to get mv^2 / r = mg.
Solving for v, we get v = sqrt(gr), where sqrt is the square root function. Plugging in the given values, we get v = sqrt(9.8 m/s^2 * 0.4 m) = 1.98 m/s.
Therefore, the minimum initial speed that the car must have in order to remain in contact with the circular track at all times is 1.98 m/s.

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It will take approximately 51 seconds to pump 11 gallons of gas at a rate of 49 liters per minute.

Given, 1 gallon = 3.78541 liters and the rate of the gasoline pumped is 49 liters per minute. We need to find out how many seconds it will take to pump 11 gallons of gas. In order to solve this problem, we can use the conversion factor method for the unit conversion.

First, we will convert gallons into liters, and then we will use the rate of gasoline to find the time taken to pump 11 gallons of gas.

Conversion of gallons into liters:11 gallons x 3.78541 liters per gallon = 41.63951 litersTo find the time taken to pump 41.63951 liters of gas:49 liters per minute = 1 minute/60 seconds = 0.8167 liters per second .Time taken to pump 41.63951 liters of gas= 41.63951/0.8167≈ 51 seconds . Therefore, it will take approximately 51 seconds to pump 11 gallons of gas at a rate of 49 liters per minute.

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Answer:

002 bc eause iy is

Answer:

263.15

. . . . . . . . . ..  ... . . . . . .. . . . . . . . ... .

Answer:

FJ = 31.48N

Explanation:

In this case you have that the torque exerted by each, thumb and finger, over the point P, is equal and opposite by the torque exerted by each Jaw.

You equal one of the torque produced by your hand, as for example, the torque of the finger, with the torque produced by one jaw:

\(\tau_F=\tau_J\\\\F_Fd_1=F_Jd_2\)         (1)

FF: finger force = 10.0N

FJ: jaw force = ?

d1: distance from finger to point P = 8.50cm = 0.085m

d2: distance form the border of the Jaws to the point P = 2.70cm = 0.027m

You solve the equation (1) for FJ and replace the values of the other parameters:

\(F_J=\frac{F_Fd_1}{d_2}=\frac{(10.0N)(0.0850m)}{0.027m}=31.48N\)

The force exerted by each jaw is 31.48N

The force that the forceps jaws exert on the plastic rod will be 31.48N.

From the information given, the following can be depicted:

Therefore, the jaw force will be calculated thus:

Fj = (Ff × d1) / d2

Fj = (10 × 0.085) / 0.027

Fj = 31.48N

Therefore, the jaw force is 31.48N.

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