find the vector sum of the 3 vectors. A= -3i - 2j + 7k, B= i + 3j + 3k, B= -5k​

Answers

Answer 1

Answer:

34k+B plus 9 :)

Explanation:


Related Questions

A sled of mass 26 kg has an 18 kg child on it. If big brother is pulling with a 30 N force to the right and 10 N up, and big sister is pushing with a 40 N force to the right and 16 N down. Assuming that μk = 0.12, calculate:A. The force of frictionB. The acceleration of the sled.

Answers

Given data:

* The mass of the sled is m_1 = 26 kg.

* The mass of the child is m_2 = 18 kg.

* The force acting on the sled in the upward direction by the big brother is F_1 = 10 N.

* The force towards the right by the big brother is F_2 = 30 N.

* The force towards the right by the big sister is F_3 = 40 N.

* The force acting on the sled in the downward direction by the big sister is F_4 = 16 N.

* The coefficient of friction is,

\(\mu_k=0.12\)

Solution:

The net mass on the sled with the child is,

\(\begin{gathered} m=m_1+m_2 \\ m=26+18 \\ m=44\text{ kg} \end{gathered}\)

The weight of the sled with the child is,

\(\begin{gathered} w=mg \\ w=44\times9.8 \\ w=431.2\text{ N} \end{gathered}\)

The normal force acting on the sled is,

\(\begin{gathered} F_N=w+F_4-F_1 \\ F_N=431.2+16-10 \\ F_N=437.2\text{ N} \end{gathered}\)

(A). The frictional force acting on the sled is,

\(\begin{gathered} F_k=\mu_kF_N \\ F_k=0.12\times437.2 \\ F_k=52.464\text{ N} \\ F_k=52.5\text{ N} \end{gathered}\)

Thus, the frictional force acting on the sled is 52.5 N.

(B). The force applied on the sled towards the right by the big brother and big sister is,

\(\begin{gathered} F=F_2+F_3 \\ F=30+40 \\ F=70\text{ N} \end{gathered}\)

The frictional force acts opposite to the direction of applied force, thus, the frictional force acts towards the left.

The net force acting on the sled is,

\(\begin{gathered} F_{\text{net}}=F-F_k \\ F_{\text{net}}=70-52.5 \\ F_{\text{net}}=17.5\text{ N} \end{gathered}\)

According to newton's second law, the acceleration of the sled is,

\(\begin{gathered} F_{\text{net}}=ma \\ a=\frac{F_{\text{net}}}{m} \\ a=\frac{17.5}{44} \\ a=0.4ms^{-2} \end{gathered}\)

Thus, the acceleration of the sled is 0.4 meters per second squared.

g consider a central bank that cares equally about inflation and output. use the 3-equation model to consider an economy that starts out at equilibrium. suppose the is curve shifts permanently to the right. describe the dynamics of the economy back to equilibrium. use a diagram.v

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Since then, a lot of central banks have established clear inflation targets. Central banks often rely on an overnight nominal interest rate to bring inflation toward the target.

The Federal Open Market Committee in the United States, for instance, sets the federal funds rate as its goal.

When inflation is high compared to the inflation target and low compared to the target, Williamson noted, "Conventional central banking practice" increases the nominal interest rate target. This method is justifiable since raising interest rates discourages spending, "cools" the economy, and lowers inflation, while lowering them encourages spending, "heats up" the economy, and raises inflation.

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a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J
walk me through this please. NO LINKS. ​

Answers

Answer:

Is there a picture?

Explanation:

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Two point charges of +2.0 μC and -6.0 μC are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a third charge of +3.0-μC be placed on the +x-axis so that the potential at the origin is equal to zero? =

Answers

Answer:

  x = -3 cm

Explanation:

The electrical potential is the sum of the potentials of each charge

       V = k ∑ \(q_{i} / r_{i}\)

let's apply this to our case where the potential is V = 0 for x = 0

         0 = k (q₁ / (x₁-0) + q₂ / (x₂-0) + q₃ / (x₃-0))

in our case

q₁ = + 2.0 10⁻⁶ C

q₂ = - 6.0 10⁻⁶ C

q₃ = + 3.0 10⁻⁶ C

x₁ = -1.0 cm = 1.0 10⁻² m

x₂ = +2.0 cm = 2.0 10⁻² m

we substitute in the equation

          0 = k (2 10⁻⁶ / 1 10⁻² - 6 10⁻⁶ / 2 10⁻² + ​​3 10⁻⁶ / x)

          3 10⁻⁶ / x = 2 10⁻⁴ - 3 10⁻⁴

          3 10⁻⁶ / x = -1 10⁻⁴

           x = - 3 10⁻² m

           x = -3 cm

Two waves overlap producing a new wave that exhibits destructive
interference. Which statement correctly describes the new wave?

A. It has a larger amplitude than the waves that overlapped to produce it.

B. It has a smaller amplitude than the waves that overlapped to produce it.

C. It has deeper troughs than the waves that overlapped to produce it.

D. It has taller crests than the waves that overlapped to produce it.

Answers

Two waves overlap producing a new wave that exhibits destructive

interference will have a smaller amplitude than the waves that overlapped to

produce it.

Interference is a phenomenon which occurs when two waves travelling in

the same medium( which could be water, air etc) meet.  There are two types

of interference  namely:

Constructive interference.Destructive interference.

The destructive interference involves the positive and negative

displacement canceling out which result in zero displacement or

amplitude.This fact validates option B which states that the new wave will

have smaller amplitude than the waves that overlapped to produce it.

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Answer: B

Explanation: just took it

Can anyone help me in this question, Please?

Can anyone help me in this question, Please?

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The net force acting on the mass \(m_{1}\) is 12 N and the tension (T) in the string is 42 N.

Both the blocks will move with the same acceleration, that is, a = 3 \(m/s^{2}\)

Now, from the free-body diagram of the block \(m_{1}\)

T - F = \(m_{1} a\)

It is given that F = 30 N

and \(m_{1} = 4 kg\)  ,  a = 3\(m/s^{2}\)

Putting all these values, we get:

T - 30 = 4*3 = 12

T = 12 + 30

T = 42 N

Hence, the tension in the string = 42 N

Now, the net force acting on the mass \(m_{1}\) is

\(F_{net}\) = T - F = 42 - 30 = 12 N

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what is the name for a force of gravity acting on an object

Answers

Answer:

Weight

Explanation:

We call it "Ralph" or "the object's weight".

Why is water often called the "universal solvent"? A. A large amount of energy is needed to raise its temperature. B. It remains a liquid over a wide range of temperatures. C. Many different substances can dissolve in it. D. Strong forces of cohesion allow it to form drops.​

Why is water often called the "universal solvent"? A. A large amount of energy is needed to raise its

Answers

Answer:

C

Explanation:

The net force on a box F as a function of the vertical position y is shown below.
What is the work done on the box from y=0 to 6.0m?

The net force on a box F as a function of the vertical position y is shown below.What is the work done

Answers

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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Describe the principle, construction and working of Hydraulic brakes.​

Answers

Answer:

E= mc^2

Explanation:

I don't know.Err.. why don't you ask another person

24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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How do nutritional needs change when a person increases their activity level to gain muscle mass?

Answers

When a person increases their activity level to gain muscle mass, their nutritional needs change.

How utritional needs change when a person increases their activity level to gain muscle mass?

The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.

Individual variations exist, so seeking personalized guidance from a professional is recommended.

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A 0.1 kg mass hangs vertically in equilibrium. In this position, the spring is extended 0.05 m beyond it's un-stretched length. The spring is then stretched an additional 0.05 m and released. What is the total energy in the oscillator?

Answers

ANSWER

0.0245 J

EXPLANATION

Given:

• The mass of the hanging object, m = 0.1 kg

,

• The extension of the spring when the mass is in equilibrium, x₁ = 0.05 m

,

• The additional extension of the spring, x₂ = 0.05 m

Find:

• The total energy in the oscillator, E

First, we have to find what is the spring constant. We can do this by applying Newton's second law of motion when the mass is in equilibrium,

The spring force and the weight of the mass, when it is in equilibrium, are equal in magnitude,

\(F_s=F_g\)

The definition of each force is,

\(k\Delta x=mg\)

Where k is the spring constant and Δx = x₁. Solving for k,

\(k=\frac{mg}{x_1}=\frac{0.1kg\cdot9.8m/s^2}{0.05m}=19.6kg/s^2\)

Now, we can find the total energy of the oscillator, which is given by,

\(E=\frac{1}{2}kA^2\)

Where k is the spring constant and A is the amplitude of the oscillation - in this case, this is how much the spring is stretched from the un-stretched length, so A = 0.05 m,

\(E=\frac{1}{2}\cdot19.6kg/s^2\cdot0.05^2m^2=0.0245\text{ }J\)

Hence, the total energy in the oscillator is 0.0245 Joules.

A 0.1 kg mass hangs vertically in equilibrium. In this position, the spring is extended 0.05 m beyond

Having come late to practice, a baseball player is forced to run from one side of the 100-meter field and back three times, which takes him 345 seconds. What is his average velocity throughout the task?

Answers

The average velocity for completing three rounds of the basketball court would be zero as initial and final position would be zero and the average speed would be 3.28 m/s.

What is average velocity ?

Average velocity is defined as the total displacement divided by the total time take to compete the total displacement.

What is average speed ?

Average speed is defined as the total distance divided by the total time take to compete the total distance.

Given:

Side of the baseball court = 100 meter

Total time taken to complete three rounds of the basketball court = 375 seconds

Total distance traveled by the player can be measured using the given side of the basketball court.

First we will find the parameter of the court,

Parameter of the court = 4 times the side of basketball court

Parameter of the basketball court = 4 × 100

Parameter of the basketball court = 400 metre

The player goes for 3 rounds of the basketball court which makes the total distance three times the parameter of the basketball court.

Total distance traveled by the basketball player = 3 × 400

Total distance traveled by the basketball player = 1200 metre

Average velocity is displacement divided by time taken.

Total displacement = 0 metre

As the player reaches the same position from where he started so the total displacement is zero.

Therefore, average velocity = 0/365

average velocity = 0 m/s

Average speed = 1200/365

Average speed = 3.28 m/s

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What is the answer please help

What is the answer please help

Answers

Answer:

I think c

Explanation:

cold air pushes warm air up and then the air mixes(im not sure)

(a) if a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) does the sp

Answers

In response to questions (a) and (b), I will say that wave speed each component of the rope must help to sustain the rope's weight, and as a result, tension will tend to rise with height.

What impact does the rope's tension have on the waves?

A wave's speed increases as a string's tension does, increasing the frequency (for a given length). By applying pressure in various locations, you may alter the string's length, the standing wave's wavelength, and consequently, its frequency.

If the rope does not expand, take note that the increase is linear. Thus, when height rises, the wave speed v= √ T/μ

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Question:-

(a) If a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) Does the speed of the ascending waves increase or decrease? Explain.

Why are the noble gases the least reactive elements?

Answers

because they have eight valence electrons, which fill their outer energy level.

19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?

Answers

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Somebody, please help me with these by April 6 I'm about to fail my class

1. Describe specific heat capacity and its use in calorimetry.
2. Define latent heat and how it is different than specific heat capacity.
3. Describe how a phase diagram changes when changing from a solid to a liquid.
4. Describe how work is done is related to a change in the volume of a fluid.
—Continue on the next page—
5. What is the relationship of change in internal energy, work, and heat? Explain the significance in terms of energy.
6. As succinctly as possible, explain why it is impossible to have an engine that is 100% efficient.
7. Describe the application of Archimedes principle in everyday terms.
Practice
8. 50 grams of a substance increases its temperature by 10 degrees when 100 J of heat is added. What is the specific heat capacity of the substance?
9. Ten kilograms of a substance has a latent heat of 1000 J/kg. How much energy does it take to change the phase of this substance?
—Continue on the next page—

10. The work done by a piston is measured to be 1000 J. If the pressure is a constant 1000 Pa, what is the change in volume of the piston?
11. Is the process described in #10 isovolumetric? Explain.
12. Is it possible for a substance to change the temperature in an isovolumetric and adiabatic process? Explain.
13. A substance is heated with 1000 J and does 700 J of work on the atmosphere. What is the change in the internal energy of the substance?
14. An engine causes a car to move 10 meters with a force of 100 N. The engine produces 10,000 J of energy. What is the efficiency of this engine?
—Continue on the next page—

15. If a ball of radius 0.1 m is suspended in water, density = 997 kg/m^3, what is the volume of water displaced and the buoyant force?
16. A 10 kg ball of volume = 0.005 m3 is set on a lake. Describe what will happen to the ball.
Application
A group of physics students heats a vial of water, which has a balloon at the top that traps the water vapor and air.
17. Describe how much the internal energy is changed if the students are adding heat to the water via a Bunsen burner. No need to calculate anything.
18. If 50 grams of water start to boil, then how much heat must be added to completely boil off the water? The latent heat of vaporization is 2,260,000 J/kg
—Continue on the next page—

19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
20. Assuming the atmospheric pressure to be constant at 101,325 Pa, by what amount does the volume of the balloon change?

Answers

Answer:

im sorry i would help but thats too much

When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.​

Answers

Answer:

Given: V=12 V

            I=2.5 mA

Let the resistance be R

By Ohm's Law, 

V=IR

12=2.5×10−3R

R=4.8×103 Ω

you are boiling water to make pasta. How could you descibribe the pot, water, and pasta using physical properties?

Answers

Answer:

Yes

Explanation:

As a personification

Answer: heat,h2o,food

Explanation:

It is all Physical properties

Select the correct answer.
Proper technique can help prevent injuries.
A.
True
B.
False

Answers

Answer:

b

Explanation:

Answer:

false

Explanation:

student measuring the mass of a rock recorded 6.759 g, 6.786 g, 6.812 g, and 6.779 g. which other measurment of the block mass would be most precise ?

Answers

Answer:   6.605

Explanation:

your apparent weight is equal to your weight group of answer choices in an elevator accelerating upwards.

Answers

inside a moving elevator, in free fall

Do you weigh the same inside an elevator?

We shall weight ourselves when the elevator is travelling at our normal weight. Because we are currently moving up or down the elevator at the same speed, nothing is changing our weight. However, once the elevator begins to move or stops, our bodies resist it.

What is the apparent weight when the elevator is running?

If the elevator accelerates downward, an is negative and the apparent weight is less than the real weight. There is no weight discernible if the elevator descends naturally. The apparent weight is zero because when a human and a scale are falling freely, they cannot clash.

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An organism is prokaryotic, unicellular, and autotrophic, and it also causes disease. Which kingdom does it belong in
pls answr

Answers

Answer:

Eubacteria Kingdom :)

Explanation:

Answer: eubacteria

Explanation:

After crossing the finish line, a race car slows down from 47 m/s to 32m/s in 3seconds. What is the car’s acceleration?

Answers

Answer: -5 m/s^2

Explanation: a = v - u/t

                         = 32 - 47/3

                         = -15/3

                         = -5 m/s^2

the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm​

Answers

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

What is the image and object distance?

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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before a school bus stops to load passengers the driver will usually flash

Answers

Answer:

yellow flashing lights

A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.

When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e

Answers

Answer:

e

Explanation:

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