fter the database system was created, the library created a program to accept book donations from users. update your er model and relational model so the system can record the donations.

Answer:

No

Explanation:

People work in engineering all over the globe.

Answer:

The answer is below

Explanation:

1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:

\(n_s=\frac{120f_s}{p}\\ Where\ p\ is \ the \ number\ of\ machine\ pole, f_s\ is\ the\ supply \ frequency\\and\ n_s\ is \ the \ synchronous\ speed(speed \ of\ stator\ magnetic \ field)\\Given: f_s=60\ Hz, p=4. Therefore\\\\n_s=\frac{120*60}{4}=1800\ rpm\)

2) The speed of the rotor is the motor speed. The slip is given by:

\(Slip=\frac{n_s-n_m}{n_s}. \\ n_m\ is\ the \ motor\ speed(rotor\ speed)\\Slip = 0.05, n_s= 1800\ rpm\\ \\0.05=\frac{1800-n_m}{1800}\\\\ 1800-n_m=90\\\\n_m=1800-90=1710\ rpm\)

3) The frequency of the rotor is given as:

\(f_r=slip*f_s\\f_r=0.04*60=2.4\ Hz\)

4) At standstill, the speed of the motor is 0, therefore the slip is 1.

The frequency of the rotor is given as:

\(f_r=slip*f_s\\f_r=1*60=60\ Hz\)

The maximum depth from which the pump can extract water from the well is the height of the pump above the water surface.

We are given a problem that discusses the reduction of air pressure in a pipe. A pump on the right side of the drawing is used to reduce the air pressure in the pipe. One atmosphere is the air pressure outside the pipe. The question asks us to calculate the maximum depth from which this pump can extract water from the well.Since the problem gives the pressure outside the pipe to be one atmosphere, we can use this value as the pressure at the water surface. The pump extracts water from the well, so we can use the Bernoulli equation to solve for the depth. Here is the equation: P_1 + (1/2)ρv_1^2 + ρgh_1 = P_2 + (1/2)ρv_2^2 + ρgh_2, where P is the pressure, ρ is the density, v is the velocity, g is the acceleration due to gravity, and h is the height. Let's assign the values: P_1 = P_2 = 1 atm, ρ = 1000 kg/m^3, v_1 = v_2 = 0 (since the pump reduces the air pressure, it does not contribute to the flow of water), and h_2 = d (the depth we are solving for). Then the equation simplifies to ρgh_1 = (1/2)ρv_2^2 + ρgh_2. Since the water is at rest at the water surface, v_2 = 0, so we get ρgh_1 = ρgh_2. Cancelling the density, we get h_1 = h_2.

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complete Question

A motor driving a 1000-W water pump has a power factor of 0.80 lagging; a second motor driving a 600-W water pump has a power factor of 0.60 lagging assuming the motors are working under 120-Vrms, 60-HZAC. When both motors working together what is the combined power factor? If a 200-μF capacitor is connected to the above system (two motors) what is the new combined power factor?

Answer:

\(p.f'=0.960\)

Explanation:

First motor Power \(P=1000W\)

First motor Power factor \(P.f=0.80\)

Second motor Power \(P=600W\)

Second motor Power factor p.f=0.60

Voltage \(V=120Vrms\)

Frequency \(F=60Hz\)

Capacitor \(C=200\mu F\)

Generally power in Var is given as

For First Motor

\(Q=\frac{1000}{0.8}\sqrt{1-0.8^2}\)

\(Q=750Var\)

For Second Motor

\(Q=\frac{600}{0.6}\sqrt{1-0.6^2}\)

\(Q=800Var\)

Generally the equation for The Reactive Power is mathematically given by

\(Q_c=\frac{V^2}{X_c}\)

Where

\(X_c=\frac{1}{2 \pi fc}\)

\(X_c=\frac{1}{2 \pi 60*200*10^{-6} }\)

\(X_c=13.3\)

Therefore

\(Q_c=-\frac{120^2}{13.3}\\\\Q_c=-1085.97j\)

Giving

Total Power Drawn by Supply

\(P_t=(1000+j750)+(600+800)-j1085.97\)

\(P_t=1600+464.03j\)

Therefore

\(p.f'=\frac{1600}{\sqrt{1600^2+464.03^2}}\)

\(p.f'=0.960\)

Answer:

Explanation:

Work, U, is equal to the force times the distance:

U = F · r

Force needed to lift the weight, is equal to the weight: F = W = m · g

so:

U = m · g · r

   = 20.4kg · 9.81 \(\frac{N}{kg}\) · 1.50m

   = 35.316 \(\frac{N}{m}\)

   = 35.316 W

To find the acceleration of the combined unit and the force of interaction between the tugboat and the barge, we can apply Newton's second law of motion.

The net force acting on the system will be the difference between the thrust force applied by the tugboat and the force of resistance from the barge.

Given:

Thrust force, P = 7000 lb

Mass of tugboat, m1 = 350 tons = 700,000 lb

Mass of barge, m2 = 800 tons = 1,600,000 lb

To find the acceleration, we can use the formula:

Net force = (m1 + m2) * acceleration

Net force = P - R (assuming R is the force of interaction between the tugboat and the barge)

Substituting the values:

7000 lb - R = (700,000 lb + 1,600,000 lb) * acceleration

Simplifying:

7000 lb - R = 2,300,000 lb * acceleration

To find R, we need additional information or an equation relating R to the masses of the two objects.

In summary, the acceleration of the combined unit can be determined using the given information, but the force of interaction between the tugboat and the barge cannot be determined without additional information.

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Answer:

i think 1844

Explanation:

2005 BMW 5 Series , that should be it

Answer:

a) The ductility = -30.12%

the negative sign means reduction

Therefore, there is 30.12% reduction

b) the true stress at fracture is 658.26 Mpa

Explanation:

Given that;

Original diameter \(d_{o}\) = 12.8 mm

Final diameter \(d_{f}\) = 10.7

Engineering stress  \(\alpha _{E}\) = 460 Mpa

a) determine The ductility in terms of percent reduction in area;

Ai = π/4(\(d_{o}\) )²  ; Ag = π/4(\(d_{f}\) )²

% = π/4 [ ( (\(d_{f}\) )² - (\(d_{o}\) )²) / ( π/4  (\(d_{o}\) )²) ]

= ( (\(d_{f}\) )² - (\(d_{o}\) )²) / (\(d_{o}\) )² × 100

we substitute

= [( (10.7)² - (12.8)²) / (12.8)² ] × 100

= [(114.49 - 163.84) / 163.84 ] × 100

= - 0.3012 × 100

= -30.12%

the negative sign means reduction

Therefore, there is 30.12% reduction

b) The true stress at fracture;

True stress  \(\alpha _{T}\) = \(\alpha _{E}\) ( 1 +  \(E_{E}\) )

\(E_{E}\)  is engineering strain

\(E_{E}\)  = dL / Lo

= (do² - df²) / df² = (12.8² - 10.7²) / 10.7² = (163.84 - 114.49) / 114.49

= 49.35 / 114.49  

\(E_{E}\) = 0.431

so we substitute the value of \(E_{E}\)  into our initial equation;

True stress  \(\alpha _{T}\) = 460 ( 1 +  0.431)

True stress  \(\alpha _{T}\) = 460 (1.431)

True stress  \(\alpha _{T}\) = 658.26 Mpa

Therefore, the true stress at fracture is 658.26 Mpa

The sections of piping immediately upstream and downstream of a primary flow measuring device are known as the "straight run."

The straight run refers to the lengths of piping that are required to be present immediately upstream and downstream of a primary flow measuring device. These sections of piping are necessary to ensure that the flow profile is fully developed and unaffected by any disturbances caused by bends, fittings, or obstructions in the pipe. The straight run allows the fluid to flow smoothly and uniformly before entering or exiting the flow measuring device, ensuring accurate and reliable measurements.

By providing sufficient straight run lengths, the flow profile becomes stable, minimizing turbulence and disturbances that could impact the accuracy of the flow measurement.

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Error message, update the game and Steam client, verify game files, and reinstall the game if necessary.

To fix the "procedure entry point Steam Controller could not be located in the dynamic link library" error, you can try the following steps:

If none of these steps work, you may need to contact the program's support team for further assistance.

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A  straight-bladed spatula is used for mixing impression material on a mixing pad, but not in a rubber bowl because it is  iron and constant use may destroy the rubber.

The term Straight edge is known to be a kind of a metal spatula that is known to have a long flat spatula.

It is one that is also known to have a straight edge that is said to be used for leveling or used in working of frosting cakes.

Note that the  Strainer - wire mesh helps to move or separates liquids from food.

Hence, A  straight-bladed spatula is used for mixing impression material on a mixing pad, but not in a rubber bowl because it is  iron and constant use may destroy the rubber.

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The pressure would be doubled (3800psi) as the day heats up because of the sun, the temperature increases to 105°F.

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The wired networking standard that specifies the order in which data is sent through the network is Ethernet.

Ethernet is a widely used wired networking standard that defines the protocols and specifications for data transmission over a local area network (LAN). It specifies the order in which data is sent through the network by utilizing the Carrier Sense Multiple Access with Collision Detection (CSMA/CD) algorithm.

The CSMA/CD algorithm ensures that multiple devices connected to an Ethernet network can share the same communication medium without interfering with each other. Before transmitting data, a device using Ethernet listens to the network to detect if it is clear to send data. If the network is busy, it waits for an opportune moment. Once the network is clear, the device sends the data, constantly monitoring for collisions. If a collision occurs (when two or more devices transmit data simultaneously), they stop transmitting, wait for a random period of time, and then retry.

By following this protocol, Ethernet ensures orderly and efficient data transmission within the network, minimizing collisions and maximizing data throughput. It has become the de facto standard for wired local area networks due to its reliability, scalability, and widespread adoption.

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Answer:

A

Explanation:

The statement "In a regular pyramid, the slant height is always longer than a lateral edge of the pyramid" is false.

In a regular pyramid, the slant height refers to the distance from the apex (top) of the pyramid to any point on the lateral face, measured along the slanted surface. A lateral edge, on the other hand, refers to the length of an edge that connects the apex to a vertex of the base.

In a regular pyramid, the slant height and the lateral edge are typically not equal to each other. The slant height is generally longer than a lateral edge. This can be understood by considering the shape of a regular pyramid, where the slant height forms a diagonal along the lateral face, while the lateral edge is a straight line connecting the apex and a vertex of the base.

However, it is important to note that the specific lengths of the slant height and lateral edge depend on the dimensions of the pyramid, such as the base size and the height. The relationship between the slant height and lateral edge can vary depending on the specific measurements of the regular pyramid.

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Answer:

the answer is B

Explanation:

because you have your gasket sealer to keep it from leaking and on 90% of cars the clutch is weighted to cause friction

Answer:

Explanation:

please mark as brainliest

The value of thermal circuits A1 = 1372[mm^2] and A2 =4 pi (12.7[mm]^3 .

where R1, R2, and R3 represent the thermal resistances of the cornea, aqueous humor, and sclera, respectively. Let T1, T2, and T3 be the temperatures of these layers, respectively, and let T_inf,o be the temperature of the surrounding air. where L1, L2, and L3 are the thicknesses of the cornea, aqueous humor, and sclera, respectively, k1 and k2 are the thermal conductivities of the cornea and aqueous humor, respectively, k3 is the thermal conductivity of the sclera, and A1, A2, and A3 are the surface areas of the cornea, aqueous humor, and sclera, respectively.

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Known :

D = 12 in = 1 ft

L = 850 ft

Q = 5.6 cfs

hA = 750 ft

hB = 765 ft

PA = 85 psi = 12240 lb/ft²

Solution :

A = πD² / 4 = π(1²) / 4

A = 0.785 ft²

Velocity of water :

U = Q / A = 5.6 / 0.785

U = 7.134 ft/s

Friction loss due to pipe length :

Re = UD / v = (7.134)(1) / (0.511 × 10^(-5))

Re = 1.4 × 10⁶

(From Moody Chart, We Get f = 0.015)

hf = f(L / d)(U² / 2g) = 0.015(850 / 1)((7.134²) / 2(32.2))

hf = 10 ft

PA + γhA = PB + γhB + γhf

PB = PA + γ(hA - hB - hf)

PB = 12240 + (62.4)(750 - 765 - 10)

PB = 10680 lb/ft²

PB = 74.167 psi

Answer:

Due to risk of damaging of brain.

Explanation:

The electrode therapy is not the most effective treatment for brain disorders because there are various other treatments which can treat the brain disorder without causing damage to the brain. electrode therapy greatly damaged the brain instead of treatment of brain disorder. Medication is the best way to treat brain disorder so that's why electrode therapy is not considered as the most effective treatment for brain disorders, and the doctors recommend an alternative treatment.

Answer:

Understand how the network works where she is working at

Explanation:

Plant wide predetermined rate= Total fixed manufacture head/Total estimated hour

Plant Wide Predetermined rate=29800/4000

Plant Wise Predetermined Rate=$7.45

Job P Applying manufacturing overhead ($6.20 per DLH x 1,300 DLHs) results in $8,060. Job Q Applying manufacturing overhead ($6.20 per DLH x 600 DLHs) results in $3,720. Together, those equal. applied to work that was already in progress.

2. Applying Manufacturing Overheads to P and Q

                                                                                                P                   Q      

Variable Manufacturing Overheads                          

Molding                                                                            7540                      5200

Fabrication                                                                      6120                        7140

Fixed Manufacturing Overheads

Molding                                                                           21605                     14900

Fabrication                                                                      13410                      15645

Total                                                                             48675                      42885

3. Total Manufacturing Cost assigned to Job P is $48675.

4. If P has 20 Units Unit Product Cost will be as below:

Direct Materials                                                                         25000

Direct Labour                                                                            30600

Total Manufacturing overheads assigned                              48675

total Product Cost                                                                   104275

Cost per unit                                                                           $5213.75  

5. $42885 is the total manufacturing cost attributed to Work Q.

Direct Materials                                                                      14000

Direct Labour                                                                           12300

Total Manufacturing Overheads                                             42885

Total Cost                                                                                 69185

Cost per Unit                                                                         $2306.167.

Selling Price for P

Total Cost of P...............................................................................$104275

Mark Up...........................................................................................$38940

Selling Price......................................................................................$ 143215 Cost per unit.....................................................................................$7160.75

Selling Price for Q

Total Cost of Q ..............................................................................69185

Markup .........................................................................................   34308

Selling Price  ................................................................................103493

Cost per unit...................................................................................$3449.76

8. Cost of Goods Sold for March...................................................$173460

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Note that the differential manufacturer that was used in the Banks Power System Testing Project is AMSOIL Incorporated.

AMSOIL Inc. is a Wisconsin-based American firm that primarily formulates and produces synthetic lubricants, gasoline additives, and filters. Throughout the mid-to-late 1960s, company founder Albert J. Amatuzio created numerous synthetic motor oil formulas.

It is to be noted that a differential manufacturer is a company that produces and sells differentials, which are mechanical devices that allow the wheels of a vehicle to rotate at different speeds. Examples of differential manufacturers include Eaton, Dana, and GKN Automotive.

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Explanation:

Alok Chaurasia

Yu Suzhu

Cheng Kuo Feng Henry

Vishal Tukaram Mogal

Sampa Saha

Answer:

Protecting yourself.

Explanation:

you didn't include answer choices but from the text I would assume remembering to do these things would be actively protecting yourself.

The watercraft in the crossing are given with the responsibility to the starboard side to give the way and avoid collision.

The crossing rules are given as the safety rules that are mediated in order to avoid the collision accidents when the two vehicles are crossing the path.

In the sea, the rules are given with the watercraft at the starboard side or the giveaway side to make the way to the other watercraft and avoid collision.

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In the two scenario above concerning port fuel-injection and sequential fuel injectors, only Technician b is correct.

A vehicle often has one fuel injector per cylinder and if one has a four-cylinder car, it would also have four fuel injectors.

Note that Fuel-pressure regulators that are found on a port fuel-injected systems is one that often work with injector pressures that is said to be of 30 to 55 PSI.

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The minimum coefficient of friction required to prevent slipping is sin(38.0°) which is 0.615.

To get minimum coefficient of friction (μ) required to prevent slipping, we will equate the gravitational force component along the slope to the frictional force.

The gravitational force component along the slope can be calculated as: Fg = m * g * sin(θ).

The frictional force can be calculated as: Ff = μ * N,

Setting Fg = Ff, we have:

m * g * sin(θ) = μ * N

m * g * sin(θ) = μ * m * g

sin(θ) = μ

So, the minimum coefficient of friction needed to prevent slipping is equal to the sine of the angle of the slope which is sin(38.0°).

Full question:

A hollow, spherical shell with mass 2.00kg rolls without slipping down a slope angled at 38.0?. Find the minimum coefficient of friction needed to prevent slipping.

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The diameter of the wires in an electrical power station that operates at 45 kV and uses a 20:1 step ideal transformer is 782.3378532132199 inches.

The formula for calculating the diameter of the wires is:

diameter = sqrt(voltage / (resistance * step_ratio)) * 25.4

In this case, the voltage is 45 kV, the resistance is 1.68 x 10^-8 Ω/m, and the step ratio is 20:1.

Plugging these values into the formula, we get:

diameter = sqrt(45000 / (1.68 x 10^-8 * 20)) * 25.4 = 782.3378532132199 inches

The diameter of the wires is so large because the voltage is very high. The higher the voltage, the larger the diameter of the wires needs to be in order to minimize the resistance and prevent power loss.

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The Analytic Hierarchy Process (AHP) can be used to make a decision when selecting a car by considering various criteria and alternatives. AHP provides a structured approach for evaluating and prioritizing different factors.

The AHP method involves breaking down the decision problem into a hierarchy of criteria and sub-criteria. The decision-maker assigns weights to each criterion based on their relative importance. Then, the alternatives (different car options) are evaluated against each criterion, and pairwise comparisons are made to determine their relative performance. These comparisons are converted into numerical values using a scale, such as the Saaty scale, to establish the preference of one alternative over another.

By applying mathematical calculations and aggregating the preferences, the AHP method generates a final ranking of the car alternatives based on their overall performance across the criteria. This enables the decision-maker to select the car that aligns most closely with their preferences and satisfies the desired criteria, considering factors such as price, fuel efficiency, safety features, comfort, reliability, and others.

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Answer:

..

Explanation:

like this

have you understood