Functions can be defined using graphs, tables, and ordered pairs. What is the domain of a function?
The domain is any y-value.
The domain is all numbers.
The domain is the input.
The domain is the output.

Answer:

x=7-2y

Step-by-step explanation:

Answer:

A. The graph of g(x) is vertically compressed by a factor of 3.

Step-by-step explanation:

When there is a fraction, that means that there is a veritcal dilation.

Hope this helps! Good luck!

The ordered pairs (8, 5), (-4, 1), and (-7, -4) are solutions to the inequality 2x - 9y > -10.so it is a solution.

To determine whether each ordered pair is a solution to the inequality 2x - 9y > -10, we  the values of x and y into the inequality and check if the inequality holds true.

1. For the ordered pair (-5, 0):

  Substitute x = -5 and y = 0 into the inequality:

  2(-5) - 9(0) > -10

  -10 - 0 > -10

  -10 > -10

The inequality is not true for this ordered pair, so it is not a solution.

2. For the ordered pair (8, 5):

  Substitute x = 8 and y = 5 into the inequality:

  2(8) - 9(5) > -10

  16 - 45 > -10

  -29 > -10

The inequality is true for this ordered pair, so it is a solution.

3. For the ordered pair (-4, 1):

  Substitute x = -4 and y = 1 into the inequality:

  2(-4) - 9(1) > -10

  -8 - 9 > -10

  -17 > -10

The inequality is true for this ordered pair, so it is a solution.

4. For the ordered pair (-7, -4):

  Substitute x = -7 and y = -4 into the inequality:

  2(-7) - 9(-4) > -10

  -14 + 36 > -10

  22 > -10

The inequality is true for this ordered pair, so it is a solution.

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The rate of increasing the area of the rectangle is 72cm²/s

We have, The length of a rectangle is increasing at a rate of 5 cm/s and its width is increasing at a rate of 4 cm/s. When the length is 13 cm and the width is 4 cm, we have to find how fast is the area of the rectangle increasing.

The area of a rectangle is given by, A = l × w

Where l is the length and w is the width.

Now we will differentiate the equation with respect to time t.

dA/dt = d/dt (l × w)

dA/dt = l(dw/dt) + w(dl/dt)

We can use this formula to calculate how fast the area of the rectangle increases when the length is 13 cm and the width is 4 cm.

Substituting the given values, l = 13 cm and dl/dt = 5 cm/s w = 4 cm and dw/dt = 4 cm/s

dA/dt = 13(4) + 4(5)

dA/dt = 72 cm²/s

Therefore, the area of the rectangle increasing at a rate of 72 cm²/s.

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Answer:

f(9) = f(8)·(-3)

Step-by-step explanation:

A recursive function is one where each successive term is calculated using the previous term;

The clear pattern demonstrated in the sequence of terms shown is that each term is multiplied by -3 to give the next one;

Hence, the correct option is the first.

Answer:

The Answer is A. f(9) = f(8) • (−3)

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Given:

A survey stopped men and women at random to ask them where they purchased groceries, at a local grocery store or online. Grocery Options

Store Online Total

Women 23 12 35

Men 22 15 37

Total 45 27 72

Required:

To find the percentage of the people surveyed shop at a local grocery store.

Explanation:

The total number of people is 75.

And the total number of people surveyed shop at a local grocery store is 45.

Now the percentage of the people surveyed shop at a local grocery store is,

Final Answer:

63% of the people surveyed shop at a local grocery store.

Answer:

40%

Step-by-step explanation:

3/5 = 0.6

0.6 x 100 = 60% (Who would like to have a party)

100 - 60 = 40

a) The statement is true. All square, upper triangular matrices are diagonalizable.

b)  The statement is false. If a matrix is diagonalizable, then it is invertible.

a) A square matrix is diagonalizable if and only if it has n linearly

independent eigenvectors, where n is the size of the matrix. For an

upper triangular matrix, the eigenvalues are simply the diagonal entries.

Since the eigenvectors of an upper triangular matrix are the standard

basis vectors (1,0,...,0), (0,1,0,...,0), ..., (0,0,...,1), they are linearly

independent. Therefore, every square, upper triangular matrix is

diagonalizable.

b)A matrix A is invertible if and only if its determinant is nonzero: det(A) ≠

0. A matrix is diagonalizable if and only if it has n linearly independent

eigenvectors, where n is the size of the matrix.

It is true that every invertible matrix is diagonalizable. However, the

converse is not true. For example, the zero matrix is diagonalizable (with

any set of linearly independent eigenvectors), but it is not invertible.

Similarly, the matrix with all entries equal to 1 is diagonalizable (with any set of linearly independent eigenvectors), but it is not invertible either.

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The trials in a binomial experiment are the steps. the likelihood of each trial being successful is. What is the likelihood of success? The probability of success is P=1.42.

The binomial distribution is used to summarise the number of trials or observations where each trial has the same probability of attaining a certain value.. When flipping a coin, the probability of witnessing a certain number of successful outcomes in a specified number of trials is determined by the binomial distribution; as there are only two possible outcomes, the likelihood of flipping a coin is 12 or 0.5 for each trial we do.

based on the facts provided;

here ,

n=500 ,p=0.4,q=0.6, X=number of successes

when n*p and n*q>5 then we can use normal approximations

here n*p=500*0.4=200 >5 ,n*q=500*0.6=300>5

so we can use normal approximation

mean =200

variance =200*0.6=120,

std. deviation=120^1/2

we need to find

P(185<=X<=220), applying continuity correction factor

P(184.5<=X<=220.5)

Z=(X-mean)/std. dev~N(0,1)

P((184.5–200)/10.95<=Z<=(220.5–200)/10.95)

=P(-1.42<=Z<=1.87)

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Answer:

6

Step-by-step explanation:

because their are six singer so

c. Yes, there is evidence of an association between grade level and preferred option to raise money.

a. The completed two-way frequency table summarizing the data on grade level and options to raise money is as follows:

         Car Wash | Bake Sale | Talent Show | Total

Seventh Graders\(| 66 | 15 | 16 | 98\)

Eighth Graders \(| - | 50 | - | 50\)

Total \(| 66 | 65 | 16 | 148\)

Note: The "-" indicates that no data is available for those specific combinations.

b. To calculate the row relative frequencies, we divide each cell value by the corresponding row total and round to the nearest thousandth:

     Car Wash | Bake Sale | Talent Show

Seventh Graders \(| 0.673 | 0.153 | 0.163\)

Eighth Graders \(| - | 1.000 | -\)

Total \(| 0.446 | 0.439 | 0.115\)

c. To determine if there is evidence of an association between grade level and preferred option to raise money, we can observe the row relative frequencies. If the relative frequencies differ substantially between the rows, it suggests an association. In this case, since the row relative frequencies for each option vary between the seventh and eighth graders, there is evidence of an association between grade level and the preferred option to raise money.

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15/19 + 14/19 = 29/19

Step-by-step explanation:

Add the number of balls in the basket together.

Subtract the number of white balls from the sample space ( the total amount of balls) your answer is written over the sample space and the same process is done for the green ball

Answer:

32.5

Step-by-step explanation:

10 ounces is in 4 pizzas so if we want 15 pizzas we need to count up

4 can not fit into 15 so we have to stop at 12 pizzas.

Now we need to add 3 pizzas

:Note: that one pizza is 2.5 of an ounce  out of 10 ounces

so after you add the 3 pizzas you have 15 but that wasnt 4 pizzas so you have 2.5 ounces left over you add those ounces to the 30 you got from the 12 ounces which you have 30 and add it to the ounces left over

2.5 + 30 = 32.5

Answer:

Step-by-step explanation:

Given that X -  the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.

Height of male pilot = 74.2 inches

We have to find the percentile

X = 74.2

Corresponding Z score = 74.2-72.6 = 1.6

P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%

i.e. only 5% are below him in height.

Thus the malepilot is in 5th percentile.

Answer:

both angles 1 and 2 measure 135°

Step-by-step explanation:

angle 1 = angle 2 = 135°

Hope this helps

Answer:

A

Step-by-step explanation:

Simply guess and check, meaning the boys category must be divisible by 2 and the girls category must be divisible by 3

A: 24 boys ÷ 2 = 12 (equals a whole number so it is divisible; not a decimal)

36 girls ÷ 3 = 12 (both of the boys and girls are divisible by their corresponding numbers)

Yes

Now make sure the boys are a lower count than the girls as the ratio says it should be 2 to 3, meaning there are more girls than boys

B: 20 ÷ 2 = 10 (divisible)

35 ÷ 3 = 11.666 (this is a decimal answer so it is not divisible)

No

C: 36 ÷ 2 = 18

24 ÷ 3 = 8

Yes, they are divisible

Now lets check if boys have a lower count than girls

36 boys > 24 girls

This is not the solution as it doesn't reflect the correct ratio of less boys than girls

D: 35 ÷ 2 = 17.5 (not divisible)

20 ÷ 3 = 6.66 (not divisible)

Using the formula of area of a circle, about 226.08in² has been eaten

The diameter of the pizza is given as 24 inches. To calculate the area of the entire pizza, we need to use the formula for the area of a circle:

Area = π * r²

where π is approximately 3.14 and r is the radius of the circle.

Given that the diameter is 24 inches, the radius (r) would be half of the diameter, which is 12 inches.

Let's calculate the area of the entire pizza first:

Area = 3.14 * 12²

Area = 3.14 * 144

Area ≈ 452.16 square inches

Now, if half of the pizza is consumed, we need to calculate the area of half of the pizza. To do that, we divide the area of the entire pizza by 2:

Area of half of the pizza = 452.16 / 2

Area of half of the pizza ≈ 226.08 square inches

Therefore, if half of the pizza is consumed, approximately 226.08 square inches of pizza would be eaten.

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False. Analysts should definitely worry about the users' perceptions of the new system during acceptance testing. Acceptance testing is the final stage of software development where the system is tested by end-users to ensure that it meets the specified requirements and is ready for deployment.

During acceptance testing, analysts need to ensure that users find the system easy to use, efficient, and effective in performing the intended tasks. If the users perceive the system to be difficult to use or inefficient, it can lead to user resistance, decreased productivity, and increased costs. Therefore, analysts need to gather feedback from users during acceptance testing and make necessary adjustments to ensure that the system meets the user's expectations. By doing so, analysts can ensure a successful deployment and adoption of the new system.

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Answer:

D

Step-by-step explanation:

Because the x-coordinate of the vertex is negative, only A or D could be the correct equation for this parabola.  D is correct because its constant (4) matches the y-coordinate of the vertex (-5, 4).

Answer:

y = -(x + 5)2 + 4

Step-by-step explanation:

If the best player makes 70% of all free throws, then this player would be expected to make 70% of the next 60 free throws, which is 42. (The equation that goes with this is \(\frac{70}{100}=\frac{x}{60}.\))

Similarly, the second-best player would make 65% of 60 throws, which is 39, and the third-best player would make 55% of 60 throws, which is 33.

First Fit Bin Packing: Core 1: T1, T2, T4, T10; Core 2: T3, T5; Core 3: T6; Core 4: T7; Core 5: Tg; Core 6: To. Scheduled with EDF.

Best Fit Bin Packing: Core 1: T1, T2, T4, T10; Core 2: T3, T5; Core 3: T6; Core 4: T7; Core 5: Tg; Core 6: To. Scheduled with EDF.

We will first use the First Fit Bin Packing algorithm to allocate tasks to cores.

Step 1: Initialize the list of cores as empty.

Step 2: For each task, allocate it to the first core that can accommodate it, if such a core exists. Otherwise, allocate it to a new core.

Initially, we have no cores, so we allocate the first task to a new core:

Core 1: T1

Next, we allocate the second task, T2, to the same core, since it has enough capacity to accommodate it:

Core 1: T1, T2

We allocate the third task, T3, to a new core, since it does not fit in the first core:

Core 1: T1, T2

Core 2: T3

The fourth task, T4, can be allocated to any of the two cores, since they both have enough capacity. We choose to allocate it to the first core:

Core 1: T1, T2, T4

Core 2: T3

The fifth task, T5, can be allocated to either of the two cores, but we choose to allocate it to the second core:

Core 1: T1, T2, T4

Core 2: T3, T5

The sixth task, T6, cannot be allocated to either of the existing cores, so we allocate it to a new core:

Core 1: T1, T2, T4

Core 2: T3, T5

Core 3: T6

The seventh task, T7, cannot be allocated to any of the existing cores, so we allocate it to a new core:

Core 1: T1, T2, T4

Core 2: T3, T5

Core 3: T6

Core 4: T7

The eighth task, Tg, cannot be allocated to any of the existing cores, so we allocate it to a new core:

Core 1: T1, T2, T4

Core 2: T3, T5

Core 3: T6

Core 4: T7

Core 5: Tg

The ninth task, To, cannot be allocated to any of the existing cores, so we allocate it to a new core:

Core 1: T1, T2, T4

Core 2: T3, T5

Core 3: T6

Core 4: T7

Core 5: Tg

Core 6: To

Finally, we allocate the tenth task, T10, to the first core, since it has enough capacity to accommodate it:

Core 1: T1, T2, T4, T10

Core 2: T3, T5

Core 3: T6

Core 4: T7

Core 5: Tg

Core 6: To

All tasks have been allocated to cores using First Fit Bin Packing. Now we need to schedule them using EDF. Since all tasks have a deadline equal to their period, we can simply schedule them according to their periods.

Core 1: T3, T5, T7

Core 2: T6, T10

Core 3: T1, T4

Core 4: T2

Core 5: Tg

Core 6: To

All tasks have been scheduled using EDF.

Now, we will repeat the same process using Best Fit Bin Packing.

Step 1: Initialize the list of cores as empty.

Step 2: For each task, allocate it to the core that has the smallest amount of unused capacity after accommodating the task

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Full Question: Assign tasks to cores using First Fit Bin Packing; once assigned, each core will run EDF. As usual, we will assume the relative deadline of a task equals its period. The task set is as follows (as before, each task is defined by a 2-tuple (ei, P:)): T1 = (4,10), T2 = (3,11), T3 = (2,10), T4 = (8, 10), T5 = (4,8), T6 = (3,15), T7 = (3, 21), Tg = (1,100), To = (10,11), T10 = (6,6). Show each step of the allocation process. (4) Repeat Question 3 using Best Fit Bin Packing. =

Answer:

A relation has an input value which corresponds to an output value. When each input value has one and only one output value, that relation is a function. Functions can be written as ordered pairs, tables, or graphs. The set of input values is called the domain, and the set of output values is called the range.

Hope this helps :P

Answer:

trapezoid

Step-by-step explanation:

Answer:

9.6

Step-by-step explanation:

Hope this help : ) . Bye.

a. The mean is 26.5, and the standard deviation is 1.154, b. The null hypothesis (H₀) and alternative would state that mean is greater , c- critical value approach is 2.997.

In the above problem given ,

Data: 28, 27, 25, 26, 28, 26, 29, 25

a. Mean:

Mean = (28 + 27 + 25 + 26 + 28 + 26 + 29 + 25) / 8 = 26.5 thousand miles

Standard Deviation:

Calculate the deviation of each value from the mean:

(28 - 26.5), (27 - 26.5), (25 - 26.5), (26 - 26.5), (28 - 26.5), (26 - 26.5), (29 - 26.5), (25 - 26.5)

Calculate the squared deviation of each value:

(28 - 26.5)², (27 - 26.5)², (25 - 26.5)², (26 - 26.5)², (28 - 26.5)², (26 - 26.5)², (29 - 26.5)², (25 - 26.5)²

Calculate the sum of squared deviations:

Sum = (28 - 26.5)² + (27 - 26.5)² + (25 - 26.5)² + (26 - 26.5)² + (28 - 26.5)² + (26 - 26.5)² + (29 - 26.5)² + (25 - 26.5)²

Divide the sum of squared deviations by (n-1), where n is the sample size:

Standard Deviation = √(Sum / (n-1)) = 1.154.

b. Null Hypothesis (H₀): The mean life expectancy of the new tires is 26,000 miles.

Alternative Hypothesis (H₁): The mean life expectancy of the new tires is greater than 26,000 miles.

c. Critical Value Approach:

With a sample size of 8, degrees of freedom (df) = n - 1 = 8 - 1 = 7. From the t-distribution table at a significance level of 0.01 and df = 7, the critical value is approximately 2.997.

Calculate the test statistic t:

t = (Sample Mean - Population Mean) / (Standard Deviation / √n)

d. P-value Approach:

To repeat the test using the p-value approach, we calculate the p-value associated with the test statistic. If the p-value is less than the significance level (0.01), we reject the null hypothesis.

Calculate the t-value using the same formula as in c.

Calculate the p-value using the t-distribution with (n-1) degrees of freedom.

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By using Chebyshev's inequality formula, the number of practitioners we must sample from each category so that we can estimate the average continuous time of administering anesthesia to within a bound of .15 is 482, 1190, and 1500 respectively.

Assume that we have 10000 people that practice anesthesiology and that it costs $5 to measure an anesthesiologist, $8 to measure a resident and $10 to measure a nurse.

Let's solve the problem using Chebyshev's inequality formula: Chebyshev's inequality formula states that

P(|X-μ|≥kσ)≤1/k₂, where X is a random variable, μ is the mean of X, and σ is the standard deviation of X. Now, let's solve for k using the formula: k= bound/σ. Here, the bound is 0.15. Hence, we have to find the standard deviation of each category, which can be calculated using the following formula:

σ=√((∑(Xi-μ)^2)/N), where Xi is the value of X, μ is the mean, and N is the total number of values in the sample.

The average continuous time of administering anesthesia for each category is given as:

Anesthesiologist - 3.5 hours Resident - 4.2 hours Nurse - 4.8 hours

Hence, using the formula above, we get:

σ(Anesthesiologist)=√(((3.5-3.5)2+(4-3.5)2+(4.5-3.5)2+(5-3.5)2+(5.5-3.5)2)/5) ⇒ 0.89443

σ(Resident)=√(((4.5-4.2)2+(5-4.2)2+(5.5-4.2)2+(6-4.2)2+(6.5-4.2)2)/5) ⇒ 0.91576

σ(Nurse) =√(((5-4.8)2+(5.5-4.8)2+(6-4.8)2+(6.5-4.8)2+(7-4.8)2)/5) ⇒ 0.9083

Now, substituting the values in the formula k= bound/σ, we get:

k(Anesthesiologist)=0.15/0.89443 ⇒ 0.1674

k(Resident)=0.15/0.91576 ⇒ 0.1637

k(Nurse)=0.15/0.9083 ⇒ 0.1651

Now, using the formula P(|X-μ| ≥ kσ) ≤ 1/k₂, we can solve for the sample size.

The sample size for each category is given as:

n= 1/k₂P(|X-μ|≥kσ)

Hence, for each category, we have:

n = 1/0.16742P(|X-3.5| ≥ 0.5946) ≤ 0.0237

n ≈ 481.9 ≈ 482

n = 1/0.16372P(|X-4.2|≥0.6072) ≤ 0.0248

n ≈ 1189.8 ≈ 1190

n = 1/0.16512P(|X-4.8| ≥ 0.5984) ≤ 0.024

n ≈ 1499.8 ≈ 1500

Hence, we need to sample 482 practitioners from the anesthesiologist category, 1190 practitioners from the resident category, and 1500 practitioners from the nurse category.

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The expression, (5 > 57 % 8), evaluates to false.

To determine if the expression (5 > 57 % 8) evaluates to true or false, we need to first calculate the value of 57 % 8.

Step 1: Calculate 57 % 8, which represents the remainder when 57 is divided by 8.
57 % 8 = 1

Step 2: Compare 5 and the result from Step 1 using the '>' operator.
5 > 1

Step 3: Determine if the comparison in Step 2 is true or false.
Since 5 is greater than 1, the expression evaluates to true.

So, the expression (5 > 57 % 8) evaluates to true.

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