Gabriella is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be modeled by where x and y are measured in inches. Where should she place the bulb to ensure a perfect beam of light

If a flexible air-filled container at 100 feet of sea water has a volume of 10 cu ft,  if it were transported to the surface it would be 10cu.

Volume is a three-dimensional measurement that is used to determine the capacity of a solid shape. It means that the amount of space a closed form can occupy in three dimensions depends on its volume.

For instance, a cup's capacity is stated to be 10 ml if it can hold 10 ml of water in its brim. The quantity of space occupied by a three-dimensional object can also be used to describe volume.

A three-dimensional object's volume is the area it takes up, and it is expressed in cubic units. Cm3 and in3 are two examples of cubic units. The amount of matter in an item can be determined by its mass, on the other hand. The weight of an object is a common way to determine mass.

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Answer:

a) Then net force acting on the wagon  30 [N] in a negative direction to the left

b)Acceleration of the wagon 3 m/s² in a negative direction to the left

Explanation:

The coordinates x and y show the positive direction in x-axis ( to the right) and negative direction to the left. In north-south direction positive y values are to the north and negative values to the south

The free-body diagram shows 4 forces acting

In y-axis:

The weight ( P = m*g =  10 [kg]*9,8 [m/s²] = 98 [N] negative

Normal reaction force  Fn = P = 98 [N]  positive ( surface is frictionless)

∑Fy = 0     P - Fn = 0     P = Fn  = 98 [N]

In x-axis:

Boris pulling force to the right (positive ) 220 [N]

Natasha pulling force to the left ( negative) 250 [N]

∑Fx = m*a

220 [N] - 250 [N]  = 10 Kg * a                      [N] = Kg * m /s²

-30 [kg*m/s²]  = 10 * Kg * a

-30/10  =  - 3  m/s²  = a

Sign (-) means the direction of acceleration vector is to the left (the same direction of the movement )

Then net force acting on the wagon  30 [N] in negative direction to the left

Acceleration of the wagon 3 m/s² in negative direction to the left

The frequency of NPR radio station is 8.87 x 107 Hz.

Frequency is the number of waves that pass a fixed point in a given amount of time. The unit of frequency is hertz (Hz).

The distance between two successive crests or troughs of a wave is known as wavelength. The unit of wavelength is meters.

The frequency of a wave is equal to the speed of light divided by its wavelength. In mathematical terms, it can be written as:

where

Given:

Wavelength of the signal = λ = 3.38 mSpeed of light = c = 3.0 x 108 m/sFrequency of the signal = ?

Formula:

Substitute the given values:

Therefore, the frequency of the NPR radio station is 8.87 x 107 Hz.

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1. The time interval when the air temperature is above freezing in the practical domain is [-4, -3] and [3, 4].

2. The time intervals when the air temperature is below freezing in the practical domain are (-∞, -4), (-3, 3), and (4, ∞).

3. The maximum temperature on the practical domain is approximately -0.6 degrees Celsius.

4. The time interval when the temperature is increasing in the practical domain is (-∞, -0.5) and (0.5, ∞).
5. The air temperature at midnight is approximately -0.6 degrees Celsius.

The air temperature profile just above the snow surface on a particular day can be modeled using the equation T(t) = -80/(t⁴ - 40t² + 144), where t represents time in hours on a practical domain [0,5] from midnight and T represents the temperature in degrees Celsius.

1. Air temperature above freezing: To determine the time interval when the air temperature is above freezing, we need to find the values of t for which T(t) is greater than 0 (above freezing temperature).

To do this, we can solve the equation T(t) > 0:
-80/(t⁴ - 40t² + 144) > 0

Since the numerator is negative, the temperature will be positive when the denominator is positive. So we need to solve the quadratic equation t⁴ - 40t² + 144 > 0.

By factoring the quadratic equation, we can rewrite it as (t² - 16)(t² - 9) > 0.

Now we can solve for t by setting each factor equal to zero and determining the sign of each factor in the intervals between the zeros. This will give us the time intervals when the temperature is above freezing.

- t² - 16 = 0  => t² = 16  => t = ±4
- t² - 9 = 0   => t² = 9   => t = ±3

Since the quadratic equation has even powers, it is always positive or zero. Therefore, the temperature is above freezing for all values of t except in the intervals [-4, -3] and [3, 4].


2. Air temperature below freezing: Similarly, to determine the time interval when the air temperature is below freezing, we need to find the values of t for which T(t) is less than 0 (below freezing temperature).

We solve the equation T(t) < 0:
-80/(t⁴ - 40t² + 144) < 0

Again, since the numerator is negative, the temperature will be negative when the denominator is positive. So we need to solve the quadratic equation t⁴ - 40t² + 144 > 0.

By factoring the quadratic equation, we can rewrite it as (t² - 16)(t² - 9) > 0.

Using the same approach as before, we find that the time intervals when the temperature is below freezing are (-∞, -4), (-3, 3), and (4, ∞).



3. Maximum temperature: To find the maximum temperature on the practical domain, we need to find the highest point of the temperature function T(t).

To do this, we can take the derivative of T(t) with respect to t and set it equal to zero, and then determine the value of t that corresponds to the maximum temperature.

By taking the derivative, we have dT(t)/dt = 0.

Simplifying the equation, we get 320t³ - 80t = 0.

Factoring out t, we have t(320t² - 80) = 0.

Solving for t, we find t = 0 and t = ±sqrt(1/4) = ±0.5.

Since t represents time in hours, we discard the negative values and conclude that the maximum temperature occurs at t = 0.

Substituting t = 0 into the temperature function, we find T(0) = -80/(0⁴ - 40*0² + 144) = -80/144 ≈ -0.56.



4. Temperature increasing: To determine the time interval when the temperature is increasing, we need to find the values of t for which the derivative of T(t) is positive.

Taking the derivative of T(t), we have dT(t)/dt = 320t³ - 80t.

To find when the derivative is positive, we solve the inequality 320t³ - 80t > 0.

By factoring out t, we get t(320t² - 80) > 0.

Solving for t, we find t = 0 and t = ±sqrt(1/4) = ±0.5.
The derivative is positive when t is in the intervals (-∞, -0.5) and (0.5, ∞).


5. Air temperature at midnight: To find the air temperature at midnight, we substitute t = 0 into the temperature function T(t).

T(0) = -80/(0⁴ - 40*0² + 144) = -80/144 ≈ -0.56.

Therefore, the air temperature at midnight is approximately -0.6 degrees Celsius.

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To construct a stereonet indicating the rake, dip, and strike of the outcrop, the following steps can be followed:

Step 1: Plotting the Pole on the Stereonet

The first step involves plotting the pole of the plane of interest on the stereonet. In this case, the plane has a strike of 110⁰ and a dip of 20⁰ southwest (SW).

To plot the pole, locate the 110⁰ line on the upper edge of the stereonet and mark it. Then, count 20⁰ from the 110⁰ line towards the SW quadrant and mark it. The intersection of the two lines is the pole of the plane.

Step 2: Plotting the Great Circle- Next, plot the great circle that is perpendicular to the plane of interest. The great circle can be obtained by rotating the plane by 90⁰ around the pole and plotting the intersection of the plane with the stereonet.

To do this, locate the pole on the stereonet and mark it. Then, rotate the plane by 90⁰ in a clockwise direction around the pole until it intersects the equator of the stereonet. Mark the points of intersection of the plane with the equator. Join these points to form the great circle.

Step 3: Plotting the RakeFinally, plot the rake of the plane. The rake is the angle between the strike of the plane and the line of intersection of the plane with a horizontal plane.

In this case, the rake is 160⁰.To plot the rake, locate the point on the great circle that corresponds to the strike of the plane (i.e., 110⁰ in this case). Then, rotate the great circle in a clockwise direction by 160⁰ from this point.

The point of intersection of the rotated great circle with the plane of interest is the point that represents the rake of the plane on the stereonet.

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Answer: A radio wave is generated by a transmitter and then detected by a receiver. An antenna allows a radio transmitter to send energy into space and a receiver to pick up energy from space. Transmitters and receivers are typically designed to operate over a limited range of frequencies.

Explanation:

Given :-

To Find :-

Solution :-

See attachment .

Firstly break the velocity of A , into it's vertical components . That will be ,

\( v_A = v_A cos60^o + v_A sin60^o \)

Now the component , \(v_A cos60^o \) coincides on side AC and is directed from A to C . Along CA, the velocity of particle C is directed . So both are in opposite directions.

So , the relative velocity of C with respect to A will be ,

\( v_{CA}= v_C - v_A \)

Substitute ,

\( v_{CA}= v - ( - v cos 60^o) \)

Value of cos 60° is 1/2 ,

\( v_{CA}= v + v\bigg(\dfrac{1}{2}\bigg)=v +\dfrac{v}{2}\)

Add the terms,

\( v_{CA}= \dfrac{2v + v}{2}=\dfrac{3v}{2}\)

Hence , now we can find the time taken by A and C ,to meet each other will be ,

\(s = v t \)

Substitute ,

\(d = \dfrac{3v}{2} t \)

Multiplying both sides by 2 ,

\( 2d = 3vt \)

Dividing both sides by 3v ,

\( t = \dfrac{2d}{3v} \)

Similarly , taking any two particles you will get the same time .

Hence the particles meet after 2d/3v time .

I hope this helps .

Answer:

  never

Explanation:

Particles moving on paths that don't meet at a point will be particles that never meet. Even if the paths meet at a point, which these don't, the particles may not meet if they arrive at different times.

__

Consider the diagrams in the attachments. In order, they show the positions of the particles shortly after takeoff, midway along the line, and after they have gone farther than the length of the line. The point of closest approach is shown in the second attachment, when the particles are halfway along the line.

Consider particles A and C. Their north/south direction is 'north' for each of them. They both have the same velocity in the 'north' direction, but have started at different points, so can never meet. Those two particles have opposite velocities in the east/west direction, so can pass each other (which they do in the second attachment), but cannot meet.

The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.

The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

The force on particle q2 due to q1 will be:

F1 = k * (q1 * q2) / (0.980m)^2

The force on particle q2 due to q3 will be:

F2 = k * (q2 * q3) / (0.750m)^2

The net force acting on q2 will be the vector sum of F1 and F2.

Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.

Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.

Answer:

2 seconds lol im just a kid but I know these lol who has tiktok

Vector is perpendicular to x axis or i component.

Hence i component is 0

j component is 63.5

\(\\ \sf\longmapsto \overrightharpoon{A}=0\hat{i} +63.5\hat{j}\)

Answer:

displacement

Explanation:

Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.

Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, position, displacement, etc.

Displacement can be defined as the change in the position of a body or an object. It is a vector quantity because it has both magnitude and direction.

This ultimately implies that, the difference between the starting and ending positions of a physical object is generally referred to as displacement

The optical power of the lens should be -2.50 diopters (or -2.50 D) to provide clear vision. This lens is a concave (diverging) lens.

The near point is the closest distance at which the eye can focus on an object. In this case, the near point is given as 80.0 cm. The person wants to clearly see an object located 30.0 cm away from their eye. To achieve clear vision, the lens needs to compensate for the difference between the near point and the desired object distance.

The formula for calculating the optical power of a lens is P = 1/f, where P is the power of the lens in diopters and f is the focal length of the lens in meters. Since the corrective lens is placed 2.0 cm (0.02 m) from the eye, we can calculate the focal length as follows:

1/f = 1/v - 1/u,

where v is the distance of the object from the lens and u is the distance of the image from the lens. In this case, v = -30.0 cm and u = -2.0 cm (negative values indicate that the object and image are on the same side of the lens). Plugging these values into the equation:

1/f = 1/-30.0 - 1/-2.0,

Simplifying the equation gives:

1/f = -1/30.0 + 1/2.0.

Solving for 1/f:

1/f = (-2 + 30)/(2 * 30) = 28/60 = 7/15.

Therefore, f = 15/7 = 2.14 cm (0.0214 m). Now, we can calculate the optical power:

P = 1/f = 1/0.0214 ≈ -46.73 D.

Rounding to two decimal places, the optical power of the lens should be approximately -2.50 D. Since the power is negative, the lens is concave (diverging) in nature.

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Answer:

increase distance

Explanation:

Inclined planes make it easier to move objects to a higher elevation. The sloping surface of the inclined plane supports part of the weight of the object as it moves up the slope. As a result, it takes less force to move the object uphill.

Answer:

Hello your answer would be increase of distance

Explanation:

I know that because than you would have to go upward with the object.

In a purely resistive circuit, the phase difference between the voltage and current is zero, which means the circuit consumes all the power delivered to it by the source. In other words, the power delivered is entirely converted into heat energy dissipated by the resistance. Therefore, 100% of the apparent power is used or consumed in a purely resistive circuit. So this statement is true.

Apparent power is the product of the root mean square (RMS) voltage and RMS current, and it represents the total power delivered to the circuit. In a purely resistive circuit, the apparent power and real power are equal since there is no reactive power. Reactive power arises in circuits with inductance and capacitance, where energy is stored and returned to the circuit, leading to a phase shift between voltage and current.

In a purely resistive circuit, the current and voltage are in phase with each other, meaning they reach their maximum and minimum values at the same time. This results in a power factor of 1, which indicates that all of the apparent power drawn by the circuit is converted into real power, which is the actual power consumed by the resistive elements in the circuit. Therefore, it is true that 100% of the apparent power is used or consumed in a purely resistive circuit.

This is not the case in circuits that have reactive elements, such as inductors and capacitors, where the current and voltage are out of phase with each other. This results in a power factor that is less than 1, and the apparent power drawn by the circuit includes both real power and reactive power. In such cases, some of the apparent power is not consumed by the resistive elements but instead is stored in the reactive elements and returned to the circuit at a later time.

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Answer:

0.085m/s²

Explanation:

Use v²=v0²+2a(d)

solve for a

v²-v0²/2d=a

Plug in givens

1.89²-0.78²/2*17.5=a

Plug into calculator

a=0.085m/s²

Answer:

a. Magnetic field is a location of a vector field around an electric current or magnet formed due to moving electric charges, or magnetic material and has a magnetic effect and exerts a force on other magnetic materials, electric current, and electric charges. The Earth's magnetic field that has the effect of turning a compass needle is an example of a magnetic field

b. The number of turns of the coil, N, in Diagram 1.1 > The number of turns of the coil, N, in Diagram 1.2

The pattern of the iron filings in Diagram 1.1 are closer with less space in between than the pattern of iron filings in Diagram 1.2

The angle of deflection of the ammeter pointer in Diagram 1.1 will be > The angle of deflection of the ammeter pointer in Diagram 1.2, given that the number of turns and current are inversely proportional

c. i. The pattern of the iron filings will have rings which are more closely arranged to each other as the strength of the magnetic field is increased

ii. As the number of turns is increased, the magnetic field is increased

Explanation:

Answer:

intial velocity, u=0 final velocity, v=0

Explanation:

Answer:

An egg with a thick shell.

Explanation:

Hope this helps.

Answer:

V= 5.3 Km/hr

Explanation:

Got the answer from class today

hope it helps :)

We did not get snow or freezing rain instead of sleet in Oklahoma because the temperature was not below freezing. Snow forms when the temperature is below freezing throughout the entire atmospheric column, causing water vapor to directly crystallize into ice crystals. Freezing rain, on the other hand, occurs when there is a layer of below-freezing air near the surface, causing raindrops to freeze upon contact with cold surfaces.

In the given scenario, the temperature was not below freezing, indicating that the atmospheric conditions did not support the formation of snow or freezing rain. Instead, sleet occurred, which is formed when raindrops pass through a layer of below-freezing air and partially freeze into ice pellets before reaching the ground.

Therefore, the absence of snow or freezing rain and the presence of sleet can be attributed to the temperature being above freezing during the weather event.

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The other main pieces of evidence supporting the big bang that were known before this discovery included the observed redshift of galaxies and the abundance of light elements.

The observed redshift of galaxies, discovered by Edwin Hubble, showed that galaxies are moving away from each other. This observation supports the idea of an expanding universe, which is a fundamental aspect of the Big Bang theory. The further away a galaxy is, the faster it moves away, suggesting that the universe started from a single point and has been expanding ever since.

Additionally, the abundance of light elements, such as hydrogen and helium, also supports the Big Bang theory. Scientists found that these elements make up about 75% and 25% of the observable universe, respectively. This proportion is consistent with theoretical predictions for the early universe and provides evidence for the initial high-temperature, high-density state from which the universe expanded. Before the discovery of the cosmic microwave background radiation (CMBR), the main pieces of evidence supporting the Big Bang theory included the observed redshift of galaxies and the abundance of light elements.

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The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:

1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.

2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.

3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.

4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.

5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.

These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.

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Answer:

D. chemical control

Explanation:

The reason for using chemical control as last resort in IPM is:

1) Impact is very high

2) The response is immediate

Answer:

Oh, I didn't know if u meant decigram or decagram! So for decagram there would be 10 grams and deci gram is 0.1 grams.  Hope this helps!!

Explanation:

Answer:

Hey there!

There are 10 grams in one decagram.

Let me know if this helps :)

Answer:the answer is B

Explanation:

APE X

The technology that is based on the work of Subrahmanyan Chandrasekhar is an orbiting observatory to detect X-rays from space objects, therefore the correct option is B.

Chandrasekhar's limit is a type of maximum limited value that is used to define the maximum mass of a white dwarf star. The generally internationally considered value of the Chandrasekhar limit is about 1.44 times the mass of the sun which is approximately 2.765×10³⁰ kg.

In other words, one can say that Chandrasekhar limit is the maximum value that can attain 1.44 times the solar mass.

In other words, one can say that star with a mass more than 1.44 times that of the Sun does not form a white dwarf but  continues to collapse, finally forming a neutron star

An orbiting observatory to detect X-rays from space objects is based on the principle of Chandrasekhar's limit. The correct option is B.

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Answer:

The same momentum as when on Earth

Explanation:

From a background understanding of science, the mass of an object is constant irrespective of its location.

This implies that the rover has the same mass on the earth as on the moon.

Now, we shall determine the momentum of the rover on Earth and on the Mar.

For Earth:

Let the mass on Earth (Mₑ) = 1 kg

Velocity on Earth (Vₑ) = 30 mph = 30 × 0.447 = 13.41 m/s

Momentum on Earth (Mₒₑ) =?

Momentum = mass × velocity

Mₒₑ = Mₑ × Vₑ

Mₒₑ = 1 × 13.41

Mₒₑ = 13.41 Kgm/s

Thus the momentum of the rover on Earth is 13.41 Kgm/s

For Mar:

Mass on Mar (Mₘ) = Mass on Earth (Mₑ), since mass is constant.

Mass on Mar (Mₘ) = 1 kg

Velocity on Mar (Vₘ) = Velocity on Earth (Vₑ), since the rover move with the same velocity as described by the question.

Velocity on Mar (Vₘ) = 13.41 m/s

Momentum on Mar (Mₒₘ) =?

Momentum = mass × velocity

Mₒₘ = Mₘ × Vₘ

Mₒₘ = 1 × 13.41

Mₒₘ = 13.41 Kgm/s

Therefore, the momentum of the rover on Mar is 13.41 Kgm/s

Summary:

Momentum on Earth (Mₒₑ) = 13.41 Kgm/s

Momentum on Mar (Mₒₘ) = 13.41 Kgm/s

Thus, the rover will have the same momentum as when on earth

The momentum of the object on Mars will be the same as on Earth.

The given parameters;

Weight is a vector quantity because it changes when acceleration due to gravity on the object changes while mass is scalar quantity, with a constant value in all places in the universe.

The momentum of an object is calculated as;

P = mv (kgm/.s)

Since the speed and mass of the object will be the same on both planets, the momentum will also be the same.

Thus, the momentum of the object on Mars will be the same as on Earth.

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Answer:

the answer is b.

plsss pa brainliest po ako

Answer:

a. Light bulb - electrical to light

b. Firework - chemical to light / thermal / sound

c. Flute - kinetic to sound

d. Leaf-  solar to chemical

Speed = (rate of acceleration) x (time)

Accelerating at 5.5 m/s² for 4 seconds, the car gains (5.5 x 4) = 22 m/s of speed.

If it's actually traveling at 25 m/s at the end of that time, then it must have already been moving at (25 - 22) = 3 m/s when the 4 seconds started.

The mass of the vessel, m = 74400 kg

The external diameter, d = 5.20 m

Radius, r = 5.2 / 2 = 2.6 m

The volume of the vessel is given by the volume of a sphere

a) The buoyant force (B) is given by the formula:

b) The tension in the cable is given by the equation

Where T represents the tension

T = 739613.35 - 74400(9.8)

T = 10493.35