An object with an initial velocity of 53 m/s has a final velocity of 77 m/s after 78 seconds. What is the object's acceleration?
Given:
The initial velocity of the object is
\(v_i\text{ = 53 m/s}\)The final velocity of the object is
\(v_f=\text{ 77 m/s}\)The time taken by the object is t = 78 s
To find the object's acceleration.
Explanation:
The object's acceleration can be calculated as
\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ =\frac{77-53}{78} \\ =0.308\text{ m/s}^2 \end{gathered}\)The acceleration of the object is 0.308 m/s^2
Question 8 (1 point)
The height from the trough to the crest of an ocean wave is 9 m. What is the
amplitude of the wave?
The amplitude of an ocean wave is half the height from the trough to the crest of the wave. Therefore, if the height from the trough to the crest of an ocean wave is 9 m, then the amplitude of the wave is:
amplitude = height / 2 = 9 m / 2 = 4.5 m
Therefore, the amplitude of the wave is 4.5 m.
How can I measure wavelength?Wavelength can be measured by measuring the distance between two consecutive points on a wave that are in phase with each other. For example, if you measure the distance between two consecutive peaks or two consecutive troughs of a wave, you can determine the wavelength of the wave. Wavelength is typically measured in meters (m) or some multiple or fraction of meters such as centimeters (cm) or nanometers (nm).
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A badminton shuttlecock leaves the racquet traveling 30 m/s. It goes over the net 0.5
seconds later with a speed of 10 m/s. Calculate its average acceleration.
Given :
A badminton shuttlecock leaves the racquet traveling 30 m/s.
It goes over the net 0.5 seconds later with a speed of 10 m/s.
To Find :
The average acceleration of the shuttlecock.
Solution :
We know, average acceleration(a) is given by :
\(a = \dfrac{\text{Change in speed}}{\text{Time taken }}\\\\a = \dfrac{10-30}{0.5 }\ m/s^2\\\\a = -40\ m/s^2\)
Therefore, the average acceleration is -40 m/s².
Compare the movement of four cars. Car A covered a distance of 60 km in 1hr.
Car B covered a distance of 30 km in 30 minutes. Car C covered a distance of 20
km in 15 minutes, Car D covered a distance of 10 km in 7 minutes, which car had
the highest velocity?"
Answer:
car D
Explanation:
1) before to compare all the values of the velocities, they must be in the same units of measurement. It means:
for car A: V=60km / 1h=60km/h;
for car B: V=30km / 0.5h=60km/h;
for car C: V=20km / 0.25h=80km/h;
for car D: V=10km / (7/60)h≈85.7km/h.
2) according to the values calculated in item 1 the car D had the highest velocity.
Answer:
Below
Explanation:
We can use this formula to find the velocity of an object
velocity = displacement / change in time
*note I converted all distances to meters and all times to seconds, its not necessary though**
CarAvelocity = 60,000 m / 3600 sec
= 16.66667 m/s
CarBvelocity = 30,000 m / 1800 sec
= 16.66667 m/s
CarCvelocity = 20,000 m / 900 sec
= 22.2222 m/s
CarDvelocity = 10,000 m / 420 sec
= 23.80952 m/s
Therefor, car D has the highest velocity
Hope this helps!
HELP PLEASE THIS IS URGENT!!!
The neutron number of an atom X, which undergoes alpha, and beta decay reduces the neutron number by 6.
Alpha decay is the nuclear process in which the parent nucleus emits an alpha or helium particle to form a daughter nucleus. When a particle emits an alpha nucleus, the nucleus loses its two protons and two neutrons. Beta decay is the nuclear process in which the parent nucleus undergoes the emission of electrons to produce a daughter nucleus.
Alpha decay decreases the atomic mass number decreases by 4 and the atomic number decreases by 2. In beta decay, the neutron is converted into a proton and the atomic number decreases by one. The neutron number is affected by alpha decay.
From the given,
X atom undergoes alpha decay. X -----> ₐ₋₂Xᵇ⁻⁴ + He₂⁴. The neutron number decreases by two. ₐ₋₂Xᵇ⁻⁴ -----> ₐ₋₂₋₂Xᵇ⁻⁴⁻⁴ + He₂⁴. The neutron number decreases by two.
When the X atom undergoes beta decay, ₐ₋₄Xᵇ⁻⁸---> ₐ₋₅Xᵇ⁻⁸ + ₋₁e⁰. The neutron number does not get affected. When the atom again undergoes alpha decay, ₐ₋₅Xᵇ⁻⁸ -----> ₐ₋₇Xᵇ⁻¹². Thus, the neutron number decreases by 6 when the atom undergoes three alpha decay.
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The diagram shows the electric field lines due to two charged parallel metal plates. We conclude
that:
a.
an electron at X could have its weight balanced by the electrical force
b.
a proton at X experiences a greater force than if it were placed at Z
c.
the upper plate is positive and the lower plate is negative
d.
a proton at X experiences less force than if it were placed at Z
e.
a proton at X would experience the same force if it were placed at Y
Based on the given diagram, we can only reasonably conclude statement c, that the upper plate is positive and the lower plate is negative
What is Electric Field?
Electric field is a concept used in physics to describe the influence that an electric charge exerts on other charges in its vicinity. It is defined as the force experienced by a positive test charge placed in the vicinity of an electric charge, divided by the magnitude of the test charge
The upper plate is positive and the lower plate is negative: This statement is a common convention for charged parallel metal plates in a capacitor. The positive plate is usually considered as the plate with electric field lines originating from it (in this case, the upper plate), and the negative plate is usually considered as the plate with electric field lines terminating on it (in this case, the lower plate). So, this statement is likely to be true based on convention.
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Does this mean Acceleration???
brandon is playing softball
Answer:
lets go brandon!
Explanation:
A plane is flying horizontally with speed
162 m/s at a height 3970 m above the ground,
when a package is dropped from the plane.
2
Neglecting air resistance, when the package hits the ground, the plane will be
1. directly above the package. 2. ahead of the package.
3. behind the package.
Answer:
2. ahead of the package.
Explanation:
Using y' - y = ut - 1/2gt², we find the time, t it takes the package to hit the ground. So, u = initial vertical velocity of package = 0 m/s, y = initial position of package = 3970 m, y' = final position of package = 0 m, g = acceleration due to gravity = 9.8 m/s².
Substituting the variables into the equation, we have
y' - y = ut - 1/2gt²
0 m - 3970 m = 0t - 1/2 × (9.8 m/s²)t²
-3970 m = -(4.9m/s²)t²
t² = -3970 m ÷ -4.9 m/s²
t² = 810.2 s²
t = √810.2 s²
t = 28.5 s
Using v = u' + at, we find the horizontal acceleration of the plane. Since the initial horizontal velocity of the package is that of the plane, u' = 162 m/s, v = 0 m/s since the package stops and t = 28.5 s when the package stops.
So, a = (v - u')/t
a = (0 m/s - 162 m/s)/28.5 s
a = -162 m/s/28.5 s
a = -5.68 m/s²
Using v² = u'² + 2as, we find the horizontal distance ,s where the package stops.
So, s = (v² - u'²)/2a
Substituting the values of the variables, we have
s = ((0 m/s)² - (162 m/s)²)/(2 × -5.68 m/s²)
= - 162 m²/s²/(-11.36 m/s²)
= 14.26 m
The horizontal distance d the plane moves after releasing the package is d = u't = 162 m/s × 28.5 s = 4617 m
Since d = 4617 m > s = 14.26 m, the plane would be ahead of the package when the package hits the ground.
Which heart rate zones are generally anaerobic in nature?
Answer:
Below
Explanation:
Not sure what numbers you have been taught to use, but heart rates (BPM) above 80% of your maximum heart rate is anaerobic
your approximate Max heart rate = ( 220 - age in years)
so if you are 20 y/o max = 220 - 20 = 200 bpm
80% of this is 160 beats per min <===above this is anaerobic
Revlew Millikan's Photoelectric Experiment Robert A. Mlkan (1868 1953). although best known for his "oil-drop experiment," which measured the charge of an electron, also perfomed pioneering research on the photoelectric effect. In experiments on lithium, for example, Millikan observed a maximum kinetic energy of 0.550 eV when electrons were ejected with 433.9-nm light. When light of 253.5 m was used, he observed a maximum kinetic energy of 2.57 eV.
Part A What is the work function,W, for lithium, as determined from Milikan's results? Express your answer to three significant figures and include appropriate units.
Part B What maximum kinetic energy do you expet illikan found when he used light with a wavelength of 362.4 TIm? Express your answer to three significant figures and include appropriate units Value Units
Answer:
A.) Work function = 2.3 eV
B.) Max. K.E observed = 1.1 eV
Explanation:
A.) Millikan observed a maximum kinetic energy of 0.550 eV when electrons were ejected with 433.9-nm light. When light of 253.5 m was used, he observed a maximum kinetic energy of 2.57 eV.
work function (f) is the minimum energy required to remove an electron from the surface of the material.
hf = Ø + K.E (maximum)
Where
h = Plank constant 6.63 x 10-34 J s
Ø = work function
hc/λ = Ø + K.E (max)
(6.63×10^-34 × 3×10^8)/433.9×10^-9 = Ø + 0.550 × 1.6×10^-19
4.58×10^-19 = Ø + 8.8×10^-20
Ø = 4.58×10^-19 - 8.8×10^-20
Ø = 3.7 × 10^-19 J
Converting Joule to eV
Ø = 3.7 × 10^-19/1.6×10^-19
Ø = 2.3 eV
B.) When light of wavelength 362.4 m is used
The maximum K.E observed = incident light K.E - (the work function).
Incident K.E = hf = hc/λ
Incident K.E =
(6.63×10^-34 × 3×10^8)/362.4
Incident K.E = 5.5 × 10^-28J
Let's convert joule to eV
Incident K.E = 5.5×10^-28/1.6×10^-19
Incident K.E = 3.4 × 10^-9
Max. K.E observed = 3.4 - 2.3
Max. K.E observed = 1.1 eV
WILL MARK BRANLIEST!!!!!
13. Rank the following stars in order from brightest (1) to dimmest (6) using apparent magnitude.
Vega
Archenar
Arcturus
Hadar
Canopus
Procyon
Here is the correct ranking of the stars in order from brightest (1) to dimmest (6) using apparent magnitude:
1-Vega
2- Arcturus
3- Canopus
4- Procyon
5- Hadar
6- Archenar
Apparent magnitude is a measure of the brightness of a star as seen from Earth. It is a logarithmic scale, where a lower apparent magnitude indicates a brighter star and a higher apparent magnitude indicates a dimmer star. Vega is the brightest of these stars, with an apparent magnitude of about 0.0, while Archenar is the dimmest, with an apparent magnitude of about 3.8. The other stars fall somewhere in between these two extremes.
1-Vega
2- Arcturus
3- Canopus
4- Procyon
5- Hadar
6- Archenar following stars in order from brightest (1) to dimmest (6) using apparent magnitude.
Which star is the one that is closest to Earth?The Alpha Centauri triple-star system, which is just 4.37 light-years or 40 trillion kilometres distant from the Earth, is the closest star system to it. Three stars called Alpha Centauri A, Alpha Centauri B, and Proxima Centauri make up the Alpha Centauri triple-star system.
An uncomplicated rendering of the star Achernar. It is flattened because, although being 6–8 times as big as our sun, it rotates or spins on its axis at a rate that is 15 times faster, taking 2 Earth days to complete one rotation as opposed to the sun's 25 days.
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Find the current flowing out of the battery.
Answer:
5A
Explanation:
An owl accidentally drops a mouse it is carrying, while flying horizontally at a speed of 16.0 m/s. The mouse drops to the ground 15.0 m below. What is the impact speed with which the mouse hits the ground?
The impact speed of the mouse is 23.3 m/s as per the data given in the question.
What is velocity?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
To solve for the impact speed, we can use the following equation:
\(v^2 = u^2 + 2as\)
Where:
v = impact speed,
u = initial speed (which is the horizontal speed of the owl),
a = acceleration due to gravity (9.8 m/\(s^2\)), and
s = vertical distance fallen (15.0 m).
Substituting the known values, we get:
\(v^2 = 16.0^2 + 2 X 9.8 X 15.0\)
\(v^2\) = 256 + 294
\(v^2\) = 550
v = sqrt(550 )
v = 23.3 m/s
Thus, the impact speed of the mouse is 23.3 m/s.
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if a satellite travels 62,000,000 miles from earth, how can we write it in scientific notation
Answer:
6.2 x 10^6
Explanation:
The 6 at the end is an exponent the carrot is the symbol
Answer:
6.2*10^7 miles
Explanation:
1.What is the heat energy needed to change 36g of water 8.0°C to 34.0°C?2. What is the amount of heat necessary to melt 34kg of ice at 0.0 °C to water at 0.0 °C?
1)
Answer:
3912.48 J
Explanation:
The formula for calculating the quantity of heat is expressed as
H = mcθ
where
m is the mass of the substance
c is the specific heat capacity of the substance
θ is the change in temperature of the substance
From the information given,
m = 36
initial temperature = 8
final temperature = 34
θ = 34 - 8 = 26
c = 4.18J/g/C
By substituting these values into the formula,
H = 36 x 4.18 x 26
H = 3912.48 J
Quantity of heat energy needed = 3912.48 J
an ac generator is connected across the terminals of a 3.25-µf capacitor. determine the frequency at which the capacitive reactance is 375 ω.
The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.
Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).
From the given,
The capacitive reactance (Xc) = 375ω
capacitance (C) = 3.25μF
capacitive reactance Xc = 1/(2π×f×C)
Frequency (f) = 1/(2π×Xc×C)
= 1/(2×3.14×375×3.25×10⁻⁶)
= 131 s⁻¹.
Thus, the frequency of the capacitive reactance is 131 s⁻¹.
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Smita is experimenting with how a paper airplane's shape affects the distance it will fly. Which action is the result of her logical reasoning? A. She records only the data that support her favorite hypothesis. B. She follows her procedure carefully. C. She decides to perform the experiment outside on a windy day. D. She decides to use the same type of paper for each airplane.
Answer:
So, the answer is eather B or D.
Explanation:
It could be b because she needs to make sure everything is good but it could be d because yopu need to keep everything the same. I personally would go d
Two identical positive charges exert a repulsive force of 6.4x10^-9 N when separated by a distance of 3.8x10^10 m. Calculate the charge of each.
Answer:F = kq2/d2 ⇒
q = √(Fd2/k)
q = d √(F/k)
d = 3.8 x 10-10 m
F = 6.4 x 10-9 N
Look up k in your physics book in appropriate units, and plug in the numbers. You should get q in coulombs.
Explanation:
The value of each charge will be 1.64 ×10⁻⁴. The concept of the columb force is used.
What is the charge?When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.
Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.
\(\rm F =K \frac{q_1Q_2}{d^2} \\\\ F = K\frac{q^2}{d^2} \\\\ q = \sqrt{\frac{dF}{k} } \\\\ q = \sqrt{\frac{3.8 \times 10^{10}\times 6.4 \times 10^{-9}}{9 \times 10^9} } \\\\ q=1.64 \times 10-4\)
Hence the value of each charge will be 1.64 ×10⁻⁴. The concept of the columb force is used.
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If the magnification is -4 then is the image larger or smaller and is it inverted or upright
If the magnification is -4 the the image is larger and is it inverted in nature.
The magnification of the body is given is -4, here the signs show the nature of the image and the numerical value is the times to which the object has been magnified. Here, it is inverted because there is negative sign and it is enlarged as the magnification is more than 1.
Therefore, a magnification of -4 indicates that the image is both inverted and larger than the object. The resultant picture will be a larger, inverted version of the object if it is seen via a lens or mirror with a magnification of -4.
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a guitar string vibrates producing a sound wave with a wavelength of 2 meters if sound moves through air at the moves at 343 per second what was the waves frequency
The frequency of the sound wave produced by the guitar string is 171.5 Hz.
The speed of a wave is the rate at which a wave propagates through a medium, which means the distance traveled by a wave per unit time. It is denoted by the letter "v" and is usually measured in meters per second (m/s) or feet per second (ft/s).
The speed of a wave depends on the properties of the medium through which it travels, such as its density, elasticity, and temperature. For example, sound waves travel at different speeds through different materials, like air, water, or solids. In general, waves travel faster through denser and more elastic mediums.
The speed of a wave can also be calculated using the formula:
v = f * λ
where "v" is the speed of the wave, "f" is its frequency, and "λ" is its wavelength. This formula relates the speed of a wave to its frequency and wavelength, and it is applicable to all types of waves, including sound waves, light waves, and water waves.
The speed of sound in air is 343 meters per second, and the wavelength of the sound wave produced by the guitar string is 2 meters. We can use the formula:
frequency = speed of sound/wavelength
Plugging in the values, we get:
frequency = 343 / 2 = 171.5 Hz
Therefore, the frequency of the sound wave produced by the guitar string is 171.5 Hz.
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John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. The rope makes an angle of 25 with the ground He is pulling horizontally with a constant force of 400 N. John and manages to get the sled going from 0 to 4 m/s in 5 s. The force due to friction on the sled is 310 N. What is the mass of Laura and the sled combined
Why did vygotsky believe that children were more dependent learners
Answer:
Vygotsky's sociocultural theory asserts that learning is an essentially social process in which the support of parents, caregivers, peers and the wider society and culture plays a crucial role in the development of higher psychological functions.
Thus, Vygotsky believed that children were more dependent learners
Please see the attached image
The moment of inertia of the flat square is MA²/6
What is moment of inertia?The moment of inertia of a body is a property of the body which shows its ability to ritate about an axis.
What is the moment of inertia of the flat square?To find the moment of inertia of the flat square through its center of mass, we know that the moment of inertia of a rectangular slab is given by
I = M(a² + b²)/12 where
M = mass of slab and a and b = side lengthsNow, for a flat square a = b. so,its moment of inertia is I = M(a² + b²)/12
I = M(a² + a²)/12
= 2Ma²/12
= Ma²/6
Now for the given flat square, we have that
its mass equals M and its length equals A.So, substituting these into the equation of moment of inertia for the flat square, we have that
The moment of inertia of the flat square is given by
I = Ma²/6
I = MA²/6
So, moment of inertia is MA²/6
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3 A ball of mass 0.5 kg has 100 J of kinetic energy. What
is the speed of the ball? plzz help
Answer:
20meter/second
Explanation:
v=squareroot of 2×K.E/mass
v=squareroot of 2×100J/0.5
v=squareroot of 200kg×m×m/s×s/0.5m
v=squareroot of 400m×m/s×s
v=20m/s
Solubility Curve Practice Problems Worksheet 1
Directions: Find the mass of solute will dissolve in 100mL of water at the following temperatures?
150
1. KCl at 70°C =
140
2. Ce,(SO.), at 100°C=
130
120
3. NH.Cl at 90°C=
4. Which of the above three substances is most
110
100
NaNO3
soluble in water at 15°C. =
90
KNO3
Grams of solute
per 100 g H,0
80
70
60
NH3
NHACI
50
KCI
40
Naci
30
20
KCIO
10
Ce2(SO4)3
0
10 20 30 40 50 60 70 80 90 100
Temperature (°C)
According to the solubility curve, KCl is soluble in water at a rate of about 40 grammes per 100 g. Given that we have 100 mL, or 100 grammes, of water, the mass of KCl that will dissolve is similarly 40 grammes.
\(Ce_2(SO_4)_3\) is soluble in water at a rate of around 30 grammes per 100 grammes at 100 °C. \(Ce_2(SO_4)_3\) will therefore dissolve in 100 mL of water at a mass of 30 grammes.
\(NH_4Cl\) dissolves in water at a rate of around 90 grammes per 100 grammes at 90 °C. The mass of \(NH_4Cl\) that will dissolve in 100 mL of water is similarly 90 grammes.
We must ascertain the solubilities of the abovementioned chemicals at 15°C in order to ascertain which substance is most soluble at that temperature.
\(NaNO_3\) has the highest solubility at 15°C, as seen by the solubility curve. At 15°C, \(NaNO_3\) dissolves in water at a rate of about 80 grammes per 100 g.
Therefore, at 15°C, NaNO3 is the most soluble substance among the three given substances.
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two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then what is the magnitude and the direction of the resultant force
what is its acceleration of x and y component
what is the magnitude of acceleration of the object
Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.
The acceleration of the object in the x-component (\(a_x\)) is 2.4 \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8 \(m/s^{2}\).
The magnitude of the acceleration of the object is 3 \(m/s^{2}\).
To find the magnitude and direction of the resultant force, we need to add the two given forces together.
Given:
f1 = (8i + 3j) N
f2 = (4i + 6j) N
To find the resultant force (\(F_res\)), we simply add the corresponding components:
\(F_res\) = f1 + f2
= (8i + 3j) + (4i + 6j)
= (8 + 4)i + (3 + 6)j
= 12i + 9j
The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:
\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)
= \(\sqrt{144 + 81}\)
= \(\sqrt{225}\)
= 15 N
So, the magnitude of the resultant force is 15 N.
To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:
θ = arctan(9/12)
= arctan(3/4)
≈ 36.87 degrees
Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.
Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:
F = ma
For the x-component:
\(F_x\)= 12 N
m = 5 kg
Using \(F_x\)= \(ma_x\), we can solve for \(a_x\):
12 N = 5 kg * \(a_x\)
\(a_x\)= 12 N / 5 kg
\(a_x\) = 2.4 \(m/s^{2}\)
For the y-component:
\(F_y\) = 9 N
m = 5 kg
Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):
9 N = 5 kg * \(a_y\)
\(a_y\) = 9 N / 5 kg
\(a_y\)= 1.8 \(m/s^{2}\)
So, the acceleration of the object in the x-component (\(a_x\)) is 2.4 \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8 \(m/s^{2}\).
To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:
|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)
= \(\sqrt{(2.4^2) + (1.8^2}\)
= \(\sqrt{5.76 + 3.24}\)
= \(\sqrt{9}\)
= 3 \(m/s^{2}\)
Therefore, the magnitude of the acceleration of the object is 3 \(m/s^{2}\)
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3. How much power does an electric light installation draw at 120 V if it creates a current of 0.8 amps?
O A. 32 watts
O B. 120 watts
Q C. 48 watts
D. 96 watts
Answer:D
Explanation:
R =
V
I
=
120 volt
0.8 ampere
= 150 ohm (Ω)
P = V × I
= 120 volt × 0.8 ampere
= 96 watt (W)
An electric light installation can draw Power of 96 Watt at 120 V if it creates a current of 0.8 amps
What is electric power ?Electric power is the rate of electric energy transfer by an electric circuit per unit time . It is denoted by P and measured using the SI unit of power that is Watt (W)
since, Electric Power = voltage * current
Power = 120 V * 0.8 A
Power = 96 Watts
An electric light installation can draw Power of 96 Watt at 120 V if it creates a current of 0.8 amps
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Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!
Here is a function machine.
Input : multiply by 6. Subtract 80: output
The input is the same as the output. Find the input.
Also can you please show me an easy to work out these type of questions
Answer:
Explanation:
Sure, I'd be happy to help you with the question!
Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.
So, the function can be written as:
Output = (6 * x) - 80
Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:
x = (6 * x) - 80
Let's solve this equation to find the value of x:
x = 6x - 80
Subtracting 6x from both sides, we get:
x - 6x = -80
Combining like terms, we have:
-5x = -80
Dividing both sides by -5, we find:
x = (-80) / (-5)
Simplifying the expression, we have:
x = 16
Therefore, the input (x) that results in the input being the same as the output is 16.
To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.
Answer:
16
Explanation:
(x*6) - 80 = x
Multiply the parentheses
6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16
malia is interested in observing cognitive development in children and wants to design a study that will allow her to observe small changes in how 6 year olds learn to solve problems. she plans to collect data from each child every week for three months
which design is her best choice
To study the small changes in 6 year old child to solve problems, the appropriate method of design is microgentic.
What is microgentic design ?A scientific approach known as microgenetic design, sometimes known as the microgentic method, iterative search studying the same environment to examine change in great detail.
Microgenetic designs offer a detailed examination of the behavior of the system while it is changing, in contrast to cross-sectional and longitudinal designs, which only offer broad strokes of the process of change.
The approach is applicable to any system human or otherwise whose behavior varies over time and where it may be interesting or necessary to investigate the specifics of these changes, even though it is frequently linked with developmental psychology.
This includes adult settings as well. Heinz Werner's description of a "genetic approach" in the early 20th century appears to be when the term "microgenetic" first appeared.
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