Answers
For a wheel spinning on an axis through its center, the ratio of the tangential acceleration of a point on the rim to the tangential acceleration of a point halfway between the center and the rim is 1/2
The tangential acceleration of a point on the rim of a wheel is given by the equation: a = r * α, where a is the tangential acceleration, r is the distance from the point to the axis of rotation, and α is the angular acceleration of the wheel. The tangential acceleration of a point halfway between the center and the rim of the wheel is also given by this equation, but with a different value for r: a' = r' * α, where a' is the tangential acceleration of the point halfway between the center and the rim, and r' is the distance from this point to the axis of rotation. To find the ratio of the tangential acceleration of the point on the rim to the tangential acceleration of the point halfway between the center and the rim, we can divide the equation for a by the equation for a': a/a' = r * α / (r' * α). Since the angular acceleration (α) cancels out, we are left with: a/a' = r / r'. Since the point on the rim is farther from the axis of rotation than the point halfway between the center and the rim, the value of r is greater than the value of r'. Therefore, the ratio of the tangential acceleration of the point on the rim to the tangential acceleration of the point halfway between the center and the rim is: a/a' = r / r' < 1, so the correct answer is C) 1/2.
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Related Questions
A 4.0 m length of gold wire is connected to a 1.5 V battery, and a current of 4.0 mA flows through it. What is the diameter of the wire? (The resistivity of gold is 2.44 × 10-8 Ω·m.) A. 9.0 μm B. 8.5 μm C. 17 μm D. 48 μm
Answers
Explanation:
Given that,
Length of gold wire, l = 4 m
Voltage of battery, V = 1.5 V
Current, I = 4 mA
The resistivity of gold, \(\rho=2.44\times 10^{-8}\ \Omega-m\)
Resistance in terms of resistivity is given by :
\(R=\dfrac{\rho l}{A}\)
Also, V = IR
So,
\(\dfrac{V}{I}=\dfrac{\rho l}{A}\)
A is area of wire,
\(\dfrac{V}{I}=\dfrac{\rho l}{\pi r^2}\), r is radius, r = d/2 (diameter=d)
\(\dfrac{V}{I}=\dfrac{\rho l}{\pi (d/2)^2}\\\\\dfrac{V}{I}=\dfrac{4\rho l}{\pi d^2}\\\\d=\sqrt{\dfrac{4\rho l I}{V\pi}} \\\\d=\sqrt{\dfrac{4\times 2.44\times 10^{-8}\times 4\times 4\times 10^{-3}}{1.5\times \pi}} \\\\d=18.2\ \mu m\)
Out of four option, near option is (C) 17 μm.
The diameter of the wire is 18μm and the closest answer is option C.
The resistance of a wire is proportional to its length and inversely proportional to its area.
Given that a 4.0 m length of gold wire is connected to a 1.5 V battery, and a current of 4.0 mA flows through it. Then,
R = (ρL)/A
where
ρ = resistivity = 2.44 × 10-8 Ω·m
L = length
A = Area = \(\pi ^{2}\)D/2
D = diameter of the wire
From Ohm's law, V = IR
make resistance R the subject of the formula
R = V/I
R = 1.5/4 x \(10^{-3}\)
R = 375 Ω
Substitute all the parameters into the formula
R = (ρL)/A
375 = (2.44 × \(10^{-8}\) x 4)/A
A = (9.76 × \(10^{-8}\))/ 375
A = 2.603 x \(10^{-10}\) \(m^{2}\)
but
A = \(\pi (D/2)^{2}\)
2.603 x \(10^{-10}\) = \(\pi (D/2)^{2}\)
\(\pi\)\(D^{2}\) /4 = 2.603 x \(10^{-10}\)
\(\pi\)\(D^{2}\) = 1.04 x \(10^{-9}\)
\(D^{2}\) = (1.04 x \(10^{-9}\))/ \(\pi\)
D = \(\sqrt{3.3 * 10^{-10} }\)
D = 1.8 x \(10^{-5}\) m
D = 18 μm
Therefore, the diameter of the wire is 18μm and the closest answer is option C.
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gravitational, magnetic, and electric forces can all be explained using fields. which of the following is a reason that we explain these forces using fields?
Answers
Fields provide a consistent framework for understanding and describing different types of forces, such as strength, direction, propagation, attenuation, and mathematically describing the behavior of forces.
What is gravitational force?Gravitational force is the force of attraction that exists between two objects that have mass. It is the weakest of the four fundamental forces in nature, but it is the most influential force when it comes to the large-scale structure of the universe. It is responsible for keeping planets and stars in orbit around one another, and also for the formation of galaxies and other large structures.
We explain these forces using fields because fields provide a consistent framework for understanding and describing different types of forces. Fields provide a way to represent the strength and direction of a force at any given point in space. They also provide a way to represent the interactions between different types of forces, such as how magnetic and electric fields interact to create electromagnetic forces. Furthermore, fields provide a way to represent how forces can propagate and attenuate over distances, allowing us to understand how things interact from afar. Finally, fields provide a way to mathematically describe the behavior of forces, allowing us to make predictions about how things interact in different situations.
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The complete question is: What is a reason to explain the gravitational, magnetic, and electric forces using the fields?
You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?
Answers
Answer:
Explanation:
A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:
Output force = Weight of object = m * g
where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:
Output force = 15 kg * 9.81 m/s^2 = 147.15 N
Therefore, the output force required to lift a 15 kg object would be 147.15 N.
B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.
C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:
Mechanical advantage = Output force / Input force = 40 N / 10 N = 4
So, the ramp multiplies your force by a factor of 4.
Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.
When you drop a 0.37 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s² to-
ward the earth's surface. According to New-
ton's third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 x 10²4 kg, what
is the magnitude of the earth's acceleration
toward the apple?
Answer in units of m/s².
Answers
The earth is accelerating toward the apple at a rate of 6.2 × 1025 m/s2.
How is this acceleration determined?The apple weighs m = 0.37 kg.
The apple's speed when it approaches the earth's surface is 9.8 meters per second.
Earth's mass, M, is 5.98 × 1024 kg.
Using Newton's Second Law of Motion, we may now:
The strength of the force exerted by Earth on the apple is,
F = ma
⇒ F = 0.37 × 9.8
⇒ F = 3.626 N
We are informed that the apple must exert an equal but opposite force on Earth in accordance with Newton's third law of motion.
Therefore, the force exerted by the apple on Earth will be of the following magnitude:
F = 3.626 N
Let "A" be the acceleration of the earth relative to the apple in m/s2.
Thus,
The following will be used to determine how quickly the earth is moving toward the apple:
F = MA
⇒ 3.626 = [5.98 × 10²⁴] × A
⇒ A = 3.626 / [5.98 × 10²⁴]
⇒ A = 0.606 × 10⁻²⁴
⇒ A = 6.06 × 10⁻²⁵ m/s²
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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?
Answer in kg
Answers
The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:
τ = r * F * sin(θ)
where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.
In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.
Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:
τ_M = r_M * F_M * sin(θ)
where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.
Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:
τ_M = τ_stick
r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)
Substituting the given values:
30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)
Solving for F_M:
F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)
F_M = 0.0264 kg * 9.8 m/s^2
F_M = 0.25872 N
Finally, we can convert the force into mass using the formula:
F = m * g
0.25872 N = M * 9.8 m/s^2
M = 0.0264 kg
Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
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A 0.140-kg baseball is dropped and reaches a speed of 1.20 m/s just before it hits the ground. It rebounds with a speed of 1.00 m/s. What is the change of the ball's momentum
Answers
Answer:
The change in momentum is Δp= 0.028 kg m/sExplanation:
An impulse describes a change in momentum. The change in momentum of an object is its mass times the change in its velocity.
The change in moment is given by the expression below
Δp=m⋅(Δv)=m⋅(vf−vi) .
Given data
mass m= 0.140-kg
initial velocity vi= 120 m/s
final velocity vf= 1 m/s
substituting we have
Δp=m⋅(Δv)=0.14⋅(1−1.2)
Δp=m⋅(Δv)=0.14⋅(-0.2)
Δp= 0.028 kg m/s
The change in momentum was found to be Δp= 0.028 kg m/s
In terms of electric pressure, describe a charged capacitor.
Answers
Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.
Compare the table of information with the bar graph shown. What makes verifying that the bar graph has the same information as the table especially challenging? own answer
Answer:The table uses metric tons as its numerical scale unit, whereas the bar graph uses pounds. This use of differing units means the reader must convert units of measurement before verifying that the information in the table matches the information in the bar graph.
Answers
When displaying sections of data, bar charts is used. As long as the number of categories to compare, vertical bar charts can be useful for comparing several category discrete data, like ages, classes, schools.
Why are graphs more illuminating than tables?Charts and graphs are useful visual aids because they make information accessible and quick to understand. So, it is not unexpected that both print and digital media frequently use graphs. When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.
What do the tables, graphs, and data represent?Visual representations of data, such as tables and graphs, are used to arrange information and reveal patterns and correlations. To present the results of their research, scientists and researchers frequently employ tables and graphs.
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Answer #49 please and thank you
Answers
when Force (N) is 10.0 Length (m) is 0.60
when Force (N) is 8.0 Length (m) is 0.40
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 2.0 Length (m) is 0.10
chatgpt
49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:
Period (T) = 2π√(Length (L) / g)
Substituting the given values:
2.3 = 2π√(L / 1.6)
To solve for L, we can rearrange the formula:
L = (2.3 / (2π))^2 * 1.6
L ≈ 0.781 meters (or 78.1 centimeters)
So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.
50. Ranking Task:
To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.
Ranking from least to greatest period:
1. A: 10 cm long, mass = 0.25 kg
2. C: 20 cm long, mass = 0.25 kg
3. B: 10 cm long, mass = 0.35 kg
There is a tie between pendulums A and C, as they have the same length but different masses.
What is the answer to this question number 2?
Answers
Answer:
1⁺ ion
Explanation:
Metals in the first group on the periodic table will prefer to form 1⁺ ion. This is because the 1 valence electron in their orbital.
Most metals are electropositive and would prefer to lose electrons than to gain it.
Like all metals, the group 1 elements called the alkali metals would prefer to lose and electron.
On losing an electron the number of protons is then greater than the number of electrons. This leaves a net positive charge.
At the instant shown in Figure 3, the blocks are moving toward each other with the same speed of 0.35 m/s. The blocks collide 0.50 seconds later. What is the speed of the two=block system's center of mass just before the blocks collide?
Answers
Answer:
The blocks c
Explanation:
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If answer is correct I'll rate you five stars a thanks and maybe even brainliest!
Please can you explain what this paragraph is trying to say. Also what does it mean in the sentence 'the difference in charge across the battery provides push for current' and what is the difference in charge.
Here's paragraph I need to have a simple definition of:
A high waterfall is also like a large voltage. It will transfer a lot of energy to the water (charge), making the river flow very fast (a large current) the difference in height makes the river flow. In a circuit , the difference in charge across battery provides push for the current.
Answers
It is saying that a high waterfall has a lot of potential energy that can transfer to the water and cause it to flow very fast, which is similar to how a large voltage in an electric circuit can create a large current. The difference in height of the waterfall causes the water to flow, just as the difference in charge across a battery provides the push or force for the current to flow in a circuit.
In an electric circuit, voltage is the measure of the electric potential difference between two points, and it is measured in volts. Current is the flow of electric charge through the circuit, and it is measured in amperes or amps. The difference in charge across the battery refers to the potential difference or voltage between the positive and negative terminals of the battery, which creates an electric field and provides the force or push for the current to flow through the circuit.
a gps satellite orbits at an altitude of 20,200 km above the surface of earth. what is the speed of the satellite? (recall that re
Answers
The speed of the GPS satellite in orbit is approximately 3.87 km/s.
What is the GPS satellite's orbital speed?MEO, or medium earth orbit, is the term used to describe orbits of this altitude.
We can use the formula for the speed of an object in circular orbit:
v = √(GM/r)
where v is the speed of the satellite, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite (which is the sum of the radius of the Earth and the altitude of the satellite).
The mass of the Earth is approximately 5.97 x 10²⁴kg, the radius of the Earth is approximately 6,371 km, and the altitude of the GPS satellite is 20,200 km.
Converting the units to meters, we have:
M = 5.97 x 10²⁴ kg
r = (6,371 km + 20,200 km) x 1000 m/km
= 26,371,000 m
G = 6.674 x 10⁻¹¹ N·m²/kg²
\(\mathrm{v = \sqrt{\dfrac{(6.674 \times 10^{-11} N\cdot m^2/kg^2) \times (5.97 x 10^24 kg)}{(26,371,000 m)} } }\)
= 3.87 km/s
Therefore, the speed of the GPS satellite in orbit is approximately 3.87 km/s.
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A projectile is fired at an upward angle of 55.0 ∘ from the top of a 155 m cliff with a speed of 165 m/s .
a)What will be its speed when it strikes the ground below? (Use conservation of energy and neglect air resistance.)
Answers
A projectile is fired at an upward angle and the speed of the object when it strikes the ground below will be 434.5 m/s.
What is Projectile motion?A projectile is an object or particle that is thrown toward the surface of the Earth and moves along a curved route only under the influence of gravity. Galileo demonstrated that this curving path was a parabola, but in the unique situation where it is hurled straight up, it may also be a straight line.
According to the question,
\(h=v_0_yt+1/2gt^2\)
-155 m = (165 × sin 55°)t - 0.5(9.8)t²
-155 = 135.16t - 4.9 t²
4.9 t² - 135.16t - 155 = 0
t = 27.5 seconds.
Now, the speed of the object when it strikes the ground will be,
\(v_f=v_i+gt\)
= 165 + (9.8)(27.5)
\(v_f\) = 434.5 m/s.
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A car travels at a constant speed of 12 m/s and has a momentum of 4800 kg∙m/s. What is the mass of the car?
Answers
Take into account that the momentum is given by the following formula:
\(p=mv\)where,
m: mass of the car = ?
v: speed = 12 m/s
p: momentum = 4800 kg*m/s
Solve the equation above for m, replace the values of p and v, and simplify:
\(m=\frac{p}{v}=\frac{4800kg\frac{m}{s}}{12\frac{m}{s}}=400kg\)Hence, the mass of the car is 400 kg
The strength of the force of friction depends on which two factors?
Answers
Answer:
coefficient of friction (μ) and normal force (N)
Answer: How hard the surfaces push together and the types of surfaces involved
Explanation:
Very Important, I need the answer
Answers
Answer:
A
Explanation:
A constant velocity means the position graph has a constant slope. It's a straight line sloping up.
3. Observe: An organelle is a cell structure that performs a specific function. Observe the samples below under the highest magnification. Click the Show labels checkbox to label the organelles. List the organelles and approximate size of the cells in each sample.
Answers
Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.
Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.
The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.
In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.
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A puck is moving on an air hockey table. Relative to an x,y coordinate system at time t =0s, the x
components of the puck's initial velocity and acceleration are Vix=1.0 m/s and ax=2.0 m/s². The y
components of the puck's initial velocity and acceleration are Viy=2.0 m/s and ay=2.0 m/s². Find the
magnitude and direction of the puck's velocity at a time of t=0.50 s. Specify the direction relative to
the x axis. HELPP!!!
Answers
The supplied puck is moving at a speed of v0x=+3.4m/s on an air hockey table at time t=0.
What is the meaning of velocity?The direction of the movement of the body or the object is defined by its velocity. Most of the time, speed is a scalar quantity. In its purest form, velocity is a vector quantity. It measures how quickly a distance changes. It is the rate at which displacement is changing.
What does the term "tangential velocity" refer to?Any object traveling in a circular motion has a linear speed known as tangential velocity. On a turntable, a point in the center moves less distance in a full rotation than a point near the outside edge.
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Two students (90.0 kg and 60.0 kg) on roller skates face-to-face push against each other. The 90.0 kg student moves at 5.0 m/s just after their hands lose contact. What is the velocity of the other student?
Answers
Given that,
Mass of student 1, m₁ = 90 kg
Mass of student 2, m₂ = 60 kg
Speed of student 1, v₁ = 5 m/s
To find,
The velocity of the other student.
Solution,
Using the conservation of momentum to find the velocity of the other student. Let it is v₂.
\(m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\v_2=\dfrac{90\times 5}{60}\\\\=7.5\ m/s\)
So, the velocity of the other student is 7.5 m/s.
A 10 kg box is on an inclined plane that is 40 degrees above the horizontal. It is sliding
down with a constant velocity.
a. Draw a free body diagram with Fg, FN, F₂ and Ff.
b. What is the weight of the box?
What is the normal force of the box?
c. What is the force of friction acting on the box?
d. What is the net force acting on the box?
Answers
A horizontal force of 10.0 N is acting on a 10 kg box that is sliding to the right along the floor with velocity v.
What are the assumptions for drawing a free-body diagram?Most people make the common assumptions of rigid body action and ignoring air resistance and friction. In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation.
The specific situation and the presumptions used will determine how many forces and moments are displayed. Most people make the common assumptions of rigid body action and ignoring air resistance and friction.
In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation. The resultant forces and moments in dynamics can have non-zero values.
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Which kind of waves is not part of the electromagnetic spectrum?
Sound waves
Radio
Microwaves
X-rays
Answers
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
Answers
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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When a projectile reaches the highest point the vertical component of the acceleration is:
(A) Less than g (B) Greater than g (C) Positive g (D) Negative g
Answers
Answer:
The acceleration is g.
Taking the upward direction as positive
V = Vy y - 1/2 g t^2
Taking the downward direction as positive
V = -V y + 1/2 g t^2
One can choose either direction as positive, but the acceleration is
the same as g (it is g) while the projectile is in the air.
When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.
What is Projectile motion?Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.
When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.
Therefore, the correct option is D.
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how many hours in space is one hour on earth
Answers
The concept of time in space can be different from time on Earth due to the effects of time dilation. Time dilation occurs due to differences in gravitational fields and relative motion.
If we consider an astronaut who is in a relatively low-gravity environment and not traveling at a significant fraction of the speed of light, the time experienced by the astronaut in space would be very similar to the time experienced on Earth. In this scenario, one hour in space would be approximately the same as one hour on Earth.
However, if we consider extreme cases, such as an astronaut near a black hole or traveling at near-light speeds, time dilation effects would become significant. In these situations, the time experienced by the astronaut would be different from the time on Earth.
It's important to note that the magnitude of time dilation effects depend on the specific conditions and relative velocities involved. For most common space travel scenarios, the difference in time between space and Earth is negligible, and one hour in space would correspond to one hour on Earth.
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1) a stationary object may have______
a.potential energy b.velocity
c.kinetic energy d.acceleration
Answers
Explanation:
I think it's option a..
I think this is it!
pls try to understand my doubt and clear it
.
Answers
If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?
Answers
H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ
The energy transferred to aluminum from 20°C to 40 °C is equal to 36840 J.
What is the specific heat capacity?The specific heat capacity can be described as the quantity of heat required to increase the temperature of 1 unit of substance by one degree Celsius. The specific heat capacity of the substance depends upon the nature of the substance.
The mathematical equation is used to calculate the specific heat is equal to:
\(Q = m\times C\times \triangle T\)
Given, the mass of the aluminum block, m = 2 Kg
The initial temperature of aluminum, T₁ = 20 °C
The final temperature of the aluminum, T₂ = 40 °C
The specific heat capacity of aluminum, C = 921 J/kg°C
The energy transferred to the aluminum block:
Q = 2 × 921 × (40-20)
Q = 36840 J
Therefore, the energy transferred to aluminum from 20°C to 40°C is 36840 J.
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how does the vertical component of a projectiles compare to the motion of vertical free fall when air resistance is neglected?
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I need help please will mark brainliest
Answers
Answer:
200
Explanation:
20m/s*10sec=200