g A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 1.97 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1680 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 4.34 V/m, (b) in the negative z direction and has a magnitude of 4.34 V/m, and (c) in the positive x direction and has a magnitude of 4.34 V/m

Answers

Answer 1

Answer:

a) 1.22*10^-18 N in the positive z direction

b) 1.65*10^-19 N in the negative z direction

c) (6.94*10^-19 N) in the positive x direction + (5.30*10^-19 N) in the positive z direction

Explanation:

See attachment for calculations

G A Proton Travels Through Uniform Magnetic And Electric Fields. The Magnetic Field Is In The Negative
Answer 2

(a) The electromagnetic force on the proton is 1.224 × 10⁻¹⁸ \(\hat k\) N

(b) The force is 1.65 × 10⁻¹⁹ \((-\hat k)\) N

(c) The force is (6.94 \(\hat i\) + 5.29 \(\hat k\)) × 10⁻¹⁹ N

Electromagnetic force on the proton:

Given a proton moving in the positive y-direction with a speed of :

v = 1680 m/s \(\hat j\)

The magnetic field is in the negative x-direction with magnitude:

B = 1.97 mT \((-\hat i)\)

(a) Electric field applied in positive z-direction :

E = 4.34 V/m \(\hat k\)

The net force on the proton is iven by:

F = q (E + v×B)

where q is the charge on proton, given by:

q = 1.6×10⁻¹⁹ C

So,

F = 1.6×10⁻¹⁹( 4.34 \(\hat k\) + 1680 \(\hat j\) × 1.97×10⁻³ \((-\hat i)\) )

F = 1.6×10⁻¹⁹ ( 4.34 \(\hat k\) + 3.309 \(\hat k\))

F = 1.224 × 10⁻¹⁸ \(\hat k\) N

(b) Electric field applied in negative z-direction :

E = 4.34 V/m \((-\hat k)\)

The net force on the proton is iven by:

F = q (E + v×B)

where q is the charge on proton, given by:

q = 1.6×10⁻¹⁹ C

So,

F = 1.6×10⁻¹⁹( 4.34 \((-\hat k)\) + 1680 \(\hat j\) × 1.97×10⁻³ \((-\hat i)\) )

F = 1.6×10⁻¹⁹ ( 4.34 \((-\hat k)\) + 3.309 \(\hat k\))

F = 1.65 × 10⁻¹⁹ \((-\hat k)\) N

(c) Electric field applied in positive x-direction :

E = 4.34 V/m \(\hat i\)

The net force on the proton is iven by:

F = q (E + v×B)

where q is the charge on proton, given by:

q = 1.6×10⁻¹⁹ C

So,

F = 1.6×10⁻¹⁹( 4.34 \(\hat i\) + 1680 \(\hat j\) × 1.97×10⁻³ \((-\hat i)\) )

F = 1.6×10⁻¹⁹ ( 4.34 \(\hat i\) + 3.309 \(\hat k\))

F = (6.94 \(\hat i\) + 5.29 \(\hat k\)) × 10⁻¹⁹ N

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Related Questions


A person holds onto an object for 2 minutes but doesn't move the object. Is work done
on the object?

A person holds onto an object for 2 minutes but doesn't move the object. Is work doneon the object?

Answers

Answer:

No

Explanation:

An electron of kinetic energy 1.59 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 35.4 cm. Find (a) the electron's speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion.

Answers

Answer:

a) \( v = 2.36 \cdot 10^{7} m/s \)

b) \( B = 3.80 \cdot 10^{-4} T \)

c) \( f = 1.06 \cdot 10^{7} Hz \)

d) \( T = 9.43 \cdot 10^{-8} s \)

Explanation:

a) We can find the electron's speed by knowing the kinetic energy:

\( K = \frac{1}{2}mv^{2} \)

Where:    

K: is the kinetic energy = 1.59 keV

m: is the electron's mass = 9.11x10⁻³¹ kg

v: is the speed =?

\( v = \sqrt{\frac{2K}{m}} = \sqrt{\frac{2*1.59 \cdot 10^{3} eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}}{9.11 \cdot 10^{-31} kg}} = 2.36 \cdot 10^{7} m/s \)

b) The electron's speed can be found by using Lorentz's equation:

\( F = q(v\times B) = qvBsin(\theta) \)   (1)

Where:

F: is the magnetic force

q: is the electron's charge = 1.6x10⁻¹⁹ C

θ: is the angle between the speed of the electron and the magnetic field = 90°

The magnetic force is also equal to:

\( F = ma_{c} = m\frac{v^{2}}{r} \)   (2)

By equating equation (2) with (1) and by solving for B, we have:

\( B = \frac{mv}{rq} = \frac{9.11 \cdot 10^{-31} kg*2.36 \cdot 10^{7} m/s}{0.354 m*1.6 \cdot 10^{-19} C} = 3.80 \cdot 10^{-4} T \)

c) The circling frequency is:

\( f = \frac{1}{T} = \frac{\omega}{2\pi} = \frac{v}{2\pi r} \)

Where:

T: is the period = 2π/ω

ω: is the angular speed = v/r

\( f = \frac{v}{2\pi r} = \frac{2.36 \cdot 10^{7} m/s}{2\pi*0.354 m} = 1.06 \cdot 10^{7} Hz \)

d) The period of the motion is:

\( T = \frac{1}{f} = \frac{1}{1.06 \cdot 10^{7} Hz} = 9.43 \cdot 10^{-8} s \)

I hope it helps you!

a shot putter heaves a 7.26kg shot with final velocity of 7.50m/s what is kinetic energy?

Answers

Answer: KE=.5mv^2

KE=.5(7.62)(7.5)^2

KE=.5(7.62)(56.25)

KE=.5(428.625)

KE=214.3125 J of KE

Explanation:

The Kinetic energy will be "214.32 J".

Given:

Mass, m = 7.26 kgFinal velocity, v = 7.50 m/s

As we know,

→ \(K.E = \frac{1}{2} mv^2\)

By substituting the values, we get

          \(= \frac{1}{2}\times 762\times (7.5)^2\)

          \(= \frac{1}{2}\times 7.62\times 56.25\)

          \(= \frac{1}{2}\times 428.625\)

          \(= 214.32 \ J\)

Thus the response above is appropriate.

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During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of 39.0 kg and its horizontal component of velocity is 6.50 m/s just before the 65.0 kg performer catches it. If the performer is initially motionless on nearly frictionless roller skates, what is his speed immediately after catching the cannon ball

Answers

Answer:

\(2.4375\ \text{m/s}\)

Explanation:

\(m_1\) = Mass of cannon ball = 39 kg

\(m_2\) = Mass of performer = 65 kg

\(u_1\) = Initial horizontal component of cannon ball's velocity = 6.5 m/s

\(u_2\) = Initial horizontal component of performer's velocity = 0

v = Velocity of combined mass

As the momentum of the system is conserved we have

\(m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{39\times 6.5+0}{39+65}\\\Rightarrow v=2.4375\ \text{m/s}\)

The speed of the performer immediately after catching the cannon ball is \(2.4375\ \text{m/s}\).

3. How much power does an electric light installation draw at 120 V if it creates a current of 0.8 amps?
O A. 32 watts
O B. 120 watts
Q C. 48 watts
D. 96 watts

Answers

Answer:D

Explanation:

R =  

V

I

=  

120 volt

0.8 ampere

=  150 ohm (Ω)

P =  V × I

=  120 volt × 0.8 ampere

=  96 watt (W)

An electric light installation  can draw Power of 96 Watt  at 120 V if it creates a current of 0.8 amps

What is electric power ?

Electric power  is the rate of electric energy transfer by an electric circuit per unit time . It is denoted by P and measured using the SI unit of power that is Watt (W)

since, Electric Power   = voltage * current

Power    = 120 V * 0.8 A

Power    = 96 Watts

An electric light installation  can draw Power of 96 Watt  at 120 V if it creates a current of 0.8 amps

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a box of mass 8.0 kg rests on a horizontal rough surface. a string attached to the box passes over a smooth pulley and supports a 2.0 kg mass at its other end, when the box is released, a frictional force of 6.0 n acts on it. (a) draw free-body diagrams of the 8.0 kg box and the 2.0 kg mass. (b) determine the (i) acceleration of the system, (in) tension in the string.

a box of mass 8.0 kg rests on a horizontal rough surface. a string attached to the box passes over a

Answers

a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.

bi) the acceleration of the system is 0.4 m/s^2

bii)  the tension in the string is 0.8 N.

How do we calculate?

Net force = ma

Net force = T - F_friction

where T is the tension force and F_friction is the frictional force.

Substituting the given values, we have:

T - F_friction = ma

T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)

T - 6.0 N = 10.0 kg a

(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:

Net force = ma

where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:

Net force = T

Substituting the given values, we get:

T = ma

T = 2.0 kg x a

To solve for T, we need to find the acceleration of the system.

To find both a and T, we can use the equations we derived above and solve them simultaneously:

T - 6.0 N = 10.0 kg a (equation 1)

T = 2.0 kg x a (equation 2)

Substituting equation 2 into equation 1, we get:

2.0 kg x a - 6.0 N = 10.0 kg a

Solving for a, we get:

a = 0.4 m/s^2

Substituting a into equation 2, we get:

T = 2.0 kg x 0.4 m/s^2 = 0.8 N

Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.

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1. Which object would have more inertia — a 1,000 kg car or a 150 kg golf cart?

Answers

Answer:a car with 1,000kg

Explanation: A car with a mass of 1,000kg has more inertia than 150 kg

Out of the two objects a 1000-kilogram car and a 150-kilogram golf cart, the 1000-kilogram cart will have more inertia as the inertia of any object is directly proportional to its mass.

What is Newton's first law?

According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.


The larger the mass of the object, the greater would be the inertia of the object.

Thus, a 1000-kilogram automobile will have higher inertia than a 150-kilogram golf cart since any object's inertia is directly proportionate to its mass.

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In a Newton’s ring arrangement with a film observed with light of wavelength 6 x 10-5 cm,
the difference of square of diameters of successive rings are 0.125 cm2
. What will happen
to this quantity if:
i) Wavelength of light is changed to 4.5 x 10-5 cm.
ii) A liquid of refractive index 1.33 is introduced between the lens and the plate.
iii) The radius of curvature of convex surface of plano-convex lens is doubled.

Answers

Answer:

In a Newton's ring arrangement, the difference in the square of the diameters of successive rings is equal to four times the wavelength of light divided by the refractive index of the medium between the planoconvex lens and the plane glass plate.

If the wavelength of light is changed to 4.5 x 10-5 cm, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by the refractive index of the medium (which is assumed to be 1 if a liquid of refractive index 1.33 is not introduced).

If a liquid of refractive index 1.33 is introduced between the lens and the plate, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by 1.33.

If the radius of curvature of the convex surface of the plano-convex lens is doubled, then the difference in the square of the diameters of successive rings will remain the same.

true/false. in a recrystallization process, the impurities should either be completely soluble in the recrystallization solvent throughout the operating temperature range or remain insoluble in the recrystallization solvent throughout the operating temperature range.

Answers

True. The impurities in a recrystallization process must either be soluble in the solvent or the operating temperature range or they must not be soluble in the solvent at all during the operating temperature range.

Which impurities in a compound should be extremely soluble or highly insoluble in the solvent while doing recrystallization?

You need to remove impurities from your compound, and they must either be soluble in the cold solvent or insoluble in the hot solvent. If not, your chemical will crystallize with theirs. In hot filtration, they are removed if they are insoluble in the hot solvent.

What happens to impurities during recrystallization, both soluble and insoluble?

After cooling, the soluble pollutants stay in the solution and go through the filter during suction filtration. If there are any insoluble contaminants in the sample, they are filtered out by gravity filtration before the heated solution cools.

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What was used as a basket at each end of the gym?

Group of answer choices

bucket

hula hoop

apple basket

peach basket

Answers

Apple basket hope this helped

Answer: apple basket ✨

Explanation:

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?

Answers

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

What is heat of fusion ?

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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How to explain third law when a boat is moving away from a paddock when a women’s feet is on the paddock and the boat

How to explain third law when a boat is moving away from a paddock when a womens feet is on the paddock

Answers

Answer:

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.

an inclined plane has a velocity ratio of 2 and efficiency of 95%. it is used to raise a load of 400newtons. determine mechanical advantage? effort required?

Answers

Answer:

1.9

Explanation:

Efficiency=mechanical advantage/velocity ratio×100

95=M.A/2×100

95=50M.A

M.A=95/50=1.9

The mechanical advantage of the inclined plane is approximately 2.1053, and the effort required to raise the load of 400 newtons is approximately 189.78 newtons.

To determine the mechanical advantage and effort required for the inclined plane, we can use the formula:

Mechanical Advantage (MA) = Velocity Ratio (VR) / Efficiency

Effort Required = Load / Mechanical Advantage

Given:

Velocity Ratio (VR) = 2

Efficiency = 95% = 0.95

Load = 400 newtons

Calculate the Mechanical Advantage (MA):

MA = VR / Efficiency

MA = 2 / 0.95

MA ≈ 2.1053

Calculate the Effort Required:

Effort Required = Load / MA

Effort Required = 400 / 2.1053

Effort Required ≈ 189.78 newtons

So, the mechanical advantage of the inclined plane is approximately 2.1053, and the effort required to raise the load of 400 newtons is approximately 189.78 newtons.

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A dart in a toy dart gun is pressed 4 cm against a spring. if it has 1.5 J of stored potential energy what is the spring constant?

Answers

U = 0.5k(x^2)
1.5 J = 0.5k(0.04m^2)
k = 1875 N/m

Check my math i might be wrong

how can an object have the same speed and mass but change its momentum?​

Answers

Answer: It can change its direction

Explanation:

Momentum is a vector, which has magnitude and direction.  An object can have the same speed and mass (magnitude) but if it changes direction, it just changed its momentum

Very Important, I need the answer

Very Important, I need the answer

Answers

Answer:

A

Explanation:

A constant velocity means the position graph has a constant slope. It's a straight line sloping up.

The number of distinct ways of placing four indistinguishable balls into five distinguishable boxes is _____

Answers

The number of distinct ways of placing four indistinguishable balls into five distinguishable boxes is 20.

To solve this problem, we can use the stars and bars method, which is a combinatorial technique used to count the number of ways to distribute indistinguishable objects into distinguishable containers. In this case, we have four indistinguishable balls and five distinguishable boxes.

The stars and bars method works by representing each ball as a star and using bars to separate the balls into different boxes. For example, if we wanted to distribute two balls into three boxes, we could use the following diagram:

* | * * | *

In this diagram, the first and last bars represent the boundaries of the containers, while the stars represent the balls.

The second bar separates the first two balls from the last ball, indicating that the first two balls are in the first container and the last ball is in the third container.

To distribute four balls into five boxes, we need to use three bars to separate the balls into four groups. We have a total of six spaces to place the bars (including the boundaries), and we need to choose three of them to place the bars.

Therefore, the number of distinct ways to place four indistinguishable balls into five distinguishable boxes is the same as the number of ways to choose three spaces out of six, which is:

6 choose 3 = (6!)/(3!3!) = 20

Therefore, there are 20 distinct ways to place four indistinguishable balls into five distinguishable boxes using the stars and bars method.

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Which psychologist contributed significantly to the humanistic psychology movement

Answers

Carl Rogers, along with Abraham Maslowsignificantly contributed to the humanistic psychology movement through his development of the person-centered approach and his emphasis on the individual's subjective experience and potential for personal growth.

Carl Rogers was a psychologist who played a significant role in the development of humanistic psychology. Alongside Abraham Maslow, Rogers helped establish and promote the humanistic approach to understanding human behavior and experience.Humanistic psychology: Humanistic psychology is a psychological perspective that emphasizes the inherent worth and potential of individuals. It focuses on the subjective experience, self-actualization, personal growth, and the importance of human values.Carl Rogers: Carl Rogers was an influential figure in the humanistic psychology movement. He developed the person-centered approach, also known as client-centered therapy or the Rogerian approach.Person-centered approach: Rogers emphasized the importance of providing a supportive and empathetic environment for individuals to promote their personal growth and self-understanding. He believed that individuals have an innate tendency towards self-actualization, and the role of the therapist is to facilitate this process by providing unconditional positive regard and empathy.Contributions: Rogers made significant contributions to the field of psychology, particularly in the areas of therapy and counseling. His emphasis on the individual's subjective experience and the importance of the therapeutic relationship had a profound impact on the field.Humanistic movement: Alongside Abraham Maslow, Rogers helped establish humanistic psychology as a distinct movement within the field. Their work focused on the holistic understanding of human experience, personal growth, and self-actualization, challenging the dominant perspectives of behaviorism and psychoanalysis.Legacy: Rogers' contributions continue to influence psychology, counseling, and therapy today. The humanistic approach has expanded beyond clinical applications to areas such as education, leadership, and personal development.

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A red horse and a black horse raced on a 1-mile long circular racetrack. The red horse
completed the race in 120 seconds, and the black horse completed the race in 150
seconds. Which choice correctly describes the speed of the horses?
A- Only the red horse ran at a constant speed
B- The red horse's average speed was greater than the black horse's average speed.
C- The black horse's average speed was greater than the red horse's average speed.
D- Only the black horse ran at a constant speed.

Answers

Answer

your format is incorrect!!

Explanation:

there is no such thing as a red horse. there are chestnuts, bays and red roans, just no reds. usually though, blacks are faster scientifically than red roans.

From the top of a cliff, 100m above sea level, a stone is thrown vertically upward with a velocity of 30m/s. After how many seconds and with what velocity will it hit the sea?.

Answers

According to the given statement After t = (√29+3) seconds and with v = 10√29 m/s velocity will it hit the sea.

What is a velocity ?

The displacement how an object and particle experiences with regard to time is expressed vectorially as velocity. The meter per second (m/s) is the accepted unit of flow speed (also known as speed). Instead, the magnitude of velocity can be expressed in centimeters per second (cm/s).

Briefing:

Initial height = 100 m

Initial velocity = 30 m/s

g = 10 m/s²

To Find

Time taken and final velocity

Solution

v²-u² = 2as & v = u + at

Assuming downward motion to be positive

According to the Question :

⇒ v²-u² = 2as

⇒ v²-30² = 2(10)(100)

⇒ v² = 900+2000

⇒ v² = 2900

⇒ v = √2900

v = 10√29 m/s

So then the time taken would be

⇒ v = u + at

⇒ 10√29 = (-30) + 10t

⇒ (10√29+30)/10 = t

t = (√29+3) sec

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Suppose the same car had at one point an acceleration of 12m/s^2 and an initial velocity of 8m/s. After 2 seconds, what would be the car's final velocity

Answers

Answer: 32 m/s

Explanation: v = u + at

                         = 8 + 12*2

                         = 8 + 24

                         = 32 m/s

A 1,200 kg car accelerates at 3 m/s2. What net force is the car experiencing during this
acceleration?
0 3600 N
0 2000 N
2400 N
O ON

Answers

Answer:

3600 N

Explanation:

F=ma

1200*3 = 3600

What is the term that describes waves that require a medium through which to travel?

Answers

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

A horizontal rope is attached from a truck to a 1480-kg car. As the truck tows the car on a horizontal straight road, the rope will break if
the tension is greater than 2693 N. Ignoring friction, what is the maximum possible acceleration of the truck if the rope does not
break?
m/s²

Answers

The maximum possible acceleration of the truck is less than 1.82 m/s².

calculation:-

Force = mass × acceleration

since force is fixed = 2693 N

acceleration = force /mass

                     = 2693 /1480

                      = 1.82 m/s²

If acceleration increases above this then the tension force increases and the rope will break.

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net force appearing on that object.

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic force is the strongest.
N

The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic

Answers

Answer:

strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Explanation:

The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.

Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

1. A 63 kg driver gets into an empty taptap to start the day's work. The springs compress 1.5x10-2 m. What is the effective spring constant of the spring system in the taptap?
2. After driving a portion of the route, the taptap is fully loaded with a total of 24 people including the driver, with an average mass of 68 kg per person. In addition, there are three 15-kg goats, five 3-kg chickens, and a total of 25 kg of bananas on their way to the market. Assume that the springs have somehow not yet compressed to their maximum amount. How much are the springs compressed?

Answers

(1) When the driver is at rest, the restoring force exerted by spring is equal in magnitude to the driver's weight, so that

F = s - mg = 0   ==>   s = mg = 617.4 N

If the spring is compressed 0.015 m, then the spring constant k is such that

617.4 N = k (0.015 m)   ==>   k = 41,160 N/m ≈ 41 kN/m

(2) The total mass of the passengers is

24 (68 kg) + 3 (15 kg) + 5 (3 kg) + 25 kg = 1717 kg

so that if everyone is at rest, the spring is compressed a distance x such that

kx = (1717 kg) g   ==>   x0.41 m

A catapult of pole length 4r throws a pumpkin from one
end of a pole which rotates about an axis at the other
end with angular speed w.
A smaller catapult of pole length r throws another
pumpkin from one end of a pole which rotates about an
axis at the other end with the same angular speed was
the first catapult.
How does the linear speed of the larger catapult's
pumpkin Vlarge compare with the smaller catapult's
pumpkin Vsmall?

Answers

Answer:

vlarge = 4vsmall

Explanation:

Khan Academy

An object traveling at 1.5 rad
accelerates at 0.75d for 12
S
seconds. What is the object's final
velocity?

Answers

The object's final velocity, given the data is 10.5 rad/s

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the final velocity

The following data were obtained from the question

Initial velocity (u) = 1.5 rad/sAcceleration (a) = 0.75 rad/s²Time (t) = 12 sFinal velocity (v) = ?

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

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1.Which among the following is measured using a Vernier Caliper?
[A] Dimensions
[B] Time
[C] Sound
[D] Temperature

Answers

Dimensions are measured using a Vernier Caliper  (option A)

What is a Vernier Caliper?

A device renowned for its accuracy in measuring the size of objects, the Vernier caliper functions with two jaws to hold an object steady as its scale offers readings. It can assess both external and internal measurements as well as depth with precision.

The Vernier caliper is made up of two main parts: the main scale and the vernier scale. The main scale is a graduated scale that is used to read the measurement in millimeters. The vernier scale is a smaller scale that is used to read the measurement in fractions of a millimeter.

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50 POINTS!! HOW DO THIS PLEASE IM SO CONFUSED

50 POINTS!! HOW DO THIS PLEASE IM SO CONFUSED

Answers


Hope this helps!
Please give Brainliest!

This is all about reflection.
So my theory on this is that you have to look at the checklist:
L : Location
O : Orientation
S : Size
T : Type

Answer the questions ( by questions I mean the LOST questions, where they ask you to choose on of the options. For example, for ‘T’ you have to choose as to whether it is ‘real or virtual’ ) by using the diagram below:
50 POINTS!! HOW DO THIS PLEASE IM SO CONFUSED
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