For every two QH2 that enter the Q cycle, one is regenerated and the other passes its two electrons to two cytochrome c1 centers. The overall equation is
QH2+2 cyt c1(Fe3+)+2H+→Q+2 cyt c1(Fe2+)+4H+
Calculate the free energy change associated with the Q cycle.

Answers

Answer 1

For every two QH2 that enter the Q cycle, one is regenerated and the other passes its two electrons to two cytochrome c1 centers. The free energy change associated with the Q cycle is -33.8 kJ/mol

Q + 2H+ + 2 e- --> QH2 Eo' = +0.045 V

One QH2 is created for every two that enter the Q cycle, while the other one transfers its two electrons to two cytochrome c1 centers. Even though cytochrome c can only take one electron, QH2 struggles to transfer  free energy the two available electrons to it. So, in a single Q cycle, two cytochrome c molecules are reduced, one ubiquinol molecule is created, four bare pumped into the intermembrane  free energy space, and two protons are taken up from the matrix.

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Related Questions

What new evidence led scientists to change their minds about the geocentric model?

Answers

Galileo disproved the Ptolemaic theory, sanctioned for centuries by the Church, which held the Earth to be the central and principal object in the universe, about which all celestial objects orbited.

The new evidence led scientists to change their minds about the geocentric model is that the Sun and stars move across the sky in the same direction everyday. They appear to be going around the Earth. However, Galileo observed moons which orbited Jupiter. This suggests that not everything orbits the Earth and that the geocentric model is not correct.

What is Geocentric Model?

Geocentric model is any theory of the structure of the solar system (or the universe) in which Earth is assumed to be at the centre of it all.

This model is  often named Ptolemaic model after its most famous supporter, the Greco-Roman astronomer Ptolemy.

The geocentric is often referred to as the Medieval view of the universe and it dominated thinking into the early modern age.

Therefore, The new evidence led scientists to change their minds about the geocentric model is that the Sun and stars move across the sky in the same direction everyday. They appear to be going around the Earth. However, Galileo observed moons which orbited Jupiter. This suggests that not everything orbits the Earth and that the geocentric model is not correct.

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What is the correct order for the first three steps of the scientific method?
A. State the question, conduct an experiment, form a hypothesis
B. Form a hypothesis, form a conclusion, conduct an experiment
C. Conduct an experiment, form a hypothesis, analyze the data
D. State the question, form a hypothesis, conduct an experiment
SUBMIT

Answers

Answer:

D.) State the question, form a hypothesis, conduct an experiment

Explanation:

https://www.colorincolorado.org/article/steps-scientific-process

Which two elements have the same number of dots around their chemical
symbols in their electron dot diagrams?
A. P and S
B. Si and As
C. P and As
D. Al and Ge

Answers

Answer:si and ge

Explanation:

Both silicon (Si) and arsenic (As) have 5 valence electrons. This means that they both have 5 dots around their chemical symbols in their electron dot diagrams. Thus, option B is correct. The images are attached below.

Phosphorus (P) has 5 valence electrons, but it also has a ground state electron configuration of 1s²2s²2p⁶3s²3p³. This means that phosphorus has 3 dots around its chemical symbol in its electron dot diagram, and 2 dots that are not shown.

Sulfur (S) has 6 valence electrons, but it also has a ground state electron configuration of 1s²2s²2p⁶3s²3p⁴. This means that sulfur has 4 dots around its chemical symbol in its electron dot diagram, and 2 dots that are not shown. Thus, option B is correct.

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Which two elements have the same number of dots around their chemicalsymbols in their electron dot diagrams?A.
Which two elements have the same number of dots around their chemicalsymbols in their electron dot diagrams?A.

True or Fasle: Kinetic-molecular theory assumes that attractive and repulsive forces between gas
particles are stronger than those between gas particles and container walls.

Answers

The statement that Kinetic-molecular theory assumes that attractive and repulsive forces between gas particles are stronger than those between gas particles and container walls is false.

Kinetic-molecular theory simply explains that gas particles are typically in constant motion and that they also have perfectly elastic collisions.

Kinetic-molecular theory doesn't assume that attractive and repulsive forces between gas particles are stronger than those between gas particles and container walls.

Lastly, in kinetic-molecular theory, the particles exert no force on each other.

In conclusion, the correct option is false.

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which of the following statements is/are true for a 0.10 m solution of a strong acid (HA)?

Answers

The question is incomplete; the complete question is;

Which of the following statements is/are true for a 0.10 M solution of a weak acid HA?

a. [ H+] >> [ A−]

b. [ H+] = [ A−]

c. The pH is 1.00.

d. The pH is less than 1.00.

Answer:

b. [ H+] = [ A−]

Explanation:

Given the acid as HA, we know that being a weak acid, its dissociation in water can never be 100%. If it were a strong acid, then it could have undergone a 100% dissociation in solution. The conjugate base of a weak acid is a always a weak base hence A^- is expected to act as a weak base. At the same concentration, weak acids have a higher pH value than strong acids. Hence if the pH of a strong acid HA is 1, then the pH of a weak acid HA must be greater than 1.

But, we look at the equation for the dissociation of the weak acid HA

HA(aq)⇄H^-(aq) + A^-(aq). This implies that the HA dissociates in a 1:1 ratio therefore; [H+] = [ A−], hence the answer given above.

Balance the redox reaction below in basic solution.PbO2(s) + I-(aq) --> Pb2+(aq) + I2(s)How many OH- ions are in the final balanced equation?

Answers

The balanced redox reaction is PbO2+2I-+4H+---Pb2+ +I2+4H2O and the number of OH- in the final balanced equation is 4

The two Half Cell reactions are as,

Reduction:                   PbO₂  +  2e⁻   →     Pb²⁺  

As it is a medium acidic reaction, so add H⁺ on the reactant side as it has more number of oxygen atoms and add OH- on the product side, and balance the elements, So,

                            4 H⁺     +   PbO₂  +  2e⁻   →     Pb²⁺   +    4OH-     (1)

Oxidation:                        I⁻     →     I₂   +  1e⁻

Balance the Number of elements along with electrons,

  2 I⁻     →     I₂   +  2e⁻                                    (2)

Compare eq. 1 and 2,

                            4 H⁺     +   PbO₂  +  2e⁻   →     Pb²⁺   +    4OH-

                                                          2 I⁻     →     I₂   +  2e⁻

                           ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

                           PbO₂  +  2 I⁻  +  4 H⁺     →     Pb²⁺  +  I₂  + 4OH-

The number of OH- ions is 4

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When a certain nuclide undergoes alpha emission, astatine-217 is produced. What is the identity of the nuclide that underwent decay?
a. actinium-219
b. francium-217
c. francium-221
d. astatine-221
e. actinium-221
Please explain the answer

Answers

Answer:

C: francium-221

Explanation:

First of all to get a broader perspective, every isotope of francium usually undergoes decay to form astatine, radium, or radon.

Now, Francium-223 and francium-221 are it's only isotopes that occur in nature.

However, francium-221 is the one that undergoes alpha decay to produce astatine-217.

CAN SOMEONE HELP WITH THIS QUESTION?✨

CAN SOMEONE HELP WITH THIS QUESTION?

Answers

The quantity of the product obtained from the reaction is generally expressed in terms of the yield of the reaction. The amount obtained actually is called the actual yield.

What is theoretical yield?

The amount of the product which is predicted by the stoichiometry is called the theoretical yield. A reaction yield is reported as the percentage of the theoretical amount.

The percentage yield is the ratio of actual yield to the theoretical yield.

% yield = Actual yield / Theoretical yield × 100

a. Molar mass of PbCO₃ = 267.21 g/mol

Molar mass of PbCl₂ = 278.1 g/mol

2.871 g of PbCO₃ gives:

2.871 × 278.1 / 267.21 = 2.988 g  PbCl₂

b. % yield = 2.385 / 2.988 × 100 = 79.82 %

Thus the theoretical yield is 2.988 g and the % yield is 79.82 %.

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does a light bulb collect energy?NEED HELP ASAP

Answers

classic light bulb running for a full year would use up 876 kWh of energy so yes it does collect energy

7) Calculate the density of helium (in g/L) if a balloon with a capacity of 5.00 L holds 0.890 g.

Answers

Answer:

Density is m/V. Also, 1 liter = 1000 . So, we get 0.890/(5*1000) = g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.

Which of the following is the stronger acid in
the acid-base equilibrium H3O*+I¯¯ ≤ H₂O +
HI?

Answers

H3O+ is the strongest acid and OH− is the strongest base that can exist in equilibrium with H₂O.

What equilibrium means in chemistry?

A reversible chemical reaction is said to be in chemical equilibrium when there is no net change in the quantity of reactants or products. When a chemical reaction is reversible, the products is react with the original reactants as soon as they are created.

Why is equilibrium important in chemistry?

We may get a sense of where the equilibrium is by using the equilibrium constant. The closer the equilibrium is to the products, the larger the equilibrium constant.

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which of the following choices provides the most probable values for the first four ionization energies of aluminum

Answers

The  most probable values for the first four ionization energies of the aluminum are : IE₁ = 578 kJ/mol, IE₂ = 1817 kJ/mol, "IE₃ = 2745 kJ/mol", IE₄ = 11577 kJ/mol.

The ionization energy is the amount of the energy required to remove the electron from an atom. The electronic configuration of Al is given as :

Al electronic configuration = 1s² 2s² 2p⁶ 3s² 3p¹. The fourth ionization energy is comparatively high because the 2p subshell is fully filled and the energy required to remove the electron from the stable electronic configuration will be high. Therefore, the fourth ionization energy is high.

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identify the example of a physical change. please choose the correct answer from the following choices, and then select the submit answer button. answer choices the formation of ash as a piece of wood burns the formation of a yellow solid when two colorless liquids are mixed the formation of sugar crystals as water evaporates from a mixture of sugar and water the formation of bubbles as baking soda and vinegar are mixed

Answers

The combustion of wood results in the generation of new substances such as carbon dioxide gas, water vapor, ash, and so on. Some compounds do not completely burn or do not react at all, resulting in the formation of fire ash.

When we burn wood, it transforms into ashes, a new material, and the process is irreversible, resulting in a chemical shift. No new material is generated while chopping the wood into little pieces. It is a bodily transformation. When two colorless liquids are put together, the creation of a solid precipitate indicates the presence of a chemical reaction. When a colorless solution of lead(II) nitrate is added to a colorless solution of potassium iodide, an immediate yellow solid known as a precipitate is formed. Dense hardwood species, such as maple and oak, contain more energy, burn hotter and slower, and release more heat, resulting in longer-lasting fires and coal beds. Because softwoods are less thick than hardwoods, they burn quicker in short-lived flames.

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Use the periodic table or graphic in lesson. Choose the correct electron configuration of carbon. 1s 22s 22p 4 1s 22s 22p 2 1s 22s 22p 1 1s 22s 12p 2

Answers

The Correct electron configuration of carbon as 1s² 2s² 2p². Option B.

To understand why this is the correct electron configuration, let's break it down step by step:

The atomic number of carbon is 6, which means it has six electrons. Electrons are distributed in energy levels or shells around the nucleus.

The first shell, known as the 1s orbital, can hold a maximum of 2 electrons. Therefore, the first part of the electron configuration is 1s², indicating that two electrons occupy the 1s orbital.

The second shell has two subshells: the 2s orbital and the 2p orbital. The 2s orbital can hold a maximum of 2 electrons, while the 2p orbital can hold a maximum of 6 electrons. In the case of carbon, after the 1s orbital, two more electrons occupy the 2s orbital. So far, we have 1s² 2s².

The remaining two electrons in carbon are placed in the 2p orbital. The 2p orbital consists of three separate p orbitals: 2px, 2py, and 2pz. Each p orbital can hold a maximum of 2 electrons. Therefore, the last part of the electron configuration for carbon is 2p², indicating that two electrons occupy the 2px and 2py orbitals. Option B is correct.

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Why does a floating leaf indicate photosynthesis has occurred

Answers

This is because leaves have air in the spaces between cells, which helps them collect CO2 gas from their environment to use in photosynthesis.

1. surpose you are provided with a salt solution briefly explain how to serperate the pure water from the solution using the simple distillation method.

2.surpose you are provided with a solution alcohol and water briefly explain how would you use simple distillation to serperate pure alcohol from the solution .

3.what is the difference between crystallization and simple distillation related to tge salt solution ​

Answers

Answer:

1. pure water and salt mixture is first heated until salt appears then the mixture is poured using filter paper.

In a titration 32.5 mL of 1.0 M sulfuric acid is required to neutralize 45.0 mL of sodium hydroxide. What is the concentration of the base?

Answers

Answer:

\(\large \boxed{\text{1.4 mol/L}}\)

Explanation:

(a) Balanced equation

2NaOH + H₂SO₄ ⟶ Na₂SO₄ + 2H₂O  

(b) Moles of H₂SO₄

\(\text{Moles of H$_{2}$SO}_{4} = \text{32.5 mL H$_{2}$SO}_{4} \times \dfrac{\text{1.0 mmol H$_{2}$SO$_{4}$}}{\text{1 mL H$_{2}$SO$_{4}$}}\\= \text{32.5 mmol H$_{2}$SO}_{4}\)

(c) Moles of NaOH

The molar ratio is 2 mol NaOH:1 mol H₂SO₄.

\(\text{Moles of NaOH} = \text{32.5 mmol H$_{2}$SO}_{4} \times\dfrac{\text{2 mmol NaOH}}{\text{1 mmol H$_{2}$SO}_{4}}\\\\= \text{65 mmol NaOH}\)

(d) Molar concentration of NaOH

\(c = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{n}{V}\\\\c= \dfrac{\text{65 mmol}}{\text{45.0 mL}} = \text{1.4 mol$\cdot$L$^{-1}$}\\\\\text{The molar concentration of the NaOH is $\large \boxed{\textbf{1.4 mol/L}}$}\)

Note: The answer can have only two significant figures because that is all you gave for the molar concentration of the sulfuric acid.

Specify the number of possible isomers of bromodimethylbenzene. 6 Write the name of one of these isomers. Abbreviate ortho (o), meta (m) and para (p), no italics, if you elect to use these terms.fill in the blank 2 Specify the number of possible isomers of aromatic compounds with the formula C7H8O. ___ Write the name of one of these isomers. Abbreviate ortho (o), meta (m) and para (p), no italics, if you elect to use these terms. fill in the blank 4

Answers

Answer:

Explanation:

See  attached file .

Specify the number of possible isomers of bromodimethylbenzene. 6 Write the name of one of these isomers.

The number of possible isomers of Bromodimethylbenze are 6. One of the isomers is 2 Bromo - m -xylene. The number of possible isomers of an aromatic compound \(\rm C_7H_8O\)  are 5. One of these isomers has been o - cresol.

(a). Bromodimethylbenze has also been known as bromoxylene. The compound has been consisted of 1 benzene ring with 2 methyl groups and a bromine atom.

The possible isomers of bromoxylene are:

4 Bromo - o -xylene3 Bromo - o -xylene2 Bromo - m -xylene4 Bromo - m -xylene5 Bromo - m -xylene2 Bromo - p -xylene

(b). Aromatic compound with formula \(\rm C_7H_8O\) has been the benzene compound. The compound has been consisted of a benzene ring with 1 methyl group and oxygen atom.

The possible isomers of  \(\rm C_7H_8O\) are:

Benzyl alcoholAnisolo - cresolp - cresolm - cresol

Thus, the number of possible isomers of Bromodimethylbenze are 6. One of the isomers is 2 Bromo - m -xylene. The number of possible isomers of an aromatic compound \(\rm C_7H_8O\)  are 5. One of these isomers has been o - cresol.

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When a solution of sodium hydroxide is mixed with iron (II) chloride, a green precipitate is formed. What is the balanced equation for that reaction?

Answers

The balanced chemical equation for the reaction is:

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

What is a chemical equation?

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

How to write the balanced equation

Sodium hydroxide => NaOH

Iron (II) chloride => FeCl₂

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

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Which of the following statements correctly describe the trends in ionic size?

a. The spin quantum number has values of +1212 or -1212.
b. The spin quantum number is a property of the electron itself.

Answers

the spin quantum number has values+1212 of -1212 describes the trends in ionic size.

spin quantum is denoted by (s) as it represents the electronic configuration of the atom and the ionic size also depends on the electronic configuration of the sub-shells of the atom like l, m, n, s.

ionic size increases as the electronic configuration increases because the electron adds as we move up to a higher atomic number

all the other quantum numbers may vary from atom to atom but the spin quantum number remains either +1212 or -1212. it also describes the orientation of the electrons in an atom and the axis of electrons in an atom.

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What is the formula for tetraphosphorus dioxide?​

Answers

Answer:

P₂O₅

Hope it helps.

Plzzz can you give me brainliest.

How many grams of oxygen O2 are in 54L at STP? hint all gases 22.4 L per mole at stp)
a. 62.2g
b.77.1g
c. 19.7g

Answers

Answer:

hope this answer will help you

Explanation:

we can simply do this by unitary method

22.4L is requires or 1 mole of oxygen gas

54L requires 1/22.4×54 = 2.41 moles

we know that no. of moles =mass/mol.mass

in order to get mass we multiply moles by mol. mass

2.41×32=77.1g

so, the correct option is

3.
Metals and nonmetals generally form ionic bonds
with each other. Which of the following sets of
elements will most likely form an ionic bond?
9
A. Na, F
B. CI, F C. Na, K D. He, O

Answers

Answer:

Na F

Explanation:

because electrovalent bond is present between them

A gas expands and does PV work on its surroundings equal to 322 J. At the same time, it absorbs 132 J of heat from the surroundings. Calculate the change in energy of the gas. Note: PV work means work done by a changing volume against constant pressure. Enter your answer in scientific notation.

Answers

From the calculations, the change in energy is - 190 J.

What is the first law of thermodynamics?

From the first law of thermodynamics, the energy is neither created nor destroyed but is transformed from one form to another.

From the law;

U = q + w

U = internal energy

q = heat

w = work

Since work is done on the surroundings and the gas absorbs heat then;

U = 132 J - 322 J

U = - 190 J

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Predict the product for the following reaction:
Н,0, Н
ОН
ООО
ОН

Answers

I think it’s OH I’m not sure

Select all of the following options that must be done in case of a fire alarm or other evacuation (when feasible).
a. gather your belongings
b. turn off all hot plates & other heating apparatus
c. turn off all water
d. stay in the lab to finish your experiment

Answers

option a,b,c are correct.gather your belongings,turn off all hot plates & other heating apparatus, turn off all water these are options that must be done in case of a fire alarm or other evacuation .

To guarantee your safety, take prompt action when the fire alarm goes off. The fire alarm system was created and constructed to give you a head start so you may safely leave the building in an emergency.Never dismiss a warning or believe it to be fake or the outcome of a test.The nearest and safest exit and/or stairs must be used by everyone to leave the building.Never leave during a fire alarm activation in an elevator.Once outside, make your way away from the structure. Gather on the sidewalk of the building next door or across the street.The firefighters and fire engines will be working in front of the structure. Don't stand in their way as they enter the building.

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questions/analysis: inhaled vs exhaled air. when we inhale, the air we breathe is comprised of a lot of different gases. for the purpose if this exercise, we are going to focus on oxygen gas, carbon dioxide and water vapor. when we exhale, the same 3 gases are present, but in different amounts. 1) using the internet, estimate the percent o2 and co2 in a breath of fresh air (inhaled air). using volume of the air in the balloon and the ideal gas law formula, calculate the number of moles of o2 and co2 as well as the number of grams of each gas. show all calculations clearly.

Answers

There are approximately 0.3392 grams of oxygen and 0.00088 grams of carbon dioxide in a single breath of fresh air.

What is Concentration?

In chemistry, concentration refers to the amount of a substance (solute) that is present in a given volume or mass of another substance (solvent). It is a measure of how much of a particular substance is present in a mixture, solution, or sample.

The concentration of gases in fresh air is approximately 21% oxygen, 0.04% carbon dioxide, and 1-2% water vapor.

To calculate the number of moles of oxygen and carbon dioxide in a breath of fresh air, we need to use the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is its volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Let's assume that the volume of a single breath of fresh air is 0.5 L at room temperature (25°C or 298 K) and atmospheric pressure (1 atm). We can then use the ideal gas law to calculate the number of moles of oxygen and carbon dioxide:

For oxygen:

PV = nRT

n = PV/RT = (1 atm)(0.21)(0.5 L)/(0.08206 L·atm/mol·K)(298 K) = 0.0106 mol

For carbon dioxide:

PV = nRT

n = PV/RT = (1 atm)(0.0004)(0.5 L)/(0.08206 L·atm/mol·K)(298 K) = 0.00002 mol

So there are approximately 0.0106 moles of oxygen and 0.00002 moles of carbon dioxide in a single breath of fresh air.

To calculate the mass of each gas, we can use the molar mass of each gas:

Using the number of moles we calculated above, we can calculate the mass of each gas:

Mass of oxygen = number of moles x molar mass = 0.0106 mol x 32 g/mol = 0.3392 g

Mass of carbon dioxide = number of moles x molar mass = 0.00002 mol x 44 g/mol = 0.00088 g

So there are approximately 0.3392 grams of oxygen and 0.00088 grams of carbon dioxide in a single breath of fresh air.

It's worth noting that the concentration of gases in exhaled air can vary depending on a number of factors, including the individual's health status, activity level, and surrounding environment.

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Aqueous solutions of copper (II) bromide and silver (1) acetate react to form solid
silver (1) bromide and aqueous copper (II) acetate according to the UNBALANCED
reaction below.
CuBr2 (aq) + AGCH3CO2 (aq)
-
AgBr (s) + Cu(CH3CO2)2 (aq)
How many grams of silver (1) bromide will form if 30.0 mL of 0.499 M copper (II)
bromide react with excess silver (1) acetate?

Answers

Answer:

5.63 g

Explanation:

Step 1: Write the balanced equation

CuBr₂(aq) + 2 AgCH₃CO₂(aq)  ⇒  2 AgBr(s) + Cu(CH₃CO₂)₂(aq)

Step 2: Calculate the reacting moles of copper (II) bromide

30.0 mL of 0.499 M CuBr₂ react. The reacting moles of CuBr₂ are:

\(0.0300L \times \frac{0.499mol}{L} = 0.0150mol\)

Step 3: Calculate the moles formed of silver (I) bromide

The molar ratio of CuBr₂ to AgBr is 1:2. The moles formed of AgBr are 2/1 × 0.0150 mol = 0.0300 mol.

Step 4: Calculate the mass corresponding to 0.0300 mol of AgBr

The molar mass of AgBr is 187.77 g/mol.

\(0.0300 mol \times \frac{187.77g}{mol} = 5.63 g\)

Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that [Sn2+]=0.0624 M, [Fe3+]=0.0437 M, [Sn4+]=0.00655 M, and [Fe2+]=0.01139 M. Standard reduction potentials can be found in this table.

Sn2+(aq)+2Fe3+(aq)↽−−⇀ Sn4+(aq)+2Fe2+(aq)

So far my incorrect answers have been:
0.28
0.798
0.178
0.142
0.881
0.61
and 0.812

Answers

Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

How to the cell potential of galvanic cell?

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

Learn more about cell potential, here:

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How many seeds would be in 14 kg of apples?
Given:12
Need to Find: Go?
Useful Equivalencies:

Answers

Answer:

thete are 672 seeds in 14 kg

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