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The value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.

Significant figures is a digit that is meaningful with respect to the precision of a measurement.

Significant figures constitutes a digit that is nonzero, followed by a nonzero digit, or (for trailing zeroes) justified by the precision of the derivation or measurement.

According to this question, the following arithmetic expression is given:

15.2 ÷ 4.368 = 3.47985348

Therefore, the value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.

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Answer:

B. Its virtual and behind the mirror.

Explanation:

Answer:  (B) Virutal, (D) Upright, (E) Smaller.  

Explanation:

Edge Physics B

Explanation:

Mathematicians seek and use patterns[8][9] to formulate new conjectures; they resolve the truth or falsity of such by mathematical proof. When mathematical structures are good models of real phenomena, mathematical reasoning can be used to provide insight or predictions about nature. Through the use of abstraction and logic, mathematics developed from counting, calculation, measurement, and the systematic study of the shapes and motions of physical objects. Practical mathematics has been a human activity from as far back as written records exist. The research required to solve mathematical problems can take years or even centuries of sustained inquiry.

Rigorous arguments first appeared in Greek mathematics, most notably in Euclid's Elements.[10] Since the pioneering work of Giuseppe Peano (1858–1932), David Hilbert (1862–1943), and others on axiomatic systems in the late 19th century, it has become customary to view mathematical research as establishing truth by rigorous deduction from appropriately chosen axioms and definitions. Mathematics developed at a relatively slow pace until the Renaissance, when mathematical innovations interacting with new scientific discoveries led to a rapid increase in the rate of mathematical discovery that has continued to the present day.[11]

Mathematics is essential in many fields, including natural science, engineering, medicine, finance, and the social sciences.

The value of force (F) if the change in length of the cable is 7.8 mm is 1500.89 N

The value of the force can be determined by using the young modulus equation that shows the relation between the tensile of the steel cable when the force is applied.

\(\mathbf{\gamma = \dfrac{F/A}{\Delta L/L}}\)

\(\mathbf{\gamma = \dfrac{F} {A }\times \dfrac{L}{\Delta L} }\)

Making the force the subject of the formula and replacing the values, we have:

\(\mathbf{F =\dfrac{A \times \gamma \times \Delta L }{L} }\)

\(\mathbf{F =\dfrac{ \pi \times (3.5 \times 10^{-3}) \times ( 20 \times 10^{10} \ N/m^2 ) \times (7.8 \times 10^{-3}) }{4 \times 10} }\)

\(\mathbf{F =1500.89 \ N }\)

Therefore, we can conclude that the value of force (F) if the change in length of the cable is 7.8 mm is 1500.89 N

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When a heat engine is operating between two temperatures (QH>QC), the maximum efficiency attainable is Carnot efficiency .

Carnot efficiency is the maximum theoretical efficiency of a heat engine, defined as the ratio of the work done by the engine to the heat absorbed from a high temperature source, as described by the Carnot cycle.

It is considered as the most efficient possible cycle for converting heat into useful work, and serves as an upper bound for the efficiency of all heat engines.

The Carnot efficiency is expressed as a function of the temperature difference between the hot and cold sources, and is independent of the working fluid or materials used in the engine.

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A body continues in its state of rest until it is acted upon by an unbalanced external force.

According to Newton's first law of motion, the reason for motion is the action of unbalanced forces. A body will continue in its state of rest or uniform motion unless it is acted upon by an unbalanced  external force. This law also referred to as the law of inertia.

Hence, an object will continue moving uniformly on a plane friction-less surface till the resultant force acting on it is not zero according to this law. Thus, the reason is an explanation for the assertion.

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Answer:

Explanation:

1) No take-off possible

2) The downward force is greater than the upward force.

3)  2000 + 950 = 2950 N upward

Answer:

Frequency= 0.25m

Period= 4.0 secs

Explanation:

Clay is surfing on a wave with a speed of 5.0m/s

The wave crests are 20m apart

Therefore, the frequency of the wave can be calculated as follows

Frequency= wave speed/distance

= 5.0/20

= 0.25m

The period (T) can be calculated as follows

T= 1/frequency

T = 1/0.25

T= 4.0secs

Hence the frequency is 0.25m and the period is 4.0 secs

a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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Let's assume the speed of the boat relative to the water is s.

The time taken for the boat to travel 1.42 km upstream is t1.

The time taken for the boat to travel 1.42 km downstream is t2.

The velocity of the river is v.

Since the speed of the boat relative to the water is constant, we have:

Upstream:

v + s = s + (1.42 km) / t1 = (1.42 km) / t1 km/hr

Downstream:

v - s = (1.42 km) / t2 km/hr

Since the boat takes 75 min for the round trip, we have:

t1 + t2 = 75 min = 1.25 hours

Rearranging the above equations, we have:

v = (1.42 km / t1 - 1.42 km / t2) / 2 km/hr

Substituting t1 + t2 = 1.25 hours, we have:

v = (1.42 km / (1.25 hours - t2) - 1.42 km / t2) / 2 km/hr

Since t2 = 1.25 hours - t1, we have:

v = (1.42 km / (1.25 hours - (1.25 hours - t1)) - 1.42 km / (1.25 hours - t1)) / 2 km/hr

v = (1.42 km / (1.25 hours) - 1.42 km / (2.5 hours - t1)) / 2 km/hr

Finally, solving for t1, we have:

t1 = (1.42 km / v) * 2 km/hr / (1 + (1.42 km / (1.25 hours * v))) hours

So, the flow velocity of the river is v.

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A laser beam that is traveling through air can deliver a maximum power of 1.84 x 106 W.

What is the beam's maximum power output?

The following formula is used to determine the maximum power that an air-propagating laser beam with a diameter of 1.4 cm can deliver:

P = ¹/₂ CεAE₀²

where;

A is the wire's surface area.

C is the permittivity of open space, and is the speed of light.

The largest electric field is E0.

A = πd² / 4

A = π ( 0.014² ) / 4

A = 1.54 x 10⁻⁴ m²

The following calculations are used to determine the laser beam's maximum power:

P is equal to half of (3 x 108 x 8.85 x 1012 x 1.54 x 104) x (3 x 106)2.

P = 1.84 x 10⁶ W

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The maximum power that can be delivered by the laser beam propagating through the air is 1.84 x 10⁶ W.

What is the beam's maximum power output?

The following formula is used to determine the maximum power that an air-propagating laser beam with a diameter of 1.4 cm can deliver:

P = ¹/₂ CεAE₀²

where;

         A is the area of the wire

         C is the speed of light        

         ε is the permittivity of free space

         E₀ is the maximum electric field

We know that,

                     A = πd² / 4

                     A = π ( 0.014² ) / 4

                     A = 1.54 x 10⁻⁴ m²

The maximum power that can be delivered by the laser beam is calculated as follows;

           P = ¹/₂ (3 x 10⁸ x 8.85 x 10⁻¹² x 1.54 x 10⁻⁴) x (3 x 10⁶)²

           P = 1.84 x 10⁶ W

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As a result, at these locations, the cylinder's side-to-side velocity looks to be the slowest. Therefore, it appears that the cylinder has the highest side-to-side motion at these locations.

An acceleration towards the circular path's middle is felt by a body travelling along a circular path at constant speed. A centripetal force produces the acceleration, which is known as centripetal acceleration.

To put it simply, an object moving in a circle at a consistent speed is said to be in uniform circular motion. Although the object is moving at a constant pace, its velocity is changing. Since velocity is a vector,

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To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

Answer:it’s A. right for ape x

Explanation:

Based on data, digital waves are more reliable because they are less likely to change when copied (Option A).

A wave is a periodic distortion capable of traveling through a suitable media (either air or water).

In conclusion, based on data, digital waves are more reliable because they are less likely to change when copied (Option A).

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Answer:

Yes, the object will turn.

Explanation:

The object will turn because there is an net clockwise moment of 5 Nm and an anti-clockwise moment of 10 Nm, resulting in a net clockwise moment of 5 Nm. According to the laws of physics, an object will rotate in the direction of the net torque acting upon it. In this case, the net torque is acting in a clockwise direction, causing the object to rotate in that direction.

Electric potential is the work done in bringing unit positive charge .

Here work(w) is given by

Again

Total change in electric potential energy (V) is given by

Final answer is -0.778J

The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.

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Answer:

Explanation:

b) light

Answer:

the voltage drop across this same diode will be 760 mV

Explanation:

Given that:

Temperature T = 300°K

current \(I_1\) = 100 μA

current \(I_2\) = 1 mA

forward voltage \(V_r\) = 700 mV = 0.7 V

To objective is to find the voltage drop across this same diode  if the bias current is increased to 1mA.

Using the formula:

\(I = I_o \begin {pmatrix} e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}\)

\(I_1 = I_o \begin {pmatrix} e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}\)

where;

\(V_r\) = 0.7

\(I_1 = I_o \begin {pmatrix} e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix}\)

\(I_2 = I_o \begin {pmatrix} e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix}\)

\(\dfrac{I_1}{I_2} = \dfrac{ I_o \begin {pmatrix} e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{ I_o \begin {pmatrix} e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }\)

\(\dfrac{100 \ \mu A}{1 \ mA} = \dfrac{ \begin {pmatrix} e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{ \begin {pmatrix} e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }\)

Suppose n = 1

\(V_T = \dfrac{T}{11600} \\ \\ V_T = \dfrac{300}{11600} \\ \\ V_T = 25. 86 \ mV\)

Then;

\(e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix} e ^{\dfrac{ 0.7} { nV_T} -1} \end {pmatrix}\)

\(e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix} e ^{\dfrac{ 0.7} { 25.86} -1} \end {pmatrix}\)

\(e^{\dfrac{V_r'}{nv_T}-1} = 5.699 \times 10^{12}\)

\({e^\dfrac{V_r'}{nv_T}} = 5.7 \times 10^{12}\)

\({\dfrac{V_r'}{nv_T}} =log_{e ^{5.7 \times 10^{12}}}\)

\({\dfrac{V_r'}{nv_T}} =29.37\)

\(V_r'=29.37 \times nV_T\)

\(V_r'=29.37 \times 25.86\)

\(V_r'=759.5 \ mV\)

\(Vr' \simeq\) 760 mV

Thus, the voltage drop across this same diode will be 760 mV

Answer:

you cant really give any answers because i cant tell u were to drag

The upward component of that force is 1039.23 N.

The parallel component of that force is  600N.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body.

The magnitude of force = 1200 Newtons.

Angle with respect to the ocean = 60°.

The upward component of that force is  = F sin60° = 1200×sin60° N = 1039.23 N.

The parallel component of that force is  = F cos60° = 1200× cos60° N = 600N.

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Given:

Distance = 1.4 m

Force applied = 5 N

Let's find the work done on the mug.

To find the work done, apply the formula:

Work done = Force x Distance

Now, plug in values into the formula:

Work done = 5 x 1.4

Work done = 7 J

Therefore, the work done on the mug is 7 Joules.

ANSWER:

7 J

Answer:

Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow

Explanation:

its basiclly luquid, water vapor, and the form of clouds.