for water to change into the gas phase, energy is required to break hydrogen bonds between h2o molecules. this energy is referred to as: a. latent heat b. specific heat capacity c. sensible heat d. kinetic energy

Answers

Answer 1

For water to change into the gas phase, energy is required to break hydrogen bonds between H₂O molecules. This energy is referred to as Latent heat. So, the right option is A.

Energy is needed for the conversion of a solid into a liquid, a liquid into a gas, or a solid into a gas. Energy will be released during fusion, condensation, or the transformation of gas into solid or liquid.

Latent heat of evaporation is the term used to describe the energy needed to change a liquid into a gas.

The molecules of water in a liquid are held together by hydrogen bonds. A single molecule must therefore have enough energy to break all of its hydrogen bonds with neighboring molecules before dissolving in order for it to evaporate. Since this molecule must have obtained its internal energy from the remaining liquid, every vaporizing molecule absorbs the same quantity from it. For this energy loss, the phrase "latent heat of vaporization" is used.

So, the correct option is C. Latent heat.

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Related Questions

The medication order for an adult states, "Give 0. 5 g of acetaminophen oral suspension PO every 12 hours. " The acetaminophen in the medication bottle is available as 100 mg/mL. How many tsp will the nurse administer to the adult? Record your answer as a whole number. Tsp

Answers

The nurse will administer 1 teaspoon of acetaminophen oral suspension to the adult.

To calculate how many teaspoons (tsp) of acetaminophen oral suspension the nurse will administer to the adult, we need to convert the given dose from grams (g) to milligrams (mg) and then determine the volume of the oral suspension required.

First, let's convert the given dose of 0.5 g to milligrams. Since there are 1000 milligrams in 1 gram, we multiply 0.5 g by 1000:

0.5 g * 1000 mg/g = 500 mg

So, the adult should receive 500 mg of acetaminophen oral suspension every 12 hours.

Next, we need to determine the volume of the oral suspension required. Given that the acetaminophen is available as 100 mg/mL, we divide the required dose (500 mg) by the concentration of the oral suspension (100 mg/mL):

500 mg / 100 mg/mL = 5 mL

Therefore, the nurse will administer 5 mL of acetaminophen oral suspension to the adult.

Finally, to convert milliliters (mL) to teaspoons (tsp), we can use the fact that 1 teaspoon is approximately equal to 5 milliliters. So, dividing the volume in milliliters by 5 gives us the volume in teaspoons:

5 mL / 5 mL/tsp = 1 tsp

Hence, the nurse will administer 1 teaspoon of acetaminophen oral suspension to the adult.

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Air has
A. a definite volume but not a definite shape
B. a definite shape but not a definite volume.
C. no definite volume or shape.
D. both a definite shape and a definite volume.

Answers

Answer would be neither!

The reason being that it can take the shape and volume of anything.

Answer:

Neither

Explanation:

Calcium carbonate decomposes into calcium oxide and carbon dioxide when heated. Calculate the mass of carbon dioxide released when 300 g of calcium carbonate is heated.

Answers

Answer: 131.9 g

Explanation:

Write a Balanced Equation for the decomposition

CaCO₃     →     CaO    +    CO₂

Find Moles of CO₂ Produced

Since the mole ratio of  CaCO₃  to CO₂ is 1 to 1,

the moles of CaCO₃ = moles of CO₂

moles of CaCO₃   = mass ÷ molar mass

                             = 300 g ÷ 100.087 g/mol

                             = 2.997 moles

∴ moles of CO₂ = 2.997 moles

Determine Mass of CO₂

Mass = moles × molar mass

         = 2.997 mol × 44.01 g/mol

         = 131.9 g

∴ when 300 g of calcium carbonate is decomposed, it produces 131.9 g of carbon dioxide.

The overall question is: What will be the approximate energy yield through aerobic metabolism, of a 22-carbon fatty acid? Describe each of the major major reactions involved. Identify the important mo

Answers

The breakdown of a 22-carbon fatty acid through aerobic metabolism via beta-oxidation and the citric acid cycle provides a substantial amount of energy in the form of ATP, allowing cells to perform various vital functions.

The approximate energy yield through aerobic metabolism of a 22-carbon fatty acid involves a series of major reactions within the mitochondria of cells. The process is known as beta-oxidation, and it generates acetyl-CoA molecules that enter the citric acid cycle (also known as the Krebs cycle) to produce ATP.

First, the 22-carbon fatty acid undergoes a series of four reactions in the beta-oxidation pathway. Each cycle of beta-oxidation removes a two-carbon acetyl-CoA molecule from the fatty acid chain, generating one molecule of NADH and one molecule of FADH2 in the process. These high-energy electron carriers will later enter the electron transport chain to produce ATP.

After the beta-oxidation process, the resulting acetyl-CoA molecules enter the citric acid cycle. In this cycle, each acetyl-CoA molecule is oxidized, leading to the production of three molecules of NADH, one molecule of FADH2, and one molecule of GTP (which can be converted to ATP). These electron carriers (NADH and FADH2) will transfer their electrons to the electron transport chain for ATP synthesis.

Finally, the electron transport chain, located in the inner mitochondrial membrane, utilizes the high-energy electrons from NADH and FADH2 to pump protons across the membrane. This establishes an electrochemical gradient that drives ATP synthesis through oxidative phosphorylation. The exact number of ATP molecules generated depends on several factors, but on average, the complete oxidation of a 22-carbon fatty acid yields approximately 129 molecules of ATP.

Overall, the breakdown of a 22-carbon fatty acid through aerobic metabolism via beta-oxidation and the citric acid cycle provides a substantial amount of energy in the form of ATP, allowing cells to perform various vital functions.

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Magnesium metal reacts with a solution of silver nitrate in a single-replacement reaction, producing aqueous magnesium nitrate and silver metal. Write the balanced equation for the reaction. If a reaction starts with 0.480 mol Mg, how many moles of silver are produced?

Answers

Answer:

0.96 mol AG

Explanation:

To see the number of atoms of an element, we need to multiply stoichiometry of that molecule to the number that is written on the foot of element. Thus the balanced reaction is

\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+2Ag\)

And the mole of silver produced from  0.480 mol is  0.96 mol    

What is Balanced equation?

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side.

The unbalanced equation is

\(\rm Mg+AgNO_{3}\rightarrow Mg(NO_{3})_{2}+Ag\)

Magnesium atoms on reactant and product side is 1.

Nitrogen atoms on reactant side is 1 and on product side it is 2 so, multiply \(AgNO_{3}\) by 2, now the reaction becomes

\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+Ag\)

Silver atom on reactant side is 2 while on product side it is 1 so, multiply Ag by 2, now the balanced equation is

\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+2Ag\)

The mole ratio of Mg to silver is 1:2

1mole of Mg produce=2 mole of Silver

0.480 mol of magnesium produce= 2×0.480=0.96 mol fo silver

Thus the balanced reaction is

\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+2Ag\)

And the mole of silver produced from  0.480 mol is  0.96 mol        

     

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A 25.0ml sample of a sample of a 30.0% hf solution has a density of 1.101g/ml. the sample is diluted to a volume of 0.0500l. what is the molarity of the final solution? (take h= 1.008, f= 19.00)

Answers

The molarity of the final solution is 27.5 M.

To find the molarity of the final solution, we need to calculate the number of moles of HF present in the 25.0 mL sample and then use that information to calculate the molarity.

Step 1: Calculate the mass of the 25.0 mL sample using its density.
Mass = Density × Volume
Mass = 1.101 g/mL × 25.0 mL
Mass = 27.525 g

Step 2: Calculate the number of moles of HF using its molar mass and mass.
Molar mass of HF = (1 × 1.008 g/mol) + (1 × 19.00 g/mol) = 20.008 g/mol
Moles = Mass / Molar mass
Moles = 27.525 g / 20.008 g/mol
Moles = 1.375 mol

Step 3: Calculate the final volume of the solution in liters.
Volume = 0.0500 L

Step 4: Calculate the molarity of the final solution.
Molarity = Moles / Volume
Molarity = 1.375 mol / 0.0500 L
Molarity = 27.5 M

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Help please, I don't understand this, and my teacher refuses to help.

Help please, I don't understand this, and my teacher refuses to help.
Help please, I don't understand this, and my teacher refuses to help.

Answers

4 moles or 68 g of ammonia reacts with 3 moles of oxygen gas or 96 g of O₂ . Then, 50 g of ammonia requires 70.5 g of oxygen gas for complete reaction.

What is balanced chemical equation ?

The balanced chemical equation of reaction represents the perfect stoichiometry of each reactants and products. The balanced equation of the given reaction is written as:

\(\rm 4 NH_{3} + 3O _{2} \rightarrow 2N_{2 }+ 6H_{2}O\)

Molar mass of ammonia = 17 g/mol

molecular mass of oxygen gas = 32 g/mol

4 moles or 68 g of ammonia reacts with  3 moles or 96 g of oxygen. Then , 50 g of ammonia needs:

(50 × 96)/68 = 70.5 g.

96 g of oxygen gas gives 56 g of nitrogen gas. Then, 75 g of oxygen gas will give:

(75 × 56)/96 = 43.75 g of N₂.

As per the balanced equation, the 68 g of ammonia gives 56 g of nitrogen gas. Then, 24 g of nitrogen gas is given by 29.1 g of ammonia.

then, mass of water formed by 29 g of ammonia is:

68 g gives 108 g of water.

( 29.14 × 108)/68 =  46.2 g.

Therefore, the mass of water formed will be 46.2 g.

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Express a mass of 0.056 mg in grams.
Answer in units of g.

Answers

Answer:

0.000056g

Explanation:

1 mg = 0.001 g

Or if it helps move your decimal sign over left 3 places.

Explain why silver iodide, Agl, a compound used in
photography, has a much higher melting point than
vanillin, C,H,O3, a sweet-smelling compound used
in flavorings.

Answers

Answer:

Vanillin consists of molecules. The attraction between particles of silver iodide is stronger than the attraction between particles of vanillin.

The silver iodide a compound used in photography because,

It affected by light.It is easily stick on the surface of photographic plate or film.

Why melting point of silver iodide has higher melting point than vanillin?The ionic compound is strong than covalent compound .So, ionic compound require more energy as compare to covalent compound to break their bond between them. So, melting point of ionic compound is higher than covalent compound .Since, silver iodide is ionic compound and  vanillin covalent compound.Therefore, melting point of silver iodide is higher than vanillin.

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As defined by Aristotle, which one of the following is an element?
1. water 2. air 3. soil 4. none of them​

Answers

Answer:

4

Explanation:

none of them

they are compounds and mixtures

Answer:

4. none of them

Explanation:

Water is a compound.

Air is a mixture.

Soil is a mixture.

None of them are elements.

What is the balanced equation for the reaction that takes place when a solution of sodium sulfate is mixed with strontium chloride?

Answers

The balanced  chemical equation for the reaction that takes place when a solution of sodium sulfate is mixed with strontium chloride is

Na2SO4 + SrCl2 → 2Nacl + SrSO4

Balanced chemical equation explained.

Balanced chemical equation is a chemical reaction in which the number of atoms and moles of the reactant side is the same as the product. This means the reactant side has equal number of atoms and moles with the product.

The balanced equation for the reaction that takes place when a solution of sodium sulfate is mixed with strontium chloride is

Na2SO4 + SrCl2 → 2Nacl + SrSO4

In this reaction, sodium sulfate with strontium chloride to form sodium chloride and strontium sulfate. The coefficients in the balanced equation indicate the stoichiometric ratios of the reactants and the products, ensuring that the same number of atoms of each element is present on both sides of the equation.

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you are given the following information at 1000 K.CaCO3(s) CaO(s) + CO2(g) K1 = 0.039C(s) + CO2(g) 2 CO(g) K2 = 1.9Determine the equilibrium constant at 1000 K for the following.CaCO3(s) + C(s) CaO(s) + 2 CO(g)

Answers

The equilibrium constant at 1000K for the reaction CaCO3(s) + C(s) --> CaO(s) + 2CO(g) is K = K1.K2 = 0,039 . 1,9 = 0,074.

The equilibrium constant at 1000 K for the given chemical reaction, CaCO3(s) + C(s) CaO(s) + 2 CO(g), can be determined as follows:

\(K1 = 0,039\\K2 = 1,9\)

We know that the equilibrium constant of a reaction is the product of the equilibrium constants of its individual steps (if the reaction is made up of more than one step) under the given conditions. Therefore, we can use the following equations to calculate the equilibrium constant of the given reaction: \(Kc = \frac{K1. K2}{Keq}\) (where Keq is the equilibrium constant of the desired reaction) \(Kc = [(P(CO))^2/(P(CaCO3).P(C))] . 0,039 . 1,9\).

Now, we have to express the pressure of all the species involved in terms of the equilibrium constant of the reaction we need to find. For this, we use the following relation:

Keq = \((P(CaO).P(CO)^2)/(P(CaCO3).P(C))\). On substituting the above expression for Keq in the expression for Kc, we get:

Kc = \([(P(CO))^2/(P(CaCO3).P(C))] . 0,039 . 1,9\)

Keq = \((P(CaO).P(CO)^2)/(P(CaCO3).P(C))\)

On comparing the expressions for Kc and Keq, we get:

\(Kc = K1 . K2/Keq\\Kc = [(P(CO))^2/(P(CaCO3).P(C))] . 0.039 . 1.9\\Kc = (P(CaO).P(CO)^2)/(P(CaCO3).P(C))\)

Therefore, we can write: \((P(CaO).P(CO)^2)/(P(CaCO3).P(C))\)

Kc =\([(P(CO))^2/(P(CaCO3).P(C))] . 0,039 . 1,9(P(CaO).P(CO)^2)/(P(CaCO3))^2\)

\(Kc = 0,039. 1,9P(CO)^2/P(CaCO3) \\Kc = 0,074251/P(CaO) \\Kc = (P(CaCO3).P(C) )/P(CO)^2.\)

Now, using the expression for Keq, we can write:

\(Keq = (P(CaO).P(CO)^2)/(P(CaCO3).P(C))\\Keq = (P(CaCO3).P(C).P(CO)^2)/(P(CaCO3).P(C))\\Keq = P(CO)^2/P(C)\\Keq = 0.07425\)

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A 10.-liter flask at a given temperature and pressure contains 6.0 × 1023 molecules of hydrogen gas. Under the same conditions of temperature and pressure, how many molecules would a 10.-liter flask of nitrogen gas contain?

Answers

Answer:

The same number of molecules, 6.0 × 10²³ molecules.

Explanation:

The amount of any given gas that can be stored in a container depends on the temperature, pressure and volume of the container. It does not depend on the nature (or identity) of the gas.

So if a 10-liter flask contains 6.0 × 10²³ molecules of hydrogen gas, it will contain the same amount of molecules of any other gas when temperature and pressure remain constant.

no links
The mass of water is 100 grams and has a specific heat capacity of 4.18 J/gC. How much energy would be required to raise the temperature from 20C to 25C?

Answers

From the calculations, the heat that is required is 2.1 kJ.

What is the specific heat capacity?

The term specific heat capacity has to do with the amount of heat that must be supplied to 1Kg of a substance in order to raise its temperature by 1K.

In this case;

H = mcdT

H = 100 grams  * 4.18 J/gC * (25 - 20)

H = 2.1 kJ

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Refer to the following balanced equation in which ammonia reacts with nitrogen monoxide to produce nitrogen and water. 4NH3(g) + 6NO(g) → 5N2(g) + 6H2O(1) How many moles of NH3 are necessary to produce 0.824 mol N2 ?

___ mol NH3 ​

Answers

Answer:

0.659 mol

Explanation:

n(NH3)/n(N2) = 4/5

n(NH3) = 4/5×0.824

= 0.659 mol

The balanced equation in which ammonia reacts with nitrogen monoxide to produce nitrogen and water. 4NH3(g) + 6NO(g) → 5N2(g) + 6H2O. 0.659 moles of NH3 are necessary to produce 0.824 mol N2.

What is balanced chemical equation ?

The term balanced chemical equation is defined as  has number atoms of each element equal on both left and right sides of the reaction.

The chemical equation must be balanced in order to obey the law of conservation of mass. When the number of different atoms of elements in the reactants side equals the number of atoms in the products side, the chemical equation is balanced.

The balanced chemical equation is as follows:

4NH3(g) + 6NO(g) → 5N2(g) + 6H2O

n (NH3) / n(N2) = 4 / 5

n (NH3) = 4 / 5 × 0.824

= 0.659 mol

Thus, 0.659 moles of NH3 are necessary to produce 0.824 mol N2.

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A student collects 25 mL of gas at 0.98 bar. What volume would this gas occupy at 1.013 bar? * 3 points 25.8 mL 24.2 mL .09 mL 34.7 mL

Answers

Answer:

24.2 mL.

Explanation:

Assuming constant temperature, we can solve this problem using Boyle's law, which states:

P₁V₁=P₂V₂

Where:

P₁ = 0.98 barV₁ = 25 mLP₂ = 1.013 barV₂ = ?

We input the data:

0.98 bar * 25 mL = 1.013 bar * V₂

And solve for V₂:

V₂ = 24.18 mL

The closest option is the second one: 24.2 mL.

Physical vs. Chemical
A physical change is a change that occurs when a substance changes composition forming one or more new substances.
O True
O False

Answers

Answer:

The answer is false.

If this answer was helpful please consider giving brainliest!

Answer:

False

Explanation:

I think it's a chemical change when the composition of a substance changes and forms a new substance

Can some please help me complete this for me it’s due today!

Can some please help me complete this for me its due today!

Answers

Answer:
Mass of (NH2)2CO formed from NH3 is 10.94g
Mass of (NH2)2CO formed from CO2 is 1.94g
Percentage yield = 82.47%

Explanation:
STEP 1
For NH3
No of moles of NH3 available for reaction = Mass/Molar mass
= 6.2/17.01
=0.3645mole
From the balanced equation of reaction, we see that 2 moles of NH3 produce 1 mole of (NH2)2CO
So, 0.3645 mole of NH3 will give 0.3645/2 moles of (NH2)2CO.
No of moles of (NH2)2CO= 0.18225mole
To find the mass of (NH2)2CO that can be produced from this, we say;
Mass = Mole × Molar mass
Mass = 0.18225mol × 60g/mol
Mass of (NH2)2CO produced from NH3 is therefore 10.94g.

For CO2
No of moles = mass/molar mass
= 1.42g/44gmol-1
= 0.03227mole
From the balanced equation of reaction, we see that 1 mole of C02 gives 1 mole of (NH2)2CO.
So, 0.03227mole of CO2 will give 0.03227mole of (NH2)2CO.
Mass of (NH2)2CO from this number of mole will then be = Mole × Molar mass of (NH2)2CO
= 0.03227 × 60
= 1.94g
The amount of (NH2)2CO formed from CO2 is therefore 1.94g

STEP 2
To calculate the percentage yield, we use;
%Yield = Actual yield/Theoretical yield × 100
The actual yield has been given to be 1.6g.
To calculate the theoretical yield, we look up to the limiting reagent of the reaction as the limiting reagent determines the extent a reaction can go.
Looking at the reactants, CO2 is the limiting reagent since it has the lowest number of mole (i.e., 0.03227mole)
So, we use this number of mole to calculate the theoretical yield of (NH2)2CO
= 0.03227mol × Molar mass of (NH2)2CO (i.e., 60gmol-1)
= 1.94g

% Yield = 1.6/1.94 × 100

% Yield = 82.47%


Select a number of substances with which KOH reacts
1) SO2, HNO3, BaCO3
OR
2) CO2, Zn(NO3)2, H3PO4

Answers

Different substances are given as SO₂, HNO₃, BaCO₃, CO₂, Zn(NO₃)₂, H₃PO₄

KOH reacts with SO₂ at a lower temperature,

KOH + SO₂ → K₂ SO₃ + H₂ O

Nitric acid (an acid) and potassium hydroxide (a base) combine to form potassium nitrate (salt) and water.

KOH + HNO₃ → KNO₃ + H₂O

When substance potassium hydroxide and Barium carbonate,

KOH + BaCO₃ → K₂ CO₃ + Ba(OH)₂

Carbon dioxide and potassium hydroxide react to produce potassium carbonate and water. Carbon dioxide is taken out of the space station using potassium hydroxide.

KOH + CO₂ → K₂ CO₃ + H₂O

Potassium hydroxide reacts with zinc nitrate,

Zn(NO₃)₂ + KOH → Zn(OH)₂ + KNO₃

Potassium phosphate and water are created when potassium hydroxide and phosphoric acid combine.

KOH (aq) + H₃ PO₄ (aq) → K₃ PO₄ (aq) + H₂O (l)

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The specific heat of aluminum is s 9.00 J/g C how much energy is needed to raise the temperature of 20.0 g block of aluminum from 22.8 C to 94.6 C

Answers

E=MC(delta)T
=20.0g x 9.00J/g x (94.4-22.8) C
= 12,924.0 J

What is the charge of cobalt in CoCl2?

Answers

Answer:

The oxidation number of cobalt is +2.

What is an action citizens can take to prevent energy waste?

Answers

Answer:

Turning the lights off when they're not needed.

The brightness of a star is determined by _____.


A. color
B. temperature
C. season
D. distance from the Earth
E. size

Answers

Answer:

Size and Temperature or E & B

Explanation:

Answer:

it is E and b I hope this helps you

Which of 2 of these will have a single covalent bond? N2, H2, O2, F2

Answers

Answer:

H2 & F2

Explanation:

A covalent bond is formed when an electron is shared between two atoms. The two electrons of the covalent bond are positioned between the nuclei of the both bonding atoms. The electron pair of the bond may be equidistant from the nucleus of the two atoms or nearer to the nucleus of one of the bonding atoms than the other depending on the relative electro negativities of the both bonding atoms.

For homonuclear covalent bonds, there is no electro negativity difference between the bonding atoms. A single line may be used to indicate the shared electron pair between the two atoms.

Hydrogen and fluorine form homonuclear covalent diatomic compounds in which only a single electron pair is shared between bonding atoms. A single covalent bond is found connecting the two bonding atoms, hence the answer.

phcl2 lewis structure

Answers

Answer:

What do you want answered?

Explanation:

is RbCl soluble or insoluble in water

Answers

Answer:

Rubidium Chloride is an excellent water soluble crystalline Rubidium source for uses compatible with chlorides.

Compound Formula: ClRb

Melting Point: 715 °C

Boiling Point: 1,390 °C

Explanation:

Choose the pair of concentrations thatcannot be in a given aqueous solution at25°C.a. [H+] = 10-3 M, [OH-] = 10-11 Mb. [H+] = 10-7 M, [OH-] = 10-7 Mc. [H+] = 10-13 M, [OH-] = 1 Md. [H+] = 10 M, [OH-] = 10-15 Me. All of these can exist

Answers

All of these can exist as the pair of concentrations in a given aqueous solution at25°C.(E)

At 25°C, the product of the concentrations of hydrogen ions and hydroxide ions in water, known as the ion product constant (Kw), is equal to 1.0 x 10^-14. This means that for any aqueous solution at 25°C, the product of [H+] and [OH-] must equal 1.0 x 10^-14.

Using this information, we can calculate the [OH-] concentration for option A, B, C and D as follows:

A) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-3 = 1.0 x 10^-11 M

B) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-7 = 1.0 x 10^-7 M

C) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-13 = 1.0 x 10^-1 M

D) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10 = 1.0 x 10^-13 M

We can see that all of the given concentrations, except for option E, satisfy the condition that the product of [H+] and [OH-] must equal 1.0 x 10^-14. Option E violates this condition and therefore cannot exist in an aqueous solution at 25°C.

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Task 3: Below are data you collected from a
reservoir. Complete tasks 3a and 3b.
Hardap Dam water parameters for different depths
taken:
Depth
Oxygen
pH
Temperature
Surface
7.5
7.9

Answers

It can be assumed that it is within the acceptable range for domestic use. Rapid temperature changes or high temperatures can also cause damage to pipes and fittings.

Task 3a: Discuss the significance of the measured water parameters collected from Hardap Dam for aquatic life.Water parameters are chemical, biological and physical characteristics of the water. They are important indicators of the quality of water. Hardap Dam is a habitat for a variety of aquatic life such as fish, birds, plants and insects. The measured water parameters for different depths include oxygen, pH and temperature.The concentration of oxygen in the water is crucial to aquatic life. Oxygen is required for respiration by aquatic animals. The surface oxygen concentration of 7.5 mg/L measured in Hardap Dam is adequate for most aquatic life. However, some fish species require higher concentrations of dissolved oxygen to survive. As water depth increases, the oxygen concentration decreases.

This can be seen in the decreasing oxygen concentration at depths below the surface. Low oxygen concentration can lead to suffocation of aquatic life, changes in species composition and nutrient cycling.PH is a measure of the acidity or alkalinity of water. Aquatic life requires a pH range of 6.5-9.0 to survive. The pH of 7.9 measured at the surface of Hardap Dam indicates that the water is slightly alkaline. The pH values for the deeper water layers were not provided but it can be assumed that they are likely to be similar. Extreme pH values can lead to stress and death of aquatic organisms.Temperature is an important parameter that influences the metabolic rates of aquatic organisms. Temperature affects the solubility of oxygen and other gases in water. It also determines the rate of biochemical reactions in organisms. The temperature of the water at the surface of Hardap Dam was not provided.

However, it can be assumed that it is within the range of tolerance for most aquatic organisms.

As water depth increases, temperature decreases. Rapid temperature changes or high temperatures can cause stress and death in aquatic organisms. Task 3b: Evaluate the significance of the measured water parameters in relation to the use of Hardap Dam water for domestic purposes.Water is a critical resource for human survival. Hardap Dam supplies water to communities for domestic purposes. The water quality is important to prevent the spread of diseases and illness. The measured water parameters for different depths of the dam include oxygen, pH and temperature.

These parameters affect the suitability of the water for domestic use.Oxygen concentration in the water is important for the removal of pollutants and odours. The surface oxygen concentration of 7.5 mg/L measured in Hardap Dam is adequate for this purpose. As the water depth increases, oxygen concentration decreases. Low oxygen concentration can lead to unpleasant tastes and odours in the water.PH is important for the taste and aesthetics of water. The pH of 7.9 measured at the surface of Hardap Dam is within the acceptable range for domestic use. Extreme pH values can cause water to taste bitter or metallic.

Changes in pH can also affect the corrosion of pipes and fittings.Temperature can affect the growth of microorganisms in the water. High temperatures can promote the growth of harmful bacteria such as E. coli. The temperature of the water at the surface of Hardap Dam was not provided. However, it can be assumed that it is within the acceptable range for domestic use. Rapid temperature changes or high temperatures can also cause damage to pipes and fittings.

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Now, using your periodic table as a reference, type the symbols for the known elements into their appropriate groups and periods in the modified table below. Note that we’re using the international group numbers (1-18), followed by the American scheme for the A-group elements in parentheses.

Answers

The symbols for some known elements using the periodic table are given below

Groups/Period

H

He

Li

Be

B

C

N

O

F

Ne

Na

Mg

Al

SI

P

S

Cl

Ar

K

CA

What is an element?

An element is a substance which cannot be split into simpler units by any ordinary chemical process

So therefore, the elements in the periodic table are classified based on their increasing atomic numbers.

The group is vertical representation of the elements

The periods is horizontal arrangements of elements in the periodic table

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Answer:

see attachment

Explanation:

plato users!!

Now, using your periodic table as a reference, type the symbols for the known elements into their appropriate

URGENT  Please I need help answering these two questions ASAP

URGENT Please I need help answering these two questions ASAP

Answers

uh I think a not too sure though
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