The volume of the given solid that is bounded by the coordinate planes and the plane 9x + 5y + z = 45 is 45 units³.
What is volume?Volume is a measurement of three-dimensional space that is occupied. It is frequently expressed quantitatively using SI-derived units, as well as several imperial or US-standard units. Volume and the notion of length are connected.For instance, a cup's capacity is stated to be 100 ml if it can hold 100 ml of water in its brim. The quantity of space occupied by a three-dimensional object can also be used to describe volume.So, we have: 9x + 5y + z = 45
Let us consider z = 0.
Then we have:
9x + 5y = 45
Now, we obtain:
x = 45/9 - y
OR
y = 45/5 - x
Hence,
45/9 × 45/5
2,025/45
45 units³
Therefore, the volume of the given solid that is bounded by the coordinate planes and the plane 9x + 5y + z = 45 is 45 units³.
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Determine the average and rms values for the function y(t)=25+10sin6πt over the time periods (a) 0 to 0.1 s, (b) 0.4 to 0.5 s, (c) 0 to 1/3 s, and (d) 0 to 20 s. Comment on the nature and meaning of the results in terms of analysis of dynamic signals.|
Comment: RMS value is equal to the average value. This means that the signal does not have any high-frequency content. It can be inferred that the function y(t) does not oscillate. When the RMS value is less than the average value, it means that the signal has a lesser amount of high-frequency content.
Average and rms values for the function y(t)=25+10sin6πt over the time periods (a) 0 to 0.1 s, (b) 0.4 to 0.5 s, (c) 0 to 1/3 s, and (d) 0 to 20 s are as follows:
a) For t=0 to t=0.1s:
Average value, y_avg = 25
RMS value, y_RMS = 25.1987
Comment: RMS value is greater than the average value. This means that the signal has a considerable amount of high-frequency content. It can be inferred that the function y(t) oscillates rapidly.
b) For t=0.4 to t=0.5s:
Average value, y_avg = 25
RMS value, y_RMS = 28.2843
Comment: RMS value is greater than the average value. This means that the signal has a considerable amount of high-frequency content. It can be inferred that the function y(t) oscillates rapidly.
c) For t=0 to t=1/3 s:
Average value, y_avg = 25
RMS value, y_RMS = 23.7176
Comment: RMS value is less than the average value. This means that the signal has a lesser amount of high-frequency content. It can be inferred that the function y(t) oscillates slowly.
d) For t=0 to t=20 s:
Average value, y_avg = 25
RMS value, y_RMS = 25
Comment: RMS value is equal to the average value. This means that the signal does not have any high-frequency content. It can be inferred that the function y(t) does not oscillate. Comment on the nature and meaning of the results in terms of analysis of dynamic signals.The results indicate that the function y(t) oscillates rapidly at the start and end of the time period and slowly in the middle. When the RMS value is greater than the average value, it means that the signal has a considerable amount of high-frequency content.
On the other hand, when the RMS value is less than the average value, it means that the signal has a lesser amount of high-frequency content.
Furthermore, if the RMS value is equal to the average value, it means that the signal does not have any high-frequency content.
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What are the ACT math formulas that you absolutely have to know?
The ACT Math section tests a wide range of mathematical concepts and skills, so there are many formulas and concepts that you should be familiar with.
Here are some of the most important ACT math formulas that you should know:
1. Basic operations: addition, subtraction, multiplication, and division.
2. Exponents and roots: \(a^n\) means a multiplied by itself n times; the nth root of a is the number that, when raised to the nth power, gives a.
3. Order of operations: parentheses, exponents, multiplication/division (from left to right), and addition/subtraction (from left to right).
4. Fractions: converting between fractions, decimals, and percents; adding, subtracting, multiplying, and dividing fractions.
5. Algebra: solving equations and inequalities; simplifying algebraic expressions; factoring quadratics; understanding linear and quadratic functions.
6. Geometry: properties of lines, angles, and polygons; Pythagorean theorem; trigonometric functions; volume and surface area of 3D shapes.
7. Probability and statistics: calculating probabilities; mean, median, and mode; standard deviation.
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Help Me Please I really need it
What is the midpoint of a line segment connecting the points (−4,6) and (8,2) Need answer fast
Answer:
-12 & -18
Step-by-step explanation:
Answer:
Step-by-step explanation:
an instructor was interested in seeing if there was a difference in the average amount of time that men and women anticipate studying for an introduction to statistics course in the summer. a group of men and women were randomly selected from the university of florida. the minitab results are below. what is the best interpretation of the results below?
The best interpretation of the results would depend on the specific statistical analysis used and the results obtained.
The results indicated a statistically significant difference between the mean anticipated study times for men and women, the interpretation would be that men and women have different average anticipated study times for the introduction to statistics course.
Conversely, if there was no statistically significant difference, the interpretation would be that there is no evidence to suggest that men and women have different average anticipated study times for the course.
As the Minitab results are not provided in the question, I cannot interpret them.
Provide a general interpretation of the statistical analysis based on the information given.
The instructor was interested in seeing if there was a difference in the average amount of time that men and women anticipated studying for an introduction to statistics course in the summer.
To test this hypothesis, a group of men and women were randomly selected from the University of Florida.
The statistical analysis may have involved using a t-test or a similar method to compare the mean anticipated study times between men and women.
The results of this analysis would provide information on whether there is a statistically significant difference between the mean anticipated study times for men and women.
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which measure of central tendency better describes the typical test score
The measure of central tendency that better describes the typical test score depends on the shape of the distribution of the scores - it can be median or mean.
The measure of central tendency that better describes the typical test score is the median. The median is the middle value in a data set when the data is arranged in ascending or descending order. It is a better measure of central tendency for test scores because it is not affected by extreme values or outliers, which can skew the mean.
To find the median, first, arrange the test scores in ascending or descending order. If there is an odd number of test scores, the median is the middle value. If there is an even number of test scores, the median is the average of the two middle values.
For example, if the test scores are 85, 90, 92, 95, and 98, the median is 92. If the test scores are 85, 90, 92, 95, 98, and 100, the median is (92 + 95)/2 = 93.5.
If the distribution of test scores is approximately symmetrical or bell-shaped, then the mean (arithmetic average) is a good measure of central tendency to describe the typical test score.
In conclusion, the choice of measure of central tendency to describe the typical test score depends on the shape of the distribution of the scores. If the distribution is approximately symmetrical or bell-shaped, the mean is preferred, and if it is skewed or contains outliers, the median is preferred.
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Please help! due tomorrow
5. Bananas cost $0.50 each, and apples cost $1.00 each. Select all the combinations of bananas and apples that Elena could buy for exactly $3.50. A. 2 bananas and 2 apples B. 3 bananas and 2 apples C. 1 banana and 2 apples D. 1 banana and 3 apples E. 5 bananas and 2 apples F. 5 bananas and 1 apple
Answer: B and D
Step-by-step explanation:
Lesson 8 Practice Problems
1. A number line can represent positions that are north and south of a truck stop on a
highway. Decide whether you want positive positions to be north or south of the
truck stop. Then plot the following positions on a number line.
a. The truck stop
b. 5 miles north of the truck stop
c. 3.5 miles south of the truck stop
The graph can be viewed at the conclusion of the response. We want to graph a number line and certain points on it.
Let A denote the truck stop and then it is 0 miles away from the truck stop.
Let us take the north side of the truck stop as the negative side.
Then the south side of the truck stop is the positive side.
We are asked to represent the following positions on the number line:
a. The truck stop
b. 5 miles to the north of the truck stop
c. 3.5 miles to the south of the truck stop
Point A refers to the truck stop.
Let B denote the point 5 miles away from A towards the north side of the truck stop.
And let C denote the point 3.5 miles away from A towards the south side of the truck stop.
Refer to the attached image for the required number line.
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HELP? .................................................
Answer:
the last option
Step-by-step explanation:
I'm smart
Answer:
1st option
Step-by-step explanation:
Consider the coordinates of the point and its image
P (- 8, - 6 ) and P' (- 3, - 3 )
From - 8 to - 3 in the x- direction means adding 5
From - 6 to - 3 in the y- direction means adding 3
Then the translation rule is
(x, y ) → (x + 5, y + 3 )
Find the Laplace transform F(s) = L{f(t)} of the function f(t) = sin^2 (wt), defined on the interval t >= 0. F(s) = L {sin^2 (wt)} = For what values of S does the Laplace transform exist
The laplace transform of f(t) is \(F(s)=\frac{1}{2s}-\frac{2w}{2(s^2+4w^2)}\) and it's values exists for \(s=w\pm\sqrt{3}wi\).
Given,
\(f(t)=sin^2(wt)\\\\\therefore sin^2x=\frac{1-cos2x}{2}\\\\f(t)=\frac{1-cos2wt}{2}\)
applying laplace transform on both sides,
\(L[f(t)]=L[\frac{1-cos2wt}{2}]\\\\F(s)=\frac{1}{2s}-\frac{2w}{2(s^2+4w^2)}\)
The range for values of s for which F(s) exists is when F(s)≥0
\(\frac{1}{2s}-\frac{2w}{2(s^2+4w^2)} \geq0\\\\\frac{1}{2s} \geq\frac{2w}{2(s^2+4w^2)}\\\\2(s^2+4w^2) \geq 2sw\\\\s^2-2sw+4w^2 \geq0\)
using formula to find roots,
\(s=\frac{-(-2w)\pm\sqrt{(-2w^2)-4(4w^2)}}{2}\\\\s=\frac{-(-2w)\pm\sqrt{(12w^2}}{2}\\\\s=w\pm\sqrt{3}wi\)
Thus, the laplace transform of f(t) is \(F(s)=\frac{1}{2s}-\frac{2w}{2(s^2+4w^2)}\) and it's values exists for \(s=w\pm\sqrt{3}wi\).
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Rosie is x years old
Eva is 2 years older
Jack is twice Rosie’s age
A) write an expression for the mean of their ages.
B) the total of their ages is 42
How old is Rosie?
Answer:
Rosie is 10 years old
Step-by-step explanation:
A)
Rosie is x years old
Rosie's age (R) = x
R = x
Eva is 2 years older
Eva's age (E) = x + 2
E = x + 2
Jack is twice Rosie’s age
Jack's age (J) = 2x
J = 2x
B)
R + E + J = 42
x + (x + 2) + (2x) = 42
x + x + 2 + 2x = 42
4x + 2 = 42
4x = 42 - 2
4x = 40
\(x = \frac{40}{4} \\\\x = 10\)
Rosie is 10 years old
A rectangular storage container without a lid is to have a volume of 10 m3. the length of its base is twice the width. material for the base costs $15 per square meter. material for the sides costs $9 per square meter. let w denote the width of the base. Find a function in the variable w giving the cost C in dollars) of constructing the box.
The function in variable w giving the cost C (in dollars) of constructing the box is C(w) = 30w² + 270/w. The result is obtained by using the formula of volume and area of the box.
How to determine the function?We have a rectangular storage container without a lid.
Volume, V = 10 m³Length, l = 2wWidth, w = wBase costs $15/m²Sides costs $9/m²The formula of volume of the box is
V = l × w × h
Where
l = lengthw = widthh = heightSo, the height is
10 = 2w × w × h
10 = 2w² × h
h = 10/2w²
h = 5/w²
To find the total cost, calculate the area of base and sides of the box!
See the picture in the attachment!
The base area is
A₁ = 2w × w = 2w² m²
The sides area is
A₂ = 2(2wh + wh)
A₂ = 2(3wh)
A₂ = 6wh
A₂ = 6w(5/w²)
A₂ = 30/w m²
The total cost is
C = $15(2w²) + $9(30/w)
C = $30w² + $270/w
The function of the total cost is
C(w) = 30w² + 270/w
Hence, the function of constructing the box is C(w) = 30w² + 270/w.
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Two identical sets of data are shown below.
Data Set 1: 58, 59, 62, 64, 67, 67
Data Set 1: 58, 59, 62, 64, 67, 67
An outlier is added to Data Set 2. Which of the following statistics must be greater in Data Set 2 when compared to Data Set 1 now that the outlier has been added? Select TWO that apply
mean
standard deviation
mode
median
range
Answer:
Standard deviation RangeStep-by-step explanation:
Two identical sets of data are:
Data Set 1: 58, 59, 62, 64, 67, 67 Data Set 2: 58, 59, 62, 64, 67, 67An outlier is added to Data Set 2. This is the number that is either smaller than 58 or greater than 67.
Mean
No, it could be greater or smallerStandard deviation
Yes, it will increase with an outlier added because the difference between the added number and the mean will be the greatest.Mode
No, it could be greater or smallerMedian
No, it could be greater or smallerRange
Yes, it will increase as either lower or the higher value will be added to the data set.when computing a confidence interval about a parameter based on sample data, what is the impact of using a different confidence level?
The confidence level determines the degree of certainty with which we can say that the true population parameter falls within the interval estimate. The higher the confidence level, the wider the interval estimate.
For example, suppose we have a sample of size n = 100, and we want to compute a confidence interval for the population mean μ based on a 95% confidence level. If the sample mean is 10 and the sample standard deviation is 2, the interval estimate is given by:
interval estimate = sample mean ± z * (standard error)where z is the critical value from the standard normal distribution corresponding to a 95% confidence level, and the standard error is the standard deviation of the sampling distribution of the mean, which is equal to the standard deviation of the sample divided by the square root of the sample size:
standard error = 2 / sqrt(100) = 0.2The critical value z for a 95% confidence level is approximately 1.96. Therefore, the interval estimate is:
10 ± 1.96 * 0.2 = [9.6, 10.4]This means that we are 95% confident that the true population mean falls within the interval [9.6, 10.4]. If we had chosen a higher confidence level, such as 99%, the critical value z would be larger (approximately 2.58), and the interval estimate would be wider:
10 ± 2.58 * 0.2 = [9.02, 10.98]This means that we would be 99% confident that the true population mean falls within the wider interval [9.02, 10.98]. Conversely, if we had chosen a lower confidence level, such as 90%, the critical value z would be smaller (approximately 1.645), and the interval estimate would be narrower:
10 ± 1.645 * 0.2 = [9.34, 10.66]This means that we would be 90% confident that the true population mean falls within the narrower interval [9.34, 10.66].
In summary, the choice of confidence level has a direct impact on the width of the interval estimate, with higher confidence levels leading to wider intervals and lower confidence levels leading to narrower intervals. The level of confidence chosen depends on the desired degree of certainty and the trade-off between the precision and accuracy of the estimate.
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a company invests $91,000 for equipment to produce a new product. each unit of the product costs $11.40 and is sold for $17.98. let x be the number of units produced and sold. (a) write the total cost c as a function of x.
Total cost c as a function of x is $94000 + 11.2x.
A company invests $94,000 for equipment to produce a new product. each unit of the product costs $11.40 and is sold for $17.98.
let x be the number of units produced and sold.
now,
Number of units = x
so,
c(x)= $94000 + 11.2x
Equation
An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
Function
A function relates an input to an output. It is like a machine that has an input and an output. And the output is related somehow to the input.
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In order to solve the equation 9x = -3 (2+ 3y) for y a student simplifies the equation as shown
Step 1: 9x = –3x + -3 (Gy)
Step 2: 9x = -3x + - y
Step 3: 92
Step 4: 6x = -Y
Step 5: Y = -6
3x = -Y
Which statement describes the error the student made in simplifying the equation?
A square has sides of length 7.8 centimeters. What is the area?
Answer:
60.84 cm²
Step-by-step explanation:
The formula for the area of a square is:
A=s²
A=7.8²
A=60.84 cm²
What is the solution of the inequality shown
below?
y+7≤-1
The solution to the inequality is y ≤ -8. This means that any value of y that is less than or equal to -8 will satisfy the original inequality.
To solve the inequality y + 7 ≤ -1, we need to isolate the variable y on one side of the inequality sign.
Starting with the given inequality:
y + 7 ≤ -1
We can begin by subtracting 7 from both sides of the inequality:
y + 7 - 7 ≤ -1 - 7
y ≤ -8
The solution to the inequality is y ≤ -8. This means that any value of y that is less than or equal to -8 will satisfy the original inequality.
In the context of a number line, all values to the left of -8, including -8 itself, will make the inequality true. For example, -10, -9, -8, -8.5, and any other value less than -8 will satisfy the inequality. However, any value greater than -8 will not satisfy the inequality.
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The following question may be like this:
What is a solution of the inequality shown below? y+7≤-1
A 10-digit number M is 1 more than a square of another integer. Is it possible for all digits of M to be distinct? this is due in 2 hours
By answering the given question, we may state that k is an integer, equation where. This number becomes squared to give us: \(n^2\) = \((100k + 9)^2\) = 10000\(k^2\) + 1800k + 81
What is equation?Using the equals symbol (=) to indicate equivalence, a math equation links two statements. Algebraic equations prove the equality of two mathematical expressions by a mathematical assertion. The equal sign, for example, provides a gap between the numbers 3x + 5 and 14 in the equation 3x + 5 = 14. You can use a mathematical formula to understand the connection between the two phrases that are written on opposite sides of a letter. Most of the time, the logo and the particular software match. e.g., 2x - 4 = 2 is an example.
Assume for the moment that there is a 10-digit number M, which is one more than the square of another integer and has unique digits throughout. This integer can be written as:
\(M = a 110*9*a 210*8*a 310*7*a 410*6*a 510*5*a 610*4*a 710*3*a 810*2*a 9*10*a 10\)
where M's digits a 1, a 2,..., a 10 are.
\(n = 10k + 1\)
k is an integer, where. This number becomes squared to give us:
\(n^2 = (10k + 1)\)
\(n^2 = 100k^2 + 20k + 1\)
\(n = 100k + 9\)
k is an integer, where. This number becomes squared to give us:
\(n^2\) = \((100k + 9)^2\) = 10000\(k^2\) + 1800k + 81
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Blake has a total of 11,000 to invest in two accounts. one account earns 4% simple interest, and the other earns 5% simple interest. how much should be invested in each account to earn exactly $490 at the end of 1 year?
Blake should invest $6,000 at 4% interest and the remaining $5,000 (11000 - 6000) at 5% interest to earn exactly $490 at the end of 1 year.
Let's denote the amount of money Blake invests at 4% interest as "x" (in dollars) and the amount he invests at 5% interest as "11000 - x" (since the total investment is $11,000).
To earn interest, we can use the formula: Interest = Principal × Rate × Time
For the 4% interest account, the interest earned is:
0.04x × 1 (1 year) = 0.04x
For the 5% interest account, the interest earned is:
0.05(11000 - x) × 1 (1 year) = 550 - 0.05x
According to the problem, the total interest earned is $490. Therefore, we can set up the equation:
0.04x + (550 - 0.05x) = 490
Simplifying the equation:
0.04x + 550 - 0.05x = 490
-0.01x + 550 = 490
-0.01x = -60
x = 6000
Blake should invest $6,000 at 4% interest and the remaining $5,000 (11000 - 6000) at 5% interest to earn exactly $490 at the end of 1 year.
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Consider the following.
t = −
4π
3
(a) Find the reference number t for the value of t.
t =
(b) Find the terminal point determined by t.
(x, y) =
The given equation t = −4π/3 represents a reference number on the unit circle. To find the reference number t, we can simply substitute the given value of t into the equation.
In trigonometry, the unit circle is a circle with a radius of 1 unit centered at the origin (0, 0) in a coordinate plane. It is commonly used to represent angles and their corresponding trigonometric functions. The equation t = −4π/3 defines a reference number on the unit circle.
To find the reference number t, we substitute the given value of t into the equation. In this case, t = −4π/3. Therefore, the reference number is t = −4π/3.
The terminal point (x, y) on the unit circle can be determined by using the reference number t. The x-coordinate of the terminal point is given by x = cos(t) and the y-coordinate is given by y = sin(t).
By substituting t = −4π/3 into the trigonometric functions, we can find the values of x and y. Hence, the terminal point determined by t is (x, y) = (cos(−4π/3), sin(−4π/3)).
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Which of the following pair of triangles demonstrates that two triangles with three congruent angles are not necessarily congruent?
Answer:
it is A.
Step-by-step explanation:
this should be A.
if it isn't sorry
Answer:
A.
Step-by-step explanation:
a school is organizing a weekend trip to a nature preserve. for each student, there is a $50 charge, which covers food and lodging. there is also a $25 charge per student for the bus. the school must also pay a $15 cleaning fee for the bus. if the total cost of the weekend is $3,765, how many students will be going on the trip?
The total number of students going for the weekend trip as per the given total cost and other charges is equal to 50.
Let us consider 'n' be the number of students going for trip.
Per student charge for food and lodging = $50
Total food and lodging charges = $50n
Bus charges per student = $25
Total bus charges = $25n
Bus cleaning fees = $15
Total cost for the trip = $3,765
Equation formed for the above condition is:
$ (50n + 25n + 15 ) = $3,765
⇒ $ ( 75n + 15 ) = $3,765
⇒ 75n = 3,765 - 15
⇒ n = 3,750/ 75
⇒ n = 50
Therefore, there are 50 students going on the weekend trip.
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In each of Problems 1 through 10 find the general solution of the given differential equation. 1. y" – 2y' + y = 0 2. 9y" + 6y' + y = 0 3. 4y" – 4y' – 3y = 0) 4. 4y" + 12y' +9y = 0 5. y" – 2y' + 10y = 0) 6. y" – 6y' +9y = 0 7. 4y" + 17y' + 4y = 0 8. 16y" + 24y' +9y = 0 9. 25y" – 20y' + 4y = 0 10. 2y" + 2y' + y = 0
1) General solution for second order differential equation, y" – 2y' + y = 0, is y = (c₁x + c₂)eˣ .
2) General solution for differential equation, 9y" + 6y' + y = 0, is y =(c₁x + c₂)e⁻³ˣ.
3) General solution for differential equation, 4y"- 4y'- 3y = 0, is y = c₁ e⁶ˣ+ c₂e⁻⁴ˣ.
4) General solution for differential equation, 4y" + 12y' +9y = 0, is y = (c₁x + c₂)e⁻⁶ˣ.
5) General solution for differential equation, y" – 2y' + 10y = 0, is y = eˣ (c₁cos(6x) + c₂sin(6x)).
6) General solution for differential equation, y" – 6y' +9y = 0 is y = (c₁x + c₂)e³ˣ.
7) General solution for differential equation, 4y" + 17y' + 4y = 0, is y = c₁e⁻ˣ + c₂e⁻¹⁶ˣ.
8) General solution for differential equation, 16y" + 24y' +9y = 0, is y = (c₁x + c₂)e⁻¹²ˣ.
9) General solution for differential equation, 25y" – 20y' + 4y = 0, is y = (c₁x + c₂)e¹⁰ˣ.
10) General solution for differential equation, 2y" + 2y' + y = 0, is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)).
General solution is also called complete solution and complete solution = complemantory function + particular Solution
Here right hand side is zero so particular solution is equals to zero. Therefore, evaluating the complementary function will be sufficient to determine the general solution to the differential equation.
1) y"-2y' + y = 0, --(1)
put D = d/dx, so (D² - 2D + 1)y =0
Auxiliary equation for (1) can be written as, m² - 2m + 1 = 0 , a quadratic equation solving it by using quadratic formula,
\(m =\frac{-(- 2) ± \sqrt { 4 - 4}}{2}\)
=> m = 1 , 1
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)eˣ .
2) 9y" + 6y' + y = 0 or (9D² + 6D + 1)y =0 Auxiliary equation can be written as, 9m² + 6m + 1 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (6) ± \sqrt {36 - 4×4}}{2}\)
=> m = - 6/2
=> m = -3 , -3
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻³ˣ.
3) 4y"- 4y'- 3y = 0
put D = d/dx, so (4D² - 4D - 3)y = 0
Auxiliary equation can be written as, 4m² - 4m - 3 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{-(-4) ± \sqrt {16 - 4×4×(-3)}}{2}\)
=> m = (4 ± 8)/2
=> m = -4 , 6
The roots of equation are real and equal. So, general solution is y = c₁ e⁶ˣ + c₂e⁻⁴ˣ.
4) 4y" + 12y' +9y = 0 or (4D² + 12D + 9)y= 0
Auxiliary equation can be written as, 4m² + 12m + 9= 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{-(12) ± \sqrt{144 - 4×4×9}}{2}\)
=> m = -12/2
=> m = -6 , -6
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻⁶ˣ.
5) y" – 2y' + 10y = 0 or (D² - 2D + 10)y = 0 Auxiliary equation can be written as, m² - 2m + 10 = 0 , a quadratic equation
solving it by using quadratic formula,
\(m =\frac{ - (-2) ± \sqrt {4 - 4×1×10}}{2}\)
=> m = (2 ± 6i)/2 ( since, √-1 = i)
=> m = 1 + 6i , 1-6i
The roots of equation are imaginary and unequal. So, general solution is y =eˣ (c₁cos(6x) + c₂sin(6x)).
6) y" – 6y' +9y = 0 or (D²- 6D + 9)y =0
Auxiliary equation can be written as, m² - 6m + 9 = 0 , a quadratic equation
solving it by using quadratic formula,
\(m =\frac{ - (-6) ± \sqrt {36 - 4×1×9}}{2}\)
=> m = 6/2 = 3,3
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e³ˣ.
7) 4y" + 17y' + 4y = 0 or (4D²+ 17D + 4)y=0
Auxiliary equation can be written as, 4m² + 17m + 4 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{- (-17) ± \sqrt {16 - 4×4×17}}{2}\)
=> m = ( -17 ± 15)/2
=> m = (-17 + 15)/2, (- 17 - 15)/2= -1, -16
The roots of equation are real and unequal. So, general solution is y = c₁e⁻ˣ + c₂e⁻¹⁶ˣ.
8) 16y"+24y'+9y =0 or (16D²+ 24D + 9)y= 0
Auxiliary equation can be written as, 16m² + 24m + 9 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (24) ± \sqrt {576 - 4×9×16}}{2}\)
=> m = (-24 ± 0)/2
=> m = -12,-12
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻¹²ˣ.
9) 25y"- 20y' +4y =0 or (25D²-20D + 4)y = 0
Auxiliary equation can be written as, 25m²- 20m + 4 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (-20) ± \sqrt {400 - 4×4×25}}{2}\)
=> m = 20/2
=> m = 10 , 10
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e¹⁰ˣ.
10) 2y" + 2y' + y = 0 or (2D²+ 2D + 1)y =0
Auxiliary equation can be written as, 2m² + 2m + 1 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (2) ± \sqrt {4 - 4×1×2}}{2}\)
=> m = (- 2 ± 4i)/2 ( since, √-1 = i)
=> m = -1 + 2i , -1 - 2i
The roots of equation are imaginary and unequal. So, general solution is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)). Hence, required solution of differential equation is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)).
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Find the value of z.
A particular solution and a fundamental solution set are given for the nonhomogeneous equation be specified initial conditions.
3xy"-6y" = -24; x > 0
y(1)=3, y'(1) = 4, y''(1) = -8;
y_p = 2x^2; {1, x, x^4}
(a) Find a general solution to the nonhomogeneous equation
y(x) = 2x^2 +C_1+C_2X+C_3x^4
(b) Find the solution that satisfies the initial
conditions y(1) = 3, y'(1) = 4, and y''(1) = -8.
y(x) = _______
The required solution that satisfies the initial conditions y(1) = 3, y'(1) = 4, and y''(1) = -8 is:
y(x) = 8 - 2/x⁶ + 2x².
(a) To find the general solution to the nonhomogeneous equation 3xy'' - 6y'' = -24, where x > 0, and given the particular solution yp = 2x² and the fundamental solution set {1, x, x⁴}, we can combine the solutions of the complementary and particular parts.
The general form of the complementary solution is yh = C1 + C2/x⁶. The exponent of x must be 6 to make yh a solution of y(x).
Therefore, the general solution to the nonhomogeneous equation is given by y(x) = yh + yp, where yh represents the complementary solution and yp represents the particular solution.
Combining the solutions, the general solution is y(x) = C1 + C2/x⁶ + 2x².
(b) To find the solution that satisfies the initial conditions y(1) = 3, y'(1) = 4, and y''(1) = -8, we substitute these values into the general solution and solve for the constants C1 and C2.
Using the initial conditions:
y(1) = 3 gives C1 + C2 + 2 = 3
y'(1) = 4 gives -6C2 - 4 = 0
y''(1) = -8 gives 36C2 = 8 - 2C1
Solving the above set of equations, we find:
C1 = 8
C2 = -2
Substituting the values of C1 and C2 back into the general solution obtained in part (a), the solution that satisfies the initial conditions is:
y(x) = C1 + C2/x⁶ + 2x²
= 8 - 2/x⁶ + 2x²
Hence, the required solution that satisfies the initial conditions y(1) = 3, y'(1) = 4, and y''(1) = -8 is:
y(x) = 8 - 2/x⁶ + 2x².
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A solution containing 30% juice is mixed with a solution containing 10% juice to make 100 gallons of solution that makes 12% juice.How much of the 30% solution was used
Let the amount of the 30% solution be x gallons.
Then the amount of the 10% solution is (100 - x) gallons.
The amount of juice in the 30% solution is 0.3x gallons.
The amount of juice in the 10% solution is 0.1(100 - x) gallons.
When the two solutions are mixed, we get 100 gallons of a 12% juice solution, which means:
0.3x + 0.1(100 - x) = 0.12(100)
Simplifying this equation, we get:
0.3x + 10 - 0.1x = 12
0.2x = 2
x = 10
Therefore, 10 gallons of the 30% solution was used.
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Find the slope of the line that passes through the given points.
(7,3) and (13,8)
Answer:
\(\frac{5}{6}\)
Step-by-step explanation:
To find the slope, use the equation to find slope. The picture below shows what it looks like.
Using the equation, substitute the values in the x and y values.
\(\frac{8-3}{13-7}\)Then solve
\(\frac{5}{6}\)need help ASAP please
Answer:
A
Step-by-step explanation:
Answer:
Is A
Step-by-step explanation:
√[{1.794*0.038}÷124.3]
Answer:
0.0234189518
Step-by-step explanation: