For the function y = (x^2 + 3)(x^3 - 4x), at (-2, 0) find the rollowing.(a) the slope of the tangent line(b) the instantaneous rate of change of the function

Answer:

See below

Step-by-step explanation:

Are you asking for the equation?

y = 2.5x + 20  

y = the total cost

x = number of movies.

Answer:

1

Step-by-step explanation: 0. 1 is a pure repeating bicimal with a repeating cycle of one digit, so the fraction it converts to is 1/1; in other words, 1

Answer:

The overall federal income tax payment for this individual would be $970 + $3,036 = $4,006. So the correct answer is A. $4,006.

Step-by-step explanation:

The individual pays $970 for the 10% tax bracket and $3,036 for the 12% tax bracket. Adding these two amounts together gives us a total federal income tax payment of $4,006.

Answer:

\(y=4x-2\)

Step-by-step explanation:

Hi there!

Slope-intercept form: \(y=mx+b\) where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

We're given that the slope is 4. Plug this into \(y=mx+b\) as m:

\(y=4x+b\)

Now, to determine the y-intercept, plug in the given point (1,2) and solve for b:

\(2=4(1)+b\\2=4+b\\b=-2\)

Therefore, the y-intercept is -2. Plug this back into \(y=4x+b\) as b:

\(y=4x+(-2)\\y=4x-2\)

I hope this helps!

\( = \frac{1}{ ({5b})^{4} } \\ = \frac{1}{ {5}^{4} b^{4} } \\ = \frac{1}{625b^{4} } \)

ATTACHED IS THE SOLUTION

Answer:

21 muffins

Step-by-step explanation:

1 cup will get you 12 muffins. Since you have 3/4 cups left over, you have to find 3/4 of 12. 1/4 is equal to 3. 3x3 equals 9. 12+9 equals 21.

Smaller sample size results in smaller sampling variation of the OLS estimator for the slope coefficient in the sample regression model due to the fact that it reduces the amount of variability in the data. Smaller error variance also reduces sampling variation as it reduces the amount of overall variation in the data.

The sampling variation of the OLS estimator for the slope coefficient in the sample regression model is affected by a variety of factors. A smaller sample size will result in smaller sampling variation because it reduces the amount of variability in the data. This is due to the fact that a smaller sample size will contain less variation in the independent variable, and therefore the estimated slope coefficient will have less variation. Additionally, a smaller error variance will also reduce the sampling variation as it reduces the amount of overall variation in the data. Finally, smaller variation in the independent variable in the sample will also lead to smaller sampling variation of the OLS estimator. This is because the slope coefficient is estimated by minimizing the sum of squared residuals, which is a function of the variation in the independent variable. Thus, if the variation in the independent variable is reduced, the slope coefficient will have less variation. In conclusion, all three factors can lead to reduction in the sampling variation of the OLS estimator for the slope coefficient in the sample regression model.

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The football travels about 29.67 meters horizontally before hitting the ground.

(a) We can find the horizontal and vertical components of the initial velocity of the football using trigonometry. Let v be the initial speed of the football, and let θ be the angle it is kicked at.

The horizontal component of the velocity is given by:

vx = v cosθ

Plugging in the values for the speed and angle, we get:

vx = 18 cos 65° ≈ 7.49 m/s

The vertical component of the velocity is given by:

vy = v sinθ

Plugging in the values for the speed and angle, we get:

vy = 18 sin 65° ≈ 16.59 m/s

So the horizontal component of the initial velocity is about 7.49 m/s, and the vertical component is about 16.59 m/s.

(b) We can find the time the football is in the air using the vertical component of the velocity and the acceleration due to gravity, which is -9.81 m/s^2 (negative because it acts downward). We can use the following kinematic equation:

vf = vi + at

where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.

When the football reaches its maximum height, its vertical velocity will be zero. We can use this to find the time it takes to reach the maximum height:

0 = vy + at_max

Solving for t_max, we get:

t_max = -vy/a = -(18 sin 65°)/(-9.81) ≈ 1.98 s

The total time the football is in the air is twice the time it takes to reach the maximum height:

t_total = 2t_max ≈ 3.96 s

So the football is in the air for about 3.96 seconds.

(c) We can find the horizontal distance the football travels before hitting the ground using the horizontal component of the velocity and the time the football is in the air. We can use the following kinematic equation:

Δx = vxt

where Δx is the distance traveled, vx is the horizontal component of the velocity, and t is the time.

Plugging in the values for vx and t, we get:

Δx = (7.49 m/s) × (3.96 s) ≈ 29.67 m

So the football travels about 29.67 meters horizontally before hitting the ground.

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Answer:

where is the question

Step-by-step explanation:

send me the question on comment and i will solve it for you

The average velocity for the [3,4] is 27m/s and for [4,5] is 37m/s

The average velocity can be found by taking the derivative of the position function and evaluating it at the midpoint of the interval.

The average velocity on the interval [3,4] is given by (s(4) - s(3)) / (4 - 3), which is equal to (s(4) - s(3)) / 1. Using the position function, s(t) = 5t^2 - 8t + 13, we find that s(4) = 5(4²) - 8(4) + 13 = 61 and s(3) = 5(3²) - 8(3) + 13 = 34. Therefore, the average velocity on the interval [3,4] is (61 - 34) / 1 = 27 m/s.

The average velocity on the interval [4,5] is given by (s(5) - s(4)) / (5 - 4), which is equal to (s(5) - s(4)) / 1. Using the position function, s(t) = 5t² - 8t + 13, we find that s(5) = 5(5²) - 8(5) + 13 = 98 and s(4) = 5(4²) - 8(4) + 13 = 61. Therefore, the average velocity on the interval [4,5] is (98 - 61) / 1 = 37 m/s.

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g(4) = 1 * g(4), which means that q(4) is equal to g(4). y(-4) = f(-4) * h(-4) = 1 * (-4) = -4. Therefore, the values of q(4), y(-4), and y(4) are determined as follows: q(4) = g(4), y(-4) = -4, and y(4) = 0.

For the first part of the problem, we are given f(t) = u(t), g(t) = 2tu(t), and g(t) = f(t - 1) * g(t). To determine q(4), we need to substitute t = 4 into the equation g(t) = f(t - 1) * g(t). This gives us g(4) = f(3) * g(4). Since f(t) = u(t), we know that f(3) = u(3) = 1 because u(t) is a unit step function that equals 1 for t ≥ 0. Therefore, we have g(4) = 1 * g(4), which means that q(4) is equal to g(4).

For the second part of the problem, we are given f(t) = u(-t), h(t) = tu(-t), and y(t) = f(t) * h(t). To determine y(-4) and y(4), we substitute t = -4 and t = 4 into the equation y(t) = f(t) * h(t). For y(-4), we have y(-4) = f(-4) * h(-4). Since f(t) = u(-t), we have f(-4) = u(4) = 1 because u(t) is a unit step function that equals 1 for t ≥ 0. Similarly, h(-4) = -4u(4) = -4. Therefore, y(-4) = f(-4) * h(-4) = 1 * (-4) = -4.

Similarly, for y(4), we have y(4) = f(4) * h(4). Since f(t) = u(-t), we have f(4) = u(-4) = 0 because u(t) is a unit step function that equals 0 for t < 0. Thus, y(4) = f(4) * h(4) = 0 * h(4) = 0.

Therefore, the values of q(4), y(-4), and y(4) are determined as follows: q(4) = g(4), y(-4) = -4, and y(4) = 0.

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If an airplane flies a total distance of 450km in 3/4 hours, the plane is traveling at an average speed of 600 kilometers per hour.

The average speed refers to the quotient of the total distance divided by the total time used by the airplane to cover the distance.

Based on the distance, time, and speed equation, we can state that there exists an equation relationship, which is given as distance = time x speed.

The total distance flown by airplane = 450 kilometers

The total time used by the airplane to travel the distance = ³/₄ hours or 0.75 hours

Thus, the average speed of the airplane is 600 kilometers per hour (450 ÷³/₄).

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Answer:

Is this what you meant?

(2x + 3x) × (3 + 15) = 12x + 36

(5x) × (18) = 12x + 36

90x = 12x + 36

78x = 36

x = 36 / 78

x = 18 / 39

_____________________

or

3(2x+3x) + 15 = 12x + 36

10x + 15 = 12x + 36

-21 = 2x

2x = -21

x = -21/2

Answer:

y = 2x + 2

Step-by-step explanation:

Add two to both sides.

Answer:

=4/5(N+7)N

Step-by-Step Explanation:

We move all terms to the left:

-(4/5(N+7)N)=0

Domain of the equation: 5(N+7)N)!=0

N∈R

We multiply all the terms by the denominator

-(4=0

We add all the numbers together, and all the variables

=0

N=0/1

N=0

\( \fbox{(2,5)}\)

Hello, substitute all the given coordinates & see if RHS match with LHS

given equation,

y = 4x-3

First coordinate,

(x,y) = (2,5)

5= 4×2-3

5=5

Hence, first solution satisfies the given equation,

let's solve for rest other cordinates,

second coordinate,

(x,y) = (5,5)

5= 4×5-3

5 ≠ 17

does not satisfy,

third coordinate,

(x,y) = (4,5)

5= 4×4-3

5 ≠ 13

does not satisfy,

fourth coordinate,

(x,y) = (4,5)

5 = 4×3-3

5 ≠ 9

does not satisfy.

Hence the correct answer is (2,5)

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The level of significance in a hypothesis test is the maximum allowable probability of a Type I error. A Type I error occurs when you reject a null hypothesis that is actually true.

The level of significance is usually denoted by the symbol α (alpha) and is expressed as a percentage or a decimal value, such as 5% or 0.05. This means that if the level of significance is set at 5%, there is a 5% chance of making a Type I error when the null hypothesis is true.
To answer the student question, the level of significance is not the same as the confidence coefficient or the p-value. The confidence coefficient is related to the confidence interval, which is a range of values within which the true population parameter is likely to fall. The confidence coefficient (1 - α) represents the probability that the true population parameter lies within the confidence interval.
The p-value, on the other hand, is the probability of obtaining a test statistic as extreme or more extreme than the one observed, assuming the null hypothesis is true. If the p-value is less than or equal to the level of significance, you reject the null hypothesis and accept the alternative hypothesis.
Lastly, the maximum allowable probability of a Type II error (denoted by β) is not the same as the level of significance. A Type II error occurs when you fail to reject a null hypothesis that is actually false. The power of a test is defined as (1 - β) and represents the probability of correctly rejecting a false null hypothesis.

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In school suspension

Answer:

Sorry please accept i need points for an answer

Step-by-step explanation:

Answer:

Answer is option A

Step-by-step explanation:

The required function [f o g(x)] is -7/√(x + 3).

The domain of the function  [f o g(x)] > - 3.

A function is  the relation between two sets. The first one is called domain and the second one is called range.

Given, f(x) = - 7/x

g(x) = √(x + 3)

Therefore, f o g(x)

= f[g(x)]

= f[√(x + 3)]

= -7/√(x + 3)

Now, the domain of f o g(x) > - 3.

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Answer:

-3k + 10

Step-by-step explanation:

you have to combine -8 and 2 because they are like terms, but since -8 is being subtracted from -3k the minus sign and the negative sign basically combine to make a positive sign so it would make it -3k + 8 + 2 which gives you -3k + 10

Answer: Heyaa! ~

Your Answer is... − 3k+10

Step-by-step explanation:

Hopefully this helps you! ~

The critical value zₐ/₂ that corresponds to an 83% level of confidence is approximately 1.381.

To find the critical value zₐ/₂, we need to determine the value that leaves an area of (1 - α)/2 in the tails of the standard normal distribution. In this case, α is the complement of the confidence level, which is 1 - 0.83 = 0.17. Dividing this value by 2 gives us 0.17/2 = 0.085.

To find the z-value that corresponds to an area of 0.085 in the tails of the standard normal distribution, we can use a standard normal distribution table or a statistical calculator. The corresponding z-value is approximately 1.381.

Therefore, the critical value zₐ/₂ that corresponds to an 83% level of confidence is approximately 1.381.

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Answer:

There are 10 cards in the stack, and 5 of them are odd (1, 3, 5, 7, and 9). There are 3 cards (1, 2, and 3) that are less than 4. Since we are replacing the first card before selecting the second, the outcomes are independent and we can multiply the probabilities of each event.

The probability of selecting an odd card on the first draw is 5/10, or 1/2.

The probability of selecting a card less than 4 on the second draw is 3/10, since there are 3 cards that meet this condition out of a total of 10.

Therefore, the probability of selecting an odd card on the first draw and a card less than 4 on the second draw is:

(1/2) x (3/10) = 3/20

So the probability of selecting an odd card on the first draw and a card less than 4 on the second draw is 3/20.

Step-by-step explanation:

Answer:

3/20.

Step-by-step explanation:

To find the probability of two independent events happening together, we multiply their individual probabilities. The probability of the first card being an odd number is 5/10, because there are 5 odd numbers out of 10 cards. The probability of the second card being less than 4 is 3/10, because there are 3 cards (1, 2, and 3) that are less than 4 out of 10 cards. Therefore, the probability of the first card being an odd number and the second card being less than 4 is:

5/10 x 3/10 = 15/100

We can simplify this fraction by dividing both the numerator and denominator by 5:

15/100 = 3/20

So, the final answer is 3/20.

Received message. To find the probability of two independent events happening together, we multiply their individual probabilities. The probability of the first card being an odd number is 5/10, because there are 5 odd numbers out of 10 cards. The probability of the second card being less than 4 is 3/10, because there are 3 cards (1, 2, and 3) that are less than 4 out of 10 cards. Therefore, the probability of the first card being an odd number and the second card being less than 4 is: 5/10 x 3/10 = 15/100 We can simplify this fraction by dividing both the numerator and denominator by 5: 15/100 = 3/20 So, the final answer is 3/20.

Given:

The figure of a right angle triangle, we hypotenuse \(\sqrt{113}\) mi and perpendicular 9 mi.

To find:

The length of the unknown leg in the right triangle.

Solution:

According to the Pythagoras theorem,

\(Hypotenuse^2=Perpendicular^2+Base^2\)

Using Pythagoras theorem, we get

\((\sqrt{113})^2=(9)^2+a^2\)

\(113=81+a^2\)

\(113-81=a^2\)

\(32=a^2\)

Taking square root on both sides.

\(\sqrt{32}=a\)

It is only positive because the side length cannot be negative.

The length of the unknown leg in the right triangle is \(\sqrt{32}\) mi.

Therefore, the correct option is B.

Answer:

Step-by-step explanation:

Answer:

16.802

Step-by-step explanation:

I just used a calculator

Answer:

f(x)= -2/5x-4

Step-by-step explanation:

-2/5 is the slope and -4 is the y intercept