f(n) is upper Bounded by g(h). As n-> infinity F(n) will grow slower or as fast as g(n) but never faster. Option D.
This gives an asymptotic upper bound on the rate of increase in algorithm execution time. Let f(n) be the execution time of the algorithm and g(n) be the time complexity associated with the algorithm. Omega notation represents a lower bound on the running time of an algorithm.
It thus provides the optimal complexity of the algorithm. The above expression can be written as a function f(n) belonging to the set Ω. If a positive constant c exists and is above CG (n) for sufficiently large n. The number d is called tolerance. Arithmetic progressions differ by d and are obtained by subtracting any pair of terms an and On +1.
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5. What are 3 ways you can alter pH for the benefit of you and
your family?
Question 10 (1 point)
A water wave in a 17 m long pool takes 3 seconds to travel to one end of the pool.
What is the speed of the wave?
Answer:
5.67 m/s
Explanation:
The speed of a wave can be calculated as the distance traveled by the wave divided by the time taken:
Speed = Distance/Time
In this case, the distance traveled by the wave is the length of the pool, which is 17 m. The time taken by the wave to travel this distance is 3 seconds.
So, the speed of the wave can be calculated as:
Speed = 17 m/3 s
Speed = 5.67 m/s
Therefore, the speed of the water wave in the 17 m long pool is 5.67 m/s.
A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
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What are possible formulas for impulse? Check all that apply.
Answer:
J = FΔt
J = mΔv
J = Δp
Explanation:
The Impulse Formula:Δp = Change in momentumF = Applied forceΔt = Elapsed timeMention 2 everyday applications each of conduction, convection and radiation
Answer:
Conduction: Touching a stove and being burned. Ice cooling down your hand. .
Explanation:
What quantity of heat is transferred when a 150.0g block of iron metal is heated from 25.0°C to 73.3°C? What is the direction of the heat flow?
Answer:
Heat is flowing into the metal.
Explanation:
From the question given above, the following data were obtained:
Mass (M) of iron = 150 g
Initial temperature (T₁) = 25.0°C
Final temperature (T₂) = 73.3°C
Direction of heat flow =?
Next, we shall determine the change in the temperature of iron. This can be obtained as follow:
Initial temperature (T₁) = 25.0 °C
Final temperature (T₂) = 73.3 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 73.3 – 25
ΔT = 48.3 °C
Next, we shall determine the heat transfered. This can be obtained as follow:
Mass (M) of iron = 150 g
Change in temperature (ΔT) = 48.3 °C
Specific heat capacity (C) of iron = 0.450 J/gºC
Heat (Q) transfered =?
Q = MCΔT
Q = 150 × 0.450 × 48.3
Q = 3260.25 J
Since the heat transferred is positive, it means the iron metal is absorbing the heat. Thus, heat is flowing into the metal.
The image shows the right-hand rule being used for a current-carrying wire.
An illustration with a right hand with fingers curled and thumb pointed up.
Which statement describes what the hand shows?
When the current flows down the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
When the current flows down the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.
When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.
Answer:
The answer is (D): When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.
Explanation:
How does the law of conservation of mass apply to chemical reactions?
Answer: mass is neither created nor destroyed
Explanation: For example, the carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.
(A) Electricity and Magnetism
A). Three point charges are aligned along the x axis as shown in
Fig. Find the electric field at (a) the position (2, 0) and (b) the
position (0, 2).
electricity
Explanation:
the position (2,o
A man applies a force of 315 N to push the block of 225 kg onto 10 m ramp. Calculate the efficiency of the person if the mass gains a height of 1.2 m.
Answer:
η = 0.84 = 84%
Explanation:
The efficiency of the man can be given by the following formula:
η = output/input
where,
η = efficiency of man = ?
output = potential energy gain of the block = mgh
input = work done by man = Fd
Therefore,
\(\eta = \frac{mgh}{Fd}\)
where,
m = mass of block = 225 kg
g = acceleration due to gravity = 9.81 m/s²
h = height gained by block = 1.2 m
F = force exerted by man = 315 N
d = distance covered by man = 10 m
Therefore,
\(\eta = \frac{(225\ kg)(9.81\ m/s^2)(1.2\ m)}{(315\ N)(10\ m)}\)
η = 0.84 = 84%
what is the weight of a 10 kg object on earth
Answer:
100N.
Its 100n. :)
The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic force is the strongest.
N
Answer:
strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.
Explanation:
The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.
Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.
A small car with mass 0.610 kg
travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m
If the normal force exerted by the track on the car when it is at the top of the track (point B
) is 6.00 N
, what is the normal force on the car when it is at the bottom of the track (point A
)?
Express your answer with the appropriate units.
The normal force on the car when it is at the bottom of the track is 8.84 N.
At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:
N = mg + mv²/r
where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.
Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:
N = mg
Substituting the given values, we get:
6.00 N = (0.610 kg)(9.81 m/s²)
Solving for g, we get:
g = 9.68 m/s²
At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:
N = mg - mv²/r
Substituting the known values, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)
Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:
mg(2r) = (1/2)mv²
where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:
v = sqrt(2gr)
Substituting the known values, we get:
v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s
Substituting this value of v into the equation for N, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N
Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.
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Why did the “yielders” conform in Asch’s experiment?
Answer:
Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.
Which is an example of a chemical change?
A pot of water boiling and turning into water vapor
Iron wheels of roller skates rusting when it rains outside
Water in a nice cube tray freezing into ice
Ripping up a piece of paper
Answer:
Iron wheels of roller skates rusting when it rains outside
Explanation:
A chemical change happens when one chemical substance is transformed into one or more different substances, such as when iron becomes rust.
A 41.6-kg person, running horizontally with a velocity of +4.21 m/s, jumps onto a 14.6-kg sled that is initially at rest. (a) Ignoring the effects of friction during the collision, find the velocity of the sled and person as they move away. (b) The sled and person coast 30.0 m on level snow before coming to rest. What is the coefficient of kinetic friction between the sled and the snow?
Answer:
a) v = 3.116 m / s, b) μ = 1.65 10⁻²
Explanation:
a) to find the velocity of the set, let's define a system formed by the person and the sled, so that the forces during the collision are internal and the moment is conserved
initial instant. Before the crash
p₀ = M v₀
final instant. After the crash
p_f = (M + m) v
the moment is preserved
M v₀ = (M + m) v
v = \(\frac{M}{M+m} \ v_o\)
let's calculate
v = \(\frac{41.6}{41.6 + 14.6} \ 4.21\)
v = 3.116 m / s
b) for this part let's use the relationship between work and kinetic energy
W = ΔK
as the body has its final kinetic energy is zero
the work of the friction forces is
W = - fr x
the negative sign is because the friction forces always oppose the movement
let's write Newton's second law
Y axis
N - W_sled -W_person = 0
N = mg + M g
N = (m + M) g
X axis
fr = ma
the friction force has the expression
fr = μ N
fr = μ g (m + M)
we substitute
- μg (m + M) x = 0- ½ (m + M) v²
μ = \(\frac{1}{2} \ \frac{v^2 }{g \ x }\)
let's calculate
μ = \(\frac{1}{2} \ \frac{3.116^2}{9.8 \ 30.0}\)
μ = 0.0165
μ = 1.65 10⁻²
how much energy is possessed by 1 mole of nitrogen atoms moving at 35.0 m/s ?
1 mole of nitrogen atoms moving at 35.0 m/s possesses approximately 27.8 joules of energy.
To calculate the energy possessed by 1 mole of nitrogen atoms moving at 35.0 m/s, we need to consider both the kinetic energy and the molecular mass of nitrogen.
The kinetic energy (KE) of an object is given by the equation KE = 1/2 * m * v^2, where m is the mass and v is the velocity.
The molar mass of nitrogen (N₂) is approximately 28.0134 g/mol, which can be converted to kilograms by dividing by Avogadro's number (6.022 × 10^23). This gives us a mass of approximately 4.65 × 10^(-26) kg for one nitrogen atom.
Plugging in the values, we have KE = 1/2 * (4.65 × 10^(-26) kg) * (35.0 m/s)^2.
Evaluating the equation, we find that the kinetic energy possessed by one nitrogen atom is approximately 4.62 × 10^(-23) joules.
Since we are considering 1 mole of nitrogen atoms, we need to multiply this value by Avogadro's number to get the energy possessed by 1 mole. Avogadro's number is 6.022 × 10^23, so the total energy is approximately 2.78 × 10^1 joules, or 27.8 J.
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Projeche Problems
1.
A ball is kicked from the top of one building towards another building that is 15.24 m away. The
initial velocity of the ball is 6.1 m/s 40° above the horizontal. How far above or below its original
level will the ball strike the opposite wall?
the ball will strike the opposite wall 6.22 m below its original level.
To solve this problem, we need to use the equations of motion for a projectile. The horizontal and vertical components of the initial velocity are:
V₀x = V₀ cosθ = 6.1 cos(40°) = 4.65 m/s
V₀y = V₀ sinθ = 6.1 sin(40°) = 3.91 m/s
The time it takes for the ball to reach the opposite wall can be found using the horizontal distance and the horizontal component of velocity:
d = V₀x t
t = d / V₀x = 15.24 m / 4.65 m/s = 3.28 s
The vertical distance traveled by the ball can be found using the equation:
y = V₀y t - 1/2 g t²
where g is the acceleration due to gravity, which is -9.81 m/s² (negative because it acts downward). Substituting the known values, we get:
y = 3.91 m/s × 3.28 s - 1/2 × 9.81 m/s² × (3.28 s)² = 6.22 m
Therefore, the ball will strike the opposite wall 6.22 m below its original level.
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Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom of the hill and car C is at the top. Suppose each car suddenly brakes hard and starts to skid. Assume μk=1.00. What is the x-component of the tangential acceleration (i.e., the acceleration parallel to the road) of car A?
Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.
How do kinetic and potential energy compare?The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.
They are being affected by the kinetic frictional force, which is caused by:
f = μk * N
Therefore,
fB = μk * N = μk * mB * g
Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,
fC = μk * N = μk * mC * g
where mC is the mass of Car C.
For Car A, the x-component of the tangential acceleration is given by:
aA = (fB - fC) / mA
where mA is the mass of Car A.
We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:
aA = (μk * mB * g - μk * mC * g) / mA
aA = μk * g * (mB - mC) / mA
Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:
aA = (mB - mC) * 9.81 / mA
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Using the momentum formula, calculate the momentum of a 325 kg rock, rolling down a hill at 1.75 m/s.
We are asked to determine the momentum of a particle that is moving at a velocity of 1.75 m/s and has a mass of 325 kg.
To do that we will use the following formula:
\(P=mv\)Where:
\(\begin{gathered} P=\text{ momentum} \\ m=\text{ mass} \\ v=\text{ velocity} \end{gathered}\)Now, we substitute the values:
\(P=(325kg)(1.75\text{ m/s\rparen}\)Now, we solve the operations:
\(P=568.75kg\text{ m/s}\)Therefore, the momentum is 568.75 kg m/s.
528.65 kgm/s
Since mass of body=325 kg
(we will not change kilograms into grams as kilograms is the standard international unit .)
velocity of the ball rolling down the hill=1.75meter/second
since we know momentum=mass x velocity
and standard international unit of momentum is kgm/s that is kilogram meter per second
hence substituting the values of mass and velocity in the above expression we get :-
momentum=(325 x 1.75) kgm/s
momentum =568.75 kgm/s
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If Nell was blocking a defensive lineman for the South Grand Prairie Warriors with a force of 126 Newtons and had a mass of 56.2 kg…what would his acceleration be equal to?
Answer:
2.24 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
m is the mass
f is the force
From the question we have
\(a = \frac{126}{56.2} \\ = 2.241992...\)
We have the final answer as
2.24 m/s²Hope this helps you
Find the x-component of this
vector:
15.3 m
65.0°
Please help!
Given :
Magnitude of vector, v = 15.3 m
Angle of vector from horizon, \(\theta = 65^o\) .
To Find :
The x - component of the given vector.
Solution :
We know, a vector is given by :
\(\vec{v} = vsin\ \theta \hat{i} + v cos \ \theta \hat{j}\\\)
Now, the x - component is :
\(\vec{v_x} = vcos\ \theta \hat{j}\\\\\vec{v_x} = 15.3 \times cos\ 65^o \hat{j}\\\\\vec{v_x} = 15.3 \times 0.42\ \hat{j}\\\\\vec{v_x} = 6.426\ \hat{j}\)
Hence, this is the required solution.
C.S. Lewis calls the rule of Right and Wrong or "Law of Human Nature" _______________. (Bk I, Mere Christianity)
C.S. Lewis calls the rule of Right and Wrong or the "Law of Human Nature" the Moral Law which states that, this law is universal and applies to all people, regardless of their faith or lack thereof.
In Mere Christianity, Lewis argues that the Moral Law is not something that can be created or invented by humans, but is instead something that is discovered. He explains that the Moral Law is like a set of rules that can be found in nature, just as one can discover the laws of mathematics or physics. The Moral Law is a set of moral principles that underlie all our ethical decisions, such as the notion of “do unto others as you would have them do unto you.” C.S. Lewis claims that this Law is universal and unchanging, and is the basis of all moral decisions and argues that it is not something that can be altered or changed by humans.
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complete question: C.S. Lewis says (1) the "Law of Human Nature" (ie. the "Moral Law") and (2) the other "laws of nature," such as the law of gravitation and the biological laws, are _______________. (Bk I, Mere Christianity)
Select the correct answer.
In general, how does an increase in distance from the Sun affect a planet?
ОА. .
The amount of sunlight the planet receives decreases.
OB.
The gravitational force exerted by the Sun increases.
ОС.
The thickness of a planet's atmosphere increases.
OD. The planet's atmosphere absorbs more heat.
Answer:
a.
gravity decreases by distance
thickness doesn't change
Less heat.
For the following distance vs time graph
Answer:
3
5
4
Explanation:
x = (8=(9+9)
(9+9) = 4, 5, 3
The pressure at the bottom of a jug filled with water does NOT depend on the
__________.
A) depth of the liquid
B) acceleration due to gravity
C) density of water
D) surface area of the water
E) none of the above
Answer:
D
Explanation:
because of the the side of the bottom
Please help me with this question.
With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.
By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.
According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.
The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
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what two things make up an ionic bond?
the temperature rise a motor when operating for 25 minutes on full load is 25 degrees Celsius and becomes 40degree when the motor operates for another 25 minutes on same load determine heating time constant and steady state temperature.
The heating time constant is 13 seconds and the steady state temperature is 38°C.
How to determine time and temperatures?To find the heating time constant and steady state temperature, use the formula:
ΔT = P × R × (1 - e^(-t/τ))
where ΔT = temperature rise, P = power, R = thermal resistance, t = time, τ = heating time constant, and e = natural logarithmic constant.
Let's use the given information to solve for τ:
ΔT1 = 25°C (for the first 25 minutes)
ΔT2 = 40°C (for the second 25 minutes)
t = 25 + 25 = 50 minutes
The temperature rise over the entire 50 minutes is:
ΔT = ΔT1 + ΔT2 = 25°C + 40°C = 65°C
The average power can be calculated as:
P = ΔT / (t × R)
Assume that the power output is the rated power of the motor. Let's assume that the rated power is 100 W.
Then, solve for R:
R = ΔT / (t × P) = 65°C / (50 min × 100 W) = 0.13 °C/W
Now, solve for the heating time constant:
τ = R × C
where C = thermal capacitance. Value of C is unknown, but make an assumption that the thermal time constant is on the order of minutes to hours. Let's assume that C = 100 J/°C.
Then, τ = 0.13 °C/W × 100 J/°C = 13 seconds
Finally, solve for the steady state temperature:
ΔT = P × R
T_ss = T_amb + ΔT = 25°C + 100 W × 0.13°C/W = 38°C
Therefore, the heating time constant is 13 seconds and the steady state temperature is 38°C.
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I NEED A 100% ACCURATE ANSWER FOR THIS QUESTION ASAP NO LINKS !!!
What is defined by force per unit area?
1: gravity
2: force
3: temperature
4: pressure
Answer:
4. pressure is defined as force per unit area
Pressure is defined by force per unit area.
WHAT IS PRESSURE:Pressure refers to the force applied to a substance per unit area. Force is measured in Newtons (N) while area is measured in m², hence, the unit of pressure is N/m² also called pascal.Therefore, according to this question, it can be said that pressure is defined by force per unit area
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