Find the x-intercept and y-intercept of the line. 6x-3y=12

Answer:

3 hours

Step-by-step explanation:

Max cleans the house in 12 hours

Max in 1 hour cleans: 1/12 part of the house

Maggie cleans the house in 4 hours

Maggie in 1 hour cleans: 1/4 part of the house

In 1 hour they together do: 1/12 + 1/4 = 1+3/12 = 4/12 = 1/3 work

1 hour===1/3 work

X hours== 1 work

X/3 = 1

X = 3 hours.

Hence, they together complete the work in 3 hours.

And so, the sister is correct.

Hope it helps.

Answer:

3  2/3

Step-by-step explanation:

change 5 2/4 into an improper fraction:  5(4)+2 over 4  =  22/4

\(\frac{2}{3}\) x \(\frac{22}{4}\) = \(\frac{44}{12}\)

\(\frac{44}{12}\) can be simplified by dividing top and bottom by 4 to get 11/3 or 3 2/3

Answer: 1.6

2.12

3.13

4.2

Step-by-step explanation:

Step-by-step explanation:

1. x/3-2=6

x-6=18

x=18+6

x=24

2. x/5+1=5

x+5=25

x=25-5

x=20

Answer:

x = 24 , x = 20

Step-by-step explanation:

(a)

\(\frac{x}{3}\) - 2 = 6 ( add 2 to both sides )

\(\frac{x}{3}\) = 8 ( multiply both sides by 3 to clear the fraction )

x = 24

(b)

\(\frac{x}{5}\) + 1 = 5 ( subtract 1 from both sides )

\(\frac{x}{5}\) = 4 ( multiply both sides by 5 to clear the fraction )

x = 20

The point estimate for the unknown population proportion is approximately 0.5761.

To find the point estimate for the unknown population proportion, we can use the formula:

Point Estimate = x / n

Given that x = 106 and n = 184, we can substitute these values into the formula:

Point Estimate = 106 / 184 ≈ 0.5761

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The first month in which the board will see the cumulative total number of candy bars sold in Manila exceeded the cumulative total in Seoul is of:

3rd month.

The slope-intercept definition of a linear function is presented as follows:

y = mx + b.

In which the coefficients are defined as follows:

For the functions in this problem, the slope and the intercept are given as follows:

Taking the end of the first month as a parameter, the functions are defined as follows:

Then Manila exceeds Seoul when:

M(m) > S(m)

20 + 80m - 80 > 40 + 60m - 60

20m > 40

m > 2.

2.1 for example is in the 3rd month, hence the 3rd month is the correct answer.

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The function f(x) = x^4 + bx^2 + 1 has an inflection point at x = 0,

What is the inflection point?

An inflection point of a function is a point on the graph of the function where the concavity (curvature) of the graph changes. In other words, an inflection point is a point where the curve switches from being concave up to concave down, or vice versa.

The function f(x) = x^4 + bx^2 + 1 has an inflection point at x = 0, because the concavity of the graph changes at that point. To find the value of b such that the function has at least one inflection point over the interval (1,2), we can set x = 1 and x = 2 in the function and solve for b.

If we set x = 1, we get the equation f(1) = 1 + b + 1 = 0. Solving for b, we find that b = -2.

If we set x = 2, we get the equation f(2) = 16 + 2b + 1 = 0. Solving for b, we find that b = -9.

Since the function has an inflection point at x = 0 for any value of b, it will have at least one inflection point over the interval (1,2) for any value of b.

Therefore, the value of b can be any real number.

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To determine whether there is enough evidence to reject the null hypothesis, we need to compare the computed test statistic to the critical value.

In this case, the computed test statistic is 2.50 and the critical value is 2.33. If the computed test statistic falls in the rejection region beyond the critical value, we can reject the null hypothesis. Conversely, if the computed test statistic falls within the non-rejection region, we fail to reject the null hypothesis.In this scenario, since the computed test statistic (2.50) is greater than the critical value (2.33), it falls in the rejection region. This means that the observed data is unlikely to occur if the null hypothesis were true.

Therefore, based on the given information, there is enough evidence for the emergency room nurse to reject the null hypothesis. This suggests that there is sufficient evidence to support the claim that the average number of cases of upper respiratory infections per day at the hospital is over 21 cases.

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There is enough evidence to reject the null hypothesis in this case because the computed test statistic (2.50) is higher than the critical value (2.33). This suggests the average number of daily respiratory infections exceeds 21, providing substantial evidence against the null hypothesis.

Yes, there is enough evidence for the emergency room nurse to reject the null hypothesis. The null hypothesis is typically a claim of no difference or no effect. In this case, the null hypothesis would be an average of 21 upper respiratory infections per day. The test statistic computed (2.50) exceeds the critical value (2.33). This suggests that the average daily cases indeed exceed 21, hence providing enough evidence to reject the null hypothesis.

It's crucial to understand that when the test statistic is larger than the critical value, we reject the null hypothesis because the observed sample is inconsistent with the null hypothesis. The statistical test indicated a significant difference, upheld by the test statistic value of 2.50. The significance level (alpha) of 0.05 is a commonly used threshold for significance in scientific studies. In this context, the finding suggests that the increase in respiratory infection cases is statistically significant, and the null hypothesis can be rejected.

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Answer:

Distributive Property, Subtraction Property of Equality, Subtraction Property of Equality, Division Property of Equality

Step-by-step explanation:

First, you need to distribute. Next, you subtract on both sides. Then, you subtract again. Finally, you divide.

The equation of the line that passes through the point (2, 5) and (6, 7) is

y = (1/2)x + 4.

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

We have,

The equation of a line passes through points (2, 5) and (6, 7).

The equation of a line can be written as:

y = mx + c ______(1)

Points (2, 5) and (6, 7) must satisfy line (1).

5 = 2m + c _____(A)

7 = 6m + c ______(B)

From (A),

c = 5 - 2m

Putting in (B).

7 = 6m + 5 - 2m

7 = 4m + 5

2 = 4m

m = 1/2

Putting in (A) we get,

5 = 2 x 1/2 + c

5 = 1 + c

c = 4

Now,

The equation of the line is:

y = (1/2)x + 4.

Thus,

The equation of the line that passes through the point (2, 5) and (6, 7) is

y = (1/2)x + 4.

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Answer:

C (7,6,5,3)

Step-by-step explanation:

Domain of a function are the x values and Range are the y values.

since f(x) = y, simply plug in the values provided in the question to the function for x.

Example:

f(x) = -x + 4

f(-3) = -(-3) + 4

Plug in the values and simplify.

Complete Question

90% of flights depart on time. 80% of flights arrive on time. 75% of flights depart on time and arrive on time.

• You are meeting a flight that departed on time. What is the probability that it will arrive on time?

• You have met a flight, and it arrived on time. What is the probability that it departed on time?

• Are the events, departing on time and arriving on time, independent?

Answer:

1st Question

       \(P(X_1) = 0.833\)

2nd  Question

      \(P(X_2) = 0.938\)

3rd Question

      The probabilities are not independent

Step-by-step explanation:

From the question we are told that

    The  probability of flight that depart on time is  P(DT) = 0.9

      The probability of flights that arrive  on time  is  \(P(AT) = 0.8\)

     The  probability of flight that depart on time and arrive on time is  \(P(DT\ |\ AT) = 0.75\)

    In the first question the flight is departed on time  so the probability that it will arrive on time is  

         \(P(X_1) = \frac{P(DT\ | \ AT)}{DT}\)

substituting values

         \(P(X_1) = \frac{0.75}{0.9}\)

        \(P(X_1) = 0.833\)

In the second question the flight arrived on time, so the probability that it departed on time is  mathematically evaluated as follows

           \(P(X_2) = \frac{P(DT\ | \ AT)}{AT}\)

substituting values

           \(P(X_2) = \frac{0.75}{0.8}\)

           \(P(X_2) = 0.938\)

Looking at the given and calculated values we see that the probability of  depart on time and arrive is not equal to the probability of  depart on time,

    i.e 0.75 =  0.8

the probability of  depart on time and arrive, and  the probability of depart on time are not independent

Answer:

x= -7

Step-by-step explanation:

-3x -5 = 16

     +5   +5

-3x = 21

divide by negative three on both sides to get your answer

Answer:

i d k but now i want candles from bath and body works

Step-by-step explanation:

Answer:

(3x + 7) (x + 5)

Step-by-step explanation:

Hope this helped :)

Answer:

(3x+7)(x+5)

Step-by-step explanation:

Answer:

The percent error of the bolt is 5.7%, which is less than the maximum allowed percent error of 6%. Therefore, this bolt should be included in the package.

Step-by-step explanation:

The percent error can be calculated using the formula:

percent error = |(experimental value - accepted value) / accepted value| x 100%

In this case, the accepted value is the diameter of the bolt stated on the label, which is 0.35 inch, and the experimental value is the diameter of the bolt tested on the production line, which is 0.37 inch.

Substituting the values into the formula, we get:

percent error = |(0.37 - 0.35) / 0.35| x 100%

percent error = |0.02 / 0.35| x 100%

percent error = 0.057 x 100%

percent error = 5.7%

The percent error of the bolt is 5.7%, which is less than the maximum allowed percent error of 6%. Therefore, this bolt should be included in the package.

It is important to round off the final answer to the nearest hundredth as specified in the question.

Answer:

16/22, 24/33, and 40/55

or

72.7272...% = Percentage form

0.7272... = Decimal form

Hope this helps :)

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The determinant of a matrix A is the product of the diagonal entries.

The determinant of a lower triangular matrix (or an top triangular matrix) is the product of the diagonal entries. in particular, the determinant of a diagonal matrix is the made from the diagonal entries.

The determinant of any diagonal n × n matrix is the product of its diagonal entries. yes, the determinant of a diagonal matrix is the made of elements of its diagonal. So, the given condition is real.

A diagonal matrix is sometimes called a scaling matrix, considering matrix multiplication with it consequences in converting scale (length). Its determinant is the fabricated from its diagonal values.

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To convert the octal number \(4137.231_8\) to a hexadecimal number, the final answer is 16.

To convert an octal number to a hexadecimal number, we first need to convert the octal number to its decimal equivalent and then convert the decimal number to hexadecimal.
The given octal number is \(4137.231_8\). To convert it to decimal, we use the positional notation and multiply each digit by the corresponding power of 8:
\(4137.231_8 = 4 \times 8^3 + 1 \times 8^2 + 3 \times 8^1 + 7 \times 8^0 + 2 \times 8^{-1} + 3 \times 8^{-2} + 1 \times 8^{-3}\)
Simplifying this expression, we get the decimal equivalent as:
\(4137.231_8 = 2223.29375_{10}\)Now, to convert the decimal number to hexadecimal, we divide the integer part and the fractional part separately by 16 repeatedly and obtain the remainder at each step. The remainders are then converted to hexadecimal digits.
Converting \(2223_{10}\) to hexadecimal, we get \(8BF_{16}\).
Converting \(0.29375_{10}\) to hexadecimal, we get \(4B_{16}\).
Combining the two parts, we have:
\(4137.231_8 = 8BF.4B_{16}\)
Therefore, the hexadecimal equivalent of \(4137.231_8\) is 16.

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Answer: 8.8 moles

Step-by-step explanation:

Fun Fun! Chemistry :)

So, 5.3 x \(10^{24}\) atoms can be converted to moles by dividing by Avogadros number, (6.02 x 10^23). This is because Avogadros number of atoms form one mole.

So the answer is about 8.8 moles of Kr

Angles of ∠y is 45° and ∠x is 135°.

An angle is a figure in Euclidean geometry made up of two rays that share a common terminal and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are in the plane where the rays are located. The meeting of two planes also creates angles. We refer to these as dihedral angles.

Given Data

SRQ = 130°

∠R = 130°

As PR is the same line

So. angles of the line is 180°.

∠Y + ∠R = 180

∠y = 180 - 135

∠y = 45°

Now, PQ is the straight line

∠y +∠x = 180

∠x = 180-45

∠x = 135°

Angles of ∠y is 45° and ∠x is 135°.

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The velocity vector of the parametric curve r(t) = (e^4, 2^2, t) at t=0 is (0, 0, 1).

To find the velocity vector, we need to take the derivative of the position vector with respect to time.

So, the velocity vector v(t) is given by

v(t) = r'(t) = (d/dt e^4, d/dt 2^2, d/dt t)

The derivative of e^4 with respect to t is 0 because e^4 is a constant. The derivative of 2^2 with respect to t is also 0 because 2^2 is also a constant. The derivative of t with respect to t is 1.

Therefore, the velocity vector at t=0 is

v(0) = (0, 0, 1)

So, the velocity vector is (0, 0, 1) when t=0.

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The given question is incomplete, the complete question is:

Let r(t) = (e^4, 2^2, t) be a parametric curve in R. Find the velocity vector when t = 0

point B is located in quadrant II (option B)

Point A: (6, 3) = (x, y)

reflection of point A across the y axis:

The x coordinate will be negative and the y coordinate will remain the same

reflection of point A across the y axis = (-6, 3)

Attaching the graph showing the point after reflection:

Since point B is the reflection of point A.

Hence, point B is located in quadrant II (option B)

Answer:

x = 7

Step-by-step explanation:

Ok, so these angle are equal, because they are opposite angle

So we could write as x+16 = 4x - 5

Now we solve the equation:

x+16 = 4x - 5

16+5 = 4x -x

21 = 3x

7 = x

The expression for the sum is 2n + 1 and the sum must be an odd number because it will leave 1 as remainder when divided by 2.

The Euclid division lemma states that when two positive integers a and b are divided then their are other two integers q and r that represent quotient and remainder. The equation for the lemma can be written as a = bq + r where r < b.

(a) The given consecutive integers are n and n + 1 respectively.

The expression for their sum can be written as,

n + n + 1

⇒ 2n + 1

(b) The general expression for the sum is 2n + 1.

Now, as per the Euclid's division lemma, the number when divide by 2 will leave remainder as 1.

Which implies the number will be an odd number.

Hence, the expression for the sum is 2n + 1 and it will be an odd number.

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So, there are 20 possible outfits.

An outfit like t-shirts is a group of garments that have been specifically chosen or created to be worn together. A firm, organisation, or group that collaborates closely is referred to as an outfit. It may be used as a verb to signify to supply with the right tools.

The term outfit can be used to refer to coordinated clothing, such as a shirt and trousers that you usually wear to job interviews. From out- + fit (v.), "act of fitting out (a ship, etc.) for an expedition," 1769. The broader sense of "articles and equipment required for an expedition" is documented in American English from 1787.

To calculate the number of outfits possible, we need to multiply the number of options for each item.

Number of options for jeans = 2 pairs = 2

Number of options for t-shirts = 5

Number of options for shoes = 2 pairs = 2

Therefore, the total number of possible outfits is:

2 x 5 x 2 = 20

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The fraction of crayons that are blue triangle is 1/5.

The ratio of blue rounds to non-blue crayons is

The fraction of footballs that are brown rubber footballs is 8/15 and here are 4 times as many rubber footballs as non-rubber footballs

A fraction represents a part of a whole.

1. Let's say Alexa had a total of 5x crayons in the bag.

the number of blue crayons in the bag is 2x,

There is one triangle for every two round crayons,

(1/2) × 2x = x (By condition)

So, the fraction of crayons that are blue triangle is x / 5x = 1/5.

The number of blue round crayons is 2x.

The number of non-blue crayons is 5x - 2x = 3x,

The ratio of blue rounds to non-blue crayons is 2x / 3x = 2/3.

2.

4 out of 5 wall footballs are rubber, 4/5 of the footballs in the bag are rubber.

The fraction of rubber footballs that are brown is 2/3.

The fraction of footballs that are brown rubber footballs is (4/5) × (2/3) = 8/15.

The fraction of non-brown rubber footballs is (4/5) - (8/15) = 4/15.

The ratio of rubber footballs to non-rubber footballs is (4/5) / (1/5) = 4.

So there are 4 times as many rubber footballs as non-rubber footballs

Hence,  the fraction of crayons that are blue triangle is 1/5.

The ratio of blue rounds to non-blue crayons is

The fraction of footballs that are brown rubber footballs is 8/15 and here are 4 times as many rubber footballs as non-rubber footballs

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