finley's pumpkin had a mass of 6.56.56, point, 5 kilograms (\text{kg})(kg)(, start text, k, g, end text, )before he carved it. after it was carved, the pumpkin had a mass of 3.9\,\text{kg}3.9kg3, point, 9, start text, k, g, end text. what was the percent decrease in the mass of the pumpkin?
Answers
According to the given statement 40.55 % was the percent decrease in the mass of the pumpkin.
What are weight and mass?In order to determine how much matter a body contains, its mass is utilized. Mass is denoted by the letters m or M. The acceleration caused by gravity on a mass is measured in terms of weight. W is usually an acronym for weight.
Briefing:6.56 kg was the pumpkin's previous mass.
Pumpkin's new weight is 3.9 kg.
Pumpkin mass loss is equal to the difference between the previous and new masses of pumpkin.
6.56 kg less 3.9 kg equals 2.66 kg
The pumpkin's mass will now have decreased by the following percentage:
\($\frac{\text { Decrease in mass }}{\text { Previous mass }} \times 100$\)
=2.66 / 6.56 * 100
= 0.40548780487 * 100
= 40.55 %
Consequently, the pumpkin's mass decreased by 40.55% as a percentage.
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Related Questions
which is a harmful role of bacteria of bacteria?
Answers
Answer:
Harmful bacteria are called pathogenic
Explanation:
Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.
We will investigate 3 different object positions for a diverging lens: inside, at and outside the focal length. We will use the same object positions used above, but with a diverging lens (f will be negative). Verify that the image is always virtual for diverging lenses.
5. Using the magnification equation, what will be the objects magnification, M, given the p and q from above? Is the object upright (M positive) or inverted (M is negative)?
6. Run the simulation. Set the lens type to diverging with a focal length of -50 cm. Place the object at a distance of 50 cm and a height of 25 cm. Compare the image sign and distance to that computed above. Does the height and direction of the image agree with your magnification computations? Comment below.
7. Using the thins lens equation, for p = +80 and f = -50, what will be the image sign and location? Show your work here.
8. What will be the objects magnification, M, given the p and q from above? Is the object upright (M positive) or inverted (M is negative)? See note above.
Answers
The magnification is M = -q/p = 1.56, indicating that the image is larger than the object and upright.
Diverging lenses always produce virtual images, regardless of the position of the object. The magnification equation is M = -q/p, where p is the object distance, q is the image distance, and the negative sign indicates that the image is upright (positive M) and virtual. In the simulation, placing the object at 50 cm with a height of 25 cm and a diverging lens with a focal length of -50 cm produces an image that is virtual, upright, and farther away than the object. Using the thin lens equation with p = +80 cm and f = -50 cm, the image distance q can be calculated as -125 cm, indicating that the image is virtual, upright, and farther away than the object. The magnification is M = -q/p = 1.56, indicating that the image is larger than the object and upright.
5. The magnification equation is M = -q/p. For diverging lenses, p is positive, and q is negative, resulting in a positive M value. This means the object is always upright for diverging lenses.
6. In the simulation with a diverging lens (f = -50 cm), object distance (p = 50 cm), and object height (h = 25 cm), you will observe a virtual, upright image, agreeing with the magnification computations.
7. Using the thin lens equation, 1/f = 1/p + 1/q, plug in values for f (-50 cm) and p (80 cm). Solving for q, you get q = -28.57 cm. This indicates a virtual image with a negative distance.
8. To find magnification, M, use M = -q/p. With p = 80 cm and q = -28.57 cm, M = 0.357 (positive). The object is upright, as M is positive.
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an old building is being demolished by swinging a heavy metal ball from a crane. suppose that the ball swings from a 20 -m-long wire at speed as the wire passes the vertical orientation. (a) what tension force must the wire be able to withstand in order not to break? (b) assume the ball stops after sinking into the wall of the building. what was the average force that the ball exerted on the wall? indicate any assumptions you made for each part of the problem.
Answers
Answer:
Explanation:
Newton's second law allows us to find the results for the questions about the forces in the motion of the ball are:
a) The cable tension is: T = 1955 N
b) The force to stop the ball is: F = 5520 N
Newton's second law gives a relationship between force, mass and acceleration of bodies.
F = ma
The bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
The ball is oscillating therefore its movement is circular, in the lower part of the trajectory the centripetal acceleration is:
a) A free body diagram is a diagram of the forces without the details of the body, in the attachment we can see a free body diagram of the system.
T - W = ma
T = W + ma
We substitute.
T = m (g + v ^ 2 / r)
Let's calculate.
T = 115 (9.8 + 12 ^ 2/20)
T = 1955 N
b) To find the average force, let's find the average acceleration to stop with kinematics.
v² = v₀² - 2 a x
When the ball moves, its velocity is zero.
Let's calculate.
a = 48 m /s²
We substitute in Newton's second law.
F = m a
F = 115 48
F = 5520 N
In conclusion using Newton's second law we can find the results for the questions about the forces in the motion of the ball are:
a) The cable tension is: T = 1955 N
b) The force to stop the ball is: F = 5520 N
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active attachment
What happens to a circuit's resistance (R), voltage (V), and current (1) when
you change the thickness of the wire in the circuit?
A. V and I will also change, but R will remain constant.
B. R and I will also change, but V will remain constant.
O C. R, V, and I will all remain constant.
OD. R and V will also change, but I will remain constant.
Answers
When you change the thickness of the wire in a circuit, option B. the resistance (R) and current (I) will also change, but the voltage (V) will remain constant.
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area (thickness). As the thickness of the wire changes, the cross-sectional area changes, which in turn affects the resistance. Thicker wires have a larger cross-sectional area, resulting in lower resistance, while thinner wires have a smaller cross-sectional area, resulting in higher resistance. Therefore, changing the thickness of the wire will cause a change in resistance.
According to Ohm's Law (V = IR), the voltage (V) in a circuit is equal to the product of the current (I) and the resistance (R). If the voltage is kept constant, and the resistance changes due to the thickness of the wire, the current will also change to maintain the relationship defined by Ohm's Law. When the resistance increases, the current decreases, and vice versa.
However, it's important to note that changing the thickness of the wire will not directly affect the voltage. The voltage in a circuit is determined by the power source or the potential difference applied across the circuit and is independent of the wire thickness. As long as the voltage source remains constant, the voltage across the circuit will remain constant regardless of the wire thickness. Therefore, the correct answer is option B.
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Knowing the direction of heat flow, explain why if you leave a hot bowl of soup out in the open on the countertop, it eventually gets cold. Where is the heat going?
Answers
The heat will flow towards the air surrounding the soup bowl and towards the countertop below the bowl.
Where does the heat go?We know that when two bodies of different temperatures there will be a flow of heat between the objects, from the hotter one to the colder one.
In this case, we have the bowl of soup as the hot object, and the ambient (the countertop, the air surrounding the bowl, etc) itself will be the cooler object.
Then the heat will flow towards the air surrounding the soup bowl and towards the countertop below the bowl.
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If the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27o, find the refractive index of the material
Answers
The refractive index of the material is 0.
When the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27°, the refractive index of the material can be determined. The formula for Snell’s law is used to calculate refractive index. It states that: `sin i / sin r = n where i is the angle of incidence, r is the angle of refraction and n is the refractive index`.Snell’s law can be re-arranged to make n the subject of the formula to be: `n = sin i / sin r`Hence, we can calculate the refractive index as follows:
For the incident ray, i = 360° and the angle of refraction within the material, r = 27°.n = sin i / sin r= sin 360°/ sin 27°= 0/1 (since sin 360° = 0)= 0Therefore, the refractive index of the material is 0. T
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a soccer player kicks a rock horizontally off a 39 m high cliff into a pool of water. if the player hears the sound of the splash 2.98 s later, what was the initial speed given to the rock (in m/s)? assume the speed of sound in air is 343 m/s.
Answers
The initial speed given to the rock was 28.18 m/s horizontally. The formula that is used is : he height, h = ut + (1/2)gt²
Given: Height, h = 39 m, Speed of sound, v = 343 m/s, Time, t = 2.98 s, Acceleration due to gravity, g = 9.8 m/s², Initial velocity of rock, u = ?
Formula: The height, h = ut + (1/2)gt² (Taking upward direction as positive)
We get, u = (h - (1/2)gt²)/t. The rock was thrown horizontally.
Therefore, there is no initial vertical velocity.
So, we have to consider only the horizontal velocity.
Hence, the formula of horizontal displacement, s is , s = v₀tAs
there is no acceleration in horizontal motion, v = v₀
Here, s = horizontal distance = ? v = 343 m/st
= 2.98 s
Substituting the given values, we get, h = (v₀/2)t
⇒ v₀
= 2h/t
g = 9.8 m/s²
Putting the values, we get, u = (39 - (1/2)(9.8)(2.98)²)/2.98
= 28.18 m/s
So, the initial speed given to the rock was 28.18 m/s horizontally.
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The fact that some well-known studies have been repeated without finding results consistent with those in the initial report describes a(n) ________ that is currently affecting research in psychology and other fields.
Answers
Answer:
Replication Crisis
Explanation:
Replication crisis in psychology- It refers to the concerns about credibility of finding the results in psychological science.
The rate at which the temperature increases with depth is called the geothermal gradient. What is the geothermal gradient in a tectonically stable region where the temperature is 119° C at a depth of 5.0 km?
(Assume a surface rock temperature of 14° C.)
Answers
The geothermal gradient in the tectonically stable region is approximately 21°C/km, indicating that the temperature increases by an average of 21 degrees Celsius per kilometer of depth.
To calculate the geothermal gradient, we need to find the rate at which the temperature increases with depth.
Temperature at the surface (T₁) = 14°C
Temperature at a depth of 5.0 km (T₂) = 119°C
Temperature difference = T₂ - T₁ = 119°C - 14°C = 105°C
Depth difference = 5.0 km - 0 km = 5.0 km
Geothermal gradient = Temperature difference / Depth difference
Geothermal gradient = 105°C / 5.0 km
Calculating this expression, we find:
Geothermal gradient ≈ 21°C/km
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What is the slope of the line plotted below? (-2,-1) (4,2) A. 1 B. 2 C. -0.5 D. 0.5
Answers
Answer: D. 0.5
Explanation:
The slope formula is y2-y1/x2-x1.
2-(-1)/4-(-2) = 2+1/4+2
2+1/4+2 = 3/6 = 1/2
1/2 = 0.5
The slope is 1/2, or 0.5.
if i raise a 2 kg book 0.8m over my head determine the amount of work that i have done
Answers
If you raise a 2 kg book 0.8m over your head, the amount of work that you have done is 15.68 J
F = m g
F = Force
m = Mass
g = Acceleration due to gravity
m = 2 kg
g = 9.8 m / s²
F = 2 * 9.8
F = 19.6 N
W = F d cos θ
W = Work done
d = Distance
θ = Angle between force and displacement vector
d = 0.8 m
θ = 0
W = 19.6 * 0.8
W = 15.68 J
Therefore, the amount of work that you have done is 15.68 J
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A resistor with resistance 640 Ω is in a series with a capacitor of capacitance What capacitance must be placed in parallel with the original capacitance to change the capacitive time constant of the combination to three times its original value?
Answers
To change the capacitive time constant of the combination to three times its original value, a capacitance of 3.47 microfarads must be placed in parallel with the original capacitance.
The time constant of an RC circuit (resistor-capacitor circuit) is given by the product of resistance and capacitance, i.e., RC. In this case, we have an RC circuit with a resistor of 640 Ω and an unknown capacitance C. Let the original time constant be τ. Then,
τ = RC = 640C
To change the time constant to three times its original value, we need:
3τ = 3RC = 640(3C)
Solving for C, we get:
C = 3.47 microfarads
Therefore, a capacitance of 3.47 microfarads must be placed in parallel with the original capacitance to change the capacitive time constant of the combination to three times its original value.
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much like a battery these generate electricity from chemical events
Answers
The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.
When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.
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. A 225-kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate
Answers
The acceleration of the crate is 1.196 m/s².
What is acceleration?This can be defined as the rate of change of velocity.
To calculate the acceleration of the crate, we use the formula below.
Formula:
a = (F-mgμ)/m................. Equation 1Where:
a = acceleration of the cratem = mass of the crateF = Force applied to the crateμ = Coefficient of frictionFrom the question,
Given:
m = 225 kgF = 710 Ng = 9.8 m/s²μ = 0.20Substitute the values above into equation 1
a = [710-(225×9.8×0.20)]/225a = (710-441)/225a = 269/225a = 1.196 m/s²Hence, The acceleration of the crate is 1.196 m/s²
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A 1.70 m long string has a standing wave with 2 loops at a frequency of 38.4 Hz. What is the speed of the waves in the string? (Unit = m/s)
Answers
Answer:65.28
Explanation:
A long string has a standing wave with 2 loops at a frequency. The speed of the waves in the string is 65.28 m/s
What is frequency?The frequency is the number of cycles completed per second.
Given the length of the string l = is 1.70 m, no of loops n =2, frequency of wave f =38.4 Hz, then the speed of the waves is
f = nv /2l
Substitute the following values, we get
v = 38.4 x 2 x 1.70 / 2
v =65.28 m/s
Thus, the speed of the waves in the string is 65.28 m/s.
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If a man with
with long-sighted eye want to
a' text book, what shoðld be the distance between
book and the lens? Give reason
Answers
the weight of a body of certain mass become zero in space.why?
Answers
Answer:
There is no force in space.
Explanation:
Weight is the gravitational force acting on the mass as in space there is no gravity so weight appeares as zero
Answer:
It is because of gravity that your weight of a certain mass becomes zero in space.
Explanation:
A closely wound rectangular coil of 80 turns has dimensions 25. 0 cm
by 40. 0 cm. The plane of the coil is rotated from a position in which it makes an angle of 37. 0 degrees with a magnetic field of 1. 10 T
to a position perpendicular to the field. The rotation takes 0. 0600 s. What is the average emf E
induced in the coil?
Answers
The average emf induced in the coil is 0. 533 V. The average emf induced in the coil can be calculated using Faraday's law of electromagnetic induction. The formula for the average emf induced in a coil is given by:
E = N * (ΔΦ / Δt)
where E is the average emf, N is the number of turns in the coil, ΔΦ is the change in magnetic flux, and Δt is the time interval.
In this case, the number of turns is 80, and the time interval is 0.0600 s. The change in magnetic flux can be calculated by finding the initial and final flux values.
The initial flux is given by Φ1 = B * A * cos(θ1), where B is the magnetic field, A is the area of the coil, and θ1 is the angle between the coil and the magnetic field.
The final flux is given by Φ2 = B * A * cos(θ2), where θ2 is 90 degrees since the coil is perpendicular to the field.
Substituting the values into the formula, we have:
\(E = 80 * (Φ2 - Φ1) / Δt\)
Calculating the values, we find:
\(Φ1 = (1.10 T) * (0.25 m) * (0.40 m) * cos(37.0°) = 0.536 WbΦ2 = (1.10 T) * (0.25 m) * (0.40 m) * cos(90°) = 0.110 WbΔΦ = Φ2 - Φ1 = 0.110 Wb - 0.536 Wb = -0.426 Wb\)
Substituting the values into the formula, we get:
E = 80 * (-0.426 Wb) / 0.0600 s = -0.568 V
Taking the absolute value, the average emf induced in the coil is 0.568 V or approximately 0.533 V.
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What would happen if an Asteroid hit earth?
Answers
Answer:
There would be tremendous earthquakes and tsunamis, followed by massive volcanism around the impact zone. The ozone layer would be destroyed. The oceans would turn acidic. The Sun would be blotted out, probably for decades.
Explanation:
Hope this helps!
Answer: Well it depends on the size. If the asteroid was the size of a basketball, it would most probably turn to dust by the time it reaches the surface. But, if it was the size of Australia, then most probably everyone would die.
Explanation:
HURRY! I HAVE 5 MIN LEFT!!!Robert picks up a metal pan lid that was covering a pot of boiling water, and he drops it immediately. Cells in his fingers sent the message that his finger had touched heat.
The message carried is the nerve impulse, which is transmitted to nearby cells. What is the space where one neuron can transmit the impulse to another neuron called?
Answers
Answer:
synapse
Explanation:
The message carried is the nerve impulse, which is transmitted to nearby cells. The space where one neuron can transmit the impulse to another neuron is known as a Synapse.
What is Neuron?
Neurons, also known as neurons or nerve cells, are the basic building blocks of the nervous system and brain. They are the cells in charge of receiving sensory information from the outside world, trying to send motor commands to with us muscles, and converting and relaying electrical signals at each stage along the way.
However, their interactions also shape what we are as people. However, our about 3 trillion neurons do connect with some other cell types that are generally referred to as glia in a close manner.
Visualizing a cell as a tree is a helpful analogy. Three essential components of a neuron are dendrites, an axon, and a cell body, or soma, that can be compared to the branches, foundations, and core of a tree, correspondingly.
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the first s-wave reaches a seismic station 22 minutes after an earthquake occurred. how long did it take the first p-wave to reach the same seismic station?
Answers
The time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.
Time of travel of the P-wave
In rock, S waves generally travel about 60% the speed of P waves, and the S wave always arrives after the P wave.
Relationship between speed and timev ∝ 1/t
v₁t₁ = v₂t₂
t₁/t₂ = v₂/v₁
t₁/t₂ = 0.6v₁/v₁
t₁/t₂ = 0.6
t₁ = 0.6t₂
t₁ = 0.6 x 22 mins
t₁ = 13.2 mins
Thus, the time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.
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8. Fig. 4.1 shows a heavy ball B of weight W suspended from a fixed beam by two ropes P and Q.
P and Q are both at an angle of 45° to the horizontal. The tensions in P and Q are each 30 N.
a. In the space below, draw a scale diagram to find the resultant of the tensions
in P and Q. Use a scale of 1.0cm to represent 5.0 N. Label the forces and show
their directions with arrows.
Answers
Answer:
The resultant tension of the two ropes is approximately 42.4 N
The length of the line representing the resultant tension is approximately 8.48 cm
Please find included with the answer the scale drawing created with Microsoft Word
Explanation:
The given parameters are;
The tension in rope P, \(T_P\) = 30 N
The tension in rope Q, \(T_Q\) = 30 N
The angle the rope, 'P', makes with the horizontal = 45°
The angle the rope, 'Q', makes with the horizontal = 45°
The scale factor of the scale diagram, S.F. = 5.0 N/cm
By the resolution of forces at equilibrium, we have;
The sum of the vertical forces, \(\Sigma F_y\) = \(T_P_y\) + \(T_Q_y\) + W = 0
∴ W = -(\(T_P_y\) + \(T_Q_y\))
W = -(30 × sin(45°) + 30 × sin(45°)) = -42.4264068712
The weight of the heavy ball, W ≈ 42.4 N acting downwards
The sum of the horizontal forces, \(\Sigma F_x\) = \(T_P_x\) + \(T_Q_x\) = 0
The length of the resultant force, W = W/(S.F.) ≈ 42.4 N/(5.0 N/cm) = 8.48 cm
The drawing of the vectors using the scale factor of 5.0 N/cm is created using Microsoft Word is included
How are rainbows formed? Please explain.
Answers
Answer:
when sun shines through rain
Explanation:
Rainbow is an arc of different colours that appears in the sky when sun shines through rain
Answer:
this is when rays of light passes through after if finish raining
Study the scenario. The particles in some system are moving around quickly. A few minutes later, the particles are moving, on average, more slowly. How does this change in motion affect the temperature of the system? A. The temperature of the system did not change. The speed of the particles has no effect on the temperature, only the type of atom affects the temperature. B. The temperature of the system is higher now than it was initially. Slower moving particles result in a higher temperature for the system. C. The temperature of the system did not change. The speed of the particles does not affect temperature, the number of particles affects the temperature. D. The temperature of the system is lower now than it was initially. Faster moving particles result in a higher temperature for the system.
Answers
Answer:
The correct answer is option D.
Explanation:
With an increase in temperature, the particles increase kinetic energy and move quicker. The normal speed of the particles relies upon their mass just as the temperature – heavier particles move more gradually than lighter ones at a similar temperature.
The temperature increase in this system since the average kinetic energy of the particles increases and particles move quickly. And after some time the temperature of the system is lower now than it was initially.
Thus, the correct answer is option D.
The impact of the change in motion should be option D.
Impact on the temperature:In the case when there is an increase in temperature, the particles should increase kinetic energy and move faster. The normal speed of the particles believes their mass is like the temperature. The temperature rises in this system because the average kinetic energy of the particles should rised and particles move faster.
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The fact that the strength of gravity decreases with distance means the force of gravity exerted by one object on another (e.g., the earth and moon) is greater on the near side than the far side. this effect is commonly referred to as a
Answers
This effect is commonly referred to as tidal forces. Tidal forces arise due to the differences in gravitational attraction across the length of an extended object.
In the case of the Earth-Moon system, the gravitational pull of the Moon on the near side of the Earth is greater than the pull on the far side.
This results in the deformation of the Earth's oceans, creating the familiar tidal bulges.
Tidal forces can also lead to tidal locking, where an object's rotation and orbital period become synchronized, as is the case with the Moon, which always shows the same face to the Earth.
Tidal forces are also important in the study of binary star systems, where they can cause significant changes in the orbits of the stars.
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why floating is important in swimming?
Answers
Answer:
floating is important in swimming because if you are ever in a bad position possibly in the ocean and get tired of swimming you can float.
Explanation:
write an expression for the magnitude of the average net force, fb, that the boxer must apply to his fist to achieve the given velocity. (write the expression in terms of m, v and t.)
Answers
F b = (m * v) / t is the formula for the amount of average net force needed to reach a specific velocity.
What is the average velocity's magnitude formula?Average speed is determined by dividing the total distance you travelled by the total time, whereas average velocity is determined by dividing your displacement (a vector pointing from your initial position to your end position) by the whole time.
The following formula can be used to determine the average net force, F b, necessary to reach a specific velocity, v:
F_b = (m * v) / t
Its net force, which is inversely related to its mass, is:
a = F_net / m
The final velocity can be related to the acceleration and time using the following kinematic equation because the fist's velocity is attained from rest:
v = a * t
When we enter the acceleration expression from Newton's second law into this equation, we obtain:
v = (F_net / m) * t
To solve for the net force by rearranging this equation, we obtain:
F_net = (m * v) / t
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Which of the following regions of the EM epxtrum has the highest
frequency?
1) x rays
2) microwaves
3) infrared light
4) ultraviolet light
Answers
Answer:
1) x rays
Explanation:
Honestly Gamma rays has the Highest frequency, but in your options, gamma rays is not among, so x rays has the highest frequency among your options.
by Manshow
Answer:
The answer is (X-rays)
number 1
Find the time required to move from the equilibrium position directly to a point a distance 12.3 cm away.A cheerleader waves her pom-pom in SHM with an amplitude of 18.0 cm and a frequency of 0.855 Hz
Answers
The time required to move from the equilibrium position directly to a point a will be 0.879 sec.
What is the period of oscillation?The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.
The standard equation for the SHM is found as;
\(\rm x = asin \omega t \\\\ \rm 12.3 \times 10^{-2} = 18.0 \times 10^{-2}sin \omega t \\\\ 0.6833=sin \omega t \\\\ \omega t =sin^{-1}0.6833 \\\\ \omega t =0.7522 \\\\ t = \frac{0.7522}{0.855 } \\\\ t=0.879\ sec\)
Hence the time required to move from the equilibrium position directly to a point a will be 0.879 sec.
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A circuit is built based on the circuit diagram shown. What is the current in the 50 Ω resistor
Answers
Answer:
1.2 A
Explanation:
From the diagram attached, The three resistors are parallel because the each ends of the resistors are connected together. Since they are in parallel, the voltage across each resistor is the same. The voltage source connected in parallel to the resistors is 60 V. Therefore the voltage across the 50 Ω resistor is 60 V. Using ohm law:
Voltage (V) = Current (I) × Resistance (R)
V = IR
I = V/R
I = 60 V/ 50 Ω
I = 1.2 A
The current in the 50 Ω resistor is 1.2 A
