From Earth stars appear very dim, but in space they are quite bright. From Earth we are seeing the stars

A) absolute magnitude
B) apparent magnitude
C) available magnitude
D) absent magnitude

The wavelength is 6.04 nm.

since

λ=hc/E

λ=6.626×10^ −34×3×10 ^8/(3.29×10−19)

λ=6.04nm

The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or down a wire is defined as the wavelength. This length is often defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

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Answer:

The gravitational potential energy of a squirrel is 53.312 J.

Explanation:

We have,

Mass of a squirrel is 0.68 kg

It is placed at a height of 8 m above the ground.

It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

\(E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J\)

So, the gravitational potential energy of a squirrel is 53.312 J.

Answer:

H

Explanation:

Answer:

Pacific Ocean and Nazca plates is moving to west

Explanation:

beacause if they move to west they will move to the left

Answer:

The combined mass of the two stars is 2.9417 solar masses.

Explanation:

The mathematical expression for Kepler's third law is;

                        \(P^{2}\) = \(\frac{4\pi ^{2} }{k^{2} (M_{1} + M_{2} }a^{3}\)

Where: P is the period in days, a is the semimajor axis in AU, \(M_{1}\) is the mass of the first star, \(M_{2}\) is the mass of the second star and k is the Gaussian gravitational constant.

Given that;

P = 10 years = 3670 days (including two leap years)

a = 6.67 AU

k = 0.01720209895 rad

\(\pi\) = \(\frac{22}{7}\)

The sum of the masses of the two star can be determined by;

\((M_{1} + M_{2})\) = \(\frac{4\pi ^{2} }{P^{2}k^{2} } a^{3}\)

                = \(\frac{4*(\frac{22}{7}) ^{2} } {(3650)^{2} * (0.01720209895)^{2} } (6.67)^{3}\)

                = \(\frac{11724.29601}{3942.2904}\)

               = 2.9417 solar masses

Thus the combined mass of the two star is 2.9417 solar masses.

A repulsive force between the two magnets causes the suspended magnet to swing to the left. Option A

We know that a magnet is any materials that has the magnetic domains in the substance being properly aligned. The implication of this is that the material is also capable of making the magnetic domains in another material to also become aligned.

The materials that can be attracted by a magnet are said to be magnetizable materials. We can see that the force that acts between two magnets can be an attractive force or repulsive force depending on the poles of the magnet that are facing each other.

Since unlike poles attract and like poles repel, the poles that have been shown in the image that is attached would repel each other.

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 The percentage error in his experimental value is -51.97%.

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

From the question,

Given:

Substitute these values into equation 1

Hence, The percentage error in his experimental value is -51.97%.

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The heat required for the change of state of the materials in the question  are;

4. a. 894000 J, b. 423000 J, c. 8040 J

5. 0.096 kg

6. 321 kJ/kg

7. a. Copper; 287625 J, Silver; 108307 J, Gold; 67795 J

b. 0.0598 kg

8 a. 1302.46 °C

b. 11157 J

Specific latent heat is the amount of heat energy required to change the state of a substance while the temperature of the substance remain the same.

4. The energy needed to evaporate;

a. 3 kg of petrol (octane) = 3 kg × 298000 J/kg = 894000 J

b. 500 g of ethanol = 0.5 kg × 846000 J/kg = 423000 J

c. 20 g of vineger (acetic acid) = 0.02 kg × 402000 J/kg = 8040 J

5. The mass of the liquid ethanol that can be evaporated by supplying 80 kJ of energy = (80 kJ)/(846 kJ/kg) ≈ 0.096 kg

6. The specific latent heat of melting of aluminium = (6420 kJ)/(20 kg) = 321 kJ/kg

7. a. The energy needed to heat each sample to its melting point:

Copper: m·c·ΔT = (0.5 kg)×(390 J/kg°C)×(1495°C - 20°C) = 287625 J

Silver: m·c·ΔT = (0.5 kg)×(230 J/kg°C)×(961.8°C - 20°C) = 108307 J

Gold: m·c·ΔT = (0.5 kg)×(130 J/kg°C)×(1063°C - 20°C) = 67795 J

7. b. The amount of copper that melts:

Energy needed to heat copper to its melting point: Q1 = m·c·ΔT = (0.5 kg)×(390 J/kg·°C)×(1495°C - 20°C) = 287625 J

Energy remaining for melting; Q2 = (300 kJ) - Q1 = (300000 J) - (287625 J) = 12375 J

Mass of copper that melts; m = Q2/Lf = (12375 J)/(207000 J/kg) ≈ 0.0598 kg

Extra challenge:

8a. Final temperature of the liquid silver;

Energy needed to heat silver to its melting point; Q1 = m·c·ΔT = (0.5 kg)×(230 J/kg·°C)×(961.8°C - 20°C) = 108307 J

Energy needed to melt silver: Q2 = m·L·f = (0.5 kg)×(88000 J/kg) = 44000 J

Energy remaining for heating liquid silver: Q3 = (200 kJ) - Q1 - Q2 = 200000 J - 108307 J - 44000 J = 47693 J

Final temperature of the liquid silver: ΔT = Q3/(m·c) = 47693/(0.5×280) ≈ 340.66

\(T_f\) ≈ 961.8 + 340.66 = 1302.46

The final temperature is about 1302.46 °C

8 b. Energy needed to obtain liquid gold at a temperature of 1200°C

Energy needed to heat gold to its melting point; Q1 = m·c·ΔT = (0.05 × 130 × (1063 - 20) = 6779.5

Energy needed = 6779.5 J

Energy needed to melt gold; Q2 = m·Lf = (0.05 kg)×(67000 J/kg) = 3350 J

Energy needed to heat liquid gold from its melting point to final temperature; Q3 = m·c·ΔT = (0.05 kg) × (150 J/kg·°C) × (1200°C - 1063°C) = 1027.5 J

The sum of the energy required, Q = Q1 + Q2 + Q3 = 6779.5 + 3350 + 1027.5 = 11157

The total energy required is 11157 J

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The particle model of light, also known as the corpuscular theory, proposes that light is composed of discrete particles, or photons, that travel in straight lines and interact with matter through collisions.

This model was developed by Isaac Newton and was used to explain the reflection and refraction of light.

On the other hand, the wave model of light proposes that light is composed of waves that travel through a medium, such as the electromagnetic field.

This model was developed by James Clerk Maxwell and was used to explain phenomena such as interference, diffraction, and polarization of light.

Both models have their strengths and limitations, and the current understanding of light incorporates elements from both models, known as wave-particle duality. This theory proposes that light exhibits characteristics of both waves and particles depending on the context of the observation.

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The simple machines that are used in the tool or device include all of the following:

In Science, a simple machine can be defined as a type of machine that is designed and developed with no moving parts, but can be used to perform a specific work.

Additionally, there are six (6) simple machines and these include the following;

Generally speaking, a simple machine allows for the transformation of energy into work.

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l=500m

speed=70m/s

t=?

t=500/70=7.14s

Kim's policy remained in force for a certain number of days even though she forgot to pay the premium. the provision that allows this is called grace period provision

If the policyowner fails to make the premium payments due to some issue or reason, the insurance company will not immediately cancel the policy , whereas the company will wait for few days if no action seen than only they will take action on that account .

The grace period provision allots a specifically designated amount of time in which the policyowner has to make the required premium payments after the stipulated due date.

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Answer:

no i dont think so

Explanation:

The average angular acceleration of the ultracentrifuge is approximately 1.46 × 10⁵ rad/s², calculated using the formula (Final angular velocity - Initial angular velocity) divided by the time interval.

To determine the average angular acceleration, we can use the formula:

Angular acceleration (α) = (Final angular velocity - Initial angular velocity) / Time

Given:

Initial angular velocity (ω₁) = 0 rad/s (since the ultracentrifuge starts from rest)

Final angular velocity (ω₂) = 100,000 rpm = (100,000 rev/min) × (2π rad/rev) / (60 s/min) ≈ 10,472.19 rad/s

Time (t) = 2.00 min = 2.00 × 60 s = 120 s

Plugging these values into the formula, we have:

α = (10,472.19 rad/s - 0 rad/s) / 120 s ≈ 87.27 rad/s²

However, since the question asks for the angular acceleration in proper scientific notation with the correct subscripts and superscripts, we can express the answer as 1.46 × 10⁵ rad/s².

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The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.

Given:

Current (I) = 5 mA = 5 * 10^(-3) A

Resistance (R) = 18 kΩ = 18 * 10^(3) Ω

Using Ohm's Law, we can calculate the voltage drop (V):

V = I * R

= (5 * 10^(-3) A) * (18 * 10^(3) Ω)

= 90 V

Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

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Answer:

Cat with 6 kg sitting on a 30 meter hill has greater potential energy.

Explanation:

gravitational potential energy (J) = mass (kg) × gravitational field × height (m)

gravitational field in Earth is 10 N/kg = fixed unit

1st Cat: 4 kg

2nd Cat: 6 kg

Both of their height is 30 meters.

1st cat = mgh = 4 × 10 × 30 = 1200 Joules

2nd cat = mgh = 6 × 10 × 30 = 1800 Joules

The speed of the sonar signal can be calculated by multiplying the frequency of the signal (288 Hz) by the wavelength (5.00 m). Thus, the speed of the sonar signal is 1,440 m/s.

To find the speed of the sonar signal, we can use the formula v = f * λ, where v represents the speed, f is the frequency, and λ is the wavelength.

Given that the frequency of the sonar signal is 288 Hz and the wavelength is 5.00 m, we can substitute these values into the formula.

v = 288 Hz * 5.00 m

By multiplying the frequency and the wavelength, we can calculate the speed of the sonar signal.

v = 1440 m/s

Therefore, the speed of the sonar signal is 1440 meters per second.

Sonar devices use the speed of sound in water to measure underwater depths. By transmitting sound waves and measuring the time it takes for them to bounce back, sonar systems can determine the distance between the device and an object underwater. The speed of the sonar signal is crucial for accurate depth calculations, as it affects the time it takes for the signal to travel and return.

The question was incomplete. find the full content below:

Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz, and the wavelength is 5.00 m, what is the speed of the sonar signal in water?

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Answer:

Sound travels more quickly through solids than through liquids and gases because the molecules of a solid are closer together and, therefore, can transmit the vibrations (energy) faster. Sound travels most slowly through gases because the molecules of a gas are farthest apart.

Given:

The mass of the oil drop is

The number of electrons is n = 11

The distance between the plates is

To find

(a) The charge absorbed by the oil drop.

(b) The potential difference between the plates.

Explanation:

The charge absorbed by the oil drop can be calculated by the formula

Here, e is the charge of the electron whose magnitude will be

On substituting the values, the charge absorbed by the oil drop will be

(b) The potential difference can be calculated as

Answer:

v = 5 [m/s]

Explanation:

Kinetic energy is related to speed, that is, whenever we have kinetic energy we will have a body with speed moving.  This can be calculated using the following equation.

\(E_{k}=\frac{1}{2}*m*v^{2}\\\)

where:

m = mass = 2 [kg]

v = velocity [m/s]

Ek = kinetic energy = 25 [J]

Now replacing:

\(25 = \frac{1}{2}*2*v^{2} \\v=\sqrt{25} \\v = 5 [m/s]\)

Answer:

they can have both ways because it turns out that they can go into different ways light waves are associated with constantly like her to certain ways or

most people use the term light waves when they usually mean visible light in physics however these terms like veins are trying to be used as a synonym of electronic waves electric razor made of skull in magnetic and electric field like always they carry energy

Answer:

3000J

Explanation:

The gravitational energy for any object is given by E=mgh

where m is mass, g is gravitational field strength anf h is height above ground

A freeway exit ramp has a single lane and consists entirely of a horizontal curve with a central angle of 90 degrees and a length of 628 ft. If the distance cleared from center line for sight distance is 19.4 ft. The design speed used for the freeway exit ramp is approximately 0.639 mph.

To calculate the design speed used for the freeway exit ramp, we can utilize the sight distance formula. The sight distance is the distance cleared from the center line that provides adequate visibility for safe driving

The formula for sight distance on a horizontal curve is:

Sight Distance = 2 × R × sin(A/2)

Where:

  Sight Distance is the distance cleared from the center line for sight distance.

   R is the radius of the curve.

   A is the central angle of the curve.

In this case, the central angle is given as 90 degrees, and the sight distance is given as 19.4 ft. We need to solve for the radius R.

Let's rearrange the formula to solve for R:

R = Sight Distance / (2 × sin(A/2))

Plugging in the values:

R = 19.4 ft / (2 × sin(90/2))

R = 19.4 ft / (2 × sin(45))

R = 19.4 ft / (2 × 0.7071)

R = 13.751 ft

Now, we can calculate the design speed using the formula:

Design Speed = (R * 0.06)^(1/3)

Design Speed = (13.751 ft * 0.06)^(1/3)

Design Speed = (0.825 ft)^(1/3)

Design Speed ≈ 0.937 ft/s

To convert this to miles per hour (mph), we multiply by 3600/5280 (since there are 3600 seconds in an hour and 5280 feet in a mile):

Design Speed ≈ (0.937 ft/s) × (3600/5280) ≈ 0.639 mph

Therefore, the design speed used for the freeway exit ramp is approximately 0.639 mph.

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The force produced on the larger piston is 2500N.

The force exerted on a fluid in a closed system is transmitted equally in all directions, according to Pascal's Principle. In this case, the force of 100N applied on the smaller piston will be transmitted equally to the larger piston through the hydraulic fluid.

The ratio of the areas of the larger and smaller piston is 0.05m² / x m², where x is the area of the smaller piston. We can solve for x by setting the ratio equal to the force ratio:

where F1 is the force applied on the smaller piston (100N) and F2 is the force produced on the larger piston.

Solving for x, we get:

Using the same equation and plugging in the values for F1, F2, and the areas of the pistons, we get:

Therefore, the force produced on the larger piston is 2500N.''

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Answer: D. Cobalt

Explanation: Cobalt has excellent magnetic properties so it is D. Cobalt.

The element which has magnetic properties from the given list of elements would be cobalt , therefore the correct answer is option C.

The elements of the periodic tables that behave as metals, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron , silicon , germanium, arsenic , antimony , tellurium , etc.

As given in the problem we have to find out the element which possesses the magnetic properties from the given list ,

Calcium belongs to group 2 of the periodic table and nonmagnetic element . Similarly , carbon is a nonmagnetic material .

Thus , the element which has magnetic properties from the given list of elements would be cobalt, therefore the correct answer is option C .

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a. The impulse acting on the car is 7.4×10³ N⋅s

b. The new impulse acting on the car is −7.4×10³ N⋅s.

c. The average force is 2.3×10³ N.

d. the new average force is 2.1×10⁴ N.

Let the initial and final momentum of the car be pi =mνi and pf =m νf, respectively. The impulse on it equals the change in its momentum, J =Δ p = pf − pi =m(νf − νi ). The average force over the duration Δt is given by  Favg = J /Δt.

(a) The initial momentum of the car is pi =m νi =(1400kg)(5.3m/s)j^ =(7400 kg⋅m/s) j^ and the final momentum after making the turn is pf​ =(7400 kg⋅m/s) i^.

Thus, the impulse is, J = pf − pI  =(7.4×10³ N⋅s)( i^ − j^ ) .

(b) The initial momentum of the car after the turn is pi'  =(7400 kg⋅m/s) i^  and the final momentum after colliding with a tree is p f′ =0.

The impulse acting on it is J′ = pf′ − pi′ =(−7.4×10³ N⋅s) i^.

(c) the average force on the car during the turn is Favg = ΔtxΔ p = ΔtxJ = 4.6s(7400⋅m/s)( i^ − j^ ) =(1600N)( i^ − j^ ) and its magnitude is Favg​=(1600N) 2 =2.3×10³ N .

(d) The average force during the collision with the tree is Favg′​ = ΔtxJ'  = 350×10 −3 s(−7400 kg⋅m/s) i^ =(−2.1×10⁴ N) i^ and its magnitude is  F  avg′

=2.1×10⁴ N.

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Answer:

λ = V T        S is distance between wavefronts, T is period of emitter

λ  = 3.00E8 m/s * 1 / 2.40E10 = .0125 m    

λ emitted by speed gun = .0125 m

But gun moves Vg * T     between wavefronts

λ' = λ - Vg T where λ' is wavelength received by stationary observer

One can calculate T' from 3.00E8 m/s the period seen by observer, that is the period measured by the observer is the speed of light divided by the wavelength received by the observer

Now if the observer is moving the wavelength observed by the observer is λ'' = λ'  - Vo T' since the observer will move a distance Vo T' between receiving wavefronts (T' has been calculated)

That is, the waves received by the tennis ball are shortened because of the motion of the tennis ball.

The  speed of the wave measured is always 3.00E8 m/s

(a) Both spheres are launched with 0 initial velocity in the vertical direction, so they both hit the ground at time t such that

10 m - 1/2 g t ² = 0

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Solve for t :

10 m = 1/2 g t ²

t ² = (20 m) / g

t ≈ 1.4 s

(b) Sphere A travels a horizontal distance of

(5.0 m/s) (1.4 s) ≈ 7.1 m

while sphere B travels a distance of

(2.5 m/s) (1.4 s) ≈ 3.6 m

The speed of the river is 0.5 Km/hr

Let X be the speed of the boat.

Let Y be the speed of the river.

Downstream speed

X - Y = 4

Upstream speed

X + Y = 5

By solving, we get

2X = 9

X =  4.5 Km/hr

Y =  0.5Km/hr

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The speed of sound in air at the temperature of 136°F (331 K) = 365.71 m/s

The speed of sound in air depends on temperature, so the higher the temperature, the greater the value of the speed of sound.

The equation for determining the speed of sound with a change in temperature is:

v = v₀ + 0.6(∆T)

where:

v = the final sound velocity (m/s)

v₀ = the initial sound velocity (m/s)

∆T = temperature change (°C)

Note: The speed of sound in air at 0°C is 331 m/s.

We have ∆T = 136°F ⇒ 57.85°C

So,

v = 331 + 0.6 (57.85)

= 365.71 m/s

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