find the weight of a 2000 kg elaphant

Answer: what ( younger brothers of hers )

Explanation:

K bye

Answer:

1)By using a measuring ruler

2)By measuring from 0cm

Explanation:

Hey there!

The energy that is stored in food is called CHEMICAL ENERGY

So, when humans/people eat foods their bodies transfigure the energy that is stored which is known as the calories.

Whereas the chains (bonds) in the middle of the atoms in the food humans eat that break up the check mal reactions that has been taken into place and newer compounds will be created. Each food that you eat stores unlikeable amounts of energy

Answer: Chemical energy

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The magnitude of the force on the barge from the water is approximately 18497 N.

Mass is a measure of the amount of matter in an object. It is a scalar quantity that is usually measured in units of kilograms (kg) or grams (g). Mass is different from weight, which is the force that gravity exerts on an object with mass.

Here, F(horse) is the force applied by the horse, F(water) is the force on the barge from the water, and the x and y axes are chosen such that the motion is along the x-axis and the force from the water is along the y-axis.

\($\rm \Sigma F_x = F_{horse,x} = F_{water}$\)

And substituting the x and y components of the forces, we get:

\($ \rm F_{horse}\cos(8^{\circ}) = m a\sin(15^{\circ})$\)

Solving for \($ \rm F_{water}$\), we get:

\($ \rm F_{water} = \dfrac{F_{horse}\cos(8^{\circ})}{\sin(15^{\circ})}$\)

Substituting the given values, we get:

\($\rm F_{water} = \dfrac{7920 N \cdot \cos(8\°)}{\sin(15\°)} \approx 18497 N$\)

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The resistance band's elasticity (stretchiness) dictates how easily it can be stretched or can be flexible.

It is the proportion of tensile stress to strain, where strain is the amount of deformation and tensile stress is the tension force applied to a surface area (amount of stretch of the resistance band).

Instead than requiring you to hold additional weight per se, resistance bands function by providing an external resistance force that can be imposed. They are flat, occasionally looping bands that might be thin or thick.

Both rubber bands and springs have a unique quality. The stretch distance affects how hard a band pulls back. The spring constant, denoted by the symbol k (in units of N/m), is a proportionality constant.

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The converging lens is also called a concave lens. The height of the image formed by the lens is 2.55 cm.

Using the lens formula;

1/f = 1/u + 1/v

f = focal length of the lens

u = object distance

v = image distance

Note that the focal length of a converging lens is positive

Substituting values;

1/12 = 1/28 + 1/v

1/v = 1/12 -  1/28

v = 8.4 cm

Magnification= image height/object height = image distance/object distance

image height = ?

object height = 8.5 cm

image distance = 8.4 cm

object distance =  28 cm

So

image height/8.5 = 8.4/28

image height = 8.5 × 8.4/28

image height = 2.55 cm

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Answer:A) Current = 1.739A, B)current density, J = 2.147x10^6 A/m2

magnitude of electric field , E =  0.036 N/C

)rate of thermal energy, P  =2.086W

Explanation:

Resistance  = R =   ρL/A

But the cross-section area of the wire. is given as

Diameter / 2 = 0.04/2 =0.02in to m = 0.02 / 39.37= 0.000508

A = πr^2 = π x  0.000508^2 = 8.10 x 10^-7

since resistivity of copper,ρ= 17x10-9 ohm.m

so resistance is   R =   ρL/A

17x10-9  x 33 / 8.1x10-7

= 0.69 ohm.

A) Current =    I = Voltage /Resistance =1.20/0.69 =1.739A

B)current density, J = Current /Area

= 1.739/8.1x10-7

= 2.147x10^6 A/m2

c)magnitude of electric field , E =  Current density x resistivity =J ρ

E = 2.147 x 10^6  x 17  x 10^-9

E = 0.036 N/C

D)rate of thermal energy, P  = I² R =1.739² X 0.69

=2.086W

This question is incomplete, the complete question is;

The entropy of an ?-ideal gas changes in the following way as a function of temperature and volume:

ΔS = nRln(V\(_f\)/V\(_i\)) + ∝nRln(T\(_f\)/T\(_i\))

For an adiabatic process, the change in T is determined by the change in V. In this problem you will compute the contributions to S from the V and T terms separately, then add them up to find the total entropy change for an adiabatic process.

Argon gas, initially at pressure 100 kPa and temperature 300 K, is allowed to expand adiabatically from 0.01 m³ to 0.026 m³ while doing work on a piston.

1) What is the change in entropy due to the volume change alone, ignoring any effects of changing internal energy? ΔS = ? J/K

2) For this adiabatic expansion, what is the final temperature?  T\(_f\) =  ? K

Answer:

1) the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.

2) the final temperature is 158.66 K

Explanation:

Given the data in the question;

ΔS = nRln(V\(_f\)/V\(_i\)) + ∝nRln(T\(_f\)/T\(_i\))

P\(_i\) = 100 kPa = 100000 Pa

V\(_i\) = 0.01 m³

V\(_f\) = 0.026 m³

T\(_i\) = 300 K

1)  the change in entropy due to the volume change alone

from the question; ΔS = nRln(V\(_f\)/V\(_i\)) + ∝nRln(T\(_f\)/T\(_i\))

so change in entropy due to the volume change alone is;

ΔS = nRln(V\(_f\)/V\(_i\))

we know that, from ideal gas law; PV = nRT

so, nR = P\(_i\)V\(_i\)/T\(_i\)  ---- let this be equation 1

∴ ΔS = P\(_i\)V\(_i\)/T\(_i\) × ln(V\(_f\)/V\(_i\))

we substitute

ΔS = [( 100000 Pa ×  0.01 m³) / 300 K ] × ln(0.026m³ / 0.01m³ )

ΔS = 3.185 J/K  

Therefore, the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.

2)  Final temperature

we know that, in an adiabatic expansion;

\(PV^Y\) = K

where Y = 5/3

so

\(P_i\)\(V_i^{(5/3)\) = \(P_f\)\(V_f^{(5/3)\)

\(P_f\) = \(P_i\)\(( \frac{V_i}{V_f})^{(5/3)\)

we substitute

\(P_f\) = ( 100000 Pa) \(( \frac{0.01 m^3}{0.026 m^3})^{(5/3)\)

\(P_f\) = 20341.255 Pa

Also from ideal gas law;

PV = nRT

T = PV / nR

so

T\(_f\) = P\(_f\)V\(_f\) / nR

but from equation 1; nR = PV/T

so

T\(_f\) = (P\(_f\)V\(_f\)) / (P\(_i\)V\(_i\)/T\(_i\) )

T\(_f\) = ( P\(_f\)V\(_f\)T\(_i\) / P\(_i\)V\(_i\) )

we substitute

T\(_f\) = ( 20341.255 Pa × 0.026 m³ ×  300 K) / 100000 Pa × 0.01 m³ )

T\(_f\) = 158.66 K

Therefore, the final temperature is 158.66 K

The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.

To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.

Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.

To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:

Resultant magnitude = √(boat velocity^2 + river velocity^2)

Plugging in the given values, we have:

Resultant magnitude = √(0.75^2 + 1.2^2)

= √(0.5625 + 1.44)

= √2.0025

≈ 1.42 m/s

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An elastic spring extends by 0.1 m due to the action of a force of 15 N. The elasticity constant of that spring will be 150 Newton/ meters.

Elastic constants are the constants which are used to determine the deformation which is produced by a given stress system acting on the material. There are many types of elastic constants such as Bulk modulus (K). The expression for Bulk modulus for elasticity.

F = kx

where, F is the force applied,

k is Elasticity constant,

x is the extension of the spring

k = F/ x

k = 15/ 0.1

k = 150

Therefore, the elasticity constant of the spring will be 150 Newton/ meters.

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Answer:

the gravitational attraction of each ball, so technically the others too lol

The time required for half of the oil droplets to coalesce is 34.65 minutes.b) Calculation to find how long it takes for practically all of the oil droplets to coalesce:To find the time it would take for practically all of the oil droplets to coalesce, we need to use the following formula and solve for time when n is equal to 0.0 = e^(-0.02t)-infinity = -0.02tNo oil droplets remain after an infinite amount of time. Therefore, it takes an infinite amount of time for all the oil droplets to coalesce.Answer: It takes an infinite amount of time for all the oil droplets to coalesce.

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The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

A primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.

Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.

On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.

Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.

In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

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Answer:

B.

Explanation:

Answer:

B

Explanation:

it is correct i just took the test and got 100% <3

The Ceres is (a).The largest asteroid identified to date is correct option.

With a diameter of around 590 miles (940 km), Ceres is the biggest asteroid between Mars and Jupiter. It is regarded as a minor planet, like Pluto, and was found in 1801 by Giuseppe Piazzi. Ceres is made of rock and ice, and due to its low density, it is likely that it contains a substantial amount of water ice inside.

The NASA Dawn spacecraft visited Ceres in 2015 and orbited the dwarf planet for more than three years, gathering useful information and taking stunning pictures of it.

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Answer:

ANSWER

A = 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

plz give brainlist

hope this helped

Answer:

\(here \: amplitude = 5cm (convert \: to \: si \: unit) = .05m \\ t = .2sec \\ omega = \frac{2\pi}{t} \\ = \frac{2\pi}{.2 } = 10\pi \frac{rad}{s} \\ we \: want \: find \: a \: and \: v \\ we \: know \: that \: a = - {omega}^{2} x \\ v = omega \sqrt{ {r}^{2} - {x}^{2} } \\(1)x = .05m \\ a = - {10\pi}^{2} \times .05 = - 5 {\pi}^{2} \frac{m}{ {s}^{2} } \\ v = 10\pi \sqrt{ {.05}^{2} - {.05}^{2} } = 0 \\ 2)x = 3cm = .03m \\ a = {(10\pi)}^{2} \times .03 = - 3 {\pi}^{2} \frac{m}{ {s}^{2} } \\ v = 10\pi \sqrt{ {.05}^{2} - {.03}^{2} } = 10\pi \times .04 = .4\pi \frac{m}{s} \\ 3)x = 0 \\ a = - {(10\pi)}^{2} \times 0 = 0 \\ v = 10\pi \times \sqrt{ {.05}^{2} - {0}^{2} } = - 10\pi \times .05 = .5\pi \frac{m}{s} \\ thank \: you\)

Answer:

f

Explanation:

a. The potential energy and its kinetic energy at the instant it is dropped will be 1126.25 J and 0 J respectively.

b. The potential energy and its kinetic energy at the time it is 15m high will be 735.75 J and 390.25 J respectively.

c. The velocity when it is 15m high will be 156.1 m/sec.

d. The height when velocity is 12 m/s will be 15.62 m

e. The potential energy and its kinetic energy at the time it strikes the ground will be 0 J and 1126.25 J respectively

f. The velocity with which it hits the ground will be 21.22 m/sec.

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

According to the law of conservation of energy, the total energy is defined as the sum of kinetic energy and potential energy.

Total energy = kinetic energy+potential energy

Also, the energy can not be created nor be destroyed can be transferred from one form to another form.

Kinetic energy is due to the position.While the kinetic energy is due to the velocity.

a)The potential energy and its kinetic energy at the instant it is dropped.

\(\rm PE_{drop}=mgh \\\\\ PE_{drop}=5 \times 9.81 \times 25 \\\\ PE_{drop}=1126.25 \ J\)

\(\rm KE_{drop}=\frac{1}{2} mv^2 \\\\ v= 0 \\\\ KE_{drop}=0 \ J\)

TE= 1126.25+0

TE= 1126.25+0

b. Potential energy and its kinetic energy at the time it is 15m high.

\(\rm PE_{15}=mgh \\\\ \rm PE_{15}= 5 \times 9.81 \times 15 \\\\ PE_{15}=735.75 \ J\)

TE=KE+PE

1126.25=KE+735.75

KE=390.25

c) Velocity when it is 15m high

\(\rm KE=390.25\\\\ 390.25=\frac{1}{2} \times 5 \times v_{15}^2 \\\\ v_{15}=156.1\ m/sec\)

d. Height when velocity is 12 m/s.

\(\rm KE = \frac{1}{2}mv^2 \\\\\ KE =\frac{1}{2} \times 5 \times (12)^2 \\\\ KE=360\ J\)

TE=KE+PE

1126.25=360+PE

PE=766.25

PE=766.25

mgh=766.25

5 ×9.81 ×h=766.25

h=15.62 m

E. Potential energy and its Kinetic energy at the time it strikes the ground.

\(\rm PE_{ground}=0 \ J\)

TE=KE+PE

TE=KE+0

TE=KE

TE= 1126.25

KE=1126.25 J

f. Velocity with which it hits the ground.

\(\rm KE_{ground}=1126.25 J \\\\ \frac{1}{2} mv^2=1126.25\\\\ v^2 = 450 \\\\ v= 21.22 \ m/sec\)

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ANSWER and EXPLANATION

The relationship between the motion of the magnet and the current produced can be described by using Faraday's law. It states that:

This law implies that when a coil is in the presence of a changing magnetic field (which may be due to a moving magnet), an electric current is produced in the coil. It is the same when the coil is moved relative to the magnetic field due to the magnet.

The faster the magnetic moves, the greater the magnitude of the current produced, which also means that if there is no motion of the magnet, the current is 0.

That is the relationship between the motion of the magnet and the current produced.

Answer:

f. 500N

Explanation:

The force exerted by the wagon on the horse is 500N directed in the opposite path .

This is premised on the Newton's third law of motion which states that "action and reaction forces are equal and opposite in direction".

So, as the action force of 500N is used by the horse to drag the wagon, the wagon also exerts an oppositely directed force of 500N on the horse.

This way, the acceleration can continue.

Answer:

if your going 15000 mph all you can do is accelerate  or go fast  unless there is a opposite

Explanation:

Given data:

* The electric field in the y-direction is,

* The distance traveled by the electron is,

Solution:

The work done in terms of electric field is,

where q is the charge on an electron,

Substituting the known values,

This work done is stored in the charge in form of energy.

Thus, the energy of the electron in eV is 20 eV.

Hi there!

To solve, we can begin by doing a summation of torques. We can place the fulcrum at the point at which the strut and wall make contact to make solving easier.

Recall that:
\(\tau = r \times F\) (Cross Product)

τ = Torque (Nm)

r = distance from lever arm (m)

F = Force (N)

This can also be written as:
\(\tau = rFsin\theta\)

For a system to be in rotational equilibrium:
\(\tau _{cw} = \tau_{ccw}\)

In this instance, we only have the torques of the force of gravity and the vertical component of the cable's tension that are in opposite directions. Additionally, these torques are PERPENDICULAR to the strut, so sin(θ) = 1.

Let 'r' represent the length of the bar.

\(rTsin\theta = rF_g\\\\Tsin\theta = F_g\\\\T = \frac{F_g}{sin\theta} = \frac{9.8 \times 160.9}{sin(25.3)} = \boxed{3689.695 N}\)

To find the compression force exerted by the wall on the strut, we can do a summation of forces in the horizontal direction.

Let F(W) represent the force on the strut by the wall, and Tx represent the horizontal component of the tension. These two sum up to zero since the system is in equilibrium.

\(\Sigma F_x = T_x - F_W\)

\(0 = T_x - F_W\\\\F_W = T_x\\\\F_W = Tcos\theta = 3689.695cos(25.3) = \boxed{3335.789 N}\)

**This is assuming the strut has no mass.

The value of the acceleration is a = 0.5 m/s². The position at 80 s is x = 3200 m and finally the average velocity is v = 40 m/s.

Acceleration:

We can use the fallowing kinematic equation to get the acceleration at 80 s.

\(a=\frac{v_{f}-v_{i}}{t}\)            

Where:

The, we have:

\(\vec{a}=\frac{60-20}{80}\)

\(\vec{a}=0.5\: m/s^{2}\)

Position:

Knowing the acceleration we can find the position using the falling equation.

\(\vec{x}=v_{i}t+0.5at^{2}\)

\(\vec{x}=20*80+0.5*0.5*80^{2}\)

\(\vec{x}=3200 m\)

Average velocity:

The definition of the average velocity is:

\(\vec{v}=\frac{\Delta x}{t}\)

\(\vec{v}=\frac{x_{f}-x_{i}}{t}\)

\(\vec{v}=\frac{3200-0}{80}\)

\(\vec{v}=40\: m/s\)

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Answer:

The value is     \( P_G  =  2.925 *10^{5} \  Pa\)

Explanation:

From the question we are told that

   The  volume of the bottle is  \(v  =  2 \  L  =  2 *  10^{-3} \  m^3\)

   The gauge pressure of the air is \(P_g  =  340 \  kPa  =  340 *10 ^{3}  \  Pa\)

Generally the volume of air before the bottle is turned upside down is  

      \(V_a  =  \frac{3}{4}  * V\)

       \(V_a  =  \frac{3}{4}  *  2 *10^{-3}\)

       \(V_a  =  0.0015 \  m^3 }\)

Generally the volume air when the bottle is turned upside-down is

      \(V_u  =  \frac{5}{6}  *  2 *10^{-3}\)

       \(V_u  =  0.00167 \  m^3 \)

From the the mathematical relation of adiabatic process we have that

     \(P_g *  V_a^r  =  P_G *  V_u^r\)

Here r is a constant with  a value  r =  1.4

So

      \( 340 *10 ^{3}  *  0.0015^{1.4}  =  P_G *  0.00167^{1.4}\)

        \( P_G  =  2.925 *10^{5} \  Pa\)

Answer:

D) See the explanation below.

Explanation:

Heat transfer is always given from a body of higher temperature to a lower temperature. In this way the heat from the boiling water is transferred to the ice bars and the energy of the phase change from solid to liquid from the ice is transferred to the environment

Answer:

Probably all but (a)

The Tyndall Effect is caused by dispersion of the incident light by the individual molecules in the liquid.

Salt water and a foggy night will cause dispersion of the incident light.

A soda drink may also cause this dispersion, but and not sure.