From its position in the periodic table, determine which atom in each pair is more electronegative: (a) N or P (b) N or Ge (c) S or F (d) Cl or S (e) H or C (f) Se or P (g) C or Si

Answer:

200K

Explanation:

Pressure is directly proportional to temperature.

100=225

x=450

(100*450)/225=x

x=45000/225

x=200

Answer: The enthalpy of combustion of iso-octane in excess oxygen at 298 K is -5462.2kJ/mol

Explanation:

The balanced reaction for combustion of isooctane is:

\(C_8H_{18}(l)+\frac{25}{2}O_2(g)\rightarrow 8CO_2(g)+9H_2O(l)\)

The equation for the enthalpy change of the above reaction is:

\(\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{(CO_2(g))})+(9\times \Delta H^o_f_{(H_2O(l))})]-[(1\times \Delta H^o_f_{(C_8H_{18}(g))})+(\frac{25}{2}\times \Delta H^o_f_{(O_2(g))})]\)

We are given:

\(\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.51kJ/mol\\\Delta H^o_{C_8H_{18}(l)}=-258.07kJ/mol\)

Putting values in above equation, we get:

\(\Delta H^o_{rxn}=[(8\times (-393.51))+(9\times (-285.8))]-[(1\times (-258.07))+(\frac{25}{2}\times (0))]\\\Delta H^o_{rxn}=-5462.2kJ/mol\)

The enthalpy of combustion of iso-octane in excess oxygen at 298 K is -5462.2kJ/mol

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

In all the patients with rheumatoid arthritis RF is not present. It can also be witnessed in patients with conditions like hepatitis, bacterial endocarditis, and tuberculosis. Some of the reasons that can also produce false-positive results for RF assay are lipemic, hemolyzed, or heavily contaminated serum, other rheumatic diseases like systemic lupus erythematous, reading test results post the specified time of two minutes, and due to some of the chronic infectious diseases like hepatitis, tuberculosis, and syphilis.

b. The symptoms of the oatient like inflammation and pain in joints and the results of the lab indicate that the synovial fluid is drying and formation of crystal is taking place. These are the conditions that suggests the existence of rheumatoid arthritis.

c. In the given case, the first choice diagnosis would be the blood test that would show the presence of anti-CCP antibodies and the drying of synovial fluid. The presence of anti-CCP antibodies results in wear and tear in the joints, thus showing the diseased conditions.

The specific heat of the solid is 4.2 J/g/°C and the specific heat of the liquid is 36.3 J/g/°C.

In this case, we know that the mass of the solid is 9.80 g, the change in temperature is 235 °C, and the heat added is 10,000 J. We can solve for the specific heat of the solid as follows:

c = Q / m ΔT

= 10,000 J / 9.80 g / 235 °C

= 4.2 J/g/°C

The latent heat of fusion for the unknown material is 334 J/g. We can now calculate the heat required to melt the solid as follows:

Q = mLf

= 9.80 g * 334 J/g

= 32,832 J

The total heat added to the liquid is 10,000 J + 32,832 J = 42,832 J. The change in temperature of the liquid is 235 °C - 20 °C = 115 °C. We can now calculate the specific heat of the liquid as follows:

c = Q / m ΔT

= 42,832 J / 9.80 g / 115 °C

= 36.3 J/g/°C

Therefore, the specific heat of the solid is 4.2 J/g/°C and the specific heat of the liquid is 36.3 J/g/°C.

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An experiment is performed on an unknown material and produces the given heat curve. The temperature of the material is shown as a function of heat added. Other experiments determine that the material has a temperature of fusion of fusion=235 °C and a temperature of vaporization of vapor=471 °C.

If the sample of material has a mass of =9.80 g, calculate the specific heat when this material is a solid, s, and when it is liquid, l.

In the case of a real gas when you're using Van Der Waals equation, the volume of a real gas is considered as (Vm - b), where b can be considered as the volume occupied by per mole.

Therefore, when the ideal gas law gets substituted with V = Vm  - b, it is given as : P(Vm  - b) = nRT

The presence of intermolecular attraction P was modified as follows.

\(\frac{P+a}{V^{2} } (Vm- b) = RT\\\frac{P+an^{2} }{V^{2} } (V - nb) = nRT\)

Where, Vm: molar volume of the gas

R: universal gas constant

T: temperature

P: pressure

V: volume

Thus, it is possible to reduce Van Der Waals equation to the ideal gas law as PVm = RT.

What is the significance of the Ideal gas Law?

The ideal gas law only functions as an approximation approach when high accuracy is not necessary because it describes the behaviour of ideal gasses, which there aren't any of. It is a solid introduction to the fundamental behaviour of gases and works well as a teaching tool, which is why it is taught to the majority of university students as part of any introduction to physics. In essence, the ideal gas law enables students to comprehend ideas such as the process of thermodynamic cycles, such as an engine, the reason an airbag expands, what transpires to a balloon at high altitude, and other related ideas.

Hence, Van Der Waals equation to the ideal gas law as PVm = RT.

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Answer:

KOH is a strong base, and therefore dissociates completely into negative  and positive ions in water solution. pH 8.35 is a high pH (> 7), therefore this is a basic solution. 4.

Explanation:

Answer: Auroras

Explanation:

Hope this helps

Answer:

Option Auroras is correct

Explanation:

I got it right.

Answer:

a base

Explanation:

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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We have a crucible and we don't heat it enough to remove all the volatile impurities. For example:

mass of crucible empty = 100 g

mass of impurities = 1 g

mass of crucible + impurities = 101 g

The real mass of the crucible is 100 g but we didn't remove all the impurities so when we weigh it we get a reading of 101 g.

We add a sample of a salt that weighs 20 g. We heat it and after that we measure the crucible and the sample weighs 115 g.

mass of sample before heating = 20 g

mass of sample + crucible after heating = 115 g

We can say that 5 g of water were vaporized but we had 1 g of impurities that also vaporized so actually they were 4 g.

So the answer is: b) your sample will weigh less than it is supposed to after heating, causing the mass of water to be higher than it is supposed to be

what's the full question so i can give you an answer?

When the equilibrium constant is higher than one, it indicates that the reaction prefers to produce products, whereas if the equilibrium constant is less than one, it indicates that the reaction prefers to produce reactants. If the equilibrium constant is equal to one, the reaction proceeds in both directions equally.

In a chemical reaction, exothermic reactions are defined as reactions that release heat into their environment. It implies that heat is given off when reactants are converted to products. At equilibrium, an exothermic reaction continues to be exothermic, meaning that heat is given off even after the reaction reaches a state of equilibrium.There are two types of reactions: exothermic and endothermic.

A reaction is classified as exothermic if it releases heat, and endothermic if it absorbs heat. The direction of the reaction is determined by whether it is exothermic or endothermic. At equilibrium, the reaction is no longer moving forwards or backwards. It's also worth noting that reactions can be exothermic in one direction and endothermic in the other.

The equilibrium constant (K) is defined as the ratio of the concentration of products to the concentration of reactants in the chemical reaction equation. It is used to express how much of the products is generated by the reaction in comparison to the reactants.  the equilibrium constant aids in the identification of the direction in which the reaction will proceed at equilibrium.

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Answer:

A or C

Explanation:

I don't know if I'm correct but I think it's A or C you don't have to choose them.

Answer:

molality

Explanation:

The SI unit for molality is moles per kilogram of solvent. A solution with a molality of 3 mol/kg is often described as "3 molal", "3 m" or "3 m". hope this helps you :)

Answer: a

. dissolving it in water

Explanation:

When the unknown material is dissolved in water, it could react with the water particles and end up producing another material. For instance an alkali metal in water could form metal oxides.

Heating the material until it melts will not change it into another material because it will still be the same material only now it will be in liquid form. The same logic applies if it is burnt in a flame.

Answer:

a). Second order reaction.

b). \($50.14\ Lmol^{-1}s^{-1}$\)

c).  \($t_{1/2}=1994.41 \ h$\)

Explanation:

a). The order of the reaction of ozone decomposition is second order reaction.

It will be second order because the plot between the Inverse of Concentration versus Time will be a straight line.

\($\frac{1}{[A]}=\frac{1}{[A_0]}+kt$\)

b). Calculating slope by

\($y_0= 100000.000$\)

\($y_1= 952380.952$\)

\($\Delta y = 852380.9524$\)

\($x_0=0E+00$\)

\($x_1= 2E+04$\)

\($\Delta x = 2E+04$\)

Slope, k = \($\frac{\Delta y}{\Delta x}=50.14$\)

Thus we see that the slope of the curve will be rate constant.

Therefore, rate constant = \($50.14\ Lmol^{-1}s^{-1}$\)

c). We know half life ,

\($t_{1/2}=\frac{1}{k[A_0]}$\)

\($[A_0]=0.00001 \ mol/L$\)

k = \($50.14\ Lmol^{-1}s^{-1}$\)

Putting the values, we get

\($t_{1/2}=\frac{1}{50.14[0.00001]}$\)

\($t_{1/2}=1994.41 \ h$\)

Answer: B.) -12.4

Explanation: This is because the sign of heat transfer is determined by the system's perspective. In this case, the system is releasing heat to the surroundings, which means that heat is flowing out of the system, making the heat transfer negative. The magnitude of the heat transfer is 12.4 J.

The mass of the carbon dioxide is  49.72 g from the calculation done.

The phrase "mole fraction," which is often referred to as "molar fraction" or "amount fraction," is used to describe the proportions of a mixture's components. It is an intangible quantity that expresses the proportion between the moles of a given component and the total moles in the combination.

We know that;

Number of moles of ethanol = 9.2/46 g/mol

= 0.2 moles

Now;

Number of moles of water = 216.0 g/18 g/mol

= 12 moles

Mole fraction of water = Number of water/ Total number of moles

0.9 = 12/12 + 0.2 + x

0.9(12.2 + x) = 12

10.98 + 0.9x = 12

x = 1.13 moles

Now;

Moles = mass/Molar mass

1.13 = x/44

x = 49.72 g

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Answer:

The percent yield is 48.29%.

Explanation:

1st) To calculate the percent yield, it is necessary to use the Actual yield (the given values in the exercise) and the Theoretical yield (the values given by the balanced chemical reaction).

Balanced chemical reaction:

With the balanced chemical reaction we know that 1 mole of Mg3N2 reacts with 6 moles of H2O to produce 3 moles of Mg(OH)2 and 2 moles of NH3.

2nd) It is necessary to convert the moles to grams, using the molar mass of each compound:

- Mg3N2 molar mass: 100.95g/mol

- H2O molar mass: 18g/mol

- NH3 molar mass: 17.03g/mol

- Conversion of Mg3N2 moles to grams:

- Conversion of H2O moles to grams:

- Conversion of NH3 moles to grams:

Now we know that 100.95g of Mg3N2 react with 108g of H2O to produce 31.06g of NH3. Those values are the Theorerical values.

3rd) To calculate the percent yield we can use the formula and replace the values of the product NH3:

So, the percent yield is 48.29%.

Answer:

B) Energy will be added

Explanation:

I just took the test...

Answer:

The concentration of this solution in units of pounds per gallon is \(2.776*10^{-5} \frac{lb}{gal}\)

Explanation:

Units of measurement are established models for measuring different quantities. The conversion of units is the transformation of a quantity, expressed in a certain unit of measure, into an equivalent one, which may or may not be of the same system of units.

In this case, the conversion of units is carried out knowing that 1 μg are equal to 2.205*10⁻⁹ Lb and  1 mL equals 0.00022 Gallons. So

\(2.77 \frac{ug}{mL} = \frac{2.77 ug}{mL}\)

If 1 μg equals 2.205*10⁻⁹  lb, 2.77 μg how many lb equals?

\(lb=\frac{2.77ug*2.205*10^{-9}lb }{1ug}\)

lb=6.10785*10⁻⁹

So, 2.77 μg= 6.10785*10⁻⁹ lb

Then:

\(2.77 \frac{ug}{mL} = \frac{2.77 ug}{mL}=\frac{6.10785*10^{-9}lb }{mL} =\frac{6.10785*10^{-9}lb }{0.00022 gal} =\frac{6.10785*10^{-9}lb }{0.00022 gal}\)

You get:

\(2.77 \frac{ug}{mL} = 2.776*10^{-5} \frac{lb}{gal}\)

The concentration of this solution in units of pounds per gallon is \(2.776*10^{-5} \frac{lb}{gal}\)

Answer:

Fe + CuCl2 = FeCl2 + Cu

Explanation:

This is already balanced.

The rate law is  mathematically given as

   Rate =k1​K[NO][O2​][NO]=K′[NO]2[O2​], where K′=k1​K

Generally, the equation for Chemical reaction is  mathematically given as

NO+O2​--->NO3​   ---- for the fast reaction                  

NO3​+NOk1​​NO2​+NO2​ ---- for the slow reaction

A rate-determining step, the slowest response

 \(Rate =k1​[NO3​][NO] \\\\K=[NO][O2​][NO3​]​\)

[NO3​]=K[NO][O2​]

   Rate =k1​K[NO][O2​][NO]=K′[NO]2[O2​], where K′=k1​K

In conclusion,

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The equilibrium expression can be written as follows:

K = [CaCO₃] × [H₂]⁴

------------------

[CaO] × [CH₄] × [H₂O]²

In this equilibrium expression, the square brackets represent the concentrations of the species involved in the reaction, and the coefficients of the balanced equation indicate the stoichiometric coefficients of the corresponding species.

The concentration of a pure solid (CaCO₃ in this case) is not included in the equilibrium expression, as it remains constant throughout the reaction.

The equilibrium constant (K) represents the ratio of the product concentrations to the reactant concentrations at equilibrium, each raised to the power of their respective stoichiometric coefficients. The specific values of these concentrations depend on the initial conditions, and K remains constant as long as the temperature is unchanged.

It is important to note that the equilibrium constant expression is written based on the balanced chemical equation. The stoichiometric coefficients determine the relationship between the concentrations of reactants and products, allowing us to express the equilibrium state quantitatively using the equilibrium expression.

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The calculation gives the product 17000 to 2 significant figures

Significant figures in a calculation or a number refers to the number of non-zero numbers that are present in a number.

If the number contains a decimal point, the number of non-zero numbers before the decimal point gives the number of significant figures.

However, if a zero occurs between non-zero numbers, it is considered significant.

Significant figures are used in approximation to indicate to what point a set of numbers become significant.

In a calculation, the number significant figure is determined by the number which has the lowest number of significant figures.

In the given calculation, the lowest significant figure is in the numbers 3700 and 5.60

3700 × 20.1 × 5.60 × 0.0407 = 17000 to 2 significant figures

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Ammonium sulfate fertilizer is more expensive than sodium nitrate fertilizer in most cases.

As a fertilizer, sodium nitrate is more cost-effective than fertilizer that contains ammonium sulfate due to its higher nitrogen content. Because sodium nitrate contains a higher percentage of nitrogen, it meets the plant's need for fertilizer while requiring less fertilizer to be applied.

You can determine the proportion of nitrogen in ammonium sulfate by dividing the molar masses of the two nitrogen atoms by the molar masses of the compound and then multiplying the result by 100. This indicates that every 100 grams of ammonium sulfate contains 21.2 grams of nitrogen.

To determine the generator and power station's percentage efficiency, divide the 3,412 Btu equivalent of a kWh of energy by the heat rate. For instance, at a heat output of 10,500 Btu, the efficiency is 33%.

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The measure of the length of events and the duration of intervals between events is time.

The duration of events or the gaps between them can be measured, compared, or even ordered using time. The lengthy period of time that the Earth's geologic history takes up is known as geologic time. Starting at the beginning of the Archean Eon  formal geologic time runs until the present. Geology is defined as the "Science of the Earth."

Geology is the fundamental Earth science that examines how the earth created, its structure and composition, and the various forces acting on it. It is sometimes known as geoscience or earth science.

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No, this statement is not correct. A weak base will not completely dissociate and accept all of the hydrogen ions released from the acid.

Instead, a weak base will partially dissociate and accept some of the hydrogen ions, helping to buffer the drop in pH but not completely preventing it. This is why weak bases are used as buffers in solutions, as they can help to maintain a relatively stable pH even when an acid is added. However, they will not completely prevent a drop in pH like a strong base would.

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