for women at hartford college, times to run 400 meters are normally distributed with a mean of 85 seconds and a standard deviation of 5 seconds. what percentage of the times are less than 80 seconds?

There is ''No solution'' of the expression |x| + 7 < 4.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

The expression is,

⇒ |x| + 7 < 4

Now, We can solve the expression as;

The expression is,

⇒ |x| + 7 < 4

Subtract 7 both side;

⇒ |x| + 7 - 7 < 4 - 7

⇒ |x| < - 3

Hence, The expression has no solution.

Thus, There is ''No solution'' of the expression  |x| + 7 < 4.

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Another name for a regression line is Least squares line

Answer:Best-Fit-Line

Step-by-step explanation:

--Or line of best fit

HOP THIS HELPS!!!

By applying the simple concept of algebra, the equation showing the number of Kenny's baseball cards (b) is b = 82 + 159. So it can be concluded that the number of Kenny's baseball cards is 241 cards.

The use of algebra in everyday life.

Algebra is a branch of mathematics that uses numbers, symbols, or letters to solve math problems. In everyday life, algebra is often used, starting from simple mathematical operations, to financial planning, calculating time/mileage, and so on.

In the above questions, we can take some notes as follows:

Baseball cards sold (x) = 82 cards.

Remaining baseball cards (y) = 159 cards.

The number of baseball cards owned by Kenny (b):

b = x + y

  = 159 + 82

  = 241 cards

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Answer:

z = 9

Step-by-step explanation:

7z = z + 54

7z - z = 54

6z = 54

z = 54 / 6

z = 9

The position of the particle is: x(6) = 4 + ∫[0,6] (e^(0.2t) - 1) dt

The average speed, we first need to determine the total distance traveled is : Average speed = Total distance traveled / 2

Part A: To find the total distance traveled by the particle from time t = 0 to time t = 5, we need to integrate the absolute value of the velocity function over the interval [0, 5].

The velocity function is given by v(t) = e^(0.2t) - 1.

The distance traveled at any given time t is the absolute value of the velocity function integrated from t = 0 to t = 5. Therefore, the integral expression for the total distance traveled is:

∫[0,5] |v(t)| dt

Part B: To find the position of the particle at time t = 6, we need to integrate the velocity function from t = 0 to t = 6 and add it to the initial position.

The position function x(t) is the integral of the velocity function v(t). Thus, the position of the particle at time t = 6 is given by:

x(6) = x(0) + ∫[0,6] v(t) dt

Given that x(0) = 4, the expression becomes:

x(6) = 4 + ∫[0,6] (e^(0.2t) - 1) dt

Part C: The average speed of the particle over the interval 0 ≤ t ≤ 2 is the total distance traveled divided by the elapsed time.

Average speed = Total distance traveled / Elapsed time

To find the average speed, we first need to determine the total distance traveled. We can use the integral expression from Part A to calculate it. Then, we divide the total distance by the elapsed time, which is 2.

Average speed = Total distance traveled / 2

Please note that the calculations and evaluations of these integrals require the use of numerical methods or a calculator.

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The area of the figure is similar to the area of a triangle with a base of 6 in and a height of 9 in.

Option C is the correct answer.

We have,

The figure has one square and one rectangle.

So,

Area of a rectangle.

= length x width

Now,

Top square.

= length x width

= 3 x 3

= 9 in²

Bottom rectangle.

= length x width

= 9 x 2

= 18 in²

Now,

The area of the figure.
= 9 + 18

= 27 in²

Now,

The area of a triangle with base 6 in and height 9 in

Area = 1/2 x 6 x 9 = 3 x 9 = 27 in²

Thus,

The area of the figure is similar to the area of a triangle with a base of 6 in and a height of 9 in.

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The market price of the watch after a discount of 10% is  $3500   .

In the question ,

it is given that

the price at which the trader sold the wrist watch = $3150

the amount of discount given by trader = 10% ,

we need to find the market price of the watch ,

let the market price of the watch be "x" .

so , the formula that can be used to calculate the market price is

selling price = market price - (discount percent)×(market price)

Substituting the values , we get

3150 = x - 10% of x

3150 = x - 0.10x          ....because 10% = 0.10

(1 - 0.10)x = 3150

0.90x = 3150

Dividing both sides by 0.90 , we get

x = 3150/0.90

x = 3500

market price is $3500  .

Therefore , The market price of the watch after a discount of 10% is  $3500   .

The given question is incomplete , the complete question is

A trader sold a wrist watch for $3150 after giving a 10% discount. Find the marked price of the watch ?

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Answer:

\(R=\dfrac{17}{3}\ \text{miles/hour}\)

Step-by-step explanation:

It is given that,

Distance covered, \(d=8\dfrac{1}{2}\ \text{miles}\)

Time taken, \(t=1\dfrac{1}{2}\ \text{hours}\)

We need to find the rate in miles per hour. It can be calculated by dividing distance covered and time taken as follows :

\(R=\dfrac{8\dfrac{1}{2}\ \text{miles}}{1\dfrac{1}{2}\ \text{hour}}\\\\R=\dfrac{\dfrac{17}{2}}{\dfrac{3}{2}}\\\\R=\dfrac{17}{3}\ \text{miles/hour}\)

Hence, Dev jogs at the rate of \(\dfrac{17}{3}\ \text{miles/hour}\).

The speed of Dev to cover 17/2 miles in 3/2 hours is 17/3 miles/hours.

It is given that

Distance covered by Dev = 17/2 miles

Time taken to cover 8.5 miles = 3/2 hours

Speed is defined as the distance covered in unit time.

So, Speed of Dev = Distance/Time

Speed of Dev = (17/2)/(3/2)

Speed of Dev = 17/3 miles/hours.

Therefore, the speed of Dev to cover 17/2 miles in 3/2 hours is 17/3 miles/hours.

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The standard form the linear function is f(x)= -3x-3.

An equation can be represented by a linear function. The standard form for the linear equation is: y= mx+b , for example, y=5x+3. Where:

m= the slope. It can be calculated for Δy/Δx .

b= the constant term that represents the y-intercept.

For the given example: m=5 and b=3.

You should replace in the minimum two given values for x and y in the standard form for a linear equation mx+b . Thus, you will write a system linear where from it, you can find the coefficients m and b. See below.

       y=mx+b

      -3=0*m+b

      -3=b

       y=mx+b

      3= -2*m+b

Now, you find b=-3, then

      3= -2*m-3

      3+3= -2m

       6=-2m

       m= -3

Thus, you can write f(x)= -3x-3.

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Step-by-step explanation:

Use z-score table to find the z-score that corresponds to .7000   ( 70%)

approx   .525   s.d.  above the mean

  .525  * 10 =  5.25  points above 100   = 105.25

Answer:

Answer:

44

Step-by-step explanation:

we know that

 [volume of right circular cylinder]=pi*r²*h

Vo=pi*r²*h--------------> original volume

Vo= 22 cm³

if twice the radius and half the height

r1=2*r

h1=h/2

then

V1=pi*ri²*h1

substituting

V1=pi*(2*r)² *(h/2)----------->V1= pi*4*r² *h/2-----------> V1=2*pi*r² *h

V1=2*[pi*r² *h]------------> V1=2Vo

V1=2*22=44 cm³

Answer:

d step 4

Step-by-step explanation:

hope it helps you on what u are doing

Answer:

n=21

Step-by-step explanation:

We must find n.

Remember PEMDAS. First we must do the Parentheses. Lets do distributive property by multiplying a number that is immediately outside the parentheses with each number inside the parentheses. Lets do this one side at a time.

First lets do 5(n - 7). We get 5n - 35

Now 2(n + 14) is 2n + 28

Okay...... now we have \(5n-35=2n+28\)

Now lets do OPPOSITES!!!! We must do the opposite of each thing to both sides.

The opposite of -35 is positive 35. Lets add 35 to both sides. We get:

\(5n=2n+63\)

Now lets do the opposite of 2n which is -2n

\(3n=63\)

this is looking quite nice isnt it..........

The opposite of 3 times n is 3 DIVIDED BY n. So lets divide both sides by 3

\(n=21\)

amazing.......

Answer:

Female, E-Book=22

Male, Print=20

Total Female=44

Print total=42

Answer:

6-1=5 times 3 =15

Step-by-step explanation:

Based on the information provided, we can assume that the sample of 700 births is representative of the population of births in the local area. The distribution of these 700 births across the days of the week can be analyzed to determine whether or not newborn babies are uniformly distributed across the days of the week.If the distribution of the 700 births is approximately equal across all seven days of the week, then we can conclude that newborn babies are uniformly distributed. However, if the distribution is significantly different from what would be expected if births were uniformly distributed, then we can conclude that there may be a non-uniform pattern of births.

Without knowing the actual distribution of the 700 births, we cannot definitively answer this question. However, if the distribution is close to equal, then we can tentatively say that newborn babies are uniformly distributed across the days of the week.

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A monomial is an algebraic expression that consists of a single term. A monomial can contain constants and/or variables, which are multiplied together.

The expression 3x²y is a monomial. It contains the constant 3, the variable x squared, and the variable y. The variables can be raised to an exponent, as in this example; however, the exponent must be a whole number.A monomial can also contain coefficients, which are the numbers that are multiplied with a variable. In the example above, the coefficient is 3. If there is no coefficient stated, then the coefficient is assumed to be 1. Therefore, the expression x²y is also a monomial, with the coefficient being 1.Additionally, a monomial can contain a product of numbers and variables, such as the expression 2xyz. This is also considered a single term, since all of the numbers and variables are multiplied together.

Monomials can be used to calculate polynomials, which are algebraic expressions consisting of multiple terms. By adding, subtracting, and multiplying monomials together, you can create a polynomial. For example, the expression (3x²y) + (2xyz) is a polynomial, since it consists of two terms. The first term is the monomial 3x²y, and the second term is the monomial 2xyz.

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Answer:

20

Step-by-step explanation:

When two numbers vary inversely, they always multiply to the same product, in this case, it is 80, because it is 8 x 10(product of two known values of p and q). This means, for q = 4, we can write:

p * 4 = 80

This means that p is equal to 20.

The value of p is 20 when q=4

Let there are two variables p and q

Then, p and q are said to be directly proportional to each other if

p = kq

where k is some constant number called constant of proportionality.

When two numbers vary inversely, then the will always multiply to the same product,

Here it is 80, because it is 8 x 10

Then product of two known values of p and q).

This means, for q = 4, we can write:

p x 4 = 80

This means that p is 20.

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The probability that at least one of the next three babies is a boy is 0.875.

Probability turned into added into arithmetic to are expecting the possibility of an occasion occurring. Probability essentially approach how in all likelihood it's miles that some thing will happen. This is the fundamental principle of possibility and is likewise utilized in possibility distributions to examine feasible consequences of random experiments.

Probability of the complement of event B:

The probability of the complement of event B is computed as follows:

P(B* )=1-P(B) P(B)=14(1-(0.5x0.5)) = 0.25

The probability of the complement of event B is B) 0.25.

Probability that at least one of the next three babies is a boy:

The probability that at least one of the next three babies is a boy is computed as follows:

at least one of the next three babies is a boy =1-(0.5x0.5x0.5) =1-0.125 = 0.875

The probability that at least one of the next three babies is a boy is D) 0.875.

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Answer: x+5 or ((x^2+8x+15)/(x+3))

Step-by-step explanation: First let's assign our variables.

x^2+8x+15 = Area

X+3 = Width

? = Length

If the equation of a=lw, then we can substitute in our variables.

a=lw

x^2+8x+15= L (x+3)

Now we must isolate L.

Divide both sides of the equation by 'x+3'

x^2+8x+15= L (x+3)

x+3                 x+3

x+5= L

A quadratic equation is in the form of ax²+bx+c. The time for which the stone was in the air is 3.526.

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

As the height of the stone will be zero or can say that the stone will be at the ground in only two conditions. When the stone will be just thrown and when the stone will complete its flight. Therefore, we can substitute the value of heigh h in the function as 0 to get those two timings.

\(h(t) = 5 + 50t - 16t^2\\\\0 = 5+50t - 16t^2\)

Substitute the quadratic equation in the formula of the root of the quadratic function,

\(x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\t = \dfrac{-50\pm\sqrt{(50)^2-4(-16)(5)}}{2(-16)}\\\\t= -0.089, 3.526\)

Hence, the time for which the stone was in the air is 3.526.

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Using synthetic division, we can divide the polynomial x³ + 7x² - 12x + 14 by the divisor 1. Performing the synthetic division, we obtain a quotient of x² + 6x - 6 and a remainder of 8.

To divide the polynomial x³ + 7x² - 12x + 14 by the divisor 1 using synthetic division, we set up the synthetic division table as follows:

1  |   1   7  -12   14

We begin by bringing down the coefficient of the first term, which is 1, and place it on the line below the division bar. Then we multiply the divisor, 1, by the value we brought down and write the result under the next coefficient. Adding the values in the second row, we obtain the new value. We continue this process for each term until we reach the last term.

1  |   1   7  -12   14

 1   8  -4     10

The values in the last row represent the coefficients of the quotient polynomial. Therefore, the quotient is x² + 6x - 6. The remainder, which is the last value in the last row, is 10. Since the divisor is 1, the remainder does not affect the quotient. Hence, the result of the division is x² + 6x - 6 with a remainder of 10.

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Answer:

The solution of \(x^3-2x^2+16x-32=0\) is \(\mathbf{x=2,x=4i,x=-4i}\)

So, the real solutions is: x = 2

Imaginary solutions are : x = 4i, x = -4i

Step-by-step explanation:

We need to find real and imaginary solutions to the equations \(x^3-2x^2+16x-32=0\)

First of all we will make groups

\((x^3-2x^2)(+16x-32)=0\)

Finding common terms from the groups

\(x^2(x-2)+16(x-2)=0\\(x-2)(x^2+16)=0\)

Now we know that if ab=0 then a=0 , b=0

\(x-2=0, x^2+16=0\\Simplifying:\\x=2, x^2=-16\\Taking\: square\: root\\x=2,\sqrt{x^2}=\sqrt{-16}\\x=2, x=\pm\sqrt{-16}\\x=2,x=\m\sqrt{-1}\sqrt{16} \\We\:know\:\sqrt{-1}=i \:and \sqrt{x} \:\sqrt{16}=4 \\x=2,x=\pm4i\\x=2,x=4i,x=-4i\)

The solution of \(x^3-2x^2+16x-32=0\) is \(\mathbf{x=2,x=4i,x=-4i}\)

So, the real solutions is: x = 2

Imaginary solutions are : x = 4i, x = -4i

Answer:

angle one is 40 degrees

Step-by-step explanation:

I'm pretty sure that the measurements of the line should be 180 and 180-140 = 40.

Laughter Landscaping has collected the following data for the December 31 adjusting​ entries is given below:

Here, we have,

Date Details                                                     Dr. $                     Cr.$

a Wages account Dr. (8000/5 x2)                     3200  

      Accrued wages account Cr.                                             3200

(Being the wages accrued for 2 days)    

b Prepaid insurance A/c Dr. (8000/2)              4000  

      Insurance A/c Cr                                                             4000

(Being the insurance prepaid for 1 year)    

c Supplies Expense A/c Dr.                                8400  

      Supplies A/c Cr. (4600+5600-1500)                             8400

(Being the office supplies used for the year)    

d   Unearned revenue A/c Dr. (6500x 40/100)         2600  

      Revenue A/c Cr.                                                            2600

(Being the Revenue earned has beed adjusted)    

e Accrued revenue A/c Dr.                                  3000  

       Revenue A/c Cr.                                                            3000

(Being the Accrued revenue has been recorded)    

f Income statement (Profit & Loss A/c) Dr.           3000  

 Provision for Depreciation on Equipment  A/c Cr.                     3000

(Being the Equipment depreciated)    

 Income statement (Profit & Loss A/c) Dr.            2200  

 Provision for Depreciation on Truck  A/c Cr.                             2200

(Being the Truck depreciated)    

g Interest A/c Dr. (550-250)                                      300  

       Accrued Interest A/c Cr.                                                       300

 (Being the amount of interest accrued)    

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Answer:

hmmm this is harder then i thought

Step-by-step explanation:

Answer:

Yes the ordered pair is a solution

Step-by-step explanation:

plug on the numbers

2< 2(-1) +8

2 < 6

4(2) > -4(-1)-6

8> 4-6

8> -2

Answer:

17p squared

Step-by-step explanation:

Answer:

D THEY TRADED WITH MESOPOTAMIA

Answer:

they did not participate in wars

Step-by-step explanation: