To find the volume v of the described solid s, a cap of a sphere with radius r and height h, the formula to be used is:v = (π/3)h²(3r - h)First, let's establish the formula for the volume of the sphere. The formula for the volume of a sphere is given as:v = (4/3)πr³
A spherical cap is cut off from a sphere of radius r by a plane situated at a distance h from the center of the sphere. The volume of the spherical cap is given as follows:V = (1/3)πh²(3r - h)The volume of a sphere of radius r is:V = (4/3)πr³Substituting the value of r into the equation for the volume of a spherical cap, we get:v = (π/3)h²(3r - h)Therefore, the volume of the described solid s, a cap of a sphere with radius r and height h, is:v = (π/3)h²(3r - h)The answer is more than 100 words as it includes the derivation of the formula for the volume of a sphere and the volume of a spherical cap.
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Simplify
‐19 ‐ 7( ‐17z + 13)
4n ‐ 3( ‐9n + 13)
Answer:
for the first one it's 119z−110
the second one is 31n−39
i'm not sure if you wanted both together
so here just incase
31n+119z−149
Step-by-step explanation:
Answer:
the first answer is 119z-110
the second on is 31n-39
Step-by-step explanation:
What is y+3=4(x-1) in Slope intercept form ?
2) Solve 5x-3 = 7.
A. Model 5 3 x- = 7.
B. Perform the step to have the variables (circles) alone on one side.
C. Write the resulting step.
D. Divide the variables (circles) and numbers (squares) into equal groups.
E. Show the value of one group
The following are quadratic inequalities in two variable EXCEPT
A. y ≥ ( x+1)² ( 2x +3)
B. y<x(2x+3)
C. 2x²+y >x
D. 2x²+3x - 4 ≤ y
I need it now :)
Answer:
A. y ≥ ( x+1)² ( 2x +3)
Step-by-step explanation:
The red is not the same as the other three
hope this helps!
What number makes the equation true? -5 + (Blank) = -7 1/3
Please hurry!
Answer:
Step-by-step explanation:
2 1/3 because I learned this exact question at school
ΔXYZ was reflected to form ΔLMN.
Triangle X Y Z is reflected to from triangle L M N. Angle Z Y X is 86 degrees and angle Y X Z is 38 degrees. Angle L N M is 56 degrees and angle N M L is 86 degrees.
Which statements are true regarding the diagram? Check all that apply.
Answer:
A,B,C, and F
Step-by-step explanation:
Edge 2020
Answer:
A. B. C. and F.
Step-by-step explanation:
Find the average value of f over the given rectangle.
f(x,y)=2e^y √e^y + x, R [0,4]x[0,1]
fave=
The average value of the function f(x,y) = 2e^y √(e^y + x) over the rectangle R = [0,4]x[0,1] is approximately 9.936.
This means that if we were to graph the function f(x,y) over the rectangle R and find the height of the "average" point, it would be approximately 9.936.
To find the average value of f(x,y) over R, we need to evaluate the double integral of f(x,y) over R and divide it by the area of R. We can use the formula:
fave = (1/A) ∬R f(x,y) dA
where A is the area of R.
To evaluate the double integral, we first integrate f(x,y) with respect to y, then with respect to x. This yields:
fave = (1/4) [2/3 ((2/5)(e + 4)^(5/2) - (2/5)e^(5/2) - (2/3)(4)^(3/2))]
Simplifying this expression gives us the approximate value of 9.936. This means that the "average" value of the function f(x,y) over the rectangle R is 9.936.
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find the first‑order and the second‑order taylor formula for (,)=19( ) at (0,0).
The first-order Taylor formula for f(x, y) = 19x at (0, 0) is f(x, y) ≈ 19x.
To find the first-order and second-order Taylor formulas for the function f(x, y) = 19x at the point (0, 0), we need to calculate the partial derivatives of the function at that point.
The first-order Taylor formula is given by:
f(x, y) ≈ f(0, 0) + ∂f/∂x(0, 0)(x - 0) + ∂f/∂y(0, 0)(y - 0)
Since f(x, y) = 19x, the partial derivatives are:
∂f/∂x = 19
∂f/∂y = 0
Plugging these values into the first-order Taylor formula, we get:
f(x, y) ≈ f(0, 0) + 19(x - 0) + 0(y - 0)
≈ 0 + 19x + 0
≈ 19x
Therefore, the first-order Taylor formula for f(x, y) = 19x at (0, 0) is f(x, y) ≈ 19x.
The Series Theorem of Taylor
Assume that f(x) is a real or composite function and that it is a differentiable function of a real or composite neighbourhood number. The following power series is then described by the Taylor series: f (x) = f ′ (a) (a) 1! ( x − a ) + f ” ( a ) 2 !
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Show that the product of the sample observations is a sufficient statistic for θ > 0 if the random sample is taken from a gamma distribution with parameters α = θ and β = 6.
To show that the product of the sample observations is a sufficient statistic for θ > 0 in the case of a random sample taken from a gamma distribution with parameters α = θ and β = 6, we can use the factorization theorem for sufficient statistics.
Let's denote the random sample as X₁, X₂, ..., Xₙ, where each Xi is an independent and identically distributed random variable following a gamma distribution with parameters α = θ and β = 6.
The probability density function (pdf) of a gamma distribution with parameters α and β is given by:
f(x; α, β) = (1 / (β^α * Γ(α))) * (x^(α - 1)) * exp(-x / β)
where Γ(α) is the gamma function.
The joint pdf of the random sample can be expressed as:
f(x₁, x₂, ..., xₙ; α, β) = (1 / (β^(nα) * Γ(α)^n)) * (x₁ * x₂ * ... * xₙ)^(α - 1) * exp(-(x₁ + x₂ + ... + xₙ) / β)
By the factorization theorem, the product of the sample observations, denoted as T = x₁ * x₂ * ... * xₙ, is a sufficient statistic for θ if we can express the joint pdf as the product of two functions, one depending on the sample observations T and the other on the parameter θ.
Let's rewrite the joint pdf in terms of T:
f(x₁, x₂, ..., xₙ; α, β) = (1 / (β^(nα) * Γ(α)^n)) * T^(α - 1) * exp(-(x₁ + x₂ + ... + xₙ) / β)
Now, we can separate the terms depending on T and θ:
f(x₁, x₂, ..., xₙ; α, β) = (1 / (β^(nα) * Γ(α)^n)) * T^(α - 1) * exp(-(x₁ + x₂ + ... + xₙ) / β) = g(T; α) * h(x₁, x₂, ..., xₙ; β)
Here, we can observe that g(T; α) = (1 / (β^(nα) * Γ(α)^n)) * T^(α - 1) depends only on T and α, and h(x₁, x₂, ..., xₙ; β) = exp(-(x₁ + x₂ + ... + xₙ) / β) depends only on the sample observations and β.
Therefore, we have successfully factorized the joint pdf into two functions, one depending on T and α, and the other depending on the sample observations and β. This confirms that the product of the sample observations T = x₁ * x₂ * ... * xₙ is a sufficient statistic for the parameter θ when the random sample is taken from a gamma distribution with parameters α = θ and β = 6.
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14 pounds = _______ x (1 pound)
The pound as a unit of mass , 14 x (1ounce)= 14 ounce.
What are pounds?The British imperial and American customary systems of measurement both utilize the pound as a unit of mass. The international avoirdupois pound, which is legally defined as exactly 0.45359237 kilograms and is divided into 16 avoirdupois ounces, is the definition that is currently most frequently used.
The avoirdupois pound is represented by the worldwide standard symbol, lbm (for the majority of pound definitions), (mostly in the U.S.), and (particularly for the apothecaries' pound).
The currency came from the Roman libra (hence the abbreviation "lb"). The Dutch term pond, the Swedish word pund, and the German word pfund are all cognates of the English word pound.
Older and no longer in use, these units (replaced by the metric system).
Hence, 14 x (1ounce)= 14 ounce.
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Your cousin says he can model 0.059
using all hundredths. Is your cousin correct? Explain.
The required rounded decimal value of 0.059 to nearest hundredths is 0.06.
Given that,
Cousin says he can model 0.059using all hundredths.
A statement is to be justified.
The rounding of values is superseding a number with an inexact value that has a more ephemeral, more uncomplicated, or more direct representation.
Here,
0.059 can be round to the nearest hundredths, So, yes cousin is correct. And number 0.059 is greater than 0.059 and near to 0.06. So, the rounded number be 0.06.
Thus, the required rounded decimal value of 0.059 to nearest hundredths is 0.06.
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In a bag of 10 marbles, there are 4 blue, 3 red, 2 green, and 1 yellow. What is the probability that you draw one marble that is blue, DO NOT replace it, and draw another marble that is green?
The probability that you draw one marble that is blue and then another marble that is green without replacing the first one is 4/45.
The probability of drawing a blue marble on the first draw is 4/10 (since there are 4 blue marbles out of 10 total marbles in the bag). Since the marble is not replaced, there will be one less marble in the bag for the second draw. So, for the second draw, the probability of drawing a green marble is 2/9 (since there will be 9 marbles left in the bag, including 2 green marbles).
To find the probability of both events happening together (drawing a blue marble and then a green marble), we need to multiply the probabilities of the individual events:
P(drawing blue marble and then green marble) = P(drawing blue marble) x P(drawing green marble after blue marble)
= (4/10) x (2/9)
= 8/90
= 4/45
Therefore, the probability of drawing one marble that is blue, DO NOT replace it, and drawing another marble that is green is 4/45.
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in the 40-60-90 triangle below, side s has a length of ___ and side q has a length of __
Answer:
D. \( 5,\: 5\sqrt 3\)
Step-by-step explanation:
According to the 30°-60°-90° triangle theorem:
Side opposite to 30° is half of hypotenuse and side opposite to 60° is \( \frac{\sqrt 3}{2} \) times of hypotenuse.
In the given figure:
side s is opposite to 30° angle.
\( \therefore s = \frac{1}{2} \times 10= 5\\\)
side q is opposite to 60° angle.
\( \therefore q =\frac{\sqrt 3}{2} \times 10= 5\sqrt 3\\\)
a hexagon has side lengths (4+7x), (60-2x), (7x+10), (10x-5),(5+8x), (8x-7). write an expression for the perimeter and simplify
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
hexagon
perimeter = ?
Step 02:
perimeter :
perimeter = (4+7x) + (60-2x) + (7x+10) + (10x-5) + (5+8x) + (8x-7)
= 7x -2x + 7x + 10x + 8x + 8x + 4 + 60 + 10 - 5 + 5 - 7
= 38x + 67
The answer is:
The perimeter of the hexagon is 38x + 67
What is the surface area of the following
Answer Choices:
80 square cm
64 square cm
112 square cm
72 square cm
Step-by-step explanation:
2(6)(4)+(4)(4)
48+16
64 square Centimeters
For each of the following statements decide whether it is true/false. If true - give a short (non formal) explanation. If False, provide a counter example. (a) For every field F and for every symmetric bilinear form B : F × Fn → F there is some basis for F such that the matrix representing B with respect to ß is diagonal. (b) The singular values of any linear operator T = L(V, W) are the eigenvalues of T*T. (c) There exists a linear operator T = L(C") which has no T-invariant subspaces besides Cn and {0}. (d) The orthogonal complement of any set S CV (S is not necessarily a subspace) is a subspace of V. (e) Linear operators and their adjoints have the same eigenvectors.
For each of the following statements decide whether it is true/false. If true - give a short (non formal) explanation are as follows :
(a) False. There exist fields F and symmetric bilinear forms B for which there is no basis that diagonalizes the matrix representing B. For example, consider the field F = ℝ and the symmetric bilinear form B defined on ℝ² as B((x₁, x₂), (y₁, y₂)) = x₁y₂ + x₂y₁. No basis can diagonalize this bilinear form.
(b) True. The singular values of a linear operator T are the square roots of the eigenvalues of the operator TT. This can be seen from the spectral theorem for normal operators, which states that a linear operator T is normal if and only if it can be diagonalized by a unitary matrix. Since TT is self-adjoint, it is normal, and its eigenvalues are nonnegative real numbers. Taking the square root of these eigenvalues gives the singular values of T.
(c) True. There exists a linear operator T on Cⁿ that has no T-invariant subspaces besides Cⁿ and {0}. One example is the zero operator, which only has the subspaces Cⁿ and {0} as T-invariant subspaces.
(d) False. The orthogonal complement of a set S in V is not necessarily a subspace of V. For example, consider V = ℝ² with the standard inner product. Let S = {(1, 0)}. The orthogonal complement of S is {(0, y) | y ∈ ℝ}, which is not closed under addition and scalar multiplication, and therefore, not a subspace.
(e) True. Linear operators and their adjoints have the same eigenvectors. If v is an eigenvector of a linear operator T with eigenvalue λ, then Tv = λv. Taking the adjoint of both sides, we have (Tv)* = λv. Since the adjoint of a linear operator commutes with scalar multiplication, we can rewrite this as T* v* = λ v*, showing that v* is also an eigenvector of T* with eigenvalue λ.
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Find the measure of line BD.
answer: line BD=8
Step-by-step explanation:
because line AD is congruent to line BD
Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0
The equations that can be used to solve for the length of the room are
(b) y²-5y=750 , (c) 750-y(y-5)=0 and (e) (y+25)(y-30)=0
Given that:
The area of rectangular room is 750 square feet.
Let the length of the rectangular room be y feet.
Since the width of the rectangular 5 less than the length of the room.
Then the width of the given rectangular room is (y-5) feet.
We know the area of a rectangular plot is = Length×width.
Thus , the area of the rectangular room is = y(y-5) square feet
According to problem,
area of the rectangular room = 750 square feet
⇒ y(y-5) =750.........(1)
⇒ y²-5y=750 .......(2)
⇒ y²-5y-750=0
⇒ y²-30y+25y-750=0
⇒ y(y-30)+25(y-30)=0
⇒ (y-30)(y+25)=0 ......(3)
⇒ y-30=0 or, y+25=0
⇒ y= 30, -25
∵ the length of a rectangle can't be negative.
So, y=30.
We can rewrite the equation (1) in form of
(i)
y(y-5) =750
⇒750= y(y-5)
⇒750-y(y-5)=0.......(4)
(ii)
y(y-5) =750
⇒y(y-5) -750=0.......(5)
Hence , the equations that can be used to solve for the length of the room are
(b) y²-5y=750 , (c) 750-y(y-5)=0 and (e) (y+25)(y-30)=0
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Let U = {1, 2, 3, 4, 5, 6, 7}, A = {2, 4, 6}, B = {1, 2, 3, 5, 7}, and C = {1, 3, 6, 7}.Find A ∩ Ø Question 47 options:a) { }b) {1, 3, 5, 7}c) {1, 2, 3, 4, 5, 6, 7}d) {2, 4, 6}
Intersection of A = {2, 4, 6} and Ø that is A ∩ Ø = { } = Ø
Intersection of set :
For two sets A and B, Intersection of sets will be the set of elements common in both the sets.
The intersection of sets can be denoted using the symbol '∩'.
A ∩ B , Read as A intersection B
Example: A = {2, 4, 6} and B = {1, 2, 3, 5, 7}
A ∩ B = {2}
Now according to question,
given,
U = {1, 2, 3, 4, 5, 6, 7}
A = {2, 4, 6}
B = {1, 2, 3, 5, 7}
Find,
A ∩ Ø =
Here,
Ø is a null set, means no element is there in the set.
Ø = { }
So,
A ∩ Ø = Ø
= { }
because between set A and Ø nothing is common.
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A rectangular prism-shaped display case is 30 1/2 inches wide, 10 1/2 inches long, and 32 1/4 inches tall.
What is the volume of the display case in cubic inches?
Responses
73 1/4 in³
73 and 1 fourth, in³
320 1/4 in³
320 and 1 fourth, in³
10,328 1/16 in³
10328 and 1 sixteenth, in³
28,372 5/8 in
The volume of the display case is 2161 1/8 cubic inches.To find the volume of a rectangular prism-shaped display case, we multiply its length, width, and height.
Given that the display case is 30 1/2 inches wide, 10 1/2 inches long, and 32 1/4 inches tall, we can calculate the volume as follows:
Volume = Length * Width * Height
Using the given measurements:
Volume = 10 1/2 inches * 30 1/2 inches * 32 1/4 inches
To simplify the calculation, we can convert the mixed numbers to improper fractions:
Volume = (21/2) inches * (61/2) inches * (129/4) inches
Next, we multiply the fractions:
Volume = (21/2) * (61/2) * (129/4) = 17289/8
The resulting fraction, 17289/8, is an improper fraction. To convert it back to mixed number form:
Volume = 2161 1/8 in³.
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i need help on this
|x/3| if x<0
After considering the given data we conclude that the value obtained from solving the given expression is x/3, under the condition that the given expression is |x/3| in the range of x<0.
The absolute value function is describes as a function in algebra in which particularly the variable is inside the absolute value bars. The most commonly and generally used form of the absolute value function is f(x) = |x|, here x is a real number.
The absolute counted value considering a negative number is claimed always positive. So, if x < 0, then |x| = -x⁴.
Then, in the given expression, if x < 0, then |x/3| = |-x/3| = x/3.
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5. Use the Lagrange multiplier method to find the values of and y which maximise the function f(x,y)=x^1/2y^1/2 subject to the constraint 2x +y = 20. 6. A sequence of numbers xo, 01.12.... is such that so = 1 and, for each n > 1
xn = 1/3xn-1 + 2
Find an explicit expression for , in terms of n. Hence describe the behaviour of xn as n -> infinity.
Using the Lagrange multiplier method, the maximum values of x and y for the given function and constraint are x = 8 and y = 4.
To maximize the function f(x, y) = x^(1/2) * y^(1/2) subject to the constraint 2x + y = 20, we can employ the Lagrange multiplier method.
Set up the Lagrange function L(x, y, λ) = f(x, y) - λ(g(x, y)), where g(x, y) represents the constraint equation.
Differentiate L with respect to x, y, and λ, and set the partial derivatives equal to zero.
Solve the resulting system of equations to find critical points.
Evaluate the critical points and check the endpoints of the feasible region.
Determine the maximum values of x and y that maximize the function f(x, y) while satisfying the given constraint.
Applying these steps, we find that x = 8 and y = 4 maximize the function f(x, y) subject to the constraint. Thus, the maximum values of x and y are 8 and 4, respectively.
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4x + 2y = 7
I need help
the answer is circle in blue
A family pays for 50 MB of internet connectivity for downloads. When measuring their internet speed, a family member observed a maximum speed of 35 MB. By what percentage is the measured speed different from the advertised speed?
PLS HELP
Answer:
its 70% of the speed they expected
Help me please random strangers on the internet!
Answer:
66 ft
Step-by-step explanation:
model: real life
1 inch : 12 ft
We have 5.5 inches so we need to multiply each side by 5.5 inches
model: real life
1 *5.5 : 12 *5.5
5.5 in: 66 ft
Answer:
66 feet
Step-by-step explanation:
1 inch of a model represents 12 feet of a real shuttle
5.5 inches as height of a model will represent 12 × 5.5 feet as height of a shuttle
=66 feet
Drag each tile to the correct box. Using the order of operations, what are the steps for solving this expression? 8 x 3 (4213) +52 +4 x 3 Arrange the steps in the order in which they are performed. 16 13 - 5² 4² 8+25 33 + 12 24 3 8 × 3 4 x 3 ↓ ↓ 40-
The steps for solving the expression 8 x 3 (4213) + 52 + 4 x 3 in the correct order are 16, 384, 12, 436, 448.
To solve the expression 8 x 3 (4213) + 52 + 4 x 3 using the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction), the steps should be performed in the following order:
Start by simplifying the expression within the parentheses: 4213 = 16.
Expression becomes: 8 x 3 x 16 + 52 + 4 x 3
Perform the multiplication operations from left to right:
8 x 3 x 16 = 384
Expression becomes: 384 + 52 + 4 x 3
Continue with any remaining multiplication operations:
4 x 3 = 12
Expression becomes: 384 + 52 + 12
Perform the addition operations from left to right:
384 + 52 = 436
Expression becomes: 436 + 12
Finally, perform the remaining addition operation:
436 + 12 = 448
Therefore, the steps for solving the expression 8 x 3 (4213) + 52 + 4 x 3 in the correct order are:
16, 384, 12, 436, 448.
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The life expectancy of Timely brand watches is normally distributed with a mean of four years and a standard deviation of eight months.
a. What is the probability that a randomly selected watch will be in working condition for more than five years?
b. The company has a three year warranty period on their watches. What percentage of their watches will be in operating condition after the warranty period?
c. What is the minimum and the maximum life expectancy of the middle 95% of the watches?
d. Ninety-five percent of the watches will have a life expectancy of at least how many months?
a.The probability that a randomly selected watch will be in working condition for more than five years is approximately 6.68%. b.Approximately 93.32% of the watches will be in operating condition after the warranty period. c. The maximum life expectancy of the middle 95% of the watches is approxiamately 63.68 months. d.The range of the middle 95% of the watches is from 32.32 months to 63.68 months. The range represents 95% of the watches, it means that 5%.
a. To find the probability that a randomly selected watch will be in working condition for more than five years, we need to convert the time to the same unit as the distribution. Since the mean is given in years and the standard deviation is given in months,
we need to convert five years to months.
Mean = 4 years = 4 x 12 months = 48 months
Standard deviation = 8 months
To calculate the probability, we need to find the area under the normal distribution curve to the right of 60 months (5 years).
Using a standard normal distribution table or a calculator, we can find the z-score corresponding to 60 months:
z = (x - μ) / σ
z = (60 - 48) / 8 = 12 / 8 = 1.5
The probability can be found by looking up the z-score in the standard normal distribution table or using a calculator. From the table or calculator, we find that the probability is approximately 0.0668, or 6.68%.
b. The warranty period for Timely brand watches is three years. To find the percentage of watches that will be in operating condition after the warranty period, we need to find the probability that a randomly selected watch will last longer than three years.
We need to convert three years to months:
Warranty period = 3 years = 3 x 12 months = 36 months
We calculate the z-score:
z = (x - μ) / σ
z = (36 - 48) / 8 = -12 / 8 = -1.5
Using the standard normal distribution table or a calculator, we find the area to the left of -1.5 is approximately 0.0668. The probability that a randomly selected watch will not last longer than three years is approximately 0.0668.
To find the percentage of watches that will be in operating condition after the warranty period, we subtract this probability from 1 (since we want the complementary probability):
Percentage = 1 - 0.0668 = 0.9332 = 93.32%
c. The middle 95% of the watches represents the range within which 95% of the watches' life expectancy falls. To find the minimum and maximum life expectancy of this range, we need to determine the z-scores that correspond to the cumulative probability of 0.025 and 0.975.
For the minimum life expectancy (lower bound), we look up the z-score that corresponds to a cumulative probability of 0.025. This z-score is approximately -1.96.
z = -1.96
Using the z-score formula, we can find the corresponding value in months:
x = μ + (z x σ)
x = 48 + (-1.96 * 8) = 48 - 15.68 = 32.32
The minimum life expectancy of the middle 95% of the watches is approximately 32.32 months.
For the maximum life expectancy (upper bound), we look up the z-score that corresponds to a cumulative probability of 0.975. This z-score is also approximately 1.96.
z = 1.96
Using the z-score formula, we can find the corresponding value in months:
x = μ + (z x σ)
x = 48 + (1.96 x 8) = 48 + 15.68 = 63.68
d. Ninety-five percent of the watches refer to the range between the 2.5th and 97.5th percentiles. We already calculated the z-scores corresponding to these percentiles in part c: -1.96 and 1.96.
To find the range in months,
we convert the z-scores back:
\(x_{1}\)= μ +\(z_{1}\) x σ = 48 + (-1.96) x 8 = 32.32 months,
and \(x_{2}\)= μ + \(z_{2}\) x σ
= 48 + 1.96 x 8
= 63.68 months.
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Solve this 30-60-90 Triangles
Answer: Actually kinda ez not gonna lie. y = 11.547, x = 23.094
Step-by-step explanation: we know that y * square root of 3 = 20. 20/ root 3 is 11.547. Hypotenuse is 2 times y. This gives us x = 23.09
here is the other part
mario
Answer: cool
Step-by-step explanation:
20 points.
The midpoint of AB is (-1, 5) and the coordinates of point A are (-3, 2) what are the coordinates of point B?
Answer:
B (1, 8 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( \(\frac{x_{1}+x_{2} }{2}\) , \(\frac{y_{1}+y_{2} }{2}\) )
with (x₁, y₁ ) = A (- 3, 2 ) and (x₂, y₂ ) = B (x, y )
Calculate the midpoint values and equate to the corresponding coordinates of the given midpoint (- 1, 5 ) , that is
\(\frac{-3+x}{2}\) = - 1 ( multiply both sides by 2 )
- 3 + x = - 2 ( add 3 to both sides )
x = 1
\(\frac{2+y}{2}\) = 5 ( multiply both sides by 2 )
2 + y = 10 ( subtract 2 from both sides )
y = 8
Then point B = (1, 8 )