= f(x)= 4 -x, for what input is the output 7

Answer:

498 leaves per bag

Step-by-step explanation:

unit rate u divide denominator (bottom#) by itself

what u do to top u do to bottom

so 7÷7=1 3486÷7=498

3486/7 turns to 498/1

Answer:

Answer: x = √3 and 8/(3√3)

Step-by-step explanation:

\({ \rm{({2}^{ {x}^{2} } )(2 \frac{3x \sqrt{3} }{2}) = 8}}\)

• For the first bracket:

\({ \rm{ {2}^{ {x}^{2} } = 8}} \\ \\ { \rm{ {2}^{ {x}^{2} } = {2}^{3} }} \\ \\ { \rm{ {x}^{2} = 3}} \\ \\ { \rm{x = \pm \sqrt{3} }}\)

• For the second bracket;

\({ \rm{ 2 \frac{3x \sqrt{3} }{2} = 8}} \\ \\ { \rm{3x \sqrt{3} = 8 }} \\ \\ { \rm{3x = \frac{8}{ \sqrt{3} } }} \\ \\ { \rm{x = \frac{8}{3 \sqrt{3} } }}\)

a. The probability that the sample mean will be within ±5 of the population mean is the area under the normal curve between these two z-scores. b. The lower bound z-score is (-10 - 0) / 10 = -1, and the upper bound z-score is (10 - 0) / 10 = 1. We can use the same normal distribution table or technology to find the probability associated with these z-scores.

(a) To find the probability that the sample mean will be within ±5 of the population mean, we can use the Central Limit Theorem (CLT) and the properties of a normal distribution.

The sample mean, is an unbiased estimator of the population mean, μ. According to the CLT, the distribution of sample means approaches a normal distribution with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

     = 200 / √400

     = 200 / 20

     = 10

To find the probability that the sample mean will be within ±5 of the population mean, we can standardize the interval using the z-score:

For the lower bound (-5), the z-score is (-5 - 0) / 10 = -0.5.

For the upper bound (+5), the z-score is (5 - 0) / 10 = 0.5.

We can now use a standard normal distribution table or technology (such as a calculator or statistical software) to find the probability associated with the z-scores -0.5 and 0.5. The probability that the sample mean will be within ±5 of the population mean is the area under the normal curve between these two z-scores.

(b) To find the probability that the sample mean will be within ±10 of the population mean, we follow the same steps as in part (a).

The lower bound z-score is (-10 - 0) / 10 = -1, and the upper bound z-score is (10 - 0) / 10 = 1. We can use the same normal distribution table or technology to find the probability associated with these z-scores.

Note: Since the question mentions rounding answers to four decimal places, please use the appropriate table or technology to obtain the precise probabilities for parts (a) and (b).

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3.4  Step-by-step explanation:

The area of path is 13.5 m².

The area can be defined as the amount of space covered by a flat surface of a particular shape. It is measured in terms of the "number of" square units (square centimeters, square inches, square feet, etc.) The area of a rectangle is the number of unit squares that can fit into a rectangle.

Thus, the formula for the area, 'A' of a rectangle whose length and width are 'l' and 'w' respectively is the product "l × w".

length of flower bed = 3m

width of flower of bed = 1.5 m

length of bed along path = 3 + 1+ 1 = 5m

width of flower bed = 1.5 + 1+ 1 = 3.5 m

So, area of flower bed along path = 5 x 3.5 = 17.5 m²

and, area of flower bed = 3 x 1.5 = 4.5 m²

Thus, area of path = 17.5 - 4.5 = 13.5 m²

hence, the area of path is 13.5 m².

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When estimating a population mean, you are more likely to be correct when using an interval estimate rather than a point estimate. An interval estimate provides a range of values within which the true population mean is likely to fall, accounting for uncertainty. This range provides a higher level of confidence compared to a single point estimate.

When estimating a population mean, you are more likely to be correct when using an interval estimate rather than a point estimate. The reason is that an interval estimate provides a range of values within which the population mean is likely to fall, taking into account the inherent uncertainty in the estimation process.

A point estimate, on the other hand, provides a single value as an estimate of the population mean, without accounting for the variability or margin of error. While a point estimate may be close to the true population mean, there is no measure of confidence or precision associated with it.

An interval estimate, such as a confidence interval, incorporates both a point estimate and a margin of error, which quantifies the uncertainty in the estimate. By providing a range of values, the interval estimate acknowledges that the true population mean may fall within that range with a certain level of confidence.

Using an interval estimate allows for a more comprehensive understanding of the population mean and provides a measure of the reliability of the estimate. It acknowledges the inherent variability in sampling and estimation processes, ultimately increasing the likelihood of being correct in estimating the population mean.

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Answer:

s and t and u and t

Step-by-step explanation:

the sides of the triangle should be the same

Field data aggregation is the process of summarizing, combining, and analyzing data that has been collected from various sources. The following are some of the common ways that field data is aggregated: Count of Failures: A count of how many times a failure has occurred within a given period of time,

such as a day or a week. Number of Failed Parts: The number of parts that have failed over a given period of time, such as a day or a week. Hours of Operation: The amount of time that a machine or system was operational during a given period of time, such as a day or a week. Maintenance Time: The amount of time that was spent maintaining a machine or system during a given period of time, such as a day or a week.

Mark for Follow-Up: An indication of which issues need to be addressed or followed up on to prevent future failures or improve performance. Field data aggregation is the process of summarizing, combining, and analyzing data that has been collected from various sources. The following are some of the common ways that field data is aggregated: Count of Failures: A count of how many times a failure has occurred within a given period of time,

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Answer:

-2x-2y=-8

-4x-8y=-20

From the 1st eqn

Dividing through by 2

you have

-x-y=-4

Multiply through by -(minus)

x+y=4

x=4-y

Substitute into eqn 2

-4x-8y=-20

-4(4-y)-8y=-20

-16 + 4y - 8y = -20

-4y = -20 +16

-4y = -4

y= 1

Substitute into any of the other eqn's to get x

x= 4-y

x= 4-1

x=3

a. The composite scores for each location are as follows: Location A: 84.34, Location B: 81.05, Location C: 82.63 (b)  Based on the composite scores, Location A should be chosen for the clothing store.

To determine the composite score for each location, we need to calculate the weighted sum of the factor ratings.

a. The composite score for each location is calculated as follows:

Location A:

Composite score = (Convenience of access * Weight) + (Parking facility * Weight) + (Frontage * Weight) + (Shopper traffic * Weight) + (Operating cost * Weight) + (Neighbourhood * Weight)

Composite score = (0.10 * 92) + (0.15 * 91) + (0.19 * 96) + (0.31 * 79) + (0.10 * 70) + (0.15 * 69)

Composite score = 84.34

Location B:

Composite score = (0.10 * 70) + (0.15 * 73) + (0.19 * 89) + (0.31 * 95) + (0.10 * 95) + (0.15 * 81)

Composite score = 81.05

Location C:

Composite score = (0.10 * 72) + (0.15 * 75) + (0.19 * 74) + (0.31 * 80) + (0.10 * 92) + (0.15 * 96)

Composite score = 82.63

b. Based on the composite scores, we can see that Location A has the highest score of 84.34, followed by Location C with a score of 82.63, and Location B with a score of 81.05. Therefore, Location A should be chosen for the clothing store.

After calculating the composite scores for each location based on the factor ratings and weights, it is determined that Location A has the highest composite score and should be chosen for the clothing store.

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The ratio of false positives to true positives is 8 over 54.

According to the Question

Results of a strep throat test performed on a sample of 400 ill people are displayed in the table's data. People who have the flu and those who don't are separated into two categories. The patients are then separated into groups based on whether they tested positive or negative for strep throat within each of these categories.

We must first define what a true positive and a false positive are in order to calculate the ratio of false positives to true positives. A patient who tests positive for strep throat but does not actually have the illness is said to have a false positive. The 8% of patients in this instance who tested positive for strep throat but did not have the flu would fall under that category. A patient who tests positive for strep throat and truly has the illness is said to have a true positive. That would be the 54% of patients who tested positive for both the flu and strep throat in this instance.

We divide the percentage of false positives (8%) by the percentage of true positives (54%), which gives us the ratio of false positives to true positives.

As a result, the ratio becomes 8% / 54%, or 8/54.

It's critical to remember that this ratio is dependent on the sample and test performed and may not be the same for different populations or testing methodologies.

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The profit-maximizing level of output can be determined by finding the quantity where the difference between (TR) and (TC) is maximized.the (Π) can be calculated by subtracting the (TC) from the (TR).

To find the profit-maximizing level of output, we need to identify the quantity at which the difference between total revenue (TR) and total cost (TC) is maximized. This occurs when the marginal revenue (MR) equals the marginal cost (MC). Since total revenue is the product of price (P) and quantity (Q), and the given information provides a revenue function, we can differentiate the total revenue function with respect to quantity to find the marginal revenue function. Equating the marginal revenue to the marginal cost, we can solve for the quantity that maximizes profit.

Once the profit-maximizing level of output is determined, we can calculate the total profit (Π) by subtracting the total cost (TC) from the total revenue (TR) at that level of output. In other words, Π = TR - TC. Plugging in the quantity obtained from part (a) into the revenue and cost functions, we can evaluate the total profit. However, without specific values for the constants in the revenue and cost functions (such as 22 and 0.5 in the total revenue function and 1/3, -8.5, 50, and 90 in the total cost function), it is not possible to provide the exact calculations in this context.

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The mean of the number of houses burglarized in this sample is 4.5 based on probability.

The probability of a house in an urban area being burglarized is 15%. This means that out of every 100 houses, 15 will be burglarized.

If 30 houses are randomly selected, we can use the binomial distribution to find the mean number of houses burglarized. The formula for the mean of a binomial distribution is:

Mean = n * p

where n is the number of trials (in this case, 30) and p is the probability of success (in this case, 0.15).

Substituting these values, we get:

Mean = 30 * 0.15
Mean = 4.5

Therefore, the mean number of houses burglarized out of 30 randomly selected houses is 4.5. Note that this is an expected value and may not represent the actual number of houses burglarized in any particular sample of 30 houses.
To find the mean of the number of houses burglarized, we can use the formula:

Mean = (Probability of success) x (Number of trials)

In this case:
- Probability of success (a house being burglarized) is 15%, or 0.15 as a decimal.
- Number of trials (randomly selected houses) is 30.

Using the formula, we get:

Mean = (0.15) x (30) = 4.5

So, the mean of the number of houses burglarized in this sample is 4.5.

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5/x = x/ 9

Cross-multiply

x² =45

Take the square root of both-side

x = 3√5 or 6.7082039325

Under Trigonometric ratios, the values of sin, cos, and tan are defined by the ratio of sides of a right-angled triangle.

 One of the three fundamental functions in trigonometry, along with cosine and tan functions, is the sine function.

The ratio of the opposite side of a right triangle to its hypotenuse is known as the sine x or sine theta.

To determine a right triangle's unknown angle or sides, utilize the sine function. The sine function for any right triangle with an angle, let's say ABC, will be:

Opposite/hypotenuse = Sin

According to the trigonometric table, the value of Sin 45=\(\sqrt\)2/2 which can be simplified as \(\sqrt{2} /2\)×\(\sqrt{2} /\sqrt{2} =2/\sqrt[]{2}\)\(=1/\sqrt{2}\)

Simplified value of Sin 45=1/\(\sqrt{2}\)

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Answer:

clue 1 with graph 3, Clue 2 with graph 4, clue three with graph 1, and clue 4 with graph 2

Step-by-step explanation:

Hope this helps :)

Yes, Paul's Online Math Notes is a good enough source for self-teaching calculus 3 and ODE.

The site is well-organized, with clear explanations and plenty of examples and practice problems. It also includes a section on differential equations, which is helpful for those studying ODE.

However, it is always a good idea to supplement your learning with additional resources, such as textbooks, online videos, and practice problems from other sources.

This will help you gain a deeper understanding of the material and ensure that you are well-prepared for exams.

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Answer:

a) 12 ( I'm pretty sure)

Step-by-step explanation:

Answer:

answer of this question is A

Answer:

25

Step-by-step explanation:

we have to subtract SPQ from SRQ=SQR

mark me as brainliest

Answer:

(a) The strip should be 5ft wide

(b) The strip around the outside field is 10ft wide.

Step-by-step explanation:

Given:

Length of the rectangular field, L= 200 ft

width of the rectangular field, w = 100 ft

Area of the rectangular field, A = 200ft x 100ft = 20000 ft^2

let the width of the strip = x

The strip around the outside field = 2x

If the field is increased by 15.5%

New area of the field = 1.155 x 20000 = 23,100 ft^2

The increase in area of the field = 3,100 ft

3,100 = New area of field - old area of the field

3100 = (200 + 2x)(100 + 2x) - 20000

3100 = 20000 + 400x 200x + 4x^2 - 20000

3100 = 600x + 4x^2

Divide through by 4

775 = 150x + x^2

x^2 + 150x - 775 = 0

Factorize

(x + 155)(x-5) = 0

x = 5 ft

The strip should be 5ft wide.

The strip around the outside field = 2 x 5 ft = 10 ft

Thus, the strip around the outside field is 10ft wide.

The correct answer is B. created in an iterative and incremental manner.

Unlike traditional Work Breakdown Structures (WBS), evolutionary WBSs are developed in an iterative and incremental manner. This means that they are built and refined over time as the project progresses, allowing for adjustments and additions to be made as new information becomes available. The evolutionary WBS is not organized in a standard manner across all projects (A) and it is not specifically designed for comparison to past projects (C). Therefore, the answer is B. created in an iterative and incremental manner.

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Answer:

Hope the picture will help you

Answer:

11x + 4y - y^2

Step-by-step explanation:

You plus the same variables, in this time you got 9x and 2x so it's 11x!

Answer:

11x + 4y - y²

Step-by-step explanation:

9x + 4y + 2x - y²

combine like terms

11x + 4y - y²

150 will show up as a demand in week 3. 150 will show up as a demand in week 3 if the lead time is two weeks and the batch size is 150.

Based on the given information, the lead time is two weeks, which means that the time between placing an order and receiving the order is two weeks. Therefore, if we place an order in week 1 for a batch size of 150, the order will arrive in week 3. Hence, the demand for 150 units will show up in week 3.

Lead time is the amount of time between placing an order and receiving the order. It is an important factor in inventory management because it affects the availability of products and the level of inventory required. Batch size is the quantity of units produced or ordered in one batch. It is also an important factor because it affects the cost of production and the level of inventory. In this case, the lead time is two weeks, and the batch size is 150. If we place an order in week 1 for a batch size of 150, the order will arrive in week 3. This means that there will be a demand for 150 units in week 3.  To understand this better, let's consider the timeline of events. In week 1, we place an order for 150 units. In week 2, the order is in transit and not yet received. In week 3, the order arrives, and we receive 150 units. Therefore, the demand for 150 units will show up in week 3.

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Answer: -11.8  =  11.8 feet below the water's surface

Step-by-step explanation:

-15 + (0.5)(4) + 3(0.4)

-15 + 2 + 1.2

-11.8

The pairs of sets in which one is a subset of the other are:

- A, D
- A, B
- B, D

To identify the pairs of sets in which one is a subset of the other, we need to check if the elements of one set are completely contained within the other set.

Let's analyze each pair of sets:

- A is a subset of D because all the elements of A (2, 4, and 6) are also present in D (4, 6, and 8).

- B is a subset of A because all the elements of B (2 and 6) are also present in A (2, 4, and 6).

- B is a subset of D because all the elements of B (2 and 6) are also present in D (4, 6, and 8).

- A is not a subset of C because A contains an element (4) that is not present in C.

- D is not a subset of C because D contains an element (8) that is not present in C.


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Answer:

v = 72 km/h

Step-by-step explanation:

Given that,

The distance covered by the Patrick, d = 288 km

Time taken, t = 4 hours

We need to find the average speed of Patrick. We know that the average speed of an object is equal to the total distance covered divided by total time taken. Let it is v. So,

\(v=\dfrac{d}{t}\\\\v=\dfrac{288\ km}{4\ h}\\\\v=72\ km/h\)

So, his average speed is equal to 72 km/h.

If the utilization of an M/M/1 model is 0.6, the c of time there is at least one person in the system is 100%.

In an M/M/1 model, the utilization represents the ratio of the arrival rate (λ) to the service rate (μ). If the utilization is less than 1, it means that the arrival rate is lower than the service rate, and the system is not fully utilized. However, even with a utilization of 0.6, there will still be instances where there is at least one person in the system. This is because the arrival rate is not zero, indicating that customers are still arriving, albeit at a lower rate compared to the service rate. Therefore, the percentage of time with at least one person in the system would be 100%. If you are told that the utilization rate for an M/M/1 model is 0.8 and the average number of people in the system is 4, it is impossible to determine the average number of people in the queue without further information. The average number of people in the queue depends on factors such as the arrival rate and service rate, which are not provided in this scenario. The utilization rate alone and the average number of people in the system do not provide sufficient information to calculate the average number of people in the queue accurately. Therefore, it is impossible to determine the average number of people in the queue based solely on the given information.

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300 teenagers went to the zoo.

given that

Tickets to the zoo cost $4 for children.

Tickets to the zoo cost $5 for teenagers.

Tickets to the zoo cost $6 for adults.

1200 people come to the zoo every day.

on a certian day, the total revenue at the zoo was $5300.

Let the number of adults be x.

The number of teenagers be y.

and the number of children that went to the zoo 8y/3.

Consider the question

1200 people come to the zoo every day.

x + y + 8y/3 = 1200

now, take L.C.M between y and 8y/3

\(x + \frac{(3y + 8y)}{3} = 1200 \\ x + \frac{11y}{3} = 1200\)

now multiply with 3 to this equation.

3x + 11y = 3600 .......................(1)

tickets to the zoo cost $4 for children, $5 for teenagers and $6 for adults.

according to the question

6x + 5y + 32y/3 = 5300

Now take the L.C.M between 5y and 32y/3

6x + 47y/3 = 5300

now multiply with 3 to this equation.

18x + 47y = 15900 ...................(2)

now, multiply equation (1) with 6

18x + 66y = 21600 .....................(3)

now, subtract equation (1) in equation (2)

(18x - 18x) + (66y - 47y) = (21600 - 15900)

19y = 5700

y = 5700/19

y = 300

Hence, the 300 teenagers went to the zoo.

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