for what absolute value of the phase angle does a source deliver 75 % of the maximum possible power to an rlc circuit?
Answers
Accordingly, 75% of the maximum power is available when the phase angle is 45°.
What does "circuit" mean in its simplest form?A full circular channel through which electricity flows is known as a circuit in electronics. A base current, conductor, or a demand together a straightforward connection. Any permanent channel via which electricity, data, or a signal may flow can be considered a circuit in a broad sense.
Circuit is a what word?Quotations about a revolution, the action of moving or rotating, or as in a circle or orbit. ▼ the length of a circle or other object's circumference; the distance along a line enclosing a region.
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Related Questions
A skier traveling downhill has this type of energy
Answers
Answer:
potential energy
Explanation:
Which two terms describe how waves of dim blue light are different from
waves of bright red light?
O A Lower amplitude
B. Higher amplitude
OC. Shorter wavelength
O D. Longer wavelength
Answers
Answer:
Although the two stimuli are very different in terms of composition, wave forms Two physical characteristics of a wave are amplitude and wavelength lower frequencies, and shorter wavelengths will have higher frequencies At the top of the figure, the red wave has a long wavelength/short frequency.
If you drop a steel metal ball off a building and it takes 3 seconds to hit
the ground, how tall is the building?
Answers
Answer:
\(40\:\mathrm{m}\)
Explanation:
We can use kinematics equation \(\Delta y={v_i}^2+\frac{1}{2}at^2\) to solve this problem. Because the metal ball's initial velocity was 0, \({v_i}^2=0\).
Therefore, our equation becomes:
\(\Delta y=\frac{1}{2}at^2\) (freefall equation).
\(t\) is given as 3 seconds and \(a\) is acceleration due to gravity (\(9.81\:\mathrm{m/s}\)).
Therefore, our answer is:
\(\Delta y = \frac{1}{2}\cdot9.81\cdot3^2=44.145=\fbox{$40\:\mathrm{m}$}\) (one significant figure).
What is the size of the planets from smallest to largest?
Answers
The size of the planets from smallest to largest is: Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter.
The planets in our solar system range in size from the small, rocky Mercury, which has a diameter of 4,879 km, to the giant gas giant Jupiter, which has a diameter of 139,822 km. The order of the planets based on size is determined by their relative diameters, with the smallest planet, Mercury, being the first in the list and the largest planet, Jupiter, being the last.
The rocky planets, Mercury, Mars, Venus, and Earth, are all relatively close in size, with diameters ranging from 4,879 km to 12,742 km. The gas giants, Jupiter, Saturn, Uranus, and Neptune, are much larger, with diameters ranging from 49,244 km to 139,822 km.
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A boat has a porthole window, of
area 0.00849 m^2, 6.25 m below
the surface. The density of sea
water is 1027 kg/m^3. The air
inside the boat is at 1 atm. What
is the NET force on the window?
(Unit = N)
(1 atm = 101300 Pa)
Answers
Answer:
F = 534.6[N]
Explanation:
We must find the pressure exerted by the water at the depth of the boat, by means of the following equation.
\(P=Ro*g*h\)
where:
Ro = density of sea water = 1027 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = wáter Depth = 6.25 [m]
Now replacing:
\(P=1027*9.81*6.25\\P=62967.93[Pa]\)
The net force is:
\(F = P*A\\F = 62967.93*0.00849\\F = 534.6[N]\)
Answer:
534.6
Explanation:
sleep and stress levels can be improved by what?
Answers
Answer:
A healthy diet, low in sugar, caffeine, and alcohol, can promote health and reduce stress.
Explanation:
A healthy diet, low in sugar, caffeine, and alcohol, can promote health and reduce stress. Get adequate sleep: A good night's sleep makes you able to tackle the day's stress more easily. When you are tired, you are less patient and more easily agitated, which can increase stress.
The goalkeeper is the only player allowed to use their hands OA True OB. False
Answers
Answer:True
Explanation:
The melting point of a pure compound is known to be 110-111°. Describe the melting behavior expected if this compound is contaminated with 5% of an impurity?
An impurity consisting of 5% total mass will lower the melting point from that of the pure compound, and it will increase the melting point range.A value of 103-107° would be consistent with this amount of impurity with the pure melting point of 110-111°; values of 100-105°, 97-100°, 102-110° are also good estimates.
Answers
Impurities will lower the melting point of a pure compound and increase the melting point range.
When an impurity is mixed with a pure substance, it lowers the melting point of the compound and expands its melting range. If a substance has a pure melting point of 110-111°C, adding a 5% impurity would cause the melting point to drop to 103-107°C, while the melting point range would broaden. It's difficult to predict the precise melting point range, but estimates such as 100-105°C, 97-100°C, and 102-110°C are all possible.
Impurities that are added to a substance have a noticeable effect on the melting point of the pure substance, which is used to evaluate the purity of the sample. The melting point of a compound is an important characteristic that chemists use to determine its identity and purity.
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A one-dimensional analog for a two-slit interfer- ence experiment is a quanton bouncing back and forth between two perfectly reflecting barriers. It turns out that the momentum eigenfunction associated with a given x-momentum value p is p(r) - A[cos (kx) +i sin (kx)l, where A is an appropriate scaling constant, i v-1, x is x-position and k 2m/h where h is Planck's constant Suppose that we prepare the quanton in the following state ?(x) = VA[cos (kox) + i sin (k, x)] +V? A[cos (-k,x1+ i sin (-k,x)] (09.24) This is a superposition of two momentum eigenfunctions one for a quanton moving to the right with x-momentum +okoh/2T, and one for the quanton moving to the ile this is a complex wavefunction, the only thing you need to know about complex numbers in this problem is that the sum of two complex numbers of the form a +ib, and a2 + ib2 (where all as and bs are real) is (a + a2) + i(b, + b2) and that the absolute square of a complex number of the form aib is left with x-momentum px--Po- (a) Argue that the wavelength associated with each cosine or sine term in this wave is ?-h/Po, consistent with the de Broglie formula (b) Argue that if we perform an experiment to localize this quanton, the probability of obtaining the value x is (Q9.25) (Hint: sin (-?)--sin ? for any value of ?. Add the real and imaginary parts of equation Q9.24 separately, thern take the absolute square of the result.) (c) Argue that this probability pattern looks like an inter- ference pattern with "bright spots" and "dark spots Where are the "bright spots" of this pattern? (d) Now suppose that we don't believe the Superposition Rule, but instead believe that the quanton actually has a pre-existing value of p that at a given time is either a positive or negative as it bounces back and forth
Answers
(a) The wavelength associated with each cosine or sine term in the wavefunction is λ = h/p₀, consistent with the de Broglie formula.
(c) The probability pattern looks like an interference pattern with "bright spots" and "dark spots," where the bright spots occur where the interference term is maximum.
(a) To argue that the wavelength associated with each cosine or sine term in the wavefunction is λ = h/p₀, we can use the de Broglie formula, which relates the momentum (p) of a particle to its wavelength (λ) as λ = h/p. In this case, the momentum eigenfunction associated with the given x-momentum value p is given as p(r) = A[cos(kx) + i sin(kx)]. Comparing this with the cosine term in the wavefunction, we can see that k = p₀/ħ, where ħ is the reduced Planck's constant (h/2π). Therefore, substituting k into the de Broglie formula, we have λ = (2πħ)/(p₀/ħ) = 2πħ/p₀ = h/p₀.
(b) To find the probability of obtaining a specific value x when localizing the quanton, we need to take the absolute square of the wavefunction Ψ(x). From equation (9.24), we have:
Ψ(x) = Vₐ[Acos(k₀x) + i sin(k₀x)] + Vₚ[Acos(-k₀x) + i sin(-k₀x)]
Taking the absolute square of Ψ(x), we get:
|Ψ(x)|² = |Vₐ|²[cos²(k₀x) + sin²(k₀x)] + |Vₚ|²[cos²(-k₀x) + sin²(-k₀x)] + 2Re[VₐVₚ*(Acos(k₀x) + i sin(k₀x))(Acos(-k₀x) - i sin(-k₀x))]
Using the identities cos(-θ) = cos(θ) and sin(-θ) = -sin(θ), we can simplify the expression:
|Ψ(x)|² = |Vₐ|²[cos²(k₀x) + sin²(k₀x)] + |Vₚ|²[cos²(k₀x) + sin²(k₀x)] + 2Re[VₐVₚ*(Acos(k₀x) + i sin(k₀x))(Acos(k₀x) + i sin(k₀x))]
Simplifying further:
|Ψ(x)|² = (|Vₐ|² + |Vₚ|²)(cos²(k₀x) + sin²(k₀x)) + 2Re[VₐVₚ(A²cos²(k₀x) + i²A²sin²(k₀x))]
Since cos²(k₀x) + sin²(k₀x) = 1 and cos²(k₀x) + sin²(k₀x) = 1, we have:
|Ψ(x)|² = |Vₐ|² + |Vₚ|² + 2Re[VₐVₚA²cos²(k₀x) + i²VₐVₚA²sin²(k₀x)]
Considering that Re[i²] = 0 and taking the absolute square again, we get:
|Ψ(x)|² = |Vₐ|² + |Vₚ|² + 2Re[VₐVₚA²cos²(k₀x)]²
Therefore, the probability of obtaining a specific value x is given by |Ψ(x)|² = |Vₐ|² + |Vₚ|² + 2Re[VₐVₚA²cos²(k₀x)]².
(c) The probability pattern obtained from the wavefunction resembles an interference pattern with "
bright spots" and "dark spots." The bright spots occur where the interference term 2Re[VₐVₚA²cos²(k₀x)] is maximum, which corresponds to the maximum constructive interference. The dark spots occur where this term is minimum or zero, corresponding to destructive interference. The exact locations of the bright and dark spots depend on the values of Vₐ, Vₚ, and the wavelength λ = h/p₀.
(d) If we do not believe in the Superposition Rule and assume that the quanton has a pre-existing value of momentum p that is either positive or negative as it bounces back and forth, then the interference pattern observed in part (c) would not occur. Instead, we would observe a simpler pattern or distribution of the quanton's position that is not characterized by interference effects.
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A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?
Answers
The speed of the wave on a string is given by Taylor's formula:
\(v=\sqrt[]{\frac{F}{\mu}}\)where
F = tension force
μ = linear density = mass per unit length
But also we can say the speed of any wave is given by:
\(v=\lambda\times f\)where:
λ = wave length
f = frequency
Plug the second equation in the first one. We get:
\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)Now solve for f:
\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.
See that 340 N = 2 x 170, so we can write:
\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
(a) How far did he travel?
(b) What was his average speed?
(c) What was his displacement?
(d) What was his average velocity?
Answers
Answer:
Explanation:
See the attachment for the details. A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times. The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.
The individual driving times and distances are summed to provide:
(a) How far did he travel?
103 km
(b) What was his average speed?
12.88 km/h
(c) What was his displacement?
73.82 km
(d) What was his average velocity?
9.228 km/h
What can be added to a solution to control the ph?
a base
a liquid
a buffer
an acid
(also my apologies if i labeled this as the wrong topic, this is my first time using this and i'm taking psychical science so. :( sry)
Answers
A buffer can be added to a solution to control the pH.
What is pH?
In chemistry, pH, which actually stands for "potential of hydrogen" (or "power of hydrogen"), is a scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions (solutions with higher concentrations of H+ ions) have lower pH values than basic or alkaline solutions. The pH scale is logarithmic and indicates the concentration of hydrogen ions in the solution inversely.
At this temperature, pH 7 solutions are neutral.
The pH neutral value is temperature dependent, being less than 7 if the temperature rises above 25 °C. The pH value can be less than 0 for highly concentrated strong acids and greater than 14 for highly concentrated strong bases.
A buffer is a special solution that prevents drastic pH changes. Every buffer has a buffer capacity and buffer range. The amount of acid or base that can be added before the pH begins to change significantly is referred to as the buffer capacity. It is also the amount of strong acid or base required to change the pH of one litre of solution by one pH unit. The pH range in which a buffer effectively neutralizes added acids and bases while maintaining a relatively constant pH is referred to as the buffer range.Hence, a buffer can be added to a solution to control the pH.
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Please explain how to do this
Answers
slope is zero therefore velocity will be 0 at B to C .
why is thrust-required, tr, converted to power-required, pr, when analyzing the performance of a propeller driven aircraft?
Answers
The thrust-required, converted to power-required, when analyzing the performance of a propeller-driven aircraft is because propeller's thrust is always directed toward the center of rotation.
When you look at the total power required by a propeller aircraft and the total power that can be used by the engine, you'll see that there's an imbalance between the two. This means that more power will be needed than is available.
To solve this problem, engineers must design their propeller aircraft so that it produces enough thrust for takeoff but not so much thrust as to exceed the engine's ability to use all of its available power.
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Car AMass: 1,500 kgVelocity: 10 m/sCar BMass: 1,500 kgVelocity: 25 m/sCar CMass: 1,000 kgVelocity: 10 m/sWhich order shows decreasing momentum?A, B, CB, A, CC, B, A
Answers
Answer:
B, A, C
Explanation:
The momentum is equal to the mass times the velocity, so for each car the momentum is equal to
Car A
Momentum = Mass x Velocity
Momentum = 1,500 kg x 10 m/s
Momentum = 15,000 kg m/s
Car B
Momentum = Mass x Velocity
Momentum = 1,500 kg x 25 m/s
Momentum = 37,500 kg m/s
Car C
Momentum = Mass x Velocity
Momentum = 1,000 kg x 10 m/s
Momentum = 10,000 kg m/s
Then, the decreasing momentum is B, A, C because
37,500 is greater than 15,000 and 15,000 is greater than 10,000
So, the answer:
B, A, C
how (and why) does a planet change its speed while in orbit?
please help asap!!!
Answers
Answer:
A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves.
Explanation: hope that helps :)
From Task 2 data, what would be a general "rule for sinking and floating" to describe how density can be used to predict if an object will sink or float in any liquid? (4 pts) 8. Write a step-by-step description of how you measured the density of each plastic. Provide enough detail that someone could repeat your exact procedure by reading the description.
Answers
The general "rule for sinking and floating" based on density states that an object will sink if its density is greater than the density of the liquid and will float if its density is less than the density of the liquid.
To determine if an object will sink or float in a liquid based on its density, we can establish a general "rule for sinking and floating." Here is a concise description of the rule:
1. Compare the density of the object to the density of the liquid.
2. If the density of the object is greater than the density of the liquid, the object will sink.
3. If the density of the object is less than the density of the liquid, the object will float.
The density of an object can be calculated by dividing its mass by its volume. By comparing this density to the density of the liquid, we can determine the object's behavior in that specific liquid. If the object's density is greater, it means it has more mass in a given volume and will sink due to the greater buoyant force acting on it. Conversely, if the object's density is lower, it means it has less mass in a given volume and will float as the buoyant force is greater than the gravitational force.
Overall, the "rule for sinking and floating" states that an object will sink if its density is greater than the density of the liquid and will float if its density is less than the density of the liquid.
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A 9V battery is attached to 6Ω and 3Ω resistor. What is the voltage going to the 3Ω resistor?
1 V
3 V
9 V
2 V
4.5 V
It is a short circuit
Answers
Answer:
Voltage across 3 resistor =13.5v
Explanation:
Voltage=resistance *Current
But we don't have total current, so we must find total current
Current =v/R
Current=9/2
Current =4.5I
From
V=R*I
V=3*4.5
V=13.5v
A bowling pin is thrown vertically upward such that it rotates as it moves through the air, as shown in the figure. Initially, the center of mass of the bowling pin is moving upward with a speed vi of
10 The maximum height of the center of mass of the bowling pin is most nearly
Answers
Answer:
Explanation:
In projectile, the formula for calculating the maximum height reached by the pin is expressed as;
H = u²/2g
u is the speed/velocity = 10m/s
g is the acceleration due to gravity = 9.81m/s²
Substitute
H = 10²/2(9.81)
H = 100/19.62
H = 5.097m
Hence the maximum height of the center of mass of the bowling pin is most nearly 5.0m
A projectile is to be launched at an angle of 30° so that it falls beyond the pond of length 20 meters as shown in the figure.
a) What is the range of values of the initial velocity so that the projectile falls between points M and N?
Answers
Answer: A
Explanation:
I want my points so yea
Is It in Equilibrium?
In Equilibrium
match burning out a shrinking beach
pendulum swinging back and forth
lake with constant water level
Not in Equilibrium
species going extinct
a seesaw with twins on it
4
Answers
Equilibrium refers to a condition in which the net force and net torque on an object are zero. The object is at rest or moves with constant speed in a straight line in the absence of an unbalanced force or torque. For a system to be in equilibrium, it must meet two conditions: the net force acting on it must be zero, and the net torque acting on it must also be zero. If the conditions are not met, the system will experience acceleration or rotation.
The balance between forces and torques determines the state of equilibrium. It is therefore necessary to analyze all forces acting on an object in order to determine whether it is in equilibrium or not. If the forces are equal and opposite, and the object is at rest or moves in a straight line at a constant speed, it is in equilibrium. If the forces are unbalanced, the object will accelerate in the direction of the net force. Likewise, if the torques are unbalanced, the object will rotate in the direction of the net torque. Therefore, analyzing forces and torques is essential to determine whether an object is in equilibrium or not. Additionally, it is important to note that equilibrium can occur in various forms, including static, dynamic, and thermal equilibrium. Each type of equilibrium has its own unique properties, but they all share the commonality of zero net force and zero net torque.For such more question on Equilibrium
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Vector B has x, y, and z components of 2.4,
9.8, and 4.1 units, respectively.
Calculate the magnitude of B.
Answers
The magnitude of the vector B is 10.9
A vector is a quantity which has magnitude as well as direction and it follows vector laws of addition.
To calculate the magnitude of the vector, we have to put the square of the components of the vector along the axes under the root.
Vector B has components,
x = 2.4
y = 9.8
z = 4.1
Applying the formula,
|B| = √x²+y²+z²
|B| = √(2.4)² + (9.8)² + (4.1)²
|B| = √5.76+96.04+16.81
|B| = √118.61
|B| = 10.9
Talking about the direction the the Vector B, it will be the line joining the origin with the points (2.4,9.8,4.1)
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1. Find the electric field of a - 3.2 n C charge from a distance of 6 m.
2. Find the electric field of a + 3.2 n C charge from a distance of 6 m.
3. If two + 3.4μC experience a force of 0.01 C/m, how far are they from one another?
4. If two - 6μC experience a force of 0.03 C/m, how far are they from one another
Answers
Plugging in these values gives an electric field of -1.07 x 10-8 N/C.
What is electric field?Electric field is a physical phenomenon that occurs when an electric charge is present in a space.
The electric field of a -3.2 nC charge from a distance of 6 m can be calculated using the equation E = kQ/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q is the charge of the particle (in this case, -3.2 nC), and r is the distance from the particle (6 m). Plugging in these values gives an electric field of -1.07 x 10-8 N/C.
2. The electric field of a +3.2 nC charge from a distance of 6 m can be calculated using the same equation as in #1, E = kQ/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q is the charge of the particle (in this case, +3.2 nC), and r is the distance from the particle (6 m). Plugging in these values gives an electric field of +1.07 x 10-8 N/C.
3. To find the distance between two +3.4 μC particles that experience a force of 0.01 C/m, we can use the equation F = kQ1Q2/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q1 and Q2 are the charges of the two particles (in this case, +3.4 μC each), and r is the distance between them. Plugging in these values gives a distance of 5.81 m.
4. To find the distance between two -6 μC particles that experience a force of 0.03 C/m, we can use the same equation as in #3, F = kQ1Q2/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q1 and Q2 are the charges of the two particles (in this case, -6 μC each), and r is the distance between them. Plugging in these values gives a distance of 1.31 m.
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What are 2 phenomenon that are caused by gravity
Answers
A ball is shot at an angle of 45 degrees into the air with initial velocity of 41 ft/sec. Assuming no air resistance, how high doss it go? How far away does it land? Hint: The acceleration due to gravity is 32ft per second squared. A particle is moving with acceleration a(t)=24t+16. its position at time t=0 is s(0)=12 and its velocity at time t=0 is v(0)=15. What is its position at time t=14 ? Find the average value of f(x)= x³8 +9x on the interval [1,2].
Answers
The ball reaches a maximum height of approximately 42.83 ft. the ball lands at a horizontal distance of approximately 81.36 ft. he average value of f(x)= x³8 +9x on the interval is 10.5.
To determine the maximum height and horizontal distance traveled by the ball shot at an angle of 45 degrees with an initial velocity of 41 ft/sec and neglecting air resistance, we can use basic kinematic equations.
Maximum Height:
The maximum height reached by the ball can be calculated using the equation for vertical displacement:
y_max = (v₀² * sin²θ) / (2g),
where v₀ is the initial velocity, θ is the launch angle (45 degrees), and g is the acceleration due to gravity (32 ft/s²).
Plugging in the values, we get:
y_max = (41² * sin²45°) / (2 * 32) = 42.83 ft.
Therefore, the ball reaches a maximum height of approximately 42.83 ft.
Horizontal Distance:
The horizontal distance traveled by the ball can be calculated using the equation for horizontal displacement:
x = v₀ * cosθ * t,
where x is the horizontal distance and t is the time of flight.
Since the ball goes up and then comes back down, the total time of flight can be calculated as:
t_total = 2 * (v₀ * sinθ) / g.
Plugging in the values, we get:
t_total = 2 * (41 * sin45°) / 32 ≈ 2.88 s.
Using this total time, we can find the horizontal distance:
x = 41 * cos45° * 2.88 ≈ 81.36 ft.
Therefore, the ball lands at a horizontal distance of approximately 81.36 ft.
Moving on to the second question:
To find the position of a particle at time t = 14, given its acceleration, initial position, and initial velocity, we can use the equations of motion.
The position function s(t) can be obtained by integrating the acceleration function twice with respect to time. Since the given acceleration is a linear function, we have:
s(t) = (1/6)at³ + (1/2)v₀t² + s₀,
where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.
Plugging in the given values, we get:
s(14) = (1/6)(24)(14)³ + (1/2)(15)(14)² + 12 ≈ 546.67.
Therefore, the position of the particle at time t = 14 is approximately 546.67.
Lastly, for the average value of f(x) = x³ + 9x on the interval [1, 2], we can use the formula for the average value of a function on an interval:
Average value = (1 / (b - a)) * ∫[a, b] f(x) dx,
where [a, b] represents the interval.
Plugging in the values, we have:
Average value = (1 / (2 - 1)) * ∫[1, 2] (x³ + 9x) dx.
Evaluating the integral, we get:
Average value = (1 / 1) * [(1/4)x⁴ + (9/2)x²] evaluated from 1 to 2,
Average value = (1/4)(2⁴ + 9(2²)) - (1/4)(1⁴ + 9(1²)),
Average value = (1/4)(16 + 36) - (1/4)(1 + 9),
Average value = (1/4)(52) - (1/4)(10),
Average value = 13 - 2.5,
Average value ≈ 10.5
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For transmissivity (T) = 2500 m2/day, storativity (S) = 1.0 x 10-3, and a pumping rate
(Q) = 500 m3/day, calculate drawdowns in a confined aquifer (isotropic, homogeneous, transient
condition) at observation wells located (i) 10 m and (ii) 50 m at t = 150
Answers
Answer:
The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:
s = Q / (4πT) * W(u),
where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:
u = r²S / (4Tt),
where r is the distance from the pumping well and t is the time since pumping began.
Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.
For (i) r1 = 10 m:
u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667
s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).
For (ii) r2 = 50 m:
u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667
s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).
Explanation:
Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.
What is the objects acceleration
Answers
Hehe
A plane needs to reach a velocity of 250 kilometers per hour to take off and leave the runway. If the wind is blowing in the direction of takeoff at a velocity of 20 kilometers per hour, what velocity must the plane reach in order to take off? a. 12.5 hours b. 230 kilometers per hour c.270 kilometers per hour d.500 kilometers
Answers
Answer:
5
Explanation:
1
3.Shanai drove 40 miles to the west, then turned around and drove 70 miles to the east.
Draw vectors that show each segment of her trip and the resultant displacement vector. Find
her resultant displacement.
Answers
Answer:
Explanation:
Comment
The main points are that
The arrowheads go in opposite directionsDisplacement is measured from the origin to the arrowhead of the last vector correctly drawn.the tail of the second vector starts where the arrowhead of the first vector is.Solution
40 miles west
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Displacement (30 km east)
Answer
30 km east
Activity 1 MATCH IT
Directions: Match Column A to Column B. Write your answer on the space provided before the number.
COLUMN A
__1. Hiking
__2. Orienteering
__3. Zumba
__4. Volleyball
__5.badminton
COLUMN B
A. It is an outdoor navigational recreational activity using specially drawn and detailed maps.
B. Created through on-the –spot aerobics class using the non- traditional music.
C.Going on an extended walk for the purpose of pleasure and exercise.
D. Can be traced from the ingenuity of William J. Morgan in 1895 at Holyoke Massachusetts.
E. Games are held inside the gym to avoid the effect of air in the flight of the shuttle.
Answers
Answer:
1. A hiking
2. C
3. B
4. D
5. E