Formaldehyde, CH20, and acetic acid, C2H4O2, have the same empirical formula but different?
kinds of cations.
kinds of atoms.
b. kinds of anions.
d. molecular formulas.

Due to electronegativity difference between H and F atom.

Thus from the above conclusion we can say the difference in electronegativity between H and F atom this is the reason for shorter bond length of HF.

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Answer:

10kg

Explanation:

because matter can not be created or destroyed

The mass of the logs were 10 kg before the fire, the mass of the ash, carbon dioxide and water be after the fire is 10 kg because it follows law of conservation of mass.

The law of conservation of mass has given a statement that mass in a isolated system can neither be created nor destroyed in a chemical reaction or by physical transformation.

It can also be stated the mass can neither be created nor destroyed but it can transformed from one form to another form.

Thus, the mass of the logs were 10 kg before the fire, the mass of the ash, carbon dioxide and water be after the fire is 10 kg because it follows law of conservation of mass.

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In the given reaction: Mg(s) + 2 HCl(aq) → MgCl(s) + H2(g) The correct statement about the reaction is: B) H is the reducing agent because it loses electrons.

Let's break down the given reaction and analyze the oxidation and reduction processes involved.

The reaction is: Mg(s) + 2 HCl(aq) → MgCl(s) + H2(g)

In this reaction, magnesium (Mg) reacts with hydrochloric acid (HCl) to produce magnesium chloride (MgCl) and hydrogen gas (H2).

To determine the oxidizing and reducing agents, we need to identify the species undergoing oxidation and reduction by looking at the changes in their oxidation states.

Oxidation involves an increase in oxidation state, while reduction involves a decrease in oxidation state.

Let's examine the oxidation states of the relevant elements:

Now, let's analyze the reaction:

Mg(s) + 2 HCl(aq) → MgCl(s) + H2(g)

Based on these observations, we can conclude the following:

Therefore, the correct statement is:

B) H is the reducing agent because it loses electrons.

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Traveling in a herd provides wildebeests with several benefits such as reducing the risk of predation, conserving energy, and enhancing mating opportunities.

Traveling in a herd offers different species of animals several benefits, including wildebeests. These benefits include but are not limited to:

Reduced risk of predation: Wildebeests are a prey species, and traveling together in large numbers provides them with group protection from predator attacks. The larger the herd, the more challenging it becomes for a predator to single out an individual wildebeest from the group.

Energy conservation: Traveling in a group allows wildebeests to switch between leaders and followers, enabling them to conserve energy. As they switch positions, the leading position becomes challenging, requiring more energy from those at the front of the group, while followers experience less resistance.

Enhanced mating opportunities: For wildebeests, traveling in a herd allows for greater opportunities for mating. Herds provide a chance for male wildebeests to compete for females. Traveling in herds allows individuals to increase their chances of finding a suitable mate and reduces the likelihood of inbreeding.

Improved resource discovery: A herd can cover a vast area, and the chances of discovering new food and water sources are improved with a group rather than an individual.

Social interaction: Traveling in herds also facilitates social interaction among wildebeests, forming bonds which help with activities like mating, birthing, and caring for offspring.

In conclusion, traveling in herds for wildebeests provide them with several benefits such as reduced risk of predation, energy conservation, enhanced mating opportunities, improved resource discovery, and social interaction. These benefits help wildebeests survive, increase their chances of reproducing, and enhance their overall well-being.

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Answer:

C: 4

Explanation:

In every single covalent bond, each atom shares one electron. 1 + 1 = 2. A double bond is just two bonds so, 2 x 2 = 4.

The term that is NOT a feature of the chemical defense system of bombardier beetles is "The Red Queen Hypothesis."

The Red Queen Hypothesis is a concept in evolutionary biology unrelated to the beetles' chemical defense system. The other options describe various aspects of bombardier beetles' defense system or consequences of it, but The Red Queen Hypothesis does not.

This hypothesis states that organisms must constantly adapt and evolve in order to survive in an ever-changing environment, but it is not related to the chemical defense system of bombardier beetles.

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The amount, in grams, of radon that will be collected in the office sample of air, would be 148.8 grams.

The air sample contains 3.20 x 10⁻⁴ mg of radon per mL of gas. A total air volume of 4.65 x 10⁴ L passed through the office. The amount of radon in the air that passed through the office can be estimated as follow:

Amount of radon per mL of gas = 3.20 x 10⁻⁴ mg

Total volume of air in sample = 4.65 x 10⁴ L

The total air volume needs to be converted to mL:

4.65 x 10⁴ L x 1000 = 4.65 x \(10^7\) mL

1 mL = 3.20 x 10⁻⁴ mg

4.65 x \(10^7\) mL = 4.65 x \(10^7\) x 3.20 x 10⁻⁴

                       = 14.88 x \(10^4\) mg

In other words, the total amount of radon gas in the sample of air is 14.88 x \(10^4\) mg.

1 g = 0.001 mg

14.88 x \(10^4\) mg = 14.88 x \(10^4\)/1000

                        = 148.8 grams

In summary, the total amount of radon gas that will be collected in the office sample would be 148.8 grams.

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The molarity of H2O2 in the reaction mixture is 0.15 M.

The molarity of KI in the reaction mixture is 0.055 M.

The balanced chemical equation for the reaction between hydrogen peroxide (H2O2) and potassium iodide (KI) is:

2 H2O2 + 2 KI → 2 H2O + I2 + 2 KOH

To calculate the molarity of H2O2 in the reaction mixture:

moles of H2O2 = volume of H2O2 x molarity of H2O2

moles of H2O2 = 10.0 mL x 0.75 mol/L

moles of H2O2 = 0.0075 mol

volume of reaction mixture = volume of H2O2 + volume of KI + volume of H2O

volume of reaction mixture = 10.0 mL + 5.0 mL + 35 mL

volume of reaction mixture = 50 mL

molarity of H2O2 = moles of H2O2 / volume of reaction mixture

molarity of H2O2 = 0.0075 mol / 0.050 L

molarity of H2O2 = 0.15 M

Therefore, the molarity of H2O2 in the reaction mixture is 0.15 M.

To calculate the molarity of KI in the reaction mixture:

moles of KI = volume of KI x molarity of KI

moles of KI = 5.0 mL x 0.55 mol/L

moles of KI = 0.00275 mol

molarity of KI = moles of KI / volume of reaction mixture

molarity of KI = 0.00275 mol / 0.050 L

molarity of KI = 0.055 M

Therefore, the molarity of KI in the reaction mixture is 0.055 M.

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Answer:

23

Explanation:

there are 23 pairs of chromosomes

46 individula chromosomes

but each parnet contribute one chromosome to each pair

Answer:

23 :)

Explanation:

Density is typically reported in units of mass per unit volume. To report the density of a solution, it is important to express it with the appropriate units.

In the given scenario, the mass of the liquid is 5.10 g and the volume is 250.0 mL. To calculate the density, divide the mass by the volume: Density = Mass / Volume

Density = 5.10 g / 250.0 mL

However, it is important to note that for consistent units, the volume should be converted to the corresponding unit of volume (e.g., cubic centimeters, liters) before calculating density. In this case, 250.0 mL is equal to 250.0 cm³ or 0.250 L.

Now, we can calculate the density:

Density = 5.10 g / 0.250 L

To report the density, it should be expressed as a final value with the appropriate units. In this case, the density would be reported as, for example, 20.4 g/cm³ or 20.4 g/mL.

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Triphenyl stereochemistry.  methanol is the product of the Grignard reaction between methyl benzoate and excess phenylmagnesium bromide.

We will have a reduction reaction in this case. We progress from an ester group to an alcohol group. The first step is to transfer a hydride from the LiAlH4 group to the carbonyl group. The ethyl group then separates to form ethanol and an aldehyde, which continues to react with more LiAlH4. In this case, another hydride is transferred to the carbonyl group, resulting in the formation of alcohol. (See Fig.)

Triphenyl methanol is the stereochemistry product of the Grignard reaction between methyl benzoate and excess phenylmagnesium bromide.

As the carbonyl moiety is attacked, the reaction proceeds via nucleophillic reaction. There is the formation of a tetrahedral intermediate. The attack of the first molecule of PhMgBr is accompanied by the loss of the -OMe group.

Trimethyl phenoxide is produced by the attack of a second PhMgBr molecule. Protonation

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When NaOH is added to water, it dissociates into Na+ and OH- ions. The OH- ions react with the H+ ions present in water, leading to an increase in the OH- ion concentration and a decrease in the H+ ion concentration. This results in a basic solution with a higher pH value. Therefore, the [H+] concentration decreases as more NaOH is added to water.

NaOH is a strong base, and when it is added to water, it dissociates completely into Na+ and OH- ions. These ions can react with the water molecules present in the solution to form hydroxide ions and hydronium ions. The reaction can be represented as follows: NaOH + H2O → Na+ + OH- + H2O The OH- ions produced in the reaction react with the H+ ions present in water, leading to the formation of water molecules. The reaction is given below: OH- + H+ → H2O As a result of this reaction, the concentration of H+ ions decreases in the solution. This decrease in the [H+] concentration causes the pH value of the solution to increase, making it more basic.

The pH value of a solution is a measure of its acidity or basicity, and it is defined as the negative logarithm of the hydrogen ion concentration [H+]. A solution with a pH value of less than 7 is considered acidic, while a solution with a pH value greater than 7 is basic. The pH scale is logarithmic, which means that a change in one pH unit represents a tenfold change in the [H+] concentration. When NaOH is added to water, the [H+] concentration decreases while the [OH-] concentration increases. The concentration of [H+] and [OH-] ions in a solution are related by the equation Kw = [H+][OH-], where Kw is the ion product constant of water (1 x 10^-14 at 25°C). Therefore, as [OH-] concentration increases, [H+] concentration decreases to maintain the equilibrium constant Kw. This relationship between [H+] and [OH-] ions in a solution is the basis of the pH scale and the acidity and basicity of solutions.
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Answer:

if you want to protect our ozone depletion you have aerosol products that don't contain HCFCs and CFCs as stimulus or incitement

Explanation:

why you should use aerosol because when the liquid mixture is freeded or released from the aerosol the liquid propellant becomes a gas so this can easily break up the product into a fine haze or a mist hope its helpful have a good luck

Answer:

This relationship between temperature and pressure is observed for any sample of gas confined to a constant volume. I find that temperature and pressure are linearly related. If the temperature on the kelvin scale increases by a certain factor, the gas pressure increases by the same factor. On the can is the warning “Store only at temperatures below 120 °F (48.8 °C). Do not incinerate.” The can contains an amount of isobutane gas at a constant volume, so if the temperature increased by heating, the pressure will increase proportionately. High temperature could lead to high pressure, causing the can to burst. Just like,  The gas in the can is initially at 24°C,  and the can has a volume of 350 mL.  If we fill a balloon with air and seal it,  If we put the balloon in a refrigerator, the gas inside gets cold and the balloon shrinks. If we make the balloon very cold, it will shrink a great deal, and it expands again when it warms up. Temperature is sometimes measured with a gas thermometer by observing the change in the volume of the gas as the temperature changes at constant pressure. A volume change caused by a temperature change at constant pressure means we should use Charles’s law. Decreasing the volume of a contained gas will increase its pressure, and increasing its volume will decrease its pressure. In fact, if the volume increases by a certain factor, the pressure decreases by the same factor, and vice versa.  The earth’s atmosphere exerts a pressure, as does any other gas. Although we do not normally notice atmospheric pressure, we are sensitive to pressure change, for example, when your ears “pop” during take off and landing while flying, or when you dive underwater.  Although the force of each collision is very small, any surface of appreciable area experiences a large number of collisions in a short time, which can result in a high pressure. In fact, normal air pressure is strong enough to crush a metal container when not balanced by equal pressure from inside the container.  Atmospheric pressure is caused by the weight of the column of air molecules in the atmosphere above an object, such as the tanker car. At sea level, this pressure is roughly the same as that exerted by a full-grown African elephant standing on a doormat, or a typical bowling ball resting on your thumbnail. These may seem like huge amounts, and they are, but life on earth has evolved under such atmospheric pressure. If you actually perch a bowling ball on your thumbnail, the pressure experienced is twice the usual pressure, and the feeling is unpleasant.

Explanation:

A contained gas's pressure rises as its volume decreases, while its pressure falls as its volume rises. In fact, if the volume increases by a certain factor, so does the pressure, and vice versa. The earth's atmosphere, like any other gas, exerts pressure.

Boyle's Law describes the relationship between pressure and volume. The volume of a gas decreases as the pressure on it increases because the gas particles are forced closer together. As the pressure on a gas decreases, the volume of the gas increases because the gas particles can now move farther apart.

As a result, volume is inversely proportional to pressure. A straight line is obtained by plotting pressure (p) against the reciprocal of volume (1/V), the gradient of which is the constant in Boyle's Law. The number of gas particles per unit volume increases as volume decreases.

The pressure-volume relationship of a confined gas is inversely proportional. This relationship is demonstrated by the data collected and the graphs plotted.

Thus, A contained gas's pressure rises as its volume decreases, while its pressure falls as its volume rises.

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Answers and explanations:

1) Lead, it is heavier than iron.

2) Lead, since it's heavier, it would have more mass and therefore more atoms.

3) (for sodium) 82.03379 gram x 6.23= 511.070512 grams= 417.05 pounds

(for sucrose) 342.29648(one molar)  x .65= 0.4 pound

The sodium would be heavier (not sure if accurate)

4) Because atoms are way too small to count, therefore we use molar masses.

The equation can be simplified as: ln (1 atm/100 mmHg) = ΔHvap/R * (1/294.2 K - 1/347.2 K)Rearranging and solving for ΔHvap:ΔHvap = -R * (1/294.2 K - 1/347.2 K) * ln (1 atm/100 mmHg)ΔHvap = 24.7 kJ/mol Therefore, the enthalpy of vaporization of PCl3 is 24.7 kJ/mol.

Vapor pressure of PCl3 at 21 degrees Celsius is 100 mmHg and its normal boiling point is 74.2 Celsius. Vapor pressure is defined as the partial pressure of a vapour in dynamic equilibrium with its liquid or solid form. The vapor pressure of PCl3 is 100 mmHg at 21 degrees Celsius and its normal boiling point is 74.2 Celsius. Vapor pressure is directly proportional to temperature. As the temperature rises, vapor pressure also rises.

Normal boiling point is defined as the temperature at which the vapor pressure of the liquid is equal to the external pressure on the liquid.

At this temperature, the liquid will change to a gas state or vapor.

The vapor pressure of PCl3 at its normal boiling point can be calculated using the Clausius-Clapeyron equation: ln (P2/P1) = ΔHvap/R * (1/T1 - 1/T2)Where:P1 = vapor pressure at temperature T1P2 = vapor pressure at temperature T2ΔHvap = enthalpy of vaporization R = ideal gas constantT1 = initial temperatureT2 = final temperature At the boiling point of PCl3, the vapor pressure will be 1 atm.

Therefore, the equation can be simplified as: ln (1 atm/100 mmHg) = ΔHvap/R * (1/294.2 K - 1/347.2 K)Rearranging and solving for ΔHvap:ΔHvap = -R * (1/294.2 K - 1/347.2 K) * ln (1 atm/100 mmHg)ΔHvap = 24.7 kJ/mol Therefore, the enthalpy of vaporization of PCl3 is 24.7 kJ/mol.

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A buffer solution is made by mixing 375 ml of 0.25 m hf and 225 ml of 0.50 m naf. The ph of:

the original buffer solution is: 3.24,

the solution after adding 0.018 mol of KOH to the original buffer solution is: 9.85,

the solution after adding 12.5 ml of 1.25 m HI to the original buffer solution is 0.88.

A buffer solution is created by combining a weak acid and its conjugate base, which together maintain a relatively constant pH despite the addition of small amounts of acid or base. In this question, 375 mL of 0.25 M HF and 225 mL of 0.50 M NaF are mixed together to form the buffer solution.

The pH of the original buffer solution can be calculated using the Henderson-Hasselbalch equation, which states that \(pH = pKa + log([A-]/[HA]).\)

In this case, [A-] is the concentration of the conjugate base (NaF) and [HA] is the concentration of the weak acid (HF). Plugging in the values given, the pH of the original buffer solution is 3.24.

After adding 0.018 moles of KOH to the original buffer solution, the pH can be calculated using the same Henderson-Hasselbalch equation. Since KOH is a strong base, the concentration of the conjugate base (NaF) increases and the concentration of the weak acid (HF) decreases. Plugging in the values, the pH of the solution after the addition of KOH is 9.85.

After adding 12.5 mL of 1.25 M HI to the original buffer solution, the pH can be calculated using the Henderson-Hasselbalch equation. Since HI is a strong acid, the concentration of the conjugate base (NaF) decreases and the concentration of the weak acid (HF) increases. Plugging in the values, the pH of the solution after the addition of HI is 0.88.

In conclusion, the original buffer solution had a pH of 3.24, the solution after the addition of 0.018 moles of KOH had a pH of 9.85, and the solution after the addition of 12.5 mL of 1.25 M HI had a pH of 0.88.

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The reaction represented by the equation CH_4 + 2 O_2 → CO_2 + 2H_2O is a combustion reaction.

A combustion reaction is a type of chemical reaction in which a substance reacts with oxygen to produce heat and light. In this case, methane (CH_4) is reacting with oxygen (O_2) to produce carbon dioxide (CO_2) and water (H_2O).

Combustion reactions are typically exothermic, meaning they release energy in the form of heat and light. They are often accompanied by a flame and are commonly observed in processes such as burning of fuels, such as natural gas, gasoline, or wood.

In this specific reaction, methane (CH_4) is the fuel that undergoes combustion, combining with oxygen (O_2) to form carbon dioxide (CO_2) and water (H_2O). The coefficients in front of the molecules indicate the stoichiometric ratio, showing that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.

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High-quality scientific research is characterized by several key criteria. Three examples of such criteria include: rigorous experimental design and methodology, reliable data analysis and interpretation, and clear and transparent reporting of results.

These criteria ensure that research is conducted in a systematic and reliable manner, leading to trustworthy and valid findings.

Rigorous Experimental Design and Methodology: High-quality scientific research requires a well-designed experimental approach. This involves careful planning, proper control groups, randomization, and replication. A rigorous methodology ensures that experiments are conducted under controlled conditions, minimizing bias and confounding variables, and allowing for accurate and reliable data collection.

Reliable Data Analysis and Interpretation: After data collection, high-quality research involves thorough and appropriate analysis of the data. This includes using appropriate statistical methods to evaluate the significance of the results and drawing valid conclusions. Proper data analysis helps researchers identify patterns, trends, and relationships, supporting or refuting their hypotheses in an objective and reliable manner.

Clear and Transparent Reporting of Results: High-quality research demands transparent reporting of the methods, procedures, and findings. This includes providing detailed descriptions of the experimental setup, data collection processes, and statistical analyses used. Clear reporting allows other researchers to replicate the study and verify its results. Additionally, complete reporting ensures that readers can understand the research methodology and draw their own conclusions based on the evidence presented.

By adhering to these criteria, high-quality scientific research maintains integrity, credibility, and reproducibility. It fosters trust among the scientific community and facilitates the advancement of knowledge by building upon reliable foundations.

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The rate at which the volume is changing, represented as dV/dt, is given by the equation (0.4155 - 0.32V(t)) / 16, where V(t) is the volume, and the values are substituted accordingly.

To find the rate at which the volume is changing, we need to differentiate the given equation with respect to time (t) using the chain rule:

PV = 8.31T

Differentiating both sides with respect to time:

P(dV/dt) + V(dP/dt) = 8.31(dT/dt)

We are given:

dT/dt = 0.05 K/s (rate of temperature change)

(dP/dt) = 0.02 kPa/s (rate of pressure change)

P = 16 kPa (initial pressure)

T = 295 K (initial temperature)

Substituting the given values into the equation, we have:

16(dV/dt) + 16V(0.02) = 8.31(0.05)

Simplifying the equation:

16(dV/dt) + 0.32V = 0.4155

Rearranging the equation to solve for dV/dt:

16(dV/dt) = 0.4155 - 0.32V

(dV/dt) = (0.4155 - 0.32V) / 16

To find the rate at which the volume is changing when T = 295 K, we substitute V = V(t) and T = 295 into the equation:

(dV/dt) = (0.4155 - 0.32V(t)) / 16

Calculating the value of (dV/dt) at the given temperature and rounding to at least 4 decimal places will provide the final answer.

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Answer: a) arsenic

Explanation:

answer:

a. arsenic

explanation:

arsenic is classified as a metalloid because it has some properties similar to a metal and others of a non-metal.

good luck :)

hopefully, this helps

have a great day !!

Answer: D. a mixture

Explanation: When you mix different types of nuts or snacks together including raisins, hazelnuts, almonds, and peanuts to make some kind of trail mix, then you are creating a mixture, specifically a heterogeneous mixture.

Given what we know, we can confirm that a general (all-inclusive) term for organic molecules that have the same molecular formula, but that differ in their structure or in the spatial arrangement of their atoms is isomers.

Therefore, we can confirm that the general (all-inclusive) term for organic molecules that have the same molecular formula, but that differ in their structure or in the spatial arrangement of their atoms is isomers.

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To solve this problem, we need to use the formula: moles of electrons = (current × time) / (charge of one electron × Faraday's constant). So, approximately 7.46 × 10^-4 mol of electrons travel through the copper wire during the 118 seconds.

First, let's convert the current to units of Amperes:
610. mA = 0.610 A
Next, we need to know the charge of one electron, which is -1.602 × 10^-19 Coulombs.
Finally, we need to know Faraday's constant, which is 96,485 Coulombs per mole of electrons.
Now, we can plug in the values and solve for moles of electrons:
moles of electrons = (0.610 A × 118 s) / (-1.602 × 10^-19 C × 96,485 C/mol)
moles of electrons = 4.48 × 10^18
Be sure to round your answer to three significant digits and include the correct unit symbol for moles of electrons, which is "mol e^-":
moles of electrons = 4.48 × 10^18 mol e^-

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The concentration of this magnesium chloride solution when the reaction described in part a required 3.92 l of magnesium chloride is 0.451 M

M(AgNO3)=0.18 M

V(AgNO3)=1.92 L

V(MgCl2)=3.83 L

According to the balanced reaction:

We can write as follows;

1*number of mol of AgNO3 =2*number of mol of MgCl2

1*M(AgNO3)*V(AgNO3) =2*M(MgCl2)*V(MgCl2)

1*0.18*1.92 = 2*M(MgCl2)*3.83

M(MgCl2) = 0.0451 M

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The volume of dry carbon dioxide is 55mL measured at 25 degrees Celsius and 785 mm hg, will result from the combustion of 2.50 g of pentane.

Carbon dioxide may be found in solid form as dry ice. Since CO2 does not have a liquid state at normal atmospheric pressure and instead sublimates directly from the solid state to the gas state, it is frequently used for short-term refrigeration. In addition to being utilised in fog machines in theatres for dramatic effects, it is largely employed as a cooling agent.

Its benefits include being colder than water ice and leaving no traces behind (apart from accidental frost from atmospheric moisture). It is helpful for keeping frozen items (like ice cream) from spoiling in situations when mechanical chilling is not possible.

At Earth's atmospheric pressure, dry ice sublimates at 194.7 K (78.5 °C; 109.2 °F). The solid is hazardous to handle without protection against frostbite injuries because to the intense cold. While typically not very toxic, the buildup in confined spaces can make the outgassing from it hypercapnic (abnormally elevated blood carbon dioxide levels).

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Answer: its D

Explanation:

because the earth sun and moon are all lined up that will cause a solar eclipse.

When you raise and push down the pressure pump handle, you are adding more gas molecules to the container.

When you click on the bucket to raise the temperature of the container, the pressure of the gas increases.

When you click on the bucket to reduce the temperature of the container, the pressure of the gas decreases.

The gas law that mathematically shows the relationship between temperature and pressure is known as the ideal gas law. The ideal gas law is represented by the equation: PV = nRT

where:

P is the pressure of the gas,

V is the volume of the gas,

n is the number of moles of the gas,

R is the ideal gas constant, and

T is the temperature of the gas in Kelvin.

According to the ideal gas law, when the volume is kept constant (as mentioned in the simulation), the relationship between temperature and pressure is directly proportional. This means that if the temperature increases, the pressure will also increase, and if the temperature decreases, the pressure will decrease.

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Answer:Click on the bucket to raise the temperature of the container to approximately 400 K (127°C). What happened to the pressure?

✔ increased

Approximately what pressure range did you observe?

✔ 7.5–8.3 atm

3. Click on the bucket to reduce the temperature to approximately 200 K (−73°C). What happened to the pressure?

✔ decreased

Approximately what pressure did you observe?

✔ 3.5–4.3 atm

4. What gas law mathematically shows the relationships between temperature and pressure?

✔ Gay-Lussac’s law

Explanation: