Answers
Answer: yep ur right
friction is when two objects tough with force basically. when an object is rubbed against something. when an object comes in contact with something else. or ig u can call it spicy air lol that works too , bud
whatever helps u ye
Related Questions
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
Answers
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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question an object of mass 0.5 kg experiences a force that is associated with the potential energy function u(x)
Answers
a. The sketch graph of U(x) versus x is in the attachment.
b. The force function that associate with the potential energy function is F(x) = 8.0 (2.0 + x)⁻²
c. The speed of the particle at x = 2 is 2 m/s.
The full question is in the attachment. To create a graph, substitute some values of x into the equation of the function to determine the pair of point coordinates.
a. Graph of U(x) = 4.0/(2.0 + x) versus x making a curve because the function is a fraction function and the curve will not intersect the x-axis.
If x = 0U(0) = 4.0/(2.0 + x) = 4.0/(2.0 + 0) = 4.0/2.0 = 2.0
(0 , 2.0) If x = 2
U(2) = 4.0/(2.0 + x) = 4.0/(2.0 + 2) = 4.0/4.0 = 1.0
(2 , 1.0)If x = 3
U(3) = 4.0/(2.0 + x) = 4.0/(2.0 + 3) = 4.0/5.0 = 0.8
(3 , 0.8)
From these coordinates a graph is created in the image.
b. A conservative force is a force that works on an object depends only on the initial and final position of the object and not on the path of the object. The total work from a conservative energy is always the same with the changes in potential energy
W = - ΔU
F × Δx = - ΔU
W = the total work (J)Δx = the distance (m)ΔU = the potential energy (J)The conservative force acting on the object is the derivate of the potential energy function for the objects
F = - dU/dx
U(x) = 4.0/(2.0 + x) = 4.0 (2.0 + x)⁻¹
F = - 4.0 × - 2 (2.0 + x)⁻² × 1
F(x) = 8.0 (2.0 + x)⁻²
c. The kinetic energy Ke = 0.5 mv²
m = the massv = the speedKe = kinetic energyWhen the object is released from rest at the origin to x = 2
The initial speed = v₁ = 0Kinetic energy = Ke₁ = 0.5 mv₁² = 0 J
Potential energy = U(0) = 4.0/(2.0 + x) = 4.0/(2.0 + 0) = 4.0/2.0 = 2.0 JAt x = 2
Potential energy = U(2) = 4.0/(2.0 + x) = 4.0/(2.0 + 2) = 4.0/4.0 = 1.0 J
According to law of conservation of energy
Ke₁ + U(0) = Ke₂ + U(2)
0 + 2.0 = Ke₂ + 1.0
Ke₂ = 2.0 - 1.0
Ke₂ = 1.0 J
0.5 mv₂² = 1.0
0.5 × 0.5 × v₂² = 1.0
v₂² = 1.0 ÷ 0.25
v₂² = 4
\(v_2 \:=\: \sqrt{4}\)
v₂ = 2 m/s
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Which value is equivalent to 178 centimeters?
Answers
Answer:
5.8399
Explanation
work:
176cm
1cm=0.39 in
1cm=0.39x178=178cm=70.07in
70.0787/12=5.8399
Answer:
1.78 meters
Explanation:
It's what you get when you convert it to meters in search
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
Answers
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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Blue light with a wavelength of 4.57 E-7 m is used in Young's experiment with the slits separated by a distance of 2.42 E-4Y
m. The screen is located at a distance from the slits of 4.5 m. Calculate the distance on the screen between the central
bright fringe and the first bright fringe. Show all work for full credit.
Answers
The distance between the central bright fringe and the first bright fringe on the screen is approximately 8.52E-3 meters.
In Young's double-slit experiment, the distance between the central bright fringe (m = 0) and the first bright fringe (m = 1) can be calculated using the following formula:
y = (m * λ * L) / d
where:
y is the distance between the fringes on the screen,
m is the order of the fringe (0 for the central bright fringe, 1 for the first bright fringe),
λ is the wavelength of the light,
L is the distance from the slits to the screen, and
d is the distance between the slits.
Given the values:
λ = 4.57E-7 m (blue light wavelength)
d = 2.42E-4 m (distance between the slits)
L = 4.5 m (distance from the slits to the screen)
For the central bright fringe (m = 0), the distance (y) is:
y = (0 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y = 0
Therefore, the central bright fringe coincides with the point where the two beams of light overlap.
For the first bright fringe (m = 1), the distance (y) is:
y = (1 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y ≈ 8.52E-3 m
This calculation demonstrates how the interference pattern in Young's experiment is formed, with bright and dark fringes being produced based on the constructive and destructive interference of the light waves from the two slits. The distance between these fringes depends on the wavelength of light, the separation of the slits, and the distance between the slits and the screen.
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Explain an example of how energy is transferred from one form to another
Answers
Answer:
Explanation:
Energy can can be transferred from one form to another in many ways,
Forms of energy that exist are Chemical Energy, Nuclear Energy
Electrical Energy Heat Energy and others.
one example is conversation of chemical energy by stove to heat energy.
Chemical energy which a form of energy that allow substance to experience chemical reaction, when a gasoline which posses chemical energy is put into stove then it convert this chemical energy to heat energy through burning which helps our food to cook as a result of heat energy gotten
Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge
Answers
F = k * (q1 * q2) / r^2
where k is Coulomb's constant (9 x 10^9 N m^2 C^-2).
In this problem, we have two equal and opposite charges, so we can assume that q1 = -q2 = q. The distance between them is 40 mm, which is 0.04 m. We are given that the force between them is 0.5 N. Therefore, we can set up an equation:
0.5 N = k * (q * q) / (0.04 m)^2
Simplifying and solving for q:
q^2 = (0.5 N * (0.04 m)^2) / k
q^2 = (0.5 N * (0.04 m)^2) / (9 x 10^9 N m^2 C^-2)
q^2 = 8.88 x 10^-12 C^2
q = sqrt(8.88 x 10^-12 C^2)
q = 2.98 x 10^-6 C
Therefore, the magnitude of each charge is 2.98 x 10^-6 C.
please I really need help, I will mark you brainliest
A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.
1. Calculate the impulse delivered to the ball.
2. What was the change in momentum of the ball?
3. What was the velocity of the ball as it left the tennis racket?
4. What would happen to the ball's velocity if it remained on the tennis racket longer than .05 s?
Answers
Explanation:
I am not sure about this question sry but u can try asking a tutor u don't need to use any points
if a liquid of a mass of 50 g and a density of 4.3 g/mL whats the volume in mL
Answers
The volume in mL is 11.62 ml.
We know that V = M/d
V = 50/4.3=11.62 ml.
The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).
Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density. For instance, while Earth has a density of 5.51 grams per cubic centimeter, water has a density of 1 grams per cubic centimeter. Another way to state density is in kilograms per cubic meter (in metre-kilogram-second or SI units). For instance, air weighs 1.2 pounds per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated.
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A student creates an electromagnet, How could the student create a larger current in the electromagnet?
Answers
Answer
When an electric current flows in a wire, it creates a magnetic field around the wire. This effect can be used to make an electromagnet. A simple electromagnet comprises a length of wire turned into a coil and connected to a battery or power supply.
A coil of insulated wire is wrapped around an iron nail. One end of the coil of wire is connected to a battery. The other is connected to a switch in the circuit
A simple electromagnet
You can make an electromagnet stronger by doing these things:
wrapping the coil around a piece of iron (such as an iron nail)
adding more turns to the coil
increasing the current flowing through the coil
There is a limit to how much current can be passed safely through the wire because the resistance of the wire causes heating.
Need help Physics Will make Brainliest
Answers
Force between q1 and q2
F= (8.99*10^9)(8*10^-6)(3.5*10^-6)
F= 25.2 N
Meaning 25.2 N to the right
Force between q2 and q3
F= (8.99*10^9)(3.5*10^-6)(-2.5*10^-6)
F= -3.5 N
Meaning 3.5 N to the left
Resultant force= 25.2-3.5
Resultant force on q2= 21.6 N to the right
Hope this helps :)
The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.
To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.
The force between two point charges can be calculated using Coulomb's law, which states that
F = k × q₁× q₂ / r²
where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.
The force between q₁ and q₂ is
F₁ = k × q₁ × q₂ / r₁²
where r₁ = 0.10 m.
Substituting the values, we get
F₁ = 9.0 x 10⁹ N m² / C² × 8.0 C × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N
The force between q₂ and q₃ is
F₂ = k × q₂ × q₃ / r₂²
where r₂ = 0.15 m.
Substituting the values, we get
F₂ = 9.0 x 10⁹ N m² / C² × 3.5 C × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N
Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.
The net force on q₂ is the vector sum of F₁ and F₂
\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N
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A cyclotron operates with a given magnetic field and at a given frequency. If R denotes the radius of the final orbit, then the final particle energy is proportional to which of the following?
A. 1/RB. RC. R^2D. R^3E. R^4
Answers
Answer:
C. R^2
Explanation:
A cyclotron is a particle accelerator which employs the use of electric and magnetic fields for its functioning. It consists of two D shaped region called dees and the magnetic field present in the dee is responsible for making sure the charges follow the half-circle and then to a gap in between the dees.
R is denoted as the radius of the final orbit then the final particle energy is proportional to the radius of the two dees. This however translates to the energy being proportional to R^2.
Some amount of ideal gas with internal energy U was heated from 100^0C to 200^0C. We can predict that internal energy after heating in terms of U is:
Answers
The internal energy after heating in terms of U is 100U.
The given parameters;
initial temperature of the gas, T₁ = 100 ⁰Cfinal temperature of the gas, T₂ = 200 ⁰CAssuming a constant pressure, the internal energy of the ideal gas is equal to the change in the enthalpy of the ideal gas.
\(\Delta H = U \times \Delta T\\\\\Delta H = U (200 - 100)\\\\\Delta H = 100 U\)
Thus, we can conclude that the internal energy after heating in terms of U is 100U.
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what would be the final size of the ballon in the example problem above if it were placed in a 18*C freezer?
Answers
Given data
The initial volume of the ballon is v = 2 L
The initial temperature is T = 20 C = 293 K
The ballon is placed inside the refrigerator at a temperator of T_f = - 18 C = 255 K
The pressure remains constant, the expression for the volume temperature relation is given as:
\(\frac{v}{T}=\frac{v_f}{T_{-f}}\)Substitute the value in the above equation.
\(\begin{gathered} \frac{2\text{ L}}{293\text{ K}}=\frac{v_f}{255\text{ K}}_{} \\ v_f=1.740\text{ L} \end{gathered}\)Thus, the final size of the ballon is 1.740 L.
Part A
What is the radius of the hydrogen-atom Bohr orbit shown in the figure? (Figure 1)
r = ____ nm
Answers
The radius of the hydrogen-atom Bohr orbit shown in the figure is 5.3 nm.
What is Bohr orbit?The path that hypothetical electrons take around the nucleus is known as Bohr's orbit.
These orbits are described by Bohr in his hypothesis of the structure of an atom as energy levels or shells where electrons move in a fixed circle around the nucleus.
These orbits resemble solar system orbits, with the exception that they are attracted by electrical forces rather than gravity. The term "ground state" refers to the amount of energy that an electron typically occupies.
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What is the reason that the liquid can flow?
Answers
Answer:
the attraction between particles
2 (a) A plane from airport A flies 280 km to the east to airport B. The plane then travelled north to airport C, 190 km away. (i) Sketch the displacement of the plane. (ii) Determine the resultant displacement. [5 marks] [ANS: DIY, DIY, 338 km, 34.16° from north of east]
Answers
Answer:
See below
Explanation:
See attached diagram
280 km east then 190 km north
Use Pythagorean theorem to find the resultant displacement
d^2 = 280^2 + 190^2
d = 338.4 km
Angle will be arctan ( 190/280) = 34.16 °
onsider laminar flow of a fluid through a square channel with smooth surfaces. now the average velocity of the fluid is doubled. determine the change in the head loss of the fluid. assume the flow regime remains unchanged
Answers
The head loss doubles when the average velocity is doubled.
The velocity formula: why?
The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).
How do velocity and speed differ?Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.
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According to Newton's First Law, what will an object in straight-line motion
tend to do?
O A. Slow down because of friction
B. Speed up
C. Stay in straight-line motion
D. Experience a force
Answers
Answer:
It will remain in straight-line motion at constant speed until acted on by an
external force. Moreover, it'll not only tend to do that ... it'll actually do it.
Explanation:
Second
class lever short note
Answers
Answer:
wow
Explanation:
A runner sprints for 20 minutes at an average pace at 7mph.what is the distance traveled?
Answers
Answer:
A runner sprints for 20 minutes at an average pace at 7mph.what is the distance traveled?
Explanation:
140
which of the following set of tools would be most useful in an experiment measuring the rate of thermal energy in four different liquids?
Answers
If an airplane is accelerating down a runway at 2.5 m/s^2, how much is it’s velocity changing each second?
Answers
If an airplane is is accelerating down a runway at 2.5 m/s². It's velocity changes 2.5 m/s in each second.
What is acceleration?Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.
Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Hence, the velocity of the airplane changes 2.5 m/s in each second when it is accelerating down a runway at 2.5 m/s².
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Whoever answers correctly gets brainlist!
Answers
Infared = used by police
gamma = short wavelength
radio = largest wavelength
visible = only ones we can see
Answer: police use infred waves,
radio waves have largest wave length, the
only part of the spectrum seen by humans is visible waves
gamma waves have shortest wave length
Explanation:
A horse track is a loop where the starting point and the finish line are at the same point. A horse gallops around a 400 m track in 20 s. Calculate the velocity of the horse
A.20 m/s
B.0.05 m/s
C.0 m/s
D.40 m/s
Answers
The velocity of the horse is 0 m/s, so the correct option is C.
The velocity is a vector that is given by the rate of change of the displacement.
\( v = \frac{d}{t} \)
Where:
d: is the displacement
t: is the time
Since in the horse track the starting point and the finish line are at the same point, the velocity of the horse is zero because the velocity depends on the direction of the displacement, and here the displacement is zero (the horse returns to the starting point).
Therefore, the correct option is C: 0 m/s.
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I hope it helps you!
Answer:
The velocity of the horse is 0 m/s:
Correct answer is C.
A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height as the point of release.
(a) What is the acceleration of the ball while it is in flight?
magnitude
_____ m/s2
direction
---Select---
(b) What is the velocity of the ball when it reaches its maximum height?
magnitude
_____ m/s
direction
---Select---
(c) Find the initial velocity of the ball.
____ m/s upward
(d) Find the maximum height it reaches.
____ m
Answers
(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.
Using the equation, we can solve for the acceleration:
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s
Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.
(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.
(c) To find the initial velocity of the ball, we can use the equation:
v = u + at
At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s upward
Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.
(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:
s = ut + (1/2)at^2
At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.
0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2
0 = 47.864 + (-5.5294)
5.5294 = 47.864
Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.
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Why is impulse and momentum important in sports like cricket??
Answers
==============================
\( \large \sf \underline{Question:}\)
Why is impulse and momentum important in sports like cricket??==============================
\( \large \sf \underline{Answer:}\)
Impulse and momentum are important in sports like cricket because from the word "momentum" it describe itself like you're getting used of it or you know what to do like there's no stopping you.
==============================
How are impulse and momentum related?
brainly.com/question/2193212brainly.com/question/904448==============================
A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?
Answers
The potential energy of the lemming when it lands is 0.9108672 J.
To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
Given:
Mass of the lemming (m) = 0.0780 kg
Height of the cliff (h) = 5.36 m
First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:
PE = mgh
PE = 0.0780 kg * 9.8 m/s² * 5.36 m
PE = 0.413616 J
Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.
Given:
Velocity of the lemming (v) = 4.84 m/s
Calculating the kinetic energy, we have:
KE = (1/2) * 0.0780 kg * (4.84 m/s)²
KE = 0.9108672 J
According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.
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A jet is flying due north relative to the ground. The speed of the jet relative to the ground is 155 m/s . The wind at the jet’s altitude is 40.0 m/s toward the northeast (45.0∘ north of east). Suppose that the +x-axis is directed eastward and the +y-axis is directed northward.
a) Find the speed of the jet relative to the air (its airspeed).
b) Find the direction in which the pilot of the jet must point the plane so that it travels due north relative to the ground. The direction angle is measured from the +x -axis toward the +y -axis.
Answers
The 155 and 40.0 m/s jet speed and wind peed, as well as the due North and North East direction of the jet and wind gives;
a) The airspeed of the jet is approximately 185.45 m/s
b) The pilot must point the jet is at approximately 98.77° measured from the positive direction of the x-axis
What is the airspeed of the jet?The speed is given by the vector sum of the wind speed and the ground speed
a) The speed of the jet relative to the ground = 155 m/s
Direction of the jet = Due North
Wind speed = 40.0 m/s
Wind direction = 45.0° North of East
Required; The airspeed, the speed of the jet relative to the air
Solution;
The velocity of the jet as a vector is presented as follows;
v(jet) = 155•j
The wind velocity, v(wind) = 40×cos(45°)•i + 40×sin(45°)•j
The airspeed is therefore;
v = 40×cos(45°)•i + (155+40×sin(45°))•j
Which gives;
v = 28.28•i + 183.28•j
v ≈ 185.45 m/sb) The resultant direction of the jet is given by the ratio of the coefficients of i and j in the vector form of the resultant velocity as follows;
\( \theta) = arctan \left(\frac{183.28}{28.28} \right) \approx 81.23^{\circ}\)
The direction the pilot of the jet should point the plane is therefore;
90 - 81.23 ≈ 8.77
Given that the jet is tilted due West by approximately 8.77°, the pilot should tilt the plane at approximately 8.77° East of North, which is at an angle of 98.77°, measure from the positive direction of the x-axis
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17. A car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. The car has energy. Calculate it.
Answers
Answer:
89.6 kj
Explanation:
k.e = .5*m*v^2
= .5*1120*(40)^2 = 896000j