For each of these relations on the set (1,2,3,4), decide whether it is reflexive, whether it is symmetric, whether it is antisymmetric, and whether it is transitive. a) {(2,2), (2,3), (2,4), (3,2), (3,3), (3,4)) b) {(1,1), (1,2), (2,1), (2,2). (3,3), (4,4)} c) {(2,4), (4,2)) d) {(1,2), (2,3), (3,4)} e) {(1,1), (2,2), (3,3), (4,4)} f) {(1,3), (1,4), (2,3), (2,4), (3,1), (3,4)}

Answer:

3/11

Step-by-step explanation:

Both numbers are easily simplified by 3 and that's as far as it can go because 11 is a prime number

9÷3=3

33÷3=11

3/11=9/33

Answer:

3/11

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator

GCD of 9 and 33 is 3

Divide both the numerator and denominator by the GCD

9 ÷ 3

33 ÷ 3

Reduced fraction: 3/11

9/33 simplified gives you your answer which is 3/11

After the second stop, there are 10 fewer people on the bus compared to the number of people on the bus before the 2:30 stop.

Before the 2:30 stop, the bus let off 15 people and let on 9 people. The total change in the number of people at that stop is -15 (let off) + 9 (let on) = -6.

Therefore, there are 6 fewer people on the bus after the 2:30 stop compared to before that stop.

Ten minutes later, the bus makes another stop and lets off 4 more people. This additional change needs to be considered.

Since the previous calculation only accounted for the changes up until the 2:30 stop, we need to adjust the total change by including the subsequent stop.

Adding the change of -4 (let off) to the previous total change of -6, we get a new total change of -10.

Therefore, after the second stop, there are 10 fewer people on the bus compared to the number of people on the bus before the 2:30 stop.

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Answer: The correct answer would be D

Step-by-step explanation:

I’m just guessing ;)

9514 1404 393

Answer:

  a) (-7, -2)

  b) 15 square units

Step-by-step explanation:

The slope at x is given by the derivative:

  y' = 3x^2 -10x +3

The slope of the normal is the negative reciprocal of this.

at a(4, -3) the slope of the normal is ...

  ma = -1/y' = -1/((3(4) -10)(4) +3) = -1/11

Then the point-slope equation of the line is ...

  y +3 = -1/11(x -4)

__

at b(1, 0) the slope of the normal is ...

  mb = -1/y' = -1/((3(1) -10)(1) +3) = -1/-4 = 1/4

Then the point-slope equation of the line is ...

  y = 1/4(x -1)

Solving these two equations will give the coordinates of point C.

  (1/4(x -1) +3) = -1/11(x -4)

  11(x -1) +132 = -4(x -4)

  15x = -105

  x = -7

  y = 1/4(-7 -1) = -2

The coordinates of point C are (-7, -2).

__

There are a few ways to find the area of a triangle that is specified by its vertex coordinates. I like the method that involves finding the determinants of pairs of coordinates around the figure. The area is half the absolute value of their sum. This can be made a little easier by listing the coordinates, repeating the first pair:

  a(4, -3)

  b(1, 0)

  c(-7, -2)

  a(4, -3)

Working down the list, the area will be ...

  A = 1/2|(4(0) -1(-3)) +(1(-2) -(-7)(0)) +((-7)(-3) -4(-2))| = 1/2|(0 +3) +(-2 +0) +(21 +8)|

  A = 1/2|30| = 15 . . . . square units

_____

The attached graph finds the intersection of the normals quite easily. The attached spreadsheet does the area calculation from the triangle coordinates. These tools are very handy for problems like this.

Answer:

Step-by-step explanation:

\(Curve:\ y=x^3-5x^2+3x+1\\\\y'(x)=3x^2-10x+3\\A=(4,-3)\\B=(1,0)\\y'(4)=3*4^2-10*4+3=11\\slope\ of\ the\ normal\ in \ A: -\frac{1}{11} \\Equation\ normal\ in \ A:\\y+3= -\frac{1}{11}*(x-4)\ or\ -x-11*y=29\ (1)\\\\y'(1)=3*1^2-10*1+3=-4\\slope\ of\ the\ normal\ in \ B: \frac{1}{4} \\Equation\ normal\ in \ B:\\y-0=\frac{1}{4} (x-1)\ or\ -x+4y=-1\ (2)\\\\Coordinates\ of\ C:\\(1)-(2) ==> y=-2\\(2) ==> x=-7\\\\C=(-7,-2)\\\)

Area of the  triangle ABC:

\(S=\dfrac{|CB|*|CA|*sin(\widehat{ACB})}{2}\\A=(4,-3),B=(1,0),C=(-7,-2)\\AB^2=(4-1)^2+(-3-0)^2=9+9=18\\AC^2=122\\BC^2=68\\\\Using\ Al'Kashi\ theorem:\\AB^2=CB^2+CA^2-2|CB||CA|*cos(\widehat{ACB})\\\\cos(\widehat{ACB})=\dfrac{68+122-18}{2\sqrt{68*122} } =\dfrac{86}{\sqrt{68*122} } \\\\sin^2(\widehat{ACB})=1-cos^2(\widehat{ACB})=1-\dfrac{86^2}{68*122} \\\\S=\dfrac{\sqrt{68} *\sqrt{122}*\sqrt{\dfrac{900}{68*122} }}{2}=15\\\)

You receive an email asking you to forward it to four other people to ensure prosperity. Assuming the chain isn't broken , how many emails will have been received and sent after 8 email generations including yours?





A.5,460 emails



B.21,844 emails



C.65,537 emails



D. 5,461 emails​

In this problem we have an exponential function of the form

y=a(1+r)^x

where

a=1 -----> initial value

r=300%-----> r=3

so

y=(1)(1+3)^x

where

y is the number of emails

x is the number of generations

For x=8

substitute

y=4^8

y=65,536

including yours

65,536+1=65,537

Answer:

it would be within the range of $0.77 <x< $0.78

Answer:

30

Step-by-step explanation:

Answer:

To sum up, the lcm of 5 and 6 is 30. In common notation: lcm (5,6) = 30.

Step-by-step explanation:

The option that can be used to verify the trigonometric identity, \(tan\left(\dfrac{x}{2}\right)+cot\left(x \right) = csc\left(x \right)\) is option C;

C. \(tan\left(\dfrac{x}{2} \right) + cot\left(x \right) = \dfrac{1-cos\left(x \right)}{sin\left( x \right)} +\dfrac{cos \left(x \right)}{sin\left(x \right)} =csc\left(x \right)\)

A trigonometric identity is an equations that consists of trigonometric functions that remain true for all values of the argument of the functions

The specified identity is presented as follows;

\(tan\left(\dfrac{x}{2} \right)+cot(x)=csc(x)\)

The half angle formula for tangent indicates that we get;

\(tan\left(\dfrac{1}{2} \cdot \left(\eta \pm \theta \right) \right) = \dfrac{tan\left(\dfrac{1}{2} \cdot \eta \right)\pm tan\left(\dfrac{1}{2} \cdot \theta \right)}{1 \mp tan\left(\dfrac{1}{2} \cdot \eta \right)\times tan\left(\dfrac{1}{2} \cdot \theta \right)}\)

\(\dfrac{tan\left(\dfrac{1}{2} \cdot \eta \right)\pm tan\left(\dfrac{1}{2} \cdot \theta \right)}{1 \mp tan\left(\dfrac{1}{2} \cdot \eta \right)\times tan\left(\dfrac{1}{2} \cdot \theta \right)}=\dfrac{sin \left(\eta\right) \pm sin\left(\theta \right)}{cos \left(\eta \right) + cos \left(\theta \right)} = -\dfrac{cos \left(\eta\right) - cos\left(\theta \right)}{sin \left(\eta \right) \mp sin \left(\theta \right)}\)

When η = 0, we get;

\(-\dfrac{cos \left(0\right) - cos\left(\theta \right)}{sin \left(0 \right) \mp sin \left(\theta \right)}=-\dfrac{1 - cos\left(\theta \right)}{0 \mp sin \left(\theta \right)}=\dfrac{1 - cos\left(\theta \right)}{sin \left(\theta \right)}\)

Therefore;

\(tan\left(\dfrac{x}{2} \right)=\dfrac{1 - cos\left(x \right)}{sin \left(x \right)}\)

\(cot\left(x \right) = \dfrac{cos(x)}{sin(x)}\)

\(tan\left(\dfrac{x}{2} \right)+cot(x)= \dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)}\)

\(\dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)}=\dfrac{1-cos(x)+cos(x)}{sin(x)} = \dfrac{1}{sin(x)}\)

\(\dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)}=\dfrac{1}{sin(x)}=csc(x)\)

Therefore;

\(tan\left(\dfrac{x}{2} \right)+cot(x)= \dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)} = csc(x)\)

The correct option that can be used to verify the identity is option C

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Answer:

1/2³ = 0.125

0.125 × 2 = 0.25

answer = 0.25

Answer:

y = 7

Step-by-step explanation:

y = 3(2-1) 2 + 1

y = 3(1)(2) + 1

y = 6 + 1

y = 7

Answer:

1. y² = 169

taking a square root of both sides

y = √169

we know that 13 * 13 = 169

since when squaring a number, the signs on the numbers do not matter

(i.e - 2* 2 = 4 and (-2)*(-2) = 4)

So (-13) * (-13) = 169 as well

Hence we can say that √169 = ±13      OR      √169 = +13   and   -13

2. Volume of a cube-shaped crate = side*side*side

Volume = side³

(We are given that volume = 27)

27 = side³

side = ∛27

Since 3*3*3 = 27     and (-3)*(-3)*(-3) = 27

So, we can say that ∛27  = ± 3

BUT

the side of a crate cannot be negative, so the side will NOT be -3 and hence,

side = 3

3. b³ = 1000

we know that 10*10*10 = 1000    and     (-10)*(-10)*(-10) = 1000

So, ∛1000 =  ∛(10*10*10)= ±10

4. Area of a square(Patio)  = Side²

Area = Side²

196 = Side² (Since we are given the area of the patio)

Side = √196 = √(14*14) or √(-14*-14)

Hence,

Side = + 14 or -14

but the side of a patio cannot be negative

Side = +14 ft

The volume of the sphere is approximately 3431.82 cubic miles.

To find the volume of a sphere, we need the radius of the sphere. The length of a great circle is the circumference of the sphere, which is related to the radius by the formula C = 2πr, where C is the circumference and r is the radius.

In this case, we are given that the length of the great circle is 60 miles. We can use this information to find the radius of the sphere.

C = 2πr

60 = 2πr

Divide both sides of the equation by 2π:

r = 60 / (2π)

r = 30 / π

Now that we have the radius, we can use the formula for the volume of a sphere:

V = (4/3)πr³

V = (4/3)π(30/π)³

V = (4/3)π(27000/π³)

V = (4/3)π(27000/π³)

V = (4/3)π(27000/π³)

V = (4/3)(27000/π²)

V = (4/3)(27000/9.87) (approximating π to 3.14)

V ≈ 3431.82 cubic miles

Therefore, the volume of the sphere is approximately 3431.82 cubic miles.

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Question

You are given the great circle of a sphere is a length of 60 miles. What is the volume of the sphere?

Answer:

A.K= 2/3 Y=15

​

SORRY I ONLY DID A

Answer:

\( (42700- 36275) -2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}= 5519.071\)

\( (42700- 36275) +2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}=7330.929\)

Step-by-step explanation:

For this case we have the following info given:

\(n_1 = 41 , \bar X_1 =42700 , s_1 = 2030\)

\(n_2 = 41 , \bar X_2 =36375 , s_2 = 1360\)

And for this case we want a 98% confidence interval. The significance would be:

\( \alpha= 1-0.98=0.02\)

The degrees of freedom are:

\( df = n_1 +n_2 -2= 41+41 -2= 80\)

And the critical value for this case is:

\( t_{\alpha/2}= 2.374\)

And the confidence interval would be given by:

\((\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}\)

And replacing we got:

\( (42700- 36275) -2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}= 5519.071\)

\( (42700- 36275) +2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}=7330.929\)

Answer:

\(c)\ 45^\circ\)

Step-by-step explanation:

Given

A semicircle divided into 8 parts

Required

Angle that can be measured with the piece

First, we calculate the minimum angle that can be calculated.

\(\theta =\frac{Semi\ circle}{8}\)

\(Semicircle = 180^\circ\)

So, we have:

\(\theta =\frac{180^\circ}{8}\)

\(\theta =22.5^\circ\)

This implies that all angles that can be measured using the piece must be a multiple of 22.5 not greater than 180 degrees (i.e. not greater than the semicircle)

So, we have:

\(\theta =22.5^\circ,\ 45^\circ,\ 67.5^\circ,\ 90^\circ,\ 112.5^\circ,\ 135^\circ,\ 157.5^\circ,\ 180^\circ\)

From the list of options, only 45 degrees appear in the possible values of \(\theta\)

Hence:

\(\theta = 45^\circ\)

Answer:

A foot is 12 inches and 4 is closer to 0 than 12 meaning 13 ft 4 in simplified is 13 ft

Step-by-step explanation:

The number of children in the school who speak a language other than English at home is 144.

The fraction of children who speak Polish is 1/6.

Percentage is the ratio of a quantity expressed as a number out of 100. Percentage is a measure of frequency. The sign that is used to represent percentage is %.

Number of children in the school who speak a language other than English at home = Percentage of the students who speak a language other than English x number of children

Number of children in the school who speak a language other than English at home = 45% x 320

Number of children in the school who speak a language other than English at home = 0.45 x 320 = 144

A fraction is a non-integer that is made up of a numerator and a denominator. The numerator is the number above and the denominator is the number below.

Fraction of the students who speak Polish = number of students that speak Polish / total number of students who speak a language other than English.

Fraction of the students who speak Polish = 24 / 144 = 1/6.

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The solution to the equation 3 / 5x-2 = 2 / 3x-1 is x = 1.

Given the equation in the question;

3 / 5x-2 = 2 / 3x-1

To solve for x, cross multiply the equation

3 / 5x-2 = 2 / 3x-1

3( 3x - 1 ) = 2( 5x - 2 )

Apply distributive property

3( 3x - 1 ) = 2( 5x - 2 )

3×3x + 3×-1 = 2×5x + 2×-2

9x - 3 = 10x - 4

Subtract 10x from both sides

9x - 10x - 3 = 10x - 10x - 4

9x - 10x - 3 = - 4

Add 3 to both sides

9x - 10x - 3 + 3 = - 4 + 3

9x - 10x  = - 4 + 3

-x = -1

Divide both sides by -1

-x/-1 = -1/-1

x = 1

Therefore, the value of x is 1.

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Answer:

270°

Step-by-step explanation:

a reflex angle is an angle which is larger than 180° but smaller than 360°

an angle around a point is 360°

so to find angle B we do \(360-90\) to give 270

so angle B is 270°

Answer:

hasn't done nothing but I think it is matrix

Answer:

Step-by-step explanation:

-3≤ x = graph 6

-3 > x = graph 3

x≥ 3 = graph 2

x ≤ 3 = graph 4

3 > x = graph 1

x > 3 = graph 5

the closed circles means greater/less than or equal to

the open circle means greater/less than

the direction of the arrow tells you if the number is greater than x or less than x

This question was not written properly

Complete Question

Determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.

7/6, 5/3, 13/6, 8/3

Answer:

a) Common difference = 1/2

b) Fifth term = 19/6

c) nth term = 7/6 + (n - 1)1/2

= 7/6 + n/2 - 1/2

d) 100th term = 152/3

Step-by-step explanation:

We solve using the formula for arithmetic sequence

an = a1 + (n - 1)d

a1 = First term

n= nth term

d = common difference

a) Common difference = Second term - first term or Third term - second term

= d = 5/3 - 7/6

d = LCD (Lowest Common Denominator = 15

d = 5 × 6 - 3 × 7/18

d = 30 - 21/15

d = 9/18

d = 1/2

b) Fifth term =

an = a1 + (n - 1)d

a1 = First term = 7/6

n= nth term = 5

d = 1/2

a5 = 7/6 + (5 - 1)1/2

a5 = 7/6 + (4)1/2

a5 = 7/6 + 4/2

a5 = 7/6 + 2

a5 = LCD = 6

= 7× 1 + 2 × 6/6

= 7 + 12/6

= 19/6

c) nth term

an = a1 + (n - 1)d

a1 = First term = 7/6

n= nth term = n

d = 1/2

= 7/6 + (n - 1)1/2

= 7/6 + n/2 - 1/2

d) 100th term

an = a1 + (n - 1)d

a1 = First term = 7/6

n= nth term = 100

d = 1/2

a5 = 7/6 + (100- 1)1/2

a5 = 7/6 + (99)1/2

a5 = 7/6 + 99/2

a5 = 7/6 + 99/2

a5 = LCD = 6

= 7× 1 + 3 × 99/6

= 7 + 297/6

= 304/6

= 152/3

Answer:

-25x-45y, because if we have got + and -, so we will write minus.

Answer:

540 minutes in hours =540/60

=9 hours

The time 540 minutes in hours will be 9 hours.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the time is 540 minutes. The value of time in hours will be calculated as,

The time of 60 minutes is equal to 1 hour. So divide the time 540 minutes by 60 minutes.

Time = 540 / 60

Time = 9 hours

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Answer: 6 units

Step-by-step explanation: first set up the distance formula

d= the square root of [(-7+1)^2+(7-7)^2}

the y values =0 so we are left with the square root of -6^2=d

and this simplifies out to d=6

answer I didn't know sorry for that

As a result, choice C is the equation that best represents the algebraic tiles since we only need to determine the total or difference.

It is possible either multiply, distribute, add, or negate in mathematics. The trying to follow is how a expression is put together: Number, expression, and scientific operator The ingredients of a mathematical expression include numbers, variables, and operations (such as addition, subtraction, multiplication or division etc.) It is possible to combine expressions and phrases. An expressions, often known as an arithmetic operation, is any mathematical statement that contains variables, numerals, and a numerical operation between them. That instance, the word m there in given equation is separated from the terms 4m and 5 by the arithmetic symbol +, as is the variable m in the phrase 4m + 5.

given

To address this issue, we just need to determine the total or difference that yields 2x2 + 2x + 2

Option A: ( x2 + 4x -2) + (x2 - 2x - 4) = 2x2 + 2x - 6

Option B: ( x2 + 4x - 2 ) + ( x2 + 2x + 4 ) = 2x2 + 6x + 2

Option C: ( x2 + 4x - 2) - ( -x2 + 2x - 4)= x2 + 4x - 2 + x2 - 2x + 4

= 2x2 + 2x + 2

As a result, choice C is the equation that best represents the algebraic tiles since we only need to determine the total or difference.

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The complete question is:-

Select the correct answer.

Which sum or difference is modeled by the algebra tiles?

A. (-x2 + 2x + 3) − (x2 − 2x − 1) = -2x2 + 2

B. (-x2 + 2x + 3) − (-x2 + 2x + 1) = -2x2 + 2

C. (-x2 + 2x + 3) + (-x2 + 2x + 1) = -2x2 + 2

D. (-x2 + 2x + 3) + (-x2 − 2x − 1) = -2x2 + 2

If a radius is drawn to the point of tangency of a tangent line, then the radius is basically perpendicular to the tangent line.

Given that the radius is drawn to the point of tangency of a tangent line.

We are required to fill the blank with the appropriate word.

Radius is basically the line segment which joins the center to any point on the circumference of the circle.

Tangent line is basically a line which is drawn from an outside point on the circumference of the circle.

When the radius is drawn to the point of tangency of a tangent line, then the radius is perpendicular to the tangent line.

Hence if a radius is drawn to the point of tangency of a tangent line, then the radius is perpendicular to the tangent line.

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\( \sf \longrightarrow \: 5 \bigg( \: n - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{n}{1} - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{10 \times n - 1 \times 1}{1 \times 10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{10n - 1}{ 10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: \: \frac{50n - 5}{ 10} = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: \: 2(50n - 5) =1(10) \\ \)

\( \sf \longrightarrow \: \: 2(50n - 5) =10 \\ \)

\( \sf \longrightarrow \: \: 100n - 10=10 \\ \)

\( \sf \longrightarrow \: \: 100n =10 + 10\\ \)

\( \sf \longrightarrow \: \: 100n =20\\ \)

\( \sf \longrightarrow \: \:n = \frac{2 \cancel{0}}{10 \cancel{0}} \\ \)

\( \sf \longrightarrow \: \:n = \frac{1}{5} \\ \)

Answer:-

To solve the equation \(\sf 5(n - \frac{1}{10}) = \frac{1}{2} \\\) for \(\sf n \\\), we can follow these steps:

Step 1: Distribute the 5 on the left side:

\(\sf 5n - \frac{1}{2} = \frac{1}{2} \\\)

Step 2: Add \(\sf \frac{1}{2} \\\) to both sides of the equation:

\(\sf 5n = \frac{1}{2} + \frac{1}{2} \\\)

\(\sf 5n = 1 \\\)

Step 3: Divide both sides of the equation by 5 to isolate \(\sf n \\\):

\(\sf \frac{5n}{5} = \frac{1}{5} \\\)

\(\sf n = \frac{1}{5} \\\)

Therefore, the solution to the equation \(\sf 5(n - \frac{1}{10})\ = \frac{1}{2} \\\) is \(\sf n = \frac{1}{5} \\\), which corresponds to option (d).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)