For the following exercises, determine whether the graphs of the polar equation are symmetric with respect to the x-axis, the y-axis, or the origin. r² = 3 cos(70) x-axis y-axis origin

Answer:

9.7%

Step-by-step explanation:

Last week the 100% cost was $31

Now it's $34, we just have to find that % cost first. A ratio is in hand

100%. x

--------. = ----------

$31. $34

Cross multiplying we get

(34)(100) = 31x

31x = 3400

Dividing both sides by 31

x = 3400/31

x = 109.7%

Now that we see that it was raised to 109.7, we can subtract this from 100% to get

9.7% increase

Answer:

110000

Step-by-step explanation:

first, expand 10^5, which is 100000

use a calculator (or long multiplication) to multiply 1.1*100000, which is 110000

Answer:

100 miles (A)

Step-by-step explanation:

determine where the lines intersect.

The proof that if bisector of an exterior angle of a triangle is parallel to a side of triangle, triangle is isosceles is shown below .

In the question ,

it is given that ,

the angle bisector of the exterior angle of a triangle is parallel to a side .

we have to prove that the triangle will be an isosceles triangle .

In the triangle ABC given below , AB is extended to AD ,

SO , the exterior angle will be angle DAC ,

let AE be the bisector of the the angle .

So , the equal angles are angle DAC and angle EAC .

it is given that AE is parallel to BC , where BC is base .

we know that ,

if any line intersects two parallel lines then every pairs of alternative  Interior angles are same and also their corresponding angles are equal .

Here AE is parallel to BC and line BD intersects them ,

So , angle ABC = angle DAE    ( corresponding angles )

angle ACB = angle EAC   ( alternate angles )

Now , as AE is the bisector of angle DAC ,

we have , angle DAC = angle EAC

So , we get , angle ABC = angle ACB .

In triangle triangle ABC two angles are equal so , the sides opposite to angles to angles will also be equal

that means , AB=AC

Hence , the given Triangle is an isosceles triangle .

Therefore , it is proved that the triangle ABC is an isosceles triangle .

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Answer:

16.75

Step-by-step explanation:

3/4+8(2.5-0.5)

3/4+8(2)

0.75+16

16.75

Answer:

The answer is D. or 16 3/4

Step-by-step explanation:

Answer:

The exact amount of British pounds would be 81.769

Step-by-step explanation:

Answer:

81.769 is the answer

Step-by-step explanation:

The correct conclusion is:

"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."

Given,

At a huge institution, a doctor is determining the typical height of the male students.

Inches are used to measure the heights of a sample of 40 male baseball team players.

The doctor computes the 95% confidence interval using this information (63.5, 74.4).

The following conclusions is valid:

"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."

We can guarantee that the target variable will be within the confidence interval for a given confidence level since we know the confidence interval reflects an interval.

The true mean of heights for male students at the college where the doctor measured heights is represented by the provided case's confidence level of 95% and confidence interval of (63.5, 74.4).

The doctor is therefore 95% certain that the range of the mean height of male students at the college is valid (63.5, 74.4).

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Answer:

7+3 = 10

Step-by-step explanation:

if I understand the problem strangeness right, and there is nothing missing in it, then this is the simple answer.

the difference of 12 and 9 is 12-9 = 3.

and then adding this 3 to 7 is 7+3 =10

Answer:

10

Step-by-step explanation:

The difference of 12 and 9 is 3.

Now,

If we add 7 to 3, the answer is 10.

Letter is of two kinds which is formal letters and informal letters.

Dear Mom,
I hope this letter finds you well. I have been fighting for the Union for the past year and it has been tough. Life as a soldier is not easy, we are constantly on the move and the conditions are not ideal. We have to sleep on the ground and we often go days without a hot meal. The war has been brutal, I have seen so much death and destruction. I miss you and the rest of the family dearly. Please take care of yourselves and know that I am fighting for a better future for all of us.
Love,
Your son
Dear John,
I hope this letter finds you safe. I am writing to you from our farm in the south. Life here has been difficult since the war started. We are constantly in fear of Union troops coming and taking our supplies. We have had to make do with less and less each day. My husband was conscripted into the Confederate army and has been gone for months now. I worry for his safety every day. Our son has been helping me on the farm and it is a struggle to keep up with the work. Please stay safe and come home to us soon.
Sincerely,
Mary

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Answer:

m=5

Step-by-step explanation:

1. Convert the logarithm into exponential form using the fact that \(log_{a}\)(x)=b is equal to x=\(a^{b}\) so ... 4m-10=\(10^{1}\)

2. Any expression raised to the power of 1 equals itself so ... 4m-10=10

3. Move the constant to the right-hand side and change its sign so ... 4m=10+10

4. Add the numbers so ... 4m=20

5. Divide both sides of the equation by 4 so ... m=5, m>\(\frac{5}{2}\)

6. Check if the solution is in the defined range so ... m=5

The one-step-ahead demand forecast for a part can be determined using forecasting methods such as moving averages, exponential smoothing, or regression analysis.

the question mentions "observations of the demand for a certain part stocked at a parts supply depot during the calendar year 1999." From this, we can assume that the demand for this part was recorded over the course of the year.

The question also mentions "one-step-ahead demand forecast" without providing further details. In general, a one-step-ahead demand forecast is a prediction of the demand for a certain period based on historical data.

To determine the one-step-ahead demand forecast, you would typically use forecasting methods such as moving averages, exponential smoothing, or regression analysis. These methods analyze the historical demand data and use it to predict future demand.

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True, a probability/impact matrix or chart lists the relative probability of a risk occurring on one side of a matrix or axis on a chart and the relative impact of the risk occurring on the other.

A probability/impact matrix or chart is a useful tool in risk management and analysis.

It helps organizations evaluate and prioritize risks by considering their probability of occurrence and potential impact if they do occur.

The matrix/chart typically presents a grid or axis with different levels of probability and impact.

The probability of a risk refers to how likely it is to happen, while the impact represents the potential consequences or severity of the risk.

By plotting risks on the matrix/chart, organizations can visually assess and compare the risks based on their probability and impact.

This helps in identifying high-priority risks that require immediate attention and mitigation efforts.

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Step-by-step explanation:

Given

A semi-circle is placed over a rectangle

width of the rectangle is w=1.5 cm

The length of the rectangle is l=9.2 cm

from the figure, we can write

\(\Rightarrow 9.2=2.5+2r\quad (\text{length of rectangle is equal})\)

where r=radius of the semi-circle

\(\Rightarrow 2r=6.7\\\Rightarrow r=3.35\ cm\)

Perimeter of figure

\(\Rightarrow 9.2+1.5+2.5+\pi r+1.5\\\Rightarrow 14.7+10.52=25.22\ cm\)

Area of the figure

\(\Rightarrow A=\text{Area of rectangle+Area of semi-circle}\\\Rightarrow A=1.5\times 9.2+\pi \times 3.35^2\\\Rightarrow A=13.8+35.26=49.06\ cm^2\)

Answer:

He is not correct.

Step-by-step explanation:

he should have done

4(x-1) = -1(6x-36)

=> 4x-4 = -6x+36

=> 4x-4+4 = -6x +36+4

=> 4x+6x = -6x+6x+40

=> 10x = 40

=> (10x)/10 = 40/10

=> x = 4.

When a point on a triangle is dilated, the coordinate of the vertex changes

The coordinate of the vertex after the dilation is (-1.5,4)

The given parameters are:

(x,y) = (-3,8)

k = 0.5

To calculate the coordinate of the vertex after the dilation, we make use of:

(x,y)' = k * (x,y)

So, we have:

(x,y)' = 0.5 * (-3,8)

Evaluate the product

(x,y)' = (-1.5,4)

Hence, the coordinate of the vertex after the dilation is (-1.5,4)

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Answer: 5

Step-by-step explanation:

4 times 5 equals 20.

I hope this helps!

Answer:

35cm

Step-by-step explanation:

Answer:

35 :)

Step-by-step explanation:

mutiply by the length 7 and the 5 width

(a) shows that {0} ∪ V is a subspace of Rp, and (b) proves that if λ is an eigenvalue of A, then it is also an eigenvalue of A.

(a) To show that {0} ∪ V is a subspace of Rp, we need to demonstrate three properties: closure under addition, closure under scalar multiplication, and the presence of the zero vector.

1. Closure under addition: Let u and v be vectors in V. Since they are eigenvectors associated with the eigenvalue λ, we have Au = λu and Av = λv. Now, consider the vector w = u + v. We can express w as follows:

Aw = A(u + v) = Au + Av = λu + λv = λ(u + v) = λw.

Therefore, w is also an eigenvector associated with λ, and it belongs to V. This shows closure under addition.

2. Closure under scalar multiplication: Let u be a vector in V, and let c be a scalar. Since u is an eigenvector associated with the eigenvalue λ, we have Au = λu. Now, consider the vector w = cu. We can express w as follows:

Aw = A(cu) = cAu = c(λu) = λ(cu) = λw.

Therefore, w is also an eigenvector associated with λ, and it belongs to V. This shows closure under scalar multiplication.

3. Zero vector: The zero vector, denoted as 0, is in {0} ∪ V since 0 is an eigenvector associated with any eigenvalue. If we apply A to the zero vector, we get A0 = 0, which means 0 is also an eigenvector associated with λ. Therefore, the zero vector is in {0} ∪ V.

Since {0} ∪ V satisfies all the properties of a subspace, it is indeed a subspace of Rp.

(b) To prove that if λ is an eigenvalue of A, then it is also an eigenvalue of A, we need to show that there exists a non-zero vector v such that Av = λv.

Let v be an eigenvector associated with λ. Since v is non-zero, we have Av = λv, which satisfies the definition of an eigenvalue. Therefore, if λ is an eigenvalue of A, it is also an eigenvalue of A.

In summary, (a) shows that {0} ∪ V is a subspace of Rp, and (b) proves that if λ is an eigenvalue of A, then it is also an eigenvalue of A.

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Answer:

Should be a collective noun.

For example: In addition to those...

Answer:

None

Step-by-step explanation:

It would be easier to ask your teacher instead of getting wrong answers from random people. Ever think of that :0

Answer:

1: 5/6

2: 3 1/6

3: 12/25

hope this helps!!

p.s

    comment if wrong

Answer:

16% drop

Step-by-step explanation:

4/25 drop

Multiply by 4/4

16/100

16% drop

Answer:

16%

Step-by-step explanation:

SInce 4 students left the class, and there are 25 students, let's make it a fraction.

4/25.

As it is asking for a percentage though we could simply convert our fraction to a percentage.

Simply divide the numerator (4) by the denominator (25).

This gives us 0.16.

Which is 16%.

Answer:

\(\displaystyle{y-1=5(x+6)}\)

Step-by-step explanation:

A point-slope form is written in the equation of  \(\displaystyle{y-y_1=m(x-x_1)}\). Where \(\displaystyle{(x_1,y_1)}\) is a coordinate point and \(\displaystyle{m}\) is slope.

The definition of parallel is to both lines have same slope. The given line equation has slope of 5. Therefore, we can write the equation in point-slope form as:

\(\displaystyle{y-y_1=5(x-x_1)}\)

Next, we are also given the point p(-6,1). Substitute \(\displaystyle{x_1}\) = -6 and \(\displaystyle{y_1}\) = 1 in:

\(\displaystyle{y-1=5[x-(-6)]}\\\\\displaystyle{y-1=5(x+6)}\)

Hence, the line equation that’s parallel to y = 5x - 4 and passes through a point (-6,1) is y - 1 = 5(x + 6)

Answer:

y - 1 = 5 ( x + 6 )

Step-by-step explanation:

       Here,

          m ⇒ slope

    y = 5x - 4 ← equation of the old line

         Now it is clear to us that,

         m ⇒ slope of the line ⇒ 5

         c  ⇒ y-intercept ⇒ -4

                 That is, m = 5

                   y - y₁ = m ( x - x₁ ).

        m = slope

           ( -6 , 1 ) ⇔ ( x₁ , y₁ )

        Let us solve this now

         y - y₁ = m ( x - x₁ )

         y - 1 = 5 ( x - ( -6) )

         y - 1 = 5 ( x + 6 )

                y - 1 = 5 ( x + 6 )