fuel line fittings are being discussed. technician a says that o-rings are used on some fuel line fittings. technician b says that clamps are used on some systems. who is correct?

Answer:

they are fictional characters featured in video games etc

Answer: Mario and Luigi are game characters, which feature in the Super Mario Maker series, the Paper Mario series, but most notably, the Super Mario Bros. series. Mario debuted in Donkey Kong (1981), while Luigi debuted in Mario Bros (1983, not to be confused with Super Mario Bros, which released two years after Mario Bros).

Answer:

\(250\ \text{lbm/min}\)

\(625\ \text{ft/min}\)

Explanation:

\(A_1\) = Area of section 1 = \(10\ \text{ft}^2\)

\(V_1\) = Velocity of water at section 1 = 100 ft/min

\(v_1\) = Specific volume at section 1 = \(4\ \text{ft}^3/\text{lbm}\)

\(\rho\) = Density of fluid = \(0.2\ \text{lb/ft}^3\)

\(A_2\) = Area of section 2 = \(2\ \text{ft}^2\)

Mass flow rate is given by

\(m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}\)

The mass flow rate through the pipe is \(250\ \text{lbm/min}\)

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

\(m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}\)

The speed at section 2 is \(625\ \text{ft/min}\).

(a) The mass flow rate will be "250 lbm/min".

(b) At section 2, the speed will be "625 ft/min".

According to the question,

Section 1 area, A₁ = 10 ft²

Section 2 area, A₂ = 2 ft²

Water's velocity, V₁ = 100 ft/min

Volume at section 1, v₁ = 4 ft³/lbm

(a) We know the formula,

Mass flow rate, m = ρA₁V₁

                              = \(\frac{A_1 V_1}{v_1}\)

By substituting the values,

                              = \(\frac{10\times 100}{4}\)

                              = \(\frac{1000}{4}\)

                              = 250 lbm/min

(2) The speed will be:

→ m = ρA₂V₂

or,

  V₂ = \(\frac{m}{\rho A_2}\)

By substituting the values,

       = \(\frac{250}{0.2\times 2}\)

       = \(\frac{200}{0.4}\)

       = 625 ft/min

Thus the responses above are correct.  

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When inspecting a post-tension installation, the inspector is responsible for checking all of the following except the initial design calculations.

During a post-tension installation inspection, the inspector typically checks for proper materials, installation techniques, and compliance with the project specifications. This may include verifying tendon placement, stressing equipment, and grouting procedures.

However, the initial design calculations, which are the responsibility of the structural engineer or designer, are not part of the inspector's responsibilities during the inspection.
The inspector focuses on ensuring that the post-tension installation is executed correctly and complies with project requirements, while the responsibility for checking the initial design calculations lies with the structural engineer or designer.

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Answer: A, B, C or D

Explanation: its either those

In this question we shall present the algorithm in pseudocode, whose structure is now summarized:

1) Inputs.

2) Algorithms.

3) Outputs.

Please notice that While-cycles consider the requirement of using the algorithm as many times as user wants.

Name: Area-or-Circunference

CHAR - decide

REAL - radius, circumference, area

Say "Do you want to calculate? [Y] - Yes/[N] - No";

Write decide;

While (decide != 'Y' and decide != 'y' and decide != 'N' and decide != 'n'):

    Say "Invalid option. Do you want to calculate? [Y] - Yes/[N] - No";

    Write decide;

end-While

While (decide = 'Y' or decide = 'y'):

    Say "Please indicate a radius";

     While (radius < 0):

          Say "Radius must be equal or greater than 0. Please indicate a  

                   radius";

          Write radius;

      end-While

      If (radius < 1):

          circumference = 2*3.14*radius;

          Say "The circumference has a value of %circumference length units";

       Else:

          circumference = 2*3.14*radius;

          area = 3.14*radius*radius;

          Say "The circumference has a value of %circumference length units

                   and the area has a value of %area square units";

        end-If

        Say "Do you want to calculate? [Y] - Yes/[N] - No";

        Write decide;

        While (decide != 'Y' and decide != 'y' and decide != 'N' and decide !=

        'n'):

              Say "Invalid option. Do you want to calculate? [Y] - Yes/[N] - No";

              Write decide;

         end-While

end-While

If (decide = 'N' or decide = 'n'):

    Say "Good luck";

end-If

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Answer:

Sure! Here's how to draw the shear and moment diagrams for the beam:

To draw the shear diagram, start by finding the shear force at the left end of the beam (V1). This will be equal to M0, since there is no external force acting on the left end of the beam. Then, draw a horizontal line segment to represent the shear force at that point.

Next, move to the right end of the beam (at x=8m). The shear force at this point (V2) will be equal to the shear force at the left end, minus the total load on the beam. So, if the total load on the beam is W, then V2 = M0 - W. Draw a horizontal line segment to represent the shear force at this point.

Finally, connect the two line segments with a smooth curve. This curve represents the variation of the shear force along the length of the beam.

To draw the moment diagram, start by finding the moment at the left end of the beam (M1). This will be equal to 0, since there is no external force acting on the left end of the beam and the shear force is constant (M0) along the length of the beam. Then, draw a horizontal line segment to represent the moment at that point.

Next, move to the right end of the beam (at x=8m). The moment at this point (M2) will be equal to the moment at the left end, plus the total load on the beam multiplied by the length of the beam (WL). So, M2 = M1 + WL = W*L. Draw a horizontal line segment to represent the moment at this point.

Finally, connect the two line segments with a smooth curve. This curve represents the variation of the moment along the length of the beam.

I hope this helps! Let me know if you have any questions.

Explanation:

Answer:

\(D=0.41m\)

Explanation:

From the question we are told that:

Discharge rate \(V_r=0.35 m3/s\)

Distance \(d=4km\)

Elevation of the pumping station \(h_p= 140 m\)

Elevation of the Exit point \(h_e= 150 m\)

Generally the Steady Flow Energy Equation SFEE is mathematically given by

\(h_p=h_e+h\)

With

\(P_1-P_2\)

And

\(V_1=V-2\)

Therefore

\(h=140-150\)

\(h=10\)

Generally h is give as

\(h=\frac{0.5LV^2}{2gD}\)

\(h=\frac{8Q^2fL}{\pi^2 gD^5}\)

Therefore

\(10=\frac{8Q^2fL}{\pi^2 gD^5}\)

\(D=^5\frac{8*(0.35)^2*0.003*4000}{3.142^2*9.81*10}\)

\(D=0.41m\)

Answer:

B

Explanation:

The refractive power of the contact lenses can be calculated using the following formula: refractive power (in diopters) = 1 / focal length (in meters).

Converting the given focal length of 30 cm to meters, we get 0.3 m. Substituting this value in the formula, we get: Refractive Power = 1 / 0.3 = 3.3 diopters. Therefore, the refractive power of her contact lenses is 3.3 diopters.

To determine the refractive power of the contact lenses, we need to use the formula:

Refractive Power (D) = 1 / Focal Length (m)

First, let's convert the focal length from centimeters to meters:

Focal Length = 30 cm = 0.3 m

Now, we can plug the value into the formula:

Refractive Power (D) = 1 / 0.3 m = 3.33 diopters

The closest answer choice to 3.33 diopters is 3.3 diopters. Therefore, the refractive power of her contact lenses is 3.3 diopters.

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The center of gravity method considers a greater number of location factors than the break-even analysis: B. False.

Break-even analysis is also referred to as cost-volume-profit analysis and it can be defined as a financial accounting technique that is used to determine the number of units (products) which a business firm must sell at a specific price, either on a monthly or annual basis, so as to cover all of its costs.

Unlike the center of gravity method, the break-even analysis considers a greater number of location factors to determine the number of units (products) which a business firm must sell at a specific price.

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Because she has a Victim mindset and having low grade in her Math class, Julianna believes: A. her low grades are the fault of her unfair teacher.

A Victim mindset is also referred to as victim mentality and it can be defined as an acquired personality trait in which an individual tends to recognize and believe that the negative and unfair actions of others towards him or her, is responsible for the bad and unpleasant things that happens.

This ultimately implies that, an individual with a Victim mindset is prejudiced and strongly believes that every other person is against him or her, and as such these people are responsible for their failures.

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Answer: Stair treads can be as narrow as 22.5 inches or as wide as 36 inches. Wider stair treads are typically used outdoors while narrower designs between 22.5 inches and 30 inches are more commonly used indoors.

Explanation:

Wheelbase, trackwidth, and tire load data can be used to determine the longitudinal CG location. The distance in inches between the center of gravity and the front wheel.

Wheelbase, trackwidth, and tire load data can be used to determine a car's longitudinal center of gravity (CG) location. The distance between the centers of the front and rear wheels is known as the wheelbase, while the distance between the left and right tire centerlines is known as the trackwidth. The amount of weight on each of the four tires that are in contact with the ground is known as the tire load. The entire weight of the vehicle is divided by the wheelbase and trackwidth, and the resulting number is multiplied by the wheelbase to determine the longitudinal center of gravity (CG) location. The resultant measurement, taken from the front wheel, is the longitudinal CG location in inches.

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

Answer:

a) True

Explanation:

In Computer programming, when a multiple thread is executing, the sequence in which the statements (codes) contained therein are executed by these multiple thread is mainly nondeterministic in nature.

When nondeterminism results from multiple threads attempting to access a shared resource such as a shared variable or a shared file, at least one of the accesses is an update, and the accesses can result in an error, we have a race condition.

A race condition can be defined as a condition in which multiple threads have the ability to access shared data at the same time and as such they both try to change (modify) the data. Thus, in a race condition occurs in computer (software) programming when a software application's behavior is solely dependent on the timing of multiple threads (processes) in order to function properly.

Answer:

Visual connectivity refers to the tangible aspects of a space; extent to which a place can be viewed from other places. It is believed that the design properties of a spatial layout of an atrium leaves unobstructed views horizontally and vertically.

Explanation:

Answer:

See the image for solution

Answer:

medium sized ears

Explanation:

Answer:

y = 0.834X - 1.58015

Slope = 0.8340 ; Intercept = - 1.5802

y = 40.9539

19.93

0.9765

Explanation:

X: Rainfall volume

6

12

14

16

23

30

40

52

55

67

72

81

96

112

127

Y : Runoff

4

10

13

14

15

25

27

48

38

46

53

72

82

99

100

The scatterplot shows a reasonable linear trend between the Rainfall volume and run off.

The estimated regression equation obtained using a linear regression calculator is :

y = 0.834X - 1.58015

y = Runoff ; x = Rainfall volume

Slope = 0.8340 ; Intercept = - 1.5802

Point estimate for Runoff, when, x = 51

y = 0.834X - 1.58015

y = 0.834(51) - 1.58015

y = 40.95385

y = 40.9539

d.)

Point estimate for standard deviation :

s = 5.145

σ = s * √n

σ = √15 * 5.145

= 19.93

e.)

r² = Coefficient of determination gives the proportion of explained variance in Runoff due to the regression line. From the model output, the r² value = 0.9765. Which means That about 97.65% Runoff is due to Rainfall volume.

Answer:

A) Rate of heat addition = 228.53 Hp

B) Maximum Air temperature = 1109 °C

Explanation:

We are given;

Cut off ratio; r_c = 1.5

Compression ratio; r = 18

Power produced; W` = 150 Hp

cp = 1.005 kJ/kg·K

cv = 0.718 kJ/kg·K

R = 0.287 kJ/kg·K

k = 1.4

Temperature;T1 = 17°C = 17 + 273 K = 290K

I've attached the rest of the explanation below.

To find the rate at which the concentrated sugar solution needs to be added to provide 12% sugar in the sweetened orange juice, we can use the concept of mass flow rate and the percentage of sugar in the concentrated solution.

Flow rate of orange juice = 40 kg/min Percentage of sugar in the concentrated sugar solution = 75% Percentage of sugar required in the sweetened orange juice = 12% Let's assume the rate at which the concentrated sugar solution needs to be added is R kg/min. The total mass flow rate of the sweetened orange juice is the sum of the orange juice flow rate and the concentrated sugar solution flow rate: Mass flow rate of sweetened orange juice = Mass flow rate of orange juice + Mass flow rate of sugar solution Since the only component added is the concentrated sugar solution, the mass flow rate of sugar solution is equal to R kg/min. According to the percentage of sugar, we can write the equation: Percentage of sugar in the sweetened orange juice = (Mass flow rate of sugar solution / Mass flow rate of sweetened orange juice) * 100 12% = (R / (40 + R)) * 10 Simplifying the equation: 0.12 = R / (40 + R) 0.12 * (40 + R) = R 4.8 + 0.12R = R 0.88R = 4.8 R ≈ 5.45 kg/min Therefore, the concentrated sugar solution needs to be added at a rate of approximately 5.45 kg/min to provide 12% sugar in the sweetened orange juice.

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Japan's most recent development is the Linear High-Speed Train, which travels at extremely fast speeds thanks to electromagnetic fields.

Japan has led the world in advanced rail technology ever since the Shinkansen bullet train was invented in the 1960s. Japan's most recent development is the Linear High-Speed Train, which travels at extremely fast speeds thanks to electromagnetic fields. A test version of the new technology recently set a world record for a manned vehicle with a speed of 581 kilometers per hour, after fifty years of development.

A brand-new motor known as a superconducting linear motor powers the train. The idea behind this is that magnets work. You probably already know that a magnet's north and south poles attract one another, whereas two poles that are the same (north and north, or south and south) repel one another. Using the attracting and repelling forces generated by coils in the tracks and magnets inside the train, the new technology applies this principle to propel the train forward.

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Turbine flow sensors generate a pulse each time a blade rotates past a rotor.

Turbine flow sensors are commonly used to measure fluid flow in various industries. These sensors consist of a rotor with blades placed in the fluid flow path. As the fluid flows through the sensor, it causes the rotor to rotate. Each rotation of the rotor corresponds to a specific volume of fluid passing through the sensor. To measure the flow rate, turbine flow sensors generate a pulse or signal each time a blade rotates past a rotor. This pulse is typically detected by a magnetic pickup or sensor, which can then be processed to determine the flow rate. The frequency or rate of these pulses is directly proportional to the flow rate of the fluid, allowing for accurate measurement and monitoring of fluid flow.

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if a pilot-operated check valve (POC) does not check flow, you will see The symptoms and symptoms of a failing swing test valve are regularly audible.

When the pilot valve reaches set strain it opens and releases the strain from the dome. The piston is then unfastened to open and the principle valve exhausts the machine fluid. The manage pilot opens both to the principle valve exhaust pipe or to the atmosphere.

Pilot operated test valves paintings through permitting unfastened go with the drift from the inlet port thru the opening port. Supplying a pilot strain to the pilot port permits go with the drift withinside the contrary direction. Air strain on the pinnacle of the poppet meeting opens the seal permitting air to go with the drift freely.

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Explanation:

sory sorry sorry sorrysorrysorry

Answer:

Horizontal force = 89.2 N

Explanation:

The frictional force = coefficient of friction * magnitude of the force (weight of the body) * cos theta

Substituting the given values, we get -

Frictional Force = 0.3*300 * cos 25 = 89.2 N

Horizontal force = 89.2 N