For each pair of carbene/alkylidene complexes shown below identify the one that should have the stronger M-C bond. Give a brief explanation for your answer (i) [(CO)5V-C(OMe)(NMe2)]- (ii) Cp2BrTa-CH2 (iii) Cp(PMe3):Re-cBu2 (iv) [Cp(dppe)Fe-CPh2] vs Cp(PMe3)-Re-СМег vs Cp(CO)(PEt3)Ru-CH2l vs Cp(CO)2(PPh3)W-C(OMe2l vs CpO)Nb-CH2 IV

ΔH for this reaction : -2668.4 (exothermic)

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)  

The value of ° H ° can be calculated from the change in enthalpy of standard formation:  

∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants)  

you can search the value of ΔHf on the internet

∆H ° rxn =( ∆H Al₂O₃+∆H AlCl₃+3.∆H NO + 6.∆H H₂O)-(∆H Al+∆H NH₄ClO₄)

\(\tt \Delta H^o~rxn=(-1669.8+-704+(3\times 90.4)+(6.\times -241.8)-(3\times 0+3\times -295)\\\\\Delta H6o~rxn=-3553.4+885=-2668.4~kJ/mol\)

The grams of the KI are in the 25.0 ml of a 3.0 % m/v of the KI solution is 0.75 g.

The volume of the solution = 25 mL

The mass by volume of KI = 3 % m/v

The potassium iodide solution will contain the 3.0 g of the potassium iodide for the every 100 mL of the solution.

The amount of the KI in grams is as follows :

The mass of the KI in grams = (25 mL× 3 g ) / 100 mL

The mass of the KI in grams = 0.75 g

Thus, the amount of the KI in the grams is 0.75 g in the volume of the 25 mL.

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Answer:

Environmental Science

Explanation:

Answer:

I dont know how to take a picture so I will just tell you the answer. The answer   is no.

Explanation:

Hope this helps.    :)      :D

Approximately, there are 5.5552 liters in 0.248 moles of oxygen gas (O2) at STP.

To determine the volume of 0.248 moles of oxygen gas (O2), we need to use the ideal gas law equation:

PV = nRT

Where:

P is the pressure (assumed constant),

V is the volume,

n is the number of moles of gas,

R is the ideal gas constant (0.0821 L·atm/(mol·K)),

T is the temperature in Kelvin.

Since we are not given the pressure or temperature, we cannot directly calculate the volume using the ideal gas law. However, if we assume standard temperature and pressure (STP), we can use the molar volume of an ideal gas at STP to make an estimation.

At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K). The molar volume of an ideal gas at STP is approximately 22.4 liters/mol.

Therefore, we can estimate the volume of 0.248 moles of O2 at STP:

Volume = (0.248 moles) * (22.4 liters/mol)

Volume ≈ 5.5552 liters

It's important to note that the volume will vary with changes in pressure and temperature, so the given value assumes STP conditions.

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Answer: approximately 18.75 mL of 3.0 M HNO₂ solution can be completely neutralized by 75 mL of 1.5 M Mg(OH)₂ solution.

Explanation:

To determine the volume of 3.0 M HNO₂ solution that can be neutralized by 75 mL of 1.5 M Mg(OH)₂ solution, we can set up an equation based on the stoichiometry of the balanced chemical equation.

The balanced chemical equation for the neutralization reaction between HNO₂ and Mg(OH)₂ is:

2 HNO₂ + Mg(OH)₂ → Mg(NO₂)₂ + 2 H₂O

From the equation, we can see that it takes two moles of HNO₂ to react with one mole of Mg(OH)₂.

First, let's calculate the number of moles of Mg(OH)₂ present in 75 mL of 1.5 M solution:

Number of moles of Mg(OH)₂ = Volume (in L) × Concentration (in mol/L)

= 75 mL × (1 L / 1000 mL) × 1.5 mol/L

= 0.1125 mol

Since the stoichiometry ratio is 2:1 (HNO₂:Mg(OH)₂), we can conclude that 0.1125 moles of Mg(OH)₂ can neutralize 0.1125/2 = 0.05625 moles of HNO₂.

Now, let's determine the volume of 3.0 M HNO₂ required to contain 0.05625 moles:

Volume (in L) = Number of moles / Concentration (in mol/L)

= 0.05625 mol / 3.0 mol/L

≈ 0.01875 L

Finally, we convert the volume from liters to milliliters:

Volume (in mL) = Volume (in L) × 1000

≈ 0.01875 L × 1000

≈ 18.75 mL

One feature that decreases in size between Australopithecus and early members of the Homo genus is cranial capacity or brain size.

Australopithecus species, such as Australopithecus afarensis, had a smaller cranial capacity compared to early members of the Homo genus, such as Homo habilis. Cranial capacity refers to the volume of the braincase, which is an indicator of brain size. Australopithecus species had an average cranial capacity of about 400-550 cubic centimeters (cc), whereas early Homo species had larger cranial capacities ranging from about 600-800 cc.

The difference in cranial capacity between Australopithecus and early Homo species can be calculated by subtracting the average cranial capacity of Australopithecus (e.g., 500 cc) from the average cranial capacity of early Homo (e.g., 700 cc):

700 cc - 500 cc = 200 cc

The cranial capacity, and thus the brain size, increased between Australopithecus and early members of the Homo genus. This increase in brain size is thought to be associated with the evolution of more advanced cognitive abilities and technological advancements observed in early Homo species compared to Australopithecus.

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Answer:

Backbone help us to be straight ,walk ,sleep etc

Explanation:

Backbone is the part of human body which is located back of our body.

It effort helps us to be straight do various work

The spine or the backbone is the central structure of the vertebrate body and it serves a few imperative capacities:

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Yes, the given equation represents a redox (reduction-oxidation) reaction. In this equation, lithium (Li) is oxidized, and oxygen (O) is reduced.

In the reaction, each lithium (Li) atom loses one electron to form Li⁺ ions. This process is known as oxidation because the oxidation state of lithium increases from 0 to +1. Therefore, lithium undergoes oxidation.

On the other hand, each oxygen (O) atom gains two electrons to form O²⁻ ions. This process is known as reduction because the oxidation state of oxygen decreases from 0 to -2. Thus, oxygen undergoes reduction.

The transfer of electrons from lithium to oxygen demonstrates the occurrence of a redox reaction. Oxidation and reduction are happening simultaneously in this equation, making it a redox reaction.

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Answer:

theory

Explanation:

if you assume something that you didn't see occuring it is called a theory

Answer: The boiling point of a 3.70 m solution of phenol in benzene is \(89.5^0C\)

Explanation:

Elevation in boiling point:

\(\Delta T_b=i\times k_b\times m\)

where,

\(\Delta T_b\) = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

\(k_b\) = boiling point constant = \(2.53^0C/kgmol\)

m = molality = 3.70

\(T_{solution}-T_{solvent}=i\times k_b\times m\)

\(T_{solution}-80.1^0C=1\times 2.53\times 3.70\)

\(T_{solution}=89.5^0C\)

Thus  the boiling point of a 3.70 m solution of phenol in benzene is \(89.5^0C\)

Answer:

First Question:

C. ΔTb = Kbm

Second Question:

C. 9.36° C

Third Question:

89.5

Explanation:

Got it right.

29.85 grams of the product(s) will be produced by complete reaction of 0.125 mole of AgNO3.

To calculate how many grams of the product(s) will be produced by complete reaction of 0.125 mole of AgNO3, we need to use the stoichiometry of the reaction and the molar mass of the product(s).

First, let's write the balanced equation for the reaction:

AgNO3(aq) + LiOH(aq) → AgOH(s) + LiNO3(aq)

From the balanced equation, we can see that 1 mole of AgNO3 reacts with 1 mole of LiOH to produce 1 mole of AgOH and 1 mole of LiNO3.

Now, let's use the molar mass of the product(s) to calculate how many grams will be produced:

Molar mass of AgOH = 169.87 g/mol
Molar mass of LiNO3 = 68.94 g/mol

Grams of AgOH = 0.125 mole × 169.87 g/mol = 21.23 g
Grams of LiNO3 = 0.125 mole × 68.94 g/mol = 8.62 g

So, the total grams of the product(s) produced by complete reaction of 0.125 mole of AgNO3 will be:

Total grams = 21.23 g + 8.62 g = 29.85 g

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

Answer:

C. guides you through the steps to complete a complex task.

Explanation:

mark me brainliest!!

The volume of the balloon is 3.788l.

Boyle's law:

Boyle's law state that the volume of a gas at constant temperature varies inversely with the pressure exerted on it.

The formula of Boyle's law:

P1V1 = P2 V2

P1 = 1.334atm

V1 = 1.88l

P2 = 0.662 atm

Putting the values in the equation we have:

1.334 × 1.88 = 0.662 × V2

V2 = 2.51/ 0.662

    = 3.788 l

Therefore the volume is 3.788l

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Answer:

It's electrons

Explanation:

Don't forget to like :)

Answer:

air is cooled by a heat source. Convection currents form when warm air rises and cold air sinks.

Scientists who make contributions to scientific knowledge often come from different backgrounds and live at different times. Option C.

The planets are in elliptical motion around the sun. The figure below shows two orbits with the same semimajor axis, focus, and orbital period. One is a circle with an eccentricity of 0.0. The other is an ellipse with an eccentricity of 0.8. Johannes Kepler was a German mathematician and astronomer who discovered that the earth and planets orbit the sun in elliptical orbits.

He gave his three basic laws of planetary motion. He also did important work in optics and geometry. Johannes Kepler is best known for his three laws of planetary motion. These laws are: Planets move in orbits shaped like ellipses. The lines between the planets and the sun cover equal areas in equal time. He formulated the law of universal gravitation. He identified the first moons of Jupiter. He collected detailed data that led to the proposal of the heliocentric model.

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Answer: 10 grams

Explanation: Original sample is 80 gram and every three days half of its composition decays so 80 down to 40 in the first 3 days, 20 in the next three days, and  10 in the last three days

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

We know that the leaves are the parts of the plant that are involved in photosynthesis. Photosynthesis is the process by which green plants produce their own food in the presence of sunlight and chlorophyll. We know that the leave has an outer protective covering.

The tissue that plays this outer covering of a plant for is the  epidermis and its waxy cuticle. It prevents damage to the plant.

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

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Answer: If a pinch of mercury is consumed you will die from it so using a mercury thermometer is very unsafe if its breaks and a child consumes that mercury.

Explanation:

Don't use one

If the glass breaks and the mercury is not properly cleaned up, the little silvery ball within a mercury thermometer might be hazardous. As the mercury evaporates, it may pollute the air around and turn dangerous to both people and animals.

Children that have been exposed to mercury have lower IQs, hearing impairments, and worse coordination.

Long-term exposure worsens and exacerbates symptoms, which may lead to personality changes or even coma.

Mercury thermometers can be replaced by a number of things:

These non-mercury fever thermometers are significantly safer and equally accurate as mercury thermometers.

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0.116 V is the e value for the oxidation of cytochrome c by the cue redox center in complex iv when the ratio of cyst c (fe3 ) /cyst c (fe2 ) is 20 and the ratio of cue (cu2 )/cue (cu ) is 3.

When cytochrome c is oxidized by mitochondrial cytochrome oxidase (COX), it attaches to Apaf-1 to produce the apoptozole, which activates pro-caspase-9 and causes cell death. Cyst can be created from cytosolic cytochrome c. In the IMS, oxidized cytochrome c can scavenge superoxide without converting it into H2O2, a process that happens naturally but is accelerated by SOD. The benefit of scavenging superoxide independently of H2O2 synthesis is reducing the possibility of hydroxyl radical generation via the Fenton reaction.

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Answer:

The percentage error is -2.4 %

Explanation:

The percentage error is calculated by the following formula;

\(Percentage \ error = \dfrac{Approximate - Exact }{Exact}\)

The given parameters are;

The atomic mass of cobalt = 58.933 amu. =  The exact value

The mass of cobalt as measured by the scientist = 57.514 = The approximate value

Therefore, the percentage error is given plugging in the values into the above equation for percentage error as follows;

\(Percentage \ error = \dfrac{(57.514- 58.933 )}{58.933 } \times 100 = -2.41\%\)

The percentage error = -2.4 %.

HF is corrosive at concentration that are ≥ 1 M (1 mol/L). Therefore the correct option is option C.

HF (hydrofluoric acid) is a very poisonous and corrosive acid that, when contacted, can result in serious burns and tissue damage. The concentration of HF affects its ability to corrode.

At concentrations of less than 1 M (1 mol/L), HF is corrosive. At this concentration, HF can quickly permeate the skin, resulting in painful tissue injury.

Because of its fast skin penetration and capacity to interact with calcium ions in the body to generate insoluble calcium fluoride (CaF2), HF has a corrosive effect on tissues and cells.

Although the effects may be delayed or less severe than at higher concentrations, severe burns and tissue damage can still occur at HF concentrations of less than 0.1 M (0.1 mol/L). Therefore the correct option is option C.

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The height of a ramp does not directly determine the strength of the frictional force between a book and an object.

The strength of the frictional force between a book and an object is not directly influenced by the height of a ramp. The nature of the surfaces in contact, the force forcing the surfaces together (normal force), and the coefficient of friction are some of the variables that affect the frictional force between two surfaces.

The coefficient of friction between the book and the object plays a major role in determining the strength of the frictional force.

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